product of squre of x and cube of y

The zeros of the given equation are -5  and -7

Quadratic equations are equations that has a leading degree of 2. Given the factors of a quadratic equation as expressed below;

(-3x - 15)(x+7) = 0

The expressions -3x -15 and x + 7 are the factors of the equation. Equating both factors to zero

-3x - 15 = 0

Add 15 to both sides of the equation

-3x -15 + 15 = 0 + 15

-3x = 15

Divide both sides of the equation by -3

-3x/-3 = 15/-3

x = -5

Similarly;

x + 7 = 0

x = -7

Hence the zeros of the given equation are -5  and -7

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The descriptive statistics for the above data is given as follows:
X = 12.5

A set of concise descriptive coefficients that describe a particular data set indicative of a whole or sample population is known as descriptive statistics.

For X (mean) = [tex]{\displaystyle X={\frac {1}{n}}\sum _{i=1}^{n}X_{i}[/tex]

= 300/24

= 12.5

For sample variance = [tex]s^2 = \frac{1}{n-1}\biggl[\, \sum_{i=1}^n X_i^2 - \frac{\Bigl(\,\sum\limits_{i=1}^n X_i\Bigr)^{\!2}}{n} \biggr][/tex]

= (1/(24-1) (4,900 - (300²/24)

= 50

Standard deviation s = √s²

= √50

= 7.0711

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The solutions of the given equation is x = -8 + 5√2 and  x = -8 - 5√2.

The quadratic formula is used to find the roots of a quadratic equation. This formula helps to evaluate the solution of quadratic equations replacing the factorization method. If a quadratic equation does not contain real roots, then the quadratic formula helps to find the imaginary roots of that equation. The quadratic formula is also known as Shreedhara Acharya’s formula

(x + 2)² + 12(x + 2) – 14 = 0

Replacing x + 2 with u we get,

u² + 12u - 14

using quadratic formula we get

u = (-12 ±√(12² - 4x1 x-14))/2

u =(-12 ±√200)/2

u = -6 ± 5√2

x +2 = u = -6 ± 5√2

x = u = -8 ± 5√2.

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The conclusion can be made from the given information

The volume of the triangular prism is equal to the volume of the cylinder

Given that there are two figures

1. A right triangular prism

2. Right cylinder

The area of the cross-section of the prism is equal to the Area of a cross-section of the cylinder.

Let this value be A.

Also given that the Height of prism = Height of cylinder = 6

The volume of a prism is will be :

[tex]V _{prism} = cross section area \times height[/tex]

[tex]V _{prism} = A \times 6 = 6A[/tex]  (1)

The Cross section of the cylinder is a circle.

hence the Area of the circle will be:

Area of cross-section, A = [tex]\pi \times r^2[/tex]

so, the Volume of the cylinder will be :

[tex]V _{cylinder} = \pi \times r^2 \times h[/tex]

[tex]V _{cylinder} = A \times h = A \times 6 = 6A[/tex]  (2)

From equations (1) and (2) we can say that

The volume of the triangular prism is equal to the volume of the cylinder.

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The Jacobian for this transformation is

[tex]J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}[/tex]

with determinant [tex]|J| = 12[/tex], hence the area element becomes

[tex]dA = dx\,dy = 12 \, du\,dv[/tex]

Then the integral becomes

[tex]\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv[/tex]

where [tex]R'[/tex] is the unit circle,

[tex]\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1[/tex]

so that

[tex]\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv[/tex]

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

[tex]\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}[/tex]

Then

[tex]\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}[/tex]

Answer:

[tex]p = x \\ r = 6\% \\ t = 2yrs[/tex]

[tex]p = 1600[/tex]

please see the attachment

Answer:

P = $1600

Step-by-step explanation:

We have to use the equation:

[tex]\boxed{I = Prt}[/tex] .

We know that:

• I = $192

• P = ?

• r = 6% = 0.06

• t = 2 years

Substituting these values into the equation:

[tex]192 = P \times 0.06 \times 2[/tex]

Solving for P:

[tex]P = \frac{192}{0.06 \times 2}[/tex]

[tex]P = \bf \$1600[/tex]

Answer:

[tex]\frac{2}{25}[/tex]

Step-by-step explanation:

Each "place" in the decimal, can be represented with a base 10 in the numerator.

For example the "tenths" place can be represented as: [tex]\frac{a}{10^1}[/tex] where a=decimal.

The hundredths place can be represented as: [tex]\frac{a}{10^2}[/tex]

The thousandths place can be represented as: [tex]\frac{a}{10^3}[/tex]

and so on...

In this case, we have a decimal in the hundredths place which can be represented as: [tex]\frac{8}{10^2} = \frac{8}{100}[/tex]. Now to simplify this fraction, you simply divide both sides by 4 (greatest common factor of 8 and 100), or in other words multiply it by 0.25/0.25 which is just 1, so the value is the same. [tex]\frac{8}{100} * \frac{0.25}{0.25} = \frac{2}{25}[/tex]

The remaining value will increase by the value of the slope. Hence the remaining missing values are -47, -44, -41, -38 and -35

The slope of a line is the ratio of the rise to run of a line. It is also defined as the rate of change of coordinate y with respect to x. Mathematically;

slope = change in y/change in x

If the slope of the table given is 3, then using the coordinate points (5, -50)and (6, y)

Substitute

3 = y-(-50)/6-5
3 = y+50/1
y+50 = 3

y = -47

The remaining value will increase by the value of the slope. Hence the remaining missing values are -44, -41, -38 and -35

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Answer:

6.98

Step-by-step explanation:

I think that you are looking for the diameter and you are given the area of a circle.

a =[tex]\pi r^{2}[/tex]  You are given pi, so [tex]r^{2}[/tex] = 72.

That means that r = [tex]\sqrt{72}[/tex] or a rounded answer of 8.49 rounded to the hundreds place.  The diameter is equal to 2 radius, so the diameter rounded is 16.98

By simplifying the fraction 10/28 ÷ 32/49 exists 35/64.

The first stage of dividing fractions exists to estimate the reciprocal (reverse the numerator and denominator) of the second fraction. Subsequently, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if required.

To find the reciprocal of the divisor

Reciprocal of 32/49 = 49/32

Now, multiply it by the dividend, then we get

So, 1028 ÷ 3249 = 10/28 × 49/32

= (10 × 49)/(28 × 32) = 490/896

After decreasing the fraction, the answer exists at 35/64.

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The 15th term in the given A.P. sequence is a₁₅ = 33.

According to the statement

we have given that the A.P. Series with the a = 5 and the d is 2.

And we have to find the 15th term of the sequence.

So, for this purpose we know that the

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

And the formula is a

an = a + (n-1)d

After substitute the values in it the equation become

an = 5 + (15-1)2

a₁₅ = 5 + 28

Now the 15th term is a₁₅ = 33.

So, The 15th term in the given A.P. sequence is a₁₅ = 33.

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Answer:

10830.87 mm³

Step-by-step explanation:

Hello!

Volume of a cylinder: [tex]V = \pi r^2(h)[/tex]

The radius for this cylinder is 9.525, after dividing 19.05 by 2.

Plug it into the volume formula to solve for the volume.

The volume is approximately 10830.87 cubic millimeters.

Answer:50%

Step-by-step explanation:  It doesn't matter how many questions there are because for each question, you have a 50% chance of getting it right. So, the probability is 50%.

Answer:

1/8

Step-by-step explanation:

say the bar has 20 pieces. he has 10 pieces. and he gave away 1/4 of those 10

1/4 x 10 = 2.5

20 / 2.5 = 8

So his friend recieved 1/8

you could also just do 1/2 x 1/4 which is 1/8

Answer:

1/8 of the candy bar.

Step-by-step explanation:

Elias has 1/2 of a candy bar.

He gave 1/4 of 1/2 to his friend.

[tex]\sf Friend's s\ share = \dfrac{1}{4} \ of \ \dfrac{1}{2}[/tex]

                      [tex]\sf =\dfrac{1}{4}*\dfrac{1}{2}\\\\=\dfrac{1}{8}[/tex]

The solution to the product of 8 and three-seventh is 2 2/7. According to Laura, she made mistake in step 2 by adding 8 and 3 instead of multiplying

Multiplication of fractions and integers

Fractions are written as a ratio of two integers. For instance a/b is a fraction where a and b are integers.

Given the following equation

Multiply 3/7 and 8

This is expressed mathematically as;

3/7 * 8

Step 1: Swap to have;

8 * 3/7

Step 2: Group the numerator

(8*2)/7

Step 3; Simplify

16/7

Step 4; Convert to mixed fraction

16/7=  2 2/7

The solution to the product of 8 and three-seventh is 2 2/7. According to Laura, she made mistake in step 2 by adding 8 and 3 instead of multiplying

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Answer:

D. 25pi

Step-by-step explanation:

"circumscribed" means the rectangle is inside the circle and just the corners (vertices) of the rectangle are touching the circle. This means the diagonal of the rectangle is the diameter of the circle. See image. If the sides of the rectangle are 6 and 8 then the third side that makes the triangle(half the rectangle) is 10. You can find this using Pythagorean Theorem or Pythagorean triples (shortcut)

6^2 + 8^2 = d^2

36 + 64 = d^2

100 = d^2

d = 10

This is the diameter of the circle. The radius would then be 5.

Area of a circle is:

A = pi•r^2

= pi•5^2

= 25pi

The area of the resulting surface of this infinite curve is π units.

In this question,

The infinite curve is y = e^−2x, x ≥ 0.

The curve is rotated about x-axis.

Since x ≥ 0, the limits will be 0 to ∞.

Then the area of the resulting surface is,

[tex]A= 2\pi \lim_{b\to \infty} (\int\limits^\infty_0{e^{-2x} } \, dx )[/tex]

Now substitute,

u = -2x

⇒ du = -2dx

⇒ dx = [tex]-\frac{1}{2} du[/tex]

Then,

[tex]\int\limits{-\frac{1}{2}e^{u} } \, du =-\frac{1}{2}\int\limits{e^{u} } \, du[/tex]

Now substitute u and du, we get

⇒ [tex]-\frac{1}{2} \int\limits {e^{-2x} }(-2) \, dx[/tex]

⇒ [tex]-\frac{-2}{2} \int\limits {e^{-2x} } \, dx[/tex]

⇒ [tex](1) \int\limits {e^{-2x} } \, dx[/tex]

⇒ [tex]\int\limits {e^{-2x} } \, dx[/tex]

Thus the area of the resulting surface is

[tex]A= 2\pi \int\limits^\infty_0{e^{-2x} } \, dx[/tex]

⇒ [tex]A= 2\pi [{e^{-2x}(\frac{1}{-2} ) } \,]\limits^\infty_0[/tex]

⇒ [tex]A= \frac{2\pi}{-2} [{e^{-2(\infty)}-e^{-2(0)} } \,]\\[/tex]

⇒ [tex]A= -\pi [0-1} \,]\\[/tex]

⇒ [tex]A= \pi[/tex]

Hence we can conclude that the area of the resulting surface is π units.

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the petrol cost for the trip is:

C = 2.125*$2.05 = $4.36

After a search online, I've found that the trip is of 25km.

Here we know that the car uses 8.5L per 100km, then in 25 km, the car will use one-fourth of 8.5L, that is:

8.5L/4 = 2.125L

So the volume of petrol that the car uses for the trio is 2.125 liters of petrol.

And each liter costs $2.05, then the petrol cost for the trip is given by the product between the total volume of petrol consumed and the cost per liter.

C = 2.125*$2.05 = $4.36

Thus, we conclude that the petrol cost for the trip is 4.36 dollars.

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The solutions for the given system are (3,2), (3,-2), (-3,2) and (-3,-2).

The quadratic function can represent a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.

The solution of these equations represents the points at which the parabolas intersect.

2x²+8y²=50 (1)

x²  + y²= 13 (2)

Multiplying the equation 2 by -2, you have:

2x²+8y²=50 (1)

-2x² -2 y²= -26(2)

Sum both equations, you have: 6y²= 24. Now, you can find y.

6y²= 24

y²=4

y=±2

If y=2, from equation 2, you have

x²  + y²= 13

x²  + 2²= 13

x²  + 4= 13

x² =13-4

x² =9

x=±3

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The double integral. 7x cos(y) da, d is bounded by y = 0, y = x2, x = 7 d is given as

[tex]\int _D 7xcosydA =7/2(-cos49+1)[/tex]

Generally, the equation for is  mathematically given as

The area denoted by the letter D that is bordered by y=0, y=x2, and x=7

The equation for the X-axis is y=0.

y=x² ---> (y-0) = (x-0)²

Therefore, the equation of a parabola is y = x2, and the vertex of the parabola is located at the point (0,0), and the axis of the parabola is parallel to the Y axis.

The equation for a straight line that is parallel to the Y-axis and passes through the point (7,0) is x=7.

[tex]\int _D 7xcosydA\\\\\int^7_0 \int^x^2 _0 7xcosydA[/tex]

Integrating we have

[tex]7/2 \int^7_0 (2xsinx^2)dx[/tex]

If x equals zero, then we know that u equals zero as well.

When x equals seven, we know that u=72=49.

Therefore, by changing x2=u into our integral, it becomes from

 [tex]7/2 \int^7_0 (2xsinx^2)dx[/tex]

[tex]7/2 \int^49_0 sin u dx[/tex]

Hence

=7/2(-cos49+1)

In conclusion,

[tex]\int _D 7xcosydA =7/2(-cos49+1)[/tex]

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Answer: d. 40 pounds

Step-by-step explanation: let e equal the number of pounds weigh on Earth and m equal the number of pounds weighs on Mars.

so

72m=180e

1m= 72m/72

e= 180/72 = 2.5

1m=2.5e

16m=1 x16

e= 16 x 2.5

e= 40

so therefore, 16m=40e

I hope this helps

The solution to the given differential equation is yp=−14xcos(2x)

The characteristic equation for this differential equation is:

P(s)=s2+4

The roots of the characteristic equation are:

s=±2i

Therefore, the homogeneous solution is:

yh=c1sin(2x)+c2cos(2x)

Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:

yp=Axsin(2x)+Bxcos(2x)

If you take the second derivative of the equation above for  yp , and then substitute that result,  y′′p , along with equation for  yp  above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side,  sin(2x) , you will find:

A=0

B=−14

Therefore,

yp=−14xcos(2x)

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Answer:

First:

5x + 9 < 2

x= 9/5= 1,8 < 2

Second:

x + 6 < 12

x= 12/6= 2 < 12

The probability distribution of X when X~B(1,1/25) is (Option A)

See the explanation below.

Given X~B(n,p)

P(x=1) = C¹ₙ * P¹ * (1-P)ⁿ⁻¹ (n≥1)

Thus, X~B [1, 1/25]

1/25 = 0.04

hence, p(x=0)

= C⁰₁ * 0.04⁰ (1 - 0.04)¹

= 0.96

P (x=1)

=  C¹₁ 0.04¹ (1-0.04)⁰

= 0.04

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Answer: 0.032, 18, 4224, 7.58

Step-by-step explanation:

5. 5 L = 5000 mL = 5000 [tex]cm^{3}[/tex]

5000/(6*6*6) = 23 r 32 so 5 L of water can fill up 23 cubic tanks length 6 cm and is left with 0.032 L

6. There is (13 - 11) x 20 x 10 = 400 [tex]cm^{3}[/tex] left unoccupied in the box

400/23 = 17.4 so it takes 18 balls to overflow the water

7. 1 mL = 1 [tex]cm^{3}[/tex]

(a) 22 x 12 x 16 = 4224 [tex]cm^{3}[/tex] = 4224 mL

(b) 2 L = 2000 mL = 2000 [tex]cm^{3}[/tex]

22 x 12 = 264

2000/264 = 7.58 cm

Answer:

600 and 200

Step-by-step explanation:

kofi  : kweku     is   3 :1

   so Kofi gets   3 out of ( 3 +1)  = 3/4 of 800  = 3/4 * 800 = 600

         kweku get s the rest   800- 600 = 200  

The value of the functions f(x) and g(x) will be √(4x + 3) and √2. Then the correct option is B.

A statement, principle, or policy that creates the link between two variables is known as a function. Functions are found all across mathematics and are required for the creation of complex relationships.

If (f g)(x) = h(x) such that h(x) = √(8x + 6). Then we have

(f g)(x) = h(x)

f(x) · g(x) = h(x)

Then put the value of h(x), then we have

f(x) · g(x) = √(8x + 6)

f(x) · g(x) = √2(4x + 3)

f(x) · g(x) = √(4x + 3) × √2

Thus, the value of the functions f(x) and g(x) will be √(4x + 3) and √2.

Then the correct option is B.

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The probability of drawing a red card from a standard deck of cards is 1/2.

Given that there is a standard deck of cards.

We are required to find the probability of drawing a rd card from a standard deck of cards.

Probability is the calculation of chance of happening an event among all the events possible. It lies between 0 and 1. It cannot be negative.

Probability=Number of items/Total items.

Total number of cards=52

Number of red cards =26

Number of black cards=26

Probability of drawing a red card =Number of red cards/ Total cards.

=26/52

=1/2

Hence the probability of drawing a red card from a standard deck of cards is 1/2.

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