Question 10 of 10
The function F(x) = log5 x is decreasing.
A. True
B. False
SUBMIT

By the quadratic formula, the solution set of the quadratic equation is formed by two real roots: x₁ = 0 and x₂ = - 12.

Herein we have a quadratic equation of the form a · m² + b · m + c = 0, whose solution set can be determined by the quadratic formula:

x = - [b / (2 · a)] ± [1 / (2 · a)] · √(b² - 4 · a · c)      (1)

If we know that a = - 1, b = 12 and c = 0, then the solution set of the quadratic equation is:

x = - [12 / [2 · (- 1)]] ± [1 / [2 · (- 1)]] · √[12² - 4 · (- 1) · 0]

x = - 6 ± (1 / 2) · 12

x = - 6 ± 6

Then, by the quadratic formula, the solution set of the quadratic equation is formed by two real roots: x₁ = 0 and x₂ = - 12.

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Answer:

2^n

Step-by-step explanation:

So whenever you flip a coin, you can see it as 2 nodes branching off of each existing node. so for example when you flip a coin once you're going to have 2 sequences initially H and T, now when you flip a coin again for each of those 2 sequences 2 are going to branch off of that, making the total sequences 4, and the next flip 2 sequences are going to branch off each of the 4 sequences and so on. this can generally be described as: 2^n

I attached an image describing this a bit better but the bottom line is that for each 'end node'/sequence you're going to have 2 branch off of it, thus for each coin flip the number of sequences multiplies by 2

Answer:

2^n

Step-by-step explanation:

dont worry bout it ur welcome

Answer:

you better give me brainliest

65/79

Step-by-step explanation:

number if boys =79-14 = 65

p of selecting a boy >> 65/79

can't cancel out so leave your answer like that

The matrix exists as a set of numbers placed in rows and columns to create a rectangular array. The manager could achieve scalar multiplication on Matrix A, utilizing the scalar 1.15.

The matrix exists as a set of numbers placed in rows and columns to create a rectangular array. The numbers exist named the elements, or entries, of the matrix. Matrices contain wide applications in engineering, physics, economics, and statistics as well as in different branches of mathematics.

Increasing the price by 15% would mean we exist taking 100% of the value + another 15%

100 + 15 = 115%

115% = 115/100 = 1.15.

Multiplying every value in Matrix A by 1.15 will give the price raised by 15%.

Therefore, the correct answer is option c. by multiplying each entry of matrix a by 1.15.

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Answer:

C - by multiplying each entry by 1.15

Step-by-step explanation:

Edmentum.

Answer:

Yes

Step-by-step explanation:

The missing angle in triangle DER is 42 (as angles in a triangle add up to 180) and the missing angle in TVA (LOKI lol ) is 110 (as angles in a triangle add up to 180) .

Since all angles are equal the triangles must be similar .

Hope this helped and have a good day

The the biggest 5 digit number based on the computation will be 87,978.

The difference between the sum of the odd-numbered digits (1st, 3rd, 5th...) and the sum of the even-numbered digits (2nd, 4th...) is divisible by 11.

An example is that 34871903 is divisible by 11

3+8+1+0=12

4+7+9+3=23

23-12=11

Here, we want (b + b) - (a + c + a) to be divisible by 11.

2b - (2a + c) to be divisible by 11

ab,cba (using 7 and 8 and 9 since they biggest)

78 987 --> 2*8 - (2*7 + 9) = 16 - (14 + 9) = 16 - 23 = -7 NO

87 978 --> 2*7 - (2*8 + 9) = 14 - (16 + 9) = 14 - 25 = -11 YES

79 897 --> 2*9 - (2*7 + 8) = 18 - (14 + 8) = 18 - 22 = -4 NO

97 879 --> 2*7 - (2*9 + 8) = 14 - (18 + 8) = 14 - 26 = -12 NO

89 798 --> 2*9 - (2*8 + 7) = 18 - (16 + 7) = 18 - 23 = -5 NO

98 789 --> 2*8 - (2*9 + 7) = 16 - (18 + 7) = 16 - 25 = -9 NO

Therefore, the biggest 5 digit number is 87,978.

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The general solution of the given differential equation be [tex]y(x)=c_1e^{4x}+c_2e^{-3x}+\frac{1}{7} xe^{4x}[/tex]

For given question,

We have been given a differential equation y'' − y' − 12y = e^(4x)

We need to solve the given differential equation by undetermined coefficients.

We can write given differential equation as [tex](D^2-D-12)y=e^{4x}[/tex] where [tex]D=\frac{d}{dx}[/tex]

First solve the corresponding homogeneous differential equation:

y'' - y' - 12y = 0

The characteristic equation is:

m² - m - 12 =0

Let's find the roots of above quadratic equation by factorization.

⇒ m² - m - 12 = 0

⇒ (m - 4)(m + 3) = 0

⇒ m - 4 = 0   OR  m + 3 = 0

⇒ m = 4   OR   m = -3

Hence the complementary solution is,

[tex]y_c=C_1e^{4x}+C_2e^{-3x}[/tex]

Let the general solution of a second order homogeneous differential equation be [tex]y(x)=C_1(x)e^{4x}+C_2(x)e^{-3x}[/tex]

The unknown functions C1(x) and C2(x) can be determined from the system of two equations:

[tex]C'_1e^{4x}+C'_2e^{-3x}=0~~~~~~~............(1)\\\\C'_1(4e^{4x})+C'_2(-3e^{-3x})=e^{4x}~~~~~~~...................(2)[/tex]

from (1),

[tex]C'_2e^{-3x}=-C'_1e^{4x}[/tex]

Substitute this value in equation (2)

[tex]4C'_1e^{4x}+3C'_1e^{4x}=e^{4x}[/tex]

[tex]\Rightarrow C'_1=\frac{1}{7}[/tex]  and  [tex]C'_2=-\frac{1}{7}e^{7x}[/tex]

[tex]\Rightarrow C_1=\frac{1}{7} x+c_3[/tex]     and     [tex]C_2=\frac{1}{49}e^{7x}+c_2[/tex]

Therefore, the general solution of the given differential equation be [tex]y(x)=c_1e^{4x}+c_2e^{-3x}+\frac{1}{7} xe^{4x}[/tex]

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The bucket number 2 will contain 45 after sorting the data.

According to the statement

we have given that the a data list which is sorted into 4 buckets then we have to find he in which the umber 45 is sorted.

So, For this purpose,

The given data list is:

76, 56, 93, 24, 45, 88, 13, 7, 37

And the data is sorted into the buckets so,it is sorted in 4 buckets. and the data contain numbers from 0 to 100.

So, let the sorting.

We know that the 100 numbers are sorted in 4 buckets then it means each bucket contain 25 numbers.

So, let us consider a

BUCKET 1 : 0 to 25

it contains the data number 7, 13,24.

Now,

BUCKET 2 : 25 to 50

it contains the data number 37,45.

Now,

BUCKET 3 : 50 to 75

it contains the data number 56.

Now,

BUCKET 4 : 75 to 100

it contains the data number 76, 88, 93.

From sorting the 45 number sort in the bucket 2.

So,The bucket number 2 will contain 45 after sorting the data.

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C = 3r + 15 is the rule for the total cost, C, where r rides are taken given that the total cost charged for a day of fun at Aussie World consists of an entry fee of $15 and a rate of $3 per ride. This can be obtained by converting the statements to algebraic equation with variables and constants.

Here in the question it is given that,

The total cost charged for a day of fun at Aussie World consists of

We have to find a rule for the total cost, C, where r rides are taken.

For one ride the rate is 3 ⇒ therefore for r rides the rate is 3r

We can convert the statements to algebraic equation so that we get the required rule,

⇒ The total cost consists of entry fee and rate of rides

⇒ The total cost = entry fee + rate of rides

⇒ C = 15 + 3r (from the given information)

⇒ C = 3r + 15

Hence C = 3r + 15 is the rule for the total cost, C, where r rides are taken given that the total cost charged for a day of fun at Aussie World consists of an entry fee of $15 and a rate of $3 per ride.

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The value of tan(X) in fraction is 7.2/6.4 and in decimal is 1.13

The complete question is added as an attachment

From the question, the given parameters are as follows:

Hypotenuse = XZ

Hypotenuse XZ = 9.6

Leg ZY = 7.2

Leg YX = 6.4

The tangent of X is then calculated as:

tan(X) = ZY/YX

Substitute the known values in the above equation

tan(X) = 7.2/6.4

Evaluate the above quotient

tan(X) = 1.125

Approximate the above result

tan(X) = 1.13

Hence, the value of tan(X) in fraction is 7.2/6.4 and in decimal is 1.13

So, the complete parameters are:

Hypotenuse = XZ

Hypotenuse XZ = 9.6

Leg ZY = 7.2

Leg YX = 6.4

tan(X) = 7.2/6.4

tan(X) = 1.13

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The distance of the boat from its starting point is 156.226 .

According to the question

A boat sails on a bearing of 63 degree for 124 miles

i.e

By making 63 degree covers 124 miles

therefore ,

In figure below

AC = 124 miles

Then turns and sails 201 miles on a bearing of 192 degree

therefore ,

In figure below

CD = 201 miles  

Now,

According to the sum of triangle

∠ACB + ∠ABC + ∠BAC = 180°

∠ACB + 90° + 63° = 180°

∠ACB = 27°

CE = 180°  (Straight line )

therefore,

∠DCE = 192°  -  180°

          = 12°

As ∠C = 90°

therefore

∠ACD = ∠C - ∠DCE - ∠ACB

          = 90° - 12°- 27 °

          = 51°

Now,

The distance of the boat from its starting point = AD

By using Law of Cosines

As

The Law of Cosines can be used to find the unknown parts of an oblique triangle(non-right triangle), such that either the lengths of two sides and the measure of the included angle is known (SAS) or the lengths of the three sides (SSS) are given.

The Law of Cosines (also called the Cosine Rule) says:

c² = a² + b² − 2ab cos(C)

As we have 2 sides and one angle available we can use   Law of Cosines

Therefore,

by substituting the value

(AD)² = (AC)² + (CD)² − 2(AC)(CD) cos(∠ACD)

(AD)² = (124)² + (201)² − 2*124*201 cos(51)

AD = 156.226

Hence, the distance of the boat from its starting point is 156.226 .

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Answer:

[tex]h = \frac{2A}{b+c}[/tex]

Step-by-step explanation:

Original Equation:

[tex]A = \frac{1}{2} (b+c)h[/tex]

Divide both sides by height

[tex]\frac{A}{h} = \frac{1}{2}(b+c)[/tex]

Raise both sides to the exponent -1 :

[tex](\frac{A}{h})^{-1} = (\frac{1}{2}(b+c))^{-1}[/tex]

Rewrite using the definition of a negative exponent: [tex](\frac{a}{b})^{-x} = (\frac{b}{a})^{x}[/tex]

[tex]\frac{h}{A} = \frac{1}{\frac{1}{2}(b+c)}\\[/tex]

Multiply 1/2 by (b+c)

[tex]\frac{h}{A} = \frac{1}{\frac{b+c}{2}}\\[/tex]

Keep, change, flip

[tex]\frac{h}{A} = \frac{1}{1} * \frac{2}{b+c} = \frac{2}{b+c}[/tex]

Multiply both sides by A

[tex]h = \frac{2A}{b+c}[/tex]

Also I forgot to mention but the exponent (-1) can be ignored after you flip it, since: [tex](\frac{a}{b})^x = \frac{a^x}{b^x}[/tex], but since in our case the exponent is 1, and [tex]a^1 = a[/tex], so there's really no need to write out the distribution part, since we just get the same fraction, after flipping it.

The statement that describes independent events is:

C. You randomly draw a blue marble from a bag, return the marble, and then randomly draw a yellow marble.

In this case, the events of drawing a blue marble and drawing a yellow marble are independent because the first draw does not affect the probability or outcome of the second draw.

Returning the marble to the bag ensures that each draw is independent of the previous one.

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Answer:

50.24 ft^2.

Step-by-step explanation:

Area = pi r^2

Here the radius r = 4

Therefore the area of the circle

= pi * 4^2

= 16 pi

= 16 *3.14

= 50.24 ft^2.

The average rate of change over the interval is 2/9

The interval is given as:

-4 ≤ x ≤ 5

From the table, we have:

f(5) = 4

f(-4) = 2

The average rate of change is then calculated as:

[tex]m = \frac{f(5) - f(-4)}{5 --4}[/tex]

This gives

[tex]m = \frac{4 - 2}{5 +4}[/tex]

Evaluate

[tex]m = \frac{2}{9}[/tex]

Hence, the average rate of change over the interval is 2/9

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The correct equation says to find R = 32 - 11 (X+2y). This gives us the value of -78.

We have this

R = 32 - 11 (X+2y)

we have the following values for x and y as 2 and 4 respectively.

What we have to do would be to find the value of R after we have put in these values in the equation.

To do this, we would then have:

R = 32 - 11(2 + 2*4)

R = 32 -11(2+8)

R = 32 - 11 * 10

R = 32 - 110

This would give us the value that says

R = -78

Hence the value of R is given as -78

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Answer:

11

Step-by-step explanation:

25 than you divided 5 + 2 than you multiply 3 and you get

Answer:

11

Step-by-step explanation:

Answer:

2

-2

Step-by-step explanation:

Use the second equation for x = -4.

f(-4) = 2

Use the third equation for x = 3.

f(x) = -x + 1 = -3 + 1 = -2

The equation that could represent a linear combination of the system 2/3x + 5/2y = 15 and 4x + 15y = 12 is 0 = 26

Linear equations are equations that have constant average rates of change, slope or gradient

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2/3x + 5/2y = 15

4x + 15y = 12

Multiply the first equation by 6, to eliminate the fractions.

6 * (2/3x + 5/2y = 15)

This gives

4x + 15y = 90

Subtract the equation 4x + 15y = 90 from 4x + 15y = 12

4x - 4x + 15y - 15y = 12 - 90

Evaluate the difference

0 + 0 = -78

Evaluate the sum

0 = -78

The above equation is the same equation as option (b) 0 = 26

This is so because they both represent that the system of equations have no solution

Hence, the equation that could represent a linear combination of the system is 0 = 26

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Complete question

The system of equations below has no solution.

2/3x + 5/2y = 15

4x + 15y = 12

Which equation could represent a linear combination of the system?

Answer:

Option D

Step-by-step explanation:

Using the surd law :

[tex]\sqrt{ab} = \sqrt{a}\sqrt{b}[/tex]

We can find the largest square number that goes into 75 :

Let's write the multiples of 75 :

1 , 75

3 , 25

5 , 15

The only square number is 25

So using the law mentioned above we split √75 into :

√25√3

The square root of 25 is 5

Now we have our final answer of 5√3

Hope this helped and have a good day

The simplified form of expression √75 is 5√3.

Option D is the correct answer.

We have,

To simplify √75, we can factor it into its prime factors and then take the square root:

√75 = √(3 * 5 * 5)

= √(3 x 5²)

Take out the perfect square factor from under the square root:

= √3 x √5²

= √3 x 5

= 5√3

Thus,

The simplified form of expression √75 is 5√3 which is option D.

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Explanation:

Assuming there are four answer choices, we can eliminate choices A through C because they are functions. This is because they pass the vertical line test.

The vertical line test is where we try to draw a single vertical line through more than one point on the curve. If such a task is possible, then it is said to "fail the vertical line test" and it's not a function.

For choice A, we cannot draw a single vertical line through more than one point on the parabola. Choice A passes the vertical line test. Hence, it is a function. The same goes for choices B and C.

Unfortunately choice D is not shown, but if it's the only thing left, then I'm assuming that it's some curve that fails the vertical line test.

In step 2, the property of equality applied was addition property of equality.

In step 4, the property of equality applied was multiplication property of equality.

The addition property of equality states that, to move a negative number over to the other side of an equation, add the number to both sides of the equation. For example, given the equation: a - c = b, to move c over to the other side of the equation, add c to both sides of the equation. we will have:

a - c + c = b + c

a = b + c.

According to the multiplication property of equality, if we have, a/c = b, to isolate a, we would multiply both sides of the equation by c. Thus:

a/c × c = b × c

a = bc

In the table given, in step 2, 6 was added to both sides of the equation. This means the property of equality that was applied was: addition property of equality.

In step 4, both sides of the equation was multiplied by -2. Thus, the property of equality that was applied was: multiplication property of equality.

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Answer: step 2 - addition property

              step 4 - multiplication property

Step-by-step explanation:

Answer:

y + 8 = -4(x - 2)

Step-by-step explanation:

Point-slope form of an equation is a fill-in-the-blank, shortcut way to write an equation of a line. This is the format:

y - Y = m(x - X)

You just fill in the slope for m and fill in the point for the X,Y.

Just leave the first y; it stays a y and the first x in the parenthesis stays as an x. You just have to be careful with your minus and negative signs.

Slope is given as -4 so fill that in for m.

and put (2,-8) in place of the X and Y.

y - Y = m(x - X)

y - -8 = -4(x - 2)

y + 8 = -4(x - 2)

Done! Hope this helps!

The discount to be increased so that he can gain only 15% is 8%.

How much is the discount to be increased so that he can gain only 15%:

The cost price of the goods - y.

The selling price of the goods - x.

The selling price is

1.2y (100% + 20% = 120%).

The refrigerator was sold at 13% VAT at Rs. 10848:

=> 1.2y + 13%(1.2y) = 10848

=> 1.2y + 0.156y = 10848

=> 1.356y = 10848

=> y = 8000

Thus, the cp is Rs 8000.

The selling price is:

=> 0.96x = 1.2y

=> 0.96x = 1.2(8000)

=> x = 10000

The selling price is Rs. 10000

For a profit of 15%, that is 1.15(8000) = 9200, the discount is:

(1 - discount)10000 = 9200

1 - discount = 0.92

Discount = 1 - 0.92 = 0.08 or 8%

How much is the discount to be increased so that he can gain only 15%: Discount=8%

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Answer:

Step-by-step explanation:

Use periodic compound formula:

[tex]F=P\cfrac{(1+r/n)^{nt}-1}{r/n}[/tex]

Substitute the values and calculate:

[tex]F=200\cfrac{(1+0.032/12)^{12*2}-1}{0.032/12} =4950.12[/tex]     rounded

Step-by-step explanation:

Use periodic compound formula:

[tex] \sf \: F=P\cfrac{(1+ \frac{r}{n})^{nt}-1}{\frac{r}{n}}[/tex]

Substitute the values and calculate:

[tex]\sf \: F=200\cfrac{(1+ \frac{0.032}{12})^{12 \times 2}-1}{\frac{0.032}{12}}[/tex]

[tex]\sf \: F=200\cfrac{( \frac{ 12 + 0.032}{12})^{24}-1}{\frac{0.032}{12}}[/tex]

[tex]\sf \: F=200\cfrac{( {11.002 }{})^{24}-1}{0.002} [/tex]

[tex]\sf \: F=200 \times 24.7506[/tex]

[tex]\sf \: F=4950.12rounded[/tex]

Answer:

y = 42 and/or x = 36

Step-by-step explanation:

y + 48 = 90
y = 42 (subtracted 48 from 90)

3x + 2x = 180 (angles are linear pairs)
5x = 180 (combine like terms)
x = 36 (divided by 5 on both sides)

I didn't know which question you needed help with, I hope this makes sense :)

❄ Hi there,

the sum of complementary angles is always 90°.

If we know one of these angles, we can set up an equation –

[tex]\triangleright\sf{y+48=90}[/tex]

and then solve for y...

[tex]\triangleright \ \sf{y=42}[/tex]

That's it!

❄

Answer:

(x + 1)² + (y - 3)² = 16

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

here (h, k ) = (- 1, 3 ) and r = 4 , then

(x - (- 1) )² + (y - 3)² = 4² , that is

(x + 1)² + (y - 3)² = 16

Answer:

(x+1)^2 + (y-3)^2 = 16

Step-by-step explanation:

The standard form of an equation of a circle with center (h,k) and radius r is (x-h)^2 + (y-k)^2 = r^2.  Plugging in those values, we get (x-(-1))^2 + (y-3)^2= 4^2  = (x+1)^2 + (y-3)^2 = 16.

The distance between point [tex](8, \sqrt{17})[/tex] and the center (0,0) is of 9 units, which is less than the radius, hence the correct option is:

Yes, the distance from the origin to the point [tex](8, \sqrt{17})[/tex] is of 9 units.

Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

In this problem, we have a circle with center at (0,0) and radius 10. Hence, every point that is less than 10 units of distance from point (0,0) will be on the circle.

The distance of [tex](8, \sqrt{17})[/tex] is:

[tex]D = \sqrt{(8 - 0)^2+(\sqrt{17} - 0)^2}[/tex]

[tex]D = \sqrt{81}[/tex]

D = 9 units.

9 < 10, hence the correct option is:

Yes, the distance from the origin to the point [tex](8, \sqrt{17})[/tex] is of 9 units.

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The first five terms of the sequence with the given n-th term [tex]a_n = cos(\frac{n\pi}{2} )[/tex] are : 0, -1, 0, 1, 0

For given question,

We have been given the n-th term of the sequence [tex]a_n = cos(\frac{n\pi}{2} )[/tex]

We need to find the first five terms of the sequence.

For n = 1

[tex]\Rightarrow a_1 = cos(\frac{1\pi}{2} )\\\\\Rightarrow a_1=0[/tex]

For n = 2,

[tex]\Rightarrow a_2 = cos(\frac{2\pi}{2} )\\\\\Rightarrow a_2=cos(\pi)\\\\\Rightarrow a_2=-1[/tex]

For n = 3,

[tex]\Rightarrow a_3= cos(\frac{3\pi}{2} )\\\\\Rightarrow a_3=0[/tex]

For n = 4,

[tex]\Rightarrow a_4 = cos(\frac{4\pi}{2} )\\\\\Rightarrow a_4=cos(2\pi)\\\\\Rightarrow a_4=1[/tex]

For n = 5,

[tex]\Rightarrow a_5 = cos(\frac{5\pi}{2} )\\\\\Rightarrow a_5=0[/tex]

Therefore, the first five terms of the sequence with the given n-th term[tex]a_n = cos(\frac{n\pi}{2} )[/tex] are : 0, -1, 0, 1, 0

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