PQR has the vertical P(0,4), Q(4,5), and R(4,1). Determine if PQR is the right triangle.

Answers

Answer 1

Answer:

no

Step-by-step explanation:

no it is not a right triangle

two angles share the same x but no angles share the same y

you can see this clearly when graphed

the answer is no


Related Questions

A book sold 42,600 copies in its first month of release. Suppose this represents 9.2% of the number of copies sold to date. How many copies have been sold to date?

Answers

Answer:

We lend 100% - 9.2% and this will equal 90.8%, then we will make this percentage of 42,600 which will give us 38,680 and we will add the 42,600 and this will give us a total of 81,460 copies.

what percent of 15.5 is 12.9? round to the nearest hundredth of 8%

Answers

Answer:

83.23%

Step-by-step explanation:

Proportioned Value = 12.9

Total Value = 15.5

Percentage = Proportioned Value / Total Value * 100%

= [tex]\frac{12.9}{15.5}*100[/tex]

= 83.23% (nearest hundredth)

The answer is 83.23%.

To find the percentage, take the ratio between 12.9 and 15.5, and multiply by 100%.

12.9/15.5 × 100%0.8323 × 100%83.23%

Calcular el valor del ángulo que falta de un triangulo rectangulo si uno de sus lados mide 25 grados.

Answers

Considerando la definición de triángulo rectángulo y sus propiedades, el valor del ángulo que falta de un triángulo rectángulo es 65°.

Definición de triángulo

Un triángulo es un polígono conformado por tres lados, así como por tres vértices y tres ángulos interiores.

Una de las propiedades de cualquier triángulo indica que la suma de los ángulos interiores es igual a 180°.

Definición de triángulo rectángulo

El triángulo rectángulo es una figura geométrica que se considera como un polígono formado por tres lados que forman un ángulo interior recto (es decir, mide 90°) y dos ángulos interiores agudos.

Valor del ángulo faltante en este caso

En este caso, sabes que:

Al ser un triángulo rectángulo, un ángulo interior mide 90°.Otro ángulo interior mide 25°.La suma de los ángulos interiores es igual a 180°.

Entonces, el valor del ángulo faltante se puede calcular mediante:

90° + 25° + ángulo faltante= 180°

Resolviendo:

115° + ángulo faltante= 180°

ángulo faltante= 180° - 115°

ángulo faltante= 65°

Finalmente, el valor del ángulo que falta de un triángulo rectángulo es 65°.

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For the function f(x)=3x²-7, find the value of f(x) when x=3.

Answers

Answer:

Step-by-step explanation:

Simply plug in a 3 where you see an x in the function:

[tex]f(3)=3(3)^2-7[/tex] so

f(3) = 3(9) - 7 and

f(3) = 27 - 7 so

f(3) = 20

A vector U has initial point (-3,-2) and terminal point (-6,1) .
Write U in component form.

Answers

Answer:

<-3,3>

Step-by-step explanation:

In a population where 81 % of voters prefer Candidate A,
an organization conducts a poll of 15 voters. Find the
probability that 11 of the 15 voters will prefer Candidate

Answers

The probability of 11 voters out of 15 voting candidate A is 0.9770

According to the statement

we have given that the percentage of voters is 81% and poll conducts are 15 and we have to find the probability that 11 of the 15 voters will prefer Candidate

So, For this purpose,  

the question in based on binomial probability which means the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes p and q and p+q=1

let probability of choosing candidate A be p

and probability of choosing candidate B be q

In question p=0.81 and q=0.16

n be total number of voters=15

x be number of successes

then P(x=x)= [tex]\frac{n}{x} p^{x} q^{n-x}[/tex]

P(x=11)= [tex]\frac{11}{15} 0.81^{11} 0.16^{4}[/tex]

= 0.9770

So, the probability of 11 voters out of 15 voting candidate A is 0.9770

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find the positive square roots by division method of 151,321 please tell me fast

Answers

Answer:

389 is the answer

Hope you like it!

a rectangular floor of a room measures 5.4m long and 4.2m wide .the room is to be covered with square tiles . Calculate the minimum number of the floor​

Answers

Answer: 22

Step-by-step explanation:

Number of floor tiles = (5.4m × 4.2m) ÷ 1m²

Number of floor tiles = 22.68

Minimum number of floor tiles = 22

[tex]\lim_{x \to 0 (\frac{x(x-2)}{2-2e^2x} )[/tex]
Help evaluting this limit

Answers

Answer: 0

Step-by-step explanation:

Substituting in x=0, we get

[tex]\frac{0(0-2)}{2-2e^{2}(0)}=0[/tex]

An administrator surveys a random sample of 48 out of 900 middle school
students. Using the survey results, the administrator estimates that 225 students
are in favor of the new dress code. How many of the 48 students surveyed were
in favor of the new dress code?

Answers

Considering the definition of probability, 12 of the 48 students surveyed were in favor of the new dress code.

Definition of probability

Probability is the greater or lesser chance that a given event will occur.

In other words, the probability establishes a relationship between the number of favorable events and the total number of possible events.

Then, the probability of any event A is defined as the ratio between the number of favorable cases (number of cases in which event A may or may not occur) and the total number of possible cases. This is called Laplace's Law.

P(A)=number of favorable events÷ number of total events

Probability that students are in favor of the new dress code

In this case, you know:

Total number of middle school students = 900 (number of possible cases)The number of students are in favor of the new dress code = 225 (number of favorable cases)

Replacing in the definition of probability:

P(A)=225 students÷ 900 students

Solving:

P(A)= 0.25

Expressed as a percentage:

P(A)= 25%

Number of the 48 students surveyed were that in favor of the new dress code

In this case, you know:

Total number of middle school students = 48 (number of possible cases)25% students are in favor of the new dress code (P(A)= 25%= 0.25)

Replacing in the definition of probability:

0.25=students in favor of the new dress code÷ 48 students

Solving:

students in favor of the new dress code= 0.25×48 students

students in favor of the new dress code= 12 students

Finally, 12 of the 48 students surveyed were in favor of the new dress code.

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HELP PLEASE will give brainliest

Answers

Answer:

This is an example of correlation because there is an obvious relationship between the two scenarios

Step-by-step explanation:

This is not cause-and-effect therefore cannot be causation or "cause"

Julio wants to calculate 200,000 × 300,000. When he used his calculator to multiply, it showed the result below:
6E+10

Write the number shown on the calculator display in standard form.

Answers

The number shown on the calculator display can be written in standard form as 6 x 10¹⁰.

Product of 200,000 and 300,000

The product of 200,000 and 300,000 is calculated as follows;

200,000 × 300,000 = 6E+10

What is standard form?

Standard form is a mathematical way or a standard way of presenting numbers as a mathematical expression.

It presents numbers in the simplest form.

Product of 200,000 and 300,000 in standard form

200,000 × 300,000 = 6 x 10¹⁰

Thus, the number shown on the calculator display can be written in standard form as 6 x 10¹⁰.

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Use the Divergence Theorem to evaluate the surface integral

Answers

Compute the divergence of [tex]\vec F[/tex].

[tex]\mathrm{div}(\vec F) = \dfrac{\partial(2x^3+y^3)}{\partial x} + \dfrac{\partial (y^3+z^3)}{\partial y} + \dfrac{\partial(3y^2z)}{\partial z} = 6x^2 + 3y^2 + 3y^2 = 6(x^2+y^2)[/tex]

By the divergence theorem, the integral of [tex]\vec F[/tex] across [tex]S[/tex] is equivalent to the integral of [tex]\mathrm{div}(\vec F)[/tex] over the interior of [tex]S[/tex], so that

[tex]\displaystyle \iint_S \vec F\cdot d\vec S = \iiint_{\mathrm{int}(S)} \mathrm{div}(\vec F)\,dV[/tex]

The paraboloid meets the [tex]x,y[/tex]-plane in a circle with radius 3, so we have

[tex]\mathrm{int}(S) = \left\{(x,y,z) \mid x^2+y^2\le3 \text{ and } 0 \le z \le 9-x^2-y^2\right\}[/tex]

and

[tex]\displaystyle \iiint_{\mathrm{int}(S)} \mathrm{div}(\vec F) \,dV = \int_{-3}^3 \int_{-\sqrt{9-x^2}}^{\sqrt{9-x^2}} \int_0^{9-x^2-y^2} 6(x^2+y^2)\,dz\,dy\,dx[/tex]

Convert to cylindrical coordinates, with

[tex]\begin{cases}x = r\cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \\ dV = dx\,dy\,dz = r\,dr\,d\theta\,d\zeta\end{cases}[/tex]

so that [tex]x^2+y^2=r^2[/tex], and the domain of integration is the set

[tex]\left\{(r,\theta,\zeta) \mid 0 \le r \le 3\text{ and } 0 \le \theta\le2\pi \text{ and } 0 \le \zeta \le 9-r^2\right\}[/tex]

Now compute the integral.

[tex]\displaystyle \int_0^3 \int_0^{2\pi} \int_0^{9-r^2} 6r^2\cdot r\,d\zeta\,d\theta\,dr = 12\pi \int_0^3 \int_0^{9-r^2} r^3\, d\zeta \, dr \\\\ ~~~~~~~~~~~~ = 12\pi \int_0^3 r^3 (9 - r^2) \, dr \\\\ ~~~~~~~~~~~~ = 12\pi \int_0^3 (9r^3 - r^5) \, dr \\\\ ~~~~~~~~~~~~ = 12\pi \left(\frac94 r^4 - \frac16 r^6\right)\bigg|_0^3 = 12\pi \left(\frac94\cdot3^4-\frac16\cdot3^6\right) = \boxed{729\pi}[/tex]

Make a table for each function rule. Then graph each equation using the points you created.

F (x) = 2x - 5
F (x) =-3x +6
F (x) =2/3x +4

Answers

Answer:

1.f(x)=2x-5

i will take the set {-2,-1,0,1,2}

f(-2)=2(-2)-5

=-4-5

=-9

f(-1)=2(-1)-5

=-2-5

=-7

f(0)=2(0)-5

=-5

f(1)=2(1)-5

=-3

f(2)=2(2)-5

=-1

so the coordinates of the function is {-9,-7,-5,-3,-1}

2.f(x)=-3x+6

i will the take the set {-2,-1,0,1,2} too

f(-2)=-3(-2)+6=6+6=12

f(-1)=-3(-1)+6=3+6=9

f(0)=-3(0)+6=6

f(1)=-3(1)+6=-3+6=3

f(2)=-3(2)+6=-6+6=0

{12,9,6,3,0}

3.f(x)=2/3.x+4

{-2,-1,0,1,2}

f(-2)=2/3(-2)+4=-4/3+4=(-4+12)/3=8/3

f(-1)=2/3(-1)+4=-2/3+4=(-2+12)/3=10/3

f(0)=2/3(0)+4=4

f(1)=2/3(1)+4=2/3+4=(2+12)/3=14/3

f(2)=2/3(2)+4=4/3+4=(4+12)/3=16/3

{8/3,10/3,4,14/3,16/3}

you're can graph those coordinates

actually you can take other coordinates...

CMIIW

,

The coordinates of point A on a coordinate grid are (−2, −3). Point A is reflected across the y-axis to obtain point B and point A is reflected across the x-axis to obtain point C. What are the coordinates of points B and C?

B(2, 3) and, C(−2, −3)
B(−2, −3) and C(2, 3)
B(2, −3) and C(−2, 3)
B(−2, 3) and C(2, −3)

Answers

Answer:  B(2, -3) and C(-2, 3) which is choice 3

Further Explanation:

The rule for a y-axis reflection is [tex](\text{x}, \text{y}) \to (-\text{x}, \text{y})[/tex] meaning the x coordinate flips from positive to negative, or vice versa. The y coordinate stays the same.

Therefore, point A(-2,-3) moves to B(2, -3) when reflecting over the y-axis.

A similar rule is [tex](\text{x}, \text{y}) \to (\text{x}, -\text{y})[/tex] to describe an x-axis reflection. This time the y coordinate flips in sign, and the x coordinate stays the same.

In this case, we move from A(-2,-3) to C(-2, 3)

The graph of all three points is shown below. I used GeoGebra to make the graph, but Desmos is another option. I also recommend graphing by hand on graph paper to get practice that way if possible.

Question: 1 An analysis of an unknown compound found it contained 40 g potassium, 52 g chromium and 56 g of oxygen. a) What is the empirical formula for this compound? b) What type of compound is it, ionic, covalent or a combination of both? Explain your choice.​

Answers

1)  The empirical formula for this compound is; K₂Cr₂O₇

2) It is an Ionic compound because it has two potassium ions (K+) and a negatively charged dichromate ion (Cr2O7-).

How to find the Empirical Formula?

1) Elements of the unknown compound are;

Potassium = 40 g

Chromium = 52 g

Oxygen = 56 g

Let us find the number of moles of each element;

Number of moles of Potassium = 40/39 = 1.026 mol K

Number of moles of Chromium = 52/52 = 1 mol Cr

Number of moles of oxygen = 56/16 = 3.5 mol O

Multiply through the number of moles by 2 and round up to the nearest whole number to get the empirical formula at; K₂Cr₂O₇

2) The compound K₂Cr₂O₇ is called Potassium dichromate. It is classified as an ionic compound because it has two potassium ions (K+) and a negatively charged dichromate ion (Cr2O7-).

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1. Transform each blue piece so that the boat changes from blue to red. Try to use as few transformations as possible to complete the task! 2. TIP: Be sure to move the blue pieces so that the corresponding letters match at the same point. 3. Write down the specific stops you made to transform the shapes in your notebook.

a. What transformations would you use on the blue segments CD to get it to match with the red segments C2D2? Explain your movement using the coordinates of the vertices.
b. What transformations would you use on the blue triangle to get it to match with the red triangle? Explain your movement using the coordinates of the vertices.
c. Which line segments on the boat are parallel? Explain your answer.
d. Which line segments on the boat are perpendicular? Explain your answer.
e. Which line segments on the boat have a slope of 0? Explain your answer.
f. Which line segments on the boat have an undefined slope? Explain your answer.
7. What is the slope of ED? Explain your answer using the change in coordinates given that E is at (-11, 4) and D is at (-10, 5).

Answers

A)  Rotate by 90° counterclockwise.

B) Reflection transformation about the line y = 5.

C) Parallel Lines are C₂D₂ and A₂B₂; EF and E₁F₁.

D) Perpendicular lines are;  D₁F₁ and  E₁F₁; DF and EF; DC and AB.

E) Line segments with slope of 0 are; AB, C₂D₂, A₂B₂, EF and E₁F₁

F) Line segments on the boat that have an undefined slope are; Lines A₁B₁, DF and DC.

G) Slope of Line ED = 1

How to carry out Transformations?

A) The blue segment CD is seen on the graph as a perpendicular line with 2 units while the line segment C₂D₂ is seen as a horizontal line. Thus, to match CD with C₂D₂, we will rotate by 90° counterclockwise.

B) The transformations that would be used on the blue triangle to get it to match with the red triangle is a reflection transformation about the line y = 5.

C) The line segments that are parallel to each other are; C₂D₂ and A₂B₂; EF and E₁F₁.

D) The line segments that are perpendicular are;  D₁F₁ and  E₁F₁; DF and EF; DC and AB.

E) Horizontal lines that are parallel to the x-axis have zero slope. Thus, AB, C₂D₂, A₂B₂, EF and E₁F₁ all have zero slopes.

F) Undefined slope is the slope of a vertical line. Thus, Lines A₁B₁, DF and DC have undefined slopes.

G) Slope of ED = (5 - 4)/(-10 - (-11))

Slope of ED = 1/1

Slope = 1

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Find the area of circle Y. The image is represented by circle Y with a sector XYZ that has an area of 85.5 square meters. That sector has an arc that measures 117 degrees. The radius of the circle is unknown.

Answers

Answer:

  263.08 m²

Step-by-step explanation:

The fraction of circle area that a sector represents is proportional to the central angle.

Proportion

  circle area/circle angle = sector area/sector angle

  circle area / 360° = 85.5 m² / 117°

Multiplying by 360°, we have ...

  circle area = (360/117)(85.5 m²) = 263.08 m²

The area of the circle is about 263.08 m².

Jake invested his whole life savings today in an investment that pays 6% interest, compounded annually. In ten years, this investment will be worth $531,402. What is Jake's life savings today?

Answers

Answer:

$ 296 732 .10

Step-by-step explanation:

FV = PV ( 1 + i)^n      FV = future value = 531402     PV = ?

                                 i = decimal interest per period = .06

                                 n = periods = 10

531 402 = PV ( 1.06)^10         Solve for PV = 296 732 .10

Which of the following represents all solutions to the equation
1/3x^2 +10 = 7

Answers

Answer:

1 +-3i

Step-by-step explanation:

Answer:

answer is 1) x=±3i

Step-by-step explanation:

Sketch the region enclosed by the given curves and find its area.

Answers

The area of the region enclosed by the curves x + y = 1, x - 3 = y, y = √x and x = 0 is 16.815 square units.

How to determine the area of a region enclosed by four functions

In this question we must determine the area generated by four functions: three linear functions and a radical function. First, we plot the four functions to determine the required combinations of definite integrals need for calculation:

[tex]A = \int\limits^{0.382}_0 {[f(x) - g(x)]} \, dx + \int\limits^2_{0.382} {[h(x) - g(x)]} \, dx[/tex], where f(x) = √x, g(x) = x - 3 and h(x) = - x + 1.

[tex]A = \int\limits^{0.382}_{0} {[\sqrt{x} - x + 3]} \, dx + \int\limits^{2}_{0.382} {[- 2 \cdot x + 4]} \, dx[/tex]

[tex]A = \int\limits^{0.382}_{0} {\sqrt{x}} \, dx - \int\limits^{0.382}_{0} {x} \, dx + 3 \int\limits^{0.382}_{0}\, dx - 2 \int\limits^{2}_{0.382} {x} \, dx + 4 \int\limits^{2}_{0.382}\, dx[/tex]

[tex]A= 2 \cdot x^{\frac{3}{2} }|_{0}^{0.382} - \frac{x^{2}}{2}|_{0}^{0.382} + 3\cdot x |_{0.382}^{2} - x^{2} |_{0.382}^{2}+4\cdot x |_{0.382}^{2}[/tex]

[tex]A = 2 \cdot (0.382^{\frac{3}{2} }-0^{\frac{3}{2} })-\left(\frac{1}{2} \right)\cdot (0.382^{2}-0^{2}) + 3 \cdot (2 - 0.382) - (2^{2}-0.382^{2})+4\cdot (2^{2}-0.382^{2})[/tex]

A = 16.815

The area of the region enclosed by the curves x + y = 1, x - 3 = y, y = √x and x = 0 is 16.815 square units.

Remark

The statement reports an inconsistency with at least one function and needs to be modified in order to apply definite integrals in a consistent manner. New form is shown below:

Sketch the region enclosed by the given curves and find its area: (i) x + y = 1, (ii) x - 3 = y, (iii) y = √x, (iv) x = 0.

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HELP PLEASE WITH THIS ASAP ASAP

Answers

Answer:

52

Step-by-step explanation:

62 - 42 = 20

20 / 2 = 10

42 + 10 = 52

52... i think :\

Solve the system of equations algebraically and create a graphical model.
[tex]3x + 2y = 8 \\ x + 2y = 4[/tex]

Answers

Answer: [tex]x=2, y=1[/tex]

Step-by-step explanation:

Subtracting the second equation from the first yields [tex]2x=4 \longrightarrow x=2[/tex].

This means that [tex]y=1[/tex].

So, the solution is [tex]x=2, y=1[/tex]

Together, two apples have 1/5 gram of fat. How many apples have a total of 4 grams of fat?

Answers

Answer:

40 apples

Step-by-step explanation:

x = (4·2)/(1/5) = 8/(1/5) = (8/1):(1/5) = (8/1)·(5/1) = 40/1 = 40 apples

It takes 10 apples to make a gram of fat. Multiply the 10 apples by 4 grams of fat to find that it takes 40 apples to make 4 grams of fat.

(x^2-y^2)dx+2xydy=0


so this is a problem of a differential equation I've been trying so hard to match with the given answer but failed every time I tried. So, is there anyone who can really can help me out to catch the mistakes that I'm making?
* The last line of my workout is just a dump guess.
The pictures are my workouts also the answer to this question is attached. Please read my solutions by this order : pic-1, pic-3 & pic-2, if necessary.

Answers

[tex](x^2 - y^2) \, dx + 2xy \, dy = 0[/tex]

Multiply both sides by [tex]\frac1{x^2}[/tex].

[tex]\left(1 - \dfrac{y^2}{x^2}\right) \, dx + \dfrac{2y}x \, dy = 0[/tex]

Substitute [tex]y=vx[/tex], so [tex]v=\frac yx[/tex] and [tex]dy=x\,dv+v\,dx[/tex].

[tex](1-v^2) \, dx + 2v (x\,dv + v\,dx) = 0[/tex]

[tex](1 + v^2) \, dx + 2xv \, dv = 0[/tex]

Separate the variables.

[tex]2xv\,dv = -(1 + v^2) \, dx[/tex]

[tex]\dfrac{v}{1+v^2}\,dv = -\dfrac{dx}{2x}[/tex]

Integrate both sides

[tex]\displaystyle \int \frac{v}{1+v^2}\,dv = -\frac12 \int \frac{dx}x[/tex]

On the left side, substitute [tex]w=1+v^2[/tex] and [tex]dw=2v\,dv[/tex].

[tex]\displaystyle \frac12 \int \frac{dw}w = -\frac12 \int\frac{dx}x[/tex]

[tex]\displaystyle \ln|w| = -\ln|x| + C[/tex]

Solve for [tex]w[/tex], then [tex]v[/tex], then [tex]y[/tex].

[tex]e^{\ln|w|} = e^{-\ln|x| + C}[/tex]

[tex]w = e^C e^{\ln|x^{-1}|}[/tex]

[tex]w = Cx^{-1}[/tex]

[tex]1 + v^2 = Cx^{-1}[/tex]

[tex]1 + \dfrac{y^2}{x^2} = Cx^{-1}[/tex]

[tex]\implies \boxed{x^2 + y^2 = Cx}[/tex]

Your mistake is in the first image, between third and second lines from the bottom. (It may not be the only one, it's the first one that matters.)

You incorrectly combine the fractions on the left side.

[tex]\dfrac1{-2v} -\dfrac v{-2} = \dfrac1{-2v} - \dfrac{v^2}{-2v} = \dfrac{1-v^2}{-2v} = \dfrac{v^2-1}{2v}[/tex]

Which graph has a domain of -∞ < x < ∞ and a range of -∞ < y

Answers

The graph of the option in the question has a domain of -∞ < x < 3.5.

Please find attached the drawing of a graph that has a domain of -∞ < x < ∞

Which method can be used to find the graph that has a domain of -∞ < x < ∞?

The domain of a graph are the possible x-values that can be obtained from the graph.

A graph that has a domain given by the inequality, -∞ < x < ∞ does not have a vertical asymptote.

An asymptote is a straight line to which a graph approaches, as either the x or y-value approaches infinity.

The given graph has a vertical asymptote at y ≈ 3.5

The domain of the given graph is therefore, -∞ < x < 3.5

Similarly, the graph has a horizontal asymptote at x ≈ 3

The range of the given graph is therefore, -∞ < y < 3.

A graph that has a domain of -∞ < x < ∞, extends to infinity to the left and the right of the graph.

A function that has a graph with a domain of -∞ < x < ∞ is one of direct proportionality.

An example is, y = x

A graph that has a domain of -∞ < x < ∞ is attached.

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A survey was done with 205 women. Each women was asked how many children she had. The results showed that 28% of the women had 3 or more children. How many surveyed women had less than 3 children?

Answers

148 women surveyed had less than 3 children

David signed up to provide snacks for his daughter and her school group's camping trip. He found a package of granola bars in bulk for $60 that he thought would be enough for everyone for a few days. He also wanted to buy some boxes of fruit snacks, which were $4 each. He just needed to decide how many to buy, and then figure the total cost.

Select the expression that will help him to determine the total cost.

Answers

The expression that will help him to determine the total cost is as follows:

y = 60 + 4x

How to construct an expression?

He signed up to provide snacks for his daughter and her school group's camping trip.

He found a package of granola bars in bulk for $60 that he thought would be enough for everyone for a few days.

He also wanted to buy some boxes of fruit snacks, which were $4 each.

The number to buy and the total cost can be expressed as follows:

let

y = total cost

x = number of boxes of fruit juice.

Therefore, the  expression that will help him to determine the total cost is as follows:

y = 60 + 4x

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The lateral edges of a prism are

Answers

Step-by-step explanation:

in a survey of 100 people ,65 read Kantipur ,45 read Gorkhapatra, 40 read himalayan times dream,25 read Kantipur as well as Gorkhapatra ,20 read kantipur as well as himalaya times,15 read gorkhapatra,as well as himalaya times and 5 read all three news papers.

1)draw a Venn diagram to illustrate the above information.

2find how many people do not read all three news paper ?

The lateral edges are congruent and parallel. The correct option is D.

A prism is a 3-dimensional object that has two bases that are similar and congruent to each other and are connected to each other with straight lines. A few examples of the prism are given in the image below.

Lateral edges are the edges that connect the two bases of the prism.

Since the lateral edges are straight lines and connect the similar vertices of the bases. Therefore, the lateral edges are always congruent and parallel.

Hence, the correct option is D.

Learn more about Prism here:

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The given question is incomplete. Probably the complete question is:

The lateral edges of a prism are

A. congruent, only

B. congruent and perpendicular

C. perpendicular, only

D. congruent and parallel

-|8-15| what is the answer

Answers

Answer:

-7

Step-by-step explanation:

8-15 = -7 but since it's an absolute value, it is 7 and then you add the negative sign in front since it is not in the absolute value.

Soo yeah -6 or -7 yeah i think it was -7
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