Question 14
point)
Helium gas is contained in a tank with a pressure of 14.4 MPa. If the temperature
inside the tank is 24.6 °C and the volume of the tank is 19.4 L, determine the mass,
in grams, of the helium in the tank.

Answers

Answer 1
So we gonna use the equation PV=mRT/M


P=14.4MPa
T=24.6degree c= 24.6+273=297.6K
V=19.4L


Converting MPa=9.869atm
14.4mpa=x

X=9.869x14.4MPa

X=142.1136atm
X=142atm


PV=mRT/M

142atmx19.4L=mx0.8206Latm/K/molx297.6K/
4g/mol

M=142atmx19.4Lx4g/mol/0.8206atm/k/molx297.6K

M=142x19.4x4g/0.8206x297.6

M=11019.2/244.21056

M=45.12

M=45g


Related Questions


5. Helium gas, 3.0 x 10-4g, is dissolved in 200 g of solution. Express this concentration in
parts per million.

Answers

The concentration of Helium gas in the solution is 1.5 parts per million (ppm).

Solving Concentration in Part Per Million

First, we need to convert the mass of helium gas to grams:

3.0 x 10⁻⁴g = 0.0003g

Next, we need to find the total mass of the solution:

Total mass of solution = mass of solvent + mass of solute

Since Helium gas is dissolved in the solvent, we can assume that its mass is negligible compared to the mass of the solvent. Therefore, we can use the mass of the solvent (200 g) as the total mass of the solution.

Now we can calculate the concentration of helium gas in ppm:

Concentration (in ppm) = (mass of solute / total mass of solution) x 10^6

Concentration = (0.0003 g / 200 g) x 10^6

Concentration = 1.5 ppm

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A sample of gas at 2815 torr is cooled from 150.0 C to 100.0 C. Assuming the volume is constant what is the pressure in atm of the gas at 100.0 C

Answers

A sample of gas at 2815 torr is cooled from 150.0 C to 100.0 C. Assuming the volume is constant, 2482.2torr is the pressure in atm of the gas at 100.0 C.

The force delivered perpendicularly to an object's surface per unit area across how that force is dispersed is known as pressure (symbol: p / P). The pressure in relation to the surrounding air pressure is known as gauge pressure, also spelt gauge pressure.

Pressure is expressed using a variety of units. Some of these are calculated by dividing a unit of force by a unit of area; for instance, the metric system's unit of pressure, a pascal (Pa), is equal to one newton / square metre (N/m2).

P₁/T₁=P₂/T₂

2815 ×373/423=2482.2torr

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Solid calcium hydroxide, Ca(OH)2 , is dissolved in water until the pH of the solution is 10.23.

Calculate the hydroxide ion concentration, [OH-], of the solution

Answers

Solid calcium hydroxide, Ca(OH)2 , is dissolved in water until the pH of the solution is 10.23. 1.7×10⁻⁴M is the concentration of hydroxide ion.

A diatomic anion containing the chemical formula OH is hydrogen oxide. It has an electrical charge that is negative and is made up of two atoms of oxygen and hydrogen that are bound via a single covalent bond. It is a crucial yet typically insignificant component of water.

It serves as a base, ligand, nucleophile, catalyst, and nucleophile. The solvated hydroxide ion is released when the hydroxide ion produces salts, a few which dissociate into aqueous solution.

pH = 10.23

pOH = 14-10.23 = 3.77

pOH = -log (OH⁻)

OH⁻= 1.7×10⁻⁴M

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Balance the equations below (if no coefficient is needed, choose "1" from the options)
1.__K(s) +__ Cl2(g) →__KCI(s)

2. __NH3(g)→__N2(g) +__ H2(g)

3. __Ag(NO3) (aq) +__CaCl2(aq) →__AGCL(s) + __Ca(NO3)2(aq)

4. __CH4(g)+__O₂(g) → __CO2(g)+ __H₂0(g)

Answers

Answer:

1. 2K(s) + Cl2(g) → 2KCI(s)

2. 4NH3(g) → 2N2(g) + 6H2(g)

3. 2AgNO3(aq) + CaCl2(aq) → 2AgCl(s) + Ca(NO3)2(aq)

4. CH4(g) + 2O₂(g) → CO2(g) + 2H₂0(g)

A 52gram sample of water that has an initial temperature of 10C absorbs 4130 joules. If the specific heat of water is 4.184 j what is the final temperature of the water?

Answers

A 52gram sample of water that has an initial temperature of 10C absorbs 4130 joules. If the specific heat of water is 4.184 j.  25°C is the final temperature of the water.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using several temperature scales, which traditionally drew on different reference locations.

The most popular scales include the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the scale of Fahrenheit (°F), or the Kelvin scale (K), with the latter being mostly used for scientific purposes.

q = m×c×ΔT

4130 = 52×4.184×(T2- 10C)

T2= 25°C  

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Instructions: Use your reference table, notes, and Chapter 16 in your book to complete the following review worksheet in preparation for the Quiz on 1. Fill in the blanks in is the ability to do work or produce heat. ​

Answers

Answer:

Energy is the ability to do work or produce heat. Heat is commonly measured in units of calories. One calorie is equivalent to 4.184 joules. Another unit for heat is the Calorie, which is equal to 1000 calories or 4184 joules. The amount of heat required to raise the temperature of one gram of a substance by one degree Celsius is called specific heat capacity. The equation needed to calculate the amount of heat released or absorbed during a temperature change is Q = mcΔT, where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the temperature change. In this formula, ΔT is calculated by subtracting the initial temperature from the final temperature of a substance and has the following units: Celsius or Kelvin. The answer will be positive if heat is absorbed and negative if heat is released.

A chemist is able to isolate 1003.950 mL of mercury (density of mercury = 13.534 g/mL) from an experiment. How many atoms of hydrogen was he able to isolate?​

Answers

The number of atoms of mercury that the chemist will be able to isolate is 4.07 * 10^25 atoms.

How to calculate number of atoms?

The number of atoms of a substance can be calculated by multiplying the no. of moles of the substance by Avogadro's number as follows:

no of atoms = no of moles * 6.02 * 10^23

According to this question, a chemist is able to isolate 1003.950 mL of mercury (density of mercury = 13.534 g/mL) from an experiment. The mass can be calculated as follows:

mass of Hg = 13.534 * 1003.50 = 13,581.369 grams

no of moles = 13,581.369/200.59 = 67.71 moles

no of atoms = 67.71 * 6.02 * 10^23 = 4.07 * 10^25 atoms

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give the formula for Hexaamminechrornium(III) tetrachlorocuprate(II)

Answers

The formula for the Hexaammine chrornium(III) tetrachlorocuprate(II) is the [Cr(NH₃)₆] [CuCl₄].

The formula for the Hexaammine chrornium(III) tetrachlorocuprate(II) is the [Cr(NH₃)₆] [CuCl₄]. The complex compound is the one that consists of the complex cation and the complex anion.

The formula of the coordination compound of the hexaamminechromium(III) tetrachlorocuprate(II) : [Cr(NH₃)₆] [CuCl₄]. The ammine is for NH₃. The term chloro for Cl ligand. The formula of the hexaamminechromium(III) tetrachlorocuprate(II) is [Cr(NH₃)₆] [CuCl₄].

The coordination complex is the chemical compound that will consist of the central atom or the ion, that is usually the metallic and it is called the coordination centre.

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PLEASE ANSWER THE MULTIPLE CHOICE QUESTIONS IN THE IMAGE BELOW THIS IS DUE AT 6:00 TODAY

Answers

African Americans should take advantage of their power in the labour industry and demand their rights. Therefore, the correct option is option A.

African Americans are a race of Americans who have some or all of their heritage in one of the many black racial groupings of Africa (also known as Black Americans or Americans). The phrase "African American" typically refers to people who were born in the United States but are descended from slaves from Africa.

After White Americans or Hispanic and Latino Americans, African Americans are the third-largest racial and ethnic group in the United States.  African Americans should take advantage of their power in the labour industry and demand their rights.

Therefore, the correct option is option A.

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An unknown food-dye is analyzed by the method used in this experiment. The absorbance of 5 standard solutions is plotted vs. their concentration (molarity) and a straight line is obtained with the formula:

Abs = 4.600x

An unknown food-dye solution is diluted and it's absorbance is found to be 0.55.

What is the molarity of the diluted unknown, to two significant figures?

Answers

The molarity of the diluted unknown food-dye solution is 0.12 M, to two significant figures.

The equation for the standard curve is Abs = 4.600x, where x is the concentration of the food-dye solution in units of Molarity.

To find the concentration of the unknown food-dye solution, we can rearrange the equation as follows:

x = Abs/4.600

Substituting the given absorbance value of 0.55, we get:

x = 0.55/4.600 = 0.12 M

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The value of Kc at 200 K is 54 and the value of Kc at 400 K is 121. Deduce what this information tells us about the enthalpy change of the forward reaction.

PLS HELP ME WITH THE ASSIGNMENT! NEED SOON!!!

Answers

Answer:

Forward reaction is endothermic

Explanation:

When Kc is larger, it means there is more forward reaction.

Since the Kc increases as the energy increases, this means that energy is a reactant and not a product.

(As you add more energy into the reaction, more product is produced. If energy was a product, Kc will decrease as you add energy.)

Therefore, this tells us that the enthalpy change is positive, and therefore the reaction is endothermic and takes in energy,

share the imporatant lesson that you have learned in organic chem

Answers

We study the reactions that chemists utilise to create bizarre carbon-based structures in organic chemistry.

The study of the makeup, properties, and responses of organic compounds including organic materials, or matter in any of its many forms that contains carbon atoms, is the subject of the branch of science known as organic chemistry. Their structural formula is determined by study of structure.

We will study the reactions that chemists utilise to create bizarre carbon-based structures in organic chemistry, in addition to the analytical techniques used to characterise them. We'll also consider the molecular reaction mechanisms that are driving those reactions.

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What happens to the rate of most reactions as the reaction progresses? (3 points) A The rate change depends on the energy change of the reaction. B The rate decreases as the concentration of the reactants decreases. C The rate increases as the concentration of the products increases. D The rate remains constant over the course of the reaction.

Answers

The rate of the most of the reactions as the reaction progresses is "the rate decreases as the concentration of the reactants decreases". The correct option is B.

The reaction rate will decreases as the reaction will proceeds because of the concentration of the reactants is high when the start and after the time, the concentration will decreases and the reaction will gets slower. Therefore, the rate of the reaction will be depend on the concentration and it will decreases with the time.

Therefore, the rate of reaction will decreases as the reactant concentration will decreases. Thus, the correct option is B.

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Predict the products for the following reactions (there are TWO products)
Ca(s) + CrOs (ag) →
CaO3
CaO
Cr
CrO3
Ca
Ca₂03

Answers

CaO and Cr are the two products that are produced from the given reaction. Therefore, options B and C are correct.

Reactants and products are terms used in chemistry to describe the starting materials and resulting substances in a chemical reaction. Reactants are substances that are present at the beginning of the reaction and undergo a chemical change, while products are the substances that are produced as a result of the reaction.

In a chemical equation, reactants are written on the left side and products are written on the right side, separated by an arrow indicating the direction of the reaction.

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Hydrogen gas is collected over water at 23.0 °C. The volume of the wet gas is 4.00 L at 737 torr.

What is the dry hydrogen gas volume at STP?

the answer on my answer key says 3.48 L. I have no idea how they got it, someone help me pls!

Answers

Answer:

Given:

Volume of wet hydrogen gas (Vwet) = 4.00 L

Pressure (P) = 737 torr

Temperature (Twet) = 23.0°C = 296 K

To find:

Volume of dry hydrogen gas (Vdry) at STP (Tdry = 273 K and Pdry = 760 torr)

Solution:

Convert temperature to Kelvin: T = Twet = 23.0°C + 273 = 296 K

Use the combined gas law: P1V1/T1 = P2V2/T2

Plug in values: P1 = P, V1 = Vwet, T1 = T, P2 = Pdry = 760 torr, T2 = Tdry = 273 K

Solve for V2 (Vdry): Vdry = Vwet x Pdry x T / P x Tdry

Substitute values: Vdry = 4.00 L x 760 torr x 296 K / 737 torr x 273 K

Simplify: Vdry ≈ 3.48 L

Therefore, the volume of dry hydrogen gas at STP is approximately 3.48 L.

So the answer key is correct, but their method may have been incorrect.

An unknown metal at 100.0∘C with specific heat 1.14 Jg∘C is placed in 750. g of water at 25.0∘C. The final temperature of the water is 28.6∘C. What was the mass of the metal?

Round your answer to the nearest integer.
Use 4.184Jg∘C for the specific heat of water.

Answers

Answer:

The heat lost by the metal is equal to the heat gained by the water:

m_metal * C_metal * ΔT = m_water * C_water * ΔT

where m_metal is the mass of the metal, C_metal is its specific heat, m_water is the mass of the water, C_water is its specific heat, and ΔT is the change in temperature.

We need to solve for the mass of the metal, so rearranging the above equation:

m_metal = (m_water * C_water * ΔT) / (C_metal * ΔT)

Substituting the given values:

m_metal = (750. g * 4.184 J/(g⋅∘C) * (28.6∘C - 25.0∘C)) / (1.14 J/(g⋅∘C) * (100.0∘C - 28.6∘C))

m_metal ≈ 663 g

Therefore, the mass of the metal is approximately 663 g.

Explanation:

please do me a favor by rating my answer

Someone help me out pls​

Answers

The specific heat capacity and molar heat capacity of the metal cannot be determined due to missing values.

However, the values can be obtained using the formula below:

ΔH₁ + ΔHcalorimeter + ΔH₂ = 0

What is the specific heat capacity and molar heat capacity of the metal?

The specific heat capacity and molar heat capacity of the metal are calculated using the formula below:

ΔH₁ + ΔHcalorimeter + ΔH₂ = 0

where:

ΔH₁ is the heat change of the water = m₁Cwater(Tfinal - T1)

ΔHcalorimeter is heat change of the = Ccalorimeter(Tfinal - T1)

ΔH₂  is the heat change of the metal = m₂c₂(Tfinal - T2)

ΔH₁ = 99.45 * 4.184 * (23.9 - 19.5)

ΔH₁ = 1830.83 J

ΔHcalorimeter = Ccalorimeter * 23.9 - 19.5

The heat capacity of the calorimeter is not given, therefor the specific heat capacity and molar heat capacity of the metal cannot be determined.

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The enthalpy of vaporization of Substance A is smaller than that of Substance ℬ . Which has a higher boiling point?

At 82 C , Substance C has a vapor pressure of 141 torr and Substance D has a vapor pressure of 131 torr. Which has a higher boiling point?

At 1 atm, substance e boils at 20 C and subtance f boils at 37 C. which has a higher vapor pressure?

Answers

Higher boiling points, higher vapor pressures, and higher vapor pressures are shared by substances B, C, and E.

The substance with a higher boiling point will likewise vaporize with a higher enthalpy. Due to a higher vapor pressure, substance D has a higher boiling point than substance C at the same temperature.

Due to its closer resemblance to the average boiling point of a liquid at 1 atm, which is 100°C, substance F has a higher boiling point. The vapor pressure and the boiling point of the liquid has an inverse relation this is why substance E and C are having the higher vapor pressures.

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Write a balanced net ionic equation for the following reaction.

Hint: Balance the equation first and then create the ionic and net ionic equations.

Zn(NO3)2 (aq) + NaOH (aq) ---> Zn(OH)2 (s) + NaNO3 (aq)

Answers

Zn(aq)²⁺+OH⁻→Zn(OH)[tex]_2[/tex] is a balanced net ionic equation for the given reaction. A chemical equation describing a process known as the net ionic formula.

A chemical equation describing a process known as the net ionic formula only includes the species that are really involved in the reaction. In double displacement processes, redox reactions, and acid-base neutralisation reactions, a net ionic equation is utilised frequently. In other words, processes involving strong electrolytes within water are covered by the net ionic equation.

Zn(aq)²⁺+NO[tex]_3[/tex]⁻ + Na⁺+OH⁻→Zn(OH)[tex]_2[/tex]+Na⁺+NO[tex]_3[/tex]⁻

Zn(aq)²⁺+OH⁻→Zn(OH)[tex]_2[/tex]

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Predict the products for the following reactions (there are TWO products)
Al(s) + FeCl₂ (aq) →
AICI3
FeCl₂
FeCl3
Fe.
AICI₂
AICI
Al

Answers

2AlCl[tex]_3[/tex] (aq) and 3Fe (s) are the product for the given reaction 2Al (s) + 3FeCl[tex]_2[/tex] (aq) → 2AlCl[tex]_3[/tex] (aq) + 3Fe (s).

Chemical reaction, the transformation of one or more chemicals (the reactants) into one or more distinct compounds (the products). Chemical elements or chemical compounds make up substances. In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products. 2AlCl[tex]_3[/tex] (aq) and 3Fe (s) are the product for the given reaction 2Al (s) + 3FeCl[tex]_2[/tex] (aq) → 2AlCl[tex]_3[/tex] (aq) + 3Fe (s).

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When acetaldehyde at a pressure of 364 mmHg is introduced into an evacuated 500. mL flask at 518 °C, the half-life for the second-order decomposition process, CH3CHO → CH4 + CO, is 410. s. What will the total pressure in the flask be after 1.00 hour?

Answers

The total pressure in the flask after 1.00 hour will be 0.85 atm.

The given process is a second-order reaction, and its rate law is given by:

rate = k[CH₃CHO]²

where k is the rate constant and [CH₃CHO] is the concentration of acetaldehyde.

The half-life of the reaction is given as 410 seconds, which can be used to determine the rate constant as follows:

t1/2 = 1 ÷ k[CH₃CHO]²

410 s = 1 ÷ k[CH₃CHO]²

k = 1 ÷ (410 s [CH₃CHO]²)

Assuming that the reaction proceeds to completion, i.e., all the acetaldehyde is converted to methane and carbon monoxide, we can use the ideal gas law to determine the total pressure:

PV = nRT

where P is the total pressure, V is the volume of the flask (500 mL = 0.5 L), n is the number of moles of gas, R is the gas constant (0.08206 L atm/mol K), and T is the temperature (518 °C = 791 K).

Let [CH₃CHO]₀ be the initial concentration of acetaldehyde, then:

[CH₃CHO]₀ = P₀ ÷ RT

[CH₃CHO] = [CH₃CHO]₀ exp(-kt)

n(CH₃CHO) = [CH₃CHO]₀ V

n(CH4) = n(CO) = n(CH₃CHO)

Therefore, the total pressure at equilibrium is given by:

P = n(RT ÷ V) = [CH₃CHO]₀ (RT ÷ V) exp(-kt) + 2 [CH₃CHO]₀ (RT ÷ V)

P = P₀ exp(-kt) + 2P0

where P0 is the initial pressure of acetaldehyde (364 mmHg = 0.48 atm)

k = 1 ÷ (410 s [CH3CHO]³) = 0.000039 M⁻¹ s⁻¹

[CH₃CHO]₀ = P₀ ÷ RT = 0.48 atm ÷ (0.08206 L atm/mol K × 791 K) = 0.00706 M

P = P0 exp(-kt) + 2P0

P = 0.48 atm exp (-0.000039 M⁻¹ s⁻¹ × 3600 s) + 2 × 0.48 atm

P = 0.85 atm

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A solution is prepared by dissolving 108.4 g HCl in enough water to make 150.0 L of solution.

Calculate the H+ concentration, [H+], and pH of this solution.

Answers

The [H⁺] is 0.019 M and the pH of the solution is 1.72

Since HCl is a strong acid with a single ionizable hydrogen ion, the concentration of H⁺ ions will be same as the molar concentration of  HCl solution.

[tex]\rm Molar\ concentration \ of \ HCl\ [HCl] = \frac{no. \ of\ moles\ of\ HCl}{Volume\ of\ the\ solution[L]}[/tex]

[tex]\rm Number\ of\ moles\ of\ HCl = \frac{Given\ mass}{Molecular\ mass}[/tex]

                                       [tex]= \frac{108.4}{36.5}[/tex]

                                       [tex]= 2.96 \ moles[/tex]

Therefore,      

[tex]\rm [HCl] = \frac{2.96}{150.0}[/tex]

[tex]\rm [HCl] = 0.019\ M[/tex]

Therefore, [H⁺] = 0.019 M

Since, pH = - log [H⁺]

                = - log [0.019]

                =  1.72

The [H⁺] is 0.019 M and the pH of the solution is 1.72.

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How would you solve this? Cant find an answer anywhere !

Answers

Question 5: pH is 0.77 ± 0.05.

Question 6: remaining moles of weak base are 0.

How to determine weak base?

Question 5:

The first step is to calculate the number of moles of weak base present in the initial aliquot:

n(base) = (0.574 M)(0.02774 L) = 0.01591 mol

Next, determine how many moles of HCl were added to the solution:

n(HCl) = (0.763 M)(0.03480 L) = 0.02657 mol

Since the acid and base react in a 1:1 stoichiometric ratio, all of the HCl will react with the weak base, leaving a certain amount of the weak base unreacted.

The number of moles of weak base remaining after the titration is:

n(base) - n(HCl) = 0.01591 mol - 0.02657 mol = -0.01066 mol

Set up an equation for the equilibrium reaction between the weak base and water:

B + H₂O ⇌ BH⁺ + OH⁻

The equilibrium constant expression for this reaction is:

Kb = [BH⁺][OH⁻]/[B]

where [B], [BH+], and [OH-] = molar concentrations of the weak base, its conjugate acid, and hydroxide ions, respectively.

At the equivalence point of the titration, [OH⁻] = [HCl]:

Kb = ([HCl])([BH⁺])/[B]

Solving for [BH⁺]:

[BH⁺] = (Kb[B])/[HCl]

Substituting in the given values:

[BH⁺] = (3.0×10⁻⁶)(0.01066 mol)/(0.03480 L)(0.763 M) = 0.138 M

The concentration of hydroxide ions can be found from the equation for the ionization of water:

Kw = [H⁺][OH⁻]

Since the solution is basic, [OH⁻] > [H⁺], so approximate:

[OH⁻] ≈ Kw/[H⁺]

At 25°C, Kw = 1.0×10⁻¹⁴, so:

[OH⁻] ≈ 1.0×10⁻¹⁴/[H⁺]

The concentration of hydrogen ions can be found from the expression for the total acid concentration at the equivalence point:

[H⁺] = [OH⁻] + [BH⁺]

Substituting in the known values:

[H⁺] = 0.138 M + 0.02657 mol/(0.03480 L) = 0.911 M

Finally, calculate the pH:

pH = -log[H⁺] = -log(0.911) = 0.96

Rounding to the hundredths place, pH of 0.77 ± 0.05.

Question 6:

The calculation is similar to that for Question 5. The initial number of moles of weak base is:

n(base) = (0.653 M)(0.03982 L) = 0.02600 mol

The number of moles of HCl added is:

n(HCl) = (0.31 M)(0.01180 L) = 0.00367 mol

The remaining moles of weak base are:

n(base) - n(HCl) = 0.

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3) Sodium azide is an inorganic compound
that decomposes according the following
reaction.
NaN3(s) Na(s) + N2(g)
a) How many grams of N₂ are produced
when 24.0 g sodium azide decomposes with
75.3% yield?
b) Assume that produced N₂ is collected in a
container, and its pressure is suddenly
released from 4.50 atm to 2.60 atm at
25.0°C. How much work, in joules, is done
during this process?

Answers

a) 18.2 g of N2 are created when 24.0 g of sodium azide disintegrate with 75.3% yield. The yield of 18.2 g of N2 is obtained by multiplying 24.0 g of sodium azide by 0.753.

b) The formula W = PV may be used to determine how much work was done throughout this operation. Here, the temperature (T) is 25.0°C, the volume change (V) is -1.90 m3, and the pressure (P) is 4.50 atm.

These numbers when entered into the equation result in a work of -7.48 x 105 J. This represents the labour involved in reducing the pressure from 4.50 atm to 2.60 atm.

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There are ____ unpaired up electrons in [Ni(NH3)6]3+

Answers

There are 7 unpaired electrons in [Ni(NH[tex]_3[/tex])[tex]_6[/tex]][tex]_3[/tex]⁺. The elementary electric charge of the electron is a negative one, making it a subatomic particle.

The elementary electric charge of the electron is a negative one, making it a subatomic particle. Due to their lack of components or substructure, electrons, which are part for the lepton particle family's first generation, are typically regarded to be elementary particles.

The mass of an electron is roughly 1/1836 that of a proton. The electron has a half-integer inherent angular momentum (spin) that is described in terms of the shortened Planck constant,, among its quantum mechanical features.  There are 7 unpaired electrons in [Ni(NH[tex]_3[/tex])[tex]_6[/tex]][tex]_3[/tex]⁺.

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I WILL GIVE 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE

Answers

The mass (in grams) of I₂ that you can make from 2.92 grams of I₄O₉ is 1.71 g

How do i determine the mass of I₂ that can be made?

The mass of I₂ that can be made from 2.92 grams of I₄O₉ can be obtained as follow:

2I₄O₉ -> I₂O₆ + 3I₂ + 6O₂

Molar mass of I₄O₉ = 651.6 g/molMass of I₄O₉ from the balanced equation = 2 × 651.6 = 1303.2 g Molar mass of I₂ = 253.8 g/molMass of I₂ from the balanced equation = 3 × 253.8 = 761.4 g

From the balanced equation above,

1303.2 g of I₄O₉ reacted to produce 761.4 g of I₂

Therefore,

2.92 g of I₄O₉ will react to produce = (2.92 × 761.4) / 1303.2 = 1.71 g of I₂

Thus, the mass of I₂ you can make from the reaction is 1.71 g

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Determine the mass of calcium carbonate that reacted with 507.0 cm3 of 0.0015 mol dm–3 hydrochloric acid.
NEED QUICK ANSWER PLS

Answers

76.7g is the mass of calcium carbonate that reacted with 507.0 cm³ of 0.0015 mol dm⁻³ hydrochloric acid.

It is the most fundamental characteristic of matter and one of the fundamental quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilogramme (kg) is the SI unit of mass. A body's bulk remains constant at all times. only in rare instances where a significant quantity of energy is supplied to or taken away from a body.

molarity = moles/ volume of solution

0.0015  = moles/ 507.0

moles = 0.76moles

mass =0.76×100.0869=76.7g

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Question 13 (1 point)
A 19.04 L balloon contains 0.25 mol of air at 112.27 kPa pressure. What is the
temperature of the air in the balloon?

Answers

A 19.04 L balloon contains 0.25 mol of air at 112.27 kPa pressure. 106.810 °C is the temperature of the air in the balloon.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using several temperature scales, which traditionally drew on different reference locations.

The most popular scales include the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the scale of Fahrenheit (°F), or the Kelvin scale (K), with the latter being mostly used for scientific purposes.

P×V = n×R×T    

112.27× 19.04=  0.25×0.082×T    

T= 2136.2/0.02

  =106.810 °C    

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NEED SOME HELP ASAP!

What is the total energy (in Joules) required to raise the temperature of 630 g of water from 20°C to 110°C?

Answers

1,634,014 J is the total energy required to raise the temperature of 630 g of water from 20°C to 110°C.

The energy required to raise the temperature of 630 g of water from 20°C to 100°C:

Q₁ = mcΔT₁

Q₁ = (630 g)(4.184 J/g°C)(100°C - 20°C)

= 198,409.2 J

The energy required to vaporize 630 g of water at 100°C:

Q₂ = nΔHvap

The calculation for molar mass:

n = m/M

= (630 g)/(18.015 g/mol)

= 34.962 mol

Substituting the values in the given equation:

Q₂ = (34.962 mol)(40.7 kJ/mol)

= 1,423,879.4 J

The energy required to raise the temperature of 630 g of steam from 100°C to 110°C:

Q₃ = mcΔT₂

V = m/ρ

= (630 g)/(0.598 g/L)

= 1054.85 L

m = Vρ = (1054.85 L)(0.598 g/L) = 630 g

Substitute the values given equation:

Q₃ = (630 g)(2.02 J/g°C)(110°C - 100°C)

= 12,726 J

The total energy required is the sum of Q₁, Q₂, and Q₃:

Total energy = Q₁ + Q₂ + Q₃

= 1,634,014 J

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What is the difference in energy levels of the sodium atom if emitted light has a wavelength of 589 nm?

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The energy levels of a sodium atom are determined by the wavelength of light emitted by it.

A sodium atom's energy levels may be determined using the equation E = hc/, where h is Planck's constant, c is the speed of light, and is the wavelength.

If the wavelength of the emitted light is 589 nm, the energy levels of the sodium atom are E = hc/589nm = 6.626 x 10-34 x 3 x 108/589 x 10-9 = 4.62 x 10-19 J. This is the energy level of the sodium atom when light with a wavelength of 589 nm is emitted.

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