question 6 what if we use a p-value cutoff of 10%? do we reject, fail to reject, or are we unable to tell using our confidence interval? assign cutoff ten percent to the number corresponding to the correct answer. reject the null / data is consistent with the alternative hypothesis fail to reject the null / data is consistent with the null hypothesis unable to tell using our staff confidence interval

\Step-by-step explanation:

convert to math form:

[tex]\frac{x}{2} \le5[/tex]

simplify:

[tex]x \le 10[/tex]

convert to word form(optional):

x is less than or equal to 5.

Answer:  The correct answer is Option D: h=2A/(b1+b2)

Step-by-step explanation:

Solve for h:

a=(1/2h)(b1+b2)

Step 1: Flip the equation

1/2b^2h+1/2b1h=a

Step 2: Factor out variable h

h((b2+b1)/2)=a

Step 3: Divide both sides by (b^2+b1)/2

h((b2+b1/2))/(b2+b1/2)=(a/(b2+b1)/2)

h=2a/(b2+b1)  

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Answer:

8p - 9

Step-by-step explanation:

→ Expand brackets

6p - 15 + 2p + 6

→ Collect like terms

8p - 9

Answer:

You have to place the numbers given or your left in the formula given. So for example: y= 2*(-2)^2

that's: y=2*4, so: y=8

1) y=8

2) y= 2*(-1)^2. y=2

3) y= 2*(0)^2. y=0

4) y= 2*(1)^2. y=2

5) y= 2*(2)^2. y=8

Answer: 2[tex]\sqrt{2}[/tex]

Step-by-step explanation: First plug in the value, which is [tex]\sqrt{8}[/tex]

Then divided to 2[tex]\sqrt{2}[/tex]

50 mg be the expected mass of the sample in the year 2002, to the nearest whole number

In 1990, a sample of a radioactive isotope had an initial mass of 110 mg and decayed exponentially over time.

A measurement in 1993 revealed that the sample's mass had decayed to 90

110 mg - 90 mg = 20 mg (amount decayed in the 3 total years)

20 mg ÷ 3 years = 6.6 mg decayed per year

6.6 × 9 years (years between 1993 and 2002) = 60 mg

110 mg - 60 mg = 50 mg, rounded to 50 mg

50 mg be the expected mass of the sample in the year 2002, to the nearest whole number

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The spreadsheet that shows the distances between the cities, indicates that the distances between the cities are as follows;

a) From Hereford to Chester, the distance is 95 miles

b) Chester is the town that is 99 miles from Kendal

c) Ellen will have driven 201 miles if she drives from Kendal to Hereford through Chester

A spreadsheet application is used for the storage analysis, organization, and computation of data.

The interpretation of the distances in the chart which is in the form of a spreadsheet are;

The value in the cell corresponding to the distance from Kendal to Chester that is the cell which is on the same column as Kendal and on the same row as Chester is 99

Therefore, the distance from Kendal to Chester is 99 miles

The value in the cell that directly links Chester to Hereford that is the cell which is on the same column as Chester and on the same row as Hereford is 95

Therefore, the distance from Chester to Hereford is 95 miles

The value in the cell that connects Kendal to Hereford, that is the cell which is on the same column as Kendal and which is on the same row as Hereford is 201

Therefore the distance from Kendal to Hereford is 201 miles

a) The distance from Hereford to Chester is 95 miles

b) The town that is 99 miles from Kendal is Chester

c) The distance Ellen will have driven if she drives from Kendal to Hereford via Chester is 201 miles

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The equation of the line in the slope-intercept form will be y = (3/4)x + 13/4.

A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

The points are given below.

(1, −4) and (5, −1)

The equation of the line that passes through (1, −4) and (5, −1) will be given as,

(y + 4) = [(−1 + 4) / (5 − 1)](x − 1)

y + 4 = (3/4)x − 3/4

y = (3/4)x + 13/4

The equation of the line in the slope-intercept form will be y = (3/4)x + 13/4.

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Answer:

[tex] \frac{ {m}^3{} }{25} [/tex]

Step-by-step explanation:

that is the answer

The inequality that could be used to determine the mean number of miles Jason would need to run each day for 5 more days to achieve his goal is 10 + 5m ≥ 45

Inequalities are created through the connection of two expressions. It should be noted that the expressions in an inequality aren't always equal. Inequalities implies that the expressions are not equal. They are denoted by the symbols ≥ < > ≤.

Let the number of miles be given as m.

Since his goal for this week is to run a minimum of 45 miles. So far this week, he has already run 10 miles. This will be:

10 + 5m ≥ 45

This expresses the inequality.

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sin^-1(-1/2) enter directly into a calculator and you'll find your answer

Answer:

-0.67

Step-by-step explanation:

What is the slope of the line created by this equation? Round your answer out to the two nearest decimal places. 6x + 9y = 1

_____________________________________________

Slope intercept form solves for y:

y = mx + b when m = slope and b = y-intercept

First, solve for y:

6x + 9y = 1

subtract 6x from both sides:

6x + 9y - 6x = 1 - 6x

9y = 1 - 6x

divide both sides by 9:

9y/9 = (1 - 6x)/9

y = 1/9 - 6/9x

reduce right side:

y = 1/9 - 2/3x

rearrange right side:

y =  - 2/3x + 1/9

Back to the equation: y = mx + b when m = slope and b = y-intercept

your slope is -2/3

in decimal form, rounded to two digits: -0.67

Answer:

x=21

Step-by-step explanation:

The angles of a triangle always add up to 180°

71+62+(2x+5)=180

First add 71 and 62

133+(2x+5)=180

Then you subtract 133

2x+5=47

Subtract 5 too

2x=42

Then divide by 2

x=21

We can check our answer by adding all the angles

71+62+(2*21+5)

71+62+(42+5)

71+62+47=180

A rectangle that maximize the enclosed area has a length 800 yards and width is 800 yards. The maximum area is 640,000 square yards.

In the given question we have to find the maximum area of the rectangular area.

Liana has 3200 yards of fencing to enclose a rectangle.

So we know that the perimeter of rectangle is

P= 2(l+b)

Let length of the rectangle is x yards and width is y yards.

So the equation should be

2(x+y) = 3200

Divide by 2 on both side we get

x+y = 1600................(1)

As we know the area of rectangle is

A = xy

From the equation the value of y is 1600-x.

Now putting the value of y

A = x(1600-x)

A = 1600x-x^2

On differentiating

dA/dx = 1600-2x

Putting dA/dx=0

1600-2x=0

Subtract 1600 on both side we get

-2x= -1600

Divide by -2 on both side we get

x = 800 yards

Now putting the value of x in the y=1600-x

y=1600-800

y=800 yards

So the maximum area is

A= 800*800

A= 640,000 square yards

Hence, a rectangle that maximize the enclosed area has a length 800 yards and width is 800 yards. The maximum area is 640,000 square yards.

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Answer:

Step-by-step explanation:

187

Using the concepts of probability, we got that  0.0764 is the probability that the sum of the 100 values is greater than 3,908 when a researcher measure the amount of sugar in several cans of the same soda.

The z-score of a measure X of a normally distributed variable with mean  and standard deviation is given by:

                 Z=(X-μ)/σ

For this problem, these parameters are given as follows:

μ=39.01,σ=0.5,n=100,s=0.5/√100=0.05

A sum of  3908 is equivalent to a sample mean of 3908/100 = 39.08, which means that the probability is the p-value of Z when X = 39.08, hence:

Z=(X-μ)/σ

By the Central Limit Theorem:

Z=(X-μ)/s

=>Z=(39.08-39.01)/0.05

=>Z=(0.07)/0.05

=>Z=7/5

=>Z=1.4

Z = 1.4 has a p-value of 0.0764.

Hence, the probability that the sum of the 100 values is greater than 3,908 is 0.0764.

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Yes, you are safe to land, If the landing angle at an airport is 4° and you are two miles out and ½ mile high.

The final approach, also known as the final leg or final approach leg, is the last leg of an aircraft's approach to landing in aviation. During this leg, the aircraft is aligned with the runway and descending for a landing. In aircraft radio lingo, it is frequently abbreviated to "final".

Given,

If the landing angle at an airport is 4° and you are two miles out and ½ mile high,

Yes, you are safe to land.

A normal airport landing pattern calls for aircraft to turn from the base leg to the final within 0.5 to 2 miles of the airport when visual meteorological conditions (VMC) are present. A "straight-in" final approach, when all other legs are skipped, is frequently employed for instrument approaches as well as VFR approaches onto controlled airfields. At American non-towered airports, straight-in approaches are discouraged.

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The domain of h(z) would be (-8,3).

The range of h(z) would be (2,9).

Point (4,8) would be moved to (0,8)

What are the domain and range of a function?

The domain is the set of all x-values that can be used to make the function "work" and produce actual y-values.

A function's range is the variety of conceivable y-values (minimum y-value to maximum y-value)

For the function f(x):

Domain: (-4,7)

Range: (2,9)

The function f(x+4) is equal to 1 (f(x+4)).

This shows, inputs: -4, outputs: 1

Domain of f(x+4):

add -4 to the Domain values of f(x)

Domain:(-4-4,7-4)=(-8,3)

Range of f(x+4):

Multiply the range values of f(x) by 1

Range: (1*2,1*9)= (2,9)

Find, where the point (4,8) would be moved:

add -4 to 4, and multiply 8 by 1

(4-4,8*1)

=(0,8)

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Answer:

a = ± [tex]\sqrt{\frac{2d-2c}{b} }[/tex]

Step-by-step explanation:

c + [tex]\frac{1}{2}[/tex] a²b = d ( multiply through by 2 to clear the fraction )

2c + a²b = 2d ( subtract 2c from both sides )

a²b = 2d - 2c ( divide both sides by b )

a² = [tex]\frac{2d-2c}{b}[/tex] ( take square root of both sides )

a = ± [tex]\sqrt{\frac{2d-2c}{b} }[/tex]

Now we have to,

→ find the required value of b.

Formula we use,

→ (AC)² = (BC)² + (AB)²

Then the value of a will be,

→ (10.5)² = b² + (3)²

→ 110.25 = b² + 9

→ b² = 110.25 - 9

→ b = √101.25

→ [ b = 10.06 in ]

Hence, value of b is 10.06 in.

The relation accepts reflexive, symmetry, and transitive.

Recall that a relation R is reflexive if the element (x, x) belongs to R for all elements X in the domain of R.

If (x, y) belongs to R, then follows that (y, x) must likewise belong to R, making the situation symmetric.

And it is transitive if (x, y) and (y, z) belongs to R necessarily implies that (x, z) belongs to R.

Given r is a relation on the set of all nonnegative integers R(a,b)

Reflexive - YES. A given number a will always have the same remainder when divided by 5.

Symmetric - YES. If a and b have the same remainder when divided by 5, then b and a are the same pair, so again they will have the same remainder.

Transitive - YES. If a and b as well as b and c have the same remainder when divided by 5, this is possible if both a and c also have the same remainder when divided by 5.

Therefore the relation accepts reflexive, symmetry, and transitive.

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The formula for the cost if the line rental is £20 and the price of calls made is £15 will be 20 + 15p.

It should be noted that an expression is used to illustrate the relationship given between the variables.

In this case, the monthly phone contract is made up of the fixed line rental and the price represented by p.

The appropriate expression to illustrate this information will be:

= Fixed cost + Calls made

= 20 + 15(p)

= 20 + 15p

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The equation that models the function is y = 8/3(x) - 5/3.

Given:

The graph of a linear function passes through the point (-2, -7).

When the input increases by 3 the value of the function increases by 8.

(x,y) = (x+3,y+8)

(-2,-7) = (-2+3,-7+8)

= (1,1)

slope between (1,1) and (-2,-7) is m = -7-1/-2-1

= -8/-3

m = 8/3.

substitute m in y = mx + c

y = 8/3(x)+c

substitute (-2,-7)

-7 = 8/3(-2) + c

-7*3 = -16 + 3c

-21+16 = 3c

-5 = 3c

c = -5/3

y = 8/3(x) - 5/3.

Therefore the equation that models the function is y = 8/3(x) - 5/3.

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The perimeter of Ragans new mural is 530cm.

Rectangle:

A rectangle is a type of quadrilateral, whose opposite sides are equal and parallel. It is a four-sided polygon that has four angles, equal to 90 degrees. A rectangle is a two-dimensional shape.

Here it is given that the measure of the rectangle is 238 cm and 435cm.

The Raegan creates a mural that is 27cm.

The formula to calculate the perimeter of a rectangle:

Perimeter = 2(length + breadth)

Earlier the length is 238cm and the breadth is 435cm.

Now replace the breath 435cm to 27cm.

length = 238cm

breadth = 27cm

Therefore we get the perimeter of the rectangle:

Perimeter = 2( 238 + 27)

= 2( 265)

=530cm

Therefore the perimeter is 530cm.

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Answer:

1400

Step-by-step explanation:

a. The relationship between time and distance is not an arithmetic sequence, as the rate of change is not constant.

b. The distance is given by: d(n) = 5n².

An arithmetic sequence happens when the change in the output is always the same when the input changes by one, that is, the rate of change is constant.

From the table, the increases when the input(time) increases by one are given as follows:

15, 15, 35, 45.

The increases are not constant, hence the relationship between time and distance is not an arithmetic sequence.

The equation for the distance is given as follows:

d(t) = 0.5gt².

The constant is:

g = 10.

Hence:

d(t) = 5t².

At a time of n seconds, the distance is found replacing the lone instance of t by n, hence:

d(n) = 5n².

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Answer:

16x² - 18x

Step-by-step explanation:

(25x² + 4 - 30x) - (9x² + 4 - 12x) ← distribute this parenthesis by - 1

= 25x² + 4 - 30x - 9x² - 4 + 12x ← collect like terms

= (25x² - 9x²) + (4 - 4) + (- 30x + 12x)

= 16x² + 0 + (- 18x)

= 16x² - 18x

Answer:

1: [tex]2\sqrt{2}[/tex]

2: [tex]10\sqrt{55}[/tex]

Step-by-step explanation:

[tex]\sqrt{16-8}[/tex]

[tex]\sqrt{8}[/tex]

[tex]\sqrt{8}=2\sqrt{2}[/tex]

2:

[tex]\sqrt{\frac{11}{16+4}[/tex]

[tex]\sqrt{\frac{11}{20}[/tex]

[tex]\sqrt{.55}[/tex]

[tex]10\sqrt{55}[/tex]

Hopes this helps

The probability of not spinning a 3 is 8/9

From the question, the given parameters are:

Number of sections = 9

Sections = Number 1 to 9

The probability of spinning a 3 = 1/9

The above probability can be represented as

P(3) = 1/3

The probability that the number 3 is not spun is the complement of the  probability of spinning a 3

This is calculated as

P(3) + P(Not 3) = 1

Substitute the known values in the above equation So, we have the following equation

1/9 + P(Not 3) = 1

Evaluate the like terms

P(not 3) = 8/9

Hence, the probability is 8/9

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