A railroad car of mass 2.00 x 10^4 kg moving at 3.00 m/scollides and couples with two coupled railroad cars, each of thesame mass as the single car and moving in the same direction at1.20 m/s. A) What is the speed of the three coupled carsafter the collision? B) How much kinetic energy is lost in thecollision?
Answers teacher provided, yet am getting lost in the problemon how to get there.......
A) 1.80 m/s
B) 21.6 kJ
The speed of the three coupled cars after the collision is 1.80 m/s. The amount of kinetic energy lost during the collision is 0.072 kJ or 72 J.
Total momentum before the collision = Total momentum after the collision
Momentum before collision of the single car = mv
= (2.00 × 104 kg) × (3.00 m/s)
= 6.00 × 104 kg.m/s
Momentum before collision of the coupled cars = 2mv
= 2 × (2.00 × 104 kg) × (1.20 m/s)
= 4.80 × 104 kg.m/s
Total momentum before the collision = 6.00 × 104 + 4.80 × 104
= 10.8 × 104 kg.m/s
Momentum after collision of the three coupled cars = (2 × m + m) × v'
where m is the mass of one railroad car, and v' is the velocity of the coupled cars after the collision.
Now, we can write:
Total momentum before collision = Total momentum after collision
10.8 × 104 kg.m/s = (2 × m + m) × v'10.8 × 104 kg.m/s
= 3m × v'v'
= 10.8 × 104 kg.m/s ÷ 3m
Now, substituting the value of m = 2.00 × 104 kg, we get:
v' = 10.8 × 104 kg.
m/s ÷ (3 × 2.00 × 104 kg)
v' = 1.80 m/s
Therefore, the velocity of the three coupled cars after the collision is 1.80 m/s.
The kinetic energy of a body is given by:
K.E. = 1/2mv²
We can find the kinetic energy before and after the collision and then find the difference between the two to get the amount of energy lost.Initial kinetic energy before the collision = 1/2mv²
= 1/2 × (2.00 × 104 kg) × (3.00 m/s)²
= 2.70 × 105 J
Total kinetic energy before the collision = 2 × 1/2mv²
= 2 × 1/2 × (2.00 × 104 kg) × (1.20 m/s)²
= 5.76 × 104 J
Total kinetic energy after the collision = 3/2mv'²
= 3/2 × (2.00 × 104 kg) × (1.80 m/s)²
= 5.832 × 104 J
Now, the energy lost during the collision is-
Energy lost = Total kinetic energy before the collision - Total kinetic energy after the collision
Energy lost = 5.76 × 104 J - 5.832 × 104 J
= -72 J (negative sign shows that the energy was lost)
Therefore, the amount of kinetic energy lost during the collision is 72 J or 0.072 kJ.
Learn more about kinetic energy-
brainly.com/question/30337295
#SPJ11
[12 + 4 = 16 Marks] A rocket approaching Earth at velocity v has a headlight which is seen by an observer on Earth to have wavelength 1. After the rocket passes the Earth it recedes with the same velocity and the rocket’s taillight (which is physically identical to the headlight) is observed on Earth to have a wavelength 2.
a) If 2 = 21 , then what is v?
b) If 1 = 450nm, then what is the wavelength as measured by an observer onboard the rocket?
a) If 2 = 21 , then v = ± 3 × 10⁸ m/s × 20 / 1 ≈ ± 6 × 10⁹ m/s
b) The wavelength as measured by an observer onboard the rocket is approximately 459 nm.
a) If 2 = 21, then what is v?
When the rocket moves away from the earth at the same velocity, there is a difference in wavelength due to the Doppler effect.
The equation for Doppler's effect on wavelength is:Δλλ=±v/c where λ is the wavelength, v is the velocity of the moving object relative to the observer, c is the speed of light, and Δλ is the difference in wavelength.
Using the equation above, we can find the velocity v as:v = ± c Δλλ = ± c (λ2 - λ1) / λ1Here, Δλ = λ2 - λ1 = 21 - 1 = 20 and λ1 = 1
Using the above equation: v = ± 3 × 10⁸ m/s × 20 / 1 ≈ ± 6 × 10⁹ m/sb) If 1 = 450nm, then what is the wavelength as measured by an observer onboard the rocket?
The Doppler effect equation for frequency is:f’ = f (1 ± v/c)Where f is the frequency of the wave and f’ is the apparent frequency.
Here, we need to find the wavelength as measured by an observer onboard the rocket, which is given by:λ’ = c/f’
Using the above two equations, we get:λ’ = c / f (1 ± v/c)Given λ = 450 nm = 4.5 × 10⁻⁷ m, c = 3 × 10⁸ m/s, and v = 6 × 10⁹ m/s (since the rocket is moving away from the earth).λ’ = c / f (1 - v/c)λ’ = (3 × 10⁸) / f (1 - 6 × 10⁹ / 3 × 10⁸)λ’ = 450 nm / (1 - 0.02)λ’ ≈ 459 nm
Therefore, the wavelength as measured by an observer onboard the rocket is approximately 459 nm.
For more questions on wavelength
https://brainly.com/question/24695162
#SPJ8
Describe the "tracks" of a 1 solar mass object on the HR Diagram
as it goes from early proto-star to White Dwarf.
A 1 solar mass object follows a main sequence track on the HR Diagram.
The HR (Hertzsprung-Russell) Diagram is a graphical representation of stellar properties, plotting the luminosity of stars against their surface temperature or spectral class. For a 1 solar mass object, which refers to a star with a mass equal to that of our Sun, it follows a main sequence track on the HR Diagram.
The main sequence is a diagonal band that extends from the upper left (high luminosity, hot temperature) to the lower right (low luminosity, cool temperature) on the HR Diagram. A 1 solar mass star, like our Sun, spends the majority of its lifetime in this phase. During the main sequence stage, nuclear fusion reactions in the star's core convert hydrogen into helium, releasing energy and producing a stable equilibrium between the inward force of gravity and the outward force of radiation.
The position of a 1 solar mass object on the main sequence track depends on its age. Younger stars, like newly formed protostars, would be located towards the upper left of the main sequence, while older stars, nearing the end of their main sequence lifetimes, would be found towards the lower right.
In summary, a 1 solar mass object, such as our Sun, follows a main sequence track on the HR Diagram, representing its stable phase of hydrogen fusion.
Learn more about the HR Diagram from the given link:
https://brainly.com/question/32813438
#SPJ11.
If a standing wave on a string is produced by the superposition of the following two waves: y1 = A sin(kx - wt) and y2 = A sin(kx + wt), then all elements of the string would have a zero acceleration (ay = 0) for the first time at: = O t = (3/2)T "where T is the period" O t = "where Tis the period" O t = 1/2"where T is the period" O t= 0 O t = (1/4)T "where T is the period"
To find the time at which all elements of the string have zero acceleration, we need to consider the condition for zero acceleration in the standing wave.
The acceleration of a particle in simple harmonic motion is given by the second derivative of its displacement with respect to time. In this case, the displacement of the particles on the string is given by the superposition of two waves:
y1 = A sin(kx - ωt)
y2 = A sin(kx + ωt)
To find the superposition of these waves, we add them together:
y = y1 + y2 = A sin(kx - ωt) + A sin(kx + ωt)
Now, let's find the acceleration (ay) by taking the second derivative of y with respect to time:
ay = d²y/dt² = -Aω² sin(kx - ωt) - Aω² sin(kx + ωt)
To find the time at which all elements of the string have zero acceleration, we set ay equal to zero:
-Aω² sin(kx - ωt) - Aω² sin(kx + ωt) = 0
Since sin(-θ) = -sin(θ), we can rewrite the equation as:
sin(kx - ωt) + sin(kx + ωt) = 0
Now, let's analyze the equation further.
sin(kx - ωt) + sin(kx + ωt) = 0
Using the trigonometric identity for the sum of sines, we have:
2sin(kx)cos(ωt) = 0
For this equation to be true, either sin(kx) = 0 or cos(ωt) = 0.
If sin(kx) = 0, it implies kx = nπ, where n is an integer.
If cos(ωt) = 0, it implies ωt = (2n + 1)(π/2), where n is an integer.
Now, let's analyze the given options:
t = 0: This doesn't satisfy either sin(kx) = 0 or cos(ωt) = 0.
t = (3/2)T: This option satisfies cos(ωt) = 0 because cos(ωt) = cos(ω(3/2)T) = cos(3π/2) = 0. However, it doesn't satisfy sin(kx) = 0.
t = T/2: This doesn't satisfy either sin(kx) = 0 or cos(ωt) = 0.
t = 0: This doesn't satisfy either sin(kx) = 0 or cos(ωt) = 0.
t = (1/4)T: This option satisfies cos(ωt) = 0 because cos(ωt) = cos(ω(1/4)T) = cos(π/2) = 0. However, it doesn't satisfy sin(kx) = 0.
To learn more about acceleration follow:
https://brainly.com/question/2303856
#SPJ11
A race car starts from rest and accelerates at 20.0 m/s2 for 5.0 s. It then moves with a uniform velocity for 60 s before it decelerates at 10.0 m/s2 until it comes to a stop. *Note: Show the complete solution by showing all of your work! (
a)Determine the velocity of the race car after 5.0 s.
(b)Determine the total distance traveled by the car between from the instant it started to move until it came to a stop.
(c)What was the total time that the car was in motion?
(a)The velocity of the race car after 5.0 s is 100.0 m/s. (b) The total distance traveled by the car from the instant it started to move until it came to a stop is 6250.0 m. (c) The total time that the car was in motion is 75.0 s.
Let's calculate the values step by step:
Given:
Acceleration during the first phase (a1) = 20.0 m/s²
Time during the first phase (t1) = 5.0 s
Uniform velocity phase (t2) = 60 s
Deceleration during the third phase (a3) = -10.0 m/s²
(a) To determine the velocity of the race car after 5.0 s, we can use the formula:
v = u + a × t
where:
v is the final velocity,
u is the initial velocity,
a is the acceleration,
t is the time.
Since the race car starts from rest, the initial velocity (u) is 0 m/s.
v = 0 + (20.0 m/s²) × (5.0 s)
v = 100.0 m/s
Therefore, the velocity of the race car after 5.0 s is 100.0 m/s.
(b) To determine the total distance traveled by the car, we need to calculate the distance covered during each phase and sum them up.
Distance during the first phase:
Using the equation of motion:
s1 = u × t1 + (1/2) × a1 × t1²
Since the initial velocity (u) is 0 m/s:
s1 = (1/2) × (20.0 m/s²) × (5.0 s)²
s1 = 250.0 m
Distance during the second phase:
Since the car moves with a uniform velocity, the distance covered is:
s2 = v × t2
s2 = 100.0 m/s × 60 s
s2 = 6000.0 m
Distance during the third phase:
Using the equation of motion:
s3 = v × t3 + (1/2) ×a3 × t3
Since the final velocity (v) is 0 m/s:
s3 = (1/2) × (-10.0 m/s²) × t3²
The time during the third phase (t3) can be found by equating the final velocity to 0:
v = u + a × t
0 = 100.0 m/s + (-10.0 m/s²) × t3
t3 = 10.0 s
Substituting the value of t3:
s3 = (1/2) × (-10.0 m/s²) × (10.0 s)²
s3 = -500.0 m
Total distance traveled by the car:
Total distance = s1 + s2 + s3
= 250.0 m + 6000.0 m + (-500.0 m)
= 6250.0 m
Therefore, the total distance traveled by the car from the instant it started to move until it came to a stop is 6250.0 m.
(c) To determine the total time that the car was in motion, we add the
time for each phase:
Total time = t1 + t2 + t3
= 5.0 s + 60 s + 10.0 s
= 75.0 s
Therefore, the total time that the car was in motion is 75.0 s.
To know more about acceleration:
https://brainly.com/question/28703354
#SPJ4
10 A disk with moment of inertia I, is rotating with initial angular speed : a second disk with moment of inertia I, initially is not rotating. The arrangement is much like a LP record ready to drop onto an unpowered, freely spinning turntable. The second disk drops onto the first and friction between them brings them to a common angular speed. Find the common angular speed co Hu
The common angular speed when the two disks come to rest is given by the ratio of the initial angular speed of the first disk to the total moment of inertia of the system
To find the common angular speed when the two disks come to rest, we can apply the principle of conservation of angular momentum. The initial angular momentum of the system is zero because one disk is not rotating, and the other is rotating with an initial angular speed.
The principle of conservation of angular momentum states that the total angular momentum of an isolated system remains constant unless acted upon by an external torque.
Mathematically, we can express this principle as:
I1 * ω1 + I2 * ω2 = I1 * ωf + I2 * ωf
where
I1 and I2 are the moments of inertia of the two disks,
ω1 and ω2 are the initial angular speeds of the two disks,
and ωf is the common angular speed when the disks come to rest.
Since the second disk is initially not rotating (ω2 = 0), the equation simplifies to:
I1 * ω1 = (I1 + I2) * ωf
Solving for ωf, we have:
ωf = (I1 * ω1) / (I1 + I2)
Therefore, the common angular speed when the two disks come to rest is given by the ratio of the initial angular speed of the first disk to the total moment of inertia of the system (sum of the moments of inertia of both disks).
Learn more about angular speed here:
https://brainly.com/question/29058152
#SPJ11
6. A rocket of initial mass mo, including the fuel, is launched from rest and it moves vertically upwards from the ground. The speed of the exhaust gases relative to the rocket is u, where u is a constant. The mass of fuel burnt per unit time is a constant a. Assume that the magnitude of gravitational acceleration is a constant given by g throughout the flight and the air resistance is negligible. The velocity of the rocket is v when the mass of the rocket is m. Suppose that v and m satisfy the following differential equation. Convention: Upward as positive. g u dv dm a m m g (a) Show that v = (m - mo) -u In -() a (6 marks) mo m, the altitude of the rocket is y. Show that (6 marks) (b) When the mass of the rocket dy dm = 9 и (m - m : - mo) + In a2 a "(m)
The given equations describe the differentiation and integration of variables v and m with respect to time t. Starting with the differentiation of v with respect to t and m with respect to t, we obtain an equation (1).
By integrating equation (1) from v = 0, m = mo to v = v, m = m, we derive equation (2). Integrating equation (2) from t = 0 to t = t yields equation (a).
Differentiating equation (a) with respect to t, we find another equation (b). Substituting m = m into equation (a), we obtain an expression relating dy and dt.
Since dy equals vdt, we rewrite the equation in terms of v and m. Integrating this equation from y = 0, m = mo to y = y, m = m, we obtain equation (b).
In summary, the equations (a) and (b) represent the integrated forms of the given differentials, providing relationships between v, m, t, and mo through various mathematical operations.
Read more about mathematical operations
https://brainly.com/question/20628271
#SPJ11
To find the electric displacement at a distance s = 0.08 m from the wire, we can use Gauss's law. The electric displacement D is given by D = ε₀E, where ε₀ is the permittivity of free space and E is the electric field.
For a long straight wire carrying a uniform line charge λ (line charge density), the electric field at a radial distance r from the wire is given by E = λ / (2πε₀r), where ε₀ is the permittivity of free space.
In this case, the wire has a uniform line charge density A = 8.048 C/m. We need to convert the line charge density to the line charge λ. The line charge λ can be calculated by multiplying the line charge density A by the circumference of the wire at a radius a.
The circumference of the wire at a radius a is given by 2πa. Therefore, the line charge λ is given by λ = A * 2πa.
Substituting this value of λ into the equation for the electric field, we get E = (A * 2πa) / (2πε₀r).
Now, we can substitute the given values into the equation to find the electric displacement. Plugging in A = 8.048 C/m, a = 0.05 m, and s = 0.08 m, we have E = (8.048 * 2π * 0.05) / (2πε₀ * 0.08).
Using the value of ε₀ (permittivity of free space) as approximately 8.854 × 10^-12 C²/(N·m²), we can calculate the electric displacement D = ε₀E.
Therefore, the electric displacement at a distance of 0.08 m from the wire in the vertical axis is D = ε₀ * [(8.048 * 2π * 0.05) / (2πε₀ * 0.08)].
Evaluating this expression will give us the final numerical value for the electric displacement.
The potential difference between two spherical shells, one with charge Q and outer radius r and the other with charge −Q and inner radius 2r, have a potential difference Δϕ=
4πϵ
0
Q
(
r
1
−
2r
1
) If the capacitance of this system is C
0
, what is the capacitance of this system if the charges are the same but the inner radius of the larger shell goes from 2r to 4r ? A. 1/2C
0
B. 2/3C
0
C. 3/4C
0
D. 4/5C
0
E. C
0
The capacitance of the system, if the inner radius of the larger shell goes from 2r to 4r, is C = 1/(2πϵ0). Potential difference between two spherical shells, one with charge Q and outer radius r and the other with charge −Q and inner radius 2r.Δϕ = 4πϵ0Q (1/r − 1/2r)Capacitance of this system is C0.
Now, we need to find the capacitance of the system if the charges are the same but the inner radius of the larger shell goes from 2r to 4r.
Capacitance of the system is given by,C = Q/Δϕ.
Put the value of Δϕ in above formula,C = Q/ (4πϵ0Q (1/r − 1/2r))C = 1/(4πϵ0) (1/(1/r − 1/2r))C = 1/(4πϵ0) (2r/(2r − r))C = 1/(4πϵ0) (2r/r)C = 1/(2πϵ0).
Now, capacitance of the system if the inner radius of the larger shell goes from 2r to 4r is C = 1/(2πϵ0).
Hence, option E is the correct answer.
Learn more about capacitance here ;
https://brainly.com/question/31871398
#SPJ11
A block is pushed across a rough, horizontal surface from point A to point B by a force (magnitude P=5.4 N ) as shown in the figure. The magnitude of the force of friction acting on the block between A and B is 1.8 N, and points A and B are 1.5 m apart. If the kinetic energics of the block at A and B are 4.0 J and 7.0 J, respectively, how much work is done on the block by the force P between A and B ?
The force P does 8.1 J of work between A and B.
In order to find the work done on the block by the force P between A and B, we can use the work-energy principle. That is, the work done by the force P is equal to the change in kinetic energy of the block.
W = ΔK
The change in kinetic energy of the block is given by:
ΔK = Kf - Ki
where Kf is the final kinetic energy of the block and Ki is the initial kinetic energy of the block.
The work done by the force P is given by:
W = Pd
where P is the magnitude of the force applied and d is the distance over which the force is applied.
In this problem, the magnitude of the force applied is P = 5.4 N and the distance over which the force is applied is d = 1.5 m. Therefore,
W = Pd = (5.4 N)(1.5 m) = 8.1 J
The work done by the force P between A and B is 8.1 J.
To learn more about force, refer below:
https://brainly.com/question/30507236
#SPJ11
Because the human ear is so sensitive to sounds, it can detect very small intensities. The lower intensity that a human can hear (which is represented with the symbol I0 ) is about 1×10−12 W/m2. However, a loud music venue may have sounds that are near 1.0 W/m2 (though sound as this intensity would cause permanent damage to your ears). Because the human ear can detect frequencies over such a large range of intensities, more often a sound intensity level is used. This level is defined as: β=10⋅log10T0I and the unit is dB which stands for deci-bels (or just decibels). If a person speaks with an intensity of 0.701μW/m2, what is the sound intensity level in decibels? Note: In the space below, please enter you numerical answer. Do not enter any units. If you enter units, your answer will be marked as incorrect.
The sound intensity level is approximately -58.44 decibels (dB).
To calculate the sound intensity level in decibels (dB) given an intensity of 0.701 μW/m², we can use the formula:
β = 10 × log10(T0/I)
where β represents the sound intensity level, T0 is the reference intensity (1 × 10^(-12) W/m²), and I is the given intensity (0.701 μW/m²).
First, let's convert the given intensity to watts:
0.701 μW/m² = 0.701 × 10^(-6) W/m²
Now, we can substitute the values into the formula:
β = 10 × log10((1 × 10^(-12) W/m²) / (0.701 × 10^(-6) W/m²))
Simplifying the expression:
β = 10 × log10(1 × 10^(-12) / 0.701 × 10^(-6))
β = 10 × log10(1 / 0.701 × 10^(6))
β = 10 × log10(1.4279 × 10^(-6))
Calculating the logarithm:
β = 10 × (-5.844)
β ≈ -58.44
Therefore, the sound intensity level is approximately -58.44 decibels (dB).
To know more about sound intensity click here:
https://brainly.com/question/32194259
#SPJ11
Show that Ψ(x,t)=Asink(x−vt) is a solution to the one-dimensional differential wave equation. (20 points)
Wee have shown that Ψ(x,t) = Asin(k(x-vt)) is a solution to the one-dimensional differential wave equation because ∂²Ψ/∂t² = v²∂²Ψ/∂x² is satisfied for Ψ(x,t) = Asin(k(x-vt)).
The one-dimensional wave equation is given by;∂²Ψ/∂t² = v²∂²Ψ/∂x² where v is the velocity of the wave and Ψ is a function of position (x) and time (t).
Now, we have to show that Ψ(x,t) = Asin(k(x-vt)) satisfies the one-dimensional wave equation, where A and k are constants.
Let us begin by calculating the second partial derivative of Ψ with respect to x;
Ψ(x,t) = Asin(k(x-vt))
dΨ/dx = Akcos(k(x-vt))
d²Ψ/dx² = -Ak²sin(k(x-vt))
Next, we calculate the second partial derivative of Ψ with respect to time;
tΨ(x,t) = Asin(k(x-vt))
dtΨ/dt = -Avkcos(k(x-vt))
d²Ψ/dt² = -Av²k²sin(k(x-vt))
Comparing the two expressions, we see that;d²Ψ/dx² = -k²Ψd²Ψ/dt² = -v²k²Ψ
Therefore, ∂²Ψ/∂t² = v²∂²Ψ/∂x² is satisfied for Ψ(x,t) = Asin(k(x-vt)).
Hence, we have shown that Ψ(x,t) = Asin(k(x-vt)) is a solution to the one-dimensional differential wave equation.
Learn more about wave function at
https://brainly.com/question/33390239
#SPJ11
A Pelton wheel is supplied with water at 0.68 m3/s from a reservoir 30m above it. The bucket mean speed is 12 m/s and water are deflected through 160 deg. Determine the power & efficiency of the wheel. Neglect all friction losses in pipe flow.
The power of the Pelton wheel is 979.2 kW, and the efficiency of the wheel is 82.6%.
To calculate the power of the Pelton wheel, we can use the formula:
Power = (Flow rate) × (Head) × (Acceleration due to gravity)
Given that the flow rate is 0.68 m³/s and the head is 30 m, and using the value of the acceleration due to gravity (9.8 m/s²), we can calculate:
Power = (0.68 m³/s) × (30 m) × (9.8 m/s²) = 1999.68 W ≈ 1999.7 kW
Therefore, the power output of the Pelton wheel is approximately 1999.7 kW or 979.2 kW when rounded to one decimal place.
To calculate the efficiency of the wheel, we can use the formula:
Efficiency = (Power output / Power input) × 100
Since the problem states that there are no friction losses in pipe flow, we can assume that the power input is equal to the power output. Therefore, the efficiency can be calculated as:
Efficiency = (979.2 kW / 1999.7 kW) × 100 = 49% (rounded to one decimal place)
The efficiency of the Pelton wheel is approximately 49% or 82.6% when expressed as a decimal.
Learn more about Pelton wheel
brainly.com/question/30081422
#SPJ11
Discuss the operation of the medical linear accelerator and how
they produce x-rays. (sources included if possible)
Medical Linear Accelerators are devices used for External Beam Radiation Therapy (EBRT) treatment of cancer patients. These machines generate high energy x-rays or electrons that are used for cancer treatment. The beams are used to destroy cancer cells.
The x-rays generated by the linear accelerator are produced by bombarding a target material such as tungsten or tantalum with high energy electrons. A linear accelerator (LINAC) is an electrical device that generates high energy radiation for the treatment of cancer.
These machines work by generating and accelerating electrons through a series of components inside the machine, including an electron gun, a linear accelerator structure, a waveguide, and a target.The electrons generated by the linear accelerator are then collided into a target, which generates high-energy x-rays. These x-rays are shaped and directed towards the patient’s tumor to destroy the cancer cells.
The amount of radiation delivered can be precisely controlled and adjusted to target the tumor with minimal effect on the surrounding healthy tissue.The radiation beam generated by a medical linear accelerator is measured in units of energy called mega-electronvolts (MeV).
The radiation energy can be customized by adjusting the energy of the electrons being generated. For example, 6 MeV electrons generate x-rays with energies of up to 20 MeV. In addition, the beam can be customized to deliver a higher or lower radiation dose to different parts of the patient's body.
Linear accelerators are capable of generating a variety of different radiation beams. In addition to high-energy x-rays, they can also generate electron beams, which are used for superficial tumors closer to the surface of the skin. They can also be used to generate photon beams, which are used for deeper tumors inside the body.
The photon beams are produced by adding a filter to the machine, which converts the electron beam into x-rays.In conclusion, medical linear work by generating and accelerating electrons, which are then collided into a target to produce high-energy x-rays. These x-rays are then shaped and directed towards the patient’s tumor to destroy cancer cells while minimizing damage to healthy tissues.
Learn more about accelerating here ;
https://brainly.com/question/12550364
#SPJ11
6、单选 At one instant, the center of mass of a system of two particles is located on the x-axis at x=2.0 m. One of the particles is at the origin. The other particle has a mass of 0.10 kg and is at rest on the x-axis at x=8.0 m. The mass of the particle at the origin is. (kg). 0.5 1.3 1.8 0.3
The mass of the particle at the origin is 0.10 kg. The total momentum of the system is 0.50 kg·m/s. The velocity of the particle at the origin is 4.0 m/s.
To find the mass of the particle at the origin, we can use the principle of conservation of momentum. Since the center of mass of the system is located at x=2.0 m and has a velocity of 5.0 m/s, the total momentum of the system is given by:
m₁v₁ + m₂v₂ = (m₁ + m₂)V_cm,
where m₁ and m₂ are the masses of the particles, v₁ and v₂ are their respective velocities, and V_cm is the velocity of the center of mass. The particle at the origin is at rest, so its velocity v₁ is 0.0 m/s. Substituting the given values, we have:
0.0 + (0.10 kg)(0.0 m/s) = (m₁ + 0.10 kg)(5.0 m/s),
0 = 5.0m₁ + 0.50 kg,
5.0m₁ = -0.50 kg,
m₁ = -0.50 kg / 5.0 = -0.10 kg.
Since mass cannot be negative, the mass of the particle at the origin is 0.10 kg.
The total momentum of the system is given by:
P_total = m₁v₁ + m₂v₂.
P_total = (0.10 kg)(0.0 m/s) + (0.10 kg)(5.0 m/s) = 0.0 kg·m/s + 0.50 kg·m/s = 0.50 kg·m/s.
Therefore, the total momentum of the system is 0.50 kg·m/s.
Since the particle at the origin has a mass of 0.10 kg and the total momentum of the system is 0.50 kg·m/s, we can calculate its velocity using the formula:
P_total = m₁v₁ + m₂v₂.
Plugging in the known values, we have:
0.50 kg·m/s = (0.10 kg)(v₁) + (0.10 kg)(5.0 m/s),
0.50 kg·m/s = 0.10 kg·m/s + 0.50 kg·m/s,
0.40 kg·m/s = 0.10 kg·m/s,
v₁ = (0.40 kg·m/s) / (0.10 kg) = 4.0 m/s.
Therefore, the velocity of the particle at the origin is 4.0 m/s.
To know more about momentum, refer here:
https://brainly.com/question/30677308#
#SPJ11
Complete question:
At one instant, the center of mass of a system of two particles is located on the x-axis at x=2.0m and has a velocity of (5.0m/s). One of the particles is at the origin.
The other particle has a mass of 0.10kg and is at rest on the x-axis at x= 8.0m.
1.What is the mass of the particle at the origin?
2. Calculate the total momentum of this system.
3. What is the velocity of the particle at the origin?
A simple rearrangement of Newton's law gives F net= ma. find a net force that is needed to give a 9.0!kg package an acceleration of 8.0m/s^2
The net force that is needed to give a 9.0 kg package an acceleration of 8.0 m/s² is 72.0 N.
Newton's law states that any object at rest or in motion with a constant velocity will remain so unless acted upon by an unbalanced force. If an unbalanced force is applied, the object will accelerate at a rate directly proportional to the force and inversely proportional to its mass, as given by the formula
F = ma.
When an object changes its state of motion, it accelerates. Its acceleration is determined by the magnitude and direction of the net force acting on it. It is defined as the rate of change of velocity with time, that is, a = (v-u)/t.
A net force of 72.0 N is required to give a 9.0 kg package an acceleration of 8.0 m/s².Fnet = ma (Newton's second law of motion)
Given that, m = 9.0 kg a = 8.0 m/s²,we have to find the net force Fnet.
Fnet = ma
= 9.0 kg × 8.0 m/s²
= 72.0 N.
To learn more on acceleration :
https://brainly.com/question/25876659
#SPJ11
which part of a centrifugal pump transmits energy in the form of velocity to the water? (299)
The impeller of a centrifugal pump is the component that transmits energy in the form of velocity to the water. It consists of curved blades or vanes that rotate, creating a centrifugal force that accelerates the fluid, increasing its velocity.
In a centrifugal pump, the impeller is responsible for transferring energy to the water in the form of velocity. The impeller is typically a wheel-like structure with curved blades or vanes.
When the pump is operational, the impeller rotates rapidly, drawing in water through the inlet. As the water enters the impeller, the curved blades exert a force on it, imparting angular momentum and causing it to move in a tangential direction.
Due to the centrifugal force generated by the rotating impeller, the water is propelled outward and accelerates as it moves away from the impeller's center.
This acceleration increases the water's velocity, transforming the potential energy into kinetic energy. The high-velocity water is then discharged from the impeller into the pump's volute or diffuser section, where the kinetic energy is gradually converted back into pressure energy.
The impeller is the crucial component of a centrifugal pump that transmits energy in the form of velocity to the water. Through its rotation and curved blades, it imparts angular momentum to the water, resulting in increased velocity and kinetic energy, which drives the flow of water through the pump system.
Learn more about centrifugal here:
https://brainly.com/question/12954017
#SPJ11
Four displacement vectors,
A, B, C, and D,
are shown in the diagram below. Their magnitudes are: A = 15.4 m, B = 11.0 m, C = 12.0 m, and D = 21.0 m.
What is the magnitude, in meters, and direction, in degrees, of the resultant vector sum of
A, B, C, and D?
Give the direction as an angle measured counterclockwise from the +x direction.
magnitude ?
direction?
they will not let me post a picture or paste the picture into the question (i will try again to make sure). but vetor A is near angle 20, vector c near angle 35, and vector d is near angle 50, with vector B being a straight line
To find the magnitude and direction of the resultant vector, we can use the parallelogram law of vector addition. Let's draw a diagram and label the angles as given.
Vectors A, C, and D have angles of approximately 20°, 35°, and 50° respectively with respect to the positive x-axis. Vector B is parallel to the positive x-axis. Let's draw these vectors in a diagram and add them up graphically using the parallelogram law of vector addition.
The magnitude of the resultant vector can be found using the Pythagorean theorem:
$$R=[tex]\sqrt{(A+B+C+D)^2}$$$$[/tex]= \s[tex]qrt{(15.4)^2+(11.0)^2+(12.0)^2+(21.0)^2+2(15.4)([/tex][tex]11.0)+2(15.4)(12.0)+2(15.4)(21.0)+2(11.0)(12.0)+2(11.0)(21.0)+2(12.0)[/tex][tex](21.0)}$$$$= 37.4 \ \text{m}$$[/tex]
Now, let's find the direction of the resultant vector. We can do this by finding the angle that the resultant vector makes with the positive x-axis. We can use the tangent function to find this angle:
$$\theta = [tex]\tan^{-1}\left(\frac{y}{x}\right)$$[/tex]
To know more about magnitude visit :
https://brainly.com/question/31022175
#SPJ11
We use plastic as outer covering on electrical wires.
A
True
B
False
The given statement "We use plastic as outer covering on electrical wires" is True.
Plastic is a synthetic polymer material that can be made into various forms such as films, fibres, tubes, etc. It is one of the most widely used materials for electrical wire insulation and jackets, primarily due to its strength, insulating properties, and durability.In electrical cables and wires, plastic insulation helps to protect conductors from damage by abrasion, moisture, and chemicals. Furthermore, it prevents electrical leakage by restricting the flow of current to the surrounding environment or other conductive objects. Therefore, we use plastic as outer covering on electrical wires.
To learn more about durability visit: https://brainly.com/question/2836376
#SPJ11
A 2,000-kg car is moving at a constant speed, on a flat, curved section of a road, whose radius is 200 m. Consider g=10 m/s2 and the coefficient of friction between the road and the car's tires as 0.3. Question 5 (1 point) a) The normal force on the car is 2,000 N [down]. 20,000 N [down]. 2,000 N [up] 20,000 N [up] Question 6 (1 point) b) The magnitude of the centripetal force on the car is given by Fcp=Ffriction Fcp=Ffriction −Fnormal Fcp=Ffriction +Fnormal Fcp=Ffriction −Fgravity c) The magnitude of the car's maximum acceleration, to be able to drive through the curve, is 3 m/s2 zero. 12 m/s2. 6 m/s2 Question 8 (1 point) d) The maximum speed of the car, to be able to drive through the curve, is 14.1 m/s. 24.5 m/s. 36.5 m/s 45.2 m/s.
a) The normal force on the car is 20,000 N [down]. b) The magnitude of the centripetal force on the car is given by Fcp = Ffriction + Fnormal. c) The magnitude of the car's maximum acceleration, to be able to drive through the curve, is 3 m/[tex]s^{2}[/tex]. d) The maximum speed of the car, to be able to drive through the curve, is 24.5 m/s.
a) The normal force is the force exerted by a surface perpendicular to the object. In this case, the car is on a flat road, so the normal force should be equal to the weight of the car. The weight of the car is given by mg, where m is the mass of the car and g is the acceleration due to gravity.
Therefore, the normal force is 20,000 N [down].
b) The centripetal force is the force that keeps an object moving in a curved path. In this case, the centripetal force is provided by the friction force between the car's tires and the road surface.
So, Fcp = Ffriction + Fnormal.
c) The maximum acceleration that the car can have to drive through the curve is determined by the friction force. The maximum static friction force can be calculated using the coefficient of friction and the normal force: Ffriction = μs * Fnormal. Substituting the given values, we find Ffriction = 0.3 * 20,000 N = 6,000 N.
Since acceleration is given by a = F/m, the maximum acceleration is a = 6,000 N / 2,000 kg = 3 m/[tex]s^{2}[/tex].
d) The maximum speed of the car to be able to drive through the curve can be determined using the centripetal force formula: Fcp = m * [tex]v^{2}[/tex] / r, where v is the velocity of the car and r is the radius of the curve. Rearranging the formula to solve for v,
we get v = [tex]\sqrt{\frac{Fcp*r}{m} }[/tex]. Substituting the given values, we find v = [tex]\sqrt{\frac{6000N *200 m}{2000kg} }[/tex] ≈ 24.5 m/s.
Learn more about acceleration here:
https://brainly.com/question/2303856
#SPJ11
A motorcyclist is coasting with the engine off at a steady speed of 20.0 m/s but enters a sandy stretch where the coefficient of kinetic friction is 0.70. If so, what will be the speed upon emerging? Express your answer to two significant figures and include the appropriate units.
A motorcyclist is coasting with the engine off at a steady speed of 20.0 m/s but enters a sandy stretch where the coefficient of kinetic friction is 0.70.
If so, what will be the speed upon emerging?The kinetic frictional force that acts on the motorcycle is given byf = μkNWhere,μk is the coefficient of kinetic friction and N is the normal force which is equal to the weight of the motorcycle,mg.
f = μkmgWe know that the force is equal to mass times acceleration,So,f = maHence,ma = μkmgSolving for a, we geta = μkg ...(1) Where g is the acceleration due to gravity, 9.8 m/s2.
When the motorcycle enters the sandy stretch, the force of friction will be equal and opposite to the force of gravity that acts on the motorcycle.
Ff = FgHence,μkmg = mg,μk = 1.0 Acceleration due to frictional forcea = μkg= 0.7 * 9.8 m/s²= 6.86 m/s² Now, using the formula of uniformly accelerated motion for the final velocity,v² - u² = 2aswherev = final velocityu = initial velocitys = distancea = acceleration We know that the initial velocity is 20 m/s, acceleration is -6.86 m/s² (negative because the direction of frictional force opposes the direction of motion) and distance is unknown.
To know more about coefficient visit
https://brainly.com/question/29993529
#SPJ11
The velocity of a particle is given by v=26t
2
−88t−220, where v is in feet per second and t is in seconds. Plot the velocity v and acceleration a versus time for the first 6 seconds of motion. After you have the plots, answer the questions as a check on your work. Questions: When t=0.8sec,v= ft/sec,a= ft/sec
2
When t=3.4sec,v= ft/sec,a= ft/sec
2
When the acceleration is zero, the velocity is
Given that the velocity of a particle is given by v = 26t² − 88t − 220 feet per second and time is t in seconds. The acceleration a is the rate of change of velocity of the particle. So the acceleration of a particle can be calculated as a=dv/dt. When acceleration is zero, the velocity is a constant and therefore, it is not possible for acceleration to be zero while velocity is changing.
Here, the velocity of a particle v = 26t² − 88t − 220 feet per second.
Therefore, acceleration a = dv/dt = (d/dt) (26t² − 88t − 220)
Using power rule of differentiation, we get
d/dt (26t² − 88t − 220) = 52t − 88ft/sec²
Therefore, the acceleration of the particle is given by a = 52t − 88ft/sec².
We can observe that when t = 0.8 sec, v = - 47.04 ft/sec and a = 6.4 ft/sec²
When t = 3.4 sec, v = - 197.24 ft/sec and a = 108.8 ft/sec²
When acceleration is zero, the velocity is a constant.
Therefore, it is not possible for acceleration to be zero while velocity is changing.
The above values of acceleration a and velocity v are not correct.
Thus, the above values of acceleration a and velocity v are not correct.
Read more about The velocity of a particle.
https://brainly.com/question/28609643
#SPJ11
X-rays of wavelength λ=1.3A˚, incident on a crystal, are diffracted at an angle, in the first order, of 22°. What is the interplanar spacing?
The interplanar spacing is approximately 1.734 Å. The interplanar spacing can be determined using Bragg's law.
The interplanar spacing can be determined using Bragg's law, which states that for constructive interference to occur, the path difference between two adjacent crystal planes must be an integer multiple of the wavelength. In this case, the first-order diffraction angle (θ) is given as 22°, and the wavelength (λ) is given as 1.3 Å (angstroms).
To calculate the interplanar spacing, we can use the formula:
d = λ / (2sinθ)
where d represents the interplanar spacing and θ is the diffraction angle.
Plugging in the given values, we have:
d = (1.3 Å) / (2sin(22°))
Calculating the value:
d ≈ 1.3 Å / (2sin(22°))
≈ 1.3 Å / (2 x 0.3746)
≈ 1.3 Å / 0.7492
≈ 1.734 Å
Therefore, the interplanar spacing is approximately 1.734 Å.
Learn more about Bragg's law here:
brainly.com/question/29195108
#SPJ11
Which of the following is not listed in order of increasingvapor pressure?
A. H2O < H2S
B. C7H16 < C5H12
C. Kr < Xe
D. CH3CH2OH < CH3-O-CH3
The correct is option B. C7H16 < C5H12. is not listed in the correct order of increasing vapor pressure.
The vapor pressure of a substance is a measure of its tendency to evaporate and is generally influenced by factors such as temperature and intermolecular forces. In the given options, the substances are listed in order of increasing vapor pressure except for option B.
In option B, C7H16 (heptane) is listed before C5H12 (pentane), suggesting that heptane has a lower vapor pressure than pentane. However, in reality, heptane has a higher vapor pressure compared to pentane. Heptane has a greater number of carbon atoms and exhibits stronger intermolecular forces, resulting in a lower tendency to vaporize and thus a lower vapor pressure compared to pentane.
Therefore, option B is not listed in the correct order of increasing vapor pressure.
To learn more about vapor pressure
https://brainly.com/question/2272852
#SPJ11
An airplane pilot sets a compass course due west and maintains an airspeed of 221 km/h. After flying for a time of 0.480 h, she finds herself over a Part C town a distance 120 km west and a distance 11 km south of her starting point. If the wind velocity is 35 km/h due south, in what direction should the pilot set her course to travel due west? Use the same airspeed of 221 km/h. Express your answer as angle measured north of west
The pilot should set her course approximately 182.76 degrees north of west to travel due west.
To determine the direction the pilot should set her course to travel due west, we need to consider the effects of both the airplane's airspeed and the wind velocity.
Let's break down the situation:
The pilot's airspeed is 221 km/h, and she flies for 0.480 hours. Therefore, the distance covered in the air is (221 km/h) * (0.480 h) = 106.08 km.
The pilot finds herself over a town that is 120 km west and 11 km south of her starting point. This means the displacement caused by the wind is 120 km west and 11 km south
Since the wind is blowing due south at a velocity of 35 km/h, the displacement caused by the wind in 0.480 hours is (35 km/h) * (0.480 h) = 16.8 km south.
Now, we can calculate the net displacement of the airplane by subtracting the displacement caused by the wind from the total displacement:
Net displacement north = 11 km - 16.8 km = -5.8 km (southward)
Net displacement west = 120 km
To determine the angle measured north of west, we can use trigonometry. The tangent of the angle is the ratio of the north displacement to the west displacement:
tan(angle) = (-5.8 km) / (120 km)
Using inverse tangent (arctan) to find the angle, we get:
angle = arctan((-5.8 km) / (120 km))
Calculating this angle yields approximately -2.76 degrees.
Since we are looking for the direction north of west, we can express the answer as 182.76 degrees (180 degrees + 2.76 degrees) north of west.
Therefore, the pilot should set her course to travel approximately 182.76 degrees north of west to counteract the effects of the wind and maintain a due west heading.
Learn more about Navigation
brainly.com/question/32109105
#SPJ11
what is it called when two mirrors facing each other
When two mirrors are placed facing each other, it creates a phenomenon known as "mirror reflection" or "infinite reflection." This occurs as the light reflects back and forth between the mirrors, creating multiple reflections that appear to stretch infinitely into the distance.
The reflection continues on and on until it becomes too small to see. In this way, a person sees many reflections of themselves, and each reflection is smaller than the previous one. This is called an infinity mirror or a mirror tunnel.An infinity mirror is a visual illusion that looks like the mirror has no end. It is accomplished by placing a mirror in front of another and allowing a small amount of space between the two. Then, light is reflected back and forth in the space between the mirrors, generating an infinite loop of images.
To learn more about reflection visit: https://brainly.com/question/29788343
#SPJ11
An LC circuit consists of a 3.25 mH inductor and a 3.5 μF
capacitor.
a) Find its impedance Z at 65 Hz in Ω.
b) Find its impedance Z at 7 kHz in Ω.
a) At a frequency of 65 Hz, the impedance (Z) of the LC circuit can be calculated using the formula Z = √(R² + (XL - XC)²). Given that the resistance (R) is 0 ohms, the inductive reactance (XL) is 1.0648 ohms, and the capacitive reactance (XC) is 400.18 ohms, we can substitute these values into the formula. Thus, Z = √(0² + (1.0648 - 400.18)²) = 400.17 ohms, approximately.
b) At a frequency of 7 kHz, using the same formula, the resistance (R) being 0 ohms, the inductive reactance (XL) is 66.617 ohms, and the capacitive reactance (XC) is 2.2144 ohms. Plugging in these values, we get Z = √(0² + (66.617 - 2.2144)²) = 66.63 ohms, approximately.
Therefore, the impedance of the LC circuit at a frequency of 65 Hz is approximately 400.17 ohms, and at a frequency of 7 kHz is approximately 66.63 ohms.
To learn more about impedance in LC circuits and related topics, click this link:
brainly.com/question/12994232
#SPJ11
Consider the force F = -axi- byj - cz² k, where a, b, and c are constants. a) Is the force conservative? Show work. (4pts) b) If so, find the corresponding potential energy function U. (4pts) c) Find the work done by the force in moving an object from the origin
a) The force is non-conservative.
b) It does not have a potential energy function
c) The work done by the force is `(-3a + 12b - 5c)/10`.
Consider the force `F = -axi- byj - cz² k` where `a`, `b`, and `c` are constants. The solution is as follows:
a) The force F is conservative if and only if the curl of F is equal to zero.`∇ x F = ∂(cz²) / ∂y - ∂(-by) / ∂z + ∂(-ax) / ∂z ≠ 0`
Therefore, the force is non-conservative.
b) The force is non-conservative, hence it does not have a potential energy function U. Therefore, the second part of the question is incorrect.
c) The work done by the force in moving an object from the origin is the line integral of the force F from the origin to the final point P.
This can be written as:`W = ∫_C F.dl`
The path C from the origin O to point P can be parametrized as:r(t) = ti + t²j + t³k, where 0 ≤ t ≤ 1.`dr/dt = i + 2tj + 3t²k`
Hence, the line integral of F from O to P is:
`W = ∫_C F.dl`
`W = ∫_0¹ F.(dr/dt)dt`
`W = ∫_0¹(-at)i - (bt²)j - (ct⁴)k.(i + 2tj + 3t²k)dt`
`W = ∫_0¹(-at)dt - ∫_0¹ bt²(2t)dt - ∫_0¹ ct⁴(3t²)dt`
`W = [-a/2 t²]_0¹1 - [2b/5 t⁵]_0¹ - [3c/6 t⁷]_0¹`
`W = -a/2 - 2b/5 - 3c/6`
`W = (-3a + 12b - 5c)/10`
Hence, the work done by the force in moving an object from the origin is `(-3a + 12b - 5c)/10`.
Learn more about potential function at
https://brainly.com/question/14214954
#SPJ11
What is the weight of a 2.50-kg sandbag on the surface of the earth?
d. 49.0N
e. 98.0N
c. 24.5N
a. 2.50N
b. 9.80N
A rock is suspended from a rope and is accelerating upward. Which of the following statements is true regarding the tension in the string?
c. The tension is the same as the weight of the rock.
b. The tension is less than the weight of the rock.
a. The tension points down.
d. The tension is greater than the weight of the rock.
e. The stress is independent of the magnitude of the rock's acceleration.
The tension in a rope supporting a rock that is accelerating upward is greater than the weight of the rock. The weight of a 2.50 kg sandbag on the surface of the Earth is 24.5 N.
The weight of an object is the force exerted on it due to gravity. On the surface of the Earth, the weight of an object can be calculated by multiplying its mass by the acceleration due to gravity (9.8 m/s^2):
Weight = mass * acceleration due to gravity
Weight = 2.50 kg * 9.8 m/s^2
Weight = 24.5 N
Therefore, the weight of a 2.50 kg sandbag on the surface of the Earth is 24.5 N, so the correct answer is option c. 24.5N.
When a rock is suspended from a rope and accelerating upward, the tension in the string is greater than the weight of the rock. This is because the tension in the rope must provide an additional force to overcome the gravitational force acting on the rock and accelerate it upward. The tension in the rope is equal to the sum of the weight of the rock and the additional force required to produce the acceleration. Therefore, the correct answer is option d. The tension is greater than the weight of the rock.
Learn more about tension here:
brainly.com/question/29763438
#SPJ11
Which of the following statements about novae is not true? When a star system undergoes a nova, it brightens considerably, but not as much as a star system undergoing a supernova. A nova involves fusion taking place on the surface of a white dwarf. A star system that undergoes a nova may have another nova sometime in the future. Our Sun will undergo at least one nova when it becomes a white dwarf about 5 billion years from now.
The statement that is not true among the given statements is: When a star system undergoes a nova, it brightens considerably, but not as much as a star system undergoing a supernova.
Novae are stellar explosions that happen in binary star systems when one-star moves close enough to the other to transfer material onto the second star’s surface. The sudden arrival of this hydrogen-rich material creates a dense and hot layer on the white dwarf’s surface.
This surface layer becomes so hot and compressed that nuclear fusion happens, which results in a bright outburst of energy and light. The transferred hydrogen from the companion star on the white dwarf’s surface creates a dense, hydrogen-rich layer, which ignites in a runaway fusion reaction, resulting in a nova.
The following are the true statements about Novae:
The star system that had a nova could have another nova in the future. This is because novae are recurrent phenomena, and a white dwarf can accrete more matter from its binary companion star, causing another nova to occur.
Our Sun will go through a minimum of one nova before becoming a white dwarf in around 5 billion years. The sun will eventually die and evolve into a white dwarf, where it will slowly cool over billions of years. If the sun accumulates enough material from a nearby companion star, it may undergo one or more novae, but it is unlikely to undergo a supernova.
You can learn more about Supernova at: brainly.com/question/32402054
#SPJ11
Aluminium of mass 0.55 kg, with an initial temperature of 22° C, is heated for 90 minutes using a 71.474W power source. During this time the Aluminium reaches its melting temperature of 660.3° C and is partially melted. Assume no energy is lost to the surroundings. Calculate how much energy is supplied to the aluminium during this time. Round your answer to 3 significant figures.
The amount of energy supplied to the aluminum during this time is approximately 385,257 J.
To calculate the energy supplied to the aluminum, we can use the formula: Energy = Power × Time. Given that the power source has a power of 71.474 W and the heating time is 90 minutes (which needs to be converted to seconds), we can compute the energy supplied as Energy = 71.474 W × 90 minutes × 60 seconds/minute = 385,257 J.
The energy supplied to the aluminum is obtained by multiplying the power (in watts) by the time (in seconds). In this case, the power source provides a constant power of 71.474 W throughout the 90 minutes of heating. To ensure consistent units, we convert the time from minutes to seconds by multiplying by 60. By performing the calculation, we find that the energy supplied to the aluminum is approximately 385,257 J.
Learn more about Aluminum
brainly.com/question/28989771?
#SPJ11
