salve by gauss jueabis method if iteration mothere aitration
4X+0.024x2-0.08x3=8
0.09x1+3x2-0.15x3=9
0.04x1+-0.08x2+4x3=20

Answers

Answer 1
I dunno g u got this tho

Related Questions

Help please
The cost, c(x), for parking in a hospital lot is given by c(x) = 5x + 3.00, where x is the number of hours. What does the slope mean in this situation?

Answers

Answer:

The slope is the cost per hour.

$5 per hour

The probability that a certain hockey team will win any given game is 0.3773 based on their 13 year win history of 389 wins out of 1031 games played (as of a certain date). Their schedule for November contains 12 games. Let X = number of games won in November.
Find the probability that the hockey team wins at least 3 games in November. (Round your answer to four decimal places.)

Answers

Answer:

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the teams wins, or they do not win. The probability of the team winning a game is independent of any other game, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3773.

This means that [tex]p = 0.3773[/tex]

Their schedule for November contains 12 games.

This means that [tex]n = 12[/tex]

Find the probability that the hockey team wins at least 3 games in November.

This is:

[tex]P(X \geq 3) = 1 - P(X < 3)[/tex]

In which:

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{12,0}.(0.3773)^{0}.(0.6227)^{12} = 0.0034[/tex]

[tex]P(X = 1) = C_{12,1}.(0.3773)^{1}.(0.6227)^{11} = 0.0247[/tex]

[tex]P(X = 2) = C_{12,2}.(0.3773)^{2}.(0.6227)^{10} = 0.0824[/tex]

Then

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0034 + 0.0247 + 0.0824 = 0.1105[/tex]

[tex]P(X \geq 3) = 1 - P(X < 3) = 1 - 0.1105 = 0.8895[/tex]

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

Find the value of x in each case:

Answers

X = 69o
2x + 42 = 180
=> x = 69

You bought a car that was $25500 and the value depreciates by 4.5% each year.

How much will the car be worth after 5 years?

How much after 8 years?

Answers

Answer:

(a) 20256.15625

(b) 17642.78546

Step-by-step explanation:

(a) There's a formula for this problem y = A(d)^t where, A is the initial value you are given, d is the growth or decay rate and t is the time period. So, in this case, as the car cost is decreasing it is a decay problem and we can write the formula as such; y = A(1-R)^t

So, in 5 years the car will be worth, 25500(1-4.5%)^5 or 20256.15625 dollars

(b) And after 8 years the car will be worth 25500(1-4.5%)^8 or 17642.78546 dollars.

match the description in column a to its corresponding word in column b.
help me plsssss​

Answers

Answer:

1-a

2-h

3-g

4-d

5-c

6-j

7-f

8-k

9-b

10-i

numbers are column A and alphabets are column B!

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Consider the equation below. The value of x in terms of b is . The value of x when b is 3 is .

Answers

Answer: x=-3/3=-1

Step-by-step explanation:

To solve for x in terms of b, simply treat b as a number, and solve for x as usual: first of all, we expand the left hand side:

-2bx+10=16

Subtract 10 from both sides:

-2bx=6

Divide both sides by -2b:

x=6/-2b=-3/b

This means that in particular, if we set b=3 , we have

x=-3/3=-1

Use quadratic regression to find the
equation for the parabola going
through these 3 points.
(-4, 7) (6, -33) (10, -105)
HELP PLZ

Answers

Answer:

[tex]y= -x^{2} -2x+15[/tex]

Step-by-step explanation:

 

[tex]y= -x^{2} -2x+15[/tex]

Assume that $4,000 I deposited into an investment account doubled in value over a six year period. What annual interest rate must I have earned over this period? Is the initial amount of the deposit relevant to the calculation of the annual interest rate? Why or why not?

Answers

Answer:

Interest rate is about 12.246%

The initial deposit doesn't matter because when you divide both sides by the initial deposit you're always left with (1+i)ⁿ=2

Step-by-step explanation:

[tex]4000(1+i)^6=8000\\(1+i)^6=2\\1+i=\sqrt[6]{2} \\1+i=1.122462048\\i=.12246[/tex]

Using the digits 2 through 8, find the number of different 5-digit numbers such that, digits can be used more than once.

Answers

Answer:

7 digits can be used for each position

There are a total of 5 positions

N = 7^5 = 16,807 numbers

You have 7 choices for the first position, second position, etc.

help help HELP!! will give brainliest

If f(x) = x², g(x) = 5x, and h(x) = x + 4, find each value.
Find h[f(4)].

Answers

Answer:

[tex]h(f(4))=20[/tex]

Step-by-step explanation:

We are given the functions:

[tex]f(x)=x^2,\, g(x)=5x\text{, and } h(x)=x+4[/tex]

And we want to find

[tex]h(f(4))[/tex]

Find f(4) first:

[tex]f(4)=(4)^2=16[/tex]

Thus:

[tex]h(f(4))=h(16)[/tex]

Now, evaluate h(16):

[tex]h(16)=(16)+4=20[/tex]

Hence:

[tex]h(f(4))=20[/tex]

A student-faculty government committee of 4 people is to be formed from 20 student
volunteers and 5 faculty volunteers.
a. If one person from the group of volunteers is chosen at random to draw the names
out of a hat, what is the probability that the person drawing the names is a student?
b. How many ways can the committee of four be formed if there are no restrictions on
composition.
C. How many ways can two of the students be chosen?
d. How many ways can 2 faculty be chosen?
e. What is the probability that the random selection of the four-person committee will
result in two students and two faculty?

Answers

the answer is c i just had this question your welcome

SECTION B
Answer ALL questions. Write your answers in the spaces provided.
1 Data set A has a median value of 3.1
Here is data set B.
14
-9
28
-38
-13
-2
(a) Write a statement to compare the median values of the two sets of data.
(2)

Answers

Answer: The median value of data set B is -5.5, which is less than the median value of 3.1 in dataset A.

Step-by-step explanation:

Order the dataset from least to greatest:

-38 → -13 → -9 → -2 → 14 → 28

Then find the values that lies in the middle:

-38 → -13 → -9 → -2 → 14 → 28

Since there are 2 values, find the average of those 2 values:

[tex]\frac{-9+(-2)}{2} =\frac{-11}{2} =-5.5[/tex]

The median value = -5.5.

The median value of data set B is -5.5, which is less than the median value of  3.1 in dataset A.

A screw manufacturer makes specialized tiny screws that are 15mm long. The manufacturing process does not make every screw exactly 15mm long. The lengths of the screws are normally distributed with mean 15mm and standard deviation 0.04mm. To test for quality control, 36 screws are to be measured. What is the probability that a sample mean is less than 14.99mm?

Answers

Answer:

The probability that a sample mean is less than 14.99mm=0.066808

Step-by-step explanation:

We are given that

Mean,[tex]\mu=15 mm[/tex]

Standard deviation,[tex]\sigma=0.04 mm[/tex]

n=36

We have to find the probability that a sample mean is less than 14.99mm.

We know that

[tex]P(\bar{x}<a)=P(Z<\frac{\bar{x}-a}{\frac{\sigma}{\sqrt{n}}})[/tex]

Using the formula

[tex]P(\bar{x}<14.99)=P(Z<\frac{14.99-15}{\frac{0.04}{\sqrt{36}}})[/tex]

[tex]P(\bar{x}<14.99)=P(Z<-1.5)[/tex]

=[tex]1-P(Z\geq -1.5)[/tex]

[tex]=1-0.93319[/tex]

=0.066808

Hence,  the probability that a sample mean is less than 14.99mm=0.066808

Suppose the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 11 million dollars. If incomes for the industry are distributed normally, what is the probability that a randomly selected firm will earn less than 114 million dollars

Answers

Answer:

95.73%

Step-by-step explanation:

Given data:

mean μ= 95

standard deviation, σ = 11

to calculate, the probability that a randomly selected firm will earn less than 114 million dollars;

Use normal distribution formula

[tex]P(X<114)=P(Z<\frac{X-\mu}{\sigma} )[/tex]

Substitute the required values in the above equation;

[tex]P(X<114)=P(Z<\frac{114-95}{11} )\\P(X<114)=P(Z<1.7272)\\P(X<114)=0.9573[/tex]

Therefore, the probability that a randomly selected firm will earn less than 114 million dollars = 95.73%

How would I simplify the expressions on the picture?

Answers

Answer:

7. [tex]x^{11}[/tex]   8. [tex]y^{2}\\[/tex]  9. [tex]p^{12}[/tex]  10.[tex]a^{3} b^{2}[/tex]  11.[tex]g^{16}[/tex]  12.[tex]r^{9} h^{3}[/tex]  13.[tex]m^{15} p^{6}[/tex]  14.[tex]k^{6} y[/tex]  15.[tex]x^6 z^4[/tex]

Step-by-step explanation:

7. [tex]x^3[/tex] × [tex]x^8[/tex] = [tex]x^{11}[/tex] when multiplying with exponents you add

8. [tex]\frac{y^{6} }{y^{4} }[/tex] = [tex]y^{2}[/tex] when dividing with exponents you subtract

9. [tex](p^{3})^4[/tex] = [tex]p^{12}\\[/tex] when it's power to power, you multiply

10. [tex]\frac{a^{9} b^{4}}{a^{6} b^{2}}[/tex] = [tex]a^{3} b^{2}[/tex]  (subtract exponents)

11. [tex](g^{8})^2[/tex] = [tex]g^{16}[/tex]  (multiply exponents)

12. [tex]r^{4} h^{2} r^{5} h[/tex] = [tex]r^{9} h^{3}[/tex]  (add exponents [tex]r^4 + r^5\\[/tex] and [tex]h^2 +h^1\\[/tex] )

13. [tex](m^{5} p^{2})^3[/tex] = [tex]m^{15} p^{6}[/tex] (multiply exponents)

14. [tex]\frac{k^{7} y^{4}}{y^{3}k}[/tex] =  [tex]k^{6} y[/tex] (subtract exponents [tex]k^7-k^1[/tex] and [tex]y^4-y^3\\[/tex] )

15. [tex]x^3 z^2 x^3 z^2[/tex] = [tex]x^6 z^4[/tex] (add exponents same as #12)

Suppose a term of a geometric sequence is a4 = 121.5 and the common ratio is 3. Write the formula for this sequence in the form an = a1 ⋅ rn−1. Explain how you arrived at your answer.

Answers

Answer:

[tex]a_n = 4.5 * 3^{n-1}[/tex]

Step-by-step explanation:

Given

[tex]a_4 = 121.5[/tex]

[tex]r = 3[/tex]

Required

[tex]a_n = a_1 * r^{n -1}[/tex]

Substitute 4 for n in [tex]a_n = a_1 * r^{n -1}[/tex]

[tex]a_4 = a_1 * r^{4 -1}[/tex]

[tex]a_4 = a_1 * r^3[/tex]

Substitute 121.5 for [tex]a_4[/tex]

[tex]121.5 = a_1 * 3^3[/tex]

[tex]121.5 = a_1 * 27[/tex]

Solve for a1

[tex]a_1 = \frac{121.5}{27}[/tex]

[tex]a_1 = 4.5[/tex]

So, we have:

[tex]a_n = a_1 * r^{n -1}[/tex]

[tex]a_n = 4.5 * 3^{n-1}[/tex]

Answer:

First I substituted 121.5 for an, 4 for n, and 3 for r in the general form. Then I solved to find a1 = 4.5. Finally, I substituted 4.5 for a1 and 3 for r in the general form to get an = 4.5 ⋅ 3n−1.

Step-by-step explanation:

sample answer on edge ;)

The lifespan, in years, of a certain computer is exponentially distributed. The probability that its lifespan exceeds four years is 0.30. Let f(x) represent the density function of the computer's lifespan, in years, for x>0. Determine an expression for f(x).

Answers

Answer:

The correct answer is "[tex]0.300993e^{-0.300993x}[/tex]".

Step-by-step explanation:

According to the question,

⇒ [tex]P(x>4)=0.3[/tex]

We know that,

⇒ [tex]P(X > x) = e^{(-\lambda\times x)}[/tex]

⇒     [tex]e^{(-\lambda\times 4)} = 0.3[/tex]

∵ [tex]\lambda = 0.300993[/tex]

Now,

⇒ [tex]f(x) = \lambda e^{-\lambda x}[/tex]

By putting the value, we get

           [tex]=0.300993e^{-0.300993x}[/tex]

If a seed is planted, it has a 90% chance of growing into a healthy plant. If 12 seeds are planted, what is the probability that exactly 2 don't grow

Answers

Answer:

0.2301 = 23.01% probability that exactly 2 don't grow.

Step-by-step explanation:

For each seed planted, there are only two possible outcomes. Either it grows into a healthy plant, or it does not. The probability of a seed growing into a healthy plant is independent of any other seed, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

90% chance of growing into a healthy plant.

This means that [tex]p = 0.9[/tex]

12 seeds are planted

This means that [tex]n = 12[/tex]

What is the probability that exactly 2 don't grow?

So 12 - 2 = 10 grow, which is [tex]P(X = 10)[/tex]. Then

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 10) = C_{12,10}.(0.9)^{10}.(0.1)^{2} = 0.2301[/tex]

0.2301 = 23.01% probability that exactly 2 don't grow.

find the first three common multiplies
6 and 8​

Answers

Answer:

24,48,72

Step-by-step explanation:

multiples of 6- 6,12,18,24,30,36,42,48,54,60,66,72

multiples of 8- 8,16,24,32,40,48,56,64,74,80


Solve the expression using the correct order of operations.
0.75x3.2+ (9.1)2-((-2.3)-(-0.9))2

Answers

Answer:

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]

Step-by-step explanation:

Given

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2[/tex]

Required

Solve

Start with the bracket

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ (9.1)^2-(-1.4)^2[/tex]

Evaluate all exponents

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ 82.81-1.96[/tex]

Evaluate all products

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 2.4+ 82.81-1.96[/tex]

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]

Help please :)......

Answers

Answer:

x | y

0 | 2

2 | 10

4 | 18

Step-by-step explanation:

the function would be y=4x+2

just plug each x value in to get each y value

help me pleaseeeeeeeeeeeeeeeeee………….

Answers

Answer:

d

Step-by-step explanation:

because u did the math for you

Lightbulbs. A company produces lightbulbs. We know that the lifetimes (in hours) of lightbulbs follow a bell-shaped (symmetric and unimodal) distribution with a mean of 7,161 hours and a standard deviation of 564 hours. Use the Empirical Rule (68-95-99.7 rule) to answer the following question: The shortest lived 2.5% of the lightbulbs burn out before how many hours

Answers

Answer:

Please find the complete question and its solution in the attached file.

Step-by-step explanation:

Shortest had survived after 6741 hours [tex]2.5\%[/tex] of the lights burnt.

[tex]\to 0.15\% + 2.35\% = 2.50\%[/tex]

19. In a random sample of 250 students, we found that 75 work out 4 or more times a week. Find the 95% confidence interval for the proportion of students who work out 4 or more times a week.

Answers

Answer:

The 95% confidence interval for the proportion of students who work out 4 or more times a week is (0.2432, 0.3568).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

In a random sample of 250 students, we found that 75 work out 4 or more times a week.

This means that [tex]n = 250, \pi = \frac{75}{250} = 0.3[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3 - 1.96\sqrt{\frac{0.3*0.7}{250}} = 0.2432[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3 + 1.96\sqrt{\frac{0.3*0.7}{250}} = 0.3568[/tex]

The 95% confidence interval for the proportion of students who work out 4 or more times a week is (0.2432, 0.3568).

You are charged $9.33 total for a meal, assume the 7% sales tax, how much was the menu price of this item?

I have already tried
$8.68
$8.71
$8.67
all were wrong ​

Answers

Answer:

$8.71.

Step-by-step explanation:

Given that you are charged $ 9.33 total for a meal, assuming the 7% sales tax, to determine how much was the menu price of this item, the following calculation must be performed:

100 + 7 = 107

107 = 9.33

100 = X

100 x 9.33 / 107 = X

933/107 = X

8.71 = X

Therefore, the menu price of this item was $ 8.71.

is there a formula for this?
help asap!!

Answers

Answer:

yes

Step-by-step explanation:

the answer is c well thats what my teacher said

Answer:

B

Step-by-step explanation:

using sine rule

[tex] \frac{y}{sin \: 45} = \frac{5}{sin \: 45} \\ y = 5[/tex]

using sin rule

[tex] \frac{x}{sin \: 90} = \frac{5}{sin \: 45} \\ \\ 5sin90 = xsin45 \\ \\ x = \frac{5 \: sin \: 90}{sin \: 45} \\ x = \frac{5}{0.7071} \\ x = 7.071[/tex]

x=5√2

A right rectangular prism has a length of 2 1/4 cm, width of 8 cm, and height of 20 1/2 cm.

What is the volume of the prism?



Enter the answer in the box.
cm³

Answers

Answer:

369 cm^3

Step-by-step explanation:

you just multiply all the numbers together

Answer:

369 cm³.

Step-by-step explanation:

Volume of a rectangular prism is just length × width × height. So:

2.25 × 8 = 18

18 × 20.5 = 369

So, the volume is 369 cm³.

^ means to the power, / indicationg fraction.
PLEASE IF YOU CAN ANSWER AND EXPLAIN TYVM!


1. simplify. 32^2/5. 32 raised to the power of 2 over 3(fraction)

27. the function f is definded below

f(x) = x^2+x-30/ x^2-10x+21

find all variables that are NOT in the domain of f

13. factor the following expression

16vx^3y^4+28v^5x^6

8. simplify, write answer without parentheses

(w^2/-3v^4)^2

24. solve for x 8=3/x-2

11. solve the following ewuation for R

Q=i^2Rt/J

16. solve for v
5v^2=-21v-4



Answers

Answer:

udirkkdjdjdjehdhebhgwdxddrergghg

the old building at the back of the school is badly in need of repair. the company Hsa and the executive are planning to renovate the building to accommodate a new music room. There are 15 rooms in the building and the dimension of the rooms to be redone with tiles are 6m long and 4 m wide. ted the tile man has 500 one meter square tiles.
Explain how you would estimate whether Ted has enough tiles to cover all the kitchen floors in the entire apartment building?
How many tiles, each measuring 1 square meter, are needed to cover one room floor?
How many tiles are needed to cover all the floors in the entire building? Show your work? ​

Answers

Answer:

a. If the area of the tiles is greater than or equal to the area of all the rooms.

b. 24

c. 360

Step-by-step explanation:

a. Explain how you would estimate whether Ted has enough tiles to cover all the kitchen floors in the entire apartment building?

Ted would have enough tiles if the  area of the tiles is greater than or equal to the area of all the rooms. Since we have 500 one meter square tiles, we have 500 m² of tiles.

Since the rooms are 6 m long and 4 m wide, the area of each room is 6 m × 4 m = 24 m². Since there are 15 rooms, the area of all the rooms is 15 × 24 m² = 360 m².

Since the area of the tiles = 500 m² is greater than the area of the rooms = 360 m², Ted would have enough tiles to cover all kitchen floors in the entire apartment building.

b. How many tiles, each measuring 1 square meter, are needed to cover one room floor?

Since the area of each room floor is 24 m² and the area of each tile is 1 m², so the number of  1 square meter tiles needed to cover each floor is n = area of floor/area of tile = 24 m²/1 m² = 24.

c. How many tiles are needed to cover all the floors in the entire building?

Since 24 tiles are needed to cover each floor and there are 15 rooms in the building, we would require 24 tiles/room × 15 rooms/building = 360 tiles.

So we require 360 tiles.

calculate the value of X in the diagram​

Answers

Answer:

that is the answer

Step-by-step explanation:

use triangle RSQ

from pythogrus theorem

a² + b² = c²

4² + 5² = RQ²

16 + 25 = RQ²

41 = R

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If the motor is used for 640 s, about how much work could it do? 8.4 J 4,800 J 6,000 J 3,500,000 J A sample of 10.6 g of KNO3 was dissolved in 251.0 g of water at 25 oC in a calorimeter. The final temperature of the solution was 21.5 oC. What is the molar heat of solution of KNO3 a full essay about life of pie Use this article excerpt to answer questions 9-10.Blair Apologizes for Katrina ResponseBritons who felt "deserted" by embassy staff during Hurricane Katrina received an apology fromPrime Minister Tony Blair today.Blair was reacting to complaints by survivors of Katrina that the response to their situation hadbeen painfully inadequate.Blair apologized, but assured survivors of the Hurricane that they had not been deserted. In fact,Blair said, embassy staff had been working "day and night" in an attempt to reach Britonstrapped in a New Orleans Superdome stadium.Which best states the purpose of this article excerpt?A. to persuade readers not to blame British diplomatsB. to convince readers to help British survivorsC. to explain to readers why Britons were "desertedD. to inform readers about Blair's apology An electric eel can generate a 180-V, 0.1-A shock for stunning its prey. What is the eel's power output environment is not ___ uniform all form Consider these versions of The War of the Worlds.Excerpt 1, from H. G. Wells's novel The War of the Worlds:The common round the sand pits was dotted with people, standing like myself in a half-fascinated terror, staring at these creatures, or rather at the heaped gravel at the edge of the pit in which they lay. And then, with a renewed horror, I saw a round, black object bobbing up and down on the edge of the pit. It was the head of the shopman who had fallen in, but showing as a little black object against the hot western sun. Now he got his shoulder and knee up, and again he seemed to slip back until only his head was visible. Suddenly he vanished, and I could have fancied a faint shriek had reached me.Excerpt 2, from Howard E. Koch's script for Orson Welles's radio adaptation:PHILLIPS: Ladies and gentlemen, you've just heard Mr. Wilmuth, owner of the farm where this thing has fallen. I wish I could convey the atmosphere . . . the background of this . . . fantastic scene. Hundreds of cars are parked in a field in back of us. Police are trying to rope off the roadway leading to the farm. But it's no use. They're breaking right through. Cars' headlights throw an enormous spot on the pit where the object's half buried. Some of the more daring souls are now venturing near the edge. Their silhouettes stand out against the metal sheen.Which statement best describes the similarity between these versions?Both versions impart an urgent tone through a residents words.Both versions impart setting details through colorful description.Both versions explain the background of a scientific phenomenon.Both versions use characterization to show the locals' intelligence. what is the comparison of handsome essential information; therefore, the writer must have morethan one brother.)EXERCISE 13 Using commas for introductory and nonessential elementsRead the sentences. Add commas as needed to set off introductory phrases and clauses and nonessential elements...1 On their vacation the Slovins are going to go to India which they've both been interested in visiting ever since an Indian family moved in next door.2 Because of busy work schedules they won't be able to spend more than two weeks there.3 They'll visit the Taj Mahal I'm sure as well as two or three major cities.4 Since the Slovins live in a warm climate they already have suitable clothes for their trip.5 They'll want to buy presents which are typical of the places that they visit.6 In my opinion they'll have a wonderful time because both are good travelers and interested in other cultures.Follow-up Write two sentences illustrating Guideline 1 and two sentences illustrating Guideline 2. Write about plans for a visit to another country.Guideline 3 how does minimum wage influence the demand and supply in the labour market? Determine the dimensions for R if R = m V / (d^2 Q) where m is a mass, V is a velocity, d is a diameter, and the dimensions of Q are M/(LT).No dimensionsM / (L T^2)M L / T^2ML / T