Line a is parallel to line b if the measure of <7 Is 114 what is the measure of <1
The measure of ∠1 is 114.
What are corresponding angles?The angles that are in the same position on two parallel lines intersected by a transversal line on the parallel lines.
Corresponding angles are equal.
We have,
∠7 = 114
From the figure,
Line a is parallel to line b.
So,
∠7 and ∠1 are alternate exterior angles.
And,
Alternate exterior angles are equal.
So,
∠7 = ∠1 = 114
Thus,
∠1 is 114.
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(5×-1)(6×2+3×+8) box method
The final result is: 30x^3 - 6x^2 + 15x^2 - 3x + 40x - 8 = 30x^3 + 9x^2 + 40x - 8
What is the Box method?The box method, also known as the FOIL method, is a way of multiplying two polynomials by using the distributive property.
Given the expression (5x - 1)(6x^2 + 3x + 8), we can use the box method to multiply the terms as follows:
First terms: (5x - 1) * 6x^2 = 30x^3 - 6x^2Outer terms: (5x - 1) * 3x = 15x^2 - 3xInner terms: (5x - 1) * 8 = 40x - 8Last terms: (5x - 1) * 8 = 8Therefore., the final result is:
30x^3 - 6x^2 + 15x^2 - 3x + 40x - 8 = 30x^3 + 9x^2 + 40x - 8
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Prove, that 32^5-16^5+2^19 is divisible by 63.
I will award brainyist
[tex]32^5[/tex] - [tex]16^5[/tex] + [tex]2^{19}[/tex] is divisible by 63.
What is an expression?An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example: 2 + 3x + 4y = 7 is an expression.
We have,
[tex]32^5[/tex] - [tex]16^5[/tex] + [tex]2^{19}[/tex]
= 33554432 - 1048576 + 524288
= 33030144
Now,
33030144 ÷ 63
= 524288
Thus,
It is divisible by 63.
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Elisa packs her suitcase before the trip the suitcase weighs 49 pounds the airline only allowed suitcases that way up to 23 km can Elisa take the suitcase on the plane show your work for every 10 kg there are about 22 pounds
The suitcase weighs 2.23 kg, which is less than the 23 kg weight limit, Elisa can take the suitcase on the plane.
To determine if Elisa's suitcase is within the weight limit of 23 kg, we need to convert the weight of the suitcase from pounds to kilograms.
the suitcase weighs 49 pounds the airline only allowed suitcases that way up to 23 km is it correct weight or not
First, we need to convert 10 kg to pounds: 10 kg * (22 pounds / 1 kg) = 220 pounds
Next, we need to convert 49 pounds to kilograms: 49 pounds / (22 pounds / 1 kg) = 2.23 kg.
Since the suitcase weighs 2.23 kg, which is less than the 23 kg weight limit, Elisa can take the suitcase on the plane.
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The actual temperature of Noah's oven is 325 degrees, but his oven thermometer is reading 340 degrees. What is the percent error?
Answer:
it has an error of 15 more then the actual temperature
Step-by-step explanation:
to find the change all you have to do is just subtract 340 -325 that is 15 so if the oven was 100 it would show 115
Given the function f(x) = 4x^3 - 4, find the value of f(- 1/2)
The function [tex]f(x) = 4x^3 - 4[/tex] is a polynomial function. It takes an input value x and returns an output value f(x) based on the expression [tex]4x^3 - 4.[/tex]So the value of f(-1/2) is -4.5.
When we evaluate f(-1/2), we substitute -1/2 for x in the expression for f(x). This gives us:
[tex]f(-1/2) = 4(-1/2)^3 - 4[/tex]
The expression inside the parentheses, [tex](-1/2)^3,\\[/tex] is the cube of -1/2. To simplify this expression, we need to first raise -1/2 to the power of 3:
[tex](-1/2)^3 = (-1/2) * (-1/2) * (-1/2) = -1/8[/tex]
Next, we substitute this value back into the expression for f(-1/2):
f(-1/2) = 4(-1/8) - 4
Now we can simplify the expression by multiplying 4 and -1/8:
f(-1/2) = -1/2 - 4
Finally, we subtract 4 from -1/2 to get the final answer:
f(-1/2) = -4.5
So the value of f(-1/2) is -4.5.
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Given the function f(x) = 4x^3 - 4, find the value of f(- 1/2)?
Mrs. Thapa wishes to grow flowers on the hanging bowls at her home. She brings 16 hemispherical bowls from the market having internal diameter 21 cm and uniform thickness 0.5 cm each and fills the bowls with compost completely. (i) If 1 cm³ of compost weighs 2.31 gm, find the total weight of required compost. (ii) If she covers outer curved surface of each bowl with polythene sheet, find the total amount of polythene
Answer:
(i) The volume of each hemispherical bowl can be calculated as follows:
Volume of a hemispherical bowl = (2/3) x pi x (d/2)^3, where d is the internal diameter of the bowl.
Substituting d = 21 cm, we get:
Volume of a hemispherical bowl = (2/3) x pi x (21/2)^3 = 4851.97 cubic centimeters
The total volume of compost required to fill all 16 bowls is therefore:
Total volume of compost = 16 x 4851.97 = 77631.52 cubic centimeters
If 1 cm³ of compost weighs 2.31 gm, then the total weight of required compost is:
Total weight of compost = 77631.52 x 2.31 = 179231.83 grams or 179.23 kilograms
Therefore, Mrs. Thapa would need 179.23 kilograms of compost to fill all 16 hemispherical bowls.
(ii) The outer curved surface area of each hemispherical bowl can be calculated as follows:
Outer curved surface area of a hemispherical bowl = 2 x pi x (d/2)^2, where d is the internal diameter of the bowl.
Substituting d = 21 cm, we get:
Outer curved surface area of a hemispherical bowl = 2 x pi x (21/2)^2 = 693.84 square centimeters
The total outer curved surface area of all 16 bowls is therefore:
Total outer curved surface area = 16 x 693.84 = 11101.44 square centimeters
If Mrs. Thapa covers the outer curved surface of each bowl with polythene sheet, then the total amount of polythene required would be equal to the total outer curved surface area of all 16 bowls.
Therefore, the total amount of polythene required would be 11101.44 square centimeters.
Step-by-step explanation:
Leslie and Ben are designing a neighborhood. Drawing their designs out on a grid, they determined that the lot for the community mailboxes would be centered at (0,0). They created the first road to pass through lots centered at (3,1) and at (9,3). They want to make another road that intersects the first road at a 90-degree angle, and they want it to intersect the center of the lot at (3,1). Determine the equation for this second road.
The equation of the second road is y = -3x + 10
The location of the mail box = (0, 0)
The first road passes through the points (3, 1) and (9,3)
The slope of the line is the change in y coordinate with respect to the change in x coordinate
The slope of the line m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Substitute the values in the equation
m = 3-1 / 9-3
m = 2/6
m = 1/3
The next road is 90 degrees to the first road
Then the slope of the second line will be
m1 = -1/m
= -1/(1/3)
= -3
The second road passing through the point (3, 1)
The equation of line
y = mx + b
Substitute the given values in the equation
1 = -3 × 3 + b
1 = -9 + b
b = 1 +9
b = 10
Therefore, the equation will be y = -3x + 10
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need help asap
how to explain the answer
By the property of SAS criterion,
ΔKMN is similar to ΔKJL.
What are similar triangles?Those triangles look the same but are different in size.
And in similar triangles,
the corresponding sides are proportionate, and the corresponding angles are equal.
Given:
In ΔJKL,
MN is parallel to JL.
That means MN and JL are equally spaced.
So,
JM/MK = LN/NK
∠KMN ≅ ∠KJL {By corresponding angles}
ΔKMN is similar to ΔKJL. {By the SAS criterion}
Therefore, ΔKMN is similar to ΔKJL.
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a sample of 64 account balances from a credit company showed an average daily balance of $1,040. the standard deviation of the population is known to be $200. we are interested in determining if the mean of all account balances (i.e., population mean) is significantly higher than $1,000. n determining if the mean of all account balances (i.e., population mean) is significantly higher than $1,000. a. develop the appropriate hypotheses for this problem. b. determine the test statistic (t statistic or z statistic?), and then compute the test statistic. c. compute the p-value. d. using the p-value approach at 95% confidence, test the above h
The test static is 1.60 and the p-value is 0.1096, null hypothesis is not rejected and the population mean is not significantly different from $1000.
Assuming normal distribution
N( μ₀ , σ )
In this case N ( 1000, 200)
From a random sample of 64 accounts we get:
n = 64
x = sample mean x = 1040
σ = standard deviation of the population σ = 200
a) Test Hypothesis
Null Hypothesis H₀ x = μ₀ = 1000
Alternative Hypothesis Hₐ x ≠ μ₀
The alternative hypothesis implies a two tail-test. Given that n > 30 and σ is known we will use z-table
b) z(s) = ( x - μ₀ ) / σ/√n
z(s) = ( 1040 - 1000 ) / 200/ √64
z(s) = 40*8/200
z(s) = 1.60
c) P-value for z (score 1.6) p-value = 0.1096
d) If significance level is 0.05 then α = 0.05 and α/2 = 0.025
p-value > α/2
Then the z(s) < z(c) 1.6 < 1.96 where z(c) is z score for α/2
Hence, null hypothesis is not rejected
e) We can claim that at 95 % (of Confidence Interval) the population mean is not significantly different from $1000.
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Question is not complete. The complete question is :
A sample of 64 account balances from a credit company showed an average daily balance of $1,040. The standard deviation of the population is known to be $200. We are interested in determining if the mean of all account balances (i.e., population mean) is significantly different from $1,000. 1. State the null and alternative hypothesis. 2. Compute the test statistic. 3. Compute the p-value. 4. Based on the p-value and the significance level of 0.05% make a decision regarding the hypotheses. 5. Interpret your results in the context of the problem.
How do I factor this polynomial?
2r³t8r²-90r
Answer: it is already factored
Step-by-step explanation:
(a) What additional information is needed to prove the triangles are congruent by ASA Postulate? Explain.
(b) What additional information is needed to prove the triangles are congruent by the HLTheorem? Explain.
Part (a)
ASA = angle side angle
To use ASA, we need two angles and a side between those angles. We already have one pair of angles (DFE and GHI). The other pair of angles must be DEF and GIH to have the side sandwiched between the angles.
Answer: We need to know if angle DEF is congruent to angle GIH===================================================
Part (b)
HL = hypotenuse leg
The sides EF and IH are congruent to one another because of the tickmarks. They are the legs of each right triangle. So that takes care of the "L" of "HL". We need to have the hypotenuses congruent to each other to be able to use HL. This theorem only applies to right triangles.
Answer: We need to know if segment DE is congruent to segment GIThe sum of three consecutive odd integers is 147. what is the third number? a. 49b. 47 c. 48 d. 51
The three consecutive odd integers are 47, 49, and 51. The third number is 51, so the answer is (d) 51.
Let's represent the first odd integer as x. Then, the next two consecutive odd integers would be x + 2 and x + 4.
According to the problem, the sum of these three consecutive odd integers is 147:
x + (x + 2) + (x + 4) = 147
We simplify and solve for x, which gives us the value of the first integer.
Simplifying and solving for x, we get:
3x + 6 = 147
3x = 141
x = 47
So the three consecutive odd integers are 47, 49, and 51. The third number is 51, so the answer is (d) 51.
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Lineshasaslopeof
–8
9. Line
tisparalleltoline
s. What
istheslopeofline
t ?
Answer: 4
Step-by-step explanation:
I NEED HELP PLEASEEEE!!!!
Answer:
Step-by-step explanation:
the answer is 420 cuase the manufatcure of math is hard i wont give an explanation.
A dairy spends $21,000 per year to maintain its barns and equipment. It costs $2000 per year to feed and care for each dairy cow. (a)
Using C for the number of dairy cows and E for the total yearly expense, in dollars, find a formula that gives the total yearly expense as a linear function of the number of dairy cows. E =
(b)
The yearly income I, in dollars, for the dairy comes from milk production, which depends on the number C of dairy cows. Each dairy cow produces 3500 gallons of milk per year, and the dairy sells milk for $2. 00 per gallon. Find a formula that gives I as a linear function of C. I =
Incorrect: Your answer is incorrect. (c)
Determine the smallest number of cows the dairy needs in order to (at least) break even. Your answer should be a whole number. Incorrect: Your answer is incorrect. Cows
a) Formula that gives the total yearly expense as a linear function of the number of dairy cows is E = 21,000 + 2,000C.
b) Formula that gives I as a linear function of C is I = 7,000C. The smallest number of cows the dairy needs to break even is 5.
(a) Let's call the number of dairy cows "C".
The yearly expense for maintaining the barns and equipment is a fixed cost of $21,000.
The yearly expense for feeding and caring for each dairy cow is $2,000.
To find the total yearly expense, we can add the fixed cost of maintaining the barns and equipment to the variable cost of caring for the cows:
E = 21,000 + 2,000C
This is a linear equation that gives the total yearly expense as a function of the number of dairy cows.
(b) Each dairy cow produces 3,500 gallons of milk per year.
The dairy sells milk for $2.00 per gallon.
To find the yearly income for the dairy, we can multiply the number of gallons of milk produced by the price per gallon:
I = 2.00(3,500)C = 7,000C
This is a linear equation that gives the yearly income as a function of the number of dairy cows.
To determine the smallest number of cows the dairy needs in order to break even, we need to find the point where the yearly income is equal to the yearly expense.
Setting I = E, we get:
7,000C = 21,000 + 2,000C
Simplifying and solving for C, we get:
5,000C = 21,000
C = 4.2
Since we cannot have a fraction of a cow, we round up to the nearest whole number.
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maths grade 8 cbse...
The value of the expression is 5.
What is order of operations?
The order of operations is a rule that specifies the correct sequence of steps to be taken when evaluating a mathematical equation.
To simplify this expression, we need to follow the order of operations, which is:
Exponents (powers, roots)
Multiplication and Division (from left to right)
Addition and Subtraction (from left to right)
So, we start with the exponents:
[tex]3^0+4^{-1} \\= 1 + 1/4 \\= 5/4[/tex]
Now we substitute this value back into the original expression:
[tex](3^0+4^{-1} )*2^2\\ = (5/4) * 2^2 \\= (5/4) * 4 \\= 5[/tex]
Therefore, the value of the expression is 5.
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Mr. Steiner purchased a car for about $14,000. Assuming his loan was
compounded monthly at an interest rate of 4. 9% for 72 months:
p=
r=
n=
t=
A. How much will he have paid total?
B. How much more did he pay than the price of the car?
Mr. Steiner will need to pay $18774 in total and he paid $4774 more than the actual price of the car.
we know that the amount of money earned, in compound interest after t years is showed as, A(t) = P (1+[tex]\frac{r}{n}[/tex])ⁿ[tex]^{t}[/tex]
here, we know that A(t) is the amount of money after t years.
P is the initial sum of money, know as principal,
r is the interest rate as a decimal value,
n is the number of times that interest is compounded per year,
and
t is the time in years for which the money is invested or borrowed.
now here we know,
P = 14000, r = 0.049, n = 12, t = 6
when we have all values we can find,
A(t) = P(1+[tex]\frac{r}{n}[/tex])ⁿ[tex]^{t}[/tex]
A(6) = 14000 (1+[tex]\frac{0.049}{12}[/tex])¹²ˣ⁶
A(6) = 18774
therefore we know that Mr. Steiner needs to pay $18774 in total.
now,
18774 - 14000 = 4774
therefore we get to know that Mr. Steiner paid $4774 more than the actual price of the car.
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Answer choices for Z -
$1.51
$25.08
$33.93
$26.59
Answer choices for X -
$22.35
$1.27
$3.72
$383.66
The correct answer choices for Z and X are $25.08 and $3.72, respectively.
What is a Simultaneous Equation?A finite set of equations for which common solutions are sought is referred to in mathematics as a set of simultaneous equations, often known as a system of equations or an equation system.
How to solve for this
To solve for Z and X simultaneously, you can use the following equation: Z + X = 59.5
You can then compare the four given answer choices for Z and X to determine which ones satisfy the equation.
For example, $1.51 + $22.35 = $23.86, which is not equal to 59.5, so neither of these answer choices is correct.
However, $25.08 + $3.72 = $28.80 which is equal to 59.5, so the correct answer choices for Z and X are $25.08 and $3.72, respectively.
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The band Leeward charges different prices for its concert tickets based on a concert-goer's age. The total cost, in dollars, of tickets for a adults and c children is 12a+6c. Edgar bought tickets for 4 adults and 6 children.
How much did Edgar pay for tickets?
Answer:
I believe Edgar payed $84 for the tickets.
Step-by-step explanation:
12(4)=48
6(6)=36
48+36=84
10
Select whether the given side lengths of a triangle form a right triangle.
Do Not Form a
Right Triangle
3 cm, 4 cm, 5 cm
8 m, 10 m, 15 m
6 in., 8 in., 10 in.
5 cm, 12 cm, 13 cm
Form a
Right Triangle
0
Answer:yes,no,yes,no i think
Step-by-step explanation:
Rewrite 26/9 as a mixed number. help me
The required mixed number of 26/9 is given as 2 8/9.
What is a mixed number?A mixed number is a number that consists of a whole number and a proper fraction. It is written in the form "a b/c", where "a" is the whole number, "b" is the numerator of the proper fraction, and "c" is the denominator of the proper fraction.
Here,
To rewrite 26/9 as a mixed number, we need to divide the numerator (26) by the denominator (9) and express the result as a whole number and a proper fraction.
26 ÷ 9 = 2 with a remainder of 8
The whole number part is 2, and the proper fraction part is 8/9, since 8 is the remainder and 9 is the denominator.
Therefore, 26/9 as a mixed number is 2 8/9.
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If these two shapes are similar, what is the measure of the missing length h?
In similar triangles, 15.07 miles is the measure of the missing length h .
What does "similarity" for triangles mean?
Triangles are said to be comparable if two of their angles have measurements that are the same as those of two other triangles' angles. In proportion, and with the same measure, are the equivalent sides and angles of identical polygons.
To test whether two triangles are similar, use one of the three triangle similarity theorems, Angle-Angle (AA), Side-Angle-Side (SAS), or Side-Side-Side (SSS).
35/65 = 28/h
h = 35 * 28/65
h = 15.07 miles
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I’m so confused about this problem:
1 5/9 ÷ -1/2
Can anyone help me?
(ToT)
Answer: -3.11111112
Step-by-step explanation:
1 and 5/9 as a decimal is 1.555555556
-1/2 as a decimal is -0.5
1.555555556 divided by -0.5 is -3.11111112
The graph of f(x) = ce^x crosses the y -axis at (0, c) where c is some constant: Where does the graph of g (x) = f(x)- d cross the y -axis? The graph of g (x) = f(x) -d crosses the Y ~axis
The graph of g(x)=f(x)-d crosses the y-axis at (0,c-d).
What does y-intercept mean?
The point on a line where it crosses the y-axis is known as the y-intercept. To put it another way, it is the value of y when x is equal to 0.
It is given that graph [tex]f(x)=ce^{x}[/tex] crosses the y-axis at (0,c).
Because at x=0,
[tex]f(0)=ce^{0}\\f(0)=c[/tex].
So, if g(x)=f(x)-d
[tex]g(x)=ce^{x}-d[/tex]
when x=0:
[tex]g(0)=ce^{0}-d\\g(0)=c-d[/tex]
So the graph of g(x)=f(x)-c touches the y-axis at (0,c-d).
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i need help with this pls
Answer:
90°
Step-by-step explanation:
every inscribed triangle with the baseline (Hypotenuse) being a diameter of the circle is a right-angled triangle.
therefore, that angle x = 90°.
the weight distribution of packages sent in a certain manner is normal with mean value 12 lb and standard deviation 3.5 lb. the package service wishes to establish a weight value c beyond which there will be a surcharge. what value of c is such that 99% of all packages are at least 1.0 lb under the surcharge weight?
The surcharge weight should be set at 12.25 lb, since 99% of all packages are at least 1.0 lb under this weight.
In this problem, we are given that the weight distribution of packages sent in a certain manner is normal, with a mean value of 12 lb and a standard deviation of 3.5 lb. The standard deviation is a measure of how much the data varies from the mean.
Now, the package service wishes to establish a weight value c, beyond which there will be a surcharge. We want to find the value of c such that 99% of all packages are at least 1.0 lb under the surcharge weight. This means that we are looking for a weight value that is exceeded by only 1% of all packages.
To find this weight value, we can use the properties of the normal distribution. We know that the area under the normal curve represents the probability of an event occurring. In this case, we want to find the weight value c that corresponds to the 1% probability.
To do this, we first need to standardize our normal distribution by converting it to the standard normal distribution, which has a mean of 0 and a standard deviation of 1. We can do this by subtracting the mean (12 lb) from our target weight value c, and then dividing by the standard deviation (3.5 lb). This gives us a z-score, which represents the number of standard deviations away from the mean our target weight value is.
Next, we can use a standard normal distribution table or calculator to find the z-score that corresponds to the 1% probability. This is approximately -2.33.
Finally, we can solve for c by reversing the standardization process. We multiply the z-score (-2.33) by the standard deviation (3.5 lb) and add the mean (12 lb) to get our target weight value c.
Therefore, c = -2.33 x 3.5 + 12 ≈ 0.25 lb.
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Similar Triangles Question
Solve for the missing length, X.
The required value of the x for the missing lengths of the side triangle is given as 28.6 ft.
What are Similar triangles?Similar triangles are those triangles that have similar properties,i.e. angles and proportionality of sides.
here,
As the triangles are similar,
The ratio of corresponding sides is equal,
So
13/5 = x/11
x = 13 × 11 / 5
x = 28.6
Thus, the required value of the x for the missing lengths of the ais given as 28.6 ft.
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5843 divided by 11 whth remainders
Answer:
Remainder:
Step-by-step explanation:
Step 1: Divide 5843 by 11.
5843/11 = 530.272727
Step 2: Find the quotient.
Quotient = 530
Step 3: Find the remainder.
Remainder = 3
what is the number of ways to choose two toppings for a pizza, one topping from a group of 5 kinds of meats and the other topping from a group of 7 kinds of vegetables?
There are 35 ways to choose two toppings for a pizza, one topping from a group of 5 kinds of meats and the other topping from a group of 7 kinds of vegetables.
The multiplication rule of counting in Permutation and Combinations states that if there are n ways to perform one task and m ways to perform a second task, then there are n x m ways to perform both tasks in sequence.
The number of ways to choose a meat topping from 5 kinds of meats = 5.
The number of ways to choose a vegetable topping from 7 kinds of vegetables = 7.
Using the multiplication rule, the number of ways to choose one meat topping and one vegetable topping is = 5 x 7 = 35 ways.
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