Review Worksheet:
What is the Intermediate Value Theorem (IVT)? What has to be true about the function in order to use the IVT?

The rate of increase in water pressure in  atmospheres 0.000992 atm/km.

To find the rate of increase in water pressure in atm/km, we need to convert the given rate of increase from atm/m to atm/km.

[tex]1 km = 1000 m[/tex]

So, we can convert the given rate of increase as follows:

[tex]0.992 atm/m = (0.992 atm/m)[/tex] × [tex](1000 m/km)[/tex]

[tex]= 992 atm/km[/tex]

Therefore, the rate of increase in water pressure in atm/km is 992 atm/km.

We must convert the stated rate of increase in water pressure from atm/m to atm/km in order to determine the rate of increase in atm/km.

We are aware that 1000 metres make up 1 kilometre. As a result, we can translate the supplied water pressure rise rate from atm/m to atm/km as follows:

[tex]0.000992 atm/km = 0.992 atm/m[/tex] × [tex](1 km/1000 m)[/tex]

0.000992 atm/km is the rate of rise in water pressure as a result.

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Complete Question:

The water pressure on Mustafa as he dives is increasing at a rate of

0. 992, atmospheres left parenthesis, start text, a, t, m, end text, right parenthesis per meter left parenthesis, start text, m, end text, right parenthesis. What is the rate of increase in water pressure in  atmospheres?

Answer:

v=d/delta t

d=v×delta t

=266 000km/h×168h

=44,688,000.km

Answer: Area, A, is x times y.

Step-by-step explanation:

The IQR is more robust to outliers than the standard deviation, which is sensitive to outliers.

Answering your questions:

Question 1:

The Stanford Five-City Project is a study of five moderately sized Northern California towns. Multiple-risk factor intervention strategies were randomly applied to two of the communities, while the other three cities served as controls. The design of this study can be outlined in schematic form as follows:

Random selection of five moderately sized Northern California towns

Two of the towns randomly assigned to receive multiple-risk factor intervention strategies

Three of the towns serve as controls and do not receive any intervention

The health outcomes of the communities are compared after the intervention to evaluate its effectiveness

Question 2:

Population: The population for this study is all employees who used the psychological counseling benefit in the prior year.

Sample: The sample is the 25 employees who completed and returned their questionnaires.

Concern: The fact that only 25 of the 100 questionnaires were completed and returned raises concerns about the representativeness of the sample. The sample may not be representative of the population, and the results of the study may not be generalizable.

Question 3:

If data are really skewed, an appropriate measure of central location would be the median. An appropriate measure of spread for skewed data would be the interquartile range (IQR), which is the difference between the third quartile (Q3) and the first quartile (Q1). The IQR is more robust to outliers than the standard deviation, which is sensitive to California

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The answers to the questions are:
(a)(i) Events X and Y are not independent.
(a)(ii) Events X and Y are not mutually exclusive.
(b)(i) P(X) = 2/3
(b)(ii) P(X U Y) = 3/5
(b)(iii) P(X|Y) = 6/5.

(a) (i) To determine if events X and Y are independent, we need to see if P(X|Y) = P(X).
P(Y|X) = P(XY)/P(X)
1/3 = 2/5 / P(X)
P(X) = (2/5)/(1/3)
P(X) = 6/5

Therefore, since P(X|Y) ≠ P(X), events X and Y are not independent.

(ii) To determine if events X and Y are mutually exclusive, we need to see if P(XY) = 0.
P(XY) = 2/5 ≠ 0

Therefore, events X and Y are not mutually exclusive.

(b)
(i) To find P(X), we can use the formula P(X) = P(XY) + P(XY').
P(Y') = 1 - P(Y) = 1 - 1/3 = 2/3

P(X) = P(XY) + P(XY')
P(X) = 2/5 + (2/3)(1 - 2/5)
P(X) = 2/5 + 4/15
P(X) = 10/15
P(X) = 2/3

(ii) To find P(X U Y), we can use the formula P(X U Y) = P(X) + P(Y) - P(XY).
P(X U Y) = 2/3 + 1/3 - 2/5
P(X U Y) = 10/15 + 5/15 - 6/15
P(X U Y) = 9/15
P(X U Y) = 3/5

(iii) To find P(X|Y), we can use the formula P(X|Y) = P(XY)/P(Y).
P(X|Y) = P(XY)/P(Y)
P(X|Y) = 2/5 / 1/3
P(X|Y) = (2/5)(3/1)
P(X|Y) = 6/5

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The area of each of the quadrilateral is calculated as:

11. 48 square meters;  12. 144.3 square centimeters;   13. 8.2 square yards.

14. 132 square yds;  

The area of each quadrilateral = height * base/width

11. Height = 6 m

Base = 8 m

Area= 6 * 8 = 48 square meters.

12. Height = 13 cm

Base = 11.1 cm

Area= 11.1 * 13 = 144.3 square centimeters.

13. Height = 4.1 yd

Base = 2 yd

Area= 2 * 4.1 = 8.2 square yards.

14. Height = 12 yd

Base = 11 yd

Area= 11 * 12 = 132 square yds

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The solution to the initial value problem is: y = (-1/9)e^(-3/2 t) + (1/3)(t – 4) + 10/9

To solve this initial value problem, we first need to find the homogeneous solution by setting H(t – 4) to 0. So we have:

2y' + 3y = 0

This is a first-order linear homogeneous differential equation, which we can solve using the separation of variables:

2y' = -3y

dy/y = -3/2 dt

ln|y| = -3/2 t + C

y = Ce^(-3/2 t)

Now we need to find the particular solution for H(t – 4) = 1. We can use the method of undetermined coefficients, guessing that the particular solution has the form y_p = A(t – 4) + B. Substituting this into the differential equation, we get:

2A + 3(A(t – 4) + B) = 1

Simplifying and equating coefficients, we get:

3A = 1

A = 1/3

Plugging this back into the equation and solving for B, we get:

2(1/3) + 3(1/3)(-4) + B = 0

B = 10/9

So the particular solution is y_p = (1/3)(t – 4) + 10/9.

The general solution is the sum of the homogeneous and particular solutions:

y = Ce^(-3/2 t) + (1/3)(t – 4) + 10/9

To find the value of C, we use the initial condition y(0) = 1:

1 = C + 10/9

C = -1/9

Therefore, the solution to the initial value problem is:

y = (-1/9)e^(-3/2 t) + (1/3)(t – 4) + 10/9

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It appears that the quality control of the repair process has worked, but we cannot say this with complete certainty.

To determine if the quality control of the repair process has worked, we need to check if the machine has gone longer than expected without repairs.

The expected time between two repairs is given by the formula:

Expected time = α x β

So, in this case, the expected time between two repairs is:

Expected time = 3 x 4 = 12 days

Since it has been 30 days since the last repair, it appears that the quality control has worked and the machine has gone longer than expected without repairs. However, we cannot say this with certainty as there is still a probability of such a long time gap occurring even without any improvement in the repair process.

To make a more precise statement, we can calculate the probability of the machine going 30 days or longer without repairs, assuming the repair process has not improved.

Using the gamma distribution with α= 3 and β= 4, we can calculate this probability as:

P(X > 30) = 1 - P(X ≤ 30)

where X is the time between two repairs.

Using a gamma distribution calculator or software, we can find that:

P(X > 30) ≈ 0.028

This means that there is only a 2.8% chance of the machine going 30 days or longer without repairs if the repair process has not improved.

Therefore, based on this probability, it appears that the quality control of the repair process has worked, but we cannot say this with complete certainty.

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The value of A such that the binary number is 35, must be A = 1.

We want to find the value of A such that:

1000A1 represents the number 35.

Remember that each of these numbers are the coefficient of the correspondent powers of 2, then we can write:

1000A1 = 1*2⁰ + A*2¹ + 0*2² + 0*2³ + 0*2⁴ + 1*2⁵

Solving that we will get:

1*2⁰ + A*2¹ + 0*2² + 0*2³ + 0*2⁴ + 1*2⁵ = 1 + 2A + 32

And that must be equal to 35, then:

1 + 2A + 32 = 35

2A = 35 - 33

2A = 2

A = 2/2 = 1

That is the value of A.

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The solution to the equation -5(x + 2) = 5 is x = -3.

Given the equation in the question:

-5( x + 2 ) = 5

First, we distribute the -5 to the expression inside the parenthesis:

-5×x + 2×-5= 5

-5x - 10 = 5

Next, let's isolate the variable x by adding 10 to both sides:

-5x - 10 + 10 = 5 + 10

-5x = 5 + 10

Simplifying the left side:

-5x = 5 + 10

-5x = 15

Finally, we can solve for x by dividing both sides by -5:

-5x / -5 = 15 / -5

x = -3

Therefore, the value of x is -3.

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The numbers that are at a distance of 3 from the number 10 are 7 and 13.

To describe all numbers x that are at a distance of 3 from the number 10, we can use the absolute value notation. The distance between two numbers is given by the absolute value of their difference. So, the numbers x that are 3 units away from 10 can be expressed as:

| x - 10 | = 3

This means that the absolute value of the difference between x and 10 is equal to 3. To find the values of x that satisfy this equation, we can solve for x as follows:

x - 10 = 3 or x - 10 = -3

Adding 10 to both sides of each equation, we get:

x = 13 or x = 7

Therefore, the numbers that are at a distance of 3 from the number 10 are 7 and 13.

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The product of the expression is 2x⁶ + 23x³ + 63

First, we should note that algebraic expressions are described as expressions that are composed of coefficients, terms, constants, variables and factors.

These algebraic expressions are also made up of mathematical operations, such as;

From the information given, we have that;

2x3 +9 and x3 +7?

Then,

(2x³ + 9)(x³ + 7)

expand the bracket

2x⁶ + 14x³ + 9x³ + 63

add like terms

2x⁶ + 23x³ + 63

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The area of the sector is  305. 2 cm²

The area of the shaded part is equivalent to the area of the sector.

The formula for determining the area of a sector is expressed with the equation;

A = θ/360 × πr²

Given that the parameters of the equation are;

From the diagram shown, we have;

Area = 120/360 × 3.14 × 18²

find the square values

Area = 0. 3 × 3. 14 × 324

multiply the values

Area = 305. 2 cm²

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The integral solution is: ∫[tex](1/(7\sqrt{(16 - x^2)))} dx = (1/112) arcsin(x/4) + C.[/tex]

To evaluate the integral ∫[tex](1/(7\sqrt{(16 - x^2)))} dx[/tex] using the substitution x = 4 sin(θ), we can start by finding dx/dθ:

dx/dθ = 4 cos(θ)

∫[tex](1/(7\sqrt{(16 - x^2)))} dx[/tex]= ∫[tex](1/(7\sqrt{(16 - 16sin^2}[/tex](θ)))) ([tex]4cos[/tex](θ)) dθ

Simplifying the denominator, we get:

∫[tex](1/(7[/tex][tex]\sqrt{(16 - 16sin^2}[/tex](θ)))) [tex](4cos[/tex](θ)) dθ = ∫[tex](1/(28cos[/tex](θ))) dθ

Now we can use the trigonometric identity cos^2(θ) = 1 - sin^2(θ) to rewrite the denominator:

∫[tex](1/(28cos[/tex](θ))) dθ = ∫[tex](1/(28[/tex]√[tex](1 - sin^2[/tex](θ)))) dθ

dx = 4 cos(θ) dθ

∫[tex](1/(28√(1 - sin^2[/tex](θ)))) dθ = ∫[tex](1/(28√(1 - (x/4)^2))) (1/4) dx[/tex]

This is the form of the integral that we can evaluate using the substitution [tex]u = x/4[/tex] and the formula for the integral of [tex]1/[/tex] √[tex](1 - u^2)[/tex], which is arcsin(u) + C.

Substituting [tex]u = x/4[/tex] and simplifying, we get:

[tex](1/112)∫(1/√(1 - (x/4)^2)) dx = (1/112) arcsin(x/4) + C[/tex]

Therefore, the solution is:

[tex]∫(1/(7√(16 - x^2))) dx = (1/112) arcsin(x/4) + C[/tex]

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The distance between the opposite sides of the trampoline can be found to be 14. 42 yards

To find the distance between the opposite sides of the trampoline, we are essentially finding the diagonal length. We can use the Pythagorean theorem to do this by dividing the trampoline into two right triangles.

The distance between the opposite sides would then be:

c ² = a ² + b ²

c ² = 8 ² + 12 ²

c ² = 64 + 144

c ² = 208

c = √ 208

c = 14. 42 yards

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In summary, using the IVT, we can say that there exists at least one root of the function f(x) = x² - 2x + 3 on the interval [3, 5]. However, we cannot say exactly where this root is located or how many roots there are.

The Intermediate Value Theorem (IVT) states that if a continuous function f(x) takes on values of opposite signs at two points a and b, then there exists at least one point c between a and b such that f(c) = 0.

In this case, we are given the function f(x) = x² - 2x + 3 on the interval [3, 5]. We can first check that f(x) is continuous on this interval, which it is since it is a polynomial function.

Next, we can evaluate f(3) and f(5) to see if they have opposite signs:

f(3) = 3² - 2(3) + 3 = 3

f(5) = 5² - 2(5) + 3 = 13

Since f(3) is positive and f(5) is positive, we know that f(x) does not cross the x-axis on the interval [3, 5]. However, we can still use the IVT to show that there exists at least one point c between 3 and 5 such that f(c) = 0.

To do this, we can consider the fact that the graph of f(x) is a parabola that opens upward (since the coefficient of x² is positive), and that the vertex of the parabola is located at the point (1, 2). This means that the minimum value of f(x) occurs at x = 1, and that f(x) is increasing on the interval [3, 5].

Therefore, since f(3) = 3 is less than the minimum value of f(x) on the interval [3, 5], and since f(5) = 13 is greater than the minimum value of f(x) on the interval [3, 5], there must exist at least one point c between 3 and 5 such that f(c) = 0 by the IVT.

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The experimental probability of landing on a number greater than 4 is 18/60

The experimental probability will be given by the number of times that the outcome was greater than 4 (so a 5 or a 6) over the total number of trials.

We can see that the total number of trials is 60, and we have:

The outcome 5 a total of 10 times.

The outomce 6 a total of 8 times.

Adding these values we will get 10 + 8 = 18

Then the experimental probability of a number greater than 4 is:

E = 18/60

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To find the number of zeros at the end of 2022!, we need to count the number of factors of 10 in its prime factorization. Since 10 = 2 x 5, we need to find the number of pairs of 2's and 5's that multiply to make 10.

First, we can count the number of factors of 5 in 2022!. There are 404 multiples of 5, 80 multiples of 25, and 16 multiples of 125. Therefore, there are 404 + 80 + 16 = 500 factors of 5.

Next, we need to count the number of factors of 2 in 2022!. This is equivalent to counting the number of multiples of 2, 4, 8, 16, 32, 64, 128, 256, 512, and 1024 that are less than or equal to 2022. We can simplify this by noticing that each power of 2 is a multiple of the previous power of 2. So we only need to count the multiples of 2, 4, and 8, and then multiply by the number of each power of 2 that divides into 2022.

There are 1011 multiples of 2, 505 multiples of 4, and 252 multiples of 8. The highest power of 2 that divides into 2022 is 2^1, so we only need to consider the factors of 2. Therefore, there are 1011 + 505 + 252 = 1768 factors of 2.

Since we need to find the number of pairs of 2's and 5's, the number of zeros at the end of 2022! is equal to the minimum of the number of factors of 2 and the number of factors of 5, which is 500. Therefore, there are 500 zeros at the end of 2022!.

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To turn on light 1, switches A, B, C, and D must all be on.

To determine which switches must be on for light 1 to function, we need to trace the path of the circuit from the battery to light 1 and see which switches need to be closed to complete the circuit.

Since this is a parallel circuit, the current can flow through multiple paths, and each light can have its own path to the battery. So, we need to identify the path that leads to light 1.

Starting at the battery, there are two paths that branch off, one leading to switch A and the other leading to switch B. Both switches must be closed for the current to flow through their respective paths.

From switch A, the current flows through light 2 and then to switch C. If switch C is open, then the current cannot flow to light 1. Therefore, switch C must be closed for light 1 to function.

From switch B, the current flows through light 3 and then to switch D. If switch D is open, then the current cannot flow to light 1. Therefore, switch D must be closed for light 1 to function.

Therefore, to turn on light 1, switches A, B, C, and D must all be on.

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Answer: x=67    x=70    x=61

Step-by-step explanation:

see image for explanaton

To determine the probability that the power supply will be inadequate on any given day, we need to find the probability that the daily consumption of electric power exceeds 12 million kilowatt-hours. We have a gamma distribution with α = 3 and β = 2.

Step 1: Identify the parameters of the gamma distribution.
α = 3 (shape parameter)
β = 2 (scale parameter)

Step 2: Set up the problem.
We want to find the probability P(X > 12), where X is the random variable representing daily power consumption in millions of kilowatt-hours.

Step 3: Calculate the cumulative distribution function (CDF) for the given parameters at X = 12.
We can use a gamma CDF calculator or software to find the CDF. For example, using the R programming language, you can use the "pgamma" function:

pgamma(12, shape = 3, scale = 2)

Step 4: Calculate the probability of power supply being inadequate.
Since we want the probability of X > 12, we can subtract the CDF from 1 to obtain the probability:

P(X > 12) = 1 - CDF(12)

After calculating the CDF with the given parameters, you'll obtain the probability that the power supply will be inadequate on any given day.

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The value of Cos K as a fraction in simplest terms is K= 42.3⁰

Pythagoras Theorem states that “In a right-angled triangle”, “the square of the hypotenuse side is equal to the sum of squares”. This theorem can be used to derive the base, perpendicular and hypotenuse formulas

CosK = Adj/Hypo

where the Adj = ?

Hypo = 12 Using pyth. rule to find adj

12² = (√51)² + x²

= 144 = 51 + x²

144-51 = x²

93 = x²

x = √93 = 9.6

Then Applying CosK = Adj/Hypo

CosK = √51/9.6

Cos K = 7.1/9.6

Cosk = 0.7396

Making K the subject of the relation we have

K = cos⁻0.7396

K= 42.3⁰

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The value of the unknown angle is 40⁰

A chord of a circle is a straight line segment whose endpoints both lie on a circular arc. If a chord were to be extended infinitely on both directions into a line, the object is a secant line. More generally, a chord is a line segment joining two points on any curve

In geometry, a circular segment (symbol:  also known as a disk segment, is a region of a disk which is "cut off" from the rest of the disk by a secant or a chord.

Circle theorems are properties that show relationships between angles within the geometry of a circle. We can use these theorems along with prior knowledge of other angle properties to calculate missing angles, without the use of a protractor. This has very useful applications within design and engineering.

Angles in the same segment are equal

The two angles marked are seen to be in the same segment and as such they are equal angles

The value of each of the angles is 40⁰

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(a) The function f(x) = 0.2, 1 < x < 6 is a probability distribution function (pdf) because it is non-negative for all x in its domain and the total area under the curve is equal to 1.

(b) The cumulative distribution function (cdf) F(x) for 1 < x < 6 is given by F(x) = 0.2(x-1), where F(x) = 0 for x ≤ 1 and F(x) = 1 for x ≥ 6.

(c) The probability P(2 < X < 4) is 0.4, which can be calculated by integrating the pdf f(x) = 0.2 over the interval [2, 4].

(d) The probability P(X > 4) is 0.6, which is obtained by subtracting the cumulative probability F(4) = 0.2(4-1) from 1.

(a) To show that f(x) = 0.2, 1 < x < 6 is a probability distribution function (pdf), we need to show that:

f(x) is non-negative for all x in its domain: f(x) = 0.2 is non-negative for all x between 1 and 6.

The total area under the curve of f(x) is equal to 1:

∫1^6 0.2 dx = 0.2(x)|1^6 = 0.2(6-1) = 1

Since both conditions are satisfied, f(x) is a pdf.

(b) The cumulative distribution function (cdf) F(x) is given by:

F(x) = ∫1^x f(t) dt

For 1 < x < 6, we have:

F(x) = ∫1^x 0.2 dt = 0.2(t)|1^x = 0.2(x-1)

For x ≤ 1, F(x) = 0, and for x ≥ 6, F(x) = 1.

(c) P(2 < X < 4) is given by:

P(2 < X < 4) = ∫2^4 f(x) dx = ∫2^4 0.2 dx = 0.2(x)|2^4 = 0.4

(d) P(X > 4) is given by:

P(X > 4) = 1 - P(X ≤ 4) = 1 - F(4) = 1 - 0.2(4-1) = 0.6

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[tex] \sqrt{ \frac{3 - 1}{5} } = \sqrt{ \frac{2}{5} } = \frac{ \sqrt{2} }{ \sqrt{5} } = \frac{ (\sqrt{2} )}{ (\sqrt{5}) } \frac{( \sqrt{5})}{ (\sqrt{5} )} = \frac{ \sqrt{10} }{5} [/tex]

The answer is V10/5

The cost per widget based on the given data is decreasing by $0.616 for every one-unit increase in volume, and the predicted cost when volume is zero is $36.94.

To determine the cost per widget based on the given data, we need to find the slope of the regression line. The slope of the regression line represents the change in cost for a one-unit change in volume.

We can use the formula for the slope of the regression line:

slope = r(Sy/Sx)

where r is the correlation coefficient, Sy is the standard deviation of Y (cost), and Sx is the standard deviation of X (volume).

From the given data, we can calculate the following:

r = -0.75 (negative correlation between cost and volume)

Sy = 4.5 (standard deviation of cost)

Sx = 5.5 (standard deviation of volume)

Substituting these values into the formula for slope, we get:

slope = -0.75(4.5/5.5) = -0.616

Therefore, the cost per widget is decreasing by $0.616 for every one-unit increase in volume.

To find the actual cost per widget, we need to look at the intercept of the regression line. The intercept represents the predicted cost when volume is zero.

We can use the formula for the intercept of the regression line:

intercept = y - slope(x)

where y is the mean of Y (cost), slope is the slope of the regression line, and x is the mean of X (volume).

From the given data, we can calculate the following:

y = $10.50 (mean of cost)

x = 40 (mean of volume)

Substituting these values into the formula for intercept, we get:

intercept = 10.50 - (-0.616)(40) = $36.94

Therefore, the cost per widget is approximately $36.94 when volume is zero.

In summary, the cost per widget based on the given data is decreasing by $0.616 for every one-unit increase in volume, and the predicted cost when volume is zero is $36.94.

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Farah's team runs a total of 3.2 kilometers in the relay race.

We have,

First, let's start with the number of laps each student runs:

2 laps per student x 4 students

= 8 laps in total

Next, let's convert the number of laps to the total distance:

8 laps x 400 meters per lap = 3200 meters

Finally, let's convert the distance from meters to kilometers:

3200 meters ÷ 1000 meters per kilometer

= 3.2 kilometers

Thus,

Farah's team runs a total of 3.2 kilometers in the relay race.

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Given the set 5, 8, 8, 8, 8, 9, 9, 9,  10, & 10. Calculate the mean which is the average of a given data set.

[tex]\bold{Mean}=\frac{Sum \ of \ all \ Data \ Points }{The \ Amount \ of \ Data \ Points \ you \ have}[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

[tex]\bold{Mean}=\frac{5+8+8+8+8+9+9+10+10 }{10}[/tex]

[tex]\Longrightarrow \bold{Mean}=\frac{75 }{10}[/tex]

[tex]\Longrightarrow \bold{Mean}=7.5[/tex]

[tex]\Longrightarrow \boxed{\bold{Mean} \approx 8} \therefore Sol.[/tex]

A X-squared goodness-of-fit test is performed on a random sample of 360 individuals to see if the number of birthdays each month is proportional to the number of days in the month. X-squared is determined to be 23.5. The P -value for this test is between d) 0.010 < P < 0.025

In this scenario, a X-squared goodness-of-fit test is performed to determine if the number of birthdays each month is proportional to the number of days in the month. With a random sample of 360 individuals and a χ-squared value of 23.5, you need to find the corresponding P-value range.

To find the P-value range, you can use a χ-squared distribution table or calculator. Since there are 12 months in a year, the degrees of freedom for this test will be 12 - 1 = 11.

Upon checking the table or using a calculator, you will find that the P-value for this test is between:

Your answer: d) 0.010 < P < 0.025

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To the nearest tenth of a mile, Mr. Miller can see 9.8 miles of the horizon along the arc of his field of vision.

Based on the given information, we can use the formula for the arc length of a circle to find how much of the horizon Mr. Miller can see within his field of vision.

The formula for the arc length of a circle is:

arc length = (angle/360) x 2πr

where angle is the central angle of the arc in degrees, r is the radius of the circle, and 2πr is the circumference of the circle.

In this case, the central angle of the arc is 140 degrees, and the radius of the circle is the distance to the horizon, which is 4 miles. We can substitute these values into the formula:

arc length = (140/360) x 2π x 4

arc length = 0.388 x 8π

arc length = 9.8 miles

Therefore, to the nearest tenth of a mile, Mr. Miller can see 9.8 miles of the horizon along the arc of his field of vision.

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