Answer:
cmon man
Step-by-step explanation:
We want to show that sinθ cosθ = cotθ is not true for all values of θ. To do this, we just need to find one counterexample, i.e., one value of θ for which the equation is not true.
Recall that cotθ = cosθ/sinθ. So, the equation sinθ cosθ = cotθ can be rewritten as sinθ cosθ = cosθ/sinθ.
Multiplying both sides by sinθ, we get:
sin^2θ cosθ = cosθ
Dividing both sides by cosθ, we get:
sin^2θ = 1
Taking the square root of both sides, we get:
sinθ = ±1
So, we need to find a value of θ such that sinθ is equal to ±1. This occurs when θ = π/2 + kπ, where k is an integer.
Now, let's check whether sinθ cosθ = cotθ is true for this value of θ. We have:
sin(π/2 + kπ) = ±1
cos(π/2 + kπ) = 0
cot(π/2 + kπ) = undefined (since cos(π/2 + kπ) = 0)
Therefore, sinθ cosθ = cotθ is not true for θ = π/2 + kπ, and we have found a counterexample. This shows that sinθ cosθ = cotθ is not a trigonometric identity.
Find the interquartile range using the following.
Minimum: 1
Q1: 3
Median: 5
Q3: 7
Maximum: 9
A. 8
B. 4
C. 5
D. 10
Answer: B. 4
Step-by-step explanation: The interquartile range is just the distance in between the upper and lower quartiles. Therefore, to find the interquartile range, the equation in this case is 7 - 3, which equals 4.
A set of data items is normally distributed with a mean of 500. Find the data item in this distribution that corresponds to the given z-score. z = -3, if the standard deviation is 80.
Answer:
260
Step-by-step explanation:
The z score for a normal distribution is given by the formula
[tex]z = \dfrac{X-\mu}{\sigma}[/tex]
where
X is the data point, μ is the mean and σ is the standard deviation
Given
Mean μ = 500
Standard deviation σ = 80
z-score = -3
and plugging in these values for z-score formula we get
[tex]-3 = \dfrac{X -500}{80}[/tex]
==>
-240 = X - 500
-240 + 500 = X
260 = X
or
X = 260
johnathannes brahms destoryed or left many because of his work unplublished because
A. He didnt want to be sucessful
B. He thought they were too good to publish
C. He was a perfectionist and was never satisfied with them.
Answer asap for brainlist
Mary has the qualities of being a team leader.
Here, we have,
Team leaders upload any other stage of control. They’re employed to persuade and construct relationships, to make matters happen. Team chief’s to-do lists may be vast, however through categorizing them, it’ll come up with readability approximately the reason of your job.
A group chief has an outline of a set of humans, motivates, offers guidance and video display units performance. It is probably an professional identify alternate or a delegation exercising out of your management, however both way, being a group chief separates you out of your friends as a depended on individual to manipulate a assignment or institution of humans.
Team leaders and executives have exceptional responsibilities. Unlike managers, group leaders won’t have the authority to direct, alternate plans, put in force or construct their groups via hiring and firing. Their position is mostly a motivational and inspirational one inside an organization. They’re professional dating developers and mediators, liaising among the humans and management.
Thus this are the qualities of team leader.
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complete question;
Mary is a perfectionist . She loves participating on teams and often takes on too many tasks because she wants to ensure that they are done on time and on budget.
a rectangular prism has 312 cubes. The cubes have an edge length of 1/5 cm. What is the volume of this rectangular prism?
Answer:
[tex] {( \frac{1}{5}) }^{3} (312) = \frac{312}{125} = 2.496[/tex]
The volume of this rectangular prism is 2.496 cubic centimeters.
The volume of the rectangular prism is 2.496 cubic centimeters.
If the rectangular prism has 312 cubes with an edge length of 1/5 cm, we may calculate the total volume by multiplying the number of cubes by the volume of each cube.
V = x3 gives the volume of a cube with edge length x. Because the edge length, in this case, is 1/5 cm, the volume of each cube is (1/5)3 = 1/125 cm3.
We multiply the number of cubes by the volume of each cube to determine the volume of the rectangular prism:
312 cubes (1/125 cm3/cube) = 2.496cm3 volume
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A machine produces metal pieces that are cylindrical in shape. A sample of these pieces is taken and the diameters are found to be 1.01, 0.97, 1.03, 1.04, 0.99, 0.98, 0.99, 1.01, and 1.03 centimeters. Use these data to calculate three interval types and draw interpretations that illustrate the distinction between them in the context of the system. For all computations, assume an approximately normal distribution. The sample mean and standard deviation for the given data are ¯x = 1.0056 and s = 0.0246. (a) Find a 99% confidence interval on the mean diameter. (b) Compute a 99% prediction interval on a measured diameter of a single metal piece taken from the machine. (c) Find the 99% tolerance limits that will contain 95% of the metal pieces produced by this machine. (Complete step by step process)
This interval is wider than the confidence interval in part (a) and the prediction interval in part (b) because it is based on the entire population of metal pieces, not just a sample.
(a) To find a 99% confidence interval on the mean diameter, we can use the t-distribution with n-1 degrees of freedom since the population standard deviation is not known. The formula for the confidence interval is:
CI = x ± tα/2,s/√n
where x is the sample mean, s is the sample standard deviation, n is the sample size, and tα/2 is the t-value with (n-1) degrees of freedom for the desired level of confidence α.
Plugging in the values, we get:
CI = 1.0056 ± t0.005/2,0.0246/√9
= 1.0056 ± 0.025
= (0.9806, 1.0306)
Therefore, we can be 99% confident that the true mean diameter of the metal pieces produced by the machine is between 0.9806 and 1.0306 centimeters.
(b) To compute a 99% prediction interval on a measured diameter of a single metal piece taken from the machine, we can use the formula:
PI = x ± tα/2,s(1 + 1/n)√(1 + 1/n)
where x is the point estimate of the diameter (in this case, the sample mean), s is the sample standard deviation, n is the sample size, and tα/2 is the t-value with (n-1) degrees of freedom for the desired level of confidence α.
Plugging in the values, we get:
PI = 1.0056 ± t0.005/2,0.0246(1 + 1/9)√(1 + 1/9)
= 1.0056 ± 0.052
= (0.9536, 1.0576)
Therefore, we can be 99% confident that a single metal piece produced by the machine will have a diameter between 0.9536 and 1.0576 centimeters.
(c) To find the 99% tolerance limits that will contain 95% of the metal pieces produced by this machine, we can use the formula:
TL = x ± kσ
where x is the sample mean, σ is the population standard deviation (which is estimated by the sample standard deviation s), k is the number of standard deviations from the mean that will contain the desired percentage of the population (in this case, 95% or 1.96 standard deviations for a normal distribution).
Plugging in the values, we get:
TL = 1.0056 ± 1.96(0.0246)
= (0.9573, 1.0539)
Therefore, we can be 99% confident that 95% of the metal pieces produced by the machine will have diameters between 0.9573 and 1.0539 centimeters. This interval is wider than the confidence interval in part (a) and the prediction interval in part (b) because it is based on the entire population of metal pieces, not just a sample.
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Solve for circle theorem
The requried measure of the angles is given as:
(1) ∠OLQ = 32, (2) ∠NQP = 38°, (3) ∠NLP = 38°, and (4) ∠NPL = 52°.
As shown in the figure,
(1) Following the property of angle subtended by an arc on the center of the circle and at a point on the circumference of a circle,
∠OLQ = ∠OQL = 64/2 = 32°.
(2)
Following the figure,
∠NQP = ∠LQP - ∠LQN
= ∠LQP-[∠OQL+∠MQN]
= 90 - [32+20]
= 38°
Similarly,
∠NLP = 38°
∠NPL = 52°
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The box plots display the scores that two different groups of students got on their last math quiz.
The correct option is A.
The interquartile range for Data Set A is 15 and the interquartile range for Data Set B is 10.
Given that, the box plots display the scores that two different groups of students got on their last math quiz.
We need to find the interquartile range of each data set.
So, the interquartile range of data set A = 80-65 = 15
the interquartile range of data set B = 90-80 = 10
Hence, the interquartile range for Data Set A is 15 and the interquartile range for Data Set B is 10.
The correct option A.
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Help help help hehehheheheh
Answer:
Step-by-step explanation:
your supposed to learn things in class pay attetion
math hw for tonight
help solve this problem! Thank you!
ap cal bc
Answer:
[tex]\sqrt{2}[/tex]
Step-by-step explanation:
When t = 0, the velocity is:
[tex]\begin{aligned}\vec{v}(t)&=3^t \vec{i}+e^{6t} \vec{j}\\\\t=0 \implies \vec{v}(0)&=3^0 \vec{i}+e^{(6 \cdot 0)} \vec{j}\\ &=1 \vec{i}+1 \vec{j} \end{aligned}[/tex]
Speed is the magnitude of the velocity of the object.
[tex]\boxed{\text{A vector $\binom{x}{y}$ has magnitude $\sqrt{x^2+y^2}$}}[/tex]
Therefore, the particle's speed at time t = 0 is:
[tex]\begin{aligned}\implies |v|&=\sqrt{1^2+1^2}\\&=\sqrt{1+1}\\&=\sqrt{2}\end{aligned}[/tex]
Find the height of the rectangular prism (You should have at least 3 steps shown in your work)
Answer:
[tex]12 \times 10 \times h = 3600[/tex]
[tex]120h = 3600[/tex]
[tex]h = 30[/tex]
The height is 30 millimeters.
Brooklyn needs to earn $14 more dollars to have $32. How much money does Brooklyn have now?
Identify the steps needed to write and solve an equation to solve the word problem. Select all that apply.
The variable, m, is equal to the amount of money Brooklyn has now.
The variable, m, is equal to the amount of money Brooklyn needs to earn.
The correct equation is 14 + m = 32.
The correct equation is 14m = 32.
To solve the equation, subtract 14 from both sides.
To solve the equation, divide 14 on both sides.
Answer:
A,C,E
Step-by-step explanation:
Answer:
a and c and e
Step-by-step explanation:
got it right on my home work
The mass of a bowling ball is 9ibs and the volume is 135 in³. How many lbs per cubic inch is its density? Round to the nearest hundreth
Answer:
9 pounds/135 cubic inches
= 1 pound/15 cubic inches
= .07 pounds/cubic inch
if u were to flip a coin 15 times how many times will the coin land on tails
Use the frequency data in the table below to compute the phi correlation coefficient.
Therapist's Approach Satisfaction Totals
Cognitive-Behavioral Psychodynamic
Client Satisfied
by Therapy?
Yes 26 15 41
No 11 24 35
Approach Totals 37 39 N = 76
What is the Fobt for the regression line?
What is the critical value (Fcrit ) for the significance test of the regression line?
Based on the Fobt you calculated is the regression line statistically significant? (i.e., Should you reject the null hypothesis?)
Use the information you computed for the regression line significant test's source table to calculate the standard error of prediction (se). What is its value? (Round your answer to 2 decimal places)
Based on the information, we cannot reject the null hypothesis because our calculated phi coefficient (0.245) is smaller than the critical value (3.84).
How to explain the hypothesisIt should be noted that to establish whether the phi coefficient is statistically significant, we can compare it to a crucial value. However, the significance level (i.e., alpha) must be specified ahead of time.
Assume a 0.05 level of significance. We calculate the crucial value for a 2x2 contingency table with 1 degree of freedom and a significance level of 0.05 using a phi coefficient table or calculator.
We cannot reject the null hypothesis because our calculated phi coefficient (0.245) is smaller than the critical value (3.84). As a result, we find that there is no statistically significant relationship between the therapist's method and client satisfaction.
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Question 4 A study has been conducted to compare male and female test performance on a standardised science exam. In this hypothetical study, the researchers reported with a sample size of n = 50, the 95% confidence interval was found to be between 0.15 and 0.55.
What would happen to the 95% confidence interval if the sample size was increased?
The 95% confidence interval would remain the same Cannot be determined from the information provided The 95% confidence interval would decrease The 95% confidence interval would increase
If the sample size was increased, the 95% confidence interval would decrease. A larger sample size would provide more precise and accurate data, resulting in a narrower confidence interval.
A confidence interval is a range of values within which a population parameter is estimated to lie with a certain level of confidence. It is commonly used in statistical inference to estimate the true value of a population parameter based on a sample from that population.
If the sample size was increased, the 95% confidence interval would likely decrease. This is because a larger sample size typically leads to more precise estimates and less variability in the data, resulting in a narrower confidence interval. However, the exact size of the decrease would depend on various factors such as the amount of variability in the data and the level of statistical significance chosen for the study.
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Ellie is going to see a movie and is taking her 2 kids. Each movie ticket costs $13 and there are an assortment of snacks available to purchase for $5 each. How much total money would Ellie have to pay for her family if she were to buy 4 snacks for everybody to share? How much would Ellie have to pay if she bought x snacks for everybody to share?
Total cost with 4 snacks:
Total cost with x snacks:
The total cost that Ellie would pay with 4 snacks is $59.
The total cost that Ellie would pay with x snacks is $29 + $5x.
What is the total cost?The first step is to determine the total number of people going to the movies. There are 3 people going to the movies.
The total cost spent by Ellie is the sum of the tickets and the total cost of the snacks.
Total cost = total cost of the tickets + total cost of the snacks
= (cost of one ticket x number of people going to the movie) + (number of snacks bought x price of one snack)
= (13 x 3) + ($5 x 4)
$39 + $20 = $59
Total cost if x snacks is bought: (13 x 3) + ($5 x x) = $39 + $5x
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Elijah can spend up to $23 on groceries. He wants to buy 3 pounds of tomatoes, 4 pounds of oranges, and x pounds
of lean ground beef. The tomatoes cost $1.35 per pound, the oranges $1.65 per pound, and the ground beef $4.94
per pound. Write an inequality that represents the possible number of pounds of ground beef, x, he can buy. Find
the value of x.
A. 1.35 x 3 +
B. 1.35 x 3 +
1.65 x 4 +
1.65 x 4 +
c.
1.35 x 3 + 1.65 x 4 +
D. 1.35 x 3 + 1.65 x 4 +
4.94x < 23; x<25
4.94x ≤ 23; x ≤ 25
4.94x >
23; x > 25
4.94x ≥
23;x ≥ 25
Answer1.35+ 4:
Step-by-step explanation:
The answer choices are distributive property, associative property, communicative property
Answer:
Step 1: Distributive Property
Step 2: Distributive Property
Step 3: Commutative Property
Step-by-step explanation:
Step 1: This is distributing the (x + 4y + z) into the (x - 7y), so each term in the prior expression is multiplied by (x - 7y). Hence, Distributive Property.
Step 2: This is doing the same thing but to each individual term. The x in the first term is multiplied by each term in the (x - 7y), the 4y in the second term is multiplied by each term in the (x - 7y), and the same for z. Hence, Distributive Property.
Step 3: This is reordering the variables in the terms. For example, 4yx is changed to 4xy, and that is possible because of the Commutative Property. zx is also reordered into a xz and 7zy into a 7yz.
Feel free to ask any more questions. Hope this helps!!!
Solve the following for θ, in radians, where 0≤θ<2π.
2cos2(θ)−8cos(θ)−1=0
Select all that apply:
1.07
1.69
4.59
2.49
2
2.33
Answer:correct answers 1.69
4.59
Step-by-step explanation:
We can solve this quadratic equation in cos(θ) by using the substitution u = cos(θ):
2u^2 - 8u - 1 = 0
Now we can use the quadratic formula to solve for u:
u = (-b ± sqrt(b^2 - 4ac)) / 2a
where a = 2, b = -8, and c = -1. Substituting these values, we get:
u = (8 ± sqrt(8^2 - 4(2)(-1))) / 2(2)
u = (8 ± sqrt(72)) / 4
u = 2 ± sqrt(18)
Therefore, either:
The capacity of a swimming pool is given by C = l × w × , where l is the length, w is the width, d1 is the depth of the shallow end, and d2 is the depth of the deep end of the pool.
Select all the correct statements.
The correct statements about the capacity of swimming pool are (a) and (d)
The capacity of a swimming pool is given by C = l × w × (d₁ + d₂)/2
where l is the length,
w is the width,
d₁ is the depth of the shallow end,
and d₂ is the depth of the deep end of the pool.
If C = 9,216 ft, l = 48 ft, w = 24 ft, and d₂ = 12 ft, then d₁ would be,
9216 = 48 × 24 × (d₁ + 12)/2
d₁ + 12 = (9216 × 2) / (48 × 24)
d₁ + 12 = 16
d₁ = 4 ft
And formula for the depth of the shallow end would be,
d₁ = (2C/lw) - d₂
Therefore, the correct statements are (a) and (d)
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The complete question is:
The capacity of a swimming pool is given by C = l × w × (d1 + d2)/2, where l is the length, w is the width, d 1 is the depth of the shallow end, and d 2 is the depth of the deep end of the pool.
Select all the correct statements.
a) The depth of the shallow end is given by d1 = 2C/lw - d2.
b) If C = 9,216 ft, l = 48 ft, w = 24 ft, and d2 = 16 ft, then d1 = 4 ft.
c) The depth of the shallow end is given by 2C - d2/lw .
d) If C = 9,216 ft, l = 48 ft, w = 24 ft, and d2 = 12 ft, then d1 = 4 ft.
A virus takes 5 days to grow from 90 to 200. How many days will it take to grow from 90 to 410? Round to the nearest whole number.
The number of days it will take the virus to grow from 90 to 410 is 15 days.
What is the growth rate of the virus?The growth rate of the virus is calculated as follows;
growth rate = (200 - 90) / 5
growth rate = 22 per day
The number of days it will take the virus to grow from 90 to 410 is calculated as follows;
growth = 410 - 90
growth = 320
Number of days = 320 / 22/day = 14.55 ≈ 15 days
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help help help help help
Can you help me solve this asap
Based on the equation, we own 100 shares of JP Morgan Emerging Markets Bond Fund and 900 shares of Fidelity Conservative Income bond fund.
How to explain the equationThe portfolio is worth $10,000 in total:
$100x + $10y = $10,000
We can now use elimination to find x:
$1100x + $110y = $110,000 -($100x + $10y = $10,000)
$1000x = $100,000 x = 100
As a result, we own 100 shares of JP Morgan Emerging Markets Bond Fund. To solve for y, we can plug this number back into the original equation:
$100x + $10y = $10,000
$100(100) + $10y = $10,000
$10y = $9,000 y = 900
As a result, we have 900 shares of Fidelity Conservative Income bond fund
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a. The following is the input/output table for two industries X and Y. The values are in million of rupees.
Producers
X
Y
X
14
7
Users
Y
6
Final Demand
8
Total Output
28
18
11
36
Determine the outputs if the final demand changes to 20 for X and 30 for Y.
[3]
The outputs for industries X and Y will be 31 million and 43.2 million, respectively supposedly the final demand changes to 20 for X and 30 for Y.
How do we calculate?We will start with industry X.
The final demand for X hade an increment from 14 million to 20 million with an increase of 6 million, hence the final output of X must also increase by 6 million to make up for demand.
Users Final Producers
Demand X Y
X 14 7
Y 6 18
Total 20 25
The table tells us that for every additional million of final demand for X, the producers in industry X need to produce 0.5 million of output.
So the new total output for industry X is 28 + 3 = 31 million.
For industry Y
The same scenario occurred for Industry Y which had final output of 12 in order to meet the demand increment.
So the new total output for industry Y is 36 + 7.2 = 43.2 million.
In conclusion, the outputs for industries X and Y will be 31 million and 43.2 million, respectively, if the final demand changes to 20 for X and 30 for Y.
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Find the angle between the pair of vectors to the nearest tenth of the degree
The value of angle between the two vectors is 86⁰.
What is the angle between the two vectors?The value of angle between the two vectors is calculated as follows;
tan θ = vy/vx
where;
vy is the sum of the vertical directionvx is the sum of vectors in horizontal direction( -8, 9), (-9, -6)
vy = (-6 - 9) = -15
vx = (-9 + 8) = -1
tan θ = ( -15 ) / ( -1 )
tan θ = 15
The value of θ is calculated by taking arc tan of the fraction,;
θ = tan ⁻¹ ( 15 )
θ = 86⁰
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3x+9-8x=-31?????????????
Margarita fue a la tienda y compro una cartera y unos jeans por un
total de RD$3,250. Sabiendo que las cartera excede al jeans en
RD$970, ¿Cuántos pago margarita por cada artículo?
Cartera = RDS
Jeans = RD$
Escribir las respuestas numéricas y sin comas.
OK
The solution is , price of jeans = RD$ 1140 and, price of handbag =
RD$ 2110.
Here, we have,
given that,
Margarita went to the store and bought a bag and some jeans for a total of RD$3,250.
Knowing that the handbag exceeds the jeans by RD$970,
now, we have to find that, how many do she pay for each article.
let, price of jeans = RD$ x
so, price of handbag = RD$ (x +970)
ATQ, we get,
RD$ x + RD$ (x +970) = RD$3,250
or, RD$ 2x + 970 = RD$3,250
or, RD$ 2x = RD$ 2280
or, x = RD$ 1140
Hence, price of jeans = RD$ 1140 and, price of handbag = RD$ 2110.
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A sack of rice wieghs 50 kilos. What is the weight of 85 sacks of rice?
Answer:
4250 kilos
Step-by-step explanation:
Find the surface area of the square pyramid (above) using its net (below)
Answer:
Step-by-step explanation:
the square base = 5 * 5 = 25
each of the triangular sides = 4*2.5=10
so… 25+(10*4)=25+40=65
clara is running a bakery she has made a street sign to direct people to her bakery . She painted one of the post and sign. What is the painted area?8in,8in,5in, 60in, 4in
The painted area of the sign is approximately 324 square inches. This was calculated by finding the area of the pole, square signboard, and triangle portion of the signboard and adding them together.
To find the painted area, we need to find the area of the pole, the area of the square signboard, and the area of the triangular portion of the signboard.
Area of pole
The pole is a rectangular prism with height 60in and width 4in. Therefore, the area of the pole is:
60in x 4in = 240 sq. in.
Area of square signboard
The square signboard has a side length of 8in. Therefore, the area of the square signboard is:
8in x 8in = 64 sq. in.
Area of triangular portion of the signboard
The triangular portion of the signboard has a base of 8in and a height of 5in. Therefore, the area of the triangular portion of the signboard is:
(1/2) x 8in x 5in = 20 sq. in.
Total painted area
The total painted area is the sum of the area of the pole, the area of the square signboard, and the area of the triangular portion of the signboard. Therefore, the painted area is:
240 sq. in. + 64 sq. in. + 20 sq. in. = 324 sq. in.
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--The given question is incomplete, the complete question is given
" clara is running a bakery she has made a street sign to direct people to her bakery . She painted one of the post and sign. What is the painted area?8in,8in,5in, 60in, 4in "--