(a) The amount of argon gas in the cylinder is approximately [tex]\rm \(4.09 \times 10^{-5}\)[/tex] moles.
(b) The change in temperature of the gas is approximately 976.7°C.
Part (a):
Given data:
Inner diameter of the cylinder (d) = 11.43 cm = 0.1143 m
Height of the cylinder ([tex]h_{max[/tex]) = 15.56 cm = 0.1556 m
Height of the disc above the bottom of the cylinder ([tex]h_0[/tex]) = 41.9% of h_max = 0.419 * 0.1556 m
Combined mass of the disc and weights (m) = 19.07 kg
Temperature of the gas (T) = 22.1°C = 22.1 + 273.15 = 295.25 K
We need to find the amount of argon gas in moles in the cylinder.
Step 1: Calculate the volume of the gas in the cylinder.
[tex]\[ V_{\text{gas}} = \pi \left(\frac{d}{2}\right)^2 \times h_0 \]\\\\\ V_{\text{gas}} = \pi \left(\frac{0.1143}{2}\right)^2 \times 0.419 \times 0.1556 \]\\\\\ V_{\text{gas}} \approx 0.00121 \, \text{m}^3 \][/tex]
Step 2: Calculate the number of moles of argon gas using the ideal gas law.
[tex]\[ PV = nRT \][/tex]
Where P is the pressure of the gas (we assume it is constant), V is the volume of the gas, n is the number of moles, R is the universal gas constant (8.314 J/(mol·K)), and T is the temperature in Kelvin.
[tex]\[ n = \frac{PV}{RT} \]\\\\\ n = \frac{1 \times 0.00121}{8.314 \times 295.25} \]\\\\\ n \approx 4.09 \times 10^{-5} \, \text{moles} \][/tex]
Part (b):
Given data:
Additional mass placed on the disc ([tex]m_{extra[/tex]) = 5.56 kg
New height of the disc above the bottom of the cylinder (h_new) = 87.8% of h_max = 0.878 * 0.1556 m
We need to find the change in the temperature of the gas.
Step 1: Calculate the new volume of the gas in the cylinder.
[tex]\[ V_{\text{gas\_new}} = \pi \left(\frac{d}{2}\right)^2 \times h_{\text{new}} \]\\\\\ V_{\text{gas\_new}} = \pi \left(\frac{0.1143}{2}\right)^2 \times 0.878 \times 0.1556 \]\\\\\ V_{\text{gas\_new}} \approx 0.00178 \, \text{m}^3 \][/tex]
Step 2: Use the ideal gas law again to find the new temperature of the gas.
[tex]\[ n_{\text{new}} = \frac{P \times V_{\text{gas\_new}}}{RT_{\text{new}}} \]\\\\\\ T_{\text{new}} = \frac{P \times V_{\text{gas\_new}}}{n_{\text{new}} \times R} \]\\\\\ T_{\text{new}} = \frac{1 \times 0.00178}{4.09 \times 10^{-5} \times 8.314} \]\\\\\ T_{\text{new}} \approx 1271.95 \, \text{K} \][/tex]
Change in temperature:
[tex]\[ \Delta T = T_{\text{new}} - T \]\\\\\ \Delta T = 1271.95 - 295.25 \]\\\\\ \Delta T \approx 976.7 \, \text{K} \][/tex]
Result:
(a) The amount of argon gas in the cylinder is approximately [tex]\rm \(4.09 \times 10^{-5}\)[/tex] moles.
(b) The change in temperature of the gas is approximately 976.7°C.
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find the work done be the force field f in moving an object along the curve pictured in the graph. do this by computing the work on each piece-wise smooth portion of c.
Find the amount of labor necessary to move an object along the specified orientated curve given the force field F. y = 3x2 on the parabola from (0, 0) to F = (y, x) (4, 48).
How can you determine the work a force field performs along a curve?A variable force's infinitesimal work can be defined in terms of the force's components and the displacement along the path,
How do you assess the force field F's work?(c) Next, determine the work that the force field F performed on the object to move it through the field by moving it along the vector d. W = F d is the formula for work.
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a large goose lands in a lake and bobs up and down for a short time. a fisherman notices that the first wave crest created by the goose reaches the shore 8.6 ss after the goose first contacts the water. the distance between two wave crests is 75 cmcm, and in 1.8 ss he sees four wave crests hit the shore.
The shore the goose landed 11.85m
Briefly:-For development of this problem we must resort to concepts of the basic kinematic equations that define the distance of a body, such as speed for a certain time, that is,
D=v*t
From the information is provided say that the distance between the cretas is= 0.6m,
Dcrets= .06m
In our information we have also that length between the first and the latest wave is in time terms of 2.2s. They are 4 waves in 3 intervals then
Dt= Dcrets*3= 2.4m
t= 1.6s
V= Dt/t
V= 1.5 m/s.
Then the distance from the shore is given by the speed of the waves for the total time. That is
X= v*t=11.85
the shore the goose landed X=11.8m
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According to Newton's Third Law, if a hammer puts a force of 100 N on a nail, how much force does the nail put back on the hammer?
A. -100 N
B. 50 N
C. 200 N
D. -200 N
Answer:
option (A) is correct.
Explanation:
Newton’s Third Law: Action & Reaction Whenever one object exerts a force on a second object, the second object exerts an equal and opposite force on the first. His third law states that for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A.
In exercising, a weight lifter loses 0.178 kg of water through evaporation, the heat required to evaporate the water coming from the weight lifter's body. The work done in lifting weights is 1.35E+5 J. Assuming that the latent heat of vaporization of perspiration is 2.44E+6 J/kg, find the change in the internal energy of the weight lifter.
The change in the internal energy of the weight lifter is -5.69 x 10⁵J.
Solution:
[tex]\Delta U = Q-W[/tex]
work done is lifting a body is [tex]1.35*10^5 J[/tex]
so, [tex]W = 1.35*10^5 J[/tex]
during perspiration, heat will be lost by the body to make water evaporate
so,
[tex]Q= -L_v \times m[/tex]
where m is the mass of water
[tex]Q= -2.44 \times 10^6 \times 0.178 J=-4.34 \times 10^5 J[/tex]
Now, change in internal energy,
[tex]\Delta U = -4.34\times 10^5- 1.35 \times 10^5 =-5.69 \times 10^5 J[/tex]
A glass of water standing on a table has no visible macroscopic potential or kinetic energy. However, water molecules have internal energy because they move randomly and each molecule contributes to the total internal energy of water. The energy involved in the system is related to the random motion of the particles and the potential energy of the molecules due to their orientation.
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arrange the selected events in the model of the early universe in chronological order, from earliest to latest.
Universe in chronological order,Inflation, Separation 2 fundamental forces, Formed subatomic, Nucleosynthesis and Formation of first stars.
Mystics, theologians, philosophers, and scientists can all have different perspectives on the universe. In science, we take the slow approach and only accept claims that can be verified through experiment or observation. The General Relativity Theory, which Albert Einstein developed, explains the relationships between mass, energy, space, and time. Einstein demonstrated how well his theory fits with a homogeneous distribution of matter in space. He made the unquestioned assumption that the universe is static and constant on a grand scale. Alexander A. Friedmann, a Russian theorist, discovered in 1922 that Einstein's universe is unstable and will expand or contract with even the smallest perturbation. Vesto M. Slipher of Lowell Observatory was gathering the initial proof that galaxies are actually separating at the time.
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water flows at a rate of 2.5 m/s over a flat plate that is parallel to the oncoming flow. (a) determine the approximate location downstream of the front of the plate where the boundary layer becomes turbulent. assume that this occurs at a reynolds number rex
The boundary layer thickness is 7.92 x 10^(-3) m.
A) Formula for Reynolds number to reflect this question is given as;
R_e = Vx/v
Where;
V is velocity
x is polar coordinate where the boundary layer will become turbulent.
R_e is reynolds number.
Reynolds number for turbulent flow of flat plates has a value of 5 x 10^(5)
v is kinematic velocity
From water tables at standard conditions, kinematic viscosity is 1.12 x 10^(-6) m²/s
Now, R_e = Vx/v
We are looking for x, so let's make x the subject.
x = v•R_e/V
Thus, plugging in the relevant values to obtain;
x = [1.12 x 10^(-6) x 5 x 10^(5)]/0.5
x = 1.12m
The boundary layer thickness at the point where the flow becomes turbulent is given by;
δ = 5√(vx/V)
Where;
V is velocity
x is polar coordinate where the boundary layer will become turbulent.
R_e is reynolds number.
Reynolds number for turbulent flow of flat plates has a value of 5 x 10^(5)
v is kinematic velocity
Plugging in the relevant values to get ;
δ = 5√(1.12 x 10^(-6)•1.12/0.5)
δ = 5√(2.5088 x 10^(-6)
δ = 7.92 x 10^(-3) m
Therefore, the boundary layer thickness is 7.92 x 10^(-3) m.
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The filament of a 75-W light bulb is at a temperature of 3300 K. Assuming the filament has an emissivity e = 0.9, find its surface area. (Use s = 5.6696 10-8 W/m2 · K4 for the Stefan-Boltzmann constant.)
Surface area is 1.10 × 10^-5 .
Stefan-Boltzmann law, statement that the total radiant heat power emitted from a surface is proportional to the fourth power of its absolute temperature.All bodies radiate energy W depending on temperature T, according to the Stefan-Boltzmann law W = ε σT4 where emissivity ε is equal to 1 for black bodies and less than 1 for grey bodies, σ being the Stefan constant.
From Stefan's law, the power radiated by an object at absolute
temperature T and surface area A is POAT, where a=5.6696 × 10
W/m²K and e is the emissivity. Thus, the surface area of the filament
must be
A =75 W / (5.6696x10 )(1.0 )(3300) = 1.10 * 10^-5
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____ are thick in the middle and thin at the edges concave lenses convex lenses concave mirrors plane mirrors
volume of right circular cone; volume of cone; how to find volume of a cone; cone formula
The volume of the right circular cone is given by the formula πR²H/3.
A right circular cone is a kind of cone in which the centre of the circular base of the cone is perpendicular to the vertical height of the cone.
The volume of any right circular cone is generally given by the formula,
V = πR²H/3
Where,
V is the volume of the right circular cone,
R is the radius of the circular base of the right circular cone.
H is the vertical height of The right circular cone.
π is a constant that has a valued 22/7.
In any general case when we are given the value of the radius of the circular base of the right circular cone and the height of the right circular cone, then we can just simply put the values in the above mentioned formula and we get the volume of the right circular cone.
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T/F which of the following best describes the energy transformations that occur when a flashlight that runs on batteries is turned on?
The chemical energy in the batteries is transformed into electrical power when the lighting is put on, which goes through the wires of the flashlight. Then, light and heat energy are created from this electrical energy.
What are two sorts of batteries?Batteries can be divided into two categories: main and secondary. Primary batteries cannot be refilled because they are "single use."Examples of primary batteries include dry phones and (most) alkaline batteries. The second type, which is rechargeable, is a secondary battery.
What exactly are batteries used for?An object that stores energy and releases it by transforming chemical energy into electrical energy is a battery. Typical batteries typically employ one or more fuel cells to chemically generate electricity.
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In photography; exposure is the amount of light allowed to strike the film_ Exposure can be adjusted by the number of stops used to take a photograph: The change in the number of stops n needed is related to the change in exposure c by n 10g2 A. How many stops would a photographer use to triple the exposure? B. How many stops would a photographer use to get 5 the exposure?
n = number of stops
c = change in exposure
n = log₂ C ..........(1)
A. Let n be no of stops needed to triple the exposure then n₁ = log(30) = n, log, 3+ log, C ..............(2)
We see using (1) in (2) n₁ = n + log 3 = n+1.5850
Thus we need to increase no. of stops by 1.585 ≈ 1.6.
B. Similarly to get exposure, changing c by c/5
n₁ = log₂ (45) = n₁ = log₂c - log₂5
n₁ = n - log₂5 = n₁ -2.3219
One needs to decrease the no. of stops by 2.3219.
Aperture is one of three camera settings that control the exposure of your image. These settings are collectively known as the exposure triangle and consist of shutter speed aperture and ISO. The aperture controls exposure by increasing or decreasing the relative amount of light entering the camera lens.
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250 students sit in an auditorium listening to a physics lecture. because they are thinking hard, each is using 125 w of metabolic power, slightly more than they would use at rest. an air conditioner with a cop of 7.5 is being used to keep the room at a constant temperature. What minimum electric power must be used to operate the air conditioner?
The minimum electric power that must be used to operate the air conditioner is 6250 W.
The total students in the auditorium are n = 250
The metabolic power each student is using is p = 125 W
The coefficient of performance ( COP ) of the air conditioner is given as 5 to maintain a constant temperature inside the auditorium.
Let the minimum electric power that must b used to run the air conditioner be P.
We know that
COP = np / P
P = np / COP
= ( 250x 125 ) / 5
= 6250W
So, 6250 W power is the minimum power.
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part b in another experiment, the intensity of the incident light and the temperature of the metal are held constant. assuming that the initial light incident on the metal surface causes electrons to be ejected from the metal, what happens if the frequency of the incident light is increased? check all that apply. view available hint(s)for part b in another experiment, the intensity of the incident light and the temperature of the metal are held constant. assuming that the initial light incident on the metal surface causes electrons to be ejected from the metal, what happens if the frequency of the incident light is increased?check all that apply. the work function of the metal increases. the number of electrons emitted from the metal per second increases. the maximum speed of the emitted electrons increases. the stopping potential increases.'\
Because whilst depth of incident mild will increase, it approach that wide variety of photons will increase in incident mild.
If wide variety of incident photons will increase, then wide variety of emitted picture graph electrons additionally will increase, therefore the picture graph electric powered contemporary will increase.
The photoelectric impact. In the photoelectric impact, mild waves (pink wavy lines) hitting a steel floor motive electrons to be ejected from the steel.
Current in picture graph electric powered impact is immediately proportional to the depth of the incident mild. paintings function, preventing potential, most kinetic electricity are unbiased of depth of incident mild, they rely upon the frequency, wavelength of the incident mild and cloth of the steel.
Using L for luminosity, the depth of mild system becomes I=LA I = L A . Because mild waves unfold in all directions, to correctly calculate mild depth, the denominator withinside the system have to be the floor vicinity of a sphere. In fact, maximum electromagnetic calculations are achieved over a sphere.
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The jumper has a mass of 55 kg, and the bridge's height above the river is 150 m. The rope has an unstretched length of 8 m and stretches a distance of 5 m before bringing the jumper to a stop. Determine the maximum speed of the jumper and the spring constant of the rope. In your calculation, use g 10 N/kg. m/s Vmax k = N/m E.
Now suppose the jumper has a mass of 80 kg. Do you think the maximum speed of the jumper will increase, decrease, or stay the same? Will the rope need a larger, smaller, or the same spring constant to bring the jumper to a stop in the same distance as part D?
The speed of jumper is 54.22 m/s and spring constant of the rope is 6468N/m.
Given data:
The mass of jumper is, m = 55 kg.
The height of bridge above the river is, h = 150 m.
The length of unstretched rope is, L = 8m.
The stretched length is, L' = 5m.
In this problem, when the jumper will jump then the only potential energy of the jumper will get converted into the spring potential energy of the rope. So we can say that the relation will be,
potential energy of jumper = spring potential energy of rope.
Here, k is the spring constant.
Solving as,
mgh = 1/2 KI²
55 × 90.8 × 150 = 1/2 × k × 5 × 5k
k = 6468 N/m
Now, apply the third kinematic equation of motion to calculate the final speed of jumper as,
v² = U² + 2as
We get U= 54.22 m/s.
Thus, we can conclude that the speed of jumper is 54.22 m/s and the spring constant of the rope is 9187.5 N/m.
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The distance around Earth's equator is about 24,000 miles. Use the formula in Question 4 to calculate the approximate rotational velocity at Earth's equator mph (using the fellowing formula: Velocity = Distance/Time miles/hour)
The distance around Earth's equator is about 24,000 miles. Thus, rotational velocity at Earth's equator is 1000 miles/hour.
What is rotational velocity?Every point on an object that is revolving about an axis has the same angular velocity. The tangential velocity of points distant from the axis of rotation is, nevertheless, different from that of points closer to the axis of rotation. Rotational velocity and an angular frequency vector are other names for angular velocity.
Given that,
The distance around Earth's equator is about 24,000 miles.
Time to complete one Rotation = 24 hours.
Thus, velocity = distance/time
or, velocity = 24,000 miles / 24 hours
or, velocity = 1000 miles/hour.
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The figure shows an overhead view of a ring that can rotate about its center like a merry-go-round. Its outer radius R2 is 0.8 m, its inner radius R1 is R2/2, its mass M is 8.0 kg, and the mass of the crossbars at its center is negligible. It initially rotates at an angular speed of 7.6 rad/s with a cat of mass m = M/4 on its outer edge, at radius R2. By how much does the cat increase the kinetic energy of the cat-ring system if the cat crawls to the inner edge, at radius R1?
The cat increase the kinetic energy of the cat-ring system is 42.4 J.
Mass of the merry-go-round = M = 7.6 kg
Outer radius of the merry-go-round = R2 = 0.9 m
Inner radius of the merry-go-round = R1 = R2/2 = 0.9/2 = 0.45 m
Moment of inertia of the merry-go-round = I
I = 3.8475 kg.m2
Mass of the cat = m = M/4 = 7.6/4 = 1.9 kg
Initially the cat is sitting at the outer edge that is at a distance of 'R2' from the center.
Initial moment of inertia of the system = I1
I1 = I + mR22
I1 = 3.8475 + (1.9)(0.9)2
I1 = 5.3865 kg.m2
Initial angular speed of the system = title=View image!
1 = 7.6 rad/s
Now the cat walks to the inner edge of the merry-go-round therefore it is at a distance 'R1' from the center.
New moment of inertia of the system = I2
I2 = I + mR12
I2 = 3.8475 + (1.9)(0.45)2
I2 = 4.23225 kg.m2
New angular speed of the system =
I = I2
(5.3865)(7.6) = (4.23225)2
= 9.673 rad/s
Initial kinetic energy of the system = E1
E2 = 198 J
Amount by which the kinetic energy of the system increases =
E = E2- E1
title=View image!
E = 198 - 155.6
ΔE = 42.4 J
Amount by which the kinetic energy of the system increases when the cat crawls to the inner edge = 42.4 J.
Kinetic Energy:
Kinetic energy is the energy that an object possesses due to its motion. It is defined as the work required to accelerate an object of specified mass from rest to a specified velocity. After the body acquires this energy during acceleration, it retains this kinetic energy as long as the velocity does not change.
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in the hydrogen spectrum, the series of lines called the lyman series results from transitions to the n=1 energy level. What is the longest wavelength in this series and in which region of the electromagnetic spectrum does it lie?
According to question the longest wavelength in the lyman series and in which region of the electromagnetic spectrum does it lie is 122nm.
What is meant by Lyman series?When an electron transitions from the smallest energy level of n = 1 to n = 2 (here n is the primary quantum number), known as the Lyman series, it emits ultraviolet light from the hydrogen atom in a sequence of changes.
Breifing:Rydberg equation: 1/L = R(1/n2 - 1/m2)
where L is wavelength, R is Rydberg constant, m and n are quantum numbers of levels involved in transition.
Longest wavelength in Lyman series: n = 1, m = 2
1/L = 1.097 x 107 x (1/1 - 1/2)
L = 1.22 x 10-7 m = 122 nm
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If a vector pointing to the right has a positive magnitude, then one pointing to the left has a negative magnitude.
"If a vector pointing to the right has a positive magnitude, then one point to the left has a negative magnitude " is a false statement.
Vector, in physics, a quantity that has both magnitude and direction. This is usually represented by an arrow whose direction is the same as the quantity and whose length is proportional to the magnitude of the quantity. A vector has magnitude and direction, but no position. In other words, the vector does not change with translation unless the length changes.
Reason :
Because magnitude is never negative, only direction may be negative or positive.
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A parallel plate capacitor using a dielectric material having a dielectric constant of 2.5 has a plate separation of 1-mm. If another material having a dielectric constant of 4.0 is used and the capacitance is to be unchanged, what must be the new spacing between the plates?
The new spacing between the plates is 1.6mm
What is capacitor?
A capacitor is a device that uses the accumulation of electric charges on two nearby surfaces that are electrically isolated from one another to store electrical energy in an electric field. It has two terminals and is a passive electrical component. The effect of a capacitor is known as capacitance.
What is dielectric constant?
A substance or material's capacity to hold electrical energy is indicated by its dielectric constant. It is a measurement of how much electric flux a substance can hold or concentrate.
Dielectric constant k = 2.5
Separation between the plates d = 1 mm
Dielectric constant k ' = 4
let new separation between the plates = d '
We know C = k A / d
In both cases C ,A are constant .
So, ( k ' / k ) = ( d ' / d)
d ' = d ( k ' / k )
= 1.6 mm
The new spacing between the plates is 1.6mm
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a radioactive material produces 1390 decays per minute at one time, and 4.1 h later produces 150 decays per minute. What is its half-life?
The half-life of the radioactive material is about 2.75 hours.
To determine the half-life of a radioactive substance, we need to determine the time it takes for the number of decays per minute to decrease by a factor of two.
You can set up an expression that relates decays per minute at two time points.
1390 decays/min ×(1/2)^(t/(half-life)) = 150 decays/min
where t is the elapsed time between two measurements (4.1 hours) and (1/2)^(t/(half-life)) is the decay factor, dividing the number of decays per minute by half. reduce to
By rearranging the equation, we can solve for the half-life.
half-life = t ×log(2) / log((1390/150)^(1/t))
Substituting the values of t and the number of decays per minute at the two time points, we get
half-life = 4.1 ×log(2) / log((1390/150)^(1/4.1))
This simplifies to:
half-life = 4.1 × 0.693 / log (9.27)
=2.747 hours.
Therefore, the half-life of the radioactive material is about 2.75 hours.
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a spring scale shows a net force of 0.8 n acting on a 1.5-kg mass. what happens to the acceleration of the object if the net force is decreased to 0.2 n?(1 point)
Answer:
0.4m/s²
Explanation:
force = 0.8–0.2 = 0.6N
mass = 1.5kg
acceleration = ?
force = mass × acceleration
f = m × a
a = f/m
a = 0.6/1.5
a= 0.4 m/s²
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aftershocks are very dangerous because: multiple choice they occur in random patterns unrelated to the location of the main quake. they are usually larger than the original earthquake. they nearly always generate a tsunami. they collapse structures damaged by the main quake.
Aftershocks are very dangerous because they collapse structures damaged by the main earthquake.
When an earthquake occurs, they usually tends to break the base of the structures.
This phenomena makes the structure very weak.
The aftershock that are generated because of the main earthquake breaks the already weak structures completely.
If there are any chances of survival of any mankind after the main earthquake, they are completely eliminated because of the after shocks created. This is why we can conclude that aftershocks are very dangerous because of their tendency to collapse the structure damaged by the earthquake.
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a negative feedback system has the forward path transfer function g and feedback path transfer function h indicated below. you wish to add a controller gc to the system in cascade compensation with the plant, which means it is in the forward path. if gc has the form indicated below, and assuming the gain k is positive, what is the upper limit on the value of k? use the frequency response methods to find your answer.
The best technique to determine a system's response at a specific frequency is to drive the system being tested with a sine wave at the target frequency while keeping an eye on the relevant system output (s).
How does frequency response analysis work?
The process of measuring points on the frequency response of a transfer function or impedance function using a sinusoidal test signal is known as frequency response analysis. The fundamental configuration of a sine wave being applied to a system with a transfer function G is represented in Figure 1 (s).
The significance of frequency response analysis?
Frequency response analysis is frequently required with many modern electrical designs to make sure they meet performance standards. You can examine how the outputs of your circuit designs respond to a wide range of various frequency inputs using this area of signal characterisation.
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A 5.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping. What was the initial speed of the bullet?
The initial speed of the bullet is 2624.7 m/s.
Conservation of momentum indicates that the total momentum of an isolated system remains the same in the absence of an external force. H. Momentum is neither created nor destroyed, but can be changed by the action of forces in the sense of Newton's laws of motion.Momentum is the product of an object's mass and its velocity, which is also equal to the total force required to keep the object at rest.One of the practical aspects of momentum conservation is the collision problem where momentum is conserved and the net external force remains zero.Mass of bullet, m = 5 g = 0.005 kg
Mass of block, M = 1.2 kg
Coefficient of friction = 0.2
Distance, d = 0.31 m
Let the initial speed of the bullet is u.
Use Conservation of momentum
m u = (M + m) v
0.005 x u = (1.2 +0.005) v
v = 4.2 x 10-4 u m/s
Now, use third equation of motion
v2 = u2 - 2μg s 0 = (4.2 x 10-4 u)2 - 2 x 0.2 x 9.8 x 0.31u = 2624.7 m/s
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a baseball leaves the bat at 76m/s, 57 degrees above the horizontal. how long is it in the air
So the time taken that the ball stays in the air was found to be 13 seconds.
what is a baseball used for ?
One of the most recognisable and crucial pieces of baseball equipment is the baseball. Every player on the field frequently uses baseballs, which are employed as the game's basic tool. There would be no game if there were no baseballs.
t = vsin∅/g
t = 76 sin 57/9.81
t = 76(0.8387)/9.81
t=63.741/9.81
t=6.497≈6.5
As the time taken for the ball for going up and down will be
2t=(6.5)2
=13
so the time that the ball stays in the air was found to be 13 seconds
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the vectors d and e are [-4,1] and [1,4] respectively .find the angle b/n and e (Use dot product )
when your car accelerates away from a stop sign, you feel like you're being pushed back into your seat.
No, when your car accelerates away from a stop sign, you feel like you're being pushed back into your seat. There is no force pushing you backward, just the seat pushing forward.
In the inertial reference frame, the only force acting on occupants while sitting inside the accelerating car is the force that causes occupants to accelerate which is given by mass times the acceleration. So from the inertial reference frame occupant accelerates.
What is the acceleration?
One of the important notions like Speed and Velocity, in Physics that is used to explain motion and to solve problems concerned to it, is called the acceleration.
No, when your car accelerates away from a stop sign, you feel like you're being pushed back into your seat. There is no force pushing you backward, just the seat pushing forward.
In the inertial reference frame, the only force acting on occupants while sitting inside the accelerating car is the force that causes occupants to accelerate which is given by mass times the acceleration. So from the inertial reference frame occupant accelerates.
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A square loop of wire lies in the plane of the page and carries a current I as shown. There is a uniform magnetic field Vector B parallel to the side MK as indicated. The loop will tend to rotate: A. about PQ with KL coming out of the page B. about PQ with KL going into the page C. about RS with MK coming out of the page D. about RS with MK going into the page E. about an axis perpendicular to the page.
The correct option A. about PQ with KL coming out of the page B; for the direction of the rotation of the loop for the uniform magnetic field.
Explain the term uniform magnetic field?The field lines must be both parallel and equally spaced in order for the region under examination to have a uniform magnetic field, which must have the same strength and direction throughout.If the magnetic field's lines are parallel, the magnetic field's intensity will be the same at every place, meaning the field's strength will be constant.Assume that the X and Y axes are, respectively, along OQ and OR.
Since the current in MK is along B, F(MK) = 0.Since the current in LN is the opposite of B, F(LN) = 0.The two forces, F(KL) and F, have different lines of attack (MN).
The angle of perpendicularity between F(KL) and F(MN) is l.
As a result, the square loop will revolve around PQ, with KL emerging from the page.
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The diagram for the question is given -
compare the final kinetic energies of pucks a and b . compare the final kinetic energies of pucks and . ka
Puck B's kinetic energy is 2 times puck A's kinetic energy.
what is kinetic energy?The energy an item has as a result of motion is known as kinetic energy. If we wish to accelerate an item, we must use force. We must put in effort in order to apply force.
Briefing:
Let the,
mass of puck A =m
mass of puck B = 2 m
The initial speed for both the pucks is the same as u and the distance is the same for both as s.
Let the tension is T for the same.
Then, the kinetic energy is given as,
KE= [tex]\frac{1}{2}[/tex] M[tex]V^{2}[/tex]
where M is the mass of an object
and v is the velocity of an object
as the speed is the same for both mass A and B so kinetic energy will depend on only the mass of the object.
[tex]\frac{KE OF A}{KE OF B}[/tex] = [tex]\frac{1}{2} M_{A} V_A^{2}[/tex] /[tex]\frac{1}{2} M_{B} V_B^{2}[/tex]
on putting the values of masses a and b
we get,
[tex]\frac{KE OF A}{KE OF B}[/tex] = [tex]\frac{1}{2}[/tex]
KE OF B= 2(KE OF A)
As a result, we can say that puck B has kinetic energy that is twice that of puck A.
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the complete question is:
Puck B has twice the mass of puck A. Starting from rest, both pucks are pulled the same distance across frictionless ice by strings with the same tension. Compare the final kinetic energies of pucks A and B.
what happens to the atomic number of an atom when the number of neutrons in the nucleus of that atom increases? (2 points) it decreases it increases it doubles it remains the same
The atomic number of an atom when the number of neutrons in the nucleus of that atom increases, it remains the same.
What is meant by atomic number?The charge number of an atomic nucleus is the chemical element's atomic number, also known as nuclear charge number (symbol Z). This is equivalent to the proton number (np), or the number of protons present in the nucleus of each atom of that element, for conventional nuclei. Ordinary chemical elements can be uniquely identified using their atomic number. The atomic number and the number of electrons are both equal in a regular, uncharged atom.Isotopes are atoms with the same atomic number but distinct neutron numbers, and thus, varying mass numbers. The standard atomic weight of an element is determined by the average isotopic mass of an isotopic mixture for that element in a particular environment on Earth. A little over three-quarters of naturally occurring elements exist as a mixture of isotopes (see monoisotopic elements).Learn more about atomic number refer to :
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