This indicates that to increase the temperature of the water in the bathtub from 2°C to 7°C, roughly 62,760 kJ of heat energy were added.
What is the water's temperature?While scientists typically use the Centigrade (or Celsius) scale, where water freezes at 0 degrees and boils at 100 degrees, we typically measure temperature in the United States using the Fahrenheit scale, where water freezes at 32 degrees and boils at 212 degrees.
According to the data given, the bathtub once held 300 kg of water at 2°C.
we can use the specific heat capacity of water and the formula:
Q = m * c * ΔT
The specific heat capacity of water is 4.184 J/(g°C), or 4184 J/(kg°C). Therefore, the amount of heat energy absorbed by the water is:
Q = 300 kg * 4184 J/(kg°C) * (7°C - 2°C)
Q = 62,760 kJ
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Which gives a greater current: 40 coulombs in 10 seconds or 2 coulombs in 1 second?
The first scenario results in a higher current of 4 amperes.
What is the current produced in both scenario?
Current is defined as the amount of charge flowing per unit time.
For the first scenario, 40 coulombs in 10 seconds, the current would be:
I = Q/t = 40 C / 10 s = 4 A
For the second scenario, 2 coulombs in 1 second, the current would be:
I = Q/t = 2 C / 1 s = 2 A
Therefore, the first scenario results in a higher current of 4 amperes than the second scenario of 2 amperes current.
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23. A hydraulic (water power) press consists of 1 cm and 5 cm diameter pistons. (a) What force must be applied on the small piston so that the large piston will be able to raise 10 N load? (b) To what height would the load be raised when the small piston has moved 0.1 m?
a. The force required on the small piston to raise a 10 N load on the large piston is 0.403 N.
b. The load would be raised to a height of 63.13 cm when the small piston has moved 0.1 m.
How to calculate?The formula is F1 / F2 = A2 / A1
where F1 is the force applied on the small piston, F2 is the force exerted on the large piston, A1 is the area of the small piston, and A2 is the area of the large piston.
A1 = (π / 4) * (1 cm)^2 = 0.0079 cm^2
A2 = (π / 4) * (5 cm)^2 = 0.196 cm^2
F1 / F2 = 0.0079 cm^2 / 0.196 cm^2 = 0.0403
F2 = 10 N
F1 = F2 * (A1 / A2) = 10 N * 0.0403 = 0.403 N
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Which of Newton's laws is related to momentum?
A.) Newton's first law
B.) Newton's second law
C.) Newton's third law
D.) fourth law
The law of Newton that is related to momentum is:
B.) Newton's second law
Newton's second law states that the rate of change of momentum of an object is directly proportional to the force applied to the object and occurs in the direction in which the force is applied. This law is often expressed as F = ma, where F is the force, m is the mass of the object, and a is the acceleration of the object. This law provides the mathematical relationship between force, mass, and acceleration, which is crucial in understanding the concept of momentum.
Option C is the accurate answer. The act of preservation of instigation is grounded on Newton’s third act because of the act of conservancy of instigation.
It can subsist deduced from the act of act and response, which states that every workforce has a repaying level and contrary force. However, the hedge pushes ago against you with an equal quantum of workforce, if you drive against a barrier.
This act signifies individual harmony in complexion workforces always do in dyads, and one core can not ply a workforce on another without passing a workforce itself.
Newton’s third act of motion states that:
“When one core exerts a workforce on the different mass, the foremost core gests a workforce which is collected at the moment on the contrary direction of the force which is wielded ”.
The above statement means that in every commerce, there's a brace of forces acting on the interacting objects. The magnitude of the workforces are level and the command of the workforce on the foremost thing is contrary to the order of the workforce on the alternate thing.
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By changing the current in the wire, you can change the ____ of an electromagnet.
An electromagnet experiences a direct current (DC) voltage that travels from the positive to the negative end of the DC circuit. This produces a magnetic field with a north and south magnetic pole.
What is the impact of polarity on electromagnet?Due to the inverse relationship between the resistance of the circuit and cross-sectional area, the thickness of the wire has an impact on the electromagnet's strength.
if the current increases, more current will flow through the electromagnet. The strength of the electromagnet is so increased by the wire's thickness.
Increasing the current through the wire. The magnetic field is produced by the current that is flowing through the wire. Stronger magnetic fields and, hence, stronger electromagnets result from larger current flow.
Therefore, an electromagnet's polarity can be altered by reversing the flow of electricity through its coil.
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States of matter that can become part a
Solution are
Solids =
Liquids =
Gases =
Saltwater
Vapors
=
Conversion of liquid into vapor or gas. - (b) Vaporization
Conversion of liquid into solid. - (d) Freezing
Conversion of solid into a liquid on heating. - (a) Melting
What is liquid?
A liquid is a nearly incompressible fluid with a (almost) constant volume regardless of pressure that adapts to the shape of its container. Being the only form with a set volume but no fixed shape, it is one of the four fundamental states of matter (the others being solid, gas, and plasma). A liquid can flow and assume a container-like shape, much like a gas can. A liquid keeps a relatively constant density and does not disperse to cover every space in a container like a gas does. a distinguishing quality of it.To know more about liquid, click the link given below:
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the perception that seemingly infertile couples who adopt a child are subsequently more likely to conceive a child themselves best illustrates
The perception that seems infertile couples who adopt a child are generally more likely to conceive a progeny themselves best describes an illusory correlation.
What is an illusory correlation?Illusory correlation when we overexcite to one outcome and ignore the other. In psychology, it states that the relationship between the variables, even such a relation does not exist.
In the given passage couples who adopt a child are subsequently more likely to conceive a child themselves best explains, suggesting the illusory correlation.
Therefore, this passage suggests an illusory correlation.
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What is the mass density of a liquid that exerts a pressure of 180 kPa at a depth of 41 m?
Answer: no answer
Explanation:
An organ pipe open at one end, but closed at the other, is vibrating in its fundamental mode, producing sound of frequency 1000 hz. If you now open the closed end, the new fundamental frequency will be.
An organ pipe with one end closed has a fundamental frequency of 1500 Hz. This pipe produces the highest number of overtones that the average person can hear.
What is the organ pipe frequency?The formula v=RTM, where M is the molar mass of the gas, determines the fundamental frequency and frequency of the sound produced when the organ pipe is filled with some gas. response the equation v2l provides the fundamental frequency.
Only one end of a closed organ pipe has an opening, and sound is transmitted through the open end. When an organ pipe is closed, the fundamental frequency is given as v=v4L, where v is the sound's velocity in the pipe's medium and L is its length.
Organ pipes have a fundamental frequency of v/4L when closed at one end and v/2L when open.
Therefore, new frequency would be 2000 Hz.
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The given question is incomplete. the complete question is given below.
An organ pipe open at one end, but closed at the other, is vibrating in its fundamental mode, producing sound of frequency 1000 hz. If you now open the closed end, the new fundamental frequency will be.
A) 2000 Hz.
B) 1000 Hz.
C) 500 Hz.
D) 250 Hz.
Below are free-body diagrams for three electric charges that lie in the same plane. Their relative positions are unknown.
Below are free-body diagrams for three electric ch
Along which of the lines (A to H) in the figure(Figure 1)should charge 2 be placed so that the free-body diagrams of charge 1 and charge 2 are consistent?
Figure 2:
Below are free-body diagrams for three electric ch
Along which of the lines (A to H) in the figure(Figure 2)should charge 2 be placed so that the free-body diagrams of charge 1 and charge 2 are consistent?
In Figure 1, charge 2 should be placed along line D to make the free-body diagrams of charge 1 and charge 2 consistent.
The electric field lines produced by charge 2 should point towards charge 1 to provide the attractive force between them. As shown in the free-body diagram of charge 1, the electric field lines point towards the left, which means that charge 2 should be placed on the left side of charge 1. Similarly, in Figure 2, charge 2 should be placed along line F to make the free-body diagrams of charge 1 and charge 2 consistent. The electric field lines produced by charge 2 should point towards the left to provide the attractive force between them. In Figure 1, charge 2 should be placed along line D to make the free-body diagrams of charge 1 and charge 2 consistent.
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Drop Tower NASA operates a 2.2-second drop tower at the Glenn Research Center in Cleveland, Ohio. At this facility, experimental packages are dropped from the top of the tower, on the 8th floor of the building. During their 2.2 seconds of free fall, experiments experience a microgravity environment similar to that of a spacecraft in orbit.
What is the drop distance of a 2.2- s tower?
(part a)
How fast are the experiments traveling when they hit the air bags at the bottom of the tower?
(part b)
If the experimental package comes to rest over a distance of 0.80 m upon hitting the air bags, what is the average stopping acceleration?
(part c)
The drop distance is 23.7402 m
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
g = Acceleration due to gravity = 9.81 m/s² = a
Equation of motion
S = ut + ½ at²
S = 0 × t × ½ × 9.81 × 2.2²
S= 23.7402 m
The drop distance is23.7402 m
v = u + at
v = 0 + 9.81 × 2.2
v= 21. 582 m/s
When they hit the airbags at the bottom of the tower the speed of the experiments is 21.582 m/s
The final speed of the fall will be the initial velocity of stopping
v² - u² = 2as
a = v² - u²/ 2s
a= 310.521816 m/s²
The average stopping acceleration is 310.521816 m/s²
What is displacement?
The temporal rate of change of the position vector can also be used to describe velocity. The velocity of P (for example, a point representing the position of a passenger walking on the train) may be referred to as a relative velocity as opposed to an absolute velocity if one considers a moving initial position, or equivalently a moving origin (e.g., an initial position or origin which is fixed to a train waggon which in turn moves on its rail track).To know more about displacement, click the link given below:
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In what units do we measure force
Answer:
Newtons
Explanation:
20. You accidentally throw your car keys horizontally at 6.0 m/s from a cliff 42 m high. How far from the base of the cliff should you look for your keys?
The keys will land 19.32 meters away from the base of the cliff.
How the solution was obtainedAssuming that there is no air resistance, the motion of the keys can be described using the equations of motion for constant acceleration.
The initial horizontal velocity of the keys is 6.0 m/s, and the vertical velocity is zero. The acceleration due to gravity is 9.8 m/s^2, and it acts vertically downwards.
The time taken for the keys to fall from the top of the cliff to the ground can be found using the equation:
h = 1/2 * g * t^2
where h is the height of the cliff (42 m), g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken.
Rearranging this equation to solve for t, we get:
t =√(2h/g)
t =√(2*42/9.8)
t = 3.22 s
During this time, the keys will have travelled a horizontal distance equal to their initial velocity multiplied by the time taken:
d = v * t
d = 6.0 * 3.22
d = 19.32 m
Therefore, the keys will land 19.32 meters away from the base of the cliff.
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Explain,
A system consists of 55 electrons and 43 protons.
Answer:
a system considered of the elements and why protons
Explanation:
no explantion
Which of the following is an effect of the varying input of solar radiation along the temperate
mid latitudes throughout the year?
Choose 1 answer:
B
Varying solar radiation causes seasonal changes in air temperature but not in
evaporation.
Varying solar radiation causes seasonal changes in evaporation but not air
temperature.
Varying solar radiation does not impact air temperature nor evaporation.
Varying solar radiation causes seasonal changes in air temperature and evaporation.
Varying solar radiation causes seasonal changes in air temperature and evaporation.
What is the effect of the varying input of solar radiation?The amount of solar radiation received by the Earth's surface changes throughout the year due to the tilt of the Earth's axis relative to the sun. In temperate mid-latitudes, this results in seasonal variations in the amount of solar radiation received, which in turn affects both air temperature and evaporation.
During the summer months, the sun is higher in the sky and the length of daylight is longer, resulting in increased solar radiation and higher air temperatures. This increased solar radiation also causes increased evaporation from bodies of water and from the soil, leading to higher levels of atmospheric moisture.
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. You are standing on a bathroom scale inside an elevator. Your weight is 140 lb, but the reading of
the scale is 120 lb. The scale reads the magnitude of the normal force. Note: 1 lb = 4.448 N.
a) What is the magnitude and direction of the acceleration of the elevator? {1.40 m/s²}
b) Can you tell whether the elevator is speeding up or slowing down? EXPLAIN.
The magnitude of the acceleration of the elevator is approximately 1.40 m/s², and it is directed downwards.
What is acceleration?Every procedure where the velocity varies is referred to as acceleration. There are only two methods to accelerate because velocity is a function of both speed and direction: changing your speed, changing your direction, or changing both.
Since the scale reads the magnitude of the normal force, we can equate the normal force with the weight of the person:
N = mg
N = (140 lb) * (4.448 N/lb) = 622.72 N
The scale reads 120 lb, which is equivalent to:
N' = (120 lb) * (4.448 N/lb) = 533.28 N
The magnitude of the acceleration can be calculated as:
ma = mg - N'
a = (g * m) - (N' / m) = [(9.81 [tex]m/s^2[/tex]) * (63.5 kg)] - (533.28 N / 63.5 kg) ≈ 1.40 [tex]m/s^2[/tex]
The elevator could be moving downwards at a constant velocity or accelerating downwards at a rate that is less than the acceleration due to gravity.
Thus, 1.40 [tex]m/s^2[/tex] is the magnitude and direction of the acceleration and
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Two balls are dropped to the ground from different heights. One is dropped 1.5 s after the other, but they
both strike the ground at the same time, 5.0 s after the first was dropped. (a) What is the difference in the
heights from which they were dropped? (b) From what height was the first ball dropped? Ans. (a) 63 m;
(b) 0.12 km
Answer:
Height difference: approximately [tex]63\; {\rm m}[/tex].
The first ball was dropped from a height of approximately [tex]123\; {\rm m}[/tex].
(Assumptions: both balls were released from rest, air friction is negligible, and that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].)
Explanation:
Under the assumptions, both ball would accelerate at a constant [tex]a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex].
Let [tex]t[/tex] denote the time since the first ball was released.
Height of the first ball at time [tex]t[/tex] can be modelled with the SUVAT equation [tex]h(t) = (1/2)\, a\, t^{2} + u\, t + h_{0}[/tex], where [tex]u[/tex] is the initial velocity. However, since [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] by assumption, this equation simplifies to [tex]h(t) = (1/2)\, a\, t^{2} + h_{0}[/tex].
Since this ball reached the ground after [tex]t = 5.0\; {\rm s}[/tex], [tex]h(5.0) = 0\; {\rm m}[/tex]. In other words:
[tex]\begin{aligned}\frac{1}{2}\, (-9.81)\, (5.0)^{2} + h_{0} = 0\end{aligned}[/tex].
Simplify and solve for the initial height of this ball, [tex]h_{0}[/tex]:
[tex]\begin{aligned}h_{0} &= -\frac{1}{2}\, (-9.81)\, (5.0)^{2} \\ &\approx 123\; {\rm m}\end{aligned}[/tex].
In other words, the first ball was dropped from a height of approximately [tex]123\; {\rm m}[/tex].
Similarly, the height of the second ball may be modelled as [tex]h(t) = (1/2)\, a\, t^{2} + h_{0}[/tex].
Since this ball reached the ground [tex]t = (5.0 - 1.5)\; {\rm s} = 3.5\; {\rm s}[/tex] after being released, [tex]h(3.5) = 0\; {\rm m}[/tex]. The initial height of this ball would be:
[tex]\begin{aligned}h_{0} &= -\frac{1}{2}\, (-9.81)\, (3.5)^{2} \\ &\approx (-60)\; {\rm m}\end{aligned}[/tex].
Subtract the initial height of the second ball from that of the first ball to find the difference in initial height:
[tex](123 - 60) \; {\rm m} \approx 63\; {\rm m}[/tex].
4 Carbon monoxide gas (CO) contained within a piston–
cylinder assembly undergoes three processes in series:
Process 1–2: Constant pressure expansion at 5 bar from V1 5
0.2 m3
to V2 5 1 m3
.
Process 2–3: Constant volume cooling from state 2 to state 3
where p3 5 1 bar.
Process 3–1: Compression from state 3 to the initial state during
which the pressure–volume relationship is pV = constant.
Sketch the processes in series on p–V coordinates and
evaluate the work for each process, in kJ.
To sketch the processes in a p-V diagram, we need to first determine the initial and final states of each process, as well as the path each process takes.
How do we determine the state of each process?Process 1-2 is a constant pressure expansion from state 1 to state 2. So, the path is a straight horizontal line on the p-V diagram, from (0.2, 5) to (1, 5) (in units of m^3 and bar).
Process 2-3 is a constant volume cooling from state 2 to state 3, so the path is a straight vertical line on the p-V diagram, from (1, 5) to (1, 1).
Process 3-1 is a compression process during which the pressure-volume relationship is pV=constant. This implies that the path on the p-V diagram is a hyperbola, passing through state 3 and returning to state 1.
The work done in each process can be calculated using the following equations:
W = P(V2 - V1) for constant pressure process (1-2)
W = 0 for constant volume process (2-3)
W = -nRT ln(V2/V1) for isothermal process (3-1), where n is the number of moles of CO, R is the gas constant, and T is the temperature of the gas.
Assuming standard temperature and pressure conditions (STP), which is 1 atm and 273.15 K, the gas constant R can be taken as 0.0821 Latm/(molK).
Using these equations, we can calculate the work for each process as follows:
W1-2 = 5*(1-0.2) = 4 kJ
W2-3 = 0
W3-1 = -nRT ln(V2/V1) = -10.0821273.15 ln(1/0.2) = 11.1 kJ
Therefore, the total work done on the gas in the three processes is the sum of the work done in each process, which is 4 kJ + 0 kJ + 11.1 kJ = 15.1 kJ.
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In the pre-lab questions, you found how the temperature of a sample depended on time as heat flowed out of it into a cold water bath. Here, you found an exponential relation. Specifically, you found that the temperature difference between the sample and the bath decayed exponentially in time as Tdif = (constant) e-t. The decay constant was found by combining the equations for heat/temperature change (Q = mcAT) for both the water bath and the sample, and the rate of heat flow through a sample, = "A (Th – T.) = 6g 2012 (T- Tu) = K520Taif, where Ks is the thermal conductivity of the sample, A = 2nrl is the lateral surface area of the cylindrical sample, I is the length of the cylindrical sample, Ax =s is the thickness (radius) of the cylindrical sample the heat must flow through (from inside to outside), and Tdif = T, – Tw is the difference between the internal temperature of the sample and the temperature of the water bath. Combining these equations and solving the resulting differential equation, we found that the exponential decay constanta = ,291 (m.c. + monew). What is the value of this exponential decay constant for Polly? Your answer should be in s-1. Assume that the average value for thermal conductivity of human tissues is 0.5 W/(m°C) and that Polly's height (length) 1 =1.5 m. Again, Polly's mass is 60 kg, assume here that Polly's specific heat is 3500 J/(kg°C), the water's mass is 300 kg, and the specific heat of water is 4186 J/(kg°C).O 2.3x10-55-1 O 4.8x10651 O 2.6x10-551 O 5.6x10651
The correct answer is c. The exponential decay constant's value is [tex]2.6*10^{-55 }s^{-1}[/tex].
To find the value of the exponential decay constant, we need to calculate Ks, the thermal conductivity of the sample. We employ the equation to arrive at this. [tex]Ks = mc + mow[/tex],
where m is the mass of Polly, c is the specific heat of the human tissues, and mow is the mass of the water. Plugging in the values for Polly's mass (60 kg), the specific heat of the human tissues (3500 J/(kg°C)) and
the mass of the water (300 kg),
and the specific heat of the water (4186 J/(kg°C)),
we get Ks = 0.5 W/(m°C).
Now, we can plug in the values for Ks, A, I, and Ax into the equation for[tex]Tdif = (constant) e^{-t}[/tex]
to calculate the exponential decay constant. By entering the values, we obtain the equation.
[tex]Tdif = (constant) e^{-t} = (0.5 W/(mC) * 2nrl * 1.5 m * 0.5 m) e^{-t}.[/tex]
Simplifying, we get [tex]Tdif = 2.6*10^{-55} e^{-t}.[/tex].
Therefore, the value of the exponential decay constant is [tex]2.6*10^{-55 }s^{-1}[/tex].
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Kangaroos have been clocked at speeds of 65 km/h
How far can a kangaroo hop in 3.90 minutes at this speed?
(part a)
How long will it take a kangaroo to hop 0.20 km
at this speed?
(part b)
a) 4225m or 4.225km b) 11.1s
For part a; convert 65km/h to km/min, to do so all you do is divide 65/60 as there are 60 minutes per hour. Afterwards, multiply by 3.90 to find the distance travelled in 3.90mins.
For part b; convert km/h to km/s, in this one we divide 65/3600 as there are 3600 seconds in one hour. Then, using the S = D/T, where S = speed, D = distance and T= time, we isolate for T and get T = D/S. So then we sub for T=0.20/0.018 (0.018 is the product of 65/3600) and we get T=11.1s.
If an object is dropped how long will it take to attain a velocity of 127.4 m/s
The time it takes for an object to attain a velocity of 127.4 m/s is 13 seconds.
What is the time of motion of the object?
The time it takes for an object to attain a velocity of 127.4 m/s after being dropped depends on several factors, including the object's mass, the strength of air resistance, and the acceleration due to gravity.
In the absence of air resistance, an object dropped from rest would attain a velocity of 127.4 m/s at a time, t calculated as;
v = u + gt
v = 0 + gt
v = gt
t = v/g
where;
g is acceleration due to gravityt = ( 127.4 ) / (9.8)
t = 13 seconds
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Without having the help of the moving pad, you and a friend have to move the very heavy
entertainment center. The kinetic friction opposing the motion is equal to 1600 N and your
maximum applied force is 1000N. How much force does your friend need to apply to make the
entertainment center move at a constant velocity?
The force needed by my friend to make the entertainment center move at a constant velocity is 600 N
How to find force application?To find the force application in a specific situation, one needs to consider the forces that are acting on an object and the net force (the vector sum of all forces acting on an object) which determines the motion of the object.
In order to make the entertainment center move at a constant velocity, the sum of the applied forces must equal the force of kinetic friction. If the maximum applied force you can provide is 1000 N, then your friend needs to apply a force of 1600 N - 1000 N = 600 N.
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Newton’s second law of motion states the relationship of mass, acceleration, and force. It says that ______
A.force equals mass divided by acceleration
B. force equals mass multiplied by acceleration
C. acceleration equals force multiplied by mass
D. every object attracts every other object in the universe
Answer:
B. force equals mass multiplied by acceleration
Explanation:
Newton's second law of motion states that the acceleration of an object equals the net force acting on the object divided by the object's mass. According to the second law, there is a direct relationship between force and acceleration and an inverse relationship between mass and acceleration.
Newton's second law of motion is F = ma, or force is equal to mass times acceleration.
Which of the following are properties of conductors?
I. Holes in the lattice allow the electricity to flow through.
II. Electricity flows easily through this type of material.
III. A few electrons in every atom are loosely held by the nuclei.
A. I only
B. II only
C. I and II
D. II and III
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Lets examine all three properties stated here ~
I) holes in lattice allow the electricity to flow through ?
- holes aren't a majority charge carrier in a conductor, in conductors electricity is conducted by free elecrons. so this statement is incorrect.
ll) Electricity flows easily through this type of material?
- That's true, conductors (usually metals) have free electrons to conduct electricity, which is responsible for good electricity Conductivity.
lll) A few electrons in every atom are loosely held by the nuclei.
- That's also true, Conductors (mainly metals) have a few electrons (say, 1, 2 or maybe 3) in there valence shell which experience quite less force of attraction from nucleus, hence they are free to move around the whole conductor randomly, making a sea of electrons.
So, the correct choice will be : D) ll and lll
A horizontal force of 23 N is required to keep a 4.5 kg box traveling at a constant speed up a frictionless incline for a vertical
height change of 4.2 m. (Enter your answers in joules.)
(a) What is the work done by gravity during this change in height?
(b) What is the work done by the normal force?
(c) What is the work done by the horizontal force?
In this case, the force is 23 N, and the distance is 4.2 m. Therefore, the work required is 97.6 joules (J).
What is joules ?Joules is a unit of energy. It is a derived unit of the International System of Units (SI) and is used to measure energy, work, or the amount of heat generated or absorbed. It is typically used to measure energy in various forms, such as the kinetic energy of a moving object, the energy of a wave, or the energy stored in an electric field or a magnetic field. In the SI, one joule is equal to the energy expended by a force of one newton when its point of application moves one meter in the direction of the force. The joule is also a unit of energy in many other systems of measurement, including the British thermal unit (BTU), the calorie, and the watt hour.
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In your own words, what is distance? Provide your own
example to illustrate your point
Answer:
the expanse or amount of space between two things, points, lines, anything in science or math.
DISTANCE...
Explanation:
A circuit with a battery, a 9 ohm resistor, a 21 ohm resistor, and a 21 ohm resistor in parallel. The total voltage in the system is 1.0V. what is the current through the battery?
The total resistance is 9 ohms + 7 ohms = 16 ohms. Thus, the current is 1.0V/16 ohms = 0.0625 A.
What is total resistance?Total resistance is the total opposition that a circuit or device encounters when an electric current is applied to it. It is the sum of all the individual resistances of each component in the circuit. Resistance is measured in ohms and is calculated by dividing voltage by current.
The current through the battery is the same as the current through the entire circuit.
To calculate the current, we can use Ohm's law which states that the current (I) is equal to the voltage (V) divided by the resistance (R).
In this case, the voltage is 1.0V and the resistance is the sum of the three individual resistances.
Since the 21 ohm resistors are in parallel, their total resistance is 7 ohms (1/R = 1/21 + 1/21).
Therefore, the total resistance is 9 ohms + 7 ohms = 16 ohms. Thus, the current is 1.0V/16 ohms = 0.0625 A.
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What is the spring constant for a supermarket scale that stretches 0. 01 m when a force of 4 n is applied? n/m what is the displacement of a spring if it has a spring constant of 10 n/m, and a force of 2. 5 n is applied? m.
400 N/m is the spring constant for a supermarket scale that stretches 0. 01 m when a force of 4N is applied. 0.25 m is the displacement of a spring if it has a spring constant of 10 n/m, and a force of 2. 5N is applied.
Hooke's Law states that as a spring is extended, the force exerted is proportional to the increase in length from the equilibrium length. The spring constant may be computed as follows:
k = F/x,
where,
k is the spring constant.
F represents the force,
x represents the change in spring length.
Now,
k = F/x
F = k × x
4 N = k × 0.01 M
k = 400 N/M
The spring constant is the proportional constant k. It is a measure of the stiffness of the spring. When a spring is stretched or compressed by an amount x from its equilibrium length, it produces a force F = -kx in the direction of its equilibrium position.
Now,
F = -kx
x = -F/k
[tex]x = \frac{2.5\ N}{10\ N/m}[/tex]
x = 0.25 m
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Order the three phases of bromine by distance between bromine particles, from least to greatest.
The three phases of bromine are: liquid, gas, and solid. To order these phases based on the distance between bromine particles, from least to greatest.
We need to consider how the intermolecular forces change as the temperature and pressure change.
In the solid phase, bromine molecules are packed tightly together, with the minimum distance between particles. This is because the intermolecular forces, including London dispersion forces and dipole-dipole forces, are strong enough to hold the particles in a fixed position.
In the liquid phase, the bromine molecules are further apart than in the solid phase, but still close enough to experience intermolecular forces. The temperature of the liquid is high enough to overcome the attractive forces and cause the particles to move about more freely, but not enough to separate the particles completely.
In the gas phase, the bromine molecules are separated by the greatest distance, with no strong intermolecular forces to hold them in place. The high temperature of the gas causes the particles to move rapidly, colliding with each other but not sticking together.
Therefore, the order of the three phases based on the distance between bromine particles is solid < liquid < gas.
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In a Newton’s ring arrangement with a film observed with light of wavelength 6 x 10-5 cm,
the difference of square of diameters of successive rings are 0.125 cm2
. What will happen
to this quantity if:
i) Wavelength of light is changed to 4.5 x 10-5 cm.
ii) A liquid of refractive index 1.33 is introduced between the lens and the plate.
iii) The radius of curvature of convex surface of plano-convex lens is doubled.
Answer:
In a Newton's ring arrangement, the difference in the square of the diameters of successive rings is equal to four times the wavelength of light divided by the refractive index of the medium between the planoconvex lens and the plane glass plate.
If the wavelength of light is changed to 4.5 x 10-5 cm, then the difference in the square of the diameters of successive rings will be equal to four times 4.5 x 10-5 cm divided by the refractive index of the medium (which is assumed to be 1 if a liquid of refractive index 1.33 is not introduced).
If a liquid of refractive index 1.33 is introduced between the lens and the plate, then the difference in the square of the diameters of successive rings will be equal to four times 4.5 x 10-5 cm divided by 1.33.
If the radius of curvature of the convex surface of the plano-convex lens is doubled, then the difference in the square of the diameters of successive rings will remain the same.
Simulate a blackbody spectrum of temperature 1700 Kelvin. Determine the peak wavelength in 3.22 nanometers of an object of that temperature nanometers What is the emissive intensity of the object
a) The peak wavelength in 3.22 nanometers of an object is 345 nanometre, b) the emissive intensity of the object is 2.82 * 10⁸ W/m².
The relationship between the temperature,T and the peak wavelength, [tex]\lambda[/tex] emitted by a black body is given by wien's displacement law:
[tex]\lambda[/tex] = b / T
Where, b is a constant and it's value is 2.898 * 10-3 m-K
Given: T = 8400 K
So, [tex]\lambda[/tex] = (2.898 * 10-3 )/8400
\lambda = 3.45 * 10-7
\lambda = 345 nm
Hence, the peak wavelength of the object at this temperature is 345 nanometre.
The amount of power emitted per unit area, P is given by Stefan Boltzmann law:
P =[tex]\sigma[/tex]T⁴
Where,
Absolute temperature, T = 8400 K
Stefan Boltzmann constant, [tex]\sigma[/tex] = 5.67 * 10-8 W/m²K⁴
So, P = 5.67 * 10-8 * (8400)⁴
P = 2.82 * 10⁸ W/m²
Hence, the power emitted per unit area is 2.82 * 10⁸ W/m².
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