The electric field should be applied is 3,694.5 .
As we know from electromagnetic theory we have a relation with electric field and magnetic field with force, which is
F = qE + qv x B
or we can write that
F = qE + qvBsinФ
To allow proton to move with the constant speed, we need to apply zero external force
It means F = 0
or we can write that
qE = -qvBsinФ
putting the appropriate values, we get
E = 4105 x 0.9
E = 3,694.5
Hence the magnitude of the electric field is 3,694.5 .
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When a solid becomes a liquid, the particles
slip and slide past each other
are vibrating
are in a lattice structure
bounce off each other
solid particles vibrate and slip past each other when they become liquid.
a playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.350 rev/s. what is its angular velocity (in rev/s) after a 15.0 kg child gets onto it by grabbing its outer edge? the child is initially at rest.
Angular velocity (in rev/s) after a 15.0 kg child gets onto it by grabbing its outer edge is 1.575 rad/s.
The angular velocity of the merry-go-round after a child gets on it is equal to the angular velocity of the child plus the angular velocity of the merry-go-round.
The angular velocity of a rotating object can be calculated using a formula:
ω = ω + (m/r)
where ω is the original angular velocity, m is the mass of an object that's been added to it, r is its radius, and (m/r) is the change in mass divided by its radius. When we plug in our values for this problem, we get:
ω = 0.350 rad/s + ((15 kg)/(1.8 m)) rad/s
= 0.350 rad/s + 1.25 rad/s
= 1.575 rad/s
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monochromatic light from a distant source is incident on a slit 0.75 mm wide. on screen 2 m away, the distance from the central maximum of the diffraction pattern to the first minimum is measured to be 1.35 mm. find the wavelength of the light.
Displacement from the center line for minimum intensity is 1.35 mm , width of the slit is 0.75 so Wavelength of the light is 506.25.
How to find Wavelength of the light?When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.
This is a straightforward situation in which we can apply the
Fraunhofer single slit diffraction equation:
y = mλD/a
Where:
y = Displacement from the center line for minimum intensity = 1.35 mm
λ = wavelength of the light.
D = distance
a = width of the slit = 0.75
m = order number = 1
Solving for λ
λ = y + a/ mD
Changing the information that the issue has provided:
λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2
=5.0625 *10^-7 = 506.25
so
Wavelength of the light 506.25.
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a solid sphere has a radius of 0.200 m and a mass of 150 kg. how much work is required to get the sphere rolling with an angular speed of 50.0 rad/s on a horizontal surface? assume the sphere starts from rest and rolls witho
Work done on sphere is 10500 J.
Kinetic energy = 1/2 [tex]iw^{2}[/tex] + 1/2 [tex]m v^{2}[/tex]
I = 2/5 [tex]m R^{2}[/tex]
w = [tex]\frac{v}{r}[/tex]
Now, put these values in formula KE = 1/2 [tex]iw^{2}[/tex] + 1/2 [tex]m v^{2}[/tex]
KE = 10500 J
Now, by work energy theorem
Work done = 10500 - 0 = 10500 J
Hence, Work done on sphere is 10500 J.
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how is cmb observed from earth
The Cosmic Microwave Background radiation, or CMB for squat, is a faint glow of light that fills the universe, falling on Earth from each direction with nearly uniform intensity.
How does CMB observe Earth?The CMB represents the heat leftover from the Big Bang. You can't see the CMB with your bare eye, but it is everywhere in the universe. It is unseen to humans because it is so cold, just 2.725 degrees above total zero. Planck mapped out the warp in the CMB due to gravitational lensing caused by dark matter's existence. The CMB materialized as an electromagnetic fog on optical telescopes and as a static hum on radio telescopes. The CMB will certainly emerge slightly different from any distant galaxy,
So we can conclude that The Cosmic Microwave Background (CMB) is the cooled remains of the first light that could ever travel freely throughout the Universe.
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lorry is moving with a uniform acceleration of 1.5ms2 .at a certain time it is travelling at a spedd of 6ms .calculate the speed of the lorry 4s later
The speed of the lorry 4 seconds later, given it was moving with uniform acceleration of 1.5 m/s² is 12 m/s
How do I determine the final speed of the lorry?We'll begin by listing out the various parameters obtained from the question. This is shown below:
Acceleration (a) = 1.5 m/s²Initial speed (u) = 6 m/sTime (t) = 4 secondsFinal speed (v) =?The final speed of the lorry can be obtained as follow:
a = (v - u) / t
1.5 = (v - 6) / 4
Cross multiply
v - 6 = 1.5 × 4
v - 6 = 6
Collect like terms
v = 6 + 6
v = 12 m/s
Thus, from the calculation made above, the final speed of the lorry is 12 m/s
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Salem, Sabrina’s magical black cat, gets scared and jumps straight upward with an initial velocity of 20 m/s from a height of 115-meters.
Draw a velocity vs time graph to describe the cat’s motion for the first five seconds of motion.
What is the cat’s velocity and acceleration at it’s maximum height?
What is the cat’s velocity when it hits the ground?
How long does it take for the cat to hit the ground?
PLS HELP!!!!!
Considering a quadratic equation to model the height of the car, we have that:
The graph is given at the end of the answer.At the maximum height, the velocity is of zero and the acceleration is of -9.8 m/s².The velocity when the cat hits the ground is: -51.54 m/s.It takes 7.30 seconds for the cat to hit the ground.What is the quadratic equation for a projectile's height?Considering an acceleration = gravity of -9.8m/s², the equation for the height is given as follows:
h(t) = -4.9t² + v(0)t + h(0).
In which:
v(0) is the initial speed.h(0) is the initial height.Considering the values of these parameters for this problem, of v(0) = 20, h(0) = 115, the equation is:
h(t) = -4.9t² + 20t + 115.
At the maximum height point, we have that:
The velocity is of zero. (standard)The acceleration if of -9.8 m/s². (standard).The velocity function is:
v(t) = v(0) - gt
v(t) = 20 - 9.8t.
Which is the linear function graphed at the end of the answer.
The cat hits the ground at t > 0 for which h(t) = 0, hence:
-4.9t² + 20t + 115 = 0.
Which is a quadratic equation with coefficients given by:
a = -4.9, b = 20, c = 115.
Using a calculator, the positive solution for this equation is:
t = 7.30s.
At this instant, the velocity is:
v(t) = 20 - 9.8(7.3) = -51.54 m/s.
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if you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out because an outward force balances the pull of gravity on the water. if you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out because an outward force balances the pull of gravity on the water. true false
We must understand both inertia and gravity to find a solution.
What is inertia?
The matter has an attribute called inertia that makes it resist changes in velocity (speed and direction). Newton's first law of motion states that an object moving at a certain speed will stay there unless an outside force acts upon it.
What is gravity?
A planet or other body's gravitational field pulls objects toward its center. The force of gravity is what keeps every planet in its orbit around the sun.
A vertical circle spun while holding a bucket full of water prevents the water from spilling out due to inertia.
Keep the bucket in place as the water tries to fly off.
Therefore we can conclude that it is false.
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two wheels, a and b, are both shaped like uniform disks and have the same overall mass, but wheel a has twice the radius of wheel b. how do we calculate the moments of inertia (around the axis of symmetry) for each wheel?
The ratio of I sub A to I sub B is 4.
How can you calculate the ratio of A to B?
A/B would be your formula if you were comparing one data point (A) to another data point (B). This indicates that you are multiplying information A by information B. For instance, your ratio will be 5/10 if A is 5 and B is 10. How do we determine each wheel's moments of inertia (around the axis of symmetry) I is equal to 1 over 2 times m times R squared is used to compute the moments of inertia for both masses and radii. We simply use a common factor to cancel. So 4:2=2:1 . The simplest representation of the ratio 4 to 2 is the ratio 2 to 1. Additionally, since each pair of numbers has the same relationship, the ratios are equivalent.
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a 500.0 kg elevator is pulled upward with a constant force of 5500.0 n for a distance of 50.0 m. what is the work done by the 5500.0 n force on the elevator?
The work done by the constant force to pulled the elevator upward is 275000 Joules.
The work done by any force is given by,
W = Fa
Where,
W is the work done,
F is the force applied,
s is the displacement along the direction of the force,
The force applied on the elevator to pull it upward is 5500N and the distance to which the elevator is pulled is 50 m.
Now, putting values,
W = 5500(50)
W = 275000 Joules.
So, the work done by the force to pull the elevator upward is 275000 Joules.
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transient heat conduction in a semi-infinite solid the appropriate to use instead of the infinite solid?
The semi-infinite body shall be considered as a system that is bounded by one surface and that extends to infinity in other directions.
What is transient heat conduction?Transient conduction is the term for the mechanism of thermal energy transport when temperatures fluctuate over time at any location within an object. Another term for the time-dependent temperature fields in an item is "non-steady-state" conduction.A solid that extends to infinity in all but one direction and has a single plane surface is said to be semi-infinite. This surface will experience brief one-dimensional conduction if a rapid alteration is applied to it.The temperature remains constant over the course of steady-state heat transmission. The temperature fluctuates over time during transient heat transfer.Temperatures are mostly unaffected by changes in surface conditions in the early stages of the transient.To learn more about transient heat conduction refer to:
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Gravity obeys an inverse square relation. This statement implies that the force due to gravity betweentwo massesa.will increase as the distance between the two masses increases.*b.will decrease as the square of the distance between the two masses increases.c.will cause the two masses to move away from each other.d.will cause the two masses to move in a straight line.e.will cause the two masses to orbit each other.
The inverse square relation implies that force resulting from gravity between two masses will decrease as the square of the distance between the two masses increases.
The force of gravity between any two objects is given by,
F = GM₁M₂/R²
Where,
M₁ and M₂ are the masses of the bodies.
R is the distance between them.
We know, if the masses are constant. then the force of gravity will be inversely proportional to the square of the distance between them.
This is what inverse square relation means here.
As the force of gravity and the square of the distance are inversely proportional to each other,
So, when the square of the distance between the masses increases, the force of gravity between the decreases.
Hence of all the options provided, b is the correc0,t which says, the force will decrease on increasing the inverse square of the distance.
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a lighthouse is located on a small island 5 km away from the nearest point p on a straight shoreline and its light makes eight revolutions per minute. how fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from p? (round your answer to one decimal place.)
The movement of the beam of light is an illustration of distance and rates
The beam of light along the shoreline is moving at 261.5 km per minute when it is 1 km from P
What is rate of change of distance?The ratio of the distance traveled to the time required is used to compute average speed, which is the rate at which distance changes in relation to time.
[tex]\frac{d\theta}{dt}[/tex] = 8 rev min⁻¹ = 16 [tex]\pi[/tex] rad min⁻¹
tan [tex]\theta[/tex] = [tex]\frac{x}{5}[/tex]
Differentiate both sides with respect to t
[tex]sec^2 (\theta) \frac{d\theta}{dt} = \frac{1}{5} \frac{dx}{dt}[/tex]
[tex]\frac{d\theta}{dt}[/tex] = 16 [tex]\pi[/tex]
Then,
[tex]\frac{dx}{dt}[/tex] = [tex]sec^2 (\theta) X 80\pi[/tex]
From the question, x = 1. calculate the hypotenuse (h) side of the triangle, using the following Pythagoras theorem.
[tex]h^2 = 1+ 5^2\\[/tex]
h =[tex]\sqrt{26}[/tex]
sec ([tex]\theta[/tex]) = [tex]\frac{\sqrt{26} }{5}[/tex]
Substitute sec ([tex]\theta[/tex]) = [tex]\frac{\sqrt{26} }{5}[/tex] in [tex]\frac{dx}{dt}[/tex] = [tex]sec^2 (\theta) X 80\pi[/tex].
[tex]\frac{dx}{dt} = (\frac{\sqrt{26} }{5} )^2 . 80\pi[/tex]
= 83.2 [tex]\pi[/tex] = 261.48
Hence, the beam of light along the shoreline is moving at 261.5 km per minute when it is 1 km from P.
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Substances in a(n)________
separate properties.
keep their separate properties, but in a(n)___________
the parts are bonded and do not keep their
Substances in a mixture keep their separate properties, but in a compound the parts are bonded and do not keep their separate properties.
Mixtures contains elements and compounds without any fixed ratio and not by any means of chemical bonds. The elements and compounds are physically mixed and so they will be visibly distinct.
Compounds contains elements in a fixed ratio and is connected by chemical bonds. They only contain one type of molecule. Since they are chemically combined the particles appear as one and is not visibly distinct.
Therefore, substances in a mixture keep their separate properties, but in a compound the parts are bonded and do not keep their separate properties.
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a spring with an m-kg mass and a damping constant 10 (kg/s) can be held stretched 1.5 meters beyond its natural length by a force of 3 newtons. if the spring is stretched 3 meters beyond its equilibrium position and then released with zero velocity, find the mass that would produce critical damping.
12.5kg is the mass that would result in critical damping.
Define the damping constant and determine it using the force or displacement equation provided.The ability of a damper to resist motion is shown by its damping coefficient, which measures the effectiveness of the damper. where c is the damping coefficient and is expressed in newton seconds per meter.
The damping coefficient is a term that has the formula where is a constant. This damping is equivalent to the kind of motion resistance and energy loss experienced when a piston with perforations is moved through a cylinder filled with a viscous fluid, like oil.
Force F = Kx
K = F/x
K = 3/1.5
K = 2N/m.
c² - 4mk = 0
m = c²/4k
m = 10²/4×2
m = 100/8
m = 12.5kg.
12.5kg is the mass that would result in critical damping.
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the moon orbits earth at an average distance of 3.84 x 108 m in a path that takes 27.3 days to complete. what is the centripetal acceleration of the moon? (remember, you must convert time into seconds.)
If the moon orbits the Earth at a distance of 3.84 x 10⁸ on a path that takes 27.3 days to complete, its centripetal acceleration will be 2.7x 10⁻³ m/s².
How can we determine the centripetal speed of the moon?A body moving in a circular path at a high rate of speed is said to be experiencing centripetal acceleration. We can calculate the moon's centripetal acceleration using the centripetal acceleration formula.
We are informed that the moon is approximately 3.84 x 10⁸ miles away from Earth and that a full rotation of the moon takes 27.3 days.
The distance traveled by the moon in 27.3 days is its velocity.
v = x/t
v = 2 πr/t
v = 2.41x10⁹/2.35x10⁶
v = 1025.5
The radius is 3.84 x 108 m and the velocity is 1,025.5 m/s. Here, we will determine the centripetal acceleration of the moon.
[tex]a_{c}[/tex] = v²/r
[tex]a_{c}[/tex] = (1025.5)²/3.84 x 10⁸
[tex]a_{c}[/tex] = 2.7 x 10⁻³
We now know the centripetal acceleration of the moon to be 2.7 103 m/s².
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A student travels on a motorcycle and moves at a constant speed of 80 k/h for 15 m, determine the distance traveled in that time
Uniform line movement
Data:
V = 80km/h
T = 15m = 0.25 h
d = ?
We perform a conversion from minutes to hours.
15 m * 1 h/60 m = 0.25 h
The formula for uniform motion is:
V = d/t
We clear for distance:
d = v * t
d = 80 km/h * 0.25 h
d = 20 km
The distance traveled in that time is 20 km.
what initial speed should a particle be given if it is to have a final speed when it is very far from the earth that it is equal to one half of esdcape verlodctyu
The initial speed of the particle is 15.83 km/s.
Consider a system having initial potential energy. With time as the system proceed, the potential energy gets converted to kinetic energy. The kinetic and potential energy changes individually, but the total energy is constant at every instant. This is known as the conservation of energy.
Escape velocity , v = 11.200 km/s
The radius of the earth, R = 6400 km
Let the mass of the particle be m.
Let the mass of Earth be by M.
Let the velocity of the particle be v.
By conservation of energy we have,
(1 ÷ 2)mv² - ((GMm) ÷ R) = (1 ÷ 2)m[tex]v_{e}^{2}[/tex]
where G is the gravitational constant.
The gravitational constant and the acceleration due to gravity is related:
g = GM ÷ R²
Thus equation (1 ÷ 2)mv² - ((GMm) ÷ R) = (1 ÷ 2)m[tex]v_{e}^{2}[/tex] becomes,
(1 ÷ 2)v² - gR = (1 ÷ 2)[tex]v_{e}^{2}[/tex]
v² - 2gR = [tex]v_{e}^{2}[/tex]
v² − 2 × 9.8 × [tex]10^{-3}[/tex] km/s² × 6400 km = (11.200km/s)²
v = 15.83km/s
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The question is -
What initial speed would a particle need to be given at the surface of Earth if it is to have a final speed that is equal to its escape speed when it is very far from Earth? Neglect any effects due to air resistance?
Dr. Amari is investigating whether automobile accidents in her city increase, decrease, or stay the same 24 hours after daylight savings (this is when the time changes to one hour earlier). She looks up public records at the police station and documents any accidents and notes the dates and times.
Dr. Amari discovers a trend. She finds that accidents do seem to increase right after clocks are reset to an hour earlier.
Which one of the following research techniques is Dr. Amari using?
A. naturalistic observational research
B. archival research
C. experimental research
D. survey research
Since Dr. Amari finds that accidents do seem to increase right after clocks are reset to an hour earlier. The research techniques that Dr. Amari using is B. archival research.
What is archival research?Archival research is any investigation that looks for, locates, and extracts data and proof from original archives. Archives are documents, records, and other sources pertaining to the actions and claims of people, groups, or both that are historical and not current.
Note that The term "data collection techniques" refers to procedures for gathering and analyzing various types of data. Examining papers pertaining to a topic, as well as conducting interviews and observations, are common methods of gathering data.
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ssm a warehouse worker exerts a constant horizontal force of magnitude 85 n on a 40 kg box that is initially at rest on the horizontal floor of the warehouse. when the box has moved a distance of 1.4 m, its speed is 1.0 m/s. what is the coefficient of kinetic friction between the box and the floor?
The coefficient of the kinetic friction between the box and the floor is μk 0.21.
Friction is the force resisting the relative motion of strong surfaces, fluid layers, and fabric elements sliding against every different. There are several sorts of friction: Dry friction is a pressure that opposes the relative lateral movement of two solid surfaces in touch.
Calculation:-
Given,
mass = 40 Kg
Applied force F = 85 N
initial velocity u = 0 (rest)
distance moved = 1.4 meter
Final velocity = 1 m/s
coefficient of kinetic friction =?
Normal force = N = mg = 400 N
v² = u² +2as
a = v²/2s
= 1/2×1.4
= 0.36 m/s²
F = μkN
μk = F/N
= 85/400
0.21
Friction is a shape of touch pressure. It exists between the surfaces which are in touch. The frictional force relies upon on the person of the surface in contact. The rougher the floor, the greater the friction is involved. The frictional force is proportional to the urgent pressure, this is the weight of the body. it's far impartial of the place of the touch.
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which answer would you choose if the rocks fall out through a hole in the floor of the car, one at a time?
The car speeds remains constant.
Using the following equation for momentum:
Pi=Pf
(c=car and r=rock)
McVc + MrVr = McV'c + MrV'r
Initially
Vc=Vr=Vi
and since rocks are being dropped directly downward, final momentum of the rocks (being dropped one at a time) should be zero because their falling down, out of the railroad car.
So:
Vi( Mc+Mr) = McV'c V'c = [Vi(Mr+Mc)] / Mc
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A person rides in an elevator.
What is the equal and opposite force for the force of the elevator floor pushing up on the person as described by Newton's third law?
The equal and opposite force for the force of the elevator floor pushing up on the person as described by Newton's third law is the weight and the reaction force from its effect.
What is an Elevator?This is referred to as a device which is used in the vertical transportation of goods and people among the floors in a buildings.
When an individual steps into the elevator, the weight acts on it and it is known as a downward force while the reaction acts upward in an opposite reaction as described by Newton's third law in this scenario.
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what is the type of blood the contains antibody B and Rh
Answer:Blood type AB Rh+
Explanation:
How can gravity's role in tectonic plate motion be described? question 6 options: earth's magnetic field reverses ridge push and slab pull circulating material in the mantle earth's internal heating
Gravity's role in the tectonic plate motion can be described on the basis of ridge push and slab pull of tectonic plates.
What are ridge push and slab pull?Ridge push refers to gravitational sliding. It is a driving force for plate motion in plate tectonics, occurring at mid-ocean ridges as the result of the rigid lithosphere sliding down the hot and raised asthenosphere below mid-ocean ridges.
Slab pull is a pulling force that is exerted by a cold and dense oceanic plate plunging into the mantle. The term for the process of a tectonic plate descending into the mantle is subduction. Subduction may emerge due to gravity.
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what is the magnitude of positive charges stored on one plate? what is the magnitude of negative charges stored on the opposite plate?
One plate of the capacitor holds a positive charge Q and the other plate holds a negative charge -Q.
When charging a capacitor, a single electron is first added to one side of the capacitor and then the charge moves so that the electron has an electric field that repels the other electrons.
This electric field penetrates space and pushes electrons into the other plate, giving that plate an induced positive charge. This will give you the same amount of charge on both plates.
So one plate of the capacitor holds a positive charge Q and the other plate holds a negative charge -Q.
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The graph shows distance versus time for an object.
Which of the following correctly describes the object's motion?
The object is moving with increasing acceleration.
The object is moving with constant acceleration.
The object is moving with increasing velocity.
The object is moving with constant velocity.
The velocity of an object is the ratio of distance to the time. The graph shows, an increase in distance with the increase in time. This linearity make the velocity constant. Hence, the option D is correct.
What is velocity?Velocity of a substance is the measure of distance travelled per unit time. Thus it is the ratio of distance to time.In physics, velocity is the rate of speed.
Velocity = distance/time.
Hence, as the time taken for the travel increases velocity will decreases. In the given graph at each point distance shows linear relation with the time and it obtains a straight line.
Therefore, the distance is increasing with increase in time means the velocity is not changing and it remains constant. Hence, option D is correct.
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an automobile manufacturer claims that its product will travel 1.2 km in 20 s, starting from rest. what is the magnitude of the constant acceleration required to do this? answer in units of m/s 2 .
The amount of constant acceleration needed to accomplish this is:
6 m/s2.
What is constant acceleration?A velocity change that does not alter over time is referred to as a constant acceleration. A car's average acceleration remains steady at 20 mph per minute even if it increases its speed by 20 mph in one minute and another 20 mph the next.
Given;
The car will drive a distance of d = 1.2 km
To convert 1.2 km to m
1.2 x 1000
= 1200 m.
beginning speed of the car, where u = 0.
Travel time, t = 20 s
To get the constant acceleration, use the following kinematic equation;
d = ut + ¹/₂at²
1200 = 0 + ¹/₂(20)²a
1200 = 400 /2
1200 = 200a
a = 1200 / 200
a = 6 m/s²
Therefore, 6 m/s² of constant acceleration is needed to accomplish this.
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The amount of constant acceleration needed to accomplish this is 6 m/s2.
What is constant acceleration?A velocity change that does not alter over time is referred to as a constant acceleration. A car's average acceleration remains steady at 20 mph per minute even if it increases its speed by 20 mph in one minute and another 20 mph the next.
Given;
The car will drive a distance of d = 1.2 km
To convert 1.2 km to m
1.2 x 1000
= 1200 m.
beginning speed of the car, where u = 0.
Travel time, t = 20 s
To get the constant acceleration, use the following kinematic equation;
d = ut + ¹/₂at²
1200 = 0 + ¹/₂(20)²a
1200 = 400 /2
1200 = 200a
a = 1200 / 200
a = 6 m/s²
Therefore, 6 m/s² of constant acceleration is needed to accomplish this.
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a funny car accelerates from rest through a measured track distance in time t with the engine operating at a constant power p. if the track crew can increase the engine power by a differential amount dp, what is the change in the time required for the run? (use any variable or symbol stated above as necessary.)
dT = -T^4/(2mD^2)dP
P = W/T = FD/T = (m a)D/T
dP = -maD/T^2 dT
dT = -T^2/(maD)dP
V = aT
D = 1/2 a T^2
a = 2D/T^2
dT = -T^4/(2mD^2)dP
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a wire with a resistance of 6.0 () is drawn out through a die so that its new length is three times its original length. find the resistance of the longer wire, assuming that the resistivity and density of the material are not changed during the drawing process.
R0 is the original resistance. Thus, R = 9(6.0Ω) = 54 Ω.
Electric current flowing through and potential difference across an electrical component can be used to determine its resistance.
Ohm's Law, which depicts the connection between potential difference, current, and resistance:
V = I R, where V is the potential difference (in volts), V I is the current (in amps), A R is the resistance (in ohms), and
The following equation can be changed to determine the resistance:
R = V ÷ I
According to Ohm's equation, I = V/R, the behaviour of the material may be predicted if the resistance remains constant over a significant range of voltage. The definition above applies to both AC and DC applications of resistors, despite the fact that it deals with DC current and voltage.
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Question 1(Multiple Choice Worth 2 points)
(05.01 LC)
Historically, what technique was used to release the "evil" that caused disease?
A- Antibiotics
B- Isolation
C- Lobotomy
D- Trepanning
Question 2(Multiple Choice Worth 2 points)
(05.01 MC)
With which of the following statements would René Descartes likely agree?
A- The mind and body cannot be separated, therefore physical illness and mental illness cannot be separated.
B- The mind and body can be separated, therefore physical illness and mental illness can be treated differently.
C- Physical illness is more serious than mental illness and deserves prompt attention.
D- Mental illness is more serious than physical illness and deserves prompt attention.
Question 5(Multiple Choice Worth 2 points)
(05.01 MC)
Which of the following was a negative consequence of deinstitutionalization?
A- Even the most severely ill were able to live freely outside of the hospital setting.
B- Individuals with mental illness were able to resume their relationships with friends and family.
C- Many people with mental illness did not continue treatment once released.
D- The stigma associated with mental illness decreased.
The technique that was used to release the "evil" that caused disease is Trepanning.
Option D is correct.
René Descartes would likely agree with the statement that The mind and body cannot be separated, therefore physical illness and mental illness cannot be separated. So option B is correct.
One of the negative consequence of deinstitutionalization was Many people with mental illness did not continue treatment once released.
So option C is correct.
What is trepanning?Trepanning, also known as trepanation, trephination, trephining or making a burr hole, is described as a surgical intervention in which a hole is drilled or scraped into the human skull.
Deinstitutionalization well-intended move was predicated on the development of a community mental health center network. But it had unintended consequences, which is that many deinstitutionalized mentally ill clients have been forced onto the street with little or no treatment.
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Answer:
A
Explanation:
