Answers
The missing nucleus in the equation is 234/90 Th
What is a nuclear reaction?A nuclear reaction is a procedure wherein an atom's nucleus is altered by being divided or fused with the nucleus of another atom. We know that the masses and the charges that we have in the nuclear reaction must be balanced according to what have been shown in the image that is attached here.
We can then see that the nuclear reaction that is shown in the image is an alpha decay and there is the loss of the helium atom from the system as has been typified in the equation.
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Related Questions
The reaction of H₂ with F2 produces HF with AH = -269 kJ/mol of HF. If the H-H and H-F bond energies are 432 and 565 kJ/mol,
respectively, what is the F-F bond energy?
H₂(g) +F₂ (g)—>2HF (g)
Answers
The F-F bond energy is 293 kJ/mol.
What is bond energy?Bond Energy also known as simply bond enthalpy, is described as a quantity that offers insight into the strength of a chemical bond.
ΔH = ∑(bond energies of bonds broken) - ∑(bond energies of bonds formed)
In this reaction above one H-H bond and one F-F bond are broken, and two H-F bonds are formed. Thus, the enthalpy change can be shown as:
ΔH = (1 × H-H bond energy) + (1 × F-F bond energy) - (2 × H-F bond energy)
Which gives us :
-269 kJ/mol = (1 × 432 kJ/mol) + (1 × F-F bond energy) - (2 × 565 kJ/mol)
Therefore, the F-F bond energy = [1 × (432 kJ/mol) + 2 × (565 kJ/mol)] - 269 kJ/mol = 293 kJ/mol
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What is the maximum concentration of equimolar solutions of ferrous sulphate and sodium sulphide so that when mixed in equal volumes, there is no precipitation of iron sulphide? (For iron sulphide, Ksp=6.3×10−18).
Answers
Every solution should have an x mol/L maximum concentration. Each solution's concentration will be lowered to half, or x/2, after mixing.
∴[FeSO4] = [Na2S] = x/2M
Then, [Fe2+] = [FeSO4] = x/2M
Also, [S2−]=[NasS] = x/2M
Fe(S)(x) ↔ Fe 2 + (aq) + S2−(aq)
Ksp=[Fe2+][S2−]
6.3 × 10−18=(x/2)(x/2)
x2/4=6.3 × 10−18
⇒ x = 5.02 × 10−9
If the concentrations of both solutions are equal to or less than 5.02 × 10–9M, then there will be no precipitation of iron sulphide.
⇒x =5.02 × 10−9
Na2S and FeSO4 are combined in an equal volume. Maximum concentrations of both solutions are 22, 51109M, and 5. Since Ba(OH)2 is the strongest base of the available alternatives, its pH is highest. BaCl2 is a strong base because it is the salt of Ba (OH)2. BaCl2 hydrolysis produces the most alkaline solutions and raises the PH of all the salts provided in the inquiry.
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Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar. Glucose solutions are used to treat patients with low blood sugar.
Suppose you prepare a glucose solution using the described procedure.
Step 1: Dissolve 227.9 g of glucose in enough water to make 500.0 mL of solution.
Step 2: Transfer 16.8 mL of the solution to a new flask and add enough water to make 250.0 mL of dilute solution.
What is the concentration (in M) of the glucose solution at the end of the procedure?
Answers
Answer:
0.0456 M
Explanation:
The concentration of glucose can be determined as follows:
Step 1: Concentration of glucose in the original solution = Mass of glucose / Volume of solution = 227.9 g / (500.0 mL x 10^-3 L/mL) = 0.456 M
Step 2: Concentration of glucose in the dilute solution = Mass of glucose / Volume of dilute solution = 0.456 M x (16.8 mL x 10^-3 L/mL) / (250.0 mL x 10^-3 L/mL) = 0.0456 M
So, the concentration of glucose in the dilute solution is 0.0456 M to 4 significant figures.
ALLEN
Calculate strain energy for the conformer pictured below, using strain energy increments from the table.
Strain Energy for Alkanes
Interaction / Compound kJ/mol kcal/mol
H : H eclipsing 4.0 1.0
H : CH3 eclipsing 5.8 1.4
CH3 : CH3 eclipsing 11.0 2.6
gauche butane 3.8 0.9
cyclopropane 115 27.5
cyclobutane 110 26.3
cyclopentane 26.0 6.2
cycloheptane 26.2 6.3
cyclooctane 40.5 9.7
(Calculate your answer to the nearest 0.1 energy unit, and be sure to specify units, kJ/mol or kcal/mol. The answer is case sensitive.)
Answers
13.8 kJ [tex]mol-1\\[/tex] is strain energy for the conformer pictured below, using strain energy increments from the table.
The problem is based on the concept of used strain energy in the conformers.
When two non bonded groups approach each other, it results in repulsion and causes steric strain in the molecule.
Structure of conformer in eclipsed form in Newman projection is as follows:
4.0 kJ mo is energy of eclipsed H-H bond
Energy of eclipsedН-СH, 3 bond is 5.8 kJ mol
Total strain energy of conformer (S,)
E 2x eclipsed (H-H)+ eclipsed (H-CH,)
Replace eclipsed (H-H) with 4.0 kJ mol and eclipsed (H-CH) with 5.8 kJ mol to get
E 2x4.0 kJ mol +5.8 kJ mol =13.8 kJ mol
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It shows that the number of individuals in the population will ________ until the carrying capacity of the environment is reached.
Ecological models are _________ because they help scientists ________ what will occur in real life.
Explain what happened to the carrying capacity of reindeer on St. Matthew Island over time. ________
In ________ times, populations do well, and the number of individuals _________ rapidly. A period of rapid population ________ often follows, followed again by a ________ in numbers.
Give some examples of organisms present in a pond community: ___________________________________
A community and its ________ _ (nonliving) environment make up an ________
Answers
It shows that the number of individuals in the population will decrease until the carrying capacity of the environment is reached.
What is the environment?
Built environments stand in stark contrast to natural environments. With the conversion of agricultural land into urban areas and other built environments, humans have fundamentally altered the landscape. The result is a greatly altered natural environment that is now more suited to human life. Even seemingly less severe actions like constructing a mud home or a solar system in the desert turn the environment into an artificial one. Despite the fact that many animals construct structures to improve their living conditions, since they are not human, beaver dams and termite mounds are seen as natural.To know more about environment, click the link given below:
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An aqueous solution of glucose (mm = 180. 2 g/mol) has a molality of 5. 21 m and a density of 1. 20 g/ml. What is the molarity of glucose in the solution?.
Answers
The molality and density of an aqueous solution of glucose (mm = 180. 2 g/mol) are 5. 21 and 1. 20 g/ml, respectively. Therefore, the molarity of glucose in the solution is 0.0355 M.
Molality is the number of moles of solute per kilogram of solvent, while molarity is the number of moles of solute per liter of solution.
molarity (M) = molality (m) * (density of solvent in g/mL) / (molar mass of solute in g/mol)
molality (m) = 5.21 m
the density of solvent (g/mL) = 1.20 g/mL
molar mass of solute (g/mol) = 180.2 g/mol
So, molarity (M) = 5.21 m * (1.20 g/mL) / (180.2 g/mol)
molarity (M) = 5.21 m * 0.0067 g/mL/g mol
molarity (M) = 0.0355 M
Therefore, the molarity of glucose in the solution is 0.0355 M.
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Cu has only two naturally occurring isotopes 63cu and 65cu if the aromic mass of cu is 63.546 then the natural abundance of the 63cu isotope will be approximately
Answers
Answer: i answerd 34cu i got coreect hopefully you get it corecct!!!!!!!
Explanation:
946.36 water * 1 mol water/ 236.59 g water * 4 mol lemonade/ 2 mol water * 225.285 g lemonade/1 mole lemonade = ? g lemonade.
Answers
According to the recipe, to make 4 moles of lemonade, you use 2 moles of water, one mole of sugar and one mole of lemon juice, expressed in grams:
2 water + sugar + lemon juice = 4 lemonade
2*(236.59) + 225g + 257.83g = 4*(719.42)g
473.18g + 225g + 257.83g = 2877.68g
So for every 2877.68g of lemonade made, they use 473.18g of water, 225g of sugar, and 257.83g of lemon juice.
You know that they made a batch of 2050.25g, so to detect the limiting reactant, first, you have to calculate, in theory, how much of each ingredient you need to make the given amount of lemonade:
Use cross multiplication
Water:
2877.68g lemonade → 473.18g water
2050.25g lemonade → X= (2050.25*473.18)/2877.68= 337.12g water
Following the recipe, to elaborate 2050.25g of lemonade, you need to use 337.12g of water.
Sugar:
2877.68g lemonade → 225g sugar
2050.25g lemonade → X= (2050.25*225)/2877.68= 160.30g sugar.
To elaborate 2050.25f of lemonade you need to use 160.30g of sugar.
Lemon juice:
2877.68g lemonade → 257.83g lemon juice
2050.25g lemonade → X= (2050.25*257.83)/2877.68= 183.69g lemon juice.
To elaborate 2050.25f of lemonade you need to use 183.69g lemon juice.
Available ingredients vs. theoretical yields for 2050.25g of lemonade:
Water 946.36 g → 337.12g
Sugar 196.86 g → 160.30g
Lemon Juice 193.37 g → 183.69g
The lemon juice will be the first ingredient to be used up, there will be a surplus of water and sugar.
What is lemonade?
In Egypt around the 13th and 14th centuries, people drank a concoction of lemon juice, dates, and honey called qatarmizat.Lemonade was sold to Parisians in cups by vendors who carried tanks of the soft drink on their backs.To know more about lemonade, click the link given below:
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Co and CO are:
A. The Same element
B. The same molecule
C. Co is an element and CO is not.
D. Co is a molecule and CO is not
Answers
Answer:
C.
Explanation:
in CO there are 2 capital letters,but in Co there is 1 capital letter because its an element.
Answer: c. Co is an element and CO is not
Explanation:
Co and CO are two different chemical substances. Co is the metal element named cobalt whereas CO is the inorganic compound i.e. carbon monoxide.
Co is a chemical element with atomic no. 27 and CO is an inorganic compound consisting of atoms of carbon and oxygen.
co is a metal whereas CO is a gas.
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helpppppppp!!!!!!!!!!
Answers
Answer:
no answer
Explanation:
I wish I could help you
Platinum is a transition metal and forms two different ions, Pt2+ and Pt4+. Write the formulas for the compounds for each platinum ion with bromide ions.
Answers
The formulas for the compounds formed between platinum ions and bromide ions are Platinum (II) bromide (PtBr2) and Platinum (IV) bromide (PtBr4)
In both of these compounds, the bonding between the platinum ion and the bromide ions is primarily ionic in nature.
In platinum (II) bromide (PtBr2), each platinum ion is surrounded by two bromide ions, and each bromide ion is bonded to one platinum ion. The platinum ion has a +2 charge, and the two bromide ions have a -1 charge each, so the overall charge of the compound is neutral.
In platinum (IV) bromide (PtBr4), each platinum ion is surrounded by four bromide ions, and each bromide ion is bonded to one platinum ion. The platinum ion has a +4 charge, and the four bromide ions have a -1 charge each, so the overall charge of the compound is neutral.
The bond between the platinum ion and the bromide ions is a result of the attraction between their opposite charges.
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What type of reaction is shown below:
C5H12+O2→H2O+CO2
Answers
C5H12 + O2 → H2O + CO2 this reaction is complete combustion reaction. Because carbon dioxide and water are formed as a product.
What is combustion reaction ?The Combustion defined as a high-temperature exothermic redox chemical reaction between a fuel and an oxidant, normally atmospheric oxygen, that produces oxidized, often gaseous products, in a mixture termed as smoke.
C5H12 + O2 → H2O + CO2 Pentane undergoes a complete combustion reaction with excess oxygen to give carbon dioxide and water.
Thus, this reaction is complete combustion reaction. Because carbon dioxide and water are formed as a product.
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Pls answer asap 100 points
For the oxidation of glucose (C6H12O6 + 6O2→6H2O + 6CO2), how many liters of carbon dioxide gas(CO2) will be produced when 950 g of glucose(C6H12O6) is oxidized completely?
Molar Masses:
C6H12O6 = 180.2 g/mol
Question 3 options:
709g
571g
960g
480g
Answers
The strength of mild steel is found to be 232.9 MPa when the grain size is 17.43 pm. and 874.2 MPa when the grain size is 0.80 um. 1. Determine the constants in the Hall-Petch equation. (Express your answer to three significant figures.) K =_____MPa um 0o =______MPa 2. Determine the strength of the mild steel when the grain size is reduced to 0.160 pm. (Express your answer to three significant figures.) 0 = MPa
Answers
When the grain size is reduced to 0.160 pm, the strength of mild steel is 1851 MPa.There are a number of variables that can affect mild steel's strength, including the grain size, which is controllable.
We may use the above information to determine the constants in the Hall-Petch equation: The strength of mild steel at grain size d1 = 17.43 pm is 1 = 232.9 MPa. Mild steel has a strength of 2 = 874.2 MPa when the grain size is d2 = 0.80 um (or 800 nm). This is the formula for the Hall-Petch equation: = o + Kd(-1/2). We can use the following equation to determine K: K = (σ2 - σ1)(d2^(1/2) - d1^(1/2))^(-1) (-1) When the values are plugged in, we get the following result: K = (874.2 - 232.9)(800(1/2) - 17.43(1/2))(-1) = 276.3 MPa um(1/2) We can use the following equation to determine o: σo = σ1 - Kd1^(-1/2) Plugging in the numbers yields the following result: o = 232.9 - 276.3(17.43(-1/2)) = 62.28 MPa. The Hall-Petch equation's constants are K = 276.3 MPa um(1/2) and o = 62.28 MPa. Hence, the power of the yield strength of mild steel at 0.160 pm grain size is 1851 MPa.
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A sample of trifluoroacetid acid C2HF3O2 contains 83.3 g of oxygen calculate the mass
Answers
The mass of trifluoroacetic acid that contains 83.3 g of oxygen is approximately 482.6 g.
How to calculate the mass of trifluoroacetic acid (C2HF3O2) containing 83.3 g of oxygenFirst we need to use the molar mass and stoichiometry of the compound.
The molar mass of trifluoroacetic acid is:
(2 x 12.01 g/mol) + (1 x 19.00 g/mol) + (3 x 19.00 g/mol) + (2 x 16.00 g/mol) = 114.02 g/mol
The molar mass of oxygen is 16.00 g/mol.
From the chemical formula of trifluoroacetic acid (C2HF3O2),
we can see that each mole of the compound contains 2 moles of carbon, 1 mole of hydrogen, 3 moles of fluorine, and 2 moles of oxygen.
Using this information, we can set up a proportion to find the mass of trifluoroacetic acid that contains 83.3 g of oxygen:
(83.3 g O2) x (1 mol O2/16.00 g O2) x (1 mol C2HF3O2/2 mol O2) x (114.02 g C2HF3O2/1 mol C2HF3O2) = 482.6 g
Therefore, the mass of trifluoroacetic acid that contains 83.3 g of oxygen is approximately 482.6 g.
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A key advantage of PDF is that it has excellent tools for creating and editing images.
Group of answer choices
True
False
Answers
A key advantage of PDF is that it has excellent tools for creating and editing images. It is true.
What is a PDF?
PDF stypestands for Portable Document Format, which is a file format developed by Adobe in the 1990s. PDF files are used to present and exchange documents reliably and consistently across different platforms and devices, regardless of the software or hardware used to create or view the file.PDFs can contain various types of content, including text, images, graphics, and interactive elements such as hyperlinks and form fields. They can be created using a variety of tools and software, including Adobe Acrobat and many other third-party applications.PDF files can be viewed and edited using a variety of software, including Adobe Reader, Acrobat, and many other free and paid applicationsTo know more about PDFs, click the link given below:
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The pressure of a sample of helium in a 200. Ml container is 2. 0 atm. If the helium is compressed to a volume of 10. Ml without changing the temperature, what would be the pressure of the gas?.
Answers
Ml without changing the temperature,The pressure of the gas is [tex]16.8atm[/tex]
The pressure of a gas is related to its volume and temperature by the ideal gas law:
PV = nRT
n is the number of moles of gas, P is the pressure, V is the volume, R is the ideal gas constant, and T is the temperature.
Since we know the initial pressure, volume, and temperature, we can rearrange the equation to solve for n:
[tex]n =\frac{ PV}{RT}[/tex]
Now that we know the amount of gas, we can use the same equation to calculate the pressure when the gas is compressed to 10. Ml without changing the temperature:
[tex]P = \frac{nRT}{V}\\\\P = (\frac{PV}{RT}) * (\frac{RT}{V})\\\\P = (2.0 atm * 200. Ml) / (0.08206 L atm K ^{-1} mol^{-1} * 298.15 K) \\\\P = 16.8 atm[/tex]
Therefore the pressure of the gas is [tex]16.8atm[/tex]
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For parts of the free-response question that require calculations, clearly show the method used and the steps involved in arriving at your answers. You must show your wo
your answer. Examples and equations may be included in your answers where appropriate.
Н
H:O:H
H:C:H
Н
:CI:
:CI:C:CI:
:CI:
Answer the following questions about CH, and CC14. The Lewis electron-dot diagrams for molecules of the compounds are shown above.
(a) Which compound has the higher boiling point? Justify your answer. The type(s) of intermolecular force(s) in both substances should be included in your answer.
Answers
The CCl4 molecule is larger and has more electrons hence it is more polarizable and has a larger boiling point
Does higher molar mass imply a higher boiling point?A higher molar mass does imply a higher boiling point for a substance, assuming that the other conditions (pressure, temperature, etc.) are constant.
This is because the boiling point is a measure of the temperature at which a substance changes from a liquid to a gas at a given pressure. As the molar mass of a substance increases, the intermolecular forces between the molecules tend to be stronger, which makes it more difficult to separate the molecules and vaporize the substance. As a result, the boiling point generally increases with increasing molar mass.
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In the chemical reaction:
CH4 + H₂O → CO + 3H₂
How many moles of methane (CH4) required to produce 9.03 g of hydrogen?
Answers
According to the stoichiometry of the given balanced chemical equation, 1.85 moles of methane are required to produce 9.03 g of hydrogen.
What is stoichiometry?It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.
In the given reaction, 16 g that is 1 mole methane gives 6 g that is 3 moles hydrogen ,hence for 9 g hydrogen 16×6/9=24.08 g methane is needed and it is equivalent to number of moles= 24.08/16=1.85 moles.
Thus,1.85 moles of methane are required to produce 9.03 g of hydrogen.
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Please help! Will give brainly, attached photo.
Answers
The mass of the HgO is 434 g.
What is the stoichiometry?Stoichiometry allows us to calculate the amount of each reactant and product involved in a reaction based on its chemical formula. This is done by using the balanced chemical equation for the reaction, which shows the ratio of moles of each reactant and product involved in the reaction.
The reaction equation is; 2HgO(s)→Hg(l)+O2(g).
The number of moles of the oxygen is; 32.1g/ 32 g/mol
= 1 mole
We have to know form the reaction equation that;
2 moles of the HgO produces 1 mole of oxygen
x moles of HgO would produce 1 moles of oxygen
x = 2 moles
Mass of the compound = 2 moles * 217 g/mol
= 434 g
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At 500 oC cyclopropane (C3H6) rearranges to propene (CH3CHCH2) as shown by C3H6(g) → CH3CHCH2(g). The reaction is first-order with a half-life of 17 minutes. How long will it take for the concentration of C3H6 to drop to 12.5% of its initial value at 500 oC?
Answers
The compound with half life of 17 minute have the rate constant of 0.040 minutes⁻¹ will take to reach to 12.5% of the initial amount .
What is half life ?Half life of a sample is the time required to consume half of its initial amount in a reaction.
For a first order reaction,
the rate constant k = 1/t ln W0/Wt
where t is the time of consumption, W0 be the initial amount and Wt be the amount after time t.
The half life of the compound = 17 minutes
rate constant = k = 0.693/17 = 0.040 minutes⁻¹
The time taken to reach the concentration of 12.5 % of its original amount is calculated as follows:
t = 1/k ln Wo/(Wt )
= ln( 100/12.5)/ 0.040 minutes⁻¹
= 52.49 minutes
Therefore, taken to reach the concentration 12.5% of the initial amount is 52.49 minutes.
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a specie with initial concentration 1.4×10^-2 mol L-1 decay by first order kinetics with a rate constant 2.35×10^2L mol-1 s-1. what is the half-life if this specie?
Answers
The half life is 2.9 * 10^-3 s
What is a first order reaction?
A first-order reaction is a chemical reaction in which the rate of reaction is directly proportional to the concentration of one of the reactants. This means that the rate of reaction increases as the concentration of the reactant increases.
The mathematical expression for a first-order reaction is:
Rate = k[A]
where Rate is the rate of the reaction, k is the rate constant, and [A] is the concentration of the reactant that the reaction rate depends on. This equation is also known as the rate law for a first-order reaction.
Half life of a first order reaction;
0.693/k
k = Decay constant
Half life = 0.693/2.35×10^2
= 2.9 * 10^-3 s
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Which formula is the mathematical representation of Charles’s law? Responses V1/T1 = V2/T2 P1/T1 = P2/T2
Answers
The mathematical representation of Charles's Law is V1/T1 = V2/T2.
What do you mean by Charles's Law?
Charles's Law, also known as the Law of Volume-Temperature, states that the volume of a gas is directly proportional to its temperature when pressure is held constant. In other words, as the temperature of a gas increases, its volume will also increase. It was first established by physicist Jacques Charles in 1787.
The mathematical representation of Charles's Law states that the ratio of the initial volume (V1) to the initial temperature (T1) is equal to the ratio of the final volume (V2) to the final temperature (T2). This means that, as the temperature of a gas increases, its volume will increase proportionally.
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Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.
2NaClO3 --> 2NaCl +3O2
How many moles of NaClO3 were needed to produce 30 moles of O2? Round your answer to the nearest whole number.
Answers
Answer:
10 moles of NaClO3 were needed to produce 30 moles of O2
Explanation:
From the equation, we know that 2 moles of NaClO3 produce 3 moles of O2. To find out how many moles of NaClO3 are needed to produce 30 moles of O2, we divide the number of moles of O2 by the mole ratio:
30 moles O2 / 3 moles O2 per 2 moles NaClO3 = 10 moles NaClO3
So, 10 moles of NaClO3 were needed to produce 30 moles of O2.
Can you help me solve number 71 ? In details please thank you
Answers
Answer:
The energy released as the mercury vapor cools from 356°C to 25°C can not be determined from the information provided. The amount of energy released depends on various factors such as the heat capacity of the substance, the mass of the substance, and the specific conditions in which it is cooling.
Explanation:
Answer:
807 cal
Explanation:
To determine the energy released as the mercury vapor cools from 356°C to 25°C, we need to determine the change in its internal energy. The internal energy of a substance is given by the equation ΔU = q + w, where ΔU is the change in internal energy, q is the heat absorbed or released by the substance, and w is the work done by the substance.
In this case, the heat absorbed by the mercury as it is heated from 25°C to 356°C is 110 cal, and the heat absorbed to vaporize the mercury is 697 cal, so the total heat absorbed is 110 + 697 = 807 cal. As the mercury vapor cools from 356°C to 25°C, it releases heat, so the heat released can be calculated as q = -807 cal.
Since no work is done in this process (the substance is not expanding or contracting against an external pressure), the work term can be ignored. Therefore, the change in internal energy of the mercury vapor as it cools from 356°C to 25°C is ΔU = q = -807 cal.
So, the mercury releases 807 cal of energy as it cools from 356°C to 25°C.
Tell me if you still confuse
ALLEN
Why is phenacetin more polar than aspirin?
Answers
Phenacetin is more polar than aspirin because of its molecular structure. Phenacetin has a polar functional group, the acetamide group (-CONH2), which makes the molecule more polar overall. This group has a positive charge on the nitrogen atom and a negative charge on the oxygen atom, making it a dipole, or a molecule with a positive and negative end.
In contrast, aspirin has a non-polar functional group, the acetyl group (-COCH3), which does not have a dipole moment. This makes aspirin less polar overall.
The polarity of a molecule affects its solubility in different solvents. Polar molecules are soluble in polar solvents, such as water, while non-polar molecules are soluble in non-polar solvents, such as oil. Phenacetin is more soluble in water because of its polar functional group, while aspirin is less soluble in water because of its non-polar functional group.
In summary, phenacetin is more polar than aspirin because it has a polar functional group, the acetamide group, while aspirin has a non-polar functional group, the acetyl group. This difference in polarity affects the solubility of the two molecules in different solvents.
The density of muscle tissue is approximately 1.055 g/mL. How many grams of muscle tissue would be contained in 24 mL of muscle tissue?
Answers
What is the molecular formula of a compound with the empirical formula sf5 and a formula mass of 254. 1 amu?.
Answers
Molecular formula S₂F₁₀ for the compound with the empirical formula SF₅ and formula weight 254.1 a.m.u.
Molecular formula for a compound with the empirical formula CH₂O and formula weight 180.156 a.m.u: C₆H₁₂O₆.
Molecular Formula:
Molecular formulas use subscripts that give the actual number of atoms of each type in the molecule of a compound. The molecular formula is related to the molecular weight in grams, which is a simple integer multiple of the mass of the corresponding empirical formula.
Empirical Formula:
The empirical formula of a compound is the formula for a substance written in terms of the smallest integer exponent. The empirical formula provides information about the atomic number ratio of a compound. The percent composition of a compound leads directly to the empirical formula.
Now,
The molecular formula of a compound with a given empirical formula can be calculated as:
molecular formula = (empirical formula)n
The molecular formula for this compound is: n = 254.1
⇒ 127n = 254.1
⇒ n = 2
Formula = (SF5)₂ = S2F10
⇒ (CH2O)n = 180.156amu 44 {41 24424} = 180. 156
⇒ (30)n = 180.156
⇒ n = 6
Molecular formula = (CH2O)₆ = C6H12O₆
Molecular formula of a compound with empirical formula CH2O and formula weight 180.156 amu: C₆H₁₂O₆.
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Answer:
The molecular formula of the compound with the empirical formula SF5 and a formula mass of 254.1 amu is S2F10. This can be determined by dividing the formula mass by the empirical formula mass (254.1/48.3 = 5.26) and then multiplying the elements of the empirical formula by this value (S x 5.26 = S2, F x 5.26 = F10).
The half-life of Tl
-201 is 3.0 days. How many days will it take until the activity of the Tl
-201 in Simones body is one-fourth of the initial activity?
Answers
It will take approximately 4.39 days until the activity of the Tl-201 in Simone's body is one-fourth of the initial activity.
How does Half-Life Reaction work?The time it takes for half of a substance's radioactive nuclei to decay is known as its half-life. It is a radioactive substance is characteristic property that is used to determine a material's rate of decay. A decay curve that plots the number of radioactive atoms remaining over time can be used to determine a substance's half-life. Radiometric dating, nuclear medicine, and radiation safety all make use of half-life.
The decay of Tl-201 follows first-order kinetics. The equation for the decay of a radioactive substance is given by:
N = N0 × [tex]1/2^{t/t/2}[/tex]
where N is the amount of the substance at time t, N0 is the initial amount of the substance, t1/2 is the half-life of the substance, and t is the time that has elapsed.
We are given that the half-life of Tl-201 is 3.0 days. This means that if we start with an initial activity of A0, the activity at any time t is given by:
A = A0 * [tex]1/2^{t/3}[/tex]
We want to know how many days it will take until the activity of the Tl-201 in Simone's body is one-fourth of the initial activity. Let's call this time t₁ :
A = A 0/4
= A0 × (1/2)[tex]^{t^{1/3} }[/tex]
Dividing both sides by A0 and taking the logarithm of both sides, we get:
ln(1/4)
= - [tex]t^{1/3}[/tex] × log(2)
Solving for t₁, we get:
t₁ = (3/log(2)) × log(4)
= 4.39 days
Therefore, it will take approximately 4.39 days until the activity of the Tl-201 in Simone's body is one-fourth of the initial activity.
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S + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O
In the above equation how many moles of H2SO4 can be made when 54 moles of HNO3 are consumed?
Answers
Answer:
27 moles of sulfuric acid are produced.
Explanation:
The equation for the reaction between nitric acid (HNO3) and sulfuric acid (H2SO4) to form nitration sulfate (HNO3) and water (H2O) is:
2 HNO3 + H2SO4 → H2SO4 + 2 H2O
For every 2 moles of nitric acid that react, 1 mole of sulfuric acid is produced. So, when 54 moles of nitric acid are consumed, 54/2 = 27 moles of sulfuric acid are produced.
