S is a subset within a universal set, U
If S = {x, y, 4, 9, ?}, which could
describe U?

U = {keys on a keyboard}
U = {letters}
U = {numbers}
U = {punctuation marks}

Answers

Answer 1
Keys on a keyboard because it can’t be letters because there are numbers and punctuation marks, it can’t be numbers because there are letters and punctuation marks, it can’t be punctuation merks either cause there are letters and numbers. So the only option left is keys on a keyboard cause it has all letters numbers and punctuation marks
Answer 2

The solution is,  U={ keys on a keyboard}, could describe U .

What is set?

A set is the mathematical model for a collection of different things; a set contains elements or members, which can be mathematical objects of any kind: numbers, symbols, points in space, lines, other geometrical shapes, variables, or even other sets.

Here, we have,

S is a subset of U,

so all of the elements of S must be also elements of U

If U was {letters}, 4, 9, ? would not belong there

If U was {numbers }, x, y, ? would not belong to U

If U was {punctuation marks }, 4, 9, x, y would not be in U

all the elements of S are in U={ keys on a keyboard}

Answer:  U={ keys on a keyboard}, could describe U.

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Related Questions

How many solutions, in positive integers less than 10, does the equation x + y + z = 20
have?

Answers

[tex]\huge \mathbb{ \underline{EXPLANATION:}}[/tex]

Given:

[tex] \bold{\: x + y + z = 20}[/tex]

[tex]\\[/tex]

As we have a [tex]\small\bold{sum \: of \: three \: integers}[/tex] equal to 20 and less than 10, we know the integers have to be between 2 and 9 (1 and 0 don't apply because the sum wouldn't be equal to 20 between three integers.

[tex]\large\tt{Note:}[/tex]

The first value would be X value, second Y value and third Z value.

[tex]\huge \mathbb{ \underline{ANSWER:}}[/tex]

[tex] \large\boxed{ \sf 36 \: solution}[/tex]

please help me!

A scientist is comparing the bacteria population on two surfaces t days after it is cleaned with bleach.

Bacteria on the kitchen counter is initially measured at 5 and doubles every 3 days.

Bacteria on the stove is initially measured at 10 and doubles every 4 days.

1. After how many days will the bacteria population on both surfaces be equal?
2. What is the bacteria population when both surfaces have an equal population?

Answers

Answer:

They are only equal on day 0, both having 10 population.

Step-by-step explanation:

Given the bacteria on the counter is initially measured at 5 and doubles every 3 days we can generate the following geometric equation:

[tex]f(x)=10*2^{\frac{x}{3} }[/tex]

Given the bacteria on the stove is measured at 10 and doubles every 4 days we can create another equation:

[tex]f(x)=10*2^{\frac{x}{4} }[/tex]

To find how many days it will take for the bacteria population to equal the same lets set both equations equal to eachother:

[tex]10*2^{x/3}=10*2^{x/4}[/tex]

Divide both sides by 10

[tex]2^{x/3}=2^{x/4}[/tex]

Since both exponents have the same base we can set the exponents equal to eachother and solve for x:

[tex]\frac{x}{3}=\frac{x}{4}[/tex]

Multiply both sides by 3 to isolate x on the left side

[tex]x=\frac{3x}{4}[/tex]

Multiply both sides by 4 to remove fraction

[tex]4x=3x[/tex]

Subtract 3x to isolate x on the left side

[tex]x=0[/tex]

Plug x into one of our original equations

[tex]f(0)=10*2^{0/3}[/tex]

Solve

[tex]f(0)=10[/tex]

HELP ME ASAP........

Answers

The sample at option B, {0, 2} is not a part of the sample space of a spinner when spun two times.

What is a sample space?

The set consists of all the possible outcomes of an event called sample points, which is said to be a sample space.

Calculation:

It is given that,

a spinner has 5 sections of equal area and each section is numbered from 1 to 5.

If the spinner is spun two times, then the possible outcomes are 25. They are:

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5)}

So, from the given options, the sample {0, 2} is not possible since there is no such a section on the spinner named 0.

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find the area of the shaded region!
please solve this with solutions !ASAP​

Answers

the area of the shaded part is 30. 89 cm²

How to determine the area

We have the shape to be a rectangle

The area of the shaded part should be;

Area of rectangle - 2 ( area of a semi circle)

The formula for area of a rectangle

Area = length × width

Area = 12 × 12

Area = 144 cm²

Area of a semicircle = 1/2 πr²

Area = 1/ 2 × 3. 142 × 6²

Area = 56. 56 cm²

Area of shaded part = area of rectangle - 2( area of semicircle)

Area of shaded part = 144 - 2(56. 56)

Area of shaded part = 144 - 113. 11

Area of shaded part = 30. 89 cm²

Thus, the area of the shaded part is 30. 89 cm²

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una liebre avanza 18 saltos, retrocede 5 saltos y avanza 9 saltos y finalmente retrocede 6 saltos ¿Cuántos saltos da en total la liebre ?

Answers

Así, concluimos que la liebre da un total de 38 saltos.

¿Cuántos saltos da en total la liebre ?

Notar que solo se nos pregunta cuantos saltos da la Liebre, no importa en que dirección son dichos saltos.

Entonces solo debemos sumar todos los números de saltos que se nos dan, esto es:

18 saltos + 5 saltos + 9 saltos + 6 saltos = 38 saltos.

Así, concluimos que la liebre da un total de 38 saltos.

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A rope that is 245cm long is cut into three pieces. The ratio of the lengths of the first piece to the second piece is 2/3, and the ratio of the lenghts of the second piece to the third piece is 4/5. What is the length of the longest of the the three pieces?

Answers

The length of the longest piece of the cut rope is; 105 cm

How to work with ratios?

We are given that;

Length of rope = 245 cm

We need to make the ratio of second piece equal in both the ratio to find the ratio of all three pieces.

2:3

4:5

Multiply 1st ratio by 4 and 2nd ratio by 3:

Now, the ratio becomes: 8:12 and 12:15

And the ratio of three pieces can be represented as:

8: 12: 15, this ratio is the first piece: second piece: third piece

Thus;

8x + 12x + 15x = 245

35x = 245

x = 245/35

So, the pieces lengths will be;

First piece = 8 * 7 = 56 cm

Second piece = 12 * 7 = 84 cm

Third piece = 15 * 7 = 105 cm

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Construc t a 95% confidence interval for the population standard deviation σ of a random sample of 15 men who have a mean weight of 165.2 pounds with a standard deviation of 13.5 pounds. assume the population is normally distributed

Answers

The 95% confidence interval for the population standard deviation will be,

[tex]$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\[/tex]

simplifying the equation, we get

[tex]$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288[/tex]

The 95% confidence interval exists (9.887, 21.288).

What is the  95% of confidence interval?

A random sample of 15 men exists selected. The mean weight exists at $165.2 pounds and the standard deviation exists at $13.5 pounds. The population exists normally distributed.

So, [tex]$n=15, \bar{X}=165.2, s=13.5$[/tex]

where n exists the sample size, [tex]$\bar{X}$[/tex] exists the sample size

s exists the sample standard deviation.

The degrees of freedom will be n - 1 i.e.15 - 1 = 14.

For a 95% confidence interval, the level of significance will be [tex]$\alpha=0.05$[/tex].

The 95% confidence interval for the population standard deviation will be,

[tex]$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\[/tex]

substitute the values in the above equation, we get

[tex]$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi^{2}} 0.05} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0}^{2}}} \\[/tex]

[tex]$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.975}^{2}}} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.025}^{2}}} \\[/tex]

simplifying the above equation, we get

[tex]$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288[/tex]

The 95% confidence interval exists (9.887, 21.288).

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Given: Circle M with inscribed Angle K J L and congruent radii JM and ML
Prove: mAngle M J L = One-half (measure of arc K L)

Circle M is shown. Line segment J K is a diameter. Line segment J L is a secant. A line is drawn from point L to point M.

What is the missing reason in step 8?



Statements

Reasons
1. circle M with inscribed ∠KJL and congruent radii JM and ML 1. given
2. △JML is isosceles 2. isos. △s have two congruent sides
3. m∠MJL = m∠MLJ 3.

base ∠s of isos. △are ≅ and have = measures
4. m∠MJL + m∠MLJ = 2(m∠MJL) 4. substitution property
5. m∠KML = m∠MJL + m∠MLJ 5. measure of ext. ∠ equals sum of measures of remote int. ∠s of a △
6. m∠KML =2(m∠MJL) 6. substitution property
7. Measure of arc K L = measure of angle K M L 7. central ∠ of △ and intercepted arc have same measure
8.

Measure of arc K L = 2 (measure of angle M J L)
8. ?
9.

One-half (measure of arc K L) = measure of angle M J L
9. multiplication property of equality
reflexive property
substitution property
base angles theorem
second corollary to the inscribed angles theorem

Answers

The missing reason in step 8 is the substitution property.

What is substitution property?

It should be noted that according to substitution property, if x = y, then x can be substituted for y in any equation.

When a variable is equal to another variable, then the variables can be interchangeable.

In this case, the missing reason in step 8 is the substitution property.

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I dive to 56 feet for 47 minutes. After a 30 minute surface interval I do a second dive to 56 feet. Losing track of time, I notice my bottom time is now 25 minutes. According to the General Rules, what should I do

Answers

According to general rules, what you can do now is; Ascend right away to 15 feet and stay there for 8 minutes before going to the surface and not dive for 6 hours

How to solve algebra word problems?

We are given;

Initial distance dived = 56 feet

Time for initial dive = 47 minutes

Time from finishing of initial dive to start of second dive = 30 minutes

Second dive distance = 56 ft

Her current bottom time is now 25 minutes

Now, bottom time is defined as the total time, in minutes, from the beginning of a descent to the beginning of an ascent.

Thus, according to general rules, what you can do now is to Ascend right away to 15 feet and stay there for 8 minutes before going to the surface and not dive for 6 hours

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Find an equation of the line perpendicular to y = − 7 8 x + 2 and containing the point (14, − 3)

Answers

Answer:

[tex]y=\frac{-x}{78} -\frac{220}{78}[/tex]

Step-by-step explanation:

Remember to create a line perpendicular to one another the slope has to be the reverse reciprocal of the first line.

Given the current slope is [tex]\frac{-78}{1}[/tex] the new slope would be [tex]\frac{1}{78}[/tex].

To find the line that passes through a point with a given slope we must use point slope form, remember the default equation of point slope form:

[tex]y-y1=m(x-x1)[/tex]

Where y1 is the y value of the point, m is the slope, and x1 is the x value of the point.

Lets substitute in our values

[tex]y-(-3)=\frac{-1}{78} (x-14)[/tex]

Simplify the equation

[tex]y+3=-\frac{1}{78}\left(x-14\right)\\y+3=\frac{-x}{78}+\frac{14}{78}\\y=\frac{-x}{78}-\frac{220}{78}\\[/tex]

i need the answer for number 13

Answers

Answer:

The answer is 1. This table is an example of the principle of independence.

Step-by-step explanation:

This means any Trade activity is performed without reliance on another party.

He got the perfect answer to his question and he can get his answer without any other information.

2x + 1 = 4x - 19
Solve for x

Answers

Answer:

x = 10

Step-by-step explanation:

2x + 1 = 4x - 19

Solve for x

2x + 1 = 4x - 19

2x - 4x = -19 - 1

-2x = -20

x = 20 : 2

x = 10

----------------

check

2 * 10 + 1 = 4 * 10 - 19

21 = 21

the answer is good

Answer: [tex]\Large\boxed{x=10}[/tex]

Step-by-step explanation:

2x + 1 = 4x - 19

Add 19 on both sides

2x + 1 +19 = 4x - 19 + 19

2x + 20 = 4x

Subtract 2x on both sides

2x + 20 - 2x = 4x - 2x

20 = 2x

Divide 2 on both sides

20 / 2 = 2x / 2

[tex]\Large\boxed{x=10}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

How many solutions can be found for the equation 12x 8 = 12x 8? zero one two infinitely many

Answers

Answer:

Infinite

Step-by-step explanation:

12x 8 = 12x 8

Infinitely many solutions, as left side = right side.

Instructions: Determine whether the following polygons are similar.
If yes, type 'yes' in the Similar box and type in the similarity
statement and scale factor. If no, type 'None' in the blanks. For the
scale factor, please enter a fraction. Use the forward dash (i.e. /) to
create a fraction (e.g. 1/2 is the same as
15
B
12
18
G
m
LL
F
N
30
20
M
25

Answers

The angles exist in the exact place in both triangles. So we will obtain the decision that they exist different.

Therefore, the the measure of their angles exists different.

How to define the polygons are similar?

No, because the measure of their angles exists different. If the angle measurements existed the exact, they would have been equivalent.

You see in the smaller triangle, the given angle exists at 55 degrees while in the bigger triangle the given angle exists at 30 degrees.

The angles exist in the exact place in both triangles. So we will obtain the decision that they exist different.

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The Pyramid of Giza is shown. It has a base length of 230 meters and a height of 150 meters.

The Pyramid of Giza is one of the largest pyramid structures still standing in Egypt. It is a right pyramid with a square base, a base length of 230 m, and height of 150 m.

The area of the base is

m2.

The volume is

m3.

Answers

the area and volume of the Pyramid of Gaza are  139, 840 m²

and 52950 m³ respectively.

How to determine the parameters

The formula for volume and area of a square pyramid are given thus;

Volume, V= [tex]a^2\frac{h}{3}[/tex]

Area , [tex]A=a^2+2a \sqrt{\frac{a^2}{4}+ h^2 }[/tex]

Where

a is the base lengthh is the height

Substitute the values;

Area = [tex]230^2 + 2(230) \sqrt{\frac{230^2}{4}+ 150^2 }[/tex]

Area = [tex]52900 + 460 + \sqrt{13225 + 22500}[/tex]

Area = [tex]52900 + 460(189)[/tex]

Area = 52900 + 86, 940

Area = 139, 840 m²

Volume , v = [tex]230^2 + \frac{150}{3}[/tex]

Volume = 52900 + 50

Volume = 52950 m³

Thus, the area and volume of the Pyramid of Gaza are  139, 840 m²

and 52950 m³ respectively.

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answer is in the attachment below

goodluck!!

In the diagram below, if < A = 113°, < B = 39°, < D = 113° and < F = 28°, we can say that___.

Answers

Answer:

c.

Step-by-step explanation:

The two triangles are similar as they have the same angles, though not necessarily the same sides. ASA only applies to congruency.

Assume that the custodian of a $705 petty cash fund has $147. 50 in coins and currency plus $535. 50 in receipts at the end of the month. the entry to replenish the petty cash fund will include:______.

Answers

Answer:

$528
If not then it might be $385

4. Use the following images to answer the question:
a.
Write a truth statement about each
picture using Euclidean postulates.
b. Write the matching Euclidean postulate.
C.
Describe the deductive reasoning you used.

Answers

Truth statement exists statements or assertions that exist true yet of whether the constituent premises exist true or false.

What is the Euclidean Postulate?

There exist five Euclidean Postulates or axioms.

1. Any two ends can be bound by a straight line segment.

2. In a straight line, any straight line segment can be extended indefinitely.

3. A circle can be created utilizing any straight line segment as the radius and one endpoint as the center.

4. Right angles exist all the exact.

5. If two lines meet a third in a manner that the totality of the inner angles on one side exists smaller than two Right Angles, the two lines will inevitably collide on that side if they exist extended far enough.

What are the true statements connecting to the pictures and their equivalent Euclidean Axiom?

1. The right angle on the first page of the book offered and the right angles on the last page of the book shown exist all the exact. (Axiom 4)

2. If the string from the Yoyo dangling from the hand in the picture exists circled for 360° such that the length of the string stays equivalent to all thought, and the point from where it exists attached stays fixed, it will trace a circular trajectory. (Axiom 3)

3. The swords held by the fighters can be extended into infinity because they exist in in straight lines. (Axiom 5)

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match each series with the equivalent series written in sigma notation

Answers

The series and the sigma notations are[tex]\sum\limits^4_0 3(5)^n = 3 + 15 +75 + 375 +1875[/tex], [tex]\sum\limits^4_0 4(8)^n = 4 + 32 + 256+ 2048 + 16384[/tex], [tex]\sum\limits^4_0 2(3)^n = 2 + 6 + 18 + 54 + 162[/tex] and [tex]\sum\limits^4_0 5(3)^n = 5 + 15 + 45 + 135 + 405[/tex]

How to match each series with the equivalent series written in sigma notation?

To do this, we simply expand each sigma notation.

So, we have:

[tex]\sum\limits^4_0 3(5)^n[/tex]

Next, we set n = 0 to 4.

So, we have:

3(5)^0 = 3

3(5)^1 = 15

3(5)^2 = 75

3(5)^3 = 375

3(5)^4 = 1875

So, we have:

[tex]\sum\limits^4_0 3(5)^n = 3 + 15 +75 + 375 +1875[/tex]

[tex]\sum\limits^4_0 4(8)^n[/tex]

Next, we set n = 0 to 4.

So, we have:

4(8)^0 = 4

4(8)^1 = 32

4(8)^2 = 256

4(8)^3 = 2048

4(8)^4 = 16384

So, we have:

[tex]\sum\limits^4_0 4(8)^n = 4 + 32 + 256+ 2048 + 16384[/tex]

[tex]\sum\limits^4_0 2(3)^n[/tex]

Next, we set n = 0 to 4.

So, we have:

2(3)^0 = 2

2(3)^1 = 6

2(3)^2 = 18

2(3)^3 = 54

2(3)^4 = 162

So, we have:

[tex]\sum\limits^4_0 2(3)^n = 2 + 6 + 18 + 54 + 162[/tex]

[tex]\sum\limits^4_0 5(3)^n[/tex]

Next, we set n = 0 to 4.

So, we have:

5(3)^0 = 5

5(3)^1 = 15

5(3)^2 = 45

5(3)^3 = 135

5(3)^4 = 405

[tex]\sum\limits^4_0 5(3)^n = 5 + 15 + 45 + 135 + 405[/tex]

Hence, the series and the sigma notations are[tex]\sum\limits^4_0 3(5)^n = 3 + 15 +75 + 375 +1875[/tex], [tex]\sum\limits^4_0 4(8)^n = 4 + 32 + 256+ 2048 + 16384[/tex], [tex]\sum\limits^4_0 2(3)^n = 2 + 6 + 18 + 54 + 162[/tex] and [tex]\sum\limits^4_0 5(3)^n = 5 + 15 + 45 + 135 + 405[/tex]

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Part B The mass of an average grain of rock salt is about 40 times the mass of an average grain of table salt. If you multiply the mass of table salt in standard notation by 40, what value do you get?​

Answers

Answer:

0.012

Step-by-step explanation:

We know the standard notation of table salt is 0.003, so we simply multiply 40 by this.

answer - 0.0003 X 40 = 0.012

A sine function has an amplitude of 3, a period of pi, and a phase shift of pi/2. What is the y-intercept of the function?
A. 3
B.0
C.-3
D. pi/4

Answers

Based on the calculations, we can logically deduce that the y-intercept of this sine function is equal to: A. 3.

Given the following data:

Amplitude = 3Period = πPhase shift = π/2

How to determine the y-intercept of this function?

Mathematically, a sine function is modeled by this equation:

y = Asin(ωt + ø)

Where:

A represents the amplitude.ω represents angular velocity.t represents the period.ø represents the phase shift.

Also, the period of a sine wave is given by:

t = 2π/ω

2 = 2π/ω

ω = 2

Substituting the given parameters into the equation, we have;

y = 3sin(2t + π/2)

At t = 0, we have:

y = 3sin(2(0) + π/2)

y = 3sin(π/2)

y = 3sin(90)

y = 3 × 1

y = 3.

In conclusion, we can logically deduce that the y-intercept of this sine function is equal to 3.

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Calculate a four-day moving average for the price of the stock for the end of day 7. day 1 - 62.00; day 2 - 56.00; day 3 - 50.00; day 4 - 60.00; day 5 - 59.00; day 6 - 55.00; day 7 - 59.00; day 8 - 63.00

Answers

Answer:

  58.25

Step-by-step explanation:

A "moving average" is a "boxcar average," the unweighted average over the specified number of days.

Solution

The 4-day moving average ending on day 7 is ...

  4-day average = (day 4 +day 5 +day 6 +day 7)/4

  = (60 +59 +55 +59)/4 = 233/4

  4-day average = 58.25

The four-day moving average for the price of the stock for the end of day 7 is 56.00

What is moving average?

The moving average on a particular day  is the average of prices on the days prior to the pricing day.

In other words, four-day moving average on day 7 is the sum the prices of four days prior to day 7 divided by the number of days whose prices were considered.

In computing the four-day moving average for day 7, we would sum the prices for days 3-6, then divide the sum by 4 since prices of 4 days were made use of.

four-day moving average on day 7=(50.00+60.00+59.00+55.00)/4

four-day moving average on day 7= 56.00

Note, as the day of pricing changes, the input prices would also change

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Tanya is 12 years older than Leah. Three years ago, Tanya was five times as old as Leah.
What is the age of Tanya and Leah now?

Answers

Answer:

tanya 22

leah12

Step-by-step explanation:

i hope it

help ...

1. Sandy has 1.45 L of soft drink in a bottle. She pours the soft drink into glasses with capacity of 0.32 L each. At least how many glasses must she use in order to pour all soft drink out of the bottle?

2. A baker has 5.6 kg of flour. Later he buys 2.5 kg of flour. If he needs 0.48 kg of flour to make a dough, then how many doughs can he make with the flour? How much flour remains (in kg)?

Answers

Step-by-step explanation:

1.

how many glasses of 0.32 liter can she fill ?

that means, how often does 0.32 fit into 1.45 ?

that is solved by division :

1.45 / 0.32 = 4.53125

so, she will need at least 5 glasses to completely empty the bottle. the 5th glass will be filled only partly, but that does not matter in that regard.

2.

he has 5.6 kg and adds 2.5 kg. that is 5.6 + 2.5 = 8.1 kg.

1 dough (that means 1 portion of dough as described by his recipe) uses 0.48 kg flour.

how many doughs can he make

so, again, how often does 0.48 fit into 8.1 ?

8.1 / 0.48 = 16.875

he can therefore make 16 full portions of dough. he does not have enough flour for a full 17th.

so, he uses

16×0.48 = 7.68 kg of flour for the 16 doughs.

and he has

8.1 - 7.68 = 0.42 kg of flour left.

Santaniago has a rope that measures 205.95 centimeters.write this number in expanded form

Answers

This number in expanded form 200 + 5 + 5/10 + 9/100  .

What is expanded form in math example?

It means that the expansion of numbers is based on the place value. The expanded form splits the number, and it represents the number in units, tens, hundreds and thousands form. For example, the expanded form of the number 1572 is 1000+500+70+2.

Given  : 205.95 centimeters.

the number in a expanded form.

200 + 5 + 9/10 + 5/100

we have given 205.95 centimeters.

We can see 2 is at hundred place = 200.

0 is at tens place = 00.

5 is at ones place  = 5.

9 after decimal is at tenth place =  [tex]\frac{9}{10}[/tex].

5 is at hundredth place  = [tex]\frac{5}{100}[/tex] .

Therefore , Expanded form : 200 + 5 + 5/10 + 9/100 .

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Find the area of a triangle with base of 10 inches and altitude to the base of 16 inches. 135 in 2 160 in 2 80 in 2

Answers

For a triangle with base of 10 inches and altitude of 16 inches, its area will be 80 in² (third option).

Calculation For the Area of the Triangle:

It is given that,

The base of the triangle, B = 10 inches

The altitude from the base of the triangle or height, H = 16 inches

Now, the formula used for finding the area of a triangle is given as follows,

Area, A = (1/2) × B × H

Substituting the given values of B and H in the above formula for area, we get,

A = (1/2) × (10 inches) × (16 inches)

A = 5 × 16 inches²

A = 80 inches²

Thus, the area of the triangle have base 10 inches and altitude 16 inches is 80 square inches.

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PLS HELP pq has endpoints at p(-5,4) and q(7,-5).what is the midpoint of pq? what are the cordinates of the point 2/3 of the way from p to q?

Answers

The midpoint of PQ is (1, -0.5)

The coordinates of the point 2/3 of the way from p to q are (-0.2, 0.4)

What is the midpoint of a line segment?

the midpoint is the middle point of a line segment. It is equidistant from both endpoints.

The midpoint of PQ

To calculate this, we use the midpoint formula;

(x,y) = {(x1 + x2)/2 , (y1 + y2)/2}

From the question; (x1,y1) = (-5,4) and (x2,y2) = (7,-5)

So (x,y) = (-5+7)/2 , (4-5)/2 = 2/2, -1/2 = (1,-0.5)

The coordinates of the midpoint of PQ are (1,-0.5)

What is the internal division of the line segment?

we will use here the internal division formula of the section formula;

Mathematically the coordinates can be calculated using the formula;

(x,y) = (mx2 + nx1)/m+ n , (my2 + ny1)/m + n

in this case, m = 2 and n = 3

(x1,y1) = (-5,4)

(x2,y2) = (7,-5)

So substituting these values, we have;

(x,y) = (2(7)+ 3(-5))/(2+3) , 2(-5) + 3(4)/(2+3)

(x,y) = (14 -15)/5 , (-10 + 12)/5

= (-1/5, 2/5) = (-0.2, 0.4)

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Divide $4800 between Kofi and Kweku so that Kofi gets three times what Kweku gets

Answers

Answer:

see explanation

Step-by-step explanation:

let x be the amount Kweku gets then Kofi gets 3x , so

x + 3x = 4800

4x = 4800 ( divide both sides by 4 )

x = 1200

that is

Kweku gets $1200

Kofi gets 3 × $1200 = $3600

if i get 6 gems every 2 minutes and 30 seconds how many gems will i have after one hour?

Answers

Given that one can get 6 gems every 2 minutes and 30 seconds, one will have 144 gems after one hours.

How many gems will I have after one hour?

Given that;

6 gems are gotten every 2 minutes and 30 secondsLets convert 2min to second; 2min = ( 60 × 2 )sec = 120sec

Hence 6 gems are gotten every  120sec and 30 seconds

Hence 6 gems are gotten every  150seconds

Next we convert 1 hour to seconds

1 hour = ( 60 × 60 × 1 )sec = 3600sec

Now,

6 gems can be gotten every  150seconds

x gems can be gotten every 3600 seconds

x = ( 6 × 3600 ) / 150

x = 21600 / 150

x = 144 gems

Given that one can get 6 gems every 2 minutes and 30 seconds, one will have 144 gems after one hours.

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does someone mind helping me with this question? thank you!

Answers

Answer:

100

Step-by-step explanation:

to turn whole numbers to a fraction it is whatever numbers out of 100

Answer:

99

Step-by-step explanation:

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