Greater than 0 is the change in entropy (AS) when a solid substance decomposes and produces gaseous products. The correct option is B.
The change in entropy (ΔS) is a measure of the degree of randomness or disorder in a system. When a solid substance decomposes and produces gaseous products, the number of particles (molecules or atoms) in the system increases, and the arrangement of the particles becomes more disordered. This results in an increase in entropy, which is greater than 0.
When a solid substance decomposes and produces gaseous products, the change in entropy (ΔS) is greater than 0. This is because the number of particles in the system increases, leading to an increase in disorder or randomness.
The entropy of a system is a measure of the degree of disorder, and it tends to increase in processes that lead to a greater dispersion of energy or matter. In the case of the decomposition of a solid substance into gaseous products, the transition from a more ordered solid state to a more disordered gas state leads to an increase in entropy.
This phenomenon is a manifestation of the second law of thermodynamics, which states that the entropy of a closed system tends to increase over time.
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Part 1(Picture 1):
Peptides isolated from rapeseed that may lower blood pressure have the following sequence of amino acids.
Part A
At physiological pH the N-terminus of an amino acid exists as the ammonium ion, and the C-terminus exists as the carboxylation ion.
Draw the structure of Arg-Ile-Tyr.
Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and charges), Atoms, and Templates toolbars, including charges where needed.
Part 2(Picture 2):
Part A
What are the amino acids in the peptide?
Spell out the full names of the compounds. Enter your answers separated by a comma.
Part B
How would you name the dipeptide in the peptide?
Spell out the full name of the compound.
The structure of Arg-Ile-Tyr is given below:
What are Peptides?Peptides make up short chains of amino acids, which act as the fundamental units for building proteins. Within these chains, peptides usually consist of no more than 50 amino acids in contrast to proteins that are made up of significantly longer structures.
Found throughout various sources such as plants, animals, and bacteria, peptides play crucial roles in multiple biological processes including signaling, enzyme activity, and immune response.
Additionally, artificially synthesized peptides serve several purposes within the medicine, cosmetics, and food industries. Scientists are also exploring certain peptide's potential therapeutic advantages mainly pertaining to anti-inflammatory, antimicrobial, and anticancer activities.
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What are some potential real-world applications for renewable energy sources such as solar power and wind power?
The some of the potential in the real world applications for the renewable energy sources such as the solar power and the wind power are electricity generation, the water heating and cooling, and the transportation.
Renewable energy defined as the energy produced from the sources like the sun and the wind energy which are the naturally replenished and which do not run out.
The Renewable energy which can be used for the electricity generation, and the water heating and the cooling, and the transportation. The most sustainable sources of the energy are the renewable bioenergy. The Renewable sources of the, like the wind and the solar, it will emit the little to no the greenhouse gases.
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1. Explain how you would determine the enthalpy of reaction for the hypothetical reaction A2X4(l) + X2(g) → 2AX3(g) using the following information. You do not need to calculate an answer. Respond to the prompt with a minimum response length of 50 words.
we can determine the enthalpy of reaction for the hypothetical reaction A2X4(l) + X2(g) → 2AX3(g) using the following steps:
write the balanced chemical equation for the reactionwe obtain the standard enthalpies of formation for each compoundwe apply Hess's law calculate the enthalpy of reactionwe then add up the changes to get the total enthalpy change for the reaction State Hess law?Hess's Law of Constant Heat Summation states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes.
The law is Hess's Law of Constant Heat Summation is described as a manifestation that enthalpy is a state function.
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What did the Constitutional Convention decide to do about the slave trade?(1 point)
Responses
It expanded it.
It expanded it.
It restricted it to slave states.
It restricted it to slave states.
It banned it.
It banned it.
It delayed taking action.
Americium-241 is used in some smoke detectors. It is an alpha emitter with a half-life of 432 years
. How long will it take in years for 45.0 %
of an Am-241 sample to decay?
Express your answer with the appropriate units.
It will take 585.5 years for 45.0% of the Am-241 sample to decay.
Half-life calculationThe half-life of Am-241 is 432 years, which means that half of the sample will decay in 432 years. We can use the half-life formula to find the time it takes for a certain percentage of the sample to decay:
N(t) = N₀(1/2)^(t/T)
where:
N(t) is the amount of Am-241 remaining after time tN₀ is the initial amount of Am-241T is the half-life(1/2)^(t/T) is the fraction of Am-241 remaining after time t.We want to find the time it takes for 45.0% of the sample to decay, so we can set N(t) equal to 0.450 N₀ and solve for t:
0.450 N₀ = N₀(1/2)^(t/T)0.450 = (1/2)^(t/T)Taking the natural logarithm of both sides:
ln(0.450) = ln(1/2)^(t/T)ln(0.450) = -(t/T)ln(2)t/T = -ln(0.450)/ln(2)t = -ln(0.450)/ln(2) x Tt = -ln(0.450)/ln(2) * 432 yearst = 585.5 yearsIn other words, it will take 585.5 years for 45.0% of the Am-241 sample to decay.
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explain how to prepare aluminium hydroxide starting with aluminium sulphate
We can see here that in preparing aluminum hydroxide starting with aluminum sulphate, we have:
Aluminum sulfate should be dissolved with water to create a solution. [tex]Al_{2} (SO_{4})^{3} + 6H_{2}O[/tex] → [tex]Al(OH)^{3} + 3H_{2} SO_{4}[/tex] is the solution.Ammonium hydroxide addition: While continually stirring the mixture, gradually add ammonium hydroxide. Aluminum hydroxide precipitates as a white gelatinous precipitate thanks to the ammonium hydroxide's role as a precipitating agent.What is aluminum hydroxide?Chemically speaking, aluminum hydroxide has the formula Al(OH)3. It is an amorphous, white powder that has no smell and is insoluble in water.
Continuation of preparation of aluminum hydroxide:
For the aluminum hydroxide to completely precipitate, the mixture needs to be stirred for a few minutes.Filter the mixture: Use filter paper to remove the precipitate from the solution by filtering the mixture.Wash the precipitate: To get rid of any contaminants, wash the precipitate with water.Dry the precipitate: To produce pure aluminum hydroxide and remove any leftover water, dry the precipitate in an oven at a low temperature.Learn more about aluminum hydroxide on https://brainly.com/question/28272266
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if two substance are at the same temperature, their enthalpy
Answer:
cannot be measure
Hope this helps :) !!!
why mendeleev's periodic law is an important milestone in the study of chemistry. write any four reasons
Answer:
1. Organized information: Mendeleev's periodic law helped organize the then-disparate information about elements into a system that made sense. This made it easier for chemists to understand the nature of the elements and make predictions about their behavior.
Imagine that you have a 7.00 L
gas tank and a 2.00 L
gas tank. You need to fill one tank with oxygen and the other with acetylene to use in conjunction with your welding torch. If you fill the larger tank with oxygen to a pressure of 155 atm
, to what pressure should you fill the acetylene tank to ensure that you run out of each gas at the same time? Assume ideal behavior for all gases.
We need to fill the acetylene tank to a pressure of 44.29 atm to ensure that we run out of each gas at the same time.
The acetylene tank pressureTo solve this problem, we need to apply the ideal gas law:
PV = nRT
Applying the ideal gas law for each tank,
PV = NkT
where N is the number of particles, k is Boltzmann's constant, and T is the temperature.
For oxygen:
(155 atm) * (7.00 L)
= N1 * k * T
For acetylene:
(P2) * (2.00 L)
= N2 * k * T
To use up both gases at the same time, we need to use the same number of moles of each gas. So we can set N1 equal to N2:
N1 = N2
Combining the two equations above to solve for P2:
(155 atm) * (7.00 L) = (N1) * k * T
(P2) * (2.00 L) = (N1) * k * T
Dividing the second equation by the first,
P2/P1 = (2.00 L)/(7.00 L)
P2 = (2.00 L)/(7.00 L) * (155 atm)
P2 = 44.29 atm
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A sample of ammonia gas has a volume of 3218 mL at 13°C and a pressure of 824 torr. What will the volume of the gas be in liters if the moles of gas and the temperature do not change but the pressure changes to 2.36 atm?
The final volume of the gas at a pressure of 2.36 atm is 1.188 L.
The first step is to convert the initial volume to liters and the initial pressure to atm:
V₁ = 3218 mL = 3.218 L
P₁ = 824 torr = 1.084 atm
Using the combined gas law equation: P₁V₁/T₁ = P₂V₂/T₂
We can solve for V₂, the final volume:
V₂ = (P₁V₁T₂) / (P₂T₁) = [(1.084 atm) x (3.218 L) x (286 K)] / [(2.36 atm) x (286 K)] = 1.188 L
As a result, the ultimate volume of the gas at 2.36 atm is 1.188 L.
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I need the math to it to show how I got to the answer, please help #2
The number of moles of the water produces by the 1.3 moles of O₂ is 1.00 mol of H₂O. The correct option is C.
The chemical equation is as :
2C₄H₁₀ + 13O₂ ----> 8CO₂ + 10H₂O
The moles of the O₂ = 1.3 moles H₂O
The molar mass of the O₂ = 32 g/mol
2 moles of the C₄H₁₀ produces the 10 moles of the water,
13 moles of O₂ produces the 10 moles of H₂O
The moles of the H₂O = (10/13) × 1.3
The moles of the H₂O = 1 mol
The number of moles of the water is 1 mol of the H₂O and the moles of the oxygen that is O₂ is the 1.3 moles.. Therefore, the correct option is C.
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A sample of 23.3 g of a candy bar was burned in a calorimeter. The calorimeter was calibrated to have a heat capacity of 8.72 kcal/ °C. The heat released caused the temperature of the calorimeter to increase 15.5 °C.
Calculate the food caloric content of the candy bar in nutritional calories per gram to three significant figures. Recall that 1 nutritional calorie (Cal) = 1 kcal.
The food caloric content of the candy bar is approximately 167 Cal/g.
The first step is to calculate the heat released by the candy bar, which is equal to the heat absorbed by the calorimeter:
q = m × C × ΔT
where q is the heat released by the candy bar, m is the mass of the candy bar, C is the heat capacity of the calorimeter, and ΔT is the temperature change of the calorimeter.
Plugging in the given values, we get:
q = (23.3 g) × (8.72 kcal/°C) × (15.5 °C) = 3,884.6 cal
Next, we need to convert the heat released to nutritional calories per gram:
Cal/g = q/m
Cal/g = 3,884.6 cal / 23.3 g = 166.6 Cal/g ≈ 167 Cal/g (to three significant figures)
As a result, the candy bar's food caloric value is roughly 167 Cal/g.
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please provide explanation!! thank you in advance!!
In the given reaction, CO + H [tex]_2[/tex] O ⇌ CO[tex]_2[/tex] + H[tex]_2[/tex], the equilibrium concentration of CO[tex]_2[/tex] and H[tex]_2[/tex] is 0.0113M. The equilibrium concentration of CO and H [tex]_2[/tex] O is 0.0113M.
When the observable qualities, like colour, temperature, pressure, concentration, etc. do not vary, the process is said to be in equilibrium. As "balance" is the definition of the word "equilibrium," it follows which a chemical reaction reflects a balance among the substances and outcomes involved in the reaction. In the given reaction, CO + H [tex]_2[/tex] O ⇌ CO[tex]_2[/tex] + H[tex]_2[/tex], the equilibrium concentration of CO[tex]_2[/tex] and H[tex]_2[/tex] is 0.0113M. The equilibrium concentration of CO and H [tex]_2[/tex] O is 0.0113M.
Therefore, the correct option is option A.
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Consider this reaction taking place in a closed 2 liter container:
2SO2(g) + O2(g) → 2SO3(g)
If the volume of the container is decreased to 1 liter, what will happen to the equilibrium of the reaction?
Question 16 options:
It will shift left.
It will remain constant.
It will shift right.
It will decrease by half.
The energy required to dissociate the Cl2 molecule to Cl atoms is 239 kJ/mol Cl2. If the dissociation of a Cl2 molecule were accomplished by the absorption of a single photon whose energy was exactly the quantity required, what would be its wavelength (in meters)?
Explanation:
The energy of a single photon can be calculated using the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J.s), c is the speed of light (2.998 x 10^8 m/s), and λ is the wavelength of the photon.
To dissociate one mole of Cl2 molecules, we need 239 kJ of energy. This corresponds to 239,000 J/mol of Cl2.
Now we can use the relationship between energy and the number of photons absorbed: E = Nhf, where N is the number of photons absorbed, h is Planck's constant, and f is the frequency of the absorbed photons.
We can relate the frequency of the absorbed photon to its wavelength using c = λf. Solving for f gives f = c/λ.
Combining these equations, we get E = Nh(c/λ), or N = E/(hc/λ). Substituting the value of E for the energy required to dissociate one mole of Cl2, we get:
N = (239,000 J/mol) / [(6.626 x 10^-34 J.s) x (2.998 x 10^8 m/s) / λ]
Solving for λ, we get:
λ = hc / (239,000 J/mol) = (6.626 x 10^-34 J.s x 2.998 x 10^8 m/s) / 239,000 J/mol
λ = 8.44 x 10^-7 m
Therefore, the wavelength of the photon required to dissociate one Cl2 molecule is approximately 8.44 x 10^-7 meters (or 844 nanometers).
What is the molarityof a 150ml of solution containing 5g of copper (1) chlorate
The molarity of 150 mL solution containing 5g of copper (1) chlorate is 0.0051 M
How do i determine the molarity of the solution?We'll begin by obtaining the number of mole in 5 g of copper (i) chlorate. This is shown below:
Mass of copper (i) chlorate = 5 grams Molar mass of iodine = 147 g/molMole of copper (i) chlorate = ?Mole = mass / molar mass
Mole of copper (i) chlorate = 5 / 147
Mole of copper (i) chlorate = 0.034 mole
Now, we shall determine the molarity of the solution. Details below:
Mole of copper (i) chlorate = 0.034 moleVolume of solution = 150 mL = 150 / 1000 = 0.15 LMolarity of solution = ?Molarity of solution = mole / volume
Molarity of solution = 0.034 / 0.15
Molarity of solution = 0.0051 M
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Given the law of conservation of energy, what happens when a 200°C iron bar is placed in thermal contact with a 30°C block of wood?
When a 200°C iron bar is placed in thermal contact with a 30°C block of wood, energy leaves the iron bar and enters the wood until the temperatures are equal.
Law of conservation of energy states that the energy cannot be lost or formed but it can only be transformed from one form to another.
According to the given question, the block of wood is at a lower temperature than an iron bar. Hence, heat will flow from the iron bar to the block of wood until the temperatures of both are equal.
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If 0.225 mol of an ideal gas has a volume of 1923 mL and a pressure of 6.00 atm, what is its temperature in degrees Celsius?
Use one of the following values:
R = 0.0821 atm • L/mol • K
R = 8.31 kPa • L/mol • K
R = 62.4 torr • L/mol • K
The temperature (in °C) given that 0.225 mole of an ideal gas has a volume of 1923 mL and a pressure of 6.00 atm is 351.6 °C
How do i determine the temperature of the ideal gas?First, we shall list out the various parameters obtained from the question. This is shown below:
Number of mole of ideal gas (n) = 0.225 moleVolume of ideal gas (V) = 1923 mL = 1923 / 1000 = 1.923 LPressure (P) = 6 atmGas constant (R) = 0.0821 atm.L/mol KTemperature of ideal gas (T) =?The temperature of the ideal gas can be obtain as follow:
PV = nRT
6 × 1.923 = 0.225 × 0.0821 × T
11.538 = 0.0184725 × T
Divide both sides by 0.0184725
T = 11.538 / 0.0184725
T = 624.6 K
Subtract 273 to obtain answer in °C
T = 624.6 - 273 K
T = 351.6 °C
Thus, we can conclude that the temperature of the ideal gas is 351.6 °C
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Le Chatelier's Principle states that when a reaction that was in equilibrium is stressed through the change in concentration, change in temperature or change in pressure, then the chemical reaction will:
a. adjust to re-reach equilibrium
b. create only products
c. become no longer in equilibrium
d. shut down entirely
Answer:
a. adjust to re-reach equilibrium
Explanation:
Le Chatelier's Principle can be logically understood based on the concept of equilibrium in chemical reactions. When a chemical reaction is in equilibrium, it means that the rate of the forward reaction (from reactants to products) is equal to the rate of the reverse reaction (from products to reactants), and the concentrations of reactants and products remain constant over time.
When an equilibrium reaction is subjected to a stress, such as a change in concentration, temperature, or pressure, it disrupts the original balance between reactants and products. In response to this stress, Le Chatelier's Principle predicts that the system will adjust its position of equilibrium to counteract the change and restore balance.
For example, if the concentration of one of the reactants is increased, the system will shift the equilibrium position to the side that consumes that reactant in order to reduce its concentration and restore the original balance. Similarly, if the temperature of the system is increased, the system will shift the equilibrium position in the endothermic or exothermic direction to counteract the change in temperature. If the pressure of the system is increased, the system will shift the equilibrium position to the side with fewer moles of gas in order to reduce the pressure.
In other words, Le Chatelier's Principle states that a system at equilibrium will adjust its position of equilibrium in response to external stresses in order to re-establish a new equilibrium and restore balance between reactants and products. This logical understanding helps to explain why option a, "adjust to re-reach equilibrium," is the correct answer.
3.
(08.04 LC)
Which of the following is a base? (3 points)
AgO
Ca(OH)2
HF
NaCl
The compound that is a base from the given list is Ca(OH)2. Option 2.
What is a base?
A base is a chemical substance that produces hydroxyl ions as the only negative ion in aqueous solutions.
Ca(OH)2 is calcium hydroxide, which is a chemical compound consisting of one calcium ion (Ca2+) and two hydroxide ions (OH-).
It is classified as a base because, when it dissolves in water, it produces hydroxide ions that can accept protons (H+) from acids in a process known as a neutralization reaction.
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The concentration of an aqueous solution of NaCl is 15% by mass. How much NaCl is in a 500 gram sample of the solution?
a. 425 grams
b. 750 grams
c. 75 grams
d. 330 grams
Answer:
To solve this problem, we can use the definition of percent concentration by mass:
percent concentration = (mass of solute ÷ mass of solution) x 100%
We know that the percent concentration of NaCl in the solution is 15% by mass, and we have a 500 gram sample of the solution. Let's assume that the mass of NaCl in the sample is x grams.
Using the percent concentration formula, we can write:
15% = (x ÷ 500) x 100%
Simplifying this equation, we get:
x = (15 ÷ 100) x 500 = 75 grams
Therefore, there are 75 grams of NaCl in a 500 gram sample of the solution.
The correct answer is c. 75 grams.
(30 pts) Please find the correct answer.
20. At its closest approach, Mars is 56 million km from Earth. How long would a radio message from a space probe on Mars take to reach Earth when the planets are at this distance?
Answer:
The time it takes for a radio message to travel from a space probe on Mars to Earth when the planets are at a distance of 56 million km can be calculated using the speed of light which is about 299,792,458 meters per second.
To convert the distance from kilometers to meters, we multiply 56 million km by 1000 to get 56 x 10^6 km = 5.6 x 10^10 m.
The time it takes for a radio signal to travel from Mars to Earth is:
time = distance/speed
time = 5.6 x 10^10 m / 299,792,458 m/s
time = 187 seconds
Therefore, a radio message from a space probe on Mars would take about 187 seconds, or just over 3 minutes, to reach Earth when the planets are at a distance of 56 million km.
Which statement is true about cytokinesis?
*
2 points
Chromosomes start to decompress
Chromosomes are pulled towards the poles
A cell plate forms in plant cells
The nuclear envelope breaks down
The correct statement about cytokinesis is that a cell plate forms in plant cells. Option C is correct.
During cytokinesis, the cytoplasm of the parent cell divides into two daughter cells, each with its own nucleus and organelles. In animal cells, a contractile ring made of actin and myosin filaments forms around the cell's equator and contracts, pinching the cell in two.
In contrast, plant cells build a cell plate, which forms from vesicles produced by the Golgi apparatus, at the cell's equator. These vesicles fuse together and form a new cell wall to separate the two daughter cells. The other three options mentioned in the question are related to mitosis, which is the division of the nucleus, whereas cytokinesis is the division of the cytoplasm. Option C is correct.
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What’s a zinc cup made of
Answer:
constructed as a cylindrical container for the battery cell, and a carbon rod surrounded by a compound with a higher Standard electrode potential (positive polarity), known as the cathode, that collects the current from the manganese dioxide electrode
Explanation:
is this what you are talking about?
A scientist is designing a space probe that will be sent to Jupiter to analyze the atmosphere there. Before building a full-scale version of the probe, the scientist is going to build a model of it to test whether the probe can withstand the extreme environmental conditions of Jupiter's atmosphere. These extreme conditions include cold temperatures, strong gravitational forces, and high winds. Urgent!!!!!
Which of the following would most likely be the same about the scientist's model probe and the eventual full-scale version of the probe?
A.
They would be the same size.
B.
They would be made of the same material.
C.
They would be able to hold the same amount of fuel.
What would be the same about the scientist's model probe and the eventual full-scale version of the probe is that; . They would be the same size. Option A
What is the conditions?It is likely that the scientist's model probe would be built to replicate the size and proportions of the full-scale version because this would be vital in determining if the full-scale probe could endure the punishing conditions of Jupiter's atmosphere. The dimensions of the model probe and the real probe would therefore likely be the same.
However, it's likely that the model probe's parts weren't exactly the same as those in the actual probe.
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Malic Acid is found in?
Hydrochloric Acid is found in?
Potassium Hydroxide is found in?
Sodium Hydroxide is found in?
Answer:
Malic Acid is found in Apples.
Hydrochloric Acid is found in Our Stomach.
Potassium Hydroxide is found in Soaps and Bleaches.
Sodium Hydroxide is found in Household Cleaners.
Explanation:
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Answer:
Its wrong the question is wrong you should delete it
Use the bond energies given below to calculate the enthalpy change for the reaction, HCN(g) + 2 H₂(g) → CH3NH₂(g)
Bond Bond Energy (kJ/mol) Bond Bond Energy (kJ/mol)
H-H
432
C-H
413
C-N
305
615
CEN
891
391
O-158 kJ
+18 kJ
-590 kJ
+158 kJ
+133 kJ
C=N
N-H
The enthalpy change for the given reaction is 1344 kJ/mol.
First, we need to write the balanced chemical equation for the given reaction:
HCN(g) + 2 H2(g) → CH3NH2(g)
To calculate the enthalpy change (ΔH) for this reaction, we need to subtract the total energy of the reactants from the total energy of the products. We can do this by calculating the energy required to break the bonds in the reactants and the energy released when new bonds are formed in the products.
Reactants:
HCN(g): 1 C-N bond (305 kJ/mol) + 1 C-H bond (413 kJ/mol) + 1 N-H bond (391 kJ/mol) = 1109 kJ/mol
2 H2(g): 4 H-H bonds (4 x 432 kJ/mol) = 1728 kJ/mol
Total energy of reactants: 1109 kJ/mol + 1728 kJ/mol = 2837 kJ/mol
Products:
CH3NH2(g): 1 C-H bond (413 kJ/mol) + 3 C-N bonds (3 x 305 kJ/mol) + 7 H-H bonds (7 x 432 kJ/mol) = 4181 kJ/mol
Total energy of products: 4181 kJ/mol
ΔH = (total energy of products) - (total energy of reactants)
ΔH = 4181 kJ/mol - 2837 kJ/mol
ΔH = 1344 kJ/mol
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For the cell shown, the measured cell potential, Ecell, is -0.3677 V at 25°C.
Pt(s) | H2(g,0.729atm) | H^+ (a,? M) || Cd^2+(aq,1.00M) | Cd(s)
The balanced reduction half-reactions for the cell, and their respective standard reduction potential values, E°, are
2H^+ (aq) + 2e^- --> H2(g) E° = 0.00 V
Cd^2+(aq) + 2e^- --> Cd(s) E° = -0.403V
Calculate the H^+ concentration.
The concentration of H⁺ is 1.0 x 10⁻⁷ M, under the condition that Ecell, is -0.3677 V at 25°C and 2H⁺ (aq) + 2e⁻-> H₂(g) E° = 0.00 VV
Here we have to calculate the H⁺ concentration
Now, we have to evaluate the cell potential at standard conditions applying the standard reduction potentials of the half-reactions
E°cell = E°reduction (cathode) - E°reduction (anode)
E°cell = 0.00 V - (-0.403 V)
E°cell = 0.403 V
Secondly, we need to evaluate the reaction quotient Q using the measured cell potential
Ecell = E°cell - (RT/nF)lnQ
-0.3677 V = 0.403 V - (0.0257 V/K)(298 K)/(2 mol e⁻/mol Cd²+)lnQ
lnQ = -1.02
[tex]Q = e^{-1.02}[/tex]
Q = 0.364
Hence, we could apply the balanced equation for the half-reaction involving H⁺ to calculate its concentration
2H⁺ + 2e⁻- --> H₂(g)
Kc = [H2]/[H⁺]²
Then, H2 is a gas and its concentration is negligible, we can consider that Kc is equal to the equilibrium constant for water
Kw = [H⁺][OH⁻]
Kw = 1.0 x 10⁻¹⁴
[H⁺] = √(Kw/Kc)
[H⁺] = √(1.0 x 10⁻¹⁴/1)
[H⁺] = 1.0 x 10⁻⁷ M
Hence, the H⁺ concentration is 1.0 x 10⁻⁷ M.
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which month do blackberries grow?
Blackberries start to grow in the months of late may and early june.
Seasonal fruits are those which grow only in particular time or season of the year. This is the reason why they can be produced fresh . There is no need of chemicals for their survival and appearance during their season. Also, it can be hand-picked when it is fully ripened, moreover it contains a rich taste and flavour. Blackberries that are containerized and hybrid berries can be planted at any time of the year. But, they best settle in between the late autumn and late spring. During the dormant season i.e from late autumn to spring bare-root plants are only available for immediate planting.
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