Answers
The percentages for each outcome are given as follows:
a) 34.4%.
b) 29.4%.
What is a percentage?The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:
P = a/b x 100%
For this problem, we already have the percentages, hence we just combine them.
For item a, he can be late in two ways, one that happens 24.4% of the time(waking up late), and the other 10%(stuck in traffic), hence the percentage is of 34.4%, as 24.4% + 10% = 34.4%.
For item b, the percentage stuck in traffic is of 5%, hence the percentage that he will be late is 24.4% + 5% = 29.4%.
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Related Questions
PLEASE HELP!
Let f be the function given by f (x) = (create an original sinusoidal function with an amplitude not equal to 1, a period not equal to 2π, and non-zero phase and vertical shifts).
ex: F of x equals negative one half times sine of quantity 3 times x plus pi over 2 end quantity minus 2
Part A: State the amplitude and vertical shift.
Part B: Determine the period of f (x), showing all necessary calculations.
Part C: Calculate the phase shift of the sinusoidal function with proper mathematical justification.
Part D: Graph the sinusoidal function by hand, using your answers from parts A–C.
Choose an angle θ, in radians, such that 2π < θ < 4π . Let θ = (create an original angle measure).
ex: Theta equals 13 pi over 6
Part E: Determine the exact value of cos θ using the sum formula. Show all necessary mathematical work.
Part F: Determine the exact value of sin θ using the difference formula. Show all necessary mathematical work.
Part G: Calculate the exact value of tan 2θ, using your answers from parts E – F.
Answers
The equation of the function f(x) is f(x) = 2 sin(π/2(x + 6)) - 3
How to create the sine function?A sine function is represented as:
f(x) = A sin(B(x + C)) + D
Where
A = Amplitude
Period = 2π/B
C = Phase shift
D = Vertical shift
The requirements in the question are:
Amplitude not equal to 1Period not equal to 2πNon-zero phase and vertical shiftsSo, we can use the following assumptions
A = 2
Period = 4
C = 6
D = -3
So, we have:
f(x) = 2 sin(B(x + 6)) - 3
The value of B is
4 = 2π/B
This gives
B = π/2
So, we have:
f(x) = 2 sin(π/2(x + 6)) - 3
The amplitude, vertical shift, period of f(x)and the phase shiftUsing the representations in (a), we have:
Amplitude = 2Vertical shift = -3Period = 4Phase shift = 6The graph of the functionSee attachment for the graph of f(x)
The value of cos θLet θ = 3π
So, we have:
cos(3π)
This is calculated as:
cos(3π) = cos(2π + π)
Expand
cos(3π) = cos(2π) *cos(π) - sin(2π) *sin(π)
Evaluate
cos(3π) = -1
The value of sin θLet θ = 3π
So, we have:
sin(3π)
This is calculated as:
sin(3π) = sin(2π + π)
Expand
sin(3π) = sin(2π) *cos(π) + cos(2π) *sin(π)
Evaluate
sin(3π) = 0
The value of tan 2θLet θ = 3π
So, we have:
tan(2 * 3π)
tan(6π)
This is calculated as:
tan(6π) = tan(3π + 3π)
Evaluate
tan(3π) = 0
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A yo-yo is moving up and down a string so that its velocity at time t is given by v(t) = 3cos(t) for time t ≥ 0. The initial position of the yo-yo at time t = 0 is x = 3.
Part A: Find the average value of v(t) on the interval open bracket 0 comma pi over 2 close bracket. (10 points)
Part B: What is the displacement of the yo-yo from time t = 0 to time t = π? (10 points)
Part C: Find the total distance the yo-yo travels from time t = 0 to time t = π. (10 points)
Answers
Part A - The average value of v(t) over the interval (0, π/2) is 6/π
Part B - The displacement of the yo-yo from time t = 0 to time t = π is 0 m
Part C - The total distance the yo-yo travels from time t = 0 to time t = π is 6 m.
Part A: Find the average value of v(t) on the interval (0, π/2)The average value of a function f(t) over the interval (a,b) is
[tex]f(t)_{avg} = \frac{1}{b - a} \int\limits^b_a {f(t)} \, dx[/tex]
So, since velocity at time t is given by v(t) = 3cos(t) for time t ≥ 0. Its average value over the interval (0, π/2) is given by
[tex]v(t)_{avg} = \frac{1}{\frac{\pi }{2} - 0} \int\limits^{\frac{\pi }{2} }_0 {v(t)} \, dt[/tex]
Since v(t) = 3cost, we have
[tex]v(t)_{avg} = \frac{1}{\frac{\pi }{2} - 0} \int\limits^{\frac{\pi }{2} }_0 {3cos(t)} \, dt\\= \frac{3}{\frac{\pi }{2}} \int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt\\= \frac{6}{{\pi}} [{sin(t)}]^{\frac{\pi }{2} }_{0} \\= \frac{6}{{\pi}} [{sin(\frac{\pi }{2})} - sin0]\\ = \frac{6}{{\pi}} [1 - 0]\\ = \frac{6}{{\pi}} [1]\\ = \frac{6}{{\pi}}[/tex]
So, the average value of v(t) over the interval (0, π/2) is 6/π
Part B: What is the displacement of the yo-yo from time t = 0 to time t = π?To find the displacement of the yo-yo, we need to find its position.
So, its position x = ∫v(t)dt
= ∫3cos(t)dt
= 3∫cos(t)dt
= 3sint + C
Given that at t = 0, x = 3. so
x = 3sint + C
3 = 3sin0 + C
3 = 0 + C
C = 3
So, x(t) = 3sint + 3
So, its displacement from time t = 0 to time t = π is
Δx = x(π) - x(0)
= 3sinπ + 3 - (3sin0 + 3)
= 3 × 0 + 3 - 0 - 3
= 0 + 3 - 3
= 0 + 0
= 0 m
So, the displacement of the yo-yo from time t = 0 to time t = π is 0 m
Part C: Find the total distance the yo-yo travels from time t = 0 to time t = π. (10 points)The total distance the yo-yo travels from time t = 0 to time t = π is given by
[tex]x(t) = \int\limits^{\pi}_0 {v(t)} \, dt\\= \int\limits^{\pi }_0 {3cos(t)} \, dt\\= 3 \int\limits^{\pi }_0 {cos(t)} \, dt\\ = 3 \int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt + 3\int\limits^{\pi }_{\frac{\pi }{2}} {cos(t)} \, dt\\= 3 \times 2\int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt\\= 6 [{sin(t)}]^{\frac{\pi }{2} }_{0} \\= 6[{sin\frac{\pi }{2} - sin0]\\\\= 6[1 - 0]\\= 6(1)\\= 6[/tex]
So, the total distance the yo-yo travels from time t = 0 to time t = π is 6 m.
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Use the table values below to select the correct statement.
Answers
The true statement is (c) the function f(x) is an exponential function
How to determine the correct statement?From the table, we can see that:
As x increases by 2.y does not increase with the same common differenceThis means that the table represents an exponential function
The rate is then calculated as:
f(n) = f(1) * r^n-1
Using f(3), we have
102 = 17 * r^3-1
This gives
r^2 = 6
Take the square roots
r = 2.45
Hence, the true statement is (c) the function f(x) is an exponential function
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45.7 kilometers =
meters
Answers
Answer:
45.7 kilometers = 45,700 meters
Explanation:
Hi!
Okay, so basically, in one kilometer, there are 1000 meters.
Using this problem, all you have to do is multiply 45.7 by 1000, which is 45,700.
Whatever value is used for kilometers (ex. 2), just multiply by 1000, and you’ll get the value as meters (ex. 2 x 1000 = 2000 meters).
Hope this helps!
To convert kilometers to meters, multiply the kilometer value by 1000 meters which is equal to 1 km.
Convert 45.7 kilometers to meters:
Knowing that 1000 m = 1 km.[tex]\boldsymbol{\sf{Therefore \ \ \longmapsto \ \ 45.7\not{km}*\left(\dfrac{1000 \ m}{1\not{km}}\right)=45700 \ m }}[/tex]
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Fill in the P(X=x) values to give a legitimate probability distribution for the discrete random variable , whose possible values are 0, 1, 3, 4, and 5.
Answers
For a probability distribution to be represented, it is needed that P(X = 0) + P(X = 1) = 0.44. Hence one possible example is:
P(X = 0) = 0.40.P(X = 1) = 0.04.What is needed for a discrete random variable to represent a probability distribution?The sum of all the probabilities must be of 1, hence:
P(X = 0) + P(X = 1) + P(X = 3) + P(X = 4) + P(X = 5) = 1.
Then, considering the table:
P(X = 0) + P(X = 1) + 0.15 + 0.17 + 0.24 = 1
P(X = 0) + P(X = 1) + 0.56 = 1
P(X = 0) + P(X = 1) = 0.44.
Hence one possible example is:
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Divide the following polynomial using synthetic division, then place the answer in the proper location on the grid. Write answer in descending powers of x. (x3 + 6x2 + 3x + 1 ) ÷ (x - 2)
Answers
When we divide [tex]x^{3} +6x^{2} +3x+1[/tex] by (x-2) we will get the quotient be [tex]x^{2} +8x+19[/tex] and remainder be 39.
Given two expressions be [tex]x^{3} +6x^{2} +3x+1[/tex] and (x-2).
We are required to divide the first expression by second expression.
Division means distributing parts of something. The number which is being divided is known as quotient.Divisor is a number which divides the number.
Expressions refers to the combination of numbers, fractions, coefficients, determinants, indeterminants. It expresses some relationship or show equation of line.
We know that relationship between quotient, divisor, divident and remainder is as under:
Dividend=Divisor*Quotient+Remainder
[tex]x^{3} +6x^{2} +3x+1[/tex]=(x-2)*([tex]x^{2} +8x+19[/tex])+39
Quotient=[tex]x^{2} +8x+19[/tex]
Remainder=39
Hence when we divide [tex]x^{3} +6x^{2} +3x+1[/tex] by (x-2) we will get the quotient be [tex]x^{2} +8x+19[/tex] and remainder be 39.
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What is the sum of ∞Σn=1 2(1/5)^n-1? s=1/5 s=2/5 s=5/3 s=5/2
Answers
The sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2
How to determine the sum of the notation?The sum notation is given as:
∞Σn=1 2(1/5)^n-1
The above notation is a geometric sequence with the following parameters
Initial value, a = 2Common ratio, r = 1/5The sum is then calculated as
S = a/(1 - r)
The equation becomes
S = 2/(1 - 1/5)
Evaluate the difference
S = 2/(4/5)
Express the equation as products
S = 2 * 5/4
Solve the expression
S= 5/2
Hence, the sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2
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Answer:
S = 5/2
Thank me later
need heeeelp please
Answers
Answer:
(x, y) = (-√3/2, 1/2)
Step-by-step explanation:
The terminal point for that angle can be read from a unit circle chart.
On the attached chart, the point of interest is the first one above the -x axis on the left side. The chart tells you the coordinates are ...
(x, y) = (-√3/2, 1/2)
Sodas cost $1.75 each. Write a direct
proportional equation using (s) for sodas and
(t) for total cost.
Answers
Answer:
t = 1.75(s)
Step-by-step explanation:
I gotchu
Stopyra Incorporated makes a single product—a cooling coil used in commercial refrigerators. The company has a standard cost system in which it applies overhead to this product based on the standard labor-hours allowed for the actual output of the period. Data concerning the most recent year appear below:
Budgeted variable manufacturing overhead $ 28,200
Budgeted fixed manufacturing overhead $ 89,280
Budgeted hours 12,000 labor-hours
Actual production (a) 16,000 units
Standard hours per unit (b) 0.60 labor-hours
Standard hours allowed for the actual production (a) × (b) 9,600 labor-hours
Actual variable manufacturing overhead $ 26,967
Actual fixed manufacturing overhead $ 74,280
Actual hours 8,900 labor-hours
The variable overhead rate variance is:
$6,528 U
$6,528 F
$6,052 U
$6,052 F
Answers
The variable overhead rate variance is: c. $6,052 U.
Variable overhead rate varianceFirst step is to calculate variable component of the predetermined overhead rate using this formula
Variable component of the predetermined overhead rate= Budgeted variable manufacturing overhead/Budgeted hours
Let plug in the formula
Variable component of the predetermined overhead rate=$ 28,200/12,000 labor-hours
Variable component of the predetermined overhead rate=$2.35 per labor-hour
Second step is to calculate variable overhead rate variance using this formula
Variable overhead rate variance=(AH×AR)-(AH×SR)
Let plug in the formula
Variable overhead rate variance= $ 26,967- ( 8,900 labor-hours×$2.35 per labor-hour)
Variable overhead rate variance= $ 26,967- $20,915
Variable overhead rate variance= $6,052 U (Unfavorable)
Therefore the variable overhead rate variance is: c. $6,052 U.
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What are the first five terms in the recursive sequence defined by the following? (only one is correct)
a1= 1
a2=1
an= an-2+an-1
a) {1,1,2,3,5}
b) {1,1,0,-1,-1}
c) {2,3,5,8,13}
d) {1,-1,2,-3,5}
Answers
Answer:
d 1-12-3-5 is the answer
x+2y=5 and 4x+12y=-20 elimination method
Answers
Answer:
x=25 and y=-10
Step-by-step explanation:
x+2y=5 ..........(1)
4x+12y=-20.........(2)
using elimination method.
multiply equ(1) by 4 and equ(2) by 1
so we have
x+2y=5..........*4
4x+12y=-20.........*1
4x+8y=20................(3)
4x+12y=-20.............(4)
subtract eq(4) from (3) we have
-4y=40
y=-10
substitute y=-10 in equation (1)
we have:
x+2(-10)=5
x-20=5
x=25
What's the Value of X in 1/2 + X = 5/6
Answers
Answer:
x = 1/3
Step-by-step explanation:
1/2 + X = 5/6
collecting the like terms
X = 5/6 - 1/2
making one fraction on the left side by taking the common denominator
X = (5 - 3)/6
X = 2/6
devide the numerator and denominator by 2, you get
X = 1/3
Madison finished 4/5 of her homework before dinner. What percent of Maddison’s homework is left to finish?
Answers
Answer:
1/5 of it
Step-by-step explanation:
5/5 represents all of her homework
5/5-4/5= 1/5
4/5 represents the homework she did before dinner
1/5 represents the homework left to do
What are the potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2?
Answers
The potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)
How to determine the potential zeros of the function f(x)?The function is given as:
f(x)=6x^4+ 2x^3 - 4x^2 +2
For a function P(x) such that
P(x) = ax^n +...... + b
The rational roots of the function p(x) are
Rational roots = ± Possible factors of b/Possible factors of a
In the function f(x), we have:
a = 6
b = 2
The factors of 6 and 2 are
a = 1, 2, 3 and 6
b = 1 and 2
So, we have:
Rational roots = ±(1, 2)/(1, 2, 3, 6)
Split the expression
Rational roots = ±1/(1, 2, 3, 6)/ and ±2/(1, 2, 3, 6)
Evaluate the quotient
Rational roots = ±(1, 1/2, 1/3, 1/6, 2, 1, 2/3, 1/3)
Remove the repetition
Rational roots = ±(1, 1/2, 1/3, 1/6, 2, 2/3)
Hence, the potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)
The complete parameters are:
The function is given as:
f(x) = 3x^3 + 2x^2 + 3x + 6
The potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)
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Help me with this equation, please. (Image Attached)
Answers
So, the equation is sin(x + y)/sin(x - y) = (1 + cotxstany)/(1 + cotxtany)
The question has to to with trigonometric identities?
What are trigonometric identities?Trigonometric identities are equations that show the relationship between the trigonometric ratios.
How to solve the equation?Given the equation sin(x + y)/sin(x - y)
Using the trigonometric identities.
sin(x + y) = sinxcosy + cosxsiny andsin(x - y) = sinxcosy - cosxsinySo, sin(x + y)/sin(x - y) = (sinxcosy + cosxsiny)/(sinxcosy + cosxsiny)
Dividing the rnumerator and denominator of ight hand side by sinx, we have
sin(x + y)/sin(x - y) = (sinxcosy + cosxsiny)/sinx/(sinxcosy + cosxsiny)/sinx
sin(x + y)/sin(x - y) = (sinxcosy/sinx + cosxsiny/sinx)/(sinxcosy/sinx + cosxsiny/sinx)
= (cosy + cotxsiny)/(cosy + cotxsiny) (since cosx/sinx = cotx)
Dividing the numerator and denominator of the right hand side by cosy, we have
= (cosy + cotxsiny)/cosy/(cosy + cotxsiny)/cosy
= (cosy/cosy + cotxsiny/cosy)/(cosy/cosy + cotxsiny/cosy)
= (1 + cotxstany)/(1 + cotxtany) [since siny/cosy = tany]
So, sin(x + y)/sin(x - y) = (1 + cotxstany)/(1 + cotxtany)
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Which expression represents seven less than the product of thirteen times a number, and two squared?
(13x + 22) · 7
7(13x · 22)
7 + 13x + 22
7 + 13x · 22
(13x · 22) − 7
Answers
Seven less than the product of thirteen times a number, and two squared is as follows;
(13x × 2²) - 7
How to represent an expression?The expression says seven less than the product of thirteen times a number, and two squared.
Let
the number = x
Hence, the product of thirteen times a number, and two squared is as follows:
13(x)(2²)
Therefore, seven less than the product of thirteen times a number, and two squared is as follows;
(13x × 2²) - 7
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What is the best estimated volume of the figure?
can anyone solve this for me with a detailed explanation step by steps and reasoning so i can grasp concepts
Answers
The answer is 756 m³.
The formula to find volume is : length × width × height
To estimate, round each dimension to the nearest whole number.
⇒ 12.3 ≅ 12
⇒ 7.2 ≅ 7
⇒ 8.6 ≅ 9
Volume = 12 × 7 × 9
Volume = 84 × 9
Volume = 756 m³
Answer:
The ans to this question is 756 which is Option (B)
Step-by-step explanation:
Estimate volume = rounding every digit
= 12.3 = 12
= 7.2 = 7
= 8.6 = 9
= 12x7x9 = 756
Write the ratio of 4 roses to 24 flowers
Answers
Initially we have 4:24 meaning 4 roses for 24 flowers. However, we can simplify this ration same as we do to fractions. If we divided both sides of the ration by 4, we get 1:6, or 1 rose for every 6 flowers.
Answer:
4:24 or also 1:6
Step-by-step explanation:
Find the value of z.
X
7
Y
3
Z
Z = √[?]
Answers
Answer:
z = [tex]\sqrt{30}[/tex]
Step-by-step explanation:
using the Altitude- on- Hypotenuse theorem
(leg of big Δ )² = (part of hypotenuse below it ) × (whole hypotenuse)
z² = 3 × (3 + 7) = 3 × 10 = 30 ( take square root of both sides )
z = [tex]\sqrt{30}[/tex]
The quadratic functions shown are written in factored form. The roots of a quadratic function will make the factors equal to 0.
Drag each function to show whether it has roots at x=−2 and x=3, roots at x=2 and x=−3, or neither.
Answers
The following classification of quadratic equations is presented below:
x = - 2 and x = 3: h(x) = (x + 2) · (x - 3), k(x) = - 3 · (x + 2) · (x - 3). x = 2 and x = - 3: g(x) = 8 · (x + 3) · (x - 2), m(x) = (x + 3) · (x - 2). Neither: j(x) = (x - 2) · (x - 3)How to classify quadratic equations in terms of its roots
In this problem we have quadratic equations in factored form, whose form is presented below:
y = a · (x - r₁) · (x - r₂) (1)
Where r₁ and r₂ are the roots of the equation and a is the leading coefficient. A value of x is a root if and only if y is zero. Besides, we must located all the quadratic equations according to their roots.
x = - 2 and x = 3
h(x) = (x + 2) · (x - 3)
k(x) = - 3 · (x + 2) · (x - 3)
x = 2 and x = - 3
g(x) = 8 · (x + 3) · (x - 2)
m(x) = (x + 3) · (x - 2)
Neither
f(x) = 3 · (x - 1) · (x + 2)
j(x) = (x - 2) · (x - 3)
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Using two six-sided number cubes, each labeled with the numbers 1 through 6, event A is rolling a sum less than 6. Which of the following shows the sample space of event A?
{(1, 1), (1, 3), (1, 4), (1, 5), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3)}
{(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1)}
{(1, 1), (1, 2), (1, 3), (1, 5), (2, 1), (2, 2), (2, 3), (3, 1), (3, 3), (4, 1)}
{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (3, 3), (4, 1), (4, 2)}
Answers
the sample space is:
{ (1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (3, 1), (4, 1), (2, 2), (2, 3), (3, 2)}
Which of the following shows the sample space of event A?Event A is rolling a sum less than 6.
Let's define the possible elements in this experiment as:
(outcome of dice 1, outcome of dice 2)
The outcomes where the sum is less than 6 are:
dice 1 dice 2 sum
1 1 2
1 2 3
1 3 4
1 4 5
2 1 3
3 1 4
4 1 5
2 2 4
3 2 5
2 3 5
So there are 10 outcomes, then the sample space is:
{ (1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (3, 1), (4, 1), (2, 2), (2, 3), (3, 2)}
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Answer:
B) {(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1)}
Step-by-step explanation:
If the question said less than 6 meaning you have to find all possible solution that are 5 or lower.
However, if the problem said equal or less than 6 then you have to find all possible solution that are 6 or lower.
B option is only option that don't have sum of 6. Therefore, option B is correct.
WILL GIVE BRAINLIEST
Directions: Factor the following trinomials containing negative numbers. Follow the rules for operations with signed numbers to identify the correct binomial factors.
1. x2 + 6x - 7
2. x2 - 5x + 6
3. x2 - 6x - 7
4. x2 + 5x - 6
5. x2 + x - 12
6. x2 - 2x - 8
7. x2 - 4x - 5
8. x2 + 2x - 3
9. x2 - 16
10. x2 - x - 12
11. x2 -9x + 18
12. x2 -5x - 14
13. x2 - 7x + 10
14. x2 -11x + 24
15. x2 - x - 30
Answers
Factorization refers to the process by which the terms that are common in an expression are obtained.
What is factorization?Factorization refers to the process by which the terms that are common in an expression are obtained.
Given the trinomials, the correct binomial factors are;
1) (x−1)(x+7)
2) (x−2)(x−3)
3) (x+1)(x−7)
4) (x−1)(x+6)
5) (x−3)(x+4)
6) (x+2)(x−4)
7) (x+1)(x−5)
8) (x−1)(x+3)
9) (x+4)(x−4)
10) (x+3)(x−4)
11) (x−3)(x−6)
12) (x+2)(x−7)
13) (x−2)(x−5)
14) (x−3)(x−8)
15) (x+5)(x−6)
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Alok started a business investing Rs 90, 000. After three
months Prabir joined him with capital of Rs 1,20000
If at the end of 2 years, the total profit made
by them was
Rs 96,000 what will the difference
between Alok and Prabir's share in it?
Answers
The difference between Alok and Prabir share exists 8000.
What will the difference between Alok and Prabir share?Given: Invested by Alok = Rs 90, 000
Invested by Prabir = Rs 1,20000
The time period of Alok = 3 months
The time period of Prabir = 2 years
They earn a profit = Rs 96,000.
Profit exists directly proportional to the product of the amount invested and the time period of investment.
8000 = 90000 [tex]*[/tex] 24/120000 [tex]*[/tex] 21
= 5/7
5x + 7x = 96000
x = 8000
first = 40000
second = 48000
so the difference exists at 8000.
The difference between Alok and Prabir share exists 8000.
Therefore, the correct answer is 8000.
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pleaseee helpp
which of the following enequalities would produce the region indicated on the graph below
Answers
Answer: C
Step-by-step explanation:
The line [tex]y=x+2[/tex] is shaded below and is solid.
This eliminates all the options except for C.
Will mark brainliest
Answers
Using the given definition and [tex]\Delta x=\frac{0-(-2)}n=\frac2n[/tex], we have
[tex]\displaystyle \int_{-2}^0 (7x^2+7x) \,dx = \lim_{n\to\infty} \sum_{i=1}^n \left(7\left(-2+\frac{2i}n\right)^2 + 7\left(-2+\frac{2i}n\right)\right) \frac2n \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac2n \sum_{i=1}^n \left(14 - \frac{42i}n + \frac{28i^2}{n^2}\right)[/tex]
Recall the well-known power sum formulas,
[tex]\displaystyle \sum_{i=1}^n 1 = \underbrace{1 + 1 + 1 + \cdots + 1}_{n\,\rm times} = n[/tex]
[tex]\displaystyle \sum_{i=1}^n i = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2[/tex]
[tex]\displaystyle \sum_{i=1}^n i^2 = 1 + 4 + 9 + \cdots + n^2 = \frac{n(n+1)(2n+1)}6[/tex]
Reducing our sum leads to
[tex]\displaystyle \int_{-2}^0 (7x^2+7x) \,dx = \lim_{n\to\infty} \frac2n \left(\frac{7n}3 - 7 + \frac{14}{3n}\right) = \lim_{n\to\infty} \left(\frac{14}3 - \frac{14}n + \frac{28}{3n^2}\right)[/tex]
As [tex]n[/tex] goes to ∞, the rational terms containing [tex]n[/tex] will converge to 0, and the definite integral converges to
[tex]\displaystyle \int_{-2}^0 (7x^2+7x) \,dx = \boxed{\frac{14}3}[/tex]
add the two equations, 0.75x+1.5y=40 and −1.5x−1.5y=−60 , to find the value of x .
Answers
The value of x in the equation is 26.7
How to solve an equation?0.75x + 1.5y = 40
−1.5x − 1.5y = −60
add both equation to eliminate y .
Therefore,
−1.5x + 0.75x = -0.75x
1.5y + (- 1.5y) = 0
40 + (-60) = -20
Hence,
-0.75x = - 20
divide both sides by -0.75
-0.75x / -0/75 = - 20 / -0.75
x = - 20 / -0.75
x = 26.6666666667
x = 26.7
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Write your answer as a fraction in simplest form.
-1 3/4 • 2 1/8
Answers
|3x-1|=4 help pleaseeeeeeeeee
Answers
Answer: x = -1 or x = 5/3
Step-by-step explanation:
|3x - 1| = 4
=> 3x - 1 = 4 or 3x - 1 = -4
=>x = 5/3 or x = -1
I need help solving this problem!
Answers
Answer: A
Step-by-step explanation:
The domain is the range of possible x that doesn't make y impossible to find, in this case, all real numbers work
The range is the range of possible y that doesn't make x impossible to find in the inverse function, in this case, all real numbers work
The answer is A.
As any number can be replaced in place of x for the function y, the domain of the function is All Real Numbers. Since any number can be inputted, the result will also vary accordingly. Hence, the range of the function is All Real Numbers.
This is true for the listed function :
[tex]\boxed {y = \sqrt[3]{x-2} - 5}[/tex]
