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Answer: -3

Step-by-step explanation:

Answer:

[tex]f(x)=-2x(x+4)[/tex]

Step-by-step explanation:

We want to find the equation of a quadratic function in factored form with zeros at x = -4 and x = 0 that passes through the point (-3, 6).

The factored form of a quadratic is given by:

[tex]f(x)=a(x-p)(x-q)[/tex]

Where p and q are the zeros and a is the leading coefficient.

Since we have zeros at x = -4 and x = 0, let p = -4 and q = 0. Substitute:

[tex]f(x)=a(x-(-4))(x-0)[/tex]

Simplify:

[tex]f(x)=ax(x+4)[/tex]

And since we know that the function passes through the point (-3, 6), f(x) = 6 when x = -3. Thus:

[tex](6)=a(-3)(-3+4)[/tex]

Simplify:

[tex]6=a(-3)(1)[/tex]

Thus:

[tex]-3a=6\Rightarrow a=-2[/tex]

So, our quadratic function is:

[tex]f(x)=-2x(x+4)[/tex]

Answer:

142 [tex]cm^3\\[/tex]

Step-by-step explanation:

You have to do [tex](7*5)+(5*3)+(7*3)+(7*3)+(5*7)+(3*5)[/tex].

This equals 142 [tex]cm^3\\[/tex].

Answer:

The answer is 142cm

Step-by-step explanation:

Answer:

D. -1/7

Step-by-step explanation:

Substitute and solve

Answer:

[tex]-\frac{1}{7}[/tex]

Step-by-step explanation:

When given the following expression,

[tex]\frac{a+c}{a^2-c^2}[/tex]

With the information that the values (a = -2) and (c = 5), one is asked to evaluate the expression. One's first instinct is probably to substitute the values into the expression and solve, however, a faster approach is to simplify the expression. The denominator is the difference of squares, thus one can rewrite it as the product of two linear expressions. Then one can simplify it by canceling out like terms in the denominator and the numerator. Finally, one can then substitute the values of the (a) and (c) into the simplified expression and solve.

[tex]\frac{a+c}{a^2-c^2}[/tex]

[tex]=\frac{a+c}{(a+c)(a-c)}[/tex]

Cross out like terms in the numerator and denominator,

[tex]=\frac{a+c}{(a+c)(a-c)}[/tex]

[tex]=\frac{1}{a-c}[/tex]

Now substitute the values of (a) and (c) into the expression and simplify to evaluate,

[tex]=\frac{1}{a-c}[/tex]

[tex]=\frac{1}{(-2)-(5)}\\\\=\frac{1}{-2-5}\\\\=-\frac{1}{7}[/tex]

Answer:

19.5 cm

Step-by-step explanation:

the remaining height = 1200 /(12×8)

= 1200/96 = 12.5 cm

so, the height of the tank = 7+ 12.5 = 19.5 cm

[tex]\displaystyle\bf \boxed{V=abh \ ; \ 1dm^3=1litre=1000cm^3} \\\\a=12cm \ ; \ b=8 cm ;\: h_1=7 \; ; \ h_0=h_1+h_2=?\\\\abh_2=1,2litre=1,2dm^3\ = 1200cm^3\\\\ 8\cdot 12 h_2=1200\\\\h_2=12.5 cm\: then \\\\h_0= 7+12,5=19,5 \\\\Answer : the \ height \ of \ the \ tank \ is \ 19,5 cm[/tex]

Answer:

406

Step-by-step explanation:

all you have to do is divide 174 by 3 and multiply 58 by 7

Answer:

$35000

Step-by-step explanation:

A = P(1+rt)

A = 25000*(1+4%*10)

A = 35000

BRAINLIEST PLEASEEEEEEEEEEE

Answer: The ratio that represents the cosine of ∠T is [tex]\frac{56}{65}[/tex]

Step-by-step explanation:

We are given:

UV = 56 units

VT = 33 units

UT = 65 units

∠V = 90°

Cosine of an angle is equal to the ratio of base and the hypotenuse of the triangle. ΔTUV is drawn in the image below.

[tex]\cos \theta=\frac{\text{base}}{\text{hypotenuse}}[/tex]

Base of the triangle is UV and the hypotenuse of the triangle is TU

Putting values in above equation, we get:

[tex]\cos \theta=\frac{UV}{TU}=\frac{56}{65}[/tex]

Hence, the ratio that represents the cosine of ∠T is [tex]\frac{56}{65}[/tex]

Answer: A. 0.25

Step-by-step explanation:

You need to divide 40 by 160 to calculate the percentage.

Answer:

Step 1: W = 7 - L

Step 2: Widths = 4, 3, 2, 1

Step-by-step explanation:

step1:

14 = 2L + 2W

14 - 2L = 2W

W = 7 - L

step2:

W = 7 - L

W = 7 - 3 = 4

W = 7 - 4 = 3

W = 7 - 5 = 2

W = 7 - 6 = 1

Answer:

The b represents the people on each bus.

Step-by-step explanation:

Answer:

C.the number of students who rode on each bus.

Step-by-step explanation:

Hello,

if A.P means arithmetic progression then

let's say a the first term and r the common difference.

[tex]\left\{\begin{array}{ccc}(a)+(a+r)+(a+2r)+...+(a+5r)&=&72\\a+r&=&7*(a+4r)\end{array}\right.\\\\\\\left\{\begin{array}{ccc}6a+15r&=&72\\6a+27r&=&0\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&\dfrac{-9}{2}*r\\-9r+5r&=&24\end{array}\right.\\\\\\\left\{\begin{array}{ccc}r&=&-6\\a&=&27\end{array}\right.\\\\[/tex]

Answer:

solve for what exactly, there is no equation here

Step-by-step explanation:

please there's no equation here

Step-by-step explanation:

What equation are you talking about

EF is tangent to the circle we'll assume; otherwise there's no progress.

Call the center C. ECD is isosceles, formed from two radii and the chord.

Angle CED is complementary to DEF

CED = 90 - 65 = 25 degrees

CDE is congruent, isosceles triangle and all that: CDE=25

That leaves DCE=180-25-25=130 degrees

That's the measure of arc DE as well:

Answer: 130 degrees, choice A

Answer:

130

Step-by-step explanation:

Hey there!

To solve this problem, we will be using Trigonometric Ratio. Trigonometry is always helpful when it comes to finding a missing side with specific measure/angle.

1. Cosine Ratio

2. Adjacent and Hypotenuse

Hope you understand this topic! If not, feel free to ask!

3. Solve The Problem

Therefore, the equation for the problem is:

[tex] \large{cos62 \degree = \frac{x}{12} }[/tex]

*cos is the short form of cosine*

At this part, we need a calculator to find the value of cos62 degrees. That's because it is not a degree like 0, 30, 45, 60 and 90 which can be found without a calculator.

When we put cos62 in a calculator, make sure to put it in degree mode since a calculator has two modes which are degree and radian.

When we put cos62 in, we should get 0.46947156... Because you want a one decimal place, we round the value up to the nearest tenth as we get 0.5 because 6 is greater than 5 and should be rounded up and not down. That makes the equation to:

[tex] \large{0.5 = \frac{x}{12} }[/tex]

Oh well! Finally to the equation part. Whenever you have to solve the equation that has decimal numbers in it, the best way to deal with decimal numbers is to make them into a whole number or integer. But how? Simply multiply the whole equation by 10. Because 0.5×10 is 5 thus 0.5 becomes an integer after multiplying 10.

[tex] \large{0.5 \times 10 = \frac{x}{12} \times 10} \\ \large{5 = \frac{10x}{12} }[/tex]

10x/12 can be simplified again.

[tex] \large{5 = \frac{5x}{6} }[/tex]

Then we isolate x-value by multiplying 6 the whole equation.

[tex] \large{5 \times 6 = \frac{5x}{6} \times 6} \\ \large{30 = 5x} \\ \large{x = 6}[/tex]

Huh, that's awkward! We want the answer in a 1 decimal place but seems like the answer for this is 6. Why? Well that is not an exact answer, but more like an approximation. Because the value of cos62 degree is actually a repeating decimal and doesn't have exact value.

When we put the equation cos62 = x/12 in the equation and solve. It appears that the the answer is 5.63365875. Because we round up to nearest tenth, it gives an approximation to 5.63365875 instead.

Hence, the equation and value above is just a rounded to the whole number from 5.63365875.

Because you want a one place decimal. Hence,

4. Final Answer

Answer:

14 or 10.4

Step-by-step explanation:

I don’t really understand the question but here I go I’ll try;

The height is 4 and the width is 10, so I think it’s 14 or 10.4.

The Constant that relates the height and width is 5/2.

The constant of proportionality k is given by k=y/x where y and x are two quantities that are directly proportional to each other.

Once you know the constant of proportionality you can find an equation representing the directly proportional relationship between x and y, namely y=kx, with your specific k.

Given:

we have the coordinates as (10, 4)

The coordinates shows that when the height of the rectangle is 4 unit then the width of the rectangle is 10.

Using Constant of Proportionality

y= k x

10 = k(4)

k = 10/ 4

k = 5/2

Learn more about Constant of Proportionality here:

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Answer:

27 degrees

Step-by-step explanation:

First, we can draw this out. Since the altitude is 8000, we can make that the height, and it goes 16000 feet through the air, that can be the length. I have drawn this out, as shown in the image. Note that when drawing, because the airplane is going up and forward, that path should represent the hypotenuse. The angle of elevation is the angle connecting the length and the path, as shown by the angle x in the picture.

We know than tan(x) = opposite/adjacent, so tan(x) here = 8000/16000 = 1/2. Then, arctan(1/2) =x = 27 degrees

Answer:

x = 7

Step-by-step explanation:

First we find out what we are using sin,cos, or tan then we plug in the numbers

Sin 26 x 16 = 7

Answer:

60% of 20 pages = .6  * 20 = 12 pages

Step-by-step explanation:

Answer:

[tex]2x - 35273 = 5361925 \\ 2x = 5361925 + 35273 \\ 2x = 5397198 \\ x = \frac{5397198}{2} \\ x = 2698599[/tex]

[tex]\displaystyle\ 2x-35273=5361925\\\\2x=53\underline{61925}+\underline{35273} \\\\2x=5397198\\\\\\x=\frac{5397198}{2} =2698599\\\\\underline{x=2698599\qquad }\\\\2\cdot 2698599-35273=5361925\\\\5397198-35273=5361925\\\\5361925=5361925[/tex]

Answer:

$58.8 million

Step-by-step explanation:

43% of x = 25.3 million

.43x = 25300000

x = 25300000 ÷ .43

x = 58837209.30

x = 58.8 million

Answer:I don’t speak Spanish so I can’t help

Step-by-step explanation:

Answer: y = $50x + 100

Answer:

6 I think

Step-by-step explanation:

Answer: 150 pounds

Step-by-step explanation:

Answer:

cosJ ≈ 0.38

Step-by-step explanation:

This is a 5- 12- 13 right triangle

with HI = 12, HJ = 13, IJ = 5

cosJ = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{IJ}{HJ}[/tex] = [tex]\frac{5}{13}[/tex] ≈ 0.38 ( to nearest hundredth )

The required value of Cos(J) for the given triangle is 0.38.

Pythagoras theorem states that in a right angled triangle, the sum of the squares of the perpendicular and base is equal to the square of the hypotenuse. It can be written as h² = p² + b².

In the given ΔHIJ the sides are given as,

JH = 13  and HI = 12.

Now, apply Pythagoras theorem to obtain,

IJ² + HI² = JH²

⇒ IJ² = 13² - 12²

⇒ IJ = 5

Use trigonometric ratio to obtain,

Cos(J) = IJ/HI = 5/13 = 0.38

Hence, the value of Cos(J) is obtained as 0.38.

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