primarily involves modifying programs to meet new business needs, but also debugging of errors that were not detected when testing the developed code.

The required fraction of chicken,whose are laying eggs irregularly.

Multiply the numerators and denominators independently to track down the item. At the point when you need to duplicate divisions, increase the 2 numerators together first and compose it on top. Then duplicate the denominators together and compose it on the lower part of the portion. Work on your response in the event that you would be able so it is in the least terms.

9/15 chickens are laying eggs regularly and 2/15 chickens never lay eggs.

Then,fraction of chicken

1 - 9/15 - 2/15

15 - 9 - 2/15

4/15

Thus, the fraction of chicken are 4/15

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Correct question:

9/15 of David's chickens lay

eggs every day. 2/15 of the chickens never lay any eggs. What fraction of the chickens lay eggs irregularly.

The area of triangle (A) is 210 cm².

What is the area of the triangle and perimeter of the triangle?

If a, b, and c are the sides of the triangle, then

Perimeter of the triangle = (a + b + c) units.

Area of the triangle = [tex]\sqrt{(s(s - a) (s - b) (s - c)) }[/tex]

The semi-perimeter of the triangle, s = (a + b + c)/2

Let the triangle is ABC,

and AB = 3x - 1, BC = 4x + 1 and AC = 3x.

       Perimeter = 70

       AB + BC + AC = 70

      3x-1 + 4x + 1 +3x = 70

       10x = 70

          x = 7

AB = a = 3x - 1 = 20

BC = b = 4x + 1 = 29

AC = c = 3x = 21

Now semi-perimeter = s = 70/2

                                     s = 35

      Area of the triangle = [tex]\sqrt{(s(s - a) (s - b) (s - c)) }[/tex] 

                                    [tex]=\sqrt{35(35-20)(35-29)(35-21)}\\\\\\=\sqrt{35(15)(6)(14)}\\\\=\sqrt{44100}\\\\=210[/tex]

        Area of the triangle = 210 square cm.

Hence, the area of triangle (A) is 210 cm².

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Answer:

2.552 [tex]\frac{feet}{minute}[/tex]

Step-by-step explanation:

The correct answer is Option D which is function.

Given that,

You can make computations using this Excel feature by simply entering the necessary inputs.

Range

Syntax

Formula

Function

Answer is Option D

Using the necessary arguments in the right sequence, a function is a predetermined formula that conducts calculations. SUM, AVERAGE, COUNT, etc. are some built-in functions. the arguments in that the calculation needs function and it is selected over Range, Syntax, Formula

So, The correct answer is Option D which is function.

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As per the required total time taken by one person to complete a task from beginning to end without taking into any account holidays, time off, or any other project work is known as Work effort estimate.

As given in the question,

Total time taken by one person to complete the task with conditions:

-: From beginning to end no holiday.

-: No time off

-: no other project work

A. Duration estimate represents the time taken to complete any project.

Incorrect option.

B. Work effort estimate represents the point clearly mentioned to what is required to complete the task.

Here clearly mentioned all the points .

Correct option.

C .  Bottom-up estimate represents estimates for individual components of work that are designed to rolled up into the overall estimate.

Incorrect option.

D. Parametric estimate represents the different parameters like total cost , time and resources required for the project.

Incorrect option.

Therefore, for the required total time taken by one person to complete a task from beginning to end without taking into any account holidays, time off, or any other project work is known as Work effort estimate.

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Answer:

8.21%

Step-by-step explanation:

r = (1/t)(A/P - 1)

t = 13

A = 6200

P = 3000

        1          6200

r = (-------) ((------------) - 1))

       13         3000

        1          31

r = (-------) ( ------ - 1)

       13         15

        1          16

r = (-------) ( ------ )

       13         15

       16

r = --------  =  0.0820512

       195

r = 0.0820512 x 100 = 8.20512

r ≈ 8.21%

I hope this helps!

Answer:

Step-by-step explanation:

Compounded Monthly:

Use A=P(1+r/n)^nt

A=6200

P=3000

t=13

n=12

​

Plug in and simplify:

1. Multiply 12 times 13

2. Divide out the 3000

3. Raise both sides to the 1/156 power to cancel out the exponent

4. Subtract 1 from both sides

5. Multiply by 12 on both sides

R should equal 0.0559716

That is about 5.60%

5.60%

If Rn has a basis of eigenvectors of A, then A is diagonalizable.

This statement is true.

If A is diagonalizable, then A is invertible.

This statement is false.

What is diagonalizable matrix?

If there is an invertible matrix P and a diagonal matrix D such that P^-1AP=D, or alternatively A=PDP^-1, then the square matrix A is said to be diagonalizable or non-defective in linear algebra.

If Rn has a basis of eigenvectors of A, then A is diagonalizable.

This statement is true.

In this case we can construct an invertible matrix P.

If A is diagonalizable, then A is invertible.

This statement is false.

It’s invertible if it doesn’t have a zero as eigen value but this doesn’t affect diagonalizabilty.

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g''(x) > 0 and hence the graph is concave up where x belong to zero to infinity and concave down when x belong to negative infinity to zero

How to find the intervals where a function is concave up and concave down?

In determining intervals where a function is concave upward or concave downward, you first find domain values where f″(x) = 0 or f″(x) does not exist. Then test all intervals around these values in the second derivative of the function. If f″(x) changes sign, then ( x, f(x)) is a point of inflection of the function.

g(x) =5x^3+8x

g'(x) = 15x^2+8

g''(x)= 30x

g''(x)= 0

this implies that

g''(x) > 0 and hence the graph is concave up where x belong to zero to infinity

and concave down when x belong to negative infinity to zero

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Answer: 10 and X and 0

Step-by-step explanation:

The following systems of equations can be used to find the number of pounds of zucchini that were solds z + c = 108 and 150.32 = 1.69z + 0.99c

A farmer sold 108 pounds of produce

The produce that consisted of z pounds of zucchini and c pounds of cucumbers.

z + c = 108

The farmer sold the zucchini for $1.69 per pound and the cucumbers for $0.99 per pound

He collected a total of $150.32.

Money collected by zucchimi = 1.69 x z = 1.69z

Money collected by cucumbers = 0.99 x c = 0.99c

Total money collected = money collected by zucchini + money collected by cucumbers

150.32 = 1.69z + 0.99c

Therefore, the system of equations is z + c = 108 and 150.32 = 1.69z + 0.99c

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Answer:

Use y = mx + b form.

Substitute x, y and m.

Solve for b.

Now you have m, and b.

Use the form again, substitute m and b.

That will give you the generalized equation. You can use it to describe every point on the line.

Answer:

[tex]\sf y = \dfrac{-1}{13}x+ \dfrac{165}{13}[/tex]

Step-by-step explanation:

Here m is the slope and b is the y-intercept.

    y = 13x - 4

     m₁ =  13

Product of slope of the Perpendicular line m * m₁ = -1

                [tex]\sf m = \dfrac{-1}{m_1}\\\\m = \dfrac{-1}{13}[/tex]

Equation of the line:

      [tex]\sf y = \dfrac{-1}{13}x+b[/tex]

The point (9,12) passes through the line. Substitute the coordinates in the above equation and find the value of 'b'.

     [tex]\sf 12 = \dfrac{-1}{13}*9+b\\\\[/tex]

[tex]\sf 12 + \dfrac{9}{13}=b\\\\ \dfrac{156}{13}+ \dfrac{9}{13}=b\\\\\boxed{b= \dfrac{165}{13}}[/tex]

Equation of line:

          [tex]\sf y = \dfrac{-1}{13}x+ \dfrac{165}{13}[/tex]

Type I error means rejecting the true null hypothesis and Type II error means failing to reject a false null hypothesis.

A Type I error occurs in hypothesis testing when one rejects the null hypothesis and the null hypothesis is true.

To reject the null hypothesis, statisticians conduct hypothesis testing. However, the process is always accompanied by the possibility of making a mistake. These are referred to as hypothesis testing errors.

Type I and Type II errors are the two mutually exclusive errors in hypothesis testing. Type II errors occur when a statistician fails to reject a false null hypothesis, whereas Type I errors occur when a statistician correctly rejects a genuine null hypothesis.

In the given question, type I error means rejecting the true null hypothesis i.e. h0: the person is free of disease but we conclude that the person has the disease. This is called a false positive. ha: Type II error means failing to reject a false null hypothesis.

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The graph that correspond to the inequality is the graph in option D

some interpretation on the information from the question include

With the equation: -2x - 3y < 6. Bearing less than, using the guide above, we lookout for graph that have dotted line and shaded above the line

The quality described makes the 4th graph the correct option

other consideration is the intercept

the first equation at x= 0, -2x - 3y < 6  y < -2  (0, -2)

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The length of the PQ is twice of the Length of the ST .

The length of the line segment connecting two points in a plane is defined as distance between two points. The method for calculating the distance between two points is typically written as

d=√((x_2-x_1)²+(y_2-y_1)²)

This formula is used to calculate the distance between two locations on a coordinate plane or an x-y plane.

from the graph

P(2,4), Q(-4,-6), S (7,2) and T (4, -3)

Find the Length of the PQ = √((x_2-x_1)²+(y_2-y_1)²)

= [tex]\sqrt{ (-4-2)^2 + (-6-4)^2}[/tex]

= [tex]\sqrt{136} =11.66[/tex]

ST = [tex]\sqrt{ (4-7)^2 + (-3-2)^2}[/tex] =[tex]\sqrt{34}[/tex] = 5.83

hence verified

The length of the PQ is twice of the Length of the ST .

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Precalculus is an example here, since x=−2 is a vertical type line, there is no  y-intercept as well as the slope is undefined.

The slope is undefined and all of the factors on the road have an x-coordinate of that (a few number). For example, if x = -2, then all factors alongside this line can have an x-coordinate of -2, making it a vertical line. y=−2 is a flat line crossing the factor at (0,−2) consequently the gradient is 0 and the the y intercept is -2.

A terrible slope approach that variables are negatively related; that is, whilst x increases, y decreases, and whilst x decreases, y increases. Graphically, a terrible slope approach that as the road on the road graph movements from left to right, the road falls. The x-coordinate -2 is represented throughout. This is NOT a function.

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Answer:

2(x + 5)

Step-by-step explanation:

1. Common factor

2x + 10

2(x + 5)

Solution

2(x + 5)

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Answer:

All looks  good but Problem 5 K

363

Step-by-step explanation:

33 x 11 = 363

Answer: I only saw one mistake. On your mixed practice, K is wrong. It is 363, not 636.

hope this helps!

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The ways to prove right triangles congruence:

Triangle in the right position

Congruent Hypotenuse-Angle.

Leg-Angle Consistency

Hypotenuse–Leg Congruence

What is a right-angle triangle?

It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.

According to the RHS Criterion:

If the hypotenuse and one of the sides of a right-angled triangle match the hypotenuse and the corresponding side of another right-angled triangle, then the two triangles are said to be congruent.

Leg-to-leg coherence Right triangles are said to be congruent if their respective legs match up with those of another right triangle.

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Answer:

y = -1/2x - 1

Step-by-step explanation:

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The integral that is an equivalent iterated integral in three of the five possible other orders is

I= [tex]\int\limits^9_0[/tex]   [tex]\int\limits^{9-z}_0[/tex][tex]\int\limits^3_{\sqrt{9-y}[/tex]  f(x, y, z)dzdydx

An integral in mathematics assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that come from merging infinitesimal data. The process of determining integrals is known as integration.

Consider the integral,

I=  [tex]\int\limits^3_0[/tex]   [tex]\int\limits^9_{9-x^{2}}[/tex]  [tex]\int\limits^{9-y}_0[/tex]f(x, y, z)dzdydx

This implies that the solid is bounded by

0≤z≤9-y

9-x²≤y≤9

0≤x≤3

Therefore, y+z=9, z=0

y=9-x², y=9

x=0, x=3

Now, the region is given by,

y=9-x², y=9, x=3, x=0

The shaded region is the required region of the figure region.

For the next integral,

√9-y≤x≤3

0≤y≤9

I= [tex]\int\limits^9_0[/tex]  [tex]\int\limits^3_{\sqrt{9-y}[/tex]  [tex]\int\limits^{9-y}_0[/tex]f(x, y, z)dzdydx

Here we have,

y+z =9, z=0

y=9-x², y=9

x=0, x=3

So, √9-y≤x≤3

The projection on the yz plane is,

y+z=0, z=0

y=9

0≤z≤9-y

0≤y≤9

I= [tex]\int\limits^9_0[/tex]   [tex]\int\limits^{9-y}_0[/tex][tex]\int\limits^3_{\sqrt{9-y}[/tex] f(x, y, z)dzdydx

Again, 0≤y≤9-z

0≤z≤9

I= [tex]\int\limits^9_0[/tex]   [tex]\int\limits^{9-z}_0[/tex][tex]\int\limits^3_{\sqrt{9-y}[/tex]  f(x, y, z)dzdydx

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ANOVA is appropriate because the independent variable is categorical and has three classes. The dependent variable is continuous, so ANOVA can be used to determine if there is a significant difference between the means of the three groups.

There are many different types of statistical tests that can be used to analyze data. When choosing a statistical test, it is important to consider the type of data that is being analyzed. In this case, the researcher is looking at an independent variable that is categorical and has three classes. The dependent variable is continuous. In this situation, the best test to use is an analysis of variance (ANOVA).

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Answer:

Step-by-step explanation:

There is no specific question here, but perhaps it is solve for Y? is there any more information?

P= 14 - Y

J= 8  +Y

The area of the triangle when the height is 12 cm would be 414 cm².

The area of the triangle is half the product of its base and height.

A = (1/2)bh

Given that the area A of a triangle whose base is b 3 cm less than six times the height h.

Consider h be the height of the triangle. With this the base may be represented as; 6h - 3.

Therefore,

A = (1/2)bh

A =  (1/2)(6h - 3)h

Now to the equation the value of h, 

  A = (1/2)((6)(12 cm) - 3)(12 cm)

A = 414 cm²

Therefore, the area of the triangle when the height is 12 cm would be 414 cm².

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1. The preparation of the journal entries for Wildhorse Company is as follows:

Date              Account Titles and Explanation     Debit      Credit

July 1, 2022: Cash                                              $98,000

                     Notes Payable                                              $98,000

Nov. 1, 2022: Cash                                          $101,000

                      Notes Payable                                           $101,000

2. The preparation of the adjusting entries for Wildhorse Company is as follows:

Date                 Account Titles and Explanation     Debit      Credit

Dec. 31, 2022: Interest Expenses                         $3,920

                        Interest Payable                                           $3,920

Dec. 31, 2022: Interest Expense                             $1,010

                        Interest Payable                                           $1,010

3. The preparation of the journal entries for Wildhorse Company is as follows:

Date              Account Titles and Explanation     Debit      Credit

Feb. 1, 2023: Interest Expense                           $505

                      Interest Payable                          $1,010

                     Notes Payable                         $101,000

                     Cash                                                           $102,515

Apr. 1, 2023: Interest Expense                         $1,960

                     Interest Payable                         $3,920

                     Notes Payable                         $98,000

                     Cash                                                        $103,880

Adjusting journal entries are made at the end of the financial period to agree with the accounting records according to the accrual concept of generally accepted accounting principles.

Other journal entries are made to recognize the business transactions in the accounting records as they occur.

July 1, 2022: Cash $98,000 Notes Payable $98,000 (9-month, 8% note)

Nov. 1, 2022: Cash $101,000 Notes Payable $101,000 (3-month, 6%)

Dec. 31, 2022: Interest Expenses $3,920 Interest Payable $3,920

Dec. 31, 2022: Interest Expense $1,010 Interest Payable $1,010.

Feb. 1, 2023: Interest Expense $505 Interest Payable $1,010 Notes Payable $101,000 Cash $102,515

Apr. 1, 2023:Interest Expense $1,960  Interest Payable $3,920 Notes Payable $98,000 Cash $103,880

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The probability that the first card is an ace and the second card is a face card is 1.78% and 12/52 respectively.

What is the probability of cards?

Probability is measured by counting and using basic math, such as addition and division. For example, you can multiply the number of spades in a complete deck (13) by the total number of cards in the deck (52) to get the probability of drawing a spade at random: 13 in 52, or 25%.

If you are dealt two cards successively from a standard 52-card deck, find the probability of getting an ace card on the first card and a face on the second.

you want to draw an ace. There are 4 aces out of the 52 cards in the deck so the probability of drawing an ace = 4/52.

So, the combined probability [tex](\frac{12}{52}) . (\frac{4}{52}) = (\frac{3}{13}) . (\frac{1}{13}) = (\frac{3}{169})[/tex]

= 1.78%.

The probability of a face card on the second draw = 12/52 because there are 12 face cards (J, Q, K x 4 of each) and 52 cards in the deck.

Hence, the probability that the first card is an ace and the second card is a face card is 1.78% and 12/52 respectively.

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The alternate includes inequality, this is a two-tailed test.

Given:

A sample of 32 observations is selected from a normal population. The sample mean is 66, and the population standard deviation is 5. Conduct the following test of hypothesis using the 0.10 significance level. H0: μ = 68 H1: μ ≠ 68 rev: 10_12_2016_QC_CS-65155 12. value: 1.00 points Required information.

Number of sample observations:

n = 32

Sample mean:

x = 66

Population standard deviation:

σ = 5

Significance level:

α = 0.10

The hypothesis is stated as,

[tex]H_0[/tex] : μ = 68

[tex]H_1[/tex] : μ ≠ 68

Since The alternate includes inequality, this is a two-tailed test.

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The scale used but Brenda is 1 inch = 5 feet

A scale is used to give context to the user about the size of the area that map covers. It is made by converting real-life measurements into physical measurements for quick calculations.

Brenda measured the middle school and made a scale drawing.

The actual length of the gym = 90 ft.

The length she used in her drawing = 18 inches.

So we will now find the scale used for this drawing,

18 inches = 90 ft.

therefore, 1 inch = 90/18 ft.

             i.e. 1 inch = 5 ft.

Hence, The scale used but Brenda is 1 inch = 5 feet.

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The pattern will be as given, in the matrix form.

We can arrange the given matrix as , A = (0 0 0 0 1 1 0 0 1)

Now,  A*TA = 0

If A has an entry 9 then, the sum of all the diagonal elements.

So the T will be the form of the matrix attached below.

Hence the Pattern will be as

W= [ 0

        0

        0

        0

        1

        1

        0

        0

        1 ]

(Written as a one column matrix.)

M= [  1

         1

         0

         1  ]

(Written as a one column matrix.)

A matrix is a rectangular array of letters, numbers, or expressions in mathematics that are arranged in rows and columns. The matrix below, for instance, has a dimension of 2 3 due to its two rows and three columns: [ 1 9 − 13 20 5 − 6 ]

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Point (-3,5) is  a solution to the system of inequalities

What is inequality?

An inequality in mathematics depicts the connection between two values in an algebraic statement that are not equal. One of the two variables on the two sides of the inequality may be greater than, greater than or equal to, less than, or less than or equal to another value, according to inequality signals.

For this case, what we must do is find a point that meets both inequalities.

y> -2

x + y <4

We have then:

For (0,4):

First inequation:

4> -2 (correct)

Second inequality:

0 + 4 <4 (incorrect)

For (1,4):

First inequation:

4> -2 (correct)

Second inequality:

1 + 4 <4 (incorrect)

For (-3,5):

First inequation:

5> -2 (correct)

Second inequality:

-3 + 5 <4 (correct)

Point (-3,5) is system solution

For (-2,-3):

First inequation:

-3> -2 (incorrect)

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