Answer:
It's the button with the x, and a blank box above it.
Explanation:
Check the attachments, you'll see what it looks like. It will probably look different on your calculator, but the icon should be the same or similar.
Write the chemical equation for the autoionization of water and label the conjugate
acid-base pairs.
The equation for the autoionization of water is-
NH3 + H2O → NH4+ + OH− (H2O acts as an acid)
HCl + H2O → H3O+ + Cl− (H2O acts as a base)
What do you mean by the autoionization of water ?Autoionization of water, the autoionization constant Kw, and the relationship between [H⁺] and [OH⁻] in aqueous solutions.
Water can undergo autoionization to form and ions.
The expression for the autoionization constant is
[tex]The expression for the autoionization constant isK_\text{w}=[\text{H}_3\text{O}^+][\text{OH}^-]\quad\quad\text{(Eq. 1)}K w =[H 3 O + ][OH − ][/tex]
In this way the autoionization of water,
NH3 + H2O → NH4+ + OH− (H2O acts as an acid)
HCl + H2O → H3O+ + Cl− (H2O acts as a base) is given.
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What does quantization refer to?
OA. Being able to move around freely
OB. Involving uncertainty in knowing a value
OC. Having a specific set of possible values
OD. Occupying a place in a continuous range
Answer:
Having a specific set of possible values
At the equivalence point of a titration of the [H+] concentration is equal to:
Group of answer choices
A. 1 x 107 M
B. 7
C. [OH-]
D. 1 x 10-7 M
B. At the equivalence point of a titration of the [H+] concentration is equal to 7.
What is equivalence point of a titration?The equivalence point of a titration is a point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution.
At the equivalence point in an acid-base titration, moles of base equals moles of acid and the solution only contains salt and water.
At the equivalence point, equal amounts of H+ and OH- ions combines as shown below;
H⁺ + OH⁻ → H₂O
The pH of resulting solution is 7.0 (neutral).
Thus, the pH at the equivalence point for this titration will always be 7.0.
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Calculate the number of moles in 15 liters of oxygen at STP.
O 0.67 mol
O 67 mol
O 360 mol
O 1.5 mol
Answer:
.67 mole
Explanation:
Using ideal gas law
PV = n RT
P = pressure = 1 atm at STP
T = 273.15 K at STP
V = 15 L
R = .082057 L-atm / K-mol
Subbing in those values:
1 (15) = n (.082057) (273.15 ) results in n = .669 moles
Calculate the molarity of a solution that has 18.0 g of glucose, C6H12O6, dissolved in 80.0 g of water.
Answer:
1.25 M
Explanation:
In this case, the solute is C₆H₁₂O₆ and the solvent is H₂O.To find the molarity, you need to (1) convert the mass C₆H₁₂O₆ to moles (via molar mass), then (2) convert grams H₂O to liters H₂O, and then (3) calculate the molarity.
(Step 1)
Molar Mass (C₆H₁₂O₆): 6(12.011 g/mol) + 12(1.008 g/mol) + 6(15.998 g/mol)
Molar Mass (C₆H₁₂O₆): 180.15 g/mol
18.0 g C₆H₁₂O₆ 1 mole
------------------------ x ----------------- = 0.0999 moles C₆H₁₂O₆
180.15 g
(Step 2)
1,000 grams = 1 L
80.0 g H₂O 1 L
-------------------- x ------------------- = 0.0800 L H₂O
1,000 g
(Step 3)
Molarity = moles solute / volume solvent (L)
Molarity = 0.0999 moles / 0.0800 L
Molarity = 1.25 M
write three disadvantages of hard water.
The three disadvantages of hard water are:
1. Hard water is unsuitable for washing because soap does not readily create a lather in it.
2. Soap may react and produce, wasting the soap.
3. Due to the development of calcium and magnesium carbonates, tea kettles will get furred.
Hard waterWater that contains a lot of minerals is referred to as hard water. In limestone, chalk, or gypsum deposits, which are mostly composed of calcium and magnesium carbonates, bicarbonates, and sulphates, hard water is created as a result of percolation. A moderate health advantage from drinking hard water is possible. In industrial settings where water hardness is regulated to prevent expensive breakdowns in boilers, cooling towers, and other water-handling equipment, it can present serious issues. Hard water is frequently detected in home settings by the build-up of lime scale in kettles and water heaters as well as by the absence of foam when soap is agitated in water. Wherever there is a worry about water hardness, water softening is frequently employed to lessen the negative impacts of hard water.
write three disadvantages of hard water.
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Which of the following elements has the largest atomic radius?
Group of answer choices
A. Iron
B. Cobalt
C. Chromium
D. Calcium
The answer is calcium.
Calcium has the largest atomic radius.
silver
nitrate
solution
A current was passed through the circuit shown in figure above. In the
experiment, 5.4 g of silver metal was discharged at the cathode in electrolysis cell
B. What mass of copper was discharged at the cathode in cell A?
[Molar mass: Ag = 108 gmol¹; Cu= 63.5 gmol ¹]
Answer:
Silver
Explanation:
What mass of copper was discharge at the cathode in a cell
A piece of copper absorbs 5000 J of energy and undergoes a temperature change from 100 °C to 200 °C. What is the mass of the piece of copper?
Group of answer choices
A. 12.9 grams
B. 129.9 grams
C. 0.385 grams
D. 1290 grams
Answer:
B.) 129.9 grams
Explanation:
To find the mass, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = energy (J)
-----> m = mass (g)
-----> c = specific heat (J/g°C)
-----> ΔT = change in temperature (°C)
The specific heat of copper is 0.385 J/g°C. Knowing this, you can plug the given values into the equation and simplify to isolate "m".
Q = mcΔT <----- Equation
5000 J = m(0.385 J/g°C)(200 °C - 100 °C) <----- Insert values
5000 J = m(0.385 J/g°C)(100) <----- Subtract
5000 J = m(38.5) <----- Multiply 0.385 and 100
129.9 = m <----- Divide both sides by 38.5
HELP NOW pls will give points due soon
Sorry for the sloppy writing I tried my best.
If you can't read the words in my photo it says
Evaporation
condensation precipitation and runoff
definition of these words
evaporation: The process of turning liquid into vapor
Condensation:water which collects as droplets on a cold surface when humid air is in contact with
Precipitation: the action or process of precipitating a substance from a solution
runoff: liquid, especially water or rainwater, that flows off or drains away
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What volume of a 0.550 M solution of potassium hydroxide (KOH) can be made with 19.9 g of potassium hydroxide?
Answer:
0.645 L
Explanation:
To find the volume, you need to (1) convert grams to moles (using the molar mass) and then (2) calculate the volume (using the molarity ratio). The final answer should have 3 sig figs to match the sig figs of the given values.
(Step 1)
Molar Mass (KOH): 39.098 g/mol + 15.998 g/mol + 1.008 g/mol
Molar Mass (KOH): 56.104 g/mol
19.9 grams KOH 1 mole
-------------------------- x ----------------------- = 0.355 moles KOH
56.014 grams
(Step 2)
Molarity = moles / volume <----- Molarity ratio
0.550 M = 0.355 moles / volume <----- Insert values
(0.550 M) x volume = 0.355 moles <----- Multiply both sides by volume
volume = 0.645 L <----- Divide both sides by 0.550
Need help, I'm kinda panicking!
Answer:
hey I saw this on brainly and thought it will help u..
and this is not my answer I saw u needed help so I screenshot it..
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and hope this is what ur looking for.
using the ideal gas law, PV = nRT, in which R is 8.31 (L•kPa/mol-K), what would the temperature be if 0.75 moles of helium gas in a 2.0 L container have a pressure of 202.65 kPa
Answer:
65.0 K
Explanation:
To find the temperature, you need to use the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (pKa)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Constant (8.31 L*kPa/mol*K)
-----> T = temperature (K)
You can plug the given values into the equation and simplify to find the temperature.
P = 202.65 pKa R = 8.31 L*kPa/mol*K
V = 2.0 L T = ? K
n = 0.75 moles
PV = nRT
(202.65 pKa)(2.0 L) = (0.75 moles)(8.31 L*kPa/mol*K)T
405.3 = (6.2325)T
65.0 K = T
What is meant by the term hydrocarbon?
[tex] \quad \quad\quad\huge \tt{ANSWER}[/tex]
Hydrocarbons are organic compounds which made up of only carbon and hydrogen.
[tex] \pink{ \star}[/tex]Carbon - ( C )
[tex] \pink{ \star}[/tex]Hydrogen - ( H )
━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
[tex] \red{✿}[/tex] Type of Hydrocarbon :
AlkanesAlkenesAlkynes[tex] \purple{\mathfrak{llXecretll}}[/tex]
Ideal Gas Law: Tutorial. At a party, you use a gas canister to fill balloons. The canister holds 4.47 moles of air. If the room is at 26.0°C and the gas pressure is 855 kilopascals, what is the volume of the canister? The volume of the canister is ___ liters. Type the correct answer in the box. Express your answer to the correct number of significant figures. Use the gas laws Fact sheet to help you.
Answer:
13.0 L
Explanation:
To find the volume, you need to use the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (kPa)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas constant (8.314 kPa*L/mol*K)
-----> T = temperature (K)
After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation and simplify to find "V". The final answer should have 3 sig figs to match the sig figs of the given values.
P = 855 kPa R = 8.314 kPa*L/mol*K
V = ? L T = 26.0 °C + 273.15 = 299.15 K
n = 4.47 moles
PV = nRT
(855 kPa)V = (4.47 moles)(8.314 kPa*L/mol*K)(299.15 K)
(855 kPa)V = 11117.48496
V = 13.0 L
What is the
molality of 30g of NACI dissolved in 350g of water
Answer:
1.45 mol/kg
Explanation:
nilered videos
Answer:
1.47 m
Explanation:
The molality can be found using the following equation:
Molality = moles solute / mass (kg) solvent
In this case, NaCl is the solute and H₂O is the solvent. To find the molality, you need to (1) convert grams NaCl to moles (via the molar mass), then (2) convert grams H₂O to kilograms, and then (3) calculate the molality.
(Step 1)
Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol
Molar Mass (NaCl): 58.443 g/mol
30 grams NaCl 1 mole
-------------------------- x ------------------------ = 0.513 moles NaCl
58.443 grams
(Step 2)
1,000 grams = 1 kg
350 grams H₂O 1 kg
-------------------------- x ----------------------- = 0.35 kg H₂O
1,000 grams
(Step 3)
Molality = moles solute / mass (kg) solvent
Molality = 0.513 moles NaCl / 0.35 kg H₂O
Molality = 1.47 m
Find the amount of heat energy needed to convert 150 grams of ice at -15°C to ice at -63°C.
Group of answer choices
A. (-) 14760 Joules because the ice is being heated.
B. (-) 14760 Joules because the ice is cooling.
C. 14760 Joules because the ice is cooling.
D. 14760 Joules because the ice is being heated.
The heat needed is (-) 14760 Joules because the ice is cooling.
What is heat?The term heat refers to a form of energy that can be observed as a result of temperature difference between two bodies. We can recall that heat always flows from the hotter to the cooler body.
Given that the heat added to a substance can be calculated by the use of H = mcdT
Where;
H = heat
m = mass
c = specific heat capacity
T = temperature change
Hence;
H = 150 g * 2.03 Jg∘C * (-63 - (-15))
H = (-) 14760 J
Hence the heat needed is (-) 14760 Joules because the ice is cooling.
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If a chemical is oxidized it is also known as the
Group of answer choices
A. the one that is reduced
B. the product
C. oxidizing agent
D. reducing agent
Answer:
D.) reducing agent
Explanation:
Oxidized chemicals gain electrons. In order to gain these electrons, another chemical must lose electrons. So, the chemical (which will be oxidized) acts as a reducing agent, causing the other chemical to be reduced and lose electrons.
The isotope sodium-24 has a half-life of 15 hours. Starting with 22 grams, how much remains in 30
hours?
Answer:
5.5 grams
Explanation:
To find how much of the isotope remains, you need to use the half-life equation:
[tex]N(t) = N_0(\frac{1}{2})^\frac{t}{h}[/tex]
In this equation,
-----> N(t) = remaining mass (g)
-----> N₀ = initial mass (g)
-----> t = time (hrs)
-----> h = half-life (hrs)
You can find the remaining mass by plugging the given values into the equation and solving.
N(t) = ? g t = 30 hrs
N₀ = 22 g h = 15 hrs
[tex]N(t) = N_0(\frac{1}{2})^\frac{t}{h}[/tex] <----- Half-life equation
[tex]N(30) = (22)(\frac{1}{2})^\frac{30}{15}[/tex] <----- Insert values
[tex]N(30) = (22)(\frac{1}{2})^2[/tex] <----- Simplify exponent
[tex]N(30) = (22)(0.25)[/tex] <----- Solve [tex](\frac{1}{2} )^2[/tex]
[tex]N(30) = 5.5[/tex] <----- Multiply 22 and 0.25
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PLA HELP WOTH THIS CHEMISTRY WORK!!!
You have 250.0 mL of 4.00 M sugar solution. You add 332.4 mL of water to this solution.
Determine the concentration of the sugar solution after the water has been added
Answer:
1.72 M
Explanation:
To find the new molarity, you need to (1) convert both volumes from mL to L, then (2) calculate the moles (using the molarity equation), and then (3) calculate the new molarity (using the new volume and molarity equation). The final answer should have 3 sig figs.
(Step 1)
1,000 mL = 1 L
250.0 mL / 1,000 = 0.250 L
332.4 mL / 1,000 = 0.3324 L
(Step 2)
Molarity = moles / volume (L)
4.00 M = moles / 0.250 L
1.00 = moles
(Step 3)
New Volume = 0.3324 L + 0.250 L = 0.5824 L
Molarity = moles / volume
Molarity = 1.00 moles / 0.5824 L
Molarity = 1.72 M
If a chemical reaction produces 20.0 grams of product, but by stoichiometry it is supposed to have 25.0 grams of product; what is the percent yield of the reaction?
Group of answer choices
A. 125%
B. 75%
C. 20%
D. 80%
Perform the following operation and express the answer in scienfific notation 7.5x1-^9 - 2.5 x 10^8
1. Consider the unbalanced equation:
Al4C3 (s) + H2O (l) ---> Al(OH)3 (s) + CH4 (g)
How many moles of H2O are needed to react with 1.48 moles of Al4C3 ?
Hint: Write the balanced equation first
2.
Consider the balanced equation:
2 CH4 (g) + 3 O2 (g) + 2 NH3 ---> 2 HCN (g) + 6 H2O (g)
If 203.6 g of NH3 is reacted with excess CH4 and O2, what mass in grams of HCN is produced?
Answer:
1.) 17.76 moles H₂O
2.) 323.1 g HCN
Explanation:
1.) An equation is balanced when there is an equal amount of each element on both sides of the reaction. The quantities can be modified by adding coefficients in front of the molecules.
The unbalanced equation:
Al₄C₃(s) + H₂O -----> Al(OH)₃(s) + CH₄(g)
Reactants: 4 aluminum, 3 carbon, 2 hydrogen, 1 oxygen
Products: 1 aluminum, 1 carbon, 7 hydrogen, 3 oxygen
The balanced equation:
Al₄C₃(s) + 12 H₂O -----> 4 Al(OH)₃(s) + 3 CH₄(g)
Reactants: 4 aluminum, 3 carbon, 24 hydrogen, 12 oxygen
Products: 4 aluminum, 3 carbon, 24 hydrogen, 12 oxygen
Now that the equation is balanced, you can use the relevant coefficients to construct a mole-to-mole ratio. This will allow you to convert between moles Al₄C₃ to moles H₂O.
1.48 moles Al₄C₃ 12 moles H₂O
---------------------------- x ------------------------ = 17.76 moles H₂O
1 mole Al₄C₃
2.) To find the mass of HCN, you need to (1) convert grams NH₃ to moles NH₃ (via molar mass), then (2) convert moles NH₃ to moles HCN (via mole-to-mole from equation coefficients), and then (3) convert moles HCN to grams HCN (via molar mass). It is important to arrange the coefficients in a way that allows for the cancellation of units.
Molar Mass (NH₃): 14.009 g/mol + 3(1.008 g/mol)
Molar Mass (NH₃): 17.033 g/mol
Molar Mass (HCN): 1.008 g/mol + 12.011 g/mol + 14.009 g/mol
Molar Mass (HCN): 27.028 g/mol
2 CH₄(g) + 3 O₂(g) + 2 NH₃(g) ------> 2 HCN(g) + 6 H₂O(g)
203.6 g NH₃ 1 mole 2 moles HCN 27.028 g
--------------------- x ---------------- x ------------------------ x ----------------- =
17.033 g 2 moles NH₃ 1 mole
= 323.1 g HCN
The _____ is the attraction of the electrons of one atom to the protons of the other atom, leading to a bond.
a. oxidation reaction
b.electron orbital
c.gravitational pull
d.electrostatic force
Answer:
d
Explanation:
The + charge of the proton and the - charge of the electron create a electrostic force of attraction ( opposites attract)
How much heat is released if a 10.0 gram piece of aluminum is cooled from 70°C to 50°C?
Group of answer choices
A. +180 J
B. -200 J
C. -180 J
D. +200 J
C. The heat released when the aluminum is cooled from 70°C to 50°C is -180 J.
What is Specific heat capacity?
Specific heat capacity is the quantity of heat needed to raise the temperature per unit mass.
Heat released when the aluminum is cooledThe heat released when the aluminum is cooled from 70°C to 50°C is calculated as follows;
Q = mcΔθ
where;
m is mass of the aluminum c is specific heat capacityΔθ is change in temperatureQ = (10)(0.9)(50 - 70)
Q = -180 J
Thus, the heat released when the aluminum is cooled from 70°C to 50°C is -180 J.
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Determine the mass % of a NaCl solution if 58.5 grams of NaCl was dissolved in 50 ml of water (assume the density of water to be 1 g/ml). [5]
Considering the definition of percentage by mass and density, the percentage by mass of a NaCl solution is 53.917%.
Percentage by massThe percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.
In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.
The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:
[tex]percentage by mass= \frac{mass of solute}{mass of solution}x100[/tex]
DensityDensity is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
[tex]density=\frac{mass}{volume}[/tex]
Percentage by mass of a NaCl solutionIn this case, you know:
mass of solute= 58.5 gramsvolume of water= 50 mLdensity of water= 1 [tex]\frac{g}{mL}[/tex]mass of solution= mass of solute + mass of waterReplacing in the definition of density, you get the mass of water:
[tex]1 \frac{g}{mL} =\frac{mass of water}{50 mL}[/tex]
Solving:
mass of water= 1 [tex]\frac{g}{mL}[/tex]× 50 mL
mass of water= 50 grams
Then, you get that the mass of solution is calculated as:
mass of solution= mass of solute + mass of water
mass of solution= 58.5 grams + 50 grams
mass of solution= 108.5 grams
So, the percentage by mass is calculated as:
[tex]percentage by mass= \frac{58.5 grams}{108.5 grams}x100[/tex]
percentage by mass= 53.917%
Finally, the percentage by mass of a NaCl solution is 53.917%.
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9) Identify the following as a physical property, physical change, chemical property, or chemical change:
a) Ethanol has a density of 0.697 g/mL.
b) The solution turns blue upon mixing water and food coloring.
c) Wood burns in an oven.
d) Methyl alcohol is highly flammable.
e) Ice melts in a beaker.
f) Methyl ethanoate smells like apples.
g) A car crashes into a wall.
h) Sugar dissolves in water.
a) physical property
b) chemical change
c) chemical change
d) chemical property
e) physical change
f) physical property
g) physical change
h) physical change
a) Ethanol has a density of 0.697 g/mL shows physical property, b) The solution turns blue upon mixing water and food coloring shows chemical change, c) Wood burns in an oven shows chemical change, d) Methyl alcohol is highly flammable shows chemical property, e) Ice melts in a beaker shows physical change, f) Methyl ethanoate smells like apples shows physical property, g) A car crashes into a wall shows physical change and h) Sugar dissolves in water shows physical change.
A physical change is a transition that modifies a substance's physical characteristics without changing its chemical makeup or identity. The substance's molecules don't change during a physical change; only their arrangement or state does. On the other hand, a chemical change entails the creation of new compounds with chemical properties that differ from the original ones. A entirely new substance is produced as a result of a chemical reaction in which the links between atoms or molecules are broken and new bonds are established.
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Chromium metal can be produced by the following reaction:
3Si + 2Cr2O3 - 4Cr + 3SiO2
In an experiment where there is an excess of cr2o3, what mass (in grams) of cr can be produced from 0.250 moles of si?
Answer:
17.3 g Cr
Explanation:
To find the mass of chromium, you need to (1) convert moles Si to moles Cr (using the mole-to-mole ratio from equation coefficients) and then (2) convert moles Cr to grams Cr (using the atomic mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (0.250).
3 Si + 2 Cr₂O₃ ---> 4 Cr + 3 SiO₂
^ ^
Atomic Mass (Cr): 51.996 g/mol
0.250 moles Si 4 moles Cr 51.996 g
------------------------- x -------------------- x ------------------- = 17.3 g Cr
3 moles Si 1 mole
Determine the acid dissociation constant (Ka) for a 0.200 M solution of hydrogen sulfate ion with
the pH of 1.35 if the reaction for the dissociation of this acid is
HSO 4 →→ H+ + SO 4-²
(Hint: [H+] = 10-PH; Ka = [product]/[reactant])
The acid dissociation constant(Ka) is 0.0095
The reaction for this dissociation of acid is
HSO4 ⇄H+ + SO4 -2
The dissociation constant can be determined from the following expression
[tex]Ka= \frac{[H+] [SO4]-2}{[HSO4}[/tex]
[H+] = 10-PH
= 10-1.35
[H+] = 0.0447
[H+] = 0.0447 mol / L
From equation, [H+] = [SO4-2] = 0.0447 mol / L
[SO4-2] = 0.0447 mol / L
From the values of [H+], [SO4-2] and [HSO4] Ka can be calculated as follows,
Ka = 0.0447 * 0.0447 / 0.200
= 0.0019 / 0.200
= 0.0095
Hence the value of the acid dissociation constant (Ka) for the given reaction is 0.0095
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