If the battery is reversed, the direction of the currents in coils 1, 2, and 3 will also be reversed. When the switch is first closed, the current will flow from the negative terminal of the battery through coil 1, then through coil 2 and finally through coil 3 before returning to the positive terminal of the battery.
As a result, the currents in coils 1, 2, and 3 will be counterclockwise, clockwise, and counterclockwise, respectively.
When the switch has been closed for a long time, the current in the circuit will reach a steady state, and the direction of the currents in the coils will remain the same as when the switch was first closed.
Just after the switch is opened, the current in the circuit will start to decrease, and the direction of the currents in the coils will be reversed. As a result, the currents in coils 1, 2, and 3 will be clockwise, counterclockwise, and clockwise, respectively.
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at what speed do a bicycle and its rider, with a combined mass of 100 kg , have the same momentum as a 1800 kg car traveling at 6.0 m/s ?
Explanation:
The momentum of an object is given by the product of its mass and velocity, so we can set up an equation to solve for the velocity of the bicycle and rider:
momentum of bicycle and rider = momentum of car
(mass of bicycle and rider) x (velocity of bicycle and rider) = (mass of car) x (velocity of car)
Substituting the given values, we get:
(100 kg) x (velocity of bicycle and rider) = (1800 kg) x (6.0 m/s)
Simplifying and solving for the velocity of the bicycle and rider, we get:
velocity of bicycle and rider = (1800 kg x 6.0 m/s) / 100 kg = 108 m/s
Therefore, the bicycle and rider would need to be traveling at 108 m/s (or approximately 386 km/h) to have the same momentum as the car traveling at 6.0 m/s.
The momentum of a bicycle and its rider, with a combined mass of 100 kg, has the same momentum as a 1800 kg car traveling at 6.0 m/s when the bicycle and rider travel at 0.033 m/s.
Momentum is calculated by multiplying the mass of an object by its velocity. The momentum of the car is 1800 x 6.0 = 10,800 kgm/s. The momentum of the bicycle and rider is 100 x v, so the momentum of the bicycle and rider is equal to the car when v = 0.033 m/s.
In other words, the bicycle and rider must travel at 0.033 m/s for the two to have the same momentum. This is much slower than the car's speed of 6.0 m/s, so the car's momentum is much greater than that of the bicycle and rider.
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A 0.75μF capacitor is charged to 80 V . It is then connected in series with a 55Ω resistor and a 150 Ω resistor and allowed to discharge completely. How much energy is dissipated by the 55Ω resistor?
the 55Ω resistor dissipates approximately 10.97μJ of energy as the capacitor discharges completely.
To find the energy dissipated by the 55Ω resistor, we first need to calculate the total resistance of the circuit, which is 55Ω + 150Ω = 205Ω.
Using the formula for the time constant of an RC circuit, we can find the time it takes for the capacitor to discharge completely: τ = RC = 0.75μF * 205Ω = 153.75μs
After one time constant, the voltage across the capacitor will have decreased to approximately 36.8% of its initial value (80 V). So, the voltage across the 55Ω resistor at this point will be:
V = 80 V * 0.368 = 29.44 V
Using Ohm's Law, we can find the current flowing through the 55Ω resistor:
I = V / R = 29.44 V / 55Ω = 0.535 A
Finally, we can use the formula for energy dissipated by a resistor: E = I^2 * R * t
where t is the time it takes for the capacitor to fully discharge, which is approximately 5 time constants (since it takes about 5 time constants for the voltage across the capacitor to decrease to less than 1% of its initial value). So:
t = 5 * τ = 768.75μs
Plugging in the values, we get: E = (0.535 A)^2 * 55Ω * 768.75μs = 10.97μJ
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At which point or points are the spring potential energy and the cart's kinetic energy both at their maximum value? Select all that apply.A B C D E F G H none
At which point or points are the spring potential energy and the cart's kinetic energy both at their maximum value, we need to consider the relationship between potential energy and kinetic energy.
Spring potential energy (PE) is at its maximum when the spring is fully compressed or fully stretched. At this point, the force exerted by the spring is at its peak. Kinetic energy (KE) is at its maximum when the cart is moving with its maximum velocity.
However, in a system involving a cart and a spring, the maximum spring potential energy and maximum kinetic energy cannot occur simultaneously. When the spring potential energy is at its maximum, the cart's velocity is zero, so the kinetic energy is at its minimum. Conversely, when the kinetic energy is at its maximum, the spring potential energy is at its minimum because the spring is neither compressed nor stretched.
Based on this understanding, none of the options (A, B, C, D, E, F, G, H) would have both maximum spring potential energy and maximum cart's kinetic energy simultaneously.
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An object is placed a distance r in front of a wall, where r exactly equals the radius of curvature of a certain concave mirror.
Part A
At what distance from the wall should this mirror be placed so that a real image of the object is formed on the wall?
Express your answer in terms of the variable r.
di = SubmitMy AnswersGive Up
Part B
What is the magnification of the image?
Express your answer using two significant figures.
m =
The magnification of the image is -1, which means that the image is inverted with respect to the object.
Part A:
The mirror should be placed at a distance of 2r from the object so that a real image is formed on the wall. This is because, for a concave mirror, when the object is placed at a distance equal to the radius of curvature, the image formed is at the same distance on the other side of the mirror. So, the distance from the object to the mirror would be r, and the distance from the mirror to the image would also be r. Therefore, the total distance from the object to the image would be 2r.
Part B:
The magnification of the image can be calculated using the formula:
m = - di/do
where di is the distance of the image from the mirror and do is the distance of the object from the mirror. Since the image is formed on the wall, which is at a distance equal to the radius of curvature of the mirror, di = r. And, as mentioned earlier, the distance of the object from the mirror is also r. Substituting these values in the above formula, we get:
m = - r/r = -1
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automobiles are designed with ""crumple zones"" intended to collapse in a collision. based on what you have learned about impulse and momentum explain why?
Automobiles are designed with crumple zones intended to collapse in a collision because of the principles of impulse and momentum. When a car is involved in a collision, it experiences a change in momentum. This change in momentum can cause a significant amount of force to be applied to the car and its occupants.
Crumple zones are designed to absorb some of this force by allowing the car to slow down over a longer period of time. This increased duration of the collision decreases the overall force that is applied to the car and its occupants. By reducing the force of the collision, crumple zones can help to reduce the severity of injuries and damage that occur in an accident. Therefore, crumple zones are an important safety feature in modern automobiles.
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Force Fx=(10N)sin(2πt/4.0s) (where t in s) is exerted on a 420 g particle during the interval 0s≤t≤2.0s.
Part A
If the particle starts from rest, what is its speed at t=2.0s?
The speed of the particle at t=2.0s is approximately 6.49 m/s.
To find the speed of the particle at t=2.0s, we first need to determine the acceleration caused by the force Fx. We can do this using Newton's second law:
F = ma
where F is the force, m is the mass of the particle, and a is the acceleration. Given that the mass of the particle is 420g, we first need to convert it to kg:
m = 420g * (1 kg/1000g) = 0.42 kg
Now, we can find the acceleration as a function of time:
a(t) = Fx(t) / m = (10N)sin(2πt/4.0s) / 0.42 kg
Next, we need to find the velocity as a function of time by integrating the acceleration function with respect to time:
v(t) = ∫a(t) dt = ∫(10/0.42)sin(2πt/4.0s) dt
To find the speed at t=2.0s, we need to evaluate the definite integral from 0s to 2.0s:
v(2.0) = ∫(10/0.42)sin(2πt/4.0s) dt from 0 to 2.0
v(2.0) ≈ 6.49 m/s
So, the speed of the particle at t=2.0s is approximately 6.49 m/s.
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2. If the truck accelerates at 0.25 m/s" and the toolbox (which again does not slip from its spot) has a mass of 1.00 kg, what is the force of friction between the toolbox and the bed of the truck? (A) 10 N (B) 4N (C) 2.5 N (D) 0.25 N (E) One needs to know the coefficient of friction to determine the friction
the force of friction between the toolbox and the bed of the truck must also be 0.25 N, which is option (D) in the answer choices.
We can use Newton's second law of motion to solve this problem. The net force acting on the toolbox is the force of friction between the toolbox and the bed of the truck, which acts in the opposite direction to the direction of motion, and the force due to the acceleration of the truck, which acts in the direction of motion. Since the toolbox does not slip from its spot, the force of friction must be equal in magnitude to the force due to the acceleration of the truck. Therefore, we can use the mass of the toolbox and the acceleration of the truck to calculate the force due to the acceleration:
F = ma = (1.00 kg)(0.25 m/s^2) = 0.25 N
Therefore, the force of friction between the toolbox and the bed of the truck must also be 0.25 N, which is option (D) in the answer choices.
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Four equal resistors connected in series have same current and same voltage across each resistor.
a) True
b) False
The given statement " Four equal resistors connected in series have same current and same voltage across each resistor." is false. Becaue, In a series circuit, the current through each resistor is the same, but the voltage across each resistor may differ.
This is because the total voltage of the circuit is divided among the resistors based on their individual resistance values. According to Ohm's Law, the voltage across a resistor is equal to the current flowing through it multiplied by its resistance. In other words, the voltage across a resistor depends on both the current flowing through it and its resistance value.
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A proton NMR signal appears as a singlet, without spin-spin coupling. This means that the H's that corresponds to the signal: Ois present at only one Hhas only one neighbor Hhas only one unique H in the moleculehas no neighbor H's
A proton NMR signal appearing as a singlet without spin-spin coupling indicates that the hydrogen atoms corresponding to the signal have no neighboring hydrogen atoms with which they interact through spin-spin coupling.
This could be because the hydrogen atoms are present in a region of the molecule where they are not in close proximity to any other hydrogen atoms or because they are shielded from the effects of neighboring hydrogen atoms by other atoms in the molecule.
In either case, the signal appears as a singlet with no splitting, indicating that the hydrogen atoms are isolated from any other hydrogen atoms that could influence their chemical shift.
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If the magnetic field halfway between two parallel wires is zero, what can be deduced about the magnitudes and directions of currents flowing in these two wires?
If the magnetic field halfway between two parallel wires is zero, it can be deduced that the currents flowing in these two wires are equal in magnitude and flowing in opposite directions.
This is known as the "right-hand rule" for parallel currents, which states that the magnetic field produced by two parallel wires is zero at a point halfway between them when the currents are equal in magnitude and flowing in opposite directions.
When two parallel wires carry equal currents in opposite directions, the magnetic fields they produce cancel out each other at the point halfway between them, resulting in a net magnetic field of zero.
Therefore, if the magnetic field halfway between two parallel wires is zero, we can infer that the currents flowing in these two wires are equal in magnitude and flowing in opposite directions.
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a 747 airliner reaches its takeoff speed of 175 mi/h in 35.4 s. part a what is the magnitude of its average acceleration? aav = m/s2
The magnitude of the average acceleration of the 747 airliner during takeoff is approximately 2.21 m/s².
To find the magnitude of the average acceleration of the 747 airliner during takeoff, we'll need to use the formula for acceleration,
a_avg = (final velocity - initial velocity) / time
Given that the airliner reaches a takeoff speed of 175 mi/h in 35.4 s, we first need to convert the speed from miles per hour (mi/h) to meters per second (m/s).
1 mi/h = 0.44704 m/s
So, 175 mi/h = 175 * 0.44704 = 78.18 m/s (approximately)
Now we can calculate the average acceleration:
a_avg = (78.18 m/s - 0 m/s) / 35.4 s
a_avg = 78.18 m/s / 35.4 s
a_avg ≈ 2.21 m/s²
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A wall clock has a 5cm long minute hand. The average velocity of the tip of the hand reaching 06.00 hrs. to 18.30 hrs. isA2.2×10 −4cm/sB1.2×10 −4cm/sC5.6×10 −4cm/sD3.2×10 −4cm/s
t is the time elapsed, which is 12.5 hours or 45,000 seconds. Therefore:
v = (5π cm) / (45,000 s) ≈ 1.1 × 10^-4 cm/s
Therefore, the closest answer choice to the calculated value is A) 2.2 × 10^-4 cm/s.
The time elapsed between 6:00 AM and 6:30 PM is 12.5 hours. During this time, the minute hand of the clock will rotate halfway around the clock face, from the 12 o'clock position to the 6 o'clock position.
The circumference of the clock face is given by:
C = 2πr
where r is the length of the minute hand, which is 5 cm. Therefore,
C = 2π(5 cm) = 10π cm
The distance traveled by the tip of the minute hand from the 12 o'clock position to the 6 o'clock position is half of the circumference of the clock face, or:
d = (1/2)C = (1/2)(10π cm) = 5π cm
The average velocity of the tip of the minute hand during this time is:
v = d/t
where t is the time elapsed, which is 12.5 hours or 45,000 seconds. Therefore:
v = (5π cm) / (45,000 s) ≈ 1.1 × 10^-4 cm/s
Therefore, the closest answer choice to the calculated value is A) 2.2 × 10^-4 cm/s.
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A crane very slowly lifts a 2.00 x 102-kg crate a vertical distance of 15.0 m. How much work w does the crane do on the crate? W = J How much work W grav does gravity do on the crate? W gray = J
The work done by gravity on the crate is -29,430 Joules when crane is lifted a distance vertically.
We'll calculate the work done by the crane and the work done by gravity on the crate.
1. Work done by the crane (W) on the crate:
To find the work done, we'll use the formula:
W = force × distance × cos(θ)
Since the crane is lifting the crate vertically, the force acting on the crate is equal to its weight (force due to gravity), which can be calculated as:
Weight = mass × gravity
Here, mass = 2.00 x 10² kg and gravity = 9.81 m/s²
Weight = 2.00 x 10² kg × 9.81 m/s² = 1962 N
Now, the angle (θ) between the force and distance is 0 degrees since they are in the same direction (upward). So, cos(0) = 1.
W = 1962 N × 15.0 m × 1
W = 29,430 J
The work done by the crane on the crate is 29,430 Joules.
2. Work done by gravity (W_grav) on the crate:
For the work done by gravity, the angle (θ) between the force due to gravity and the distance is 180 degrees (downward), so cos(180) = -1.
W_grav = 1962 N × 15.0 m × -1
W_grav = -29,430 J
The work done by gravity on the crate is -29,430 Joules.
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how much force must you apply (down toward the ground) to the wrench to just start the bolt turning? you may treat the wrench as a uniform rectangle.
A force of approximately 3.92 newtons downwards towards the ground to just start the bolt turning with a uniform rectangle wrench.
To calculate the force needed to start turning the bolt with a uniform rectangle wrench, you need to consider the static friction between the bolt and the wrench. The formula for static friction is F_friction = coefficient of static friction * F_normal, where F_normal is the normal force acting perpendicular to the surface.
Assuming the wrench is horizontal, the normal force is equal to the weight of the wrench, which can be calculated as F_weight = mass * gravity. Let's say the wrench has a mass of 1 kilogram and gravity is 9.8 meters per second squared, then F_weight = 1 * 9.8 = 9.8 newtons.
The coefficient of static friction varies depending on the materials in contact. Let's assume a value of 0.4 for steel on steel contact. So, the force needed to start turning the bolt can be calculated as F_friction = 0.4 * 9.8 = 3.92 newtons.
Therefore, you would need to apply a force of approximately 3.92 newtons downwards towards the ground to just start the bolt turning with a uniform rectangle wrench.
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An unmanned spacecraft that is used to collect information about distant objects in space is called:______
An unmanned spacecraft that is used to collect information about distant objects in space is called a probe.
A probe is a spaceship that explores the universe in search of scientific data. Astronauts are not present aboard probes. Scientists can analyse the data the probes relay back to Earth.
The first probe to enter space was Sputnik 1. On October 4, 1957, the former Soviet Union launched it. The United States launched Explorer 1 into orbit on January 31, 1958. These initial probes observed Earth from orbit. Additionally, they gained experience in space travel
The Space Race between the United States and the Soviet Union officially began at this point.
The two nations began sending probes to fly by the moon and other planets as soon as they could send them into space. The first probe to investigate a different planet was Mariner 2. Venus was passed by Mariner 2 on December 14, 1962. It attested to Venus' extreme heat.
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red light has a wavelength of 650 nm. green light has a wavelength of 550 nm. the speed of light is 3×108 m/s
The frequency of red light is 4.62×10¹⁴ Hz and the frequency of green light is 5.45×10¹⁴ Hz.
The wavelength of red light is 650 nm and the wavelength of green light is 550 nm. The speed of light is 3×10⁸ m/s. The wavelength of light is related to its frequency and speed by the formula λ = c/f, where λ is the wavelength, c is the speed of light, and f is the frequency.
Since the speed of light is constant, we can use this formula to find the frequency of each color of light.
For red light, we have:
λ = c/f
650 nm = (3×10⁸ m/s)/f
Solving for f, we get:
f = (3×10⁸ m/s)/650 nm
f = 4.62×10¹⁴ Hz
Similarly, for the green light, we have:
λ = c/f
550 nm = (3×10⁸ m/s)/f
Solving for f, we get:
f = (3×10⁸ m/s)/550 nm
f = 5.45×10¹⁴ Hz
So, the frequency of red light is 4.62×10¹⁴ Hz and the frequency of green light is 5.45×10¹⁴ Hz.
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a 367 kg box is pulled 7.00 m up a 30° frictionless, inclined plane by an external force of 4875 n that acts parallel to the plane. calculate the work done by the external force.
The work done by the external force on the 367 kg box pulled 7.00 m up the 30° frictionless inclined plane is 34,125 J (joules).
To calculate the work done by the external force on the 367 kg box being pulled 7.00 m up a 30° frictionless inclined plane, you can use the following formula:
Work = Force × Distance × cos(θ)
In this case, the external force (Force) is 4875 N, the distance (Distance) is 7.00 m, and the angle (θ) between the force and the direction of motion is 0° because the force acts parallel to the plane. So:
Work = 4875 N × 7.00 m × cos(0°)
Since cos(0°) = 1, the formula simplifies to:
Work = 4875 N × 7.00 m
Now, multiply the force by the distance:
Work = 34125 J (joules)
So, the work done by the external force on the 367 kg box pulled 7.00 m up the 30° frictionless inclined plane is 34,125 J (joules).
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stars can form most easily in clouds that are stars can form most easily in clouds that are cold and dense. warm and dense. hot and low-density.
Stars can form most easily in clouds that are cold and dense. This is the correct option.
The process of star formation begins in regions of space known as molecular clouds, which are vast collections of gas and dust. These clouds are characterized by low temperatures and high densities, which create an environment conducive for star formation.
When a molecular cloud is cold and dense, the gravitational forces within the cloud can overcome the thermal pressure of the gas, leading to the collapse of regions within the cloud. As these regions contract, the density increases, and the temperature begins to rise. Eventually, a protostar forms at the center of the collapsing region, surrounded by an accretion disk of gas and dust.
As the protostar accumulates mass from its surrounding material, the temperature, and pressure within its core increase. Once the core temperature becomes high enough, nuclear fusion of hydrogen into helium begins, and a new star is born.
In contrast, warm and dense or hot and low-density clouds are less conducive for star formation. In warm and dense clouds, the increased thermal pressure counteracts the gravitational forces, making it more difficult for the cloud to collapse and form a protostar.
Meanwhile, hot and low-density clouds lack the necessary concentration of material to initiate the process of gravitational collapse, preventing star formation from occurring in these conditions.
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a proton is launched with a speed of 4.30 ✕ 106 m/s perpendicular to a uniform magnetic field of 0.410 t in the positive z direction.(a) What is the radius of the circular orbit of the proton?
(b) What is the frequency of the circular movement of the proton in this field?
(a) The force on a charged particle moving in a magnetic field is given by the equation: F = qvB
where F is the force, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field.
In this case, the proton has a charge of +1.6 × 10^-19 C, a velocity of 4.30 × 10^6 m/s, and is moving perpendicular to the magnetic field of 0.410 T. Plugging these values into the equation, we get:
F = (1.6 × 10^-19 C)(4.30 × 10^6 m/s)(0.410 T) = 2.34 × 10^-13 N
The force on the proton is directed towards the center of the circular orbit, and is given by the equation:
F = mv^2/r
where m is the mass of the proton and r is the radius of the orbit. Equating the two expressions for F, we get:
mv^2/r = qvB
Solving for r, we get:
r = mv/qB =
[tex](1.67 × 10^-27 kg)(4.30 × 10^6 m/s)/(1.6 × 10^-19 C)(0.410 T) = 1.09 × 10^-2 m[/tex]
Therefore, the radius of the circular orbit of the proton is 1.09 × 10^-2 m.
(b) The frequency of the circular movement of the proton can be calculated using the equation:
f = v/(2πr)
where f is the frequency, v is the velocity of the particle, and r is the radius of the orbit. Plugging in the values we have calculated, we get:
[tex]f = (4.30 × 10^6 m/s)/(2π × 1.09 × 10^-2 m) = 1.22 × 10^8 Hz[/tex]
Therefore, the frequency of the circular movement of the proton is 1.22 × 10^8 Hz.
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zero sequence voltage line to neutral is always zero. true or false
The statement " zero sequence voltage line to neutral is always zero " is not always true.
In an adjusted three-phase framework, the zero grouping voltage is undoubtedly zero since the three stages break even within greatness and 120 degrees out of stage with each other.
In this case, the entirety of the three-phase voltages is zero and there's no voltage awkwardness within the framework.
Be that as it may, in an uneven three-phase framework or in a framework with single-phase loads, the zero sequence voltage may not be zero. Usually, the three-phase voltages do not rise in size or are not 120 degrees out of stage with each other, resulting in voltage lopsidedness within the framework.
The zero arrangement voltage could be a degree of this voltage lopsidedness and can be nonzero in such cases.
Subsequently, the proper reply depends on the framework being considered. In an adjusted three-phase framework, the zero arrangement voltage line to impartial is continuously zero.
In a lopsided(unbalanced) three-phase framework or in a framework with single-phase loads, the zero arrangement voltage may not be zero.
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When ÎG (the change in free energy) for a reaction is less than zero (negative), the reaction is _____ and the entropy change (ÎS) for the universe is _____.
When ÎG (the change in free energy) for a reaction is less than zero (negative), the reaction is spontaneous and the entropy change (ÎS) for the universe is positive.
This is because a negative ÎG value indicates that the reaction is exothermic (releases energy) and increases the disorder (entropy) of the system and its surroundings, resulting in a net increase in the entropy of the universe.
When ΔG (the change in free energy) for a reaction is less than zero (negative), the reaction is spontaneous and the entropy change (ΔS) for the universe is positive.
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average speed is calculated bymultiple choicedividing the elapsed time by the distance traveled.multiplying distance traveled by the elapsed time.dividing the distance traveled by the elapsed time.dividing the acceleration by the elapsed time.
The average speed of the car is 50 kilometers per hour.
Average speed is calculated by dividing the distance traveled by the elapsed time. This is given by the formula:
Average Speed = Total Distance Traveled / Elapsed Time
Here, the total distance traveled refers to the distance covered by an object from its initial position to the final position. The elapsed time refers to the time taken by the object to travel this distance.
For example, if a car travels a distance of 100 kilometers in 2 hours, then its average speed is:
Average Speed = Total Distance Traveled / Elapsed Time
= 100 km / 2 hours
= 50 km/hour
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a tornado passes by your house. when the first windows break, does the glass blow inside the house or outside the house? why?
When a tornado passes by your house and the window breaks, the glass blows outside due to the low pressure.
Due to the low wind pressure outside the home, where the wind velocity is exceptionally strong, doors, windows, and the roof fly off during storms and tornadoes.
On the other hand, there is high pressure and low velocity air within the house. An explosion is produced as a result of the pressure differential.
Similar circumstances may be seen when a roof is blowing, when pressure is high at the bottom of the roof because the wind speed is low there and high above.
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find the kinetic energy ke that the electron must have in order to excite the atom.
The minimum kinetic energy required to excite an atom with an electron collision depends on the internal energy of the excited state and the masses of the atom and electron and can be calculated using the conservation of energy and momentum.
To determine the minimum kinetic energy required to excite an atom with an electron collision, we can use the conservation of energy and momentum. Before the collision, the total energy is the kinetic energy of the electron (Kei), as the atom is initially at rest. After the collision, the atom and electron move together with a final kinetic energy (Kef), and internal energy (E) are also present in the system.
Conservation of momentum tells us that the total momentum before and after the collision must be equal. Since the atom is initially at rest, the momentum of the system before the collision is simply the momentum of the electron. After the collision, the momentum of the atom and electron must be equal and opposite to the initial momentum of the electron.
Conservation of energy tells us that the total energy before and after the collision must also be equal. Before the collision, the total energy is just the kinetic energy of the electron (Kei). After the collision, we have the kinetic energy of the combined atom and electron system (Ke), the internal energy (E), and the kinetic energy of the motion of the atom and electron [tex]$\frac{1}{2}(m_e + M)v_{ef}^2$[/tex]
By solving the equations for Kei and Ke, we get:
[tex]$Ke_{i} = \frac{m_{e}v_{ei}^{2}}{2}$[/tex]
[tex]$Ke = \frac{(m_{e}+M)v_{ef}^{2}}{2} - E$[/tex]
To excite the atom to the higher energy state with internal energy E, Ke must be equal to or greater than E.
Substituting the expressions for Kei and Ke into this inequality and solving for vei, we get:
[tex]$ v_{ei} \geq \sqrt{\frac{2E_m e}{(m_e + M)^2}} $[/tex]
Thus, the minimum kinetic energy required to excite an atom is:
[tex]$K_{ei} = \frac{1}{2}m_e v_{ei}^2 \geq \frac{E}{1+\frac{m_e}{M}}$[/tex]
This equation shows that the minimum kinetic energy required depends on the mass of the electron and the atom, as well as the internal energy of the excited state. If the internal energy is high, then higher kinetic energy will be required to excite the atom. Additionally, if the mass of the atom is much larger than the mass of the electron, then a higher kinetic energy will be required to overcome the inertia of the atom.
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Complete question:
An atom of mass M is initially at rest, in its ground state. A moving (nonrelativistic) electron of mass me collides with the atom. The atom+electron system can exist in an excited state in which the electron is absorbed into the atom. The excited state has an extra, "internal," energy E relative to the atom's ground state. Find the kinetic energy Ke that the electron must have in order to excite the atom. Express your answer in terms of E, me, and M.
A power adapter for a laptop computer is rated at P= 89 W (meaning this is the highest power it can handle before the circuits start to fail). The voltage of the battery is represented as AV. (a) If the laptop is used at a potential difference of 12 V what is the maximum current it can draw in terms of P? (b) What is the minimum internal resistance of the laptop in Ω? (c) How much energy in joules does the laptop consume in one hour at maximum?
The maximum current the laptop can draw is 7.4 A. The minimum internal resistance is 1.62 Ω. The laptop consumes 320.4 kJ in one hour.
(a) Utilizing the power recipe P= IV, where I is the current and V is the voltage, we can modify the equation to settle for the most extreme current (I) as I = P/V. Hence, the greatest current the PC can draw at an expected contrast of 12 V is I = 89 W/12 V = 7.42 A.
(b) The inner obstruction (r) of the PC can be determined utilizing the equation r = (AV - V)/I, where AV is the battery voltage. In this way, the base inward obstruction of the PC is r = (AV - 12 V)/7.42 A.
(c) The energy consumed in 60 minutes (E) can be determined utilizing the recipe E = P x t, where t is the time in hours. Accordingly, the energy consumed in one hour at greatest is E = 89 W x 1 hour = 89 Wh = 89 x 3600 J = 3.204 x [tex]10^5[/tex] J.
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A stationary charge Q is point charge. A particle of charge mores in the electric field created by Q from infinity to the distance R between them Part(a)_Findthepotentialatthe distance Rfrom the_chargeQ(ie_thepotential diffetence trarersedby_thetestcharge_ coming from infinity ) Part (6) If the charge q = 0.98 LC; distance R = 128. cm and Q = Ill nC; what is the Work (in J) done by the external force to move into the position R?'
Part (a): The potential at a distance R from a point charge Q can be found using the equation:
V = kQ / R
Where k is the Coulomb constant (k = 9 x 10^9 Nm^2/C^2)
So in this case, the potential at a distance R from the point charge Q is:
V = (9 x 10^9 Nm^2/C^2) x (1.11 x 10^-7 C) / (0.128 m)
V = 7.23 x 10^5 V
Therefore, the potential difference traversed by the test charge coming from infinity is 7.23 x 10^5 V.
Part (b):
The work done by the external force to move the charge q to a distance of 128 cm from Q can be found using the equation:
W = q * V
Where q is the charge of the particle, and V is the potential difference (in volts) calculated in part (a).
So in this case, the work done is:
W = (0.98 x 10^-6 C) x (7.23 x 10^5 V)
W = 708 J
Therefore, the work done by the external force to move the charge q to a distance of 128 cm from Q is 708 J.
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for voltage measurements, you need to select auto range volts dc on the dmm and connect the _____ lead to _____, and the _____ lead to _____.
for voltage measurements, you need to select auto range volts dc on the dmm and connect the positive lead to ground, and the negative lead to voltage source.
What is voltage?Voltage is an electrical potential difference between two points in a circuit. It is measured in volts (V) and is created by the energy of electrons moving through a conductor. Voltage plays a key role in electricity, as it is responsible for the power, current and resistance in a circuit. Voltage is what allows electrons to move through a circuit and do work. In a battery, an electrochemical reaction creates a build up of electrons on one side, resulting in a potential difference between the two sides. This potential difference is the voltage. In an AC circuit, the voltage alternates between two levels, positive and negative. This changing voltage is what allows an AC current to flow. Voltage can be used to power electrical devices such as lights, motors and electronics. Voltage is also used to measure and control the flow of electricity in a circuit.
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what was the average force of air resistance exerted on it if it came in at a constant glide angle of 10 ∘ to the earth's surface?
The average force of air resistance exerted on an object gliding at a constant angle of 10° to the Earth's surface.
To determine the average force of air resistance exerted on an object at a constant glide angle of 10° to the Earth's surface, we need to first understand the relationship between the angle, the object's weight, and the air resistance.
Step 1: Determine the weight of the object (W) in the vertical direction. This can be calculated using the object's mass (m) and the acceleration due to gravity (g), which is approximately 9.81 m/s². The formula for weight is:
W = m * g
Step 2: Calculate the vertical component of the weight (W_vertical). Since the glide angle is given as 10°, we can use the sine function to find the vertical component:
W_vertical = W * sin(10°)
Step 3: Determine the force exerted by air resistance (F_air). The object is gliding at a constant angle, which means it is in equilibrium, and the net force is zero. In this case, the air resistance force is equal and opposite to the vertical component of the weight:
F_air = W_vertical
By following these steps, you can find the average force of air resistance exerted on an object gliding at a constant angle of 10° to the Earth's surface. Keep in mind, you will need to know the object's mass to perform these calculations.
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a 0.14-n baseball is dropped from rest. it has a momentum of 0.68 kg⋅m/s just before it lands on the ground. for what amount of time was the ball in the air?
Hi! To find the time the baseball was in the air, we can use the formula for momentum:
momentum = mass × velocity
First, we need to find the velocity of the baseball just before it lands. We can rearrange the formula to solve for velocity:
velocity = momentum/mass
velocity = 0.68 kg⋅m/s / 0.14 kg
velocity ≈ 4.86 m/s
Now, we'll use the equation of motion to find the time the baseball was in the air. Since the baseball was dropped, its initial velocity is 0 m/s, and we can ignore the horizontal motion. We'll use the formula:
final velocity = initial velocity + (acceleration × time)
where the acceleration is due to gravity (approximately 9.81 m/s²). Rearranging the formula to solve for time:
time = (final velocity - initial velocity) / acceleration
time = (4.86 m/s - 0 m/s) / 9.81 m/s²
time ≈ 0.495 s
So, the baseball was in the air for approximately 0.495 seconds.
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the horizontal steel shaft has a mass of 480 kg and is suspended by a vertical cable from a and by a second cable bc which lies in a vertical transverse plane and loops underneath the shaft. calculate the tensions t1 and t2 in the cables.
The tensions in cables AB and BC are both 2356.8 N.
To solve this problem, we need to draw a free-body diagram of the shaft and consider the forces acting on it. Let T₁ and T₂ be the tensions in cables AB and BC, respectively, and let g be the acceleration due to gravity.
Since the shaft is suspended by two cables, the tension in each cable must support half of the weight of the shaft. Therefore, we have:
T₁ = T₂ = (1/2)mg
where m is the mass of the shaft, which is given as 480 kg. Thus, we have:
T₁ = T₂ = (1/2)(480 kg)(9.81 m/s^2) = 2356.8 N
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