quired
1) Coordinate point B is at (4,3). What will the coordinates be for B' after a
translation of (x-2y+3)?
OB' (5,4)
OB' (2,6)
OB' (6,2)
OB' (-2,3)

Answers

Answer 1

The coordinates after the translation are (2, 6).

Which will be the coordinates after the translation?

Here we start with the point (4, 3) and we want to apply the translation defined by (x - 2, y + 3)

This would be a translation of 2 units to the left and 3 units up, using a "coordinate-axis" notation.

So we just need to subtract 2 from the x-value and add 3 to the y-value, we will get the new coordinates:

(4 - 2, 3 + 3) = (2, 6)

These are the coordinates of point B after the translation, the correct option is the second one.

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Answer 2

Answer:

OB' (2,

Step-by-step explanation:

take your first point (B) (4,3) and plug it into the x and y in (x-2, y+3) so you get (4-2, 3+3) which will give you (2,


Related Questions

Identify the transformations that have been applied to the parent function y=-(1)/(2)(x-3)^(2)-5. Select all that apply.

Answers

The transformations that have been applied to the parent function y=-(1)/(2)(x-3)^(2)-5 are: horizontal shift, vertical shift, and vertical stretch.

The transformations that have been applied to the parent function y=-(1)/(2)(x-3)^(2)-5 are:

- Horizontal shift: The parent function has been shifted to the right by 3 units. This is indicated by the subtraction of 3 from x in the equation.
- Vertical shift: The parent function has been shifted downward by 5 units. This is indicated by the subtraction of 5 from the entire equation.
- Vertical stretch: The parent function has been stretched vertically by a factor of (1)/(2). This is indicated by the multiplication of the entire equation by (1)/(2).

Therefore, the correct answers are horizontal shift, vertical shift, and vertical stretch.

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Help me fast its late and I gotta sleep this was due 6 minutes ago, I barely understand anything from this lesson and I don't got the best teacher so please help

Answers

Answer:

Step-by-step explanation:

Im not sure I can't see the picture.

Answer: Hence, the width of the path is 4 meters.

First we should find the area of the pool. Our width is 14 and our length is 18. In order to find the area, we must multiply these two numbers. 14 times 18 is 252. This means that the area of the pool is 252.

Since we know that one side of the pool is 18 and one side is 14, we can write out the equation below.

572= (18+2x)(14+2x)

The first thing we should do is combine like-terms.Our equation would now be as below.

x^2+16-80=0

Next we would take our quadratic equation- x=-b+-√b2-4ac/2a and fill it in with the numbers that we had in the first equation, our equation would be like below.  A=1   B=16   C=-80

x=-16+-√16^2-4* 1 * -80 /2 * 1

When then simplify our equation leaving us with x=-16+-√16^2-4*1(-80)/2 * 1, which broken down is x=-16+-√+-24/2.

Lastly we must subtract and add to receive our two answers.

One side is 4 and the other is -20. Since the width of the walk cannot not be a negative number, we know that the width of the path is 4 meters.

Hence, the width of the path is 4 meters.

I hope this helped & Good Luck <3!!!

Which equation can be used to find the area of the figure below?





F.A = (10⋅82
)+
(16⋅8
)
G.A = (6⋅82
)+
(10⋅8
)
H.A = (6⋅82
)+
(6⋅8
)
J.A = (6⋅8
)+
(10⋅8
)

Answers

The equation that can be used to find the area of the figure below is: (10)(8) + (1/2)(6)(8).

What is area of composite figure?

The area of mixed shapes is the area that is covered by any hybrid shape. The composite shape is a shape created by joining a small number of polygons to create the desired shape. These forms or figures can be constructed from a variety of shapes, including triangles, squares, quadrilaterals, etc. To calculate the area of a composite object, divide it into simple shapes such a square, triangle, rectangle, or hexagon.

A composite form is essentially a combination of fundamental shapes. A "composite" or "complex" shape is another name for it.

The area of the rectangle is given as:

A = (l)(w)

A = 10(8)

A = 80 sq. units

The area of the triangle is:

A = 1/2(b)(h)

In the figure:

b = 16 - 10 = 6 and h = 8.

A = 1/2(6)(8)

A = 24 sq. units

The total area of the figure is:

Area = area of rectangle + area of triangle

Area = 80 + 24

Area = 104 sq. units

Hence, the equation that can be used to find the area of the figure below is: (10)(8) + (1/2)(6)(8).

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Question 4: Abstract Vector Spaces LetWbe the set of all vectorsu=(x,y)inR2such that the product of its componentsxandysatisfy the equationx⋅y=0. Check whether this set (a) is closed under operation of standard scalar multiplication in the plane. (b) is closed under operation of standard vector addition in the plane. Is the information you found is sufficient to conclude whether this set forms a vector space or not? Explain why yes or why not. What does this set represent geometrically?

Answers

The set W represents the x-axis and y-axis in the plane. Any vector with one of its components equal to 0 will satisfy the equation x⋅y = 0, and these vectors lie on either the x-axis or y-axis.

(a) The set W is closed under standard scalar multiplication in the plane. This is because for any scalar c and any vector u = (x,y) in W, the product of the components of cu = (cx,cy) is (cx)(cy) = c2(xy) = c2(0) = 0, so cu is also in W.

(b) The set W is not closed under standard vector addition in the plane. For example, the vectors u = (1,0) and v = (0,1) are both in W, but their sum u + v = (1,1) is not in W because the product of its components is 1(1) = 1, which does not satisfy the equation x⋅y = 0.

Since the set W is not closed under standard vector addition, it does not form a vector space. A set must be closed under both scalar multiplication and vector addition in order to be a vector space.

Geometrically, the set W represents the x-axis and y-axis in the plane. Any vector with one of its components equal to 0 will satisfy the equation x⋅y = 0, and these vectors lie on either the x-axis or y-axis.

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1. Let the point \( P \) be \( (-1,3) \) and the point \( Q \) be \( (3,7) \). Find the following. a. \( \mathbf{v}=\overrightarrow{P Q} \) b. \( \|\mathbf{v}\| \) c. \( \overrightarrow{P Q}+\overrigh

Answers

The answers are:
a. \( \mathbf{v}=\overrightarrow{P Q} = (4, 4) \)
b. \( \|\mathbf{v}\| = 4\sqrt{2} \)
c. \( \overrightarrow{P Q}+\overrightarrow{Q P} = (0, 0) \)

The given points are point \( P \) be \( (-1,3) \) and point \( Q \) be \( (3,7) \).

a. To find \( \mathbf{v}=\overrightarrow{P Q} \), we subtract the coordinates of point \( P \) from the coordinates of point \( Q \):

\( \mathbf{v}=\overrightarrow{P Q} = (3-(-1), 7-3) = (4, 4) \)

b. To find \( \|\mathbf{v}\| \), we use the distance formula:

\( \|\mathbf{v}\| = \sqrt{(4-0)^2 + (4-0)^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2} \)

c. To find \( \overrightarrow{P Q}+\overrightarrow{Q P} \), we add the coordinates of \( \overrightarrow{P Q} \) and \( \overrightarrow{Q P} \):

\( \overrightarrow{P Q}+\overrightarrow{Q P} = (4, 4) + (-4, -4) = (0, 0) \)

Therefore, the answers are:

a. \( \mathbf{v}=\overrightarrow{P Q} = (4, 4) \)

b. \( \|\mathbf{v}\| = 4\sqrt{2} \)

c. \( \overrightarrow{P Q}+\overrightarrow{Q P} = (0, 0) \)

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The heart of a black bear beats about 50 times per minute during normal sleep in the fall. When the animal hibernates in winter, its heart rate decrease by 84%. How many times per minute does a black bear’s heart beat during hibernation? Answer fast pls

Answers

Answer: 8 times per minute

Step-by-step explanation: 50 (1-84%) = 8

Please state sin and cos of an angle of a right triangle if a
side opposite to this angle is 6, and a side adjacent to this angle
is 8?

Answers

The sin of the angle is 0.6 and the cos of the angle is 0.8.

In a right triangle, the sine (sin) of an angle is the ratio of the length of the side opposite to the angle to the length of the hypotenuse. The cosine (cos) of an angle is the ratio of the length of the side adjacent to the angle to the length of the hypotenuse.

In this case, the side opposite to the angle is 6 and the side adjacent to the angle is 8. To find the hypotenuse, we can use the Pythagorean theorem:

a^2 + b^2 = c^2

Where a and b are the lengths of the two legs of the right triangle, and c is the length of the hypotenuse.

Plugging in the given values:

6^2 + 8^2 = c^2

36 + 64 = c^2

100 = c^2

c = 10

So the hypotenuse of the right triangle is 10.

Now we can find the sin and cos of the angle:

sin = opposite/hypotenuse = 6/10 = 0.6

cos = adjacent/hypotenuse = 8/10 = 0.8

Therefore, the sin of the angle is 0.6 and the cos of the angle is 0.8.

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8:02 PM Wed Feb 22 L Allie Stevenson's practice S.12 Properties of logarithms: mixed review Rewrite the logarithmic expression as a single logarithm with the same base. Assume all expressions exist and are well-defined. Simplify any fractions. 2log_(w)x+4log_(w)2x

Answers

The simplified expression  is log_(w)(16x^6)

To rewrite the logarithmic expression as a single logarithm with the same base, we need to use the properties of logarithms. The properties we will use are:

1) log_b(x)+log_b(y) = log_b(xy)

2) a*log_b(x) = log_b(x^a)

Using the first property, we can combine the two terms with the same base:

2log_(w)x+4log_(w)2x = log_(w)x^2+log_(w)(2x)^4

Using the second property, we can simplify the exponents:

log_(w)x^2+log_(w)(2x)^4 = log_(w)x^2+log_(w)16x^4

Using the first property again, we can combine the two terms with the same base:

log_(w)x^2+log_(w)16x^4 = log_(w)(x^2*16x^4)

Simplifying the expression inside the logarithm:

log_(w)(x^2*16x^4) = log_(w)(16x^6)

Therefore, the final expression is:

2log_(w)x+4log_(w)2x = log_(w)(16x^6)

Answer: log_(w)(16x^6)

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The height of the real table is inches. What is the height of the table in the scale model?

Answers

Therefore , the solution of the given problem of unitary method  comes out to be the height of the table in the scale model because we lack any measurements to base our calculations on.

What does unitary method mean?

Divide the measures of just this microsecond portion by two in order to complete the task using the unitary variable technique. Briefly stated, the characterised by a group and colour subgroups are both removed from the unit method when a wanted item is present. For example, 40 pens subset with a changeable price would cost Rupees ($1.01). It's possible that one country will have total influence over the approach taken to accomplish this. Almost every living creature has a distinctive quality.

Here,

We could use the scale factor to determine the height of the table in the scale model if we knew the measurements of the actual table and the scale model. The scale factor is the ratio of the actual object's dimensions to the scale model's dimensions. For instance, if the scale factor is 1:12 and the actual table is 48 inches tall, the scale model table would be 12 inches tall.

12 times 48 inches, or 4 inches,

However, we are unable to calculate the height of the table in the scale model because we lack any measurements to base our calculations on.

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Calculate the mean: 13, 21, 45, 62, 10

Answers

Answer:30.2

Step-by-step explanation:

Answer:

30.2

Calculate the mean: 13, 21, 45, 62, 10

13 + 21 + 45 + 62 + 10

= 151

151  ÷ 5

= 30.2

Step-by-step explanation:

You're welcome.

The relationship between the postage rate and the weight of a letter can be defined by a piecewise function.

The graph shows the 2018 postage rates for using regular service to mail a letter.


Kiran and Mai wrote some rules to represent the postage function, but each of them made some errors.

Answers

The initial symbol in the Kiran equation is erroneous, and there are two rates for weights of 1, 2, and 3 ounces. In contrast, the prices for 1, 2, and 3 ounces are incorrectly expressed in the Mai equation.

What do you mean by contract rate?

A contract rate, also known as the coupon rate, stated rate, or nominal rate, is the interest rate that is stipulated in a certain contract.

What went wrong for Kiran?

1. For 1, 2, and 3 ounces, there are two rates: Kiran used the wrong symbols to describe the rates for 1, 2, and 3 ounces. Let's look at an illustration:

0.71  1  ≤  w ≤ 2

0.92  2  ≤ w  ≤ 3

Because in the first line the rate is 0.71 for weights less than or equal to 2, and because this also occurs in the second line, it appears that the rate for 2 pounds here can be both 0.71 and 0.92.

2. He chose the wrong initial symbol since it implies that there is a charge even when the weight is 0, which is not conceivable.

0.50 0 ≤ w ≤ 1 (The rate is 0.50 if the weight is less than or equal to 0)

What is Mai's error?

1. Similar to Kiran, she did not express the rate and the pounds. Let's consider one instance:

0.71 1 < w < 2 (The rate is 0.71 if the weight is less than 2; this is false because the rate is 0.71 if the weight is less than or equal to 2)

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LetP(x)=10x7−2x6+5x5+x3−7x2−1. (a) Find the possible number of positive real zeros ofP(x). LetP(x)=10x7−2x6+5x5+x3−7x2−1. (b) Use Descartes' Rules of Signs to show that1−2​cannot be a zero ofP(x)

Answers

(a) The possible number of positive real zeros of P(x) can be determined using Descartes' Rule of Signs. The Rule of Signs states that a polynomial with real coefficients can have at most as many positive real zeros as its leading coefficient has sign changes in the coefficients. This means that the polynomial has at most 3 positive real zeros.

(b) Descartes' rule of signs can also be used to prove that 1-2 cannot be a zero of P(x). According to the Rule of Signs, the number of positive real zeros of P(x) is limited to 3. However, if 1-2 is a zero of P(x), then the polynomial would have 4 sign changes, which is not possible. Therefore, 1-2 cannot be a zero of P(x).

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given the parent function f(x)=2^(x)and the translated function g(x)=2^((x+3)), determine the effect the transformation has on the maximum value on the interval [-2,2]

Answers

The parent function f(x) = 2^(x) is transformed into the function g(x) = 2^((x+3)) by shifting the graph 3 units to the left.

This means that the maximum value on the interval [-2,2] for the parent function will now occur at the point (-2+3) = 1 for the transformed function.

Therefore, the maximum value for the transformed function on the interval [-2,2] will be 2^(1) = 2.

In summary, the transformation shifts the graph of the parent function 3 units to the left, causing the maximum value on the interval [-2,2] to occur at x = 1 and have a value of 2.

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Man this shi 40 points

Answers

The match of the terms and correct locations are:

1. A - Amplitude

2. B is compression

3. C is rarefaction

What are longitudinal waves?

A longitudinal wave is a form of wave in which its direction of propagation is similar to the direction of vibration of the particles of the medium through which the wave is travelling. The waves generated by a stretched or compressed spiral spring produces longitudinal waves.

When a spiral spring is streched or compressed, on removal of the force a series of compression and rarefactions of the sections of the spring are produced. This sections vibrates in the direction of propagation of the waves produced.

Thus the match of the terms and correct locations are:

i. A - Amplitude

ii. B is compression

iii. C is rarefaction

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Write a quadratic function f whose zeros are -2 and 9 .

Answers

To write a quadratic function f whose zeros are -2 and 9 , we have to factor the function by (x+2) and (x-9).

How to find the quadratic function of f?

A quadratic function is a second-degree mathematical function whose graph is a parabola. The general form of a quadratic function is given by f(x) = ax² + bx + c, where a, b and c are constants and a cannot be equal to zero. The variable x represents the input of the function and f(x) represents the output or result of the function. To find the quadratic function of f we first need to multiply these factors, like this:

f(x)= (x+2) (x-9)Expanding the product, we have:f(x)= x²-7x-18

So the quadratic function whose zeros are -2 and 9 is:

f(x)=x²-7x-18

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POLYNOMIALS AND FACTORING Introduction to the GCF of two monomials Find the greatest common factor of 8m^(2) and 7b^(3).

Answers

The greatest common factor of 8m2 and 7b3 is the largest monomial that can divide both 8m2 and 7b3. So, the greatest common factor of 8m^(2) and 7b^(3) is 1.


The greatest common factor (GCF) of two monomials is the product of the greatest common factor of their coefficients and the greatest common factor of their variables. In this case, the greatest common factor of the coefficients is 1, since 8 and 7 have no common factors other than 1. The GCF of the variables is 1, since m and b have no common factors. Therefore, the GCF of 8m^(2) and 7b^(3) is 1*1 = 1.

Here is a step-by-step explanation:
1. Find the GCF of the coefficients: GCF(8,7) = 1
2. Find the GCF of the variables: GCF(m^(2),b^(3)) = 1
3. Multiply the GCF of the coefficients and the GCF of the variables: 1*1 = 1
4. The GCF of 8m^(2) and 7b^(3) is 1.

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Concrete tiles are made using buckets of cement,sand and gravel mixed into the ratio of 1:4:6. How many buckets of gravel are needed for 4 bucket of cement?

Answers

24 buckets of gravel are needed for 4 buckets of cement when making concrete tiles using the given ratio.

What is the ratio?

The ratio is a mathematical concept that represents the relationship between two quantities or values. It is defined as the comparison of two numbers by division, where the first number is called the "antecedent" and the second number is called the "consequent."

According to the given ratio, the amount of gravel needed is 6 times the amount of cement, or 6/1.

To find out how many buckets of gravel are needed for 4 buckets of cement, we can set up a proportion:

6/1 = x/4

where x is the number of buckets of gravel needed.

To solve for x, we can cross-multiply:

6 x 4 = 1 x x

24 = x

Hence, 24 buckets of gravel are needed for 4 buckets of cement when making concrete tiles using the given ratio.

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Perform the following conversions. With math explanation
300 ft = m
130 cm = in
0.5hp = W
350psi = Pa
10 ????????/????????3 = ????????/m3
350 W = ????T????/ℎ
10,000 cal = ????

Answers

a)91.44 m

b)51.18 in

c)372.85 W

d)2383186.955 Pa

e)10000 ????????/m3

f)0.4667 T????/ℎ

g)41840 J

300 ft = m

1 ft = 0.3048 m, so 300 ft = 300 * 0.3048 m = 91.44 m



130 cm = in

1 in = 2.54 cm, so 130 cm = 130/2.54 in = 51.18 in



0.5hp = W

1 hp = 745.7 W, so 0.5 hp = 0.5 * 745.7 W = 372.85 W



350psi = Pa

1 psi = 6894.757 Pa, so 350 psi = 350 * 6894.757 Pa = 2383186.955 Pa



10 ????????/????????3 = ????????/m3

1 ????????/????????3 = 1000 ????????/m3, so 10 ????????/????????3 = 10 * 1000 ????????/m3 = 10000 ????????/m3



350 W = ????T????/ℎ

1 W = 0.00134 T????/ℎ, so 350 W = 350 * 0.00134 T????/ℎ = 0.4667 T????/ℎ



10,000 cal = ????

1 cal = 4.184 J, so 10,000 cal = 10,000 * 4.184 J = 41840 J

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Write
tanz
in terms of
secz
using the Pythagorean Identity for: Part: 0 / 2 Part 1 of 2 (a)
z
in Quadrant II.
tanz=
Part:
1/2
Part 2 of 2 (b)
z
in Quadrant IV.

Answers

We can write tanz in terms of secz using the Pythagorean Identity as:
tanz = -sqrt(sec^2z - 1)

Part 1 of 2:
The Pythagorean Identity states that sin^2z + cos^2z = 1. We can use this identity to write tan^2z in terms of sec^2z.

First, let's rearrange the Pythagorean Identity to isolate cos^2z:
cos^2z = 1 - sin^2z

Next, we can divide both sides of the equation by cos^2z to get:
1 = sec^2z - (sin^2z)/(cos^2z)

Since tan^2z = (sin^2z)/(cos^2z), we can substitute this into the equation:
1 = sec^2z - tan^2z

Finally, we can rearrange the equation to isolate tan^2z:
tan^2z = sec^2z - 1

Now, let's consider the case when z is in Quadrant II. In this quadrant, tanz is negative and secz is negative. Therefore, we can write:
tanz = -sqrt(sec^2z - 1)

Part 2 of 2:
In the case when z is in Quadrant IV, tanz is negative and secz is positive. Therefore, we can write:
tanz = -sqrt(sec^2z - 1)

So, in both cases, we can write tanz in terms of secz using the Pythagorean Identity as:
tanz = -sqrt(sec^2z - 1)

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Find an nth-degree polynomial function with real coefficients satisfying the given conditions. If you are using graphing utility. Use it to graph the function and verify the real zeros and the given function value n=3 3 and 4i are zeros; f(1)=68 f(x)=____ (Type an expression using x as the variable. Simplify your answer.)

Answers

x = 1 is 68

The polynomial function that satisfies the given conditions is f(x) = (x-3)(x-3i)(x-4)(x-4i) = x4 - 11x3 + 34x2 + 104x - 324. Graphically, this function has 4 real zeros at x = 3, 3i, 4, and 4i, and the function value at x = 1 is 68.

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Michelle's phone plan charges $0.22 per text message. Jeff's plan charges $0.12 a text plus an additional $1 a day. for what number of texts are the cost of the phone plans the same? write an algebraic equation and solve.

Answers

Answer:

Let's assume that the number of text messages sent in a day is x. Then the cost of Michelle's phone plan is:

Cost of Michelle's plan = 0.22x

And the cost of Jeff's phone plan is:

Cost of Jeff's plan = 0.12x + 1

We want to find the number of text messages for which the two plans have the same cost. So we can set the two expressions for the cost equal to each other and solve for x:

0.22x = 0.12x + 1

0.1x = 1

x = 10

Therefore, for 10 text messages per day, the cost of Michelle's plan and Jeff's plan will be the same.

We can also verify this by plugging x = 10 into the two expressions for the cost:

Cost of Michelle's plan = 0.22(10) = $2.20

Cost of Jeff's plan = 0.12(10) + 1 = $2.20

So the cost of the two plans is indeed the same for 10 text messages per day.

Answer:

Step-by-step explanation:

cost m = 0.22x

cost j = 0.12x+1

0.22x=0.12x+1

0.1=1

x=10

cost m = 0.22(10) = $2.20

cost J =0.12(10)+1=$2.20

So the answer is 10

Airplane tickets to Fairbanks, Alaska will cost $958 each. Airplane tickets to Vancouver, Canada will cost $734. How much can the four members of the Harrison family save on airfare by vacationing to Vancouver

Answers

Answer:

The family will save $896 on airfare by vacationing to Vancouver

Step-by-step explanation:

Tickets to Fairbanks - $958 each (4 total people)

Total cost - 958 times 4 = $3832

Tickets to Vancouver - $734 each (4 total people)

Total cost - 734 times 4 = $2936

$3832 - $2936 = $896

A book sold 31,100 copies in its first month of release, suppose this represents 8. 3% of the number of copies sold to date. How many copies have been sold to date?

Answers

The total number of copies sold is 374,096, calculated using proportion and percentage based on the copies sold in the first month.

Let x be the total number of copies sold to date.

We know that the number of copies sold in the first month represents 8.3% of the total number of copies sold to date, so we can set up the following equation:

31,100 = 0.083x

Solving for x:

x = 31,100 / 0.083

x = 374,096.39

Rounding to the nearest whole number, we get:

x = 374,096

Therefore, approximately 374,096 copies have been sold to date.

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Find the factors of function f, and use them to complete this statement. f ⁡ ( x ) = 2 ⁢ x 4 − x 3 − 18 ⁢ x 2 + 9 ⁢ x From left to right, function f has zeros at x = , x = , x = , and x = .

Answers

From left to right, function f has zeros at x = 0, x = 3, x = -3, x = 1/2, and x = -3/2.

What, in your perspective, does a function accomplish?

An expression, rule, or law in mathematics that explains how one independent variable and one dependent variable are connected (the dependent variable).

The factors of the function f(x) can be found by factoring the expression:

f(x) = 2x⁴ - x³ - 18x² + 9x = x(2x³ - x² - 18x + 9)

To find the zeros of f(x), we need to find the values of x that make the expression in the parentheses equal to zero:

2x³ - x² - 18x + 9 = 0

We can use synthetic division or other methods to factor this polynomial and find its zeros. Alternatively, we can use the Rational Zeros Theorem to test possible rational zeros:

Possible rational zeros: ±1, ±3, ±9, ±1/2, ±3/2, ±9/2

Testing x = 1: 2(1)³ - (1)² - 18(1) + 9 = -8, not a zero

Testing x = -1: 2(-1)³ - (-1)² - 18(-1) + 9 = 28, not a zero

Testing x = 3: 2(3)³ - (3)² - 18(3) + 9 = 0, a zero

Testing x = -3: 2(-3)³ - (-3)² - 18(-3) + 9 = 0, a zero

Using polynomial division or factoring by grouping, we can factor the polynomial further:

2x³ - x² - 18x + 9 = (x - 3)(2x² + 5x - 3)

The quadratic factor can be factored using the quadratic formula or other methods:

2x² + 5x - 3 = (2x - 1)(x + 3)

Therefore, the zeros of f(x) are:

x = 0 (from the factor x)

x = 3 (from the factor x - 3)

x = -3 (from the factor x + 3)

x = 1/2 (from the factor 2x - 1)

x = -3/2 (from the factor 2x - 1)

So the completed statement is:

From left to right, function f has zeros at x = 0, x = 3, x = -3, x = 1/2, and x = -3/2.

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PLEASE HELP WILL GIVE BRAINLIEST!!

Proof attached

Prove AD || EF

Answers

Answer:It is given that

In △ABC,

DE∥AC

What is similarity of triangles?

Two triangles are similar if corresponding angles are equal and corresponding sides are in proportion.

Let us consider △BDE and △ABC,

∠B=∠B.....common angles

∠BDE =∠BAC....corresponding angles

so, △BDE∼△ABC

Since △BDE and △ABC are similar so, corresponding sides will be in proportion,

Subtract 1 from both sides,

Thus, we proved   using the similarity of triangles.

Step-by-step explanation:

Math part 2 question 4

Answers

Answer:

[tex]\dfrac{x}{x + 1}\\\\\text{which is the first answer choice }[/tex]

Step-by-step explanation:

We are given
[tex]f(x) = x^2 - x\\g(x) = x^2 - 1\\\\\text{and we are asked to find $ \left(\dfrac{f}{g}\right)\left(x\right)$}[/tex]

[tex]\left(\dfrac{f}{g}\right)\left(x\right) = \dfrac{f(x)}{g(x)}\\\\\\= \dfrac{x^2-x}{x^2 - 1}[/tex]

[tex]x^2 - x = x(x - 1)\text{ by factoring out x}\\\\x&2 - 1 = (x + 1)(x - 1) \text{ using the relation $a^2 - b^2 = (a + 1)(a - 1)$}[/tex]

Therefore,

[tex]\dfrac{x^2-x}{x^2 - 1} = \dfrac{x(x-1)}{(x + 1)(x - 1)}[/tex]

x - 1 cancels out from numerator and denominator with the result
[tex]\dfrac{x}{x+1}[/tex]

So

[tex]\left(\dfrac{f}{g}\right)\left(x\right)$} = \dfrac{x}{x + 1}[/tex]

For a certain 2-year polytechnic school, studies by the registry show that the probability of a randomly selected first-year student returning for a second year is 0.54. Assume that 8 first-year students are randomly selected.
Create a probability distribution showing the possible outcomes and corresponding probabilities.
Compute and interpret P(X≤3).
Compute the expected number from many trials of randomly selected groups of 8 freshmen that return for the second year.
Compute the standard deviation.
The Student Services Department randomly selected 8 freshmen and met with them for two one-on-one advising sessions during the freshmen year. Of the 8 students who participated, 7 returned for the second year. Can you consider the advising program a success?

Answers

The probability distribution for the possible outcomes can be created using the binomial distribution formula:
P(X=x) = (n choose x) * p^x * (1-p)^(n-x)
Where n is the number of trials (in this case, 8), x is the number of successes (returning for a second year), p is the probability of success (0.54), and 1-p is the probability of failure.

The probability distribution is as follows:
| X | P(X) |
|---|------|
| 0 | 0.010 |
| 1 | 0.059 |
| 2 | 0.167 |
| 3 | 0.282 |
| 4 | 0.313 |
| 5 | 0.223 |
| 6 | 0.106 |
| 7 | 0.033 |
| 8 | 0.005 |
To compute P(X≤3), we add the probabilities for X=0, X=1, X=2, and X=3:
P(X≤3) = 0.010 + 0.059 + 0.167 + 0.282 = 0.518
This means that there is a 51.8% chance that 3 or fewer of the randomly selected first-year students will return for a second year.
The expected number of students returning for a second year can be calculated using the formula:
E(X) = n * p = 8 * 0.54 = 4.32
This means that on average, 4.32 of the randomly selected first-year students will return for a second year.

The standard deviation can be calculated using the formula:
σ = √(n * p * (1-p)) = √(8 * 0.54 * 0.46) = 1.39

Finally, to determine if the advising program was a success, we can compare the observed number of students returning (7) to the expected number (4.32). Since 7 is greater than 4.32, it appears that the advising program may have had a positive effect on the students' decision to return for a second year. However, further analysis would be needed to determine if this difference is statistically significant.

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Nolan was studying birth weights of infants in Somalia. He took an SRS (simple random sample) of 100 births and calculated a sample mean birth
weight of & = 3.2 kg. The sample data was slightly skewed with a few
outliers. He is considering using his data to construct a confidence interval for the mean birth weight in Somalia.
Which conditions for constructing at interval have been met?

Answers

It appears that Nolan has met the conditions for constructing a confidence interval for the mean birth weight in Somalia. However, he should also check the skewness and presence of outliers in the sample to ensure that the normal approximation is appropriate.

What is skewed data?

In other words, data with a lower bound are frequently skewed right, and data with an upper bound are typically biased left.

Start-up effects can also cause skewness.

To construct a confidence interval for the mean birth weight in Somalia, we need to ensure that the following conditions are met:

Random Sampling: Nolan used a simple random sample of 100 births, which meets the condition of random sampling.

Independence: Each birth weight in the sample should be independent of the other. This condition is met if the sample size is less than 10% of the total population of births in Somalia.

Sample size: In general, a sample size of at least 30 is recommended to use the normal distribution to approximate the sampling distribution of the sample mean. Since Nolan's sample size is 100, this condition is met.

Skewness and outliers: Nolan mentioned that the sample data was slightly skewed with a few outliers.

Therefore, all the required conditions are given above.

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Answer:

the data is a random sample from the population of interest.

the sampling distribution of x is approximately normal.

individual observations can be considered independent.

Step-by-step explanation:

A regular hexagon is a polygon that has six sides with equal length and six interior angles with equal measure. In Figure 1, regular hexagon ABCDEF has side length 2x and its vertices lie on the circle with centre O. The diagonals AD, BE and CF divide ABCDEF into six congruent equilateral triangles. (a) In terms of x, what is the radius of the circle?

Answers

radius of the circle is sqrt(3)x.

The radius of the circle can be found by using the Pythagorean Theorem. The side lengths of each equilateral triangle created by the diagonals is 2x, so the hypotenuse of the triangle is sqrt(3)x. Since the hypotenuse of each triangle is the same as the radius of the circle, the radius of the circle is sqrt(3)x.

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three times a number, added to 4, is 40

Answers

Answer:

12

Step-by-step explanation:

12 × 3= 36

36 + 4= 40

so the answer is 12

Answer:

Not true with all numbers!

Step-by-step explanation:

see.Ex.3x3=9+4=13 not 40

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