Answer: I believe it’s oxygen (0)
Explanation: Tell me if it’s correct :)
Light enters a transparent material from air at 30.0° to the normal. It continues within the material at the angle of refraction of 23.0°. What is the critical angle for total internal reflection when this material is surrounded by air?
Answer:
The value is [tex]c = 51.38 ^o[/tex]
Explanation:
From the question we are told that
The angle of incidence is [tex]\theta_i = 30^o[/tex]
The angle of refraction is [tex]\theta_r = 23^o[/tex]
Generally at the point where the light enters the material , from Snell's law we have that
[tex]n = \frac{sin (\theta_i)}{sin (\theta_{r})}[/tex]
Here n is the refractive index of the material
=> [tex]n = \frac{sin (30)}{sin (23)}[/tex]
=> [tex]n = 1.28[/tex]
Generally for total internal reflection , the critical angel is evaluated using Snell law as follows
[tex]n = \frac{sin (90)}{sin (c)}[/tex]
=> [tex]1.28 * sin (c) = sin(90)[/tex]
=> [tex]c = sin^{-1} [0.7813 ][/tex]
=> [tex]c = 51.38 ^o[/tex]
Which statement is true of all matter?
A. It must have volume only
B. It must be visit
C. It must be solid
D. It must have made and volume
Answer:
D. It must have mass and volume
Explanation:
In science, matter is referred to as any substance that has weight and occupies space. This means that the substance must have a MASS of its own when weighed and also a VOLUME.
Matter include elements, molecules, humans, etc. In fact, almost every substance on Earth is considered MATTER. Therefore, the fact that a substance must "have mass and volume" is true for all matter.
how does technology or research of a nuclear physicist involve electromagnetic or sound waves
Answer: While quantum physics is usually concerned with the basic building blocks of light and matter, for some time scientists have now been trying to investigate the quantum properties of larger objects, thereby probing the boundary between the quantum world and everyday life. For this purpose, particles are slowed down with the help of electromagnetic waves and the motional energy is drastically reduced. Therefore, one also speaks of "motional cooling."
Quantum properties occur when particles are cooled to their fundamental quantum ground state, that is to the lowest possible energy level. While so far the only way to cool particles to the ground state has been to make them interact with photons trapped in an electromagnetic resonator, theoretical physicists led by Carlos Gonzalez-Ballestero and Oriol Romero-Isart from the Department of Theoretical Physics at the University of Innsbruck and the Institute of Quantum Optics and Quantum Information (IQOQI) of the Austrian Academy of Sciences in collaboration with experimentalist Jan Gieseler from Harvard University and ICFO in Barcelona now propose to make the motion of magnetic particles interact with the internal acoustic waves that are confined inside every particle.
Explanation:
Sound waves in micro-magnets
In analogy to photons -- the quanta of light -- vibrations in a solid body can be described as so-called phonons. These small sound wave packets propagate through the crystal lattice of the solid. "The phonons are very isolated and interact with the movement of the particle motion only through magnetic waves," explains Carlos Gonzalez-Ballestero. "In our work we now show that this interaction can be controlled by a magnetic field." This allows to realize quantum experiments without photons, and therefore even with light-absorbing particles. "Conversely, we also show that the strong interaction between motion and phonons provides a path to probe and manipulate the elusive and exotic dynamics of acoustic and magnetic waves in very small particles," adds Oriol Romero-Isart. The new method also opens up new possibilities for quantum information processing, for example, by using phonons as a quantum memory.
The first law of thermodynamics relates the heat transfer into or out of a system to the change of internal and the work done on the system. How much heat, in joules, is transferred into a system when its internal energy decreases by 155 J while it was performing 28.5 J of work?
Answer:
The heat transferred into the system is 183.5 J.
Explanation:
The first law of thermodynamics relates the heat transfer into or out of a system to the change of internal and the work done on the system, through the following equations.
ΔU = Q - W
where;
ΔU is the change in internal energy
Q is the heat transfer into the system
W is the work done by the system
Given;
ΔU = 155 J
W = 28.5 J
Q = ?
155 = Q - 28.5
Q = 155 + 28.5
Q = 183.5 J
Therefore, the heat transferred into the system is 183.5 J.
How does the magnitude of the gravitational force FYFY exerted by Planet Y on its satellite compare to the gravitational force FXFX exerted by Planet X on its satellite
Answer:
B ( Fy=3/4Fx)
Explanation:
A 90-kg skydiver jumps from a height of 6000 m above the ground, falling head-first (pike position). The area of the diver is 0.14 m^2. The value for C is 1.0, and the density of air is 1.21 kg/m^3. Determine the terminal velocity.
a. 49 m/s
b. 68 m/s
c. 83 m/s
d. 102 m/s
Answer:
The correct option is d: 102 m/s.
Explanation:
The terminal velocity is given by:
[tex]v = \sqrt{\frac{2mg}{\rho AC}}[/tex] (1)
Where:
m: is the mass = 90 kg
g: is the gravity = 9.81 m/s²
A: is the area = 0.14 m²
C: is the drag coefficient = 1.0
ρ: is the density of the air = 1.21 kg/m³
Now, by entering the above values into equation (1) we have:
[tex]v = \sqrt{\frac{2mg}{\rho AC}} = \sqrt{\frac{2*90 kg*9.81 m/s^{2}}{1.21 kg/m^{3}*0.14 m^{2}*1.0}} = 102 m/s[/tex]
Therefore, the correct option is d: 102 m/s.
I hope it helps you!
A 0.50-kg block slides across a tabletop with an initial velocity of 20 cm/s and comes to rest in a distance of 70 cm. Find the friction force that act on the block.
Answer:
FAE= 0.014 N
Explanation:
The KE of block is decreased because of the slowing action of the friction force .
Change in KE of block = work done on block by friction ƒ
⠀ ➪ ½mu²ƒ - ½mu²i = Fƒs cos θ
Because the friction force on the block is opposite in direction to the displacement , cos θ = -1
➢ Using Uƒ = 0 , Vƒ = 0.20 m/s , and s = 0.70 m
✒ We find ,
➪½mu²ƒ - ½mu²i = Fƒs cos θ
➪0-½ (0.50 kg) (0.20 m/s)² = (Fƒ) (0.70 m) (-1)
➪ Fƒ = 0.014 N
Hope this helped, can i pls have brainliest
The force of friction that acts on the block is equal to 0.07143 N.
What is kinetic friction?Kinetic friction can be described as a force that acts between moving surfaces of objects. An object moving on the surface will experience a force in the opposite direction of its movement. The magnitude of the friction force will depend on the coefficient of kinetic friction between the two objects.
The mathematical equation of the kinetic friction can be expressed as:
F = μ N
where 'μ' is the coefficent of Kinetic friction of the body.
Given, the initial velocity of the block, u = 20 cm/s = 0.2 m/s
The final velocity of the block, v = 0
The mass of the sliding block, m = 0.50 Kg
The distance traveled by the block, S = 0.70 m
The average force of friction can be calculated as:
W = (1/2) m(v - u)
- F. S = 1/2 m (v - u)
- F ×0.7 = 1/2 [0.5 × (0 - 0.2)]
- 0.7 F = - 0.05
F = 0.07143 N
Therefore, the friction force acting on the block is 0.07143 N.
Learn more about kinetic friction, here:
https://brainly.com/question/14111192
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The net force on a 2.1 kg bowling ball is 120 N forward. What is the acceleration of
the bowling ball?
Answer:
[tex]57.1 \ m/s^2[/tex]
Explanation:
The Newton's Second Law of Motion
The second Newton's law states that the acceleration of an object is dependent upon two variables: the net force acting upon the object and the mass of the object.
The formula is:
[tex]\displaystyle a=\frac{F}{m}[/tex]
The bowling ball has a mass of m=2.1 Kg and is exerted a force of 120 N, thus:
[tex]\displaystyle a=\frac{120}{2.1}[/tex]
[tex]a=57.1 \ m/s^2[/tex]
The acceleration of the bowling ball is [tex]\mathbf{57.1 \ m/s^2}[/tex]
If a car is rounding a flat curve on a highway, what is the centripetal force on the car?
Answer:
The net force on a car traveling around a curve is the centripetal force, Fc = m v2 / r, directed toward the center of the curve.
For a level curve, the centripetal force will be supplied by the friction force between the tires and roadway.
A banked curve can supply the centripetal force by the normal force and the weight without relying on friction.
Explanation:
Two cars A and B are moving along a straight road in the same direction with velocities of 25km/h and 30km/h , respectively. Find the velocity of car B relative to car A
if you exert a force of 12 N to lift a box a distance of 1.46m, how much work do you do?
Answer: work of 17.52 J is done
Explanation:
Given that;
Force F = 12 N
distance d = 1.46 m
work W = ?
we know that work done is force F multiple by distance d
so Work W = force F × distance d
we substitute our values
Work done W = 12 × 1.46
W = 17.52 J
Therefore a work of 17.52 J is done
Calculate the mass of an object given a net force of 5N right and an
acceleration of 5 m/s2 right.
Explanation:
F= MA
5N= M multiply by 5m/s 2
M=5/5
M = 1 kg
The average mass for a spacesuit plus astronaut is 191 kg. The average speed for air molecules inside the space suit is 549 m/s and has a density of 1.05 kg/m^3. If the air escapes Whatney's suit at 0.020 m^3/s moving directly away from him, how fast will he be going after 8.1 seconds (in m/s) if he started from rest?
Answer:
The value is [tex]v_a = 0.489 \ m/s[/tex]
Explanation:
From the question we are told that
The mass of the spacesuit plus astronaut is [tex]m = 191 \ kg[/tex]
The average speed of air molecules is [tex]v = 549 \ m/s[/tex]
The density of air molecule is [tex]\rho = 1.05 \ kg / m^3[/tex]
The acceleration of the air from Whatney's suit is [tex]a = 0.020 \ m/s^2[/tex]
The time considered is [tex]t = 8.1 \ s[/tex]
Generally the mass of air that have left Whatney's suit after the time considered is mathematically represented as
[tex]M = a * \rho * t[/tex]
=> [tex]M = 0020 * 1.05 * 8.1[/tex]
=> [tex]M = 0.1701 \ kg[/tex]
Generally the momentum of the escaped air is
[tex]p = M * v[/tex]
=> [tex]p = 0.1710 * 549[/tex]
=> [tex]p = 93.38 \ kg \cdot m/s[/tex]
Generally from the law of momentum conservation
[tex]p = p_a[/tex]
Here [tex]p_a[/tex] is the momentum of the astronaut at the considered time
[tex]93.38 = m * v_a[/tex]
Here [tex]v_a[/tex] is the velocity of the astronaut at the considered time
=> [tex]93.38 = 191 * v_a[/tex]
=> [tex]v_a = 0.489 \ m/s[/tex]
Which gas is forming in the test tube shown below?
Answer:
Oxygen
Explanation:
The goal of photosynthesis is to convert radiant energy from a light source, which the lamp acts as this form of energy; and thus, turns that into chemical energy that is used for its 'food'. As a result of the green water plant and water present, photosynthesis converts carbon dioxide and water into oxygen, and even glucose! Without photosynthesis making the glucose, it would not be possible for cellular respiration to make ATP (or much less ATP would be produced). Both processes are important to the carbon cycle.
A rock of mass M with a density twice that of water is sitting on the bottom of an aquarium tank filled with water. The normal force exerted on the rock by the bottom of the tank is:________.a. Mg/2b. 2Mgc. zerod. impossible to determine from the information givene. Mg
Answer:
a) Mg/2
Explanation:
if the rock is sitting on the bottom of the aquarium, this means that it is not accelerated in the vertical direction.In this direction , we have three forces acting on the rock:1) Gravity, going downward.2) Buoyant Force, going upward.3) Normal Force, going upward.The gravity force, can be expressed in terms of the mass as the product of the density times volume, as follows:[tex]F_{g} = \delta_{r} *V*g (1)[/tex]
The buoyant force is equal to the weight of the water displaced by the rock, which can be expressed also in terms of the density, as follows:[tex]F_{b} = \delta_{w} *V*g (2)[/tex]
From the givens, we know that δr = 2*δw (3)Now, applying Newton's 2nd law in the vertical direction, as net force is zero, we have:[tex]F_{g} =F_{b} + F_{n} (4)[/tex]
Due to the normal force can take any value, we can write (4) as follows:[tex]F_{n} = F_{g} -F_{b} (5)[/tex]
Replacing Fg and Fb by (1) and(2), applying the condition (3), we get:[tex]F_{n} =2* \delta_{w} *V*g - \delta_{w} *V*g = \delta_{w} *V*g (6)[/tex]
⇒ Fn = (m*g)/2
How many half-lives must go by for the radioactivity of this isotope to drop to (1/512) of its original value?
Answer:
I think 32
Explanation:
A student using a tuning fork of frequency 512 Hz observes that the speed of sound is 340.0 m/s. What is the wavelength of this sound wave
Answer:
0.066m
Explanation:
Step one:
given
frequency =512 Hz
The speed of sound is 340.0 m/s.
Required
The wavelength
Step two:
the formula for wavelength is
[tex]v=f \lambda[/tex]
[tex]\lambda= v/f[/tex]
substitute the given data
[tex]\lambda= 340/514\\\\\lambda= 0.66m[/tex]
For the circuit below, calculate the current drawn from the battery and in the current through each 8 W resistors.
An object with a initial velocity of 0m/s accelerates at a rate of 4m/s how much time did it take to go 88m?
Answer:
6.633s
Explanation:
For this equation we use the following kinematic equation:
^D = Vi(t)+(1/2)(a)(t)^2
88m-0m = 0m/s(t)+(0.5)(4m/s^2)(t)^2
88m = 2m/s^2(t^2)
t^2 = 44s
t = sqrt(44)
t = 6.633s
Describe how water can be both physical and chemical weathering.
Explanation:
Both because water can fall in holes and then freeze. However, water can also be chemically react with other elements and substances to wear something away.
Kindly answer the question about Work and Power. Image is attached below.
Brainliest to correct answer.
Answer:
89600 Watts.
Explanation:
From the question given above, the following data were obtained:
Mass (m) of speedboat = 2800 Kg
Initial velocity (u) = 0 m/s
Final velocity (v) = 16 m/s
Time (t) = 8 s
Power (P) expended by the speedboat =?
Next, we shall determine the acceleration of the speedboat. This can be obtained as follow:
Initial velocity (u) = 0 m/s
Final velocity (v) = 16 m/s
Time (t) = 8 s
Acceleration (a) =?
v = u + at
16 = 0 + (a × 8)
16 = 0 + 8a
16 = 8a
Divide both side by 8
a = 16/8
a = 2 m/s²
The acceleration of the speedboat is 2 m/s²
Next, we shall determine the force exerted by the speedboat. This can be obtained as follow:
Mass (m) of speedboat = 2800 Kg
Acceleration (a) of speedboat = 2 m/s²
Force (F) of speedboat =?
F = ma
F = 2800 × 2
F = 5600 N
Finally, we shall determine the expended by the speedboat at maximum speed. This can be obtained as follow:
Force (F) of speedboat = 5600 N
Maximum velocity (v) = 16 m/s
Power (P) expended by the speedboat =?
P = F × v
P = 5600 × 16
P = 89600 Watts
Thus, the power expended by the speedboat is 89600 Watts.
A light spring obeys Hooke's law. The spring's unstretched length is 33.5 cm. One end of the spring is attached to the top of a doorframe and a weight with mass 7.00 kg is hung from the other end. The final length of the spring is 42.0 cm. What if
Answer:
807.88N/m
Explanation:
The question has some missing details in it, nevertheless, based on the given data we want to find the spring constant K
Step one
given data
Unstretched length = 33.5 cm
Final length of the spring = 42.0 cm
Δx= 42-33.5
Δx=8.5cm to m= 0.085m
mass m= 7kg
The force on the spring
F=mg
F= 7*9.81
F=68.67N
Step two:
From Hooke's law, we can make k subject of formula and find the spring constant k, we have
F=kΔx---------1
make k subject of the formula
k=F/Δx
k= 68.67/ 0.085
k=807.88N/m
7. Physical responses to stress can include
a. faster breathing.
b. tense muscles.
c. widening of the pupils.
d. All of the above
Answer:
D
Explanation:
I'm not sure but I think so haha
If it requires 2.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be required to stretch it an additional 4.0 cm?
Answer:
16 J
Explanation:
It is given that,
Work done, W = 2 J
A spring is stretched by 2.0 cm from its equilibrium length
We need to find how much more work will be required to stretch it an additional 4.0 cm.
Let k is the spring constant of the spring. When W = 2J, and x = 2 cm, then energy required to stretch the spring is :
[tex]U=\dfrac{1}{2}kx^2\\\\k=\dfrac{2U}{x^2}\\\\k=\dfrac{2(2)}{(0.02)^2}\\\\k=10000\ N/m[/tex]
The energy required to stretch the spring from 2 cm to additional 4 cm i.e. 2+4= 6 cm.
[tex]W=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 10000\times ((0.06)^2-(0.02)^2)\\\\W=16\ J[/tex]
So, the required work done is 16 J.
What does a negative acceleration mean if the object has positive velocity?
Answer:
An object which moves in the positive direction has a positive velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion . If velocity and acceleration have opposite signs, you slow down. Negative velocity = You move backwards. Negative acceleration - You slow down or you go faster in the backwards direction
Explanation:
Explanation:
An object which moves in the positive direction has a positive velocity.
If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion aka negative velocity.
PLS HURRY
Which statement best compares potential and kinetic energy?
O Objects always have more potential energy than kinetic energy.
O Kinetic energy increases and potential energy decreases when the velocity of an object increases
O Only potential energy decreases when an object's height increases.
O Objects always have more kinetic energy than potential energy.
Answer:
The second one is the answer
Suppose a 6.00 nC electric charge is in the beam. What is the maximum electric force (in N) it experiences? If the static charge moves at 300 m/s, what maximum magnetic force (in N) can it feel?
Complete Question
Electromagnetic radiation from a 3.00 mW laser is concentrated on a 2.00 mm2 area. Suppose a 6.00 nC electric charge is in the beam. What is the maximum electric force (in N) it experiences? If the static charge moves at 300 m/s, what maximum magnetic force (in N) can it feel?
Answer:
The value are
[tex]F = 6.378 *10^{-6} \ N[/tex]
and
[tex]F_k = 6.381 *10^{-12} \ N[/tex]
Explanation:
From the question we are told that
The power of the laser is [tex]P = 3.00 mW = 3.00*10^{-3} \ W[/tex]
The area is [tex]A = 2.00 \ mm^2 = 2.0 *10^{-6} \ m^2[/tex]]
The speed is [tex]v = 300 \ m/s[/tex]
The magnitude of the electric charge is [tex]Q = 6.00 nC = 6.00 *10^{-9} \ C[/tex]
Generally the intensity of the beam is mathematically represented as
[tex]I = \frac{P}{A}[/tex]
=> [tex]I = \frac{3.00 *10^{-3}}{ 2.0 *10^{-6}}[/tex]
=> [tex]I = 1500 \ W/m^2[/tex]
Generally the magnitude of the electric field is mathematically represented as
[tex]E_m = \sqrt{\frac{2I}{c \epsilon_o} }[/tex]
Here c is the speed of light with value [tex]c = 3.0*10^{8} \ m/s[/tex]
[tex]\epsilon_o[/tex] is the permittivity of free space with value [tex]\epsilon_o = 8.85*10^{-12} C/(V \cdot m)[/tex]
[tex]E_m = \sqrt{\frac{2 * 1500 }{3.0*10^{8} *8.85*10^{-12} } }[/tex]
=> [tex]E_m = 1063 \ V/m[/tex]
Generally the maximum electric force is mathematically represented as
[tex]F = Q * E_m[/tex]
=> [tex]F = 6*10^{-9 } * 1063[/tex]
=> [tex]F = 6.378 *10^{-6} \ N[/tex]
Generally the intensity of the beam can also be mathematically represented as
[tex]I = \frac{ c * B^2 }{ 2 * \mu_o}[/tex]
Here B is the magnetic field
[tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]
So
[tex]B = \sqrt{\frac{2 * \mu_o * I }{c} }[/tex]
=> [tex]B = \sqrt{\frac{2 * 4 \pi *10^{-7} * 1500 }{3.0*10^{8}} }[/tex]
=> [tex]B = 3.545*10^{-6} \ T[/tex]
Generally the maximum magnetic force is mathematically represented as
[tex]F_k = Q * v * B[/tex]
=> [tex]F_k = 6.00 *10^{-9} * 300 * 3.545*10^{-6}[/tex]
=> [tex]F_k = 6.381 *10^{-12} \ N[/tex]
A body with mass m slides down a frictionless ramp inclined at 600, with an initial speed v1 = 3 m/s,
starting at height h, and continues its motion upward on a 300 inclined ramp with a friction. Than this
body hits a spring which is fixed to a wall and compresses it 10 cm. The spring is initially at a distance R
on horizontal plane, and at height h. Find:
a) The speed v2 at the point 0, where the body starts to climb up to 300 inclined ramp, in terms of h.
b) The speed v3 where it hits the spring.
c) The spring constant k.
m=0.1 kg, µk=0.1, R=2.5 m., v1=3 m/s, Cos(600) = 0.5, Sin(600)=0.87, x=10 cm. and g= 10 m/s2 .
Going down the first ramp:
• net force parallel to the ramp:
∑ F = W sin(60°) = m a₁
(W for weight)
• net force perpendicular to the ramp:
∑ F = N + W cos(60°) = 0
(N for normal force)
The body has mass 0.1 kg, and with g = 10 m/s², its weight is W = 1 N. So in the first equation, we get
(1 N) sin(60°) = (0.1 kg) a₁ → a₁ ≈ 8.7 m/s²
Let d₁ be the distance the body moves down the ramp, i.e. the distance along the ramp between the starting point and the point O. Then
sin(60°) = h / d₁ → d₁ = 2h/√(3) ≈ 1.15h
Given an initial speed v₁ = 3 m/s, we find the speed v₂ at point O to be
v₂² - (3 m/s)² = 2 (8.7 m/s²) d₁
v₂ ≈ √(9 m²/s² + (17.4 m/s²) (1.15h))
v₂ ≈ √(9 m²/s² + (20 m/s²) h)
Going up the second ramp:
• net parallel force:
∑ F = -Fr - W sin(30°) = m a₂
(Fr for friction)
• net perpendicular force:
∑ F = N - W cos(30°) = 0
sin(30°) = cos(60°), and cos(30°) = sin(60°), so the second equation gives N = 0.87 N. Then with µ = 0.1, we have Fr = µ N = 0.087 N. The first equation then gives
-0.087 N - 0.5 N = (0.1 kg) a₂ → a₂ ≈ -5.9 m/s²
We now have
tan(30°) = h/R → h = (2.5 m)/√3 ≈ 1.4 m
(which, by the way, tells us that v₂ ≈ 6.2 m/s)
Then the distance traveled up the ramp is
d₂ = √(h² + R ²) ≈ 2.9 m
Use this to solve for the speed at the top of the ramp:
v₃² - v₂² = 2 (-5.9 m/s²) d₂
v₃ = √((6.2 m/s)² - (11.8 m/s²) (2.9 m)) ≈ 2.0 m/s
At the top of the second ramp:
• net parallel force:
∑ F = -Fsp - W sin(30°) = m a₂
(Fsp for spring)
• net perpendicular force:
∑ F = N - W cos(30°) = 0
By Hooke's law, Fsp = kx, so in the first equation we get
-k (0.10 m) - (1 N) cos(60°) = (0.1 kg) (-5.9 m/s²)
→ k ≈ 0.87 N/m
How are free throws diffrent from ordinary shots
Answer: They are only taken when a player from the other team does something wrong. And they are only worth 1 point
Explanation:
Answer: You don't jump on your free throws, since they are not a jumpshot or layup and since u were fouled, they're only worth 1pt each.
Explanation:
Two waves overlap producing a new wave that exhibits destructive
interference. Which statement correctly describes the new wave?
A. It has a larger amplitude than the waves that overlapped to produce it.
B. It has a smaller amplitude than the waves that overlapped to produce it.
C. It has deeper troughs than the waves that overlapped to produce it.
D. It has taller crests than the waves that overlapped to produce it.
Two waves overlap producing a new wave that exhibits destructive
interference will have a smaller amplitude than the waves that overlapped to
produce it.
Interference is a phenomenon which occurs when two waves travelling in
the same medium( which could be water, air etc) meet. There are two types
of interference namely:
Constructive interference.Destructive interference.The destructive interference involves the positive and negative
displacement canceling out which result in zero displacement or
amplitude.This fact validates option B which states that the new wave will
have smaller amplitude than the waves that overlapped to produce it.
Read more about Interference here https://brainly.com/question/9655287
Answer: B
Explanation: just took it
