Questions are in the picture

Answer:

See below

Step-by-step explanation:

Salary (y)       =    30 000   +  50 x        

y = 30 000 + 50x     where x is the number of sales

How many sales for 50 000 ?

50 000 = 30 000 + 50 x

20 000 = 50 x

x = 400 sales

I. Model Problems

A linear model is a linear equation that represents a real-world

scenario. You can write the equation for a linear model in the same way

you would write the slope-intercept equation of a line. The y-intercept

of a linear model is the quantity that does not depend on x. The slope is

the quantity that changes at a constant rate as x changes. The change

must be at a constant rate in order for the equation to be a linear model.

Example 1 A machine salesperson earns a base salary of $40,000 plus

a commission of $300 for every machine he sells. Write an equation

that shows the total amount of income the salesperson earns, if he sells

x machines in a year.

The y-intercept is $40,000; the salesperson earns a $40,000 salary in a

year and that amount does not depend on x.

The slope is $300 because the salesperson’s income increases by $300

for each machine he sells.

Answer: The linear model representing the salesperson’s total income

is y = $300x + $40,000.

Linear models can be used to solve problems.

Example 2 The linear model that shows the total income for the

salesperson in example 1 is y = 300x + 40,000. (a) What would be the

salesperson’s income if he sold 150 machines? (b) How many

machines would the salesperson need to sell to earn a $100,000

income?

(a) If the salesperson were to sell 150 machines, let x = 150 in the linear

model; 300(150) + 40,000 = 85,000.

Answer: His income would be $85,000.

(b) To find the number of machines he needs to sell to earn a $100,000

income, let y = 100,000 and solve for x:

=============================================================

Explanation:

Angles EBA and DBC are congruent because of the similar arc marking. Both are x each.

Those angles, along with EBD, combine to form a straight angle of 180 degrees. We consider those angles to be supplementary.

So,

(angleEBA) + (angleEBD) + (angleDBC) = 180

( x ) + (4x+12) + (x) = 180

(x+4x+x) + 12 = 180

6x+12 = 180

6x = 180-12

6x = 168

x = 168/6

x = 28

Angles EBA and DBC are 28 degrees each.

This means angle D = 3x+5 = 3*28+5 = 89

-----------

Then we have one last set of steps to finish things off.

Focus entirely on triangle DBC. The three interior angles add to 180. This is true of any triangle.

D+B+C = 180

89 + 28 + C = 180

117+C = 180

C = 180 - 117

C = 63 degrees

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\qquad❖ \: \sf \: \angle C = 63 \degree[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

[tex]\qquad❖ \: \sf \:x + 4x + 12 + x=180°[/tex]

( Angle EBA= Angle DBC, and the three angles sum upto 180° due to linear pair property )

[tex]\qquad❖ \: \sf \:6x + 12 = 180[/tex]

[tex]\qquad❖ \: \sf \:6x = 180 - 12[/tex]

[tex]\qquad❖ \: \sf \:6x = 168[/tex]

[tex]\qquad❖ \: \sf \:x = 28 \degree[/tex]

Next,

[tex]\qquad❖ \: \sf \: \angle C + \angle D + x = 180°[/tex]

[tex]\qquad❖ \: \sf \: \angle C +3x + 5 + x = 180°[/tex]

[tex]\qquad❖ \: \sf \: \angle C +4x = 180 - 5[/tex]

[tex]\qquad❖ \: \sf \: \angle C +4(28) = 175[/tex]

( x = 28° )

[tex]\qquad❖ \: \sf \: \angle C +112 = 175[/tex]

[tex]\qquad❖ \: \sf \: \angle C = 175 - 112[/tex]

[tex]\qquad❖ \: \sf \: \angle C = 63 \degree[/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

[tex]\qquad❖ \: \sf \: \angle C = 63 \degree[/tex]

Answer:

x = 48/7

Step-by-step explanation:

There's two good ways to do this problem.

Option 1:

Translate "x varies directly as y" into the equation y=kx

Then you have to find k. After you "reset" your y=kx equation, fill in k and then solve for x. See image.

Option 2:

Translate "varies directly" into a proportion, which is two fractions equal to each other:

x/y = x/y

Fill in the three numbers given and cross multiply and solve to find the fourth number. See image.

X=1.33

Y=4.9875;approx. 5.0

Answer:

(2/120=X/80)=Y/300

2×80=120×X

X=160/120

X=1.33

X/80=Y/300

But X=1.33

By substituting

X=1.33, We have that

1.33/80=Y/300

80×Y=1.33×300

80Y=399

Y=399/80

Y=399/80

Y=5.0 approx.

Answer:

  no

Step-by-step explanation:

The angle subtended by the radius of the target at Emily's distance can be found using the tangent relation.

  tan(α) = opposite/adjacent = (1/4 ft)/(150 ft) = 1/600

The angle is found using the inverse relation:

  α = arctan(1/600) ≈ 0.095°

If Emily's aim is off by 0.2°, she will miss the target by several inches.

__

Additional comment

Emily's projectile will miss her aiming point by ...

  (150 ft)tan(0.2°) ≈ 0.524 ft ≈ 6.28 in

Answer:

Step-by-step explanation:

You want to begin by making each fraction have  the same common denominator. The LCF (least common factor) is 77. So, knowing this, we can now multiply the fractions that need to have a denominator of 77.

1. 5/7*11/11=55/77

2. 9/11 * 7/7 =63/77

Now we can add

55/77 + 63/77 + 21/77 = 139/77 or 1.805194805

Answer:

[tex]\left(a-b\right)\sqrt{\frac{2}{a^2-b^2}}[/tex]

=

[tex]\frac{ \sqrt{2} }{a + b} [/tex]

Step-by-step explanation:

[tex]\left(a-b\right)\sqrt{\frac{2}{a^2-b^2}}[/tex]

[tex](a - b)( \frac{ {2}^{ \frac{1}{2} } }{(a + b)(a - b)} )[/tex]

[tex] \frac{(a - b)( {2}^{ \frac{1}{2} }) }{(a - b)(a + b)} = \frac{ \sqrt{2} }{a + b} [/tex]

The missing length of the box with square base is 20.370 inches.

This box can be represented by a right prism, whose volume (V), in cubic inches, is the product of the area of the base (A), in square inches, and the height of the box (h), in inches. The area of the base is equal to the square of the side length (l):

V = l² · h      (1)

If we know that V = 2 200 in³ and l = 108 in, then the height of the box is:

h = V / l²

h = (2 200 in³) / (108 in)

h = 20.370 in

The missing length of the box with square base is 20.370 inches.

The statement presents typing mistakes, correct form is shown below:

A box with a square base has a side length of 108 in. What is the length of the box if its volume is 2 200 in³?

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Check the picture below.

The answer is -7.

The coefficient is the part of the variable that does not change with respect to the variable.

Hence, in the monomial -7x²y⁴, the coefficient is -7.

Answer: d

Step-by-step explanation:

The graph is increasing, so the base must be more than 1.

Also, the y-intercept is 2.

This leaves d.

Answer:

L

Step-by-step explanation:

interior angle formula so

(number of sides - 2)*180

2*180 = 360

you can also just take an example from a square 4*90 = 360

360-121-58-70 = 111

By using an online graphing calculator, the overall equation represented by this scenario is plotted in the image attached below.

Based on the information provided about this company with respect to its delivery and total number of miles to be covered, we would assign variables as follows:

Next, we would translate the word problem into an algebraic equation by using an inequality:

y > x/2 - 3

Also, we would determine the intercepts as follows:

When x = 0, we have;

y = 0/2 - 3

y = -3.

y-intercept = (0, -3).

For the x-intercept, we have:

When y = 0, we have;

0 = x/2 - 3

x/2 = 3

x = 6.

x-intercept = (6, 0).

By using an online graphing calculator, the overall equation represented by this scenario is plotted in the image attached below.

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Answer:

c

Step-by-step explanation:

c is the answer

The initial membership fee for Club A is; $2.5.

The initial membership fee for Club B is; $3.

Hence, Club A has a lower initial membership fee.

It follows from the concepts of linear graphs that the interpretation of the initial membership fee is the y-intercept of the graphs given.

This is so because, it corresponds to the total cost at a point when the number of movies watched is; 0. That is, before any movie is watched.

Consequently, the graph calibrations (including the missing Club A graph) allow the determination of the initial membership fee (y-intercept) as declared above.

Ultimately, Club A has a lower initial membership fee.

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Answer: B

Step-by-step explanation:

Answer:

S = √( 1009)

Step-by-step explanation:

S = √( h² + 1/2)²)

S = √(28² + 15²)

S = √( 1009)

Hope this helps u!

The equation 7x + 28 = 7(x + 4) has infinite many solutions

Linear equations are equations that have constant average rates of change, slope or gradient

A system of linear equations is a collection of at least two linear equations.

In this case, the equation is given as

7x + 28 = 7(x + 4)

Open the bracket

7x + 28 = 7x + 28

Subtract 7x from both sides of the equation

28 = 28

Subtract 28 from both sides of the equation

0 = 0

The above equation is true, because both sides of the equation are the same

This means that the equation has infinite many solutions

Hence, the equation 7x + 28 = 7(x + 4) has infinite many solutions

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A quadrilateral PQRS is a parallelogram. PQ and RS are opposite sides then the answer of this particular question is , x = 4, the parallelogram PQRS is a rhombus, QR = 31, The opposite angles are congruent. Thus, more than one answer is correct.

According to the question,

PQ = 7x+12; RS = 5x -20 and QR = 31

Solving PQ and RS we get x = 4. Thus, PQ = 40 and RS = 40.

A quadrilateral is a parallelogram if a pair of its opposite sides is parallel and congruent.  A quadrilateral that has all sides equal and opposite sides parallel is called Rhombus.

Thus, the parallelogram PQRS is a rhombus.

Hence,  a quadrilateral PQRS is a parallelogram. PQ and RS are opposite sides then the answer of this particular question is , x = 4, the parallelogram PQRS is a rhombus, QR = 31, The opposite angles are congruent. Thus, more than one answer is correct.

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Answer:

bx/a (3rd choice)

Step-by-step explanation:

The length of an arc, s, in a circle of radius r, and central angle Θ given in radians is

s = rΘ

Circle M has radius a. The central angle in radians of the sector is Θ. The length of the arc is x.

x = aΘ

Solve for Θ:

Θ = x/a      Eq. 1

Circle N has radius b. The central angle in radians of the sector is Θ. The length of the arc is s.

s = bΘ

Solve for Θ:

Θ = s/b      Eq. 2

Since Θ = Θ, then equate the right sides of Equations 1 and 2 above.

x/a = s/b

Multiply both sides by ab.

abx/a = abs/b

bx = as

as = bx

s = bx/a

Answer: bx/a

Given the height of the tree and the angle of elevation from point B, the distance between the tree is from point B is approximately 70ft.

Given the data in the question;

Since the scenario form a right angle triangle, we use trig ratio.

tanθ = Opposite / Adjacent

tan( 26° ) = 34ft / x

We solve for x
x = 34ft / tan( 26° )

x = 34ft / 0.4877

x = 70ft

Given the height of the tree and the angle of elevation from point B, the distance between the tree is from point B is approximately 70ft.

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Based on the information, it is expected Fareed can be assigned to live on any of the floors.

The only condition that limits the floor Fareed can be assigned to is that he cannot be immediately below Damaris. This means that as long as Damaris is not immediately above him, he can be assigned to all floors. Here are two possible arrangements:

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Answer: 3/8

Step-by-step explanation:

1/2 is also 4/8 so you subtract 4/8 from 7/8 to get 3/8

Answer:

  y = x +5

Step-by-step explanation:

The equation of a parallel line will have the same x- and y-coefficients, but a different constant. You need to find the constant that makes the line go through the given point.

The given line is y = x +1. The equation you're looking for is

  y = x +c . . . . . . for some new constant c

We want this equation to be true for (x, y) = (-2, 3). Putting these values into the equation, we can solve for c.

  3 = -2 +c

  5 = c . . . . . . add 2

The desired equation is y = x +5.

Assuming you mean

[tex]\displaystyle \sum_{i=0}^n {}_nC_{i}[/tex]

where

[tex]{}_n C_i = \dbinom ni = \dfrac{n!}{i! (n-i)!}[/tex]

we have by the binomial theorem

[tex]\displaystyle (1 + 1)^n = \sum_{i=0}^n {}_nC_{i} \cdot 1^i \cdot 1^{n-i}[/tex]

so that the given sum has a value of [tex]\boxed{2^n}[/tex].

Jet 1 moves with a speed of  672 mi/h, while jet 2 moves with a speed of  672 mi/h + 80mi = 752 mi/h.

Let's say that the rate (or speed) of the slower jet is R, then the rate of the faster jet is:

R + 80mi/h

Now, if we step on any of the two jets (such that we view it as if it doesn't move) the other jet will move with a speed equal to:

S = R + R + 80mi/h

We know that after 8 hours, the to jets are 11,392 mi apart, then we know that:

(R + R + 80mi/h)*8h = 11,392 mi

Now we can solve that for R:

2*R + 80mi/h = 11,392 mi/8h = 1,424 mi/h

R = 1,424 mi/h - 80mi/h)/2 = 672 mi/h

So Jet 1 moves with a speed of  672 mi/h, while jet 2 moves with a speed of  672 mi/h + 80mi = 752 mi/h.

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a) The monthly payment for each loan is as follows:

30-year $1,954.93

15-year $3,053.25

b) The savings in interest by using the 15-year loan is $154,189,20 ($286,774.20 - $132,585).

c) No. the monthly payment for the 15-year loan is not twice that of the 30-year loan as the loan term.

d) The interest savings for the 15-year loan are more than one-half of the interest paid on the 30-year loan.

The calculations for the monthly payments, including interests can be carried out using an online finance calculator, as follows:

N (# of periods) = 360 months (12 x 30 years)

I/Y (Interest per year) = 3.85%

PV (Present Value) = $417000

FV (Future Value) = $0

Results:

PMT = $1,954.93

Sum of all periodic payments = $703,774.80 ($1,954.93 x 360)

Total Interest = $286,774.20 ($703,774.80 - $417,000)

N (# of periods) = 180 months (12 x 15 years)

I/Y (Interest per year) = 3.85%

PV (Present Value) = $417000

FV (Future Value) = $0

Results:

PMT = $3,053.25

Sum of all periodic payments = $549,585 ($3,053.25 x 180)

Total Interest = $132,585 ($549,585 - $417,000)

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