Represent each of the following units as a combination of primitive
dimensions where M=mass, L=length, T=time

PLS show work

Watt

Newton

Horsepower

Answers

Answer 1

Some important and basic points:

Unit of time is second (s).

Unit of mass is kilogram (kg).

Unit of distance/displacement is meter (m).

P.S. Displacement and distance are nearly same things, their unit is same.

Speed/velocity = distance/time

So, its unit is m/s.

Acceleration = (final velocity-initial velocity)/time.

So, its unit is m/s² or m.s^-2

We know from the formula that,

Force = mass × acceleration

=> F = ma

Putting units:

Newton = kg.m/s² or kg.m.s^-2 _____(1)

Putting dimensions:

Newton = M.L.T^-2

________________________

We know from the formula that,

Work = force × displacement

=> W = Fs

Putting units:

Joule = Newton.m

=> Joule = kg.m.s^-2.m [from (1)]

=> Joule = kg.m².s^-2 ______(2)

Putting dimensions:

Joule = M.L².T^-2

________________________

We know from the formula that,

Power = work/time

Putting units:

Watt = joule/s

=> Watt = kg.m².s^-2/s [from (2)]

=> Watt = kg.m².s^-3 ______(3)

Putting dimensions:

Watt = M.L².T^-3

________________________

We know from the formula that,

Horsepower = 746 watt

=> Horsepower = 746kg.m².s^-3 [from (3)]

Putting dimensions:

Horsepower = 746M.L².T^-3

Hope it helps!!
Answer 2

The dimension of Watt, Newton and horsepower are ML²T⁻³, MLT⁻² and ML²T⁻³ respectively

Units and dimension

Units are measure of a quantity. Dimensions are derived from the units. Gi

Force = mass × acceleration

For Newton:

Another representation for unit of Newton is  kg.m/s². Writing in terms of the dimension

Newton = MLT⁻²

For Watts;

The unit of Watt is also kg.m².s⁻²/s which is equivalent to  kg.m².s⁻³

In terms of dimension

Dimension of Watt = ML²T⁻³

For Horse power:

The unit of horse power is  kg.m².s⁻³

Dimension of horsepower = ML²T⁻³

Learn more on units and dimension here: https://brainly.com/question/28464

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Answers

Answer:

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Answers

Answer:

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Exam Guidelines
Exam Instructions
Question 8 of 15 :
Select the best answer for the question.
8. You've been contracted to install hardwood flooring on a basketball court. The court
measures 125' x 70'. How many square feet of flooring do you need to order for the job?
Allow 20% for waste.
k
O A. 10,500 sq. ft.
O B.234 sq. ft.
O C. 100,500 sq. ft.
O. D. 8,750 sq. ft.

Answers

Answer:

our answer is d because if you multiple 125 by 70 and subtracted from 20 you Will get D.8,750 sq. ft.

Answer:

A. 10,500 sq. ft.

Explanation:

125*70 is 8750 and 20% of 8750 is 1750 so you add it and get 10,500

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Answers

Answer:

Hence Both technicians A and B are correct that is Technician A says that the system must provide an adequate volume of fuel to the high-pressure fuel injection system. Technician B says that the system must provide fuel at a minimum pressure to the high-pressure fuel injection system are true.

Explanation:

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MARK ME AS A BRIANLIEST .........

PLS HELP
Determine the dimensions for T if T = M V^2 A / L^3 where M is a mass, V is a velocity, A is an area, and L is a length.



L / T



No dimensions



M L / T^2



M



M / (L T^2)

Answers

Answer:

T=kg·m^2/s^2

Explanation:

T = kg (m^2/s^2) m^3 /m^3

Here I wrote down the unit for every dimension.

T=kg m^2 / s^2

m^3 is divided between m^3, this is equal to 1.

Result: T=kg·m^2/s^2

PD: I'm not sure if this is what you ask for. I hope it helps

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Answers

Answer:

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Yall pls help me out
Determine the dimensions for T if T = M V^2 A / L^3 where M is a mass, V is a velocity, A is an area, and L is a length.


L / T


No dimensions


M L / T^2


M


M / (L T^2)

Answers

Answer:

M·L/T²

Explanation:

The given equation for T is presented as follows;

[tex]T = \dfrac{M \cdot V^2 \cdot A}{L^3}[/tex]

Where;

m = Mass with dimension M

V = Velocity, having the dimensions L/T

A = Area, having the dimensions L²

l = Length, having the dimensions, L

Therefore;

[tex]The \ dimensions \ of \ T = \dfrac{M \times (L/T)^2 \cdot L^2}{L^3} = \dfrac{M \times L^4/T^2 }{L^3} = M \cdot L/T^2[/tex]

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