Question 2 (10 points) When hydrogen is added to the structure of an oil, the melting points goes down, and the oil becomes thinner and easier to pour. True False

Answer:

5% is the answer I think

Step-by-step explanation:

I hope this helps

Answer:

5

Step-by-step explanation:

Y= 4/80

4/80 * 100/100 = 5/100

Y= 5

To find the probability of the event "the first die is 6 or the sum is 8," we need to count the number of outcomes that satisfy this event and divide it by the total number of possible outcomes.

To find the probability of the event "the first die is 6 or the sum is 8," we need to consider the total possible outcomes when rolling two dice and the favorable outcomes for this event.

Total possible outcomes: 6 sides on each die, so there are 6 x 6 = 36 possible outcomes.

Favorable outcomes:
1. First die is 6: There are 6 possible outcomes (6,1), (6,2), (6,3), (6,4), (6,5), and (6,6).
2. Sum is 8: There are 5 possible outcomes (2,6), (3,5), (4,4), (5,3), and (6,2).

However, (6,2) is counted twice, so we should subtract 1 from the total favorable outcomes: 6 + 5 - 1 = 10.

Probability = Favorable outcomes / Total possible outcomes = 10/36. Simplifying the fraction gives 5/18.

So, the probability of the event "the first die is 6 or the sum is 8" is 5/18.

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The sample space for rolling a fair six-sided die is {1, 2, 3, 4, 5, 6}.

option C.

A sample space describes the possible outcome of an event.

The sample space for rolling a fair six-sided die consists of the six possible outcomes and we can list them as follows;

S = {1, 2, 3, 4, 5, 6}

Each outcome represents the number that appears on the top face of the die after it is rolled. So this sample space contains all the likely outcome each time we roll the die.

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Answer

The result of 48 - 36 is 12. Then, if you divide 12 by 36, the result is 0.3333 or 1/3.

Step-by-step explanation:

The given absolute value function is f(x) = |x - 3x|.

To evaluate absolute value function f(-2), we substitute -2 in place of x:

f(-2) = |-2 - 3(-2)|

= |-2 + 6|

= |4|

= 4

Therefore, f(-2) = 4.

To evaluate f(0), we substitute 0 in place of x:

f(0) = |0 - 3(0)|

= |0|

= 0

Therefore, f(0) = 0.

To evaluate f(2), we substitute 2 in place of x:

f(2) = |2 - 3(2)|

= |-4|

= 4

Therefore, f(2) = 4.

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The approximate amount of area in the circle is 113.04 square feet.

The area of a circle is given through the expression [tex]A = \pi r^2[/tex], in which π is about equal to 3.14, and r is the radius of the circle.

In this instance, we are given the diameter of the circle, that is 12 feet. The radius of the circle is half of the periphery, so the radius is

r = 12 / 2 = 6 feet

Now, we're suitable to use the methodology for the area of a circle to discover the approximate amount of space within the circle

[tex]A = \pi r^2 = 3.14 * 6^2 = 3.14 * 36 \approx 113.04[/tex] square feet[tex]A = \pi r^2[/tex]

Accordingly, the approximate amount of area in the circle is 113.04 square feet.

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The component form and magnitude of the vector are;

v = 3·i - 2·j

||v|| = √(14)

The component form of a vector is expressed as <x, y>, which indicates the distance of the vector to the right or left, x-component, and the distance up or down of the y-component.

The coordinate points on the vector are; (0, 0), and (3, -2)

The component form of the vector consists of the horizontal and vertical components, which can be found as follows;

Horizontal component = (3 - 0)·i = 3·i

The vertical component = (-2 - 0)·j = -2·j

The component form of the vector is therefore;

v = ⟨3, -2⟩

The magnitude of the vector can be obtained as follows;

||v|| = √((3 - 0)² + (-2 - 0)²) = √(14)

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Step-by-step explanation:

g(6) = 3 - 5(6) = 3 - 30 = -27

We know the value of function g at 1 single point, g(6) = -27.

That is not enough to know what function g is.

Since the problem states that g(6) = 3 - 5(6), the problem is trying to guide you into answering that g(x) = 3 - 5x, but this is simply an assumption.

The smaller number is 1 and the larger number is 2. To find these numbers, we used algebraic equations and solved for one variable in terms of the other.

To solve this problem, we need to use algebraic equations. Let's call the smaller number "x" and the larger number "y".

From the problem, we know that:

x + y = 3 (the sum of two numbers is 3)

y - 2x = 0 (the larger number minus twice the smaller number is zero)

Now, we can solve for one variable in terms of the other:

y = 2x (by rearranging the second equation)

Substituting this into the first equation, we get:

x + 2x = 3

3x = 3

x = 1

Now that we know x is 1, we can use the equation y = 2x to find y:

y = 2(1) = 2

Therefore, the two numbers are 1 and 2.

In summary, the smaller number is 1 and the larger number is 2. To find these numbers, we used algebraic equations and solved for one variable in terms of the other. It's important to carefully read and understand the problem and to keep track of the information given.

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Answer:

11

Step-by-step explanation:

Volume of right cone = (1/3) · π · r² · h

V = 968π

h = 24 units

Let's solve

968π = (1/3) · π · r² · 24

2904π =  π · r² · 24

121π = π · r²

121 = r²

r = 11

So, the radius is 11 units.

The solution to this equation 4x² – 15x = 4 include the following: D. x = 4, -1/4.

In Mathematics and Geometry, the general form of a quadratic function can be modeled and represented by using the following quadratic equation;

y = ax² + bx + c

Where:

Next, we would solve the quadratic function by using the factorization method as follows;

4x² – 15x = 4

Subtract 4 from both sides of the quadratic function:

0 = 4x² – 15x - 4

0 = 4x² - 16x + x - 4

(4x + 1)(x - 4)

x = 4 or x = -1/4.

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The area of the given rectangle is 322 square miles.

We know that the area of a rectangle is equal to the product between the dimensions. In this case we know that the dimensions of the rectangle are:

Length  = 23 miles.

Width = 14 miles.

Then the area of this rectangle will be a product between these two values, we will get:

Area = (23 mi)*(14 mi)

Area = 322 mi ²

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The estimated value of λ and x = 2.91, we get:

P(1.2 ≤ median load ≤ 6) = 1 - e^(-0.38*2.91) - (

2.2.1 To calculate the probability that the maximum load is at least 3, we first need to find the distribution of the maximum load. Let X be the random variable representing the loads. Then the probability that the maximum load is less than or equal to x is given by:

P(X ≤ x)^n = (1 - e^(-λx))^n

where n is the sample size. Taking the derivative of this expression with respect to x and setting it equal to zero, we get:

n(1 - e^(-λx))^(n-1)λe^(-λx) = 0

Solving for x, we get

x = -ln(1 - 1/n)/λ

Now, we can calculate the probability that the maximum load is at least 3 as follows:

P(X ≤ 3)^n = (1 - e^(-λ*3))^n

P(maximum load ≥ 3) = 1 - P(X ≤ 3)^n

Substituting the estimated value of λ (sample variance of the loads) and the sample size n = 5, we get:

P(maximum load ≥ 3) = 1 - (1 - e^(-0.38*3))^5 ≈ 0.578

Therefore, the probability that the maximum load is at least 3 is approximately 0.578.

2.2.2 To calculate the probability that the minimum load is no more than 4.11, we can use the same approach as in 2.2.1, but with the inequality flipped:

P(minimum load ≤ 4.11) = 1 - P(X ≥ 4.11)^n

where we need to find the distribution of the minimum load. The probability that the minimum load is greater than or equal to x is given by:

P(X ≥ x) = e^(-λx)

Substituting the estimated value of λ and x = 4.11, we get:

P(minimum load ≤ 4.11) = 1 - e^(-0.38*4.11) ≈ 0.448

Therefore, the probability that the minimum load is no more than 4.11 is approximately 0.448.

2.2.3 To calculate the probability that the median load is between 1.2 and 6, we first need to estimate the median load from the sample. The sample is already sorted as 2.39, 2.51, 2.91, 3.08, 3.11. The median load is the middle value, which is 2.91.

The probability that the median load is less than or equal to x is given by:

P(median load ≤ x) = P(X1 ≤ x, X2 ≤ x, X3 ≥ x, X4 ≥ x, X5 ≥ x) + P(X1 ≤ x, X2 ≤ x, X3 ≥ x, X4 ≥ x, X5 ≤ x) + P(X1 ≤ x, X2 ≤ x, X3 ≥ x, X4 ≤ x, X5 ≥ x)

where Xi represents the ith load in the sample. The probability that the median load is between 1.2 and 6 is then given by:

P(1.2 ≤ median load ≤ 6) = P(median load ≤ 6) - P(median load ≤ 1.2)

Substituting the estimated value of λ and x = 2.91, we get:

P(1.2 ≤ median load ≤ 6) = 1 - e^(-0.38*2.91) - (

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The cam lift is 3 1/2 inches, which is option D.

To determine the lift of the cam, we need to find the distance from the center of the disc to the highest point of the cam surface.

First, we can find the distance from the center of the disc to the edge of the 1/2" hole. Since the hole is drilled 1 1/2" off-center, this distance is:

(4"/2) - 1 1/2" = 1"

Next, we can find the radius of the cam surface by adding the radius of the shaft (1/2") to the distance from the center of the disc to the edge of the 1/2" hole (1"):

1/2" + 1" = 1 1/2"

Finally, we can find the distance from the center of the disc to the highest point of the cam surface by adding the radius of the disc (4"/2 = 2") to the radius of the cam surface (1 1/2"):

2" + 1 1/2" = 3 1/2"

Therefore, the lift of the cam is 3 1/2 inches, which is option D.

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Answer:

To calculate the probability that Kaelyn was selected out of 30 people chosen at random from a group of 480 people, we can use the concept of probability.

Given:

Total number of people in the group (N) = 480

Number of people chosen (n) = 30

We want to find the probability of Kaelyn being selected, which is the probability of selecting 1 person out of 480 people, or 1/480.

So, the probability that Kaelyn was selected is:

P(Kaelyn) = 1/480

This is the final answer, as it represents the probability of Kaelyn being selected out of 30 people chosen at random from a group of 480 people.

Step-by-step explanation:

Answer:

To calculate the probability that Kaelyn was selected out of 30 people chosen

Step-by-step explanation:

The probability that the answer is correct given that the

a) Let's use Bayes' theorem to calculate the probability that the answer is correct given that the person you asked said "East". Let H be the event that the person is honest, L be the event that the person is a liar, E be the event that Julia resides in the East and W be the event that Julia resides in the West. Then we have:

P(E|H) = 2/3 (the probability that an honest person gives the correct answer)

P(E|L) = 1/2 (the probability that a liar gives the correct answer)

P(H) = 1/4 (the probability that the person is honest)

P(L) = 3/4 (the probability that the person is a liar)

By the law of total probability, we have:

P(E) = P(E|H)P(H) + P(E|L)P(L) = (2/3)(1/4) + (1/2)(3/4) = 5/12

Then, using Bayes' theorem, we have:

P(H|E) = P(E|H)P(H)/P(E) = (2/3)(1/4)/(5/12) = 2/5

So the probability that the answer is correct given that the person said "East" is 2/5.

b) The probability that the same person gives the same answer twice in a row is:

P(E∩E) = P(E)P(E|H)P(H) + P(E)P(E|L)P(L) = (5/12)(2/3)(1/4) + (5/12)(1/2)(3/4) = 5/24

Using Bayes' theorem again, we have:

P(H|EE) = P(EE|H)P(H)/P(EE) = (2/3)^2(1/4)/(5/24) = 8/15

So the probability that the answer is correct given that the person said "East" twice in a row is 8/15.

c) The probability that the same person gives the same answer three times in a row is:

P(E∩E∩E) = P(E)P(E|H)^2P(H) + P(E)P(E|L)^2P(L) = (5/12)(2/3)^2(1/4) + (5/12)(1/2)^2(3/4) = 5/32

Using Bayes' theorem again, we have:

P(H|EEE) = P(EEE|H)P(H)/P(EEE) = (2/3)^3(1/4)/(5/32) = 4/5

So the probability that the answer is correct given that the person said "East" three times in a row is 4/5.

d) The probability that the same person gives the same answer four times in a row is:

P(E∩E∩E∩E) = P(E)P(E|H)^3P(H) + P(E)P(E|L)^3P(L) = (5/12)(2/3)^3(1/4) + (5/12)(1/2)^3(3/4) = 5/48

Using Bayes' theorem again, we have:

P(H|EEEE) = P(EEEE|H)P(H)/P(EEEE) = (2/3)^4(1/4)/(5/48) = 16/25

So the probability that the answer is correct given that the

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When you add opposite numbers, the sum is 0. Then the correct option is A.

A number line refers to a straight line in mathematics that has numbers arranged at regular intervals or portions along its width. A number line is often shown horizontally and can be postponed in any direction.

Let if 'a' lie on the number axis. Then the opposite of the number 'a' will be '-a'. Then the addition of the numbers is calculated as,

⇒ a + (-a)

⇒ a - a

⇒ 0  

When you add opposite numbers, the sum is 0. Then the correct option is A.

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In either case, we can solve for A and B using the initial condition i(0) = 0. This gives us the final form of the current function i(t) for the given RLC circuit.

The current function i(t) in the RLC circuit, we need to solve the differential equation given by Kirchhoff's Second Law: L di/dt + Ri(t) + 1/c ∫ i(r) dr= V(t), subject to the initial condition i(0) = 0.

To begin, we can simplify the equation by substituting V(t) = 1/(1+t) and integrating the integral term by parts. This gives us:

L di/dt + Ri(t) + 1/c [i(t) * t - ∫t0 i(t)dt] = 1/(1+t)

Next, we can differentiate both sides with respect to t, which gives:

[tex]L d^2i/dt^2 + R di/dt + i(t)/c = -1/(1+t)^2[/tex]

This is a second-order linear ordinary differential equation with constant coefficients, and we can solve it by assuming a solution of the form i(t) = [tex]e^{(rt)[/tex]. Substituting this into the differential equation and solving for r.

We have two cases, depending on whether the discriminant R^2 - 4L(1/c) is positive, negative, or zero.

Case 1: [tex]R^2 - 4L(1/c) > 0[/tex]

In this case, we have two distinct real roots:

[tex]r_1 = (-R + \sqrt{(R^2 - 4L(1/c)))/(2L} )\\r_2 = (-R - \sqrt{(R^2 - 4L(1/c)))/(2L} )[/tex]

The general solution to the differential equation is then given by:

i(t) = A [tex]e^{(r1t)} + B e^{({(r2t)} - 1/(1+t)^2c[/tex]

Case 2: [tex]R^2 - 4L(1/c) = 0[/tex]

In this case, we have a repeated real root:

r = -R/(2L)

The general solution to the differential equation is then given by:

i(t) = [tex](A + Bt) e^{(rt)} - 1/(1+t)^2c[/tex]

Here A and B are constants determined by the initial conditions.

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Mathematical induction can be used to prove that for every integer k ≥ 5, k^2 - 3k ≥ 10.

Base Case: Let k = 5,

Then,  k^2 - 3k = 5^2 - 3(5) = 10

Since 10 >= 10 is true, the base case holds.

Inductive Step: Assume that for some integer n >= 5, n^2 - 3n >= 10 is true.

We want to prove that (n + 1)^2 - 3(n + 1) >= 10 is also true.

Expanding the left-hand side of the inequality, we get:
(n + 1)^2 - 3(n + 1) = n^2 + 2n + 1 - 3n - 3

On simplifying ,we get:
n^2 - n - 2 >= 0
On factoring,we get:

(n - 2)(n + 1) >= 0

Since n >= 5, n - 2 >= 3, and n + 1 >= 6, so both factors are positive. Therefore, the inequality is true for all n >= 5.

By mathematical induction, we have proved that for every integer k >= 5, k^2 - 3k >= 10.

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The population growth rate is given as follows:

k = 0.0213.

The exponential function modeling the population after t years is given as follows:

P(t) = P(0)e^(kt).

In which:

Considering the population in 2007, the initial population is given as follows:

P(0) = 46.8.

21 years later, we have that:

P(21) = 73.2.

Hence the rate is obtained as follows:

46.8e^(21k) = 73.2

e^(21k) = 73.2/46.8

21k = ln(73.2/46.8)

k = ln(73.2/46.8)/21

k = 0.0213.

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The difference between the two price options is $117.

After a 25% off, the annual subscription in option A would be lower.

Price after the 25% off = initial annual subscription x (1 - discount/100)

$308 x (1 - 25/100)

$308 x (1 - 0.25)

$308 x 0.75 = $231

Annual fee with option B = cost per month x 12

$29 x 12 = $348

Price difference = $348 - $231 = $117

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The exact values of the cosecant, secant, and cotangent ratios of 5π/6 are 2, -2/√3, and -√3, respectively.

To find the exact values of the cosecant, secant, and cotangent ratios of an angle of 5π/6, we need to use the definitions of these trigonometric functions and the values of the sine, cosine, and tangent of this angle.

First, we can find the sine and cosine of 5π/6 using the unit circle or reference angles:

sin(5π/6) = sin(π/6) = 1/2

cos(5π/6) = -cos(π/6) = -√3/2

Then, we can use the definitions of the cosecant, secant, and cotangent ratios:

cosec(5π/6) = 1/sin(5π/6) = 1/(1/2) = 2

sec(5π/6) = 1/cos(5π/6) = -2/√3

cot(5π/6) = cos(5π/6)/sin(5π/6) = (-√3/2)/(1/2) = -√3

Therefore, the exact values of the cosecant, secant, and cotangent ratios of 5π/6 are 2, -2/√3, and -√3, respectively.

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The simplified expression for this problem is given as follows:

[tex]\sqrt{y^6} = y^3[/tex]

The expression for this problem is defined as follows:

[tex]\sqrt{y^6}[/tex]

The power of a power rule is used when a single base is elevated to multiple exponents, and the simplified expression is obtained keeping the bases and multiplying the exponents.

The square root is equivalent to an exponent of 1/2, while the exponent of y is of 6, hence the exponent f the simplified expression is given as follows

1/2 x 6 = 3.

Hence the simplified expression for this problem is given as follows:

[tex]\sqrt{y^6} = y^3[/tex]

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If a point (x,y) is equidist point from the point (2,3) and (6,1) then the equation of locus is given by 2x -y =6

Using distance formula, the distnace between point (x, y) and (2, 3) is,

d₁ = √[(2 - x)² + (3 - y)²]

And  the distnace between point (x, y) and (6, 1) is,

d₂ = √[(6 - x)² + (1 - y)²]

A point (x,y) is equidist point from the point (2,3) and (6,1)

⇒ d₁ = d₂

⇒  √[(2 - x)² + (3 - y)²] = √[(6 - x)² + (1 - y)²]

⇒ (2 - x)² + (3 - y)² = (6 - x)² + (1 - y)²

⇒ 4 - 4x + x² + 9 - 6y + y² = 36 - 12x + x² + 1 - 2y + y²

⇒ -4x + 12x - 6y + 2y = 37 - 13

⇒ 8x - 4y = 24

⇒ 2x -y = 6

Hence proved.

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The complete question is:

if a point (x,y) is equidist point from the point (2,3) and (6,1) show that the equation of locus is given by 2x -y = 6

The ratio StartFraction 14 Over 35 EndFraction is equivalent to the other three ratios, and the ratio that is different from the others is StartFraction 8 Over 20 EndFraction.

To determine which ratio is not equivalent to the others, we need to simplify each ratio to its lowest terms.

Give the following ratios :

[tex]2 / 5 = 6 /10 = 8 / 20 = 12 / 30.[/tex]

- StartFraction 2 Over 5 EndFraction: This ratio is already in its simplest form.

- StartFraction 6 Over 10 EndFraction: We can simplify this ratio by dividing both the numerator and denominator by their greatest common factor (GCF), which is 2.

-StartFraction 6 Over 10 EndFraction = StartFraction 3 Over 5 EndFraction

- StartFraction 8 Over 20 EndFraction: We can simplify this ratio by dividing both the numerator and denominator by their GCF, which is 4.

StartFraction 8 Over 20 EndFraction = StartFraction 2 Over 5 EndFraction

- StartFraction 12 Over 30 EndFraction: We can simplify this ratio by dividing both the numerator and denominator by their GCF, which is 6.

StartFraction 12 Over 30 EndFraction = StartFraction 2 Over 5 EndFraction

Therefore, the ratios StartFraction 6 Over 10 EndFraction, StartFraction 8 Over 20 EndFraction, and StartFraction 12 Over 30 EndFraction are all equivalent to StartFraction 2 Over 5 EndFraction. The ratio that is different from the others is StartFraction 14 Over 35 EndFraction, which can be simplified by dividing both the numerator and denominator by their GCF, which is 7.

[tex]StartFraction 14 Over 35 EndFraction = StartFraction 2 Over 5 EndFraction.[/tex]

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The slope of the given line is -1.

Given is a line passing through the points (-2, 3) and (4, -3) we need to find the slope of the line,

Slope = y₂ - y₁ / x₂ - x₁

Here, (x₁, y₁) and (x₂, y₂) are (-2, 3) and (4, -3),

So, the slope of the line =

Slope = -3-3 / 4+2

= -6 / 6

= -1

Hence, the slope of the given line is -1.

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Phrase 1: A. is at most (5 2) = 10
Phrase 2: B. is at most (6 2) = 15
Phrase 3: E. equals 5 + 7 = 12
Phrase 4: E. is at most 11 + 13 + 12 = 36



To prove that two people of the same nationality shook hands, we need to estimate the maximum number of handshakes between people of different nationalities.

For Phrase 1, we need to find the maximum number of handshakes between Ukrainians and Poles. We have 6 Ukrainians and 5 Poles, and each Ukrainian can shake hands with at most 5 Poles (since they cannot shake hands with themselves or with another Ukrainian), giving us a maximum of 6 x 5 = 30 handshakes.

However, each handshake is counted twice (once for each person involved), so we divide by 2 to get the maximum number of handshakes, which is (5 x 2) = 10.

For Phrase 2, we need to find the maximum number of handshakes between Ukrainians and Slovaks. We have 6 Ukrainians and 7 Slovaks, and each Ukrainian can shake hands with at most 7 Slovaks, giving us a maximum of 6 x 7 = 42 handshakes.

However, each handshake is counted twice, so we divide by 2 to get the maximum number of handshakes, which is (6 x 2) = 12.

For Phrase 3, we need to find the maximum number of handshakes between Poles and Slovaks. We have 5 Poles and 7 Slovaks, and each Pole can shake hands with at most 7 Slovaks, giving us a maximum of 5 x 7 = 35 handshakes.

However, each handshake is counted twice, so we divide by 2 to get the maximum number of handshakes, which is (7 x 2) = 12.

For Phrase 4, we need to find the total number of handshakes between people of different nationalities. We add up the maximum number of handshakes between Ukrainians and Poles, Ukrainians and Slovaks, and Poles and Slovaks, which gives us (10 + 12 + 12) = 34.

However, we need to remember that each handshake is counted twice, so we divide by 2 to get the total number of handshakes, which is (34/2) = 17.

Since we are given that the total number of handshakes is 110, which is greater than the total number of handshakes between people of different nationalities (17), we can conclude that there must be at least one pair of people who have the same nationality and shook hands. Therefore, we have proven that if 110 handshakes were exchanged in total, then two people of the same nationality shook hands.

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The amount of money left for gift c is 15 5/10 dollars

Timothy had 30 dollars to spend on three gifts

He spent 10 9/10 dollars on gift A

He spent 3 3/5 dollars on gift B

The amount spent on gift C can be calculated as follows

10 9/10 + 3 3/5

= 109/10 + 18/5

= 545 + 180/50

= 725/50

= 145/10

30 - 145/10

= 30/1 - 145/10

= 300-145/10

= 155/10

= 15 5/10

Hence the amount of Money left for gift C is 15 5/10 dollars

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(a) 40,475,358.

(b) 330
(c) 0.0008%.

(a) To find |S|, the total number of sets of 7 distinct numbers a player can choose, we need to find the combinations of choosing 7 numbers from the 80 available options. This can be calculated using the combination formula:

C(n, k) = n! / (k! * (n - k)!)

In this case, n = 80 (total numbers) and k = 7 (numbers to choose). So, |S| = C(80, 7):

|S| = 80! / (7! * (80 - 7)!)
|S| = 80! / (7! * 73!)

(b) To find |E|, the number of sets where all 7 numbers chosen by the player are in the winning set of 11 numbers chosen by the organizers, we need to find the combinations of choosing 7 numbers from the 11 available options in the winning set:

|E| = C(11, 7)
|E| = 11! / (7! * (11 - 7)!)
|E| = 11! / (7! * 4!)

(c) To find the probability of winning, we need to calculate the ratio of the favorable outcomes (|E|) to the total possible outcomes (|S|):

P(winning) = |E| / |S|

P(winning) = (11! / (7! * 4!)) / (80! / (7! * 73!))

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