The proof of third equation of motion is determined as v² = 2as + u².
What is the proof of third equation of motion?
The proof of third equation of motion is determined as follows;
The first equation is given as;
v = u + at
t = ( v - u ) /a
where;
u is the initial velocitya is the accelerationt is the time of motionThe formula for the average distance traveled by an object is;
s = (v + u)/2 x t
Expand the equation above as;
s = (v + u)/2 x (v - u)/a
s = (v² - u²) / 2a
2as = v² - u²
v² = 2as + u², proved
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as a car skids to a stop, friction transforms kinetic energy to
Answer:
potential energy
Explanation:
What is the magnitude of the gravitational force acting on the car?
A) 14700N
B)13690N
C)5800N
D)775N
The magnitude of the gravitational force acting on the car is 14700 N.
What is gravitational force?In mechanics, gravity, often known as gravitation, is the force of attraction that acts on all matter. It has little impact on determining the intrinsic characteristics of common stuff because it is by far the weakest known force in nature.
In contrast, it governs the formations and evolution of stars, galaxies, and the entire cosmos by its extensive and ubiquitous action, which affects the trajectories of objects in the solar system and beyond the universe.
In this free body diagram: 14700 N force acting downwards due to its weight. Hence, it is the magnitude of the gravitational force acting on the car.
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1. How far away will a ball land when thrown from a hill 70 m high at a 45 angle from the horizontal at an initial velocity of 9 m/s?
2. How long will it take for the ball in problem 1 to fall to the ground? Remember the pull of gravity is (-9.8 m/s)
3. What is the maximum height reached by the object?
Answer:
[tex]28.53\ \text{m}[/tex]
[tex]4.48\ \text{s}[/tex]
[tex]72.1\ \text{m}[/tex]
Explanation:
[tex]y_0[/tex] = Height from where the ball is thrown = [tex]70\ \text{m}[/tex]
[tex]\theta[/tex] = Angle of inclination = [tex]45^{\circ}[/tex]
[tex]u[/tex] = Initial velocity = [tex]9\ \text{m/s}[/tex]
[tex]g[/tex] = Acceleration due to gravity = [tex]9.8\ \text{m/s}^2[/tex]
Range of projectile is given by
[tex]R=\dfrac{u\cos \theta }{g}\left(u\sin \theta +{\sqrt{u^{2}\sin ^{2}\theta +2gy_{0}}}\right)\\\Rightarrow R=\dfrac{9\cos45^{\circ}}{9.8}\left(9\sin45^{\circ}+\sqrt{9^2\left(\sin45^{\circ}\right)^2+2\times 9.8\times 70}\right)\\\Rightarrow R=28.53\ \text{m}[/tex]
The ball will land [tex]28.53\ \text{m}[/tex] away.
Time of flight is given by
[tex]t=\dfrac{u\sin \theta +{\sqrt{(u\sin \theta )^{2}+2gy_{0}}}}{g}\\\Rightarrow t=\dfrac{9\sin 45^{\circ} +{\sqrt{(9\sin 45^{\circ} )^{2}+2\times 9.8\times 70}}}{9.8}\\\Rightarrow t=4.48\ \text{s}[/tex]
The time the ball will stay in the air is [tex]4.48\ \text{s}[/tex]
Maximum height is given by
[tex]h=y_0+\dfrac{u^2\sin^2\theta}{2g}\\\Rightarrow h=70+\dfrac{9^2\times \sin^245^{\circ}}{2\times 9.8}\\\Rightarrow h=72.1\ \text{m}[/tex]
Maximum height the object will reach above the ground is [tex]72.1\ \text{m}[/tex].
please help me with this question asap
PLEASE HURRY AND HELP
What is the correct unit for acceleration?
A. m
B. m/s
C. m/s2
12. A train is traveling away from you at a constant speed.
What would a distance-time graph look like for this train?
Answer:
b
Explanation:because think about it its going straight so you have to coiunt the miles the train is going and boom your answer is b
Answer:
It would be choice b
Explanation:
speed is constant so they value won't change, on the other hand time is always going.
A boy starts jogging with a speed of 4.0 m/s and
reaches a speed of 5.0 m/s after covering a distance
of 9 m. What is the boy's acceleration?
Answer:
acceleration=0.111 m/s²
Explanation:
acceleration = change in velocity/time taken
1/9=0.1111
acceleration=0.111 m/s²
what is the properties of polarization
Answer:
Explanation:
The polarization characteristics depend on the shape, size, and optical properties of the surface particles. Generally, the radiation is linearly polarized and is said to be negatively polarized if it lies in the scattering plane and positively polarized if it is perpendicular to the scattering plane.
HEY CAN ANYONE ANSWER DIS RQ PLS!!!!
Answer:
scale and balance
Explanation:
Answer:
scale and balance
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In a complete description of a force vector, which is usually not necessary?
Answer:
Position
Explanation:
A force vector has both magnitude and direction, which can be represented by a line with an arrow head. The length of the line describes magnitude, while the arrows points in the required direction.
generally, the position of a vector is unimportant when describing the vector. Thus, when a force vector is to be described, it is unnecessary to make reference to its original position. Majorly, its magnitude and direction is considered.
difference between
Atmospheric pressure and Liquid pressure.
Answer:
one is Atmospheric and one is a Liquid
Explanation:
CORRECT ANSWER GETS BRANLIEST PLZ HELP
1. What is the velocity of a car that traveled a total of 85 km South in 5 hours?
2. A plane traveled 3000 miles from New York to Los Angeles in 5 hours. What is the plane’s
velocity?
Answer:
I think 1. is 17 and 2. is 600
Explanation:
sorry its been a while..
if Sarah melts 10g of tin. What mass of melted tin would she have at the end of the experiment?
Answer:
10g
Explanation:
As the Law of Conservation of Mass states that " Mass can neither be created nor be destroyed in a chemical reaction".
Though melting of tin isn't a chemical change, the same logic is applied here...
Hence,
The mass of tin will be 10 g itself...
Answer:
10g
Explanation:
The experiment is about melting of tin. When solid tin is melted, it retains the amount of substance it originally has and we expect it to still be 10g.
Mass is the quantity or amount of matter contained in a substance. For most chemical processes, the law of conservation of matter is always succinctly observed.
The law states that "matter is neither created nor destroyed in a chemical reaction or process". Although melting is a phase change, we can adapt this law to the process. Owning to no loss of matter in the melting procedure, the amount of substance remains the same.
Therefore, we are left with about the same mass of substance we started with which is 10g.
A ball is thrown straight upward and returns to the thrower's hand after 3 seconds in the air. A second ball is thrown at an angle of 30 degrees with the horizontal. At what speed (remember that this is the resultant magnitude of the vertical and horizontal speeds) must the second ball be thrown so that it reaches the same height as the one thrown vertically?
Explanation:
Given that the first ball is thrown vertically and upward.
since it reaches the throwers hand after 3 seconds, then the time taken to reach maximum height is
= T/2
=3/2
=1.5 seconds
Also, the projection angle for the second ball is 30°
we know that at maximum height vertical velocity is 0
therefore the final velocity of the first ball is
Vy= 0
Also, since the first ball is thrown upward the horizontal velocity is 0
Vx=0
from the first law of motion
Vy=u+at
Vy=0, a= -g
Uy=gt
Uy=9.81*1.5
Uy=14.7m/s
since both reach the same height, they will have the same vertical velocity
Uy= Vo sin∅
Vo=Uy/sin∅
Vo= 14.7/sin 30
Vo=29.4m/s
For objects in free-fall, what is the relationship between an object's mass and its acceleration
Answer:
the objects mass is independent of its acceleration in free fall
The acceleration of the object equals the gravitational acceleration. The mass, size, and shape of the object are not a factor in describing the motion of the object. So all objects, regardless of size or shape or weight, free fall with the same acceleration.
During an ,
experiment, a siginal from a spaceship
reached the ground station in five minutes. What was the
distance of
the spaceship from
the ground station? The
signal travels at the speed of light, that is 3x 109 ms‐1
Answer:
1.5*10^9
Explanation:
distance =V x T
=3x10^8x5
=1.5*10^9
A handball is hit toward a wall with a velocity of 14.3 m/s in the forward direction. It returns with a velocity of 13.5 m/s in the backward direction. If the time interval during which the ball is accelerated is 0.011 s, what is the handball's average acceleration?
Answer:
Let's define t = 0 as the moment when the ball hits the wall.
in this moment, we have a given acceleration, but if we only want to calculate the average acceleration, then let's consider the acceleration constant.
a(t) = A.
To find the velocity equation we should integrate, and the constant of integration will be the initial velocity, in this case, is 14.3m/s.
v(t) = A*t + 14.3m/s
Now we know that at t = 0.011s, the velocity is -13.5m/s (the sign is negative because the ball is moving in the opposite direction as before).
Then we can solve the equation:
v(0.011s) = -13.5m/s = A*0.011s + 14.3m/s
Now we can solve it for A, the average acceleration:
-13.5m/s - 14.3m/s = A*0.011s
(-27.8m/s)/0.011s = A = -1313.5 m/s^2
4. An object is thrown vertically upward with a speed of 25 m/s. How much time passes before it
comes back down at 15 m/s? (Air resistance is negligible.)
a. 1.0 S
d. 18 s
b. 4.1 s
e. 27 s
c. 9.85
Can you also explain how you got the answer please?
Answer:
Option b is correct: 4.1 s
Explanation:
Vertical Launch
An object launched thrown vertically upward where air resistance is negligible, reaches its maximum height in a time t, given by the equation:
[tex]\displaystyle t=\frac{v_o}{g}\qquad\qquad[1][/tex]
Where vo is the initial speed and g is the acceleration of gravity g=9.8 [tex]m/s^2[/tex].
Once the object reaches that point, it starts a free-fall motion, whose speed is (downward) given by:
[tex]v_f=g.t\qquad\qquad[2][/tex]
The object considered in the question is thrown with vo=25 m/s. The time taken to reach the maximum height is given by [1]:
[tex]\displaystyle t=\frac{25}{9.8}=2.551\ sec[/tex]
The object starts its falling motion and at some time, it has a speed of vf=15 m/s. Let's find the time by solving [2] for t:
[tex]\displaystyle t=\frac{15}{9.8}=1.531\ sec[/tex]
The total time taken by the object to go up and down is
[tex]t_t=2.551\ s+1.531\ s=4.081\ s[/tex]
a. This option is incorrect because it's far away from the answer.
d. This option is incorrect because it's far away from the answer.
b. This option is correct because it's a good approximation to the calculated answer.
e. This option is incorrect because it's far away from the answer.
c. This option is incorrect because it's far away from the answer.
1.)what is the acceleration of a ball with a mass of 0.40 kg is hit with a force of 16N
Answer:
a = 40 [m/s^2]
Explanation:
This problem can be solved using Newton's second law which tells us that the sum of forces acting on a body must be equal to the product of mass by acceleration.
F = m*a
where:
m = mass = 0.4 [kg]
F = force = 16 [N]
a = acceleration [m/s^2]
Now replacing we have:
16 = 0.4*a
a = 40 [m/s^2]
Which has more momentum, a 2.0 kg dog at 41 m/s or a 75 kg pony at 1.0 m/s?
Answer:
The dog has more momentum than the pony.
Explanation:
To solve this problem, we must remember the formula for calculating momentum, which is given below:
momentum = p = m*v
where m represents the mass of the object and v represents the velocity of the object
Using this knowledge, let's calculate the momentum for the dog and the pony.
Dog: p = m*v = (2kg)*(41 m/s) = 82 kg*m/s
Pony: p = m*v = (75kg)*(1 m/s) = 75 kg*m/s
Since 82 > 75, we can conclude that the dog has more momentum.
Hope this helps!
A car accelerates from 6.0 m/s to 18 m/s at a rate of 3.0 m/s^2. How far does it travel while accelerating?
A. 82m
B. 29m
C. 48m
D. 144m
Answer:
48
Explanation:
we know that
v^2=u^2+2as
18^2=6^2+2*3s
324=36+6s
6s=324-36
6s=288
s=48
plz markbas brainalist
A tennis ball is dropped from 1.77 m above
the ground. It rebounds to a height of 1.05 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s2. (Let
down be negative.)
Answer in units of m/s.
Answer:
5.89 m/s
Explanation:
Given:
Δy = 1.77 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (9.8 m/s²) (1.77 m)
v = 5.89 m/s
A trainer is training a horse for the Kentucky Derby. The trainer knows the horse needs to have an opening acceleration of 10 m/s^2. If the horse has a mass of 450 kilograms, how much force will the horse need to produce to reach the needed acceleration?
2500 N
4500 N
3500 N
3000 N
Answer:
4500 N
Explanation:
Acceleration = 10 m/s²
Mass = 450 kilograms
Force = ?
[tex]force \: = mass \times acceleration \: \\ force \: = 450 \times 10 \\ force = 450[/tex]
Force = 450 Newton
A5 kg football is launched 45 degrees above the horizontal at a speed of 26 m/s.
What is the time of flight for the football from the point it left the ground until it hit the ground?
PLEASE HELP AND HURRY
At what point will the vertical component of the balls velocity be the smallest?
A. point x
B. point y
C. point z
D. not enough information
Answer:
I believe your answer would be B. point y
What is the momentum of a baseball with a mass of 4 kg being thrown at a velocity of 84 m/s towards the hitter
Answer:
The answer is 336 kgm/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocityFrom the question
mass = 4 kg
velocity = 84 m/s
We have
momentum = 4 × 84
We have the final answer as
336 kgm/sHope this helps you
which part of the central nervous system controls reflexes?
a. cerebrum
b. cerebellum
c. brain
d. spinal cord
Answer:
spinal cord becuse it does all of the reflexes
Answer:
none of these
Explanation:
what actually controlls reflexes is the brain stem
who makes the first atomic bomb?
Answer:
Robert Oppenheimer made the first atomic bomb.
Silvia rides her bike 2.7km to school. After school, she rides an additional 1.3 km to the mall in the opposite direction. What is her total distance traveled?
Answer:
4.0 km
Explanation:
Total distance traveled doesn't care about direction:
Total distance traveled = 2.7km + 1.3 km = 4.0 km
The temperature of a sample of iron with a mass of 10.0 g changed
from 50.4°C to 25.0°C with the release of 114.3 J of heat. What is the
specific heat of iron
Answer:
Q = mc(θ₂-θ₁)
47 calories = 10 g *c*(50.4 - 25)
47cal = 10*c* 25.4
47 /(10*25.4) = c
0.185 = c
Specific heat of iron = 0.185 cal/g°C
Explanation:
