Answer:
[tex]f(126) \approx 5.01333[/tex]
Step-by-step explanation:
Given
[tex]\sqrt[3]{126}[/tex]
Required
Solve using differentials
In differentiation:
[tex]f(x+\triangle x) \approx f(x) + \triangle x \cdot f'(x)[/tex]
Express 126 as 125 + 1;
i.e.
[tex]x = 125; \triangle x = 1[/tex]
So, we have:
[tex]f(125+1) \approx f(125) + 1 \cdot f'(125)[/tex]
[tex]f(126) \approx f(125) + 1 \cdot f'(125)[/tex]
To calculate f(125), we have:
[tex]f(x) = \sqrt[3]{x}[/tex]
[tex]f(125) = \sqrt[3]{125}[/tex]
[tex]f(125) = 5[/tex]
So:
[tex]f(126) \approx f(125) + 1 \cdot f'(125)[/tex]
[tex]f(126) \approx 5 + 1 \cdot f'(125)[/tex]
[tex]f(126) \approx 5 + f'(125)[/tex]
Also:
[tex]f(x) = \sqrt[3]{x}[/tex]
Rewrite as:
[tex]f(x) = x^\frac{1}{3}[/tex]
Differentiate
[tex]f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}\\[/tex]
Using law of indices, we have:
[tex]f'(x) = \frac{x^\frac{1}{3}}{3x}[/tex]
So:
[tex]f'(125) = \frac{125^\frac{1}{3}}{3*125}[/tex]
[tex]f'(125) = \frac{5}{375}[/tex]
[tex]f'(125) = \frac{1}{75}[/tex]
So, we have:
[tex]f(126) \approx 5 + f'(125)[/tex]
[tex]f(126) \approx 5 + \frac{1}{75}[/tex]
[tex]f(126) \approx 5 + 0.01333[/tex]
[tex]f(126) \approx 5.01333[/tex]
A researcher conducts a repeated-measures design study comparing 2 treatment conditions and obtains 20 scores in EACH treatment condition. How many participants participated in the study
Answer:
20 participants
Step-by-step explanation:
Given
[tex]Conditions = 2[/tex]
[tex]Scores = 20[/tex]
Type: Repeated design
Required
The number of participants (n)
The repeated measure design implies that the test was conducted repeatedly on the same sample size.
Since the score in each test is 20; then:
[tex]n = 20[/tex] --- the number of participants
Examine the two normal probability curves and complete the statements.
The mean of the shorter normal curve is ["equal to", "greater than", "less than"] the mean of the taller normal curve.
The standard deviation of the shorter normal curve is ["less than", "greater than", "equal to"] the standard deviation of the taller normal curve.
The area under the shorter normal curve is ["equal to", "greater than", "less than"] the area under the taller normal curve.
Answer: hello the two normal probability curves are missing
answer:
a) equal to
b) greater than
c) equal to
Step-by-step explanation:
a) The mean of the shorter normal curve is equal to The mean of the taller normal curve is
b) The standard deviation of the shorter normal curve is greater than the standard deviation of the taller normal curve
c) The area under the shorter normal curve is equal to the area under the taller normal curve
By recognizing the series as a Taylor series evaluated at a particular value of x, find the sum of each of the following convergent series
1 + 3 + 9/2! + 27/3! + 81/4! + .....
Answer:
the answer should be e^3
Step-by-step explanation:
i hope it helps you
1000^1000
i would like to simplify it into 10^x, how?
Answer:
10^3000
Step-by-step explanation:
1000¹⁰⁰⁰
= (10³)¹⁰⁰⁰
= 10^(3×1000)
= 10³⁰⁰⁰ or 10^3000
Answered by GAUTHMATH
Suppose the sales (1000s of $) of a fast food restaurant are a linear function of the number of competing outlets within a 5 mile radius and the population (1000s of people) within a 1 mile radius. The regression equation quantifying this relation is (sales)
Answer:
[tex]Sales = 86.749[/tex]
Step-by-step explanation:
Given
[tex]Sales = 0.845*(competitors) + 5.79*(population) + 13.889[/tex]
[tex]Competitors = 4[/tex]
[tex]Population = 12000[/tex]
See comment for complete question
Required
The sales
We have:
[tex]Sales = 0.845*(competitors) + 5.79*(population) + 13.889[/tex]
Substitute values for competitors and population
[tex]Sales = 0.845*4 + 5.79*12 + 13.889[/tex]
[tex]Sales = 3.38 + 69.48 + 13.889[/tex]
[tex]Sales = 86.749[/tex]
How would the fraction [tex]\frac{7}{1-\sqrt{5} }[/tex] be rewritten if its denominator is rationalized using difference of squares?
Answer:
[tex] \frac{7 + 7 \sqrt{5} }{ - 4} [/tex]
Step-by-step explanation:
We would multiply the fraction by its conjugate
( A conjugate is a expression that has the same integer or number values but have different signs) for example
[tex]5x + 2[/tex]
and
[tex]5x - 2[/tex]
ARE Conjugates.
The conjugate of
[tex]1 - \sqrt{5} [/tex]
is
[tex]1 + \sqrt{5} [/tex]
So this means we will multiply the expression by 1 plus sqr root of 5 on the numerator and denominator.
Our new numerator will be
[tex]7 \times (1 + \sqrt{5} ) = 7 + 7 \sqrt{5} [/tex]
We can apply the difference of squares for the denominator.
[tex](x + y)(x - y) = x {}^{2} - {y}^{2} [/tex]
So our denominator will be
[tex]1 - 5 = - 4[/tex]
So our rationalized fraction will be
[tex] \frac{7 + 7 \sqrt{5} }{ - 4} [/tex]
[tex]z^{7}=128i[/tex]
z = ____ + ____ i
If z ⁷ = 128i, then there are 7 complex numbers z that satisfy this equation.
[tex]z^7 = 128i = 2^7i = 2^7e^{i\frac\pi2}[/tex]
[tex]\implies z=\sqrt[7]{2^7} e^{i\frac17\left(\frac\pi2+2n\pi\right)}[/tex]
(where n = 0, 1, 2, …, 6)
[tex]\implies z = 2 e^{i\left(\frac\pi{14}+\frac{2n\pi}7\right)}[/tex]
[tex]\displaystyle\implies z = 2 \left(\cos\left(\frac\pi{14}+\frac{2n\pi}7\right)+i\sin\left(\frac\pi{14}+\frac{2n\pi}7\right)\right)[/tex]
NO LINKS OR ANSWERING WHAT YOU DON'T KNOW?
1. Suppose y varies inversely with x, and y = 25 when x = 1/5. What is the value of y when x = 5?
a. 15
b. 5
c. 25
d. 1
2. Suppose y varies inversely with x, and y = a when x = a^2. What inverse variation equation related x and y?
a. y = a^2/x
b. y = a^3/x
c. y= a^3x
d. y = ax
3. Suppose y varies inversely with x, and y = 3 when x = 1/3. What is the inverse variation equation that relates x and y?
a. y = 1/x
b. y =x
c. y = 3x
d. y = 3/x
Answer:
1. D. 1
2. B. y=a³/x
3. A. y=1/x
Step-by-step explanation:
too long to give te explanations but they're there in the attachments
Ben starts walking along a path at 3 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the same path at 7 mi/h. How long (in hours) will it be before Amanda catches up to Ben?
Enter the exact answer.
Hint: The distance formula is that distance = rate * time, so for example in one and a half hours, Ben has walked 3 * 1.5 miles.
Amanda catches up to Ben in ____________ hours.
Answer:
1.125 hours
Step-by-step explanation:
Given :
Ben's speed = 3 mi/hr
Time before Amanda starts = 1.5 hours
Amanda's speed = 7 mi/hr
Time before Amanda catches up with Ben
Recall :
Distance = speed * time
Distance already covered by Ben before Amanda starts :
(3 * 1.5) = 4.5
Hence, we can setup the equation :
Ben's distance = Amanda's distance
Let time taken = x
4.5 + 3x = 7x
4.5 = 7x - 3x
4.5 = 4x
x = 4.5 / 4
x = 1.125 hours
1.125 * 60 = 67. 5 minutes
Look at photo help please I will give brainliest
Answer:
3x² + 13x + 4
Step-by-step explanation:
I did the steps in my book
Find the length of arc AB
Step 1: Find the circumference of the circle
Formula for circumference: C = 2 * pi * r
C = 2 * pi * 27
C = 54pi
Step 2: Find the length of the desired arc
We are only looking for 20 degrees out of 360 degrees, therefore we can multiply our circumference by 20/360.
20/360 * 54pi = 3pi units
Hope this helps!
One of the factor of x² +3x+2 is x+1 then the other factor is …..
Hi there!
[tex]\large\boxed{(x + 2)}[/tex]
x² + 3x + 2
We know that x + 1 is a factor, so:
We must find another number that adds up to 3 when added to 1 and multiplies into 2 with 1. We get:
x + 2
(x + 1)(x + 2)
y + x + z =762500
z : x = 15/9 : 2
y : x = 1 : 3/4
Step-by-step explanation:
true
How many people have at least 1?
Answer:
15
Step-by-step explanation:
3+7+5
PLEASE BRAINLIESTTTTTTTTT
NO LINKS OR ANSWERING WHAT YOU DON'T KNOW?
4. Suppose y varies inversely with the x, and y = -1 when = 3. What inverse variation equation relates x and y?
a. y = 3/x
b. b. y = -3x
c. y = 3x
d. y = -3/x
5. Suppose y varies inversely with x and y = 68 when x = 1/17. What is the value of x when y = 16?
a. 64
b. 32
c. 1/4
d. 1/16
6. Suppose y varies inversely with x, and y = 5 when x = 15. What is the value of y when x = 25
a. 3
b. 5
c. 25
d. 15
Answer:
4,a
5.d
6.c
plz mark me as brainliest
Step-by-step explanation:
Answer:
1. A
2. C
3. A
Step-by-step explanation:
all the explanations are In the image above
A certain lottery has 37 numbers. in how many different ways can 4 of the numbers be selected?
The probability that a certain movie will win an award for acting is 0.15, the probability that it will win an award for direcing is 0.23, and the probability that it will win both is 0.09. Find the probabilities of the following.
a. The movie wins an award for acting, given that it wins both awards.
b. The movie wins an award for acting, given that it wins exactly one award.
c. The movie wins an award for acting, given that it wins at least one award.
Answer:
a) 0.15 / 0.09
b) 0.15 / 1
c) 0.15 / 0.23
Type the correct answer in each box. The volume of a cube is given by and the total surface area of a cube is given by , where s is the side length of the cube. If the side length of a cube is 5 inches , the volume of the cube is ____ cubic inches and its total surface area is ____ square inches.
Answer:
hope this will help you a lot
Sam takes a job with a starting salary of $50,000 for the first year. He earns a 4% increase each year. Which expression gives the partial sum, S3, (in thousands)?
Assume that 300 births are randomly selected and 5 of the births are girls. Use subjective judgment to describe the number of girls as significantly high, significantly low, or neither significantly low nor significantly high.g
Answer:
Following are the response to the given choice.
Step-by-step explanation:
Please find the complete question in the attached file.
Subjective opinion = Question of opinion.
Therefore this requires only just opinion and we don't have to do any actual calculations.
Does this seem like a great number of girls, a little number of girls, or a decent number of girls to you but if 1,300 babies were born, 5 of whom were females?
This is a small number of beautiful gals, in my honest opinion. We anticipate boys and girls to be produced about the very same frequency, thus I expect some half of them to be females if there are 1 300 newborns. You should have roughly 650 girls if 50% of the infants are girls, but now we only have five. That appears to me to be considerably low. which is your own opinion.
Your EZ Pass account begins with $80. It costs you $4/day. Write an equation
for the amount in your account (A) in terms of the number of days (D).
Answer:
The equation is [tex]A(d) = 80 - 4d[/tex]
Step-by-step explanation:
Linear function:
A linear function for the amount of money in an account after t days is given by:
[tex]A(d) = A(0) - md[/tex]
In which A(0) is the initial value and m is the daily cost.
Your EZ Pass account begins with $80. It costs you $4/day.
This means that [tex]A(0) = 80, m = 4[/tex]
So
[tex]A(d) = A(0) - md[/tex]
[tex]A(d) = 80 - 4d[/tex]
Which statements below represent the situation? Select three options.
Answer:
where is the statement
Step-by-step explanation:
its incomplete po
Problem: The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72
inches and standard deviation 3.17 inches. Compute the probability that a simple random sample of size n=
10 results in a sample mean greater than 40 inches. That is, compute P(mean >40).
Gestation period The length of human pregnancies is approximately normally distributed with mean u = 266
days and standard deviation o = 16 days.
Tagged
Math
1. What is the probability a randomly selected pregnancy lasts less than 260 days?
2. What is the probability that a random sample of 20 pregnancies has a mean gestation period of 260 days
or less?
3. What is the probability that a random sample of 50 pregnancies has a mean gestation period of 260 days
or less?
4. What is the probability a random sample of size 15 will have a mean gestation period within 10 days of
the mean?
Know
Learn
Booste
V See
Answer:
0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.
Gestation periods:
1) 0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.
2) 0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.
3) 0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.
4) 0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.
Step-by-step explanation:
To solve these questions, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72 inches and standard deviation 3.17 inches.
This means that [tex]\mu = 38.72, \sigma = 3.17[/tex]
Sample of 10:
This means that [tex]n = 10, s = \frac{3.17}{\sqrt{10}}[/tex]
Compute the probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.
This is 1 subtracted by the p-value of Z when X = 40. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{40 - 38.72}{\frac{3.17}{\sqrt{10}}}[/tex]
[tex]Z = 1.28[/tex]
[tex]Z = 1.28[/tex] has a p-value of 0.8997
1 - 0.8997 = 0.1003
0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.
Gestation periods:
[tex]\mu = 266, \sigma = 16[/tex]
1. What is the probability a randomly selected pregnancy lasts less than 260 days?
This is the p-value of Z when X = 260. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{260 - 266}{16}[/tex]
[tex]Z = -0.375[/tex]
[tex]Z = -0.375[/tex] has a p-value of 0.3539.
0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.
2. What is the probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less?
Now [tex]n = 20[/tex], so:
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{260 - 266}{\frac{16}{\sqrt{20}}}[/tex]
[tex]Z = -1.68[/tex]
[tex]Z = -1.68[/tex] has a p-value of 0.0465.
0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.
3. What is the probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less?
Now [tex]n = 50[/tex], so:
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{260 - 266}{\frac{16}{\sqrt{50}}}[/tex]
[tex]Z = -2.65[/tex]
[tex]Z = -2.65[/tex] has a p-value of 0.0040.
0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.
4. What is the probability a random sample of size 15 will have a mean gestation period within 10 days of the mean?
Sample of size 15 means that [tex]n = 15[/tex]. This probability is the p-value of Z when X = 276 subtracted by the p-value of Z when X = 256.
X = 276
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{276 - 266}{\frac{16}{\sqrt{15}}}[/tex]
[tex]Z = 2.42[/tex]
[tex]Z = 2.42[/tex] has a p-value of 0.9922.
X = 256
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{256 - 266}{\frac{16}{\sqrt{15}}}[/tex]
[tex]Z = -2.42[/tex]
[tex]Z = -2.42[/tex] has a p-value of 0.0078.
0.9922 - 0.0078 = 0.9844
0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.
PLZ PLZ HELP
Mark is investing $47,000 in an account paying 5.26% interest compounded continuously.
What will Mark's account balance be in 17 years?
O $114,932.80
$114,925.39
$114,921.47
$114.925.46
===============================================
Work Shown:
A = P*e^(r*t)
A = 47000*e^(0.0526*17)
A = 114,932.799077198
A = 114,932.80
Notes:
P = 47,000 is the principal or amount depositedr = 0.0526 is the decimal form of 5.26%The "e" refers to the special constant e = 2.718... which is similar to pi = 3.14... I would let your calculator handle this constant. There should be a button labeled "e".Mark's account balance after 17 years would be $114,932.8
What is the formula for the continuous compounding?[tex]A=Pe^{rt}[/tex]
where,
A = Accrued amount
P = Principal amount
r = interest rate as a decimal
R = interest rate as a percent
r = R/100
t = time in years
For given question,
P = $47000, t = 17 years
R = 5.26%
[tex]\Rightarrow r =\frac{5.26}{100}\\\\\Rightarrow r = 0.0526[/tex]
Using the Continuous Compounding Formula,
[tex]\Rightarrow A=Pe^{rt}\\\\\Rightarrow A=47000\times e^{0.0526\times 17}\\\\\Rightarrow A=114932.8[/tex]
Therefore, Mark's account balance after 17 years would be $114,932.8
Learn more about the Continuous Compounding here:
https://brainly.com/question/24246899
#SPJ2
Points A, B and C are collinear . Point B is between A andSolve for given the following
Answer:
[tex]x = 7[/tex]
Step-by-step explanation:
Given
[tex]AC = 3x +3[/tex]
[tex]AB = -1+2x\\[/tex]
[tex]BC =11[/tex]
Required
Find x
We have:
[tex]AC = AB + BC[/tex]
So, we have:
[tex]3x + 3 = -1 + 2x + 11[/tex]
Collect like terms
[tex]3x - 2x = -1 + 11 - 3[/tex]
[tex]x = 7[/tex]
Solve the following equation or inequality for the unknown variable. Round answer to two decimal places if necessary.
(3x)2 - 10 = 56
4
x =
Answer:
x = 2.7
Step-by-step explanation:
The given equation is :
[tex](3x)^2-10=56[/tex]
We need to solve it for x.
It can be rewrite as follows:
[tex]9x^2-10=56[/tex]
Adding 10 to both sides,
[tex]9x^2-10+10=56+10\\\\9x^2=66\\\\x=\sqrt{\dfrac{66}{9}}\\\\x=2.70[/tex]
So, the value of x is equal to 2.7.
HELP ASAP PLS Select the correct answer.
A light bulb's brightness is reduced when placed behind a screen. The amount of visible light produced by the light bulb decreases by 25% with
each additional layer that is added to the screen. With no screen, the light bulb produces 750 lumens. The lumen is a unit for measuring the total
quantity of visible light emitted by a source,
Select the correct equation that can be used to represent the lumens, L, after x screen layers are added.
Answer:
D. 750(0.75)ˣ
Step-by-step explanation:
Let the new brightness be L'. Since our initial brightness L₀ reduces by 25 %, we have that L' = L₀ - 25% of L₀
L' = L₀ - 0.25L₀
L' = 0.75L₀
Adding the second screen, the new intensity is L" = L' - 25 % of L'
L" = L' - 0.25 L'
L" = 0.75L'.
Since L' = 0.75L₀,
L" = 0.75L' = 0.75(0.75L₀) = 0.75²L₀
Adding the third screen, the new intensity is L"' = L'' - 25 % of L''
L'" = L" - 0.25 L"
L"' = 0.75L".
Since L" = 0.75L' = 0.75²L₀
L"' = 0.75L" = 0.75(0.75²L₀) = 0.75³L₀
So, we see a pattern here.
The intensity after x screens is L = (0.75)ˣL₀
Since L₀ = 750 lumens,
L = 750(0.75)ˣ
Find the limit of f as or show that the limit does not exist. Consider converting the function to polar coordinates to make finding the limit easier. f(x,y)
Answer:
[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2} = 0[/tex]
Step-by-step explanation:
Given
[tex]f(x,y) = \frac{x^2 \sin^2y}{x^2+2y^2}[/tex]
Required
[tex]\lim_{(x,y) \to (0,0)} f(x,y)[/tex]
[tex]\lim_{(x,y) \to (0,0)} f(x,y)[/tex] becomes
[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2}[/tex]
Multiply by 1
[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2}\cdot 1[/tex]
Express 1 as
[tex]\frac{y^2}{y^2} = 1[/tex]
So, the expression becomes:
[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2} \cdot \frac{y^2}{y^2}[/tex]
Rewrite as:
[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 y^2}{x^2+2y^2} \cdot \frac{\sin^2y}{y^2}[/tex]
In limits:
[tex]\lim_{(x,y) \to (0,0)} \frac{\sin^2y}{y^2} \to 1[/tex]
So, we have:
[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 y^2}{x^2+2y^2} *1[/tex]
[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 y^2}{x^2+2y^2}[/tex]
Convert to polar coordinates; such that:
[tex]x = r\cos\theta;\ \ y = r\sin\theta;[/tex]
So, we have:
[tex]\lim_{(x,y) \to (0,0)} \frac{(r\cos\theta)^2 (r\sin\theta;)^2}{(r\cos\theta)^2+2(r\sin\theta;)^2}[/tex]
Expand
[tex]\lim_{(x,y) \to (0,0)} \frac{r^4\cos^2\theta\sin^2\theta}{r^2\cos^2\theta+2r^2\sin^2\theta}[/tex]
Factor out [tex]r^2[/tex]
[tex]\lim_{(x,y) \to (0,0)} \frac{r^4\cos^2\theta\sin^2\theta}{r^2(\cos^2\theta+2\sin^2\theta)}[/tex]
Cancel out [tex]r^2[/tex]
[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{\cos^2\theta+2\sin^2\theta}[/tex]
[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{\cos^2\theta+2\sin^2\theta}[/tex]
Express [tex]2\sin^2 \theta[/tex] as [tex]\sin^2\theta+\sin^2\theta[/tex]
So:
[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{\cos^2\theta+\sin^2\theta+\sin^2\theta}[/tex]
In trigonometry:
[tex]\cos^2\theta + \sin^2\theta = 1[/tex]
So, we have:
[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{1+\sin^2\theta}[/tex]
Evaluate the limits by substituting 0 for r
[tex]\frac{0^2 \cdot \cos^2\theta\sin^2\theta}{1+\sin^2\theta}[/tex]
[tex]\frac{0 \cdot \cos^2\theta\sin^2\theta}{1+\sin^2\theta}[/tex]
[tex]\frac{0}{1+\sin^2\theta}[/tex]
Since the denominator is non-zero; Then, the expression becomes 0 i.e.
[tex]\frac{0}{1+\sin^2\theta} = 0[/tex]
So,
[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2} = 0[/tex]
Mark looked at the statistics for his favorite baseball player, Jose Bautista. Mark looked at seasons
when Bautista played 100 or more games and found that Bautista's probability of hitting a home run
in a game is 0.173
If Mark uses the normal approximation of the binomial distribution, what will be the variance of
the number of home runs Bautista is projected to hit in 100 games? Answer choices are rounded
to the tenths place.
O 0.8
O 14.3
0 3.8
O 17.3
⭕ 17.3
#CARRYONLEARNING
[tex]{hope it helps}}[/tex]
Can someone help me out here please? I tried dividing and multiplying but still have not got the correct answer. How do I go about solving this problem and where do I start?
9514 1404 393
Answer:
$4000
Step-by-step explanation:
The problem tells you the relation between commission (c) and stock value (v) is ...
c = 10 + 0.025v . . . . $10 + .025 of the value traded
We want to find the value (v) for the given commission (c=110). We can put these numbers into the formula and solve for v:
110 = 10 + 0.025v
100 = 0.025v . . . . . . . subtract 10
100/0.025 = v = 4000 . . . . divide by the coefficient of v
The value of stock traded was $4000.
_____
Additional comment
As always, you start by reading and comprehending the problem. You look for what is being asked for, what is being given, and any information that relates one to the other.
Here, the value of stock traded is asked for, the amount of commission is given, and a description of the relation of one to the other is provided. Translate that description to an equation, fill in the given value, and solve for the unknown. (That's what we did above.)
__
You can also work this in your head. The commission is $10 more than some fraction of the amount traded. Since the commission is $110, only $100 of that is the fraction of the amount traded. With a little experience, you can recognize the fraction 0.025 as being 1/40. That means $100 is 1/40 of the value traded, or the value traded is 40 × $100 = $4000.
