Explanation
the acceleration due to gravity formula is given by:
[tex]\begin{gathered} g=\frac{GM}{R^2}^{} \\ \text{where} \\ G\text{ is the universal gravitational constatn G=6.674 }\cdot10^{-11}\frac{m^3}{\operatorname{kg}\cdot s^2} \\ R\text{ is the radius of the massive body ( in meters)} \\ g\text{ is the acceleration due to gravity} \\ M\text{ is the mass of the massive body ( kg)} \end{gathered}[/tex]Step 1
Find g(acceleration due to gravity)
Let
[tex]\begin{gathered} M=\text{ mass of the moon=7.35}\cdot10^{22}\operatorname{kg} \\ G=\text{=6.674 }\cdot10^{-11}\frac{m^3}{\operatorname{kg}\cdot s^2} \\ R=\text{radius of the moon=}1.74\cdot10^6m \end{gathered}[/tex]now, replace in the formula
[tex]\begin{gathered} g=\frac{GM}{R^2}^{} \\ g=\frac{\text{6.674 }\cdot10^{-11}\frac{m^3}{\operatorname{kg}\cdot s^2}\cdot\text{7.35}\cdot10^{22}\operatorname{kg}}{(1.74\cdot10^6m)^2} \\ g=\frac{4.90539\cdot10^{12}}{(3.0276\cdot10^{12})} \\ g=1.62\frac{m}{s^2} \end{gathered}[/tex]Step 2
to find the force , use the formula
[tex]\begin{gathered} F=\text{mg} \\ \text{where m is the mass of the object} \\ g\text{ is the acceleration due to gravity} \end{gathered}[/tex]replace
[tex]\begin{gathered} F=7\operatorname{kg}\cdot1.625\text{ }\frac{m}{s^2} \\ F=11.375\text{ Newtons} \end{gathered}[/tex]therefore, the force would be
11.375 N
How does Newton's second law affect a seat-belted vs. an unseat-belted passenger in an automobile that is involved in a car crash (before the crash, during the crash, and immediately after the crash).
According to Newton's Second Law, acceleration increases as force does. The acceleration decreases with increasing mass.
Newton's Second LawSeat belts are related to Newton's Second Law since it asserts that larger forces result in greater acceleration, whereas bigger masses result in less acceleration. It goes without saying that a seat belt prevents you from accelerating. If you were in a car accident and were hit hard, you would accelerate more quickly, but the seat belt would prevent you from doing so. Have you ever heard the belief that if a tissue box is on a car's back dashboard, it will suddenly stop? The tissue box, which might pierce a person's head, flew from the back dashboard forward and toward the front of the vehicle.To learn more about Newton's Second Law refer :
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13 of the group visited the eiffel tower 16 of the group visited the notra-dame cathederal 7 of the group did not visit any of these places. a person is chosen at random from the group what is the probibility that this person only visited 1 of the 2 placesThere are 30 people in total
Answer:
0.5667
Explanation:
If there are 30 people in total and 7 of them didn't visit any of the places, we have 23 people that visit the Eiffel tower or the Notre-dame cathedral because
30 - 7 = 23
Now, we know that 13 people visited the Eiffel tower and 16 people visited the Notre-dame cathedral. If we add these numbers, we get
13 + 16 = 29
Since 29 is greater than 23 and 29 - 23 = 6, we get that 6 people visited the Eiffel tower and the Notre-dame cathedral.
Then,
13 - 6 = 7
16 - 6 = 10
So, 7 people only visited the Eiffle tower and 10 people only visited the Notre-dame cathedral. It means that 17 people (10 + 7 = 17) from the 30 visited only 1 of the 2 places.
Then, the probability is calculated as
[tex]P=\frac{17}{30}=0.5667[/tex]Therefore, the answer is 0.5667
How does the Coulomb force affect charge interactions?A.Like and opposite charges attract.B.Like charges repel, and opposite charges attract.C.Like and opposite charges repel.D.Like charges attract, and opposite charges repel.
B. Like charges repel, and opposite charges attract.
Given Data:
Let us consider two e
A pool cue strikes a 0.25 kg billiard ball with a force of 22 N. If the felt on the pool table supplies
a force of 7 N what is the acceleration of the billiard ball.
Answer:
Approximately [tex]0.06\; {\rm m \cdot s^{-2}}[/tex], assuming that the force from the pool cue is horizontal.
Explanation:
As the billiard ball moves forward, the pool table will exert friction on the ball. In this question, it is given that the magnitude of this friction is [tex]7\; {\rm N}[/tex]. If the ball is moving forward, this friction will point backward.
The cue exerts a forward force of magnitude [tex]22\; {\rm N}[/tex] on the billiard ball. The [tex]22\; {\rm N}[/tex] forward force from the cue and the [tex]7\; {\rm N}[/tex] backward force from the table interact with each other. The resultant force on the ball will be [tex](22\; {\rm N} - 7\; {\rm N}) = 15\; {\rm N}[/tex], forward.
When an object of mass [tex]m[/tex] experiences a net force of [tex]F[/tex], the acceleration [tex]a[/tex] of that object will be [tex]a = (F / m)[/tex].
Apply unit conversion and ensure that the mass of the billiard ball is in standard units (grams): [tex]m = 0.25\; {\rm kg} = 250\; {\rm g}[/tex].
In this question, the net force on this billiard ball is [tex]F = 15\; {\rm N}[/tex]. With a mass of [tex]m = 250\; {\rm g}[/tex], the acceleration [tex]a[/tex] of this billiard ball will be:
[tex]\begin{aligned}a &= \frac{F}{m} \\ &= \frac{15\; {\rm N}}{250\; {\rm g}} = 0.06\; {\rm m\cdot s^{-2}}\end{aligned}[/tex].
1 then replaced the old light bulb with a new 7 watt LED light bulb that gives off the same amount oflight. The next time I leave the light on for the same amount of time I will save money because I'm usingless kilowatts. What else am I using less of? Make a claim about something else I am using less of andprovide evidence and reasoning to support your answer. (3 pts) CER
Your using less energy as well. The energy is given by:
[tex]E=Pt[/tex]where P is the power of the bulb and t is the time. In this case the we will use the following amount of energy:
[tex]\begin{gathered} E=(7)(168) \\ E=1176=1.176\times10^3=1.176\text{ KWH} \end{gathered}[/tex]Hence we would save energy since we only use 1.176 KWH in this case.
5. The graphs above show the magnitude F of a force exerted on an object as a function of the object's position xfor two trials in an experiment. W, and W, are the work done on the object by force 1 and force 2, respectively.How do w, and W2 compare, and why?(A) W, > W2, because the maximum value of force 1 is greater than the maximum value of force 2.(B) W, > Wą, because the slope of force 1's graph increases, while the slope of force 2's graph decreases.(C) W,
We are given the graphs of two forces F1 and F2.
Notice that the graph of force 1 is increasing whereas the graph of the force 2 is decreasing.
This means that the slope of force 1 is increasing and the slope of force 2 is decreasing.
So, the work done by force 1 is greater than the work done by force 2.
Therefore, the correct answer is option B.
W1 > W2, because the slope of force 1's graph increases, while the slope of force 2's graph decreases.
A heavy sled is being pulled by two people as shown in the figure. The coefficient of static friction between the sled and the ground is s=0.579, the coefficient of kinetic friction is k=0.405, and the combined mass of the sled and its load is =336 kg. The ropes are separated by an angle =29∘, and they make an angle with the horizontal. Assuming both ropes pull equally hard, what is the minimum rope tension required to get the sled moving?
The minimum rope tension required to get the sled with a load of 336 kg moving if the coefficient of static friction between the sled and the ground is s=0.579 is 1155.5 N
[tex]F_{s}[/tex] = μ[tex]_{s}[/tex] * N
N = m g
[tex]F_{s}[/tex] = Static frictional force
μ[tex]_{s}[/tex] = Co-efficient of static friction
N = Normal force
m = Mass
g = Acceleration due to gravity
μ[tex]_{s}[/tex] = 0.579
m = 336 kg
g = 9.8 m / s²
[tex]F_{s}[/tex] = 0.579 * 336 * 9.8
[tex]F_{s}[/tex] = 1906.5 N
[tex]F_{s}[/tex] = 2 T cos θ cos ( φ / 2 )
T = Tension
θ = Angle between horizontal and rope
φ = Angle between the two ropes
θ = 32°
φ = 29°
1906.5 = 2 * T * cos 32° * cos ( 29 / 2 )°
1906.5 = 2 * T * 0.85 * 0.97
T = 1906.5 / 1.65
T = 1155.5 N
Therefore, the minimum rope tension required to get the sled moving is 1155.5 N
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Given a ball at some height above the ground where its total mechanical energy is 5.00 J. If the ball falls down to a lower height in free fall where it’s gravitational potential energy is 2.00 J then what must its kinetic energy be at this lower height?A) 3.00 JB) 9.10X10^-1 JC) 12.9 JD)15.3 JE)6.40 J
ANSWER
A. 3.00 J
EXPLANATION
By the law of conservation of energy, total mechanical energy must be conserved. At both points, the kinds of mechanical energy the ball has are gravitational potential energy and kinetic energy,
[tex]ME=PE+KE[/tex]At some point, the total mechanical energy is 5 J. This energy must be conserved, so if at the lower height its gravitational potential energy is 2J, then its kinetic energy must be such that the sum gives 5J,
[tex]\begin{gathered} 5J=2J+KE \\ KE=5J-2J=3J \end{gathered}[/tex]Hence, the kinetic energy at the lower height is 3.00 J.
If a piece of paper is cut in half, it will become two pieces of paper that are each half the size of the original piece. If one of the half-pieces is cut in half again, it will become two pieces of paper that are each one quarter the size of the original piece
If the piece of paper is cut in half over and over again, will there ever be a point at which it is no longer paper? Explain your answer.
No, cutting paper is a physical alternative. which means that it's far nonetheless paper irrespective of how many times you narrow it.
Upon infinite cutting, we reach its atom, which further can not be broken but at this point, it will not be called paper any longer.
An atom is a particle of remember that uniquely defines a chemical element. An atom includes a central nucleus that is surrounded by way of one or greater negatively charged electrons. The nucleus is undoubtedly charged and consists of one or greater pretty heavy debris called protons and neutrons.
Atoms encompass 3 essential types of debris, protons, electrons and neutrons. Neutrons and protons have about equal mass and in the assessment of this, the mass of an electron is negligible. A proton includes a fantastic price, a neutron has no price and an electron is negatively charged.
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A 1200-kg car accelerates from rest to 20.5 m/s in 4.50 s. What is the average power delivered by the engine? Use the work-energy theorem to calculate for the work (in terms of kilojoules [kJ]). Show your complete solutions.
Answer:
Explanation:
Given:
m = 1200 kg
V₀ = 0 m/c
V = 20.5 m/s
t = 4.50 s
____________
N - ?
1)
Car acceleration:
a = (V - V₀) / t = (20.5 - 0) / 4.50 ≈ 4.56 m/s²
2)
Vehicle traction force:
F = m·a = 1200·4.56 ≈ 5 470 N
3)
Vehicle speed:
V = V₀ + a·t = 0 + 4.56·4.50 ≈ 20.5 m/s
4)
Average vehicle speed:
N = F·V / 2 = 5 470·20.5 / 2 ≈ 56 000 W
i need help with this mechanical question please
The maximum velocity of the water that will allow it to fall into the bowl is 9.4 m/s.
What is the time of motion of the water?
The time of motion of the water is the time taken for the water to travel from the bubbler into the drinking bowl.
The time of motion of the water is calculated as follows;
h = vt + ¹/₂gt²
where;
v is the initial vertical velocity of the water = 0t is the time of motion of the water = ?h is the height travelled = 5 cm = 0.05 mg is acceleration due to gravity = 9.8 m/s²h = 0 + ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
t = √(2 x 0.05 / 9.8)
t = 0.1 second
The maximum velocity of the water that will allow it to fall into the bowl is calculated as follows;
X = Vₓt
where;
X is the maximum horizontal displacement of the waterVₓ is the maximum horizontal speed of the watert is the time of motion of the waterX = diameter of the bowl minus 3 cm
X = 50 cm - 3 cm
X = 47 cm
X = 0.47 m
X = Vₓt
X = (V cosθ)t
where;
V is the largest or maximum velocity of the waterθ is the angle of inclination of the water0.47 = [V cos(60)](0.1)
0.47 / 0.1 = V cos(60)
4.7 = V(0.5)
V = 4.7 / 0.5
V = 9.4 m/s
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What would happen to the orbits of the planets if the amount of gravity produced bythe Sun were reduced to almost zero?A. The planets would abandon their orbit and move out into space.B. The planets would start crashing into each other.C. The planets would orbit as usual.
Given:
The amount of gravity produced by the Sun was reduced to almost zero.
To find:
What would happen to the orbits of the planets
Explanation:
The centripetal force for the rotation of every planet is supplied by the gravitational force between the sun and the planet. If the gravitational force by the sum becomes zero, the planets would begin moving away from their usual path into space.
Hence, the planets would abandon their orbit and move out into space.
What is the energy of a baby who weighs 20 N sitting in a high chair 1.5 m high?
The gravitational potential energy of a baby with a weight of 20N and 1.5m from the ground is 30 Joules.
What is the energy of the baby?The gravitational potential energy is equal to the weight of a body multiply by its height from ground level.
It is expressed as;
U = mgh
Where m and g are the mass and acceleration due to gravity, which is also called weight, h is the height from the ground level.
Given the data in the question;
Weight of the baby mg = 20NHeight h = 1.5mGravitational potential energy U = ?Plug the given values into the formula and solve for U.
U = mg × h
U = 20N × 1.5
U = 30Nm
U = 30 Joules.
Therefore, the gravitational potential energy is 30 Joules.
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A 100 g piece of copper is at room temperature (20°C). It is then held over a flame and its temperature increases to 120°C after which it is dropped in a thermally insulated beaker which contains 200 g of oil. The specific heat of copper is 388 J/kg Ka) How much heat has the copper piece absorbed from the flame?b) Describe if and how the temperatures of the copper and the oil change after the metal was dropped in the oil.
We will have the following:
[tex]Q=C\cdot m\cdot\Delta T[/tex]a) The heat that the copper piece absoved was:
[tex]Q=(388J/kg\cdot K)(0.1kg)(120-20+273.15)\Rightarrow Q=14478.22J[/tex][tex]\Rightarrow Q=14.47822kJ[/tex]So, the heat that the copper piece absorved was 14.47822 kJ.
b) The temperature of the copper will decrease when dropped in the oil, since the oil has a smaller energy state then the heat will disperse towards the lower energy state, thus making the copper colder and making the oil hotter. At some point the temperature of both will reach equilibrium and the temperature of the copper piece and the oil will be the same; this means the temperature of the copper piece will be lower and the temperature of the oil will be greater.
Electrons are transferred from one atom to another Covalent bonds onlylonic bonds onlyBoth ionic and covalent chemical bonds
When electrons are transferred from one atom to another, the atom that gained an electron becomes negatively charged, and the one that has lost an electron becomes positively charged. Atoms like these are called ions.
These 2 ions are held together by an ion bond.
Answer: Ionic Bond
A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of 22 N · m. If the mechanic grasps the wrench as shown in the figure below, determine the magnitude (in N) of the force she must exert on the wrench.
Given,
The magnitude of the torque is
[tex]T=22\text{ N.m}[/tex]The angle is
[tex]\theta=60\text{ }[/tex]The distance d is
[tex]d=0.30\text{ m}[/tex]Solution:
The torque is calculated by the formula,
[tex]T=dFsin\theta[/tex]Calculate the magnitude of the force.
[tex]\begin{gathered} F=\frac{T}{dsin\theta} \\ F=\frac{22\text{ N.m}}{0.30\text{ m}\times sin(60)} \\ F=\frac{22\text{ N.m}}{0.30\times\frac{\sqrt{3}}{2}} \\ F=157.8\text{ N} \end{gathered}[/tex]Thus, the magnitude of the force is 157.8 N.
The deflection of a 160-cm-long beam in bending will be _____ times the deflection of an equivalent 120-cm-long beam.1.330.560.751.782.370.42
Given data
*The deflection of the length of the beam in bending is 160 cm
*The equivalent length of the beam is 120 cm
The deflection of a 160-cm-long beam in bending is calculated as
[tex]\begin{gathered} l=\frac{160}{120} \\ =1.33 \end{gathered}[/tex]Hence, the deflection of a 160-cm-long beam in bending will be 1.33 times the deflection of an equivalent 120-cm-long beam
The dust in a molecular cloud emits at maximum intensity at a wavelength of 101 µm. What is the temperature of the cloud (in K)?
The temperature of the cloud is mathematically given as
T = 28.683k
This is further explained below.
. What is the temperature of the cloud in K?Generally, using wiens law to calculate the temperature the equation is mathematically given as
T = b/landa* m
where b = 2.897 x 10^-3
T = 2.897*10^-3/101 x 10^-6
T = 28.683k
In conclusion, The interstellar medium often consists of dust as its typical minor component. It is usually considered that its dynamic involvement in the contraction of the diffuse gas into molecular clouds plays no significant role at all because of the tiny mass fraction, which is f less than 0.01.
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An infinitely long line of charge has linear charge density 5.00×10−12 C/m5.00×10−12 C/m. A proton (mass 1.67×10−27 kg1.67×10−27 kg, charge +1.60×10−19 C+1.60×10−19 C) is 18.0 cm from the line and moving directly toward the line at 3.50×103 m/s.3.50×103 m/s. (a) Calculate the proton’s initial kinetic energy. (b) How close does the proton get to the line of charge?
(a) The initial kinetic energy of the proton is 1.023 x 10⁻²⁰ J.
(b) The position of the proton from the line of charge depends on the time of motion of the proton.
What is the initial kinetic energy of the proton?The initial kinetic energy of the proton is the energy of the proton due to its motion.
Mathematically, the initial kinetic energy of the proton is given by the following formula,
K.E = ¹/₂mv²
where;
m is the mass of the protonv is the initial velocity of the protonK.E = ¹/₂(1.67 x 10⁻²⁷)(3.5 x 10³)²
K.E = 1.023 x 10⁻²⁰ J
The position of the line is calculated as follows;
x = Q/σ
where;
Q is the charge of the protonσ is the linear charge densityx = (1.6 x 10⁻¹⁹ C) / (5 x 10⁻¹² C/m)
x = 3.2 x 10⁻⁸ m
We can determine the how close the proton get to the line of charge, if we know the time of motion of the proton. Unfortunately, more information is needed to determine the time of motion of the proton.
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Changing which of the following would affect the power output or a person climbing stairs? Select all that apply.
SELECT ALL THAT APPLY
The number of stairs the person runs up.
The mass of the person.
The height of the person.
The amount of time that it takes for the person to climb the stairs.
The power output of a person climbing stairs is the mass of the person. Option B.
It is clear that carrying a heavy object up a flight of stairs requires more strength than carrying a lighter one. But even if you don't have anything you have to support your weight against gravity. Therefore, the heavier the weight the greater the force required to climb the stairs. Climbing stairs improves the amount of good cholesterol in your blood.
Stair climbing can be an important priority for building leg strength and reducing the risk of fall injury in older adults. Climbing stairs helps you achieve and maintain a healthy weight. Calculate the amount of power developed Power is the amount of work divided by the time it took to do the work. The work done in climbing stairs is the force applied by multiplying the weight by the distance climbed and the height of the stairs.
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If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). what is theminimum speed required to take 84 meter radius banked at 17 degree so that you don't slide inward.
For the car to stay on the road without sliding in or sliding out, all the forces on the x-axis must equal each other. Thus by equating all the forces on the x-axis, we can find the coefficient of the friction.
In order to determine the minimum speed of the car, use the following expression:
[tex]v=\sqrt[]{R\cdot g\cdot\tan \theta}[/tex]where,
R: radius of the road = 84m
g: gravtitational acceleration constant = 9.8m/s^2
θ: angle of banking of the road = 17 degrees
Replace the previous values of the parameters into the formula for v:
[tex]\begin{gathered} v=\sqrt[]{(84m)(9.8\frac{m}{s^2})(\tan 17)} \\ v\approx15.86\frac{m}{s} \end{gathered}[/tex]Hence, the minimum speed requierd is approximately 15.86m/s
In order to determine the value of the minimum coefficient friction required, use the following formula:
[tex]\mu=\frac{v^2-Rg\tan \theta}{v^2\tan \theta+Rg}[/tex]by replacing, you get:
[tex]undefined[/tex]Which of the following is the weakest hypothesis for the question, "Is there evidence of water on Mars?"
OA.
OB.
O C.
OD.
There is water under the surface of Mars.
There might have been water but it's difficult to tell.
There was never water on Mars.
Mars once had a lake filled with water.
There might have been water but it's difficult to tell is the weakest hypothesis for the question, "Is there evidence of water on Mars.
The rusty red color of Mars, the fourth planet from the sun, is well known. The atmosphere of the cold, arid Red Planet is extremely thin. However, the dusty, (as far as we can tell) dead planet is everything from boring.Extreme dust storms may cover the whole planet, the atmosphere can get so frigid that carbon dioxide condenses into snow or ice, and marsquakes, a type of earthquake that occurs on Mars, are a common occurrence.Because of its considerable distance from the sun, Mars is significantly colder than Earth. It's roughly - 80 degrees Fahrenheit on average.To know more about Marsvisit : https://brainly.com/question/14623285
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A planet moving in an elliptical orbit moves1) slower when it is closer to the Sun.2) faster when it is farther away from the Sun.3) slower when it is farther away from the Sun.4) faster when it is closer to the Sun.5) both c and d.
4) faster when it is closer to the Sun.
According to Keplers second Law, the closer the planet is to the sun, the stronger the sun's gravitational pull on it, and the faster the planet moves.
A race car rounds a curve at 54 m/s. The radius of the curve is 441 m, and the car’s mass is 610 kg. (Assume that the car’s speed remains constant. Take the radially inward direction to be positive) The car’s acceleration is 6.61 m/s2. What is the value of this acceleration in terms of "g"?
Given:
The speed of the car is: v = 54 m/s
The radius of the curve is: r = 441 m
The mass of the car is: m = 640 kg
The acceleration of the car is: a = 6.61 m/a^2
To find:
The value of acceleration in terms of g (acceleration due to gravity).
Explanation:
The car has an acceleration of 6.61 m/s^2.
The acceleration of 6.61 m/s^2 can be written in terms of g (acceleration due to gravity) as:
[tex]a_g=\frac{a}{9.8\text{ m/s}^2}\times g=\frac{6.61\text{ m/s}^2}{9.8\text{ m/s}^2}\times g=0.675g[/tex]Final answer:
The acceleration of the car in terms of g (acceleration due to gravity) is 0.675g.
A brick dropped from rest falls for 4 seconds. How far does the brick fall?
Free fall acceleration of any object at any time is 10 m/s^2
distance = 1/2 a t ^2 = 1/2 * 10m/s^2 * (4s )^2= 80 m
As the swings ride hits top speed, what applies centripetal force to keep the riders traveling in a circle?
a the chains holding the seats on the ride
b the people themselves
c nothing
d the seat
As the swings ride hits top speed, the force that applies to the centripetal force to keep the riders traveling in a circle is option A: the chains holding the seats on the ride.
Which provides the centripetal force in a rotating swing carnival ride?The centripetal force is the resultant force because the swings move in a circle. The centripetal force is seen aa the force that keeps the rider in a circle and the horizontal component of the tension force that is said to be produced by the total of the forces acting along the x-axis.
Therefore, Moving objects are continuously forced to shift their path toward the center of rotation by centripetal force, which stops them from escaping a curve.
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1. What is the acceleration of a car that takes 8.5 seconds to change its velocity from 35 m/s to 5 m/s?
Knowns:
Unknowns:
Formula:
Solve:
Answer:
Final velocity(v)= 25m/s^2
Initial velocity(u)=10m/s^2
Acceleration(a)=5m/s^2
let time taken be t sec
From first eq of motion
v=u+at
v-u=at
25–10=5t
15=5t
t=3s.
Convert 690cm^3 to litres.
We need to convert 690 cu cm to liters
First we have the next equivalence
1 liter= 1000 cm^3
[tex]\frac{690\text{ cm}^3\times1L}{1000\operatorname{cm}^3}=0.69L[/tex]690 cm^3=0.69 liters
Your heating system is 45 percent energy efficient. A) What amount of energy would it consume to transform 9000 kWh into useful thermal energy for heating the house during the winter?
Let E be the total amount of energy that the heating system would consume in order to transform 9000kWh into useful thermal energy.
Since the efficiency of the system is 45%, then, 9000kWh is equal to 45% of E.
This means that 45% of the total energy consumed is transformed into useful thermal energy. Then:
[tex]\frac{E}{100}=\frac{9000kWh}{45}[/tex]Solve for E:
[tex]E=\frac{100}{45}\times9000kWh=20,000kWh[/tex]Therefore, the total amount of energy consumed by the system would be 20,000kWh.
Question 6 of 25What does the labeled point in the diagram represent?АА2A. A crestB. A troughO C. The frequency
By definition, the trough of a wave is the lowest point on a wave, since the labelled is on such a point we conclude that the point is representing a trough and the answer is B.
