Rutherford's scattering experiment demonstrated that the mass of an atom was uniformly distributed throughout its volume this statement is incorrect.
Hence, Option B is correct answer.
What is Rutherford's Scattering Experiment ?Rutherford's Alpha Scattering Experiment demonstrated that Rutherford bombarded most of the alpha particles passed straight through the gold foil. Rutherford observed that most part of the atom is empty.
What is Thomson Atomic Model ?The mass of an atom was uniformly distributed throughout its volume this experiment was given by Thomson Model.
Thus from the above conclusion we can say that Rutherford's scattering experiment demonstrated that the mass of an atom was uniformly distributed throughout its volume this statement is incorrect.
Hence, Option B is correct answer.
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Which state of matter is being described below? it can be squashed easily, spreads out slowly, has low density,
Answer:
liquid
Explanation:
Gas has very low density but spreads fast. Solid has high density.
When nahco3 completely decomposes, it can follow this balanced chemical equation: 2nahco3 → na2co3 h2co3 determine the theoretical yields of each product using stoichiometry if the mass of the nahco3 sample is 3.80 grams. (show work for both) in an actual decomposition of nahco3, the mass of one of the products was measured to be 2.36 grams. identify which product this could be and justify your reasoning. calculate the percent yield of the product identified in part b. (show your work)
Theoretical yield = 2.397
The product could be sodium carbonate
percent yield = 98.456%
When nahco3 completely decomposes, it can follow this balanced chemical equation:
2nahco3 → na2co3 h2co3
If the mass of the NaHCO3 sample is 3.80 g, we must use stoichiometry to calculate the theoretical yields of each of the products.
mass of NaHCO₃ = 3.80 g
molar mass of NaHCO₃ = 84 g/mol
so the no of moles of NaHCO₃ = 3.80/84 = 0.0452 mol
You see, one mole of sodium carbonate and one mole of hydrogen carbonate are produced from two moles of sodium bicarbonate.
so, the no of moles of sodium carbonate = 0.0452/2 = 0.0226 mol
∴ mass of sodium carbonate ( Na₂CO₃) = no of moles of Na₂CO₃ × molar mass of Na₂CO₃
= 0.0226 × 106 ≈ 2.397 g
no of moles of hydrogen carbonate = 0.0452/2 = 0.0226 mol
mass of the hydrogen carbonate ( H₂CO₃) = no of moles of H₂CO₃ × molar mass of H₂CO₃
= 0.0226 × 62 g = 1.401 g
mass of one of the products was measured to be 2.36 g , from above data, we can say it must be sodium carbonate because value is the nearest of 2.397 g.
percentage yield = experimental yield/theoretical yield × 100
here experimental yield of Na₂CO₃ = 2.36 g
and theoretical yield of Na₂CO₃ = 2.397 g
∴ % yield = 2.36/2.397 × 100 ≈ 98.456%
Therefore the percentage yield of the product is 98.456%
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THEIR ANSWER IS RIGTH, ALL THREE PARTS
Theoretical yeild is 2.397, sodium bicarbonate is the possible product I chose, and percent yeild is 98.456
In addition to the use of complex metal hydrides, what other reaction can be used to reduce aldehydes and ketones to alcohols?
The reaction with H₂ & Raney Ni (Catalytic Hydrogenation) can be used to reduce aldehydes and ketones to alcohols.
What is Aldehyde ?An Aldehyde is a functional group which contains the carbonyl group that is -C = O. The structural formula for aldehyde is RCHO.
Reaction of Aldehyde with H₂ & Raney Ni gives Primary alcohol
RCHO + H₂ & Raney Ni → RCH₂OH
What is Ketone ?A Ketone is a functional group which contains the carbonyl group that is -C = O. The structural formula for ketone is RCOR.
Reaction of Ketone with H₂ & Raney Ni gives Secondary alcohol
RCOR + H₂ & Raney Ni → RCH(OH)R
Thus from the above conclusion we can say that The reaction with H₂ , Raney Ni can be used to reduce aldehydes and ketones to alcohols.
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Which reason best explains why both venus' and mars' atmospheres are primarily carbon dioxide, but the earth's is much less than 1arbon dioxide?
Because carbon dioxide dissolves in water and is transported by rain to the surface where it combines with rocks to generate carbonates, the Earth's atmosphere contains significantly less carbon dioxide than Venus's atmosphere.
Why does Earth's atmosphere have so much less carbon dioxide compared to Venus?Since Venus' atmosphere is around 100 times thicker than the earth's and extremely dense. Venus must be sufficiently close to the Sun for the little carbon dioxide in its early atmosphere to have heated the surface and released additional carbon dioxide into the atmosphere. Nitrogen makes up 79% of the atmosphere on Earth, along with oxygen (20%) and a trace amount of other gases including carbon dioxide and water vapor. On Venus and Mars, however, carbon dioxide makes up the majority of the atmosphere.
In Venus's original ocean drained, water vapor molecules were dispersed by ultraviolet light, and hydrogen was released into space. There was no longer any surface water, and the amount of carbon dioxide increased.
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A student weighs out 0. 0422 g of magnesium metal. The magnesium metal is reacted with excess hydrochloric acid to produce hydrogen gas. A sample of hydrogen gas is collected over water in a eudiometer at 32. 0°c. The volume of collected gas is 43. 9 ml and the atmospheric pressure is 832 mmhg. Using the experimentally collected data, calculate r and the percent error.
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The energy of the ground state in the bohr model is -13. 6 ev. the energy of the n = 2 is:_______
Bohr's model explained the position of the electron, proton, and neutron in the atom of the element. The energy at the n = 2 level of the atom will be - 3.40 eV.
What is the principal quantum number (n)?The principal quantum number (n) has been the distance of the electron of that atom in the nucleus and its energy in the structure. It can also be said to define the size of the atomic orbit.
n = 2 is the first excited state whose energy is calculated as:
Eₙ = − 13.6 ÷ n² eV
E₂ = - 13.6 eV ÷ 2²
= -3.40 eV
Therefore, -3.40 eV is the energy of electron at n = 2.
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how to build 6 individual atoms?
The 6 models of the atom:
1. John Dalton's atomic model: Daltons Billiard Ball (Solid Sphere) Model
2. J.J. Thomson's model: Plum Pudding model
3. Ernest Rutherford's model: Nuclear model
4. Niels Bohr's model: Planetary model
5. Erwin Schrdinger's model: Electron Cloud Model/Quantum Model
6. Wave mechanical model
AtomThe smallest component that makes up a chemical element is an atom. Atoms that are neutral or ionized are the building blocks of all solids, liquids, gases, and plasma. A normal atom is 100 picometers across, which is incredibly small. Because of quantum effects, they are so small that it is impossible to predict their behavior with sufficient precision using classical physics, as if they were, say, tennis balls. One or more electrons are attached to the nucleus of every atom, which is made up of a nucleus. Protons and neutrons, in various numbers, make up the nucleus. Neutrons exist only in the most prevalent type of hydrogen. An atom's nucleus makes up more than 99.94% of its mass.
how to build 6 individual atoms?
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What mass of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.
91.4 grams
91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.
C = mol/volume
2.45M=mol/0.5L
2.45M⋅0.5L = mol
mol = 1.225
Convert no. of moles to grams using the atomic mass of K + Cl
1.225mol * [tex]\frac{39.1+35.5}{mol}[/tex]
mol=1.225
=1.225 mol . [tex]\frac{74.6g}{mol}[/tex]
=1.225 . 74.6
=91.4g
therefore, 91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.
What is 1 molar solution?
In order to create a 1 molar (M) solution, 1.0 Gram Molecular Weight of the chemical must be dissolved in 1 liter of water.
58.44 g make up a 1M solution of NaCl.
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Calculate the ph at the equivalence point for the titration of 0. 22 m hcn with 0. 22 m naoh. (ka = 4. 9 × 10^–10 for HCN).
The pH at the equivalence point for the titration of 0. 22 m HCN with 0. 22 m NaOH is 11.17
Calculation,
Concentration of NaCN = 0. 22 m/ 2 = 0.11 M ( at equal volumes of acid and base will be used).
The equilibrium is ,
HCN +[tex]H_{2} O[/tex] → [tex]H^{+} + CN^{-}[/tex]
C(1-x) Cx Cx
Where x , is the degree of hydrolysis and
[tex]K_{h}[/tex] = C[tex]x^{2}[/tex]/(1-x)
We know that [tex]K_{h}[/tex] = [tex]K_{w}/K_{a}[/tex] = 1 ×[tex]10^{-14}[/tex]/4. 9 ×[tex]10^{-10}[/tex] = 2.04×[tex]10^{-5}[/tex]
[tex]K_{h}[/tex] = C[tex]x^{2}[/tex] = 2.04×[tex]10^{-5}[/tex] = 0.11 M×[tex]x^{2}[/tex]
[tex]x^{2}[/tex] = 2.04×[tex]10^{-5}[/tex]/0.11 M
x = 1.36×[tex]10^{-2}[/tex]
[tex][OH^{-} ][/tex] = Cx = 1.36×[tex]10^{-2}[/tex] × 0.11 M = 0.15×[tex]10^{-2}[/tex]
[tex][H^{+} ][/tex] = 1 ×[tex]10^{-14}[/tex]/ 0.15×[tex]10^{-2}[/tex] = 6.66×[tex]10^{-12}[/tex]
pH = -㏒[tex][H^{+} ][/tex] = -㏒6.66×[tex]10^{-12}[/tex] = 11.17
The pH at the equivalence point for the titration is 11.17.
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What would the corresponding
concentration values of OH- be for
the pH values: 1, 3, 5, 7, 9, 11?
The corresponding concentration values of OH⁻ for the pH values
of following are -
1- 10⁻¹
3- 10⁻³
5- 10⁻⁵
7- 10⁻⁷
9- 10⁻⁹
11- 10⁻¹¹
What do you mean by the pH value ?
pH is a logarithmic measure of the hydrogen ion concentration of an aqueous solution pH = -log[H+]
pH describes how acidic or basic an aqueous solution is, where a pH below 7 is acidic and a pH greater than 7 is basic. pH of 7 is considered neutral .
Functions of OH− :
OH− functions as a base .
Hydroxide is a diatomic anion with chemical formula OH−. It consists of an oxygen and hydrogen atom held together by a single covalent bond, and carries a negative electric charge.
Hence, this way pH values of these concentrations are mentioned .
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Calculate the kf of ag(nh3)2 from ag (aq) e- ⇋ ag(s) e0= 0. 81 v ag(nh3)2 (aq) e- ⇋ ag(s) 2nh3(aq) e0= 0. 39 v enter number as e notation (e. g. 2. 34e6 or 4. 56e-4)
The kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.
What is kf value?kf value can be calculated by dividing the molal concentration with the freezing point of depression.
The reaction are given:
Ag+(aq) + e- ⇋ Ag(s) E0= 0.81 V
Ag(NH₃)₂ +(aq) + e- ⇋ Ag(s) + 2NH₃(aq) E0= 0.37 V
To get Kf of Ag(NH₃)₂ we will rearrange the above written equations
a. Ag +(aq) + e- ⇋ Ag(s) E0= 0.81 V
b. Ag(s) + 2NH₃(aq) ⇋ Ag(NH₃)₂ +(aq) + e- E0= - 0.37 V
Adding equation (a) and equation (b) we will get
Ag +(aq) + 2NH₃(aq) ⇋ Ag(NH₃)₂ + (aq) Eo = 0.81 -0.37 = 0.44 V
By the Ernst equation,
E = E° - 0.0591 logkf
Now Kf is calculated at equilibrium and at equilibrium E = 0,
The number of transfer of electron is 1 ( 1 e-) , n=1
E° = 0.44 V
Substituting all the values in Ernst equation
0 - 0.44 - 0.0591/ 1 logkf
logkf = 0.44/ 0.0591
kf = 10 (0.44/ 0.0591)
Kf = 2.786 x 10⁷
Hence, Kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.
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A student sets up the following equation to convert a measurement.
(The ? stands for a number the student is going to calculate.)
Fill in the missing part of this equation.
Note: your answer should be in the form of one or more fractions multiplied together.
Answer:
[tex]\frac{1,000 g}{1 kg}[/tex] · [tex]\frac{100 cm}{1 m}[/tex]Explanation:
The final answer has a different set of units. In particular, kilograms (kg) changes to grams (g) and meters (m) changes to centimeters (cm). To make this change, you need to multiply the first value by proportions.
When writing these proportions, it is important that they are arranged in a way that allows for the cancellation of units. For instance, since both kg and m are located in the numerator, they must be located in the denominators of the conversions.
Proportions:
1 kg = 1,000 g
1 m = 100 cm
The full expression:
[tex]-4.3*10^4 \frac{kg*m}{s}[/tex] · [tex]\frac{1,000 g}{1 kg}[/tex] · [tex]\frac{100 cm}{1 m}[/tex] = [tex]?\frac{g*cm}{s}[/tex] ^ ^As you can see, the old units cancel out and you are left with g and cm in the numerator.
If the ph at the half-titration point of a monoprotic weak acid is 4. 2, what is the ka of the acid?.
The ka of the acid will be-
Ka=2.1106Finding the ka of the acid-The notion is that the pH of the solution will be equal to the pKa of the weak acid at the half-equivalence point.You know that at the equivalence point, the strong base will totally neutralize the weak acid if you're titrating a weak monoprotic acid, which I'll refer to as HA.HA(aq)+OH−(aq)→A−(aq)+H2O(l)
Therefore, upon adding an equal number of moles of a weak acid and strong base, all of the weak acid's moles will be consumed, leaving you with A, the weak acid's conjugate base.At this point, you have added enough moles of the strong base to neutralize half of the weak acid molecules in the solution. This is known as the half equivalence point.The weak acid, the strong base, and the conjugate base are all in 1:1 mole ratios, indicating that what you consume from the weak acid and the strong base, you make as the conjugate base. The reaction will use half of the moles of the weak acid and produce just as many moles of the conjugate base.As a result, the solution will contain an equal number of moles of the weak acid and its conjugate base at the half equivalence point, indicating that you are now working with a buffer solution.As you are aware, the Henderson-Hasselbalch equation pH=pKa+log can be used to calculate the pH of a weak acid-conjugate base buffer ([conjugate base][weak acid])You have the half-equivalence point when
[HA]=[A−]
it suggests that
log([HA][A−])=log(1)=0
As a result, it can be said that the pH of the solution and the pKa of the weak acid are equivalent at the half-equivalence point.
At the halfway point of equivalence: pH=pKa
The acid dissociation constant of the weak acid, Ka, determines the pKa. pKa=log(Ka), which indicates that Ka=10pKa.
Ka=10pH will be present when the two points are half equal.
Enter your value to determine Ka=105.67=2.1106.
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How many electrons are present in the nonbonding π molecular orbital of the allyl anion? a. 2 b. 1 c. 3 d. 0
The number of electrons, which are present in the nonbonding π molecular orbital of the allyl anion is "0".
Anions, cations, but also allylic radicals have always been frequently mentioned as reaction intermediates. Each one has three adjacent [tex]sp^{2}[/tex]-hybridized carbon centers, and they all rely on resonance for stability. Two resonance structures would be used to present each species, with the charge as well as unpaired electron scattered across both the 1,3 and 0 positions.
The Aufbau principle states that these orbitals would fill up based on the order of stability, therefore a typical pi bond, will have 2 electrons in the Pi orbital as well as zero in the Pi* orbital.
Therefore, the correct answer will be option (d)
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Benzoic acid is a common food preservative. the pka of benzoic acid is 4. 20. what is true of the relative strengths of benzoic acid (ba) and its conjugate base (b-)?
Here BA is benzoic acid and B- is conjugate base;
BA is weaker than B- because the Ka < Kb
--> BA is stronger than B- because the Ka > Kb
BA is stronger than B- because the Ka < Kb
BA is weaker than B- because the Ka > Kb
A conjugate acid-base pair, according to the Brnsted-Lowry definition of acids and bases, consists of two substances that are distinct only in that they contain a proton (H+). When a proton is supplied to a base, a conjugate acid is created, and vice versa when a proton is taken away from an acid, a conjugate base is created. Yuki Jung was the creator.
The power of an acid (or base) is inversely proportional to the power of its conjugate base (or conjugate acid): The conjugate base of an acid is weaker the stronger it is. The conjugate base of a weaker acid has a stronger base. A pair of chemical species known as conjugate acid and conjugate base exhibit opposing chemical behaviors.
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What is the mass of 4. 00 moles of helium, the gas commonly used to fill party balloons and lighter-than-air ships?
There are TWO isotopes of chlorine. Under normal conditions, chlorine exists as diatomic molecule, Cl₂. The mass of the Cl₂ molecule is the sum of masses of the two atoms in the molecule. The mass spectrum of Cl₂ has three peaks, as shown below. From this data, what is the mass of the heavier isotope of chlorine (in amu)?
Peak 1- 69.938 amu
Peak 2- 71.935 amu
Peak 3- 73.932 amu
The the mass of the heavier isotope of chlorine (in amu) is 73.932 amu.
What are isotopes?The term isotopes refers atoms that have the same atomic number but different mass number. We must know that all these atoms belong to the same element an differ only in the number of neutrons present in the atom of the element. Hence isotopes are different atoms of the same element hence they have the same chemical properties or reactivity. The mass spectrum is able to show the masses of each of the isotopes according to their order of relative abundance in nature.
Looking at the peaks, we know that the heaviest isotope is the one whose mass will have the highest peak as shown in the mass spectrum of the element as shown. Thus, the the mass of the heavier isotope of chlorine (in amu) is 73.932 amu. The mass spectrum of element also shows this fact.
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Student e accounted for the equivalent weight found for succinic acid by analyzing its titration with naoh(aq) and concluding that it is:________
Student e accounted for the equivalent weight found for succinic acid by analyzing its titration with [tex]NaOH[/tex] (aq) and concluding that it is diprotic.
One mole of succinic acid required two mole of base to neutralize completely. In this titration phenolphthalein indicator is used to observe the completion of the reaction. In an aqueous solution, succinic acid readily ionize to form succenate. Succinic acid undergoes two successive deprotonation reaction.
The succinic acid results in succinate ( dicarboxylic acid dianion ) which is form by removal of a proton from both carboxy groups of succinic acid.
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A dark purple liquid is diluted by adding water.
The diluted liquid becomes a pale purple colour.
Explain the process that causes this change.
Refer to particles in your answer
Answer: The process is diffusion.
Explanation:
a dark liquid will have the highest concentration of dark purple atoms/molecules so it gives a concentrated colour.
when water is added to it, the colourless water molecules fill up the gaps between the purple particles and so their colour fades and becomes lighter and lighter as we add more water. see the image attached where imagine the red particles are water and the blue particles are purple particles. thats why the colour fades.
carbon 4+ ion protons neutrons electrons
Answer 6
Explanation: That means a carbon atom has 6 protons, 6 neutrons, and 6 electrons.
At what temperature will he atoms have the same crms value as N2 molecules at 25°c?
At -230 °C temperature will He atoms have the same rms value as [tex]N_{2}[/tex] molecules at 25°C .
Calculation ,
Given temperature = 25°C = 25+273 = 298 K
[tex]V_{rms}[/tex] =√3RT/M
[tex]V_{rms}[/tex] =√3R[tex]T_{1}[/tex]/[tex]M_{He}[/tex] ......( i )
[tex]V_{rms}[/tex] =√3R[tex]T_{2}[/tex]/[tex]M_{N_{2}[/tex] ......( ii )
Equalize equation ( i ) and ( ii )
√3R[tex]T_{1}[/tex]/[tex]M_{He}[/tex] = √3R[tex]T_{2}[/tex]/[tex]M_{N_{2}[/tex]
[tex]T_{1}[/tex]/[tex]M_{He}[/tex] = [tex]T_{2}[/tex]/[tex]M_{N_{2}[/tex]
[tex]T_{1}[/tex] = [tex]M_{He}[/tex] × [tex]T_{2}[/tex]/[tex]M_{N_{2}[/tex] = 4 ×298 K/28 = 42.57 K
Temperature in°C = 42.57 - 273 = -230 °C
Therefore , at -230 °C temperature will He atoms have the same rms value as [tex]N_{2}[/tex] molecules at 25°C .
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A pharmaceutical company wants to test the efficiency of its new drug production techniques so they run 3 shifts of production for 4 hours each and collect the product at the end of each shift. Their chemical engineers predict a maximum of 7000 grams of product can be created each shift. Shift one produces 4562 grams. Shift two produces 5783 grams. Shift three produces 5247 grams. What is the average percent yield for this new production technique?
The percentage yield of the new production technique is 82.8%
What is the percentage yield?Production is the procedure by which finished products are obtained form the raw materials. The production process involves the passing of raw materials through a certain procedure that involves the use of certain machines and equipment to give us the required products.
We are told in the question that there are three shifts;
Shift 1 produces 4562 grams
Shift 2 produces 5783 grams
Shift 3 produces 5247 grams
Average production from the three shifts = 4562 grams + 5783 grams + 5247 grams/3 = 5197 grams
The theoretical average yield is = 7000 grams + 7000 grams + 7000 grams/3 = 7000 grams
Now the percentage yield = actual yield/ theoretical yield * 100/1
percentage yield = 5197 grams/7000 grams * 100/1
percentage yield = 82.8%
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How many molecules are in 1.75 mol of CHCl3
Answer:
1.0535×10(exponent24)
Explanation:
N (number of molecules)
n(number of moles)
L( Avogadro's constant )
N=n×L
N=1.75×6.02×10(exponent 23)
Explanation:
In one mole we always have:
1 mol = 6.02 X 10²³ molecules
So emulates simple rule of 3 we will have;
1 mol ----------> 6.02 X 10²³
1.75 moles ----> X
X = 1.0535 X 10²⁴ molecules
Hope this helps, Good studies!
What is the percent by volume of ethanol in gasohol when 95 ml of ethanol is added to sufficient gasoline to make 1.0 l of gasohol?
The percentage of volume of ethanol is 9.5%.
What is volume by volume percentage?Volume/volume percentage (v/v% or percent v/v) is a unit used to express how much of a material is present in a solution. It is defined as the volume of the solute divided by the sum of the volumes of the solution, multiplied by one hundred. Examples: The average alcohol concentration (v/v%) of wine is 12 percent.
The formula used to get the volume of ethanol in percentages is
Percent of volume of ethanol = (volume of solute / total volume) * 100
Percent volume of Ethanol = (volume of ethanol / total volume) * 100
= 95mL / 1000mL * 100
= 9.5%
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Please help,
How could you tell a Ca(NO3)2 solution from a Zn(NO3)2 solution?
Answer:
you better give me brainliest
Explanation:
Zinc nitrate and calcium nitrate solution can be distinguished by reaction with ammonium hydroxide. Zinc forms a white gelatinous ppt. whereas there is no precipitation of calcium hydroxide even with excess of ammonium hydroxide
The best way to differentiate chart elements is by using _____.
i. colors
b. labels
c. bubbles chart
d. titles
The best way to differentiate chart elements is by using labels.
So, option B is correct one.
The table should be used when
The reader needs to refer to specific numerical values.The reader needs to make precise comparison between different values and not just relative comparisons.The values being displayed have different displayed have different units or very different magnitudes.The column chart is probably the most used chart type. This chart best used to compare different values when specific values are important.
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Assuming an experimental value of enthalpy of –655 kj/mol and a true value of –603, what is the percent error of the experiment? use a calculator and round to the nearest hundredth as well as the absolute value of the percentage. %
8.62%
8.62% is the percent error of the experiment.
Rounding to the nearest hundredth value will be 8.620.
Determine the difference between the figures provided and divide by the actual value to find the percent error.(-655 - -603)/(-603) = 0.0862
Multiply by 100%,
(0.0862) x 100% = 8.62%
What is percent error?The percent error is the difference between the estimated value and the actual value in relation to the actual value.
What does percent error enable us to establish?Error margins are easily understood when expressed as a percentage. It reveals the size of the inaccuracy. A 3-percent error value, for example, indicates that your measured number is quite near to the true amount. A 50% margin, however, indicates that your measurement is far from the true number.The significance of percentage errorWhen you measure something in an experiment, the percentage of mistakes indicates the size of your errors. Greater proximity to the accepted or genuine value is indicated by smaller values.To learn more about percent error visit:
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The oxygen consumption rate of a 200 kg seal is 10 ml/(g h). assuming that it has oxygen stores of 2 liters, how many minutes can it dive before running completely out of oxygen?
The oxygen consumption rate of a 200 kg seal is 10 ml/(g h). If it has oxygen stores of 2 liters, then minutes can it dive before running completely out of oxygen is 0.06min.
What is meant by oxygen consumption?Oxygen is one of the most vital element of the organism which is required by almost all the cellular and for all metabolic activities to perform body function.
It is consumed by the respiratory system and passed ro each cell by circulatory system of the body.
Given,
Mass of seal = 200kg = 200000 g
Rate of oxygen consumption = 10 ml/gh
The volume of stored O2 = 2000mL
The time of consumption is calculated as
t = V/mr
t = 2000/200000×10
t = 0.001 hrs
In minutes
t = 0.06min.
Thus 0.06min is required to dive out the oxygen stores of 2 litre.
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Please help.. I'm Giving Brainliest :)
Answer:
i think its -91.6
Explanation:
2 ( - 950.8) - (( - 1130.7) + ( - 393.5) + ( - 285.8))
The standard enthalpy change for the given reaction is approximately 91.9 kJ mol⁻¹.
The heat produced during a chemical reaction under specific conditions is known as the standard enthalpy change, abbreviated as H° (zero delta H). Standard conditions often refer to all reactants and products in their standard states, which are their most stable forms at 298 K and 1 bar (or 1 atm) pressure.
Hess's law, which states that the total enthalpy change of a reaction is equal to the sum of the enthalpy changes of its component phases, is used to calculate the standard enthalpy change of the reaction.
The following reaction is given:
[tex]\rm 2 NaHCO_3(s)--- > Na_2CO_3(s)+ CO_2(g) + H_2O(l)[/tex]
The relevant enthalpy changes of formation are:
ΔH°[NaHCO3(s)] = -950.8 kJ mol⁻¹
ΔH°[Na2CO3(s)] = -1130.7 kJ mol⁻¹
ΔH°[CO2(g)] = -393.5 kJ mol⁻¹
ΔH°[H2O(l)] = -285.8 kJ mol⁻¹
By using Hess's Law, the standard enthalpy change (ΔH°) for the reaction can be calculated as follows:
ΔH° = Σ (products) - Σ (reactants)
ΔH° = [ΔH°[[tex]\rm Na_2CO_3[/tex](s)] + ΔH°[[tex]\rm CO_2[/tex](g)] + ΔH°[H2O(l)]] - [2 × ΔH°[[tex]\rm NaHCO_3[/tex](s)]]
ΔH° = [-1130.7 kJ mol⁻¹ + (-393.5 kJ mol⁻¹) + (-285.8 kJ mol⁻¹)] - [2 × (-950.8 kJ mol⁻¹)]
ΔH° = [-1809.7 kJ mol⁻¹] - [-1901.6 kJ mol⁻¹]
ΔH° ≈ -1809.7 kJ mol⁻¹ + 1901.6 kJ mol⁻¹
ΔH° ≈ 91.9 kJ mol⁻¹
Hence, the standard enthalpy change for the given reaction is approximately 91.9 kJ mol⁻¹.
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At 2525 °c, what is the hydroxide ion concentration, [oh−][oh−] , in an aqueous solution with a hydrogen ion concentration of [h ]=1. 5×10−6[h ]=1. 5×10−6 m?
The hydroxide ion concentration [OH-] in an aqueous solution is 6.66 x 10⁻⁹ M
Experimental measurements of the pKw of water at 25ºC yielded a result of 14.0. The same method used to determine the pKa of all other water-soluble compounds that can function as acids in aqueous solution can also be used to determine this value from the examination of thermodynamic or electrochemical data for these aqueous solutions.
Water has a pkw=14
So it can be represented as,
[H+] [OH-] = 1×10^-14
Given [H+] = 1. 5×10^−6
So, [OH-] = (1*10^-14) / ( 1.5*10^-6)
= 6.66 x 10⁻⁹ M
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