Select all statements that are true about the linear equation.

y=−2x+4
t or f-The graph of the equation is the set of points that are solutions to the equation.
t or f-The point (0, 2) lies on the graph of the equation.
t or f-The graph of the equation is the set of all points on the coordinate plane.
t or f-The point (1, 2) lies on the graph of the equation.

Answer:

D

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

Answer:

2x^2+x-6

Step-by-step explanation:

Use the F.O.I.L method

2x^2+4x-3x-6

Answer:

1.

Step-by-step explanation:

Answer:

4.6620663x10^19 or 46,620,663,000,000,000,000 total configurations

Step-by-step explanation:

Since each couple must get adjacent seats, we can first think of the row as having 17 seats instead of 34 since the people in each pair does not change and we consider instead the position of the pair rather than the two people.

There are 17 places where each couple can sit in the 34 chairs. Therefore the number of ways to order the 17 pairs (regardless of the order of individual people in those pairs) is 17!.

This is because first place could be taken by any of the 17 couples so there are 17 possibilities. After the first place is taken, there are only 16 possible couples to take the second place to we have 17x16. After the first two are taken there are only 15 possible couples to take the third place so we multiply by 15. This continues with each respective place so the total number of configurations is: 17x16x15x14x13x12x11x10x9x8x7x6x5x4x3x2x1 OR 17! which is equal to 3.5568743x10^14, or 355,687,430,000,000 different configurations.

Now we must also consider the order of the individual people in the pairs as one can sit on the left or on the right of the other person (e.g. 1,2 or 2,1). And since each pair can have two possible orders, every possible configuration of the pairs in the 17 places must be multiplied by 2^17 to accommodate for this (2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2 for the 17 couples), which is equal to: 131072

Therefore the total number of ways to seat 17 couples in a row of 34 is 131072x355,687,430,000,000= 4.6620663x10^19 or 46,620,663,000,000,000,000 total configurations.

Hope this helped!

Answer:

2^17 × 17!

Step-by-step explanation:

Seat 1 = 34 possibilities

Seat 2 = 1 possibility

Seat 3 = 32 possibilities

Seat 4 = 1 possibility

And so on

So it is 34 × 32 × 30 × ... × 2

So it is

[tex] {2}^{17} \times 17factorial[/tex]

I hope this helps you :)

Answer:

Alright, angle 4 IS congruent, angle 8 is ALSO congruent, and angle 1 is congruent.

Angle 7 is not congruent :)

Step-by-step explanation:

Sp = rs 800

loss = 10%

Cp = ?

we know that,

cp= sp×100÷ 100-L%

= 800×100÷100-10

= 80000÷90

= 888.89#

Answer:

8000/9

Step-by-step explanation:

Loss%=CP-RS/CP*100%------------------------------------------- The formula

 Let's substitute

10/100=CP-800/CP

  Crisscross it

10*CP=100(CP-800)

10CP=100CP-80000

-90CP= -80000

CP=-80000/-90=           So the answer is 8000/9            

Notice that I understand "rs" as selling price

To determine the marginal and conditional probability distributions across states, we examine the given joint probability distribution. Let's denote the endowment in period t as yt and in period t+1 as yt+1.

(a) The marginal probability distribution of yt represents the probabilities of different endowment values in period t. From the joint probability distribution, we can see that:

[tex]Pr(yt=L) = Pr(yt+1=L, yt=L) + Pr(yt+1=L, yt=H) = 0.2 + 0.1 = 0.3Pr(yt=H) = Pr(yt+1=H, yt=L) + Pr(yt+1=H, yt=H) = 0.1 + 0.5 = 0.6[/tex]

The conditional probability distribution represents the probabilities of different endowment values in period t+1 given the endowment value in period t. From the joint probability distribution, we have:

Pr(yt+1=L | yt=L) = 0.2/0.3 ≈ 0.667

Pr(yt+1=H | yt=L) = 0.1/0.3 ≈ 0.333

Pr(yt+1=L | yt=H) = 0.1/0.6 ≈ 0.167

Pr(yt+1=H | yt=H) = 0.5/0.6 ≈ 0.833

(b) The price of a one-period bond represents the expected present value of receiving one unit of the endowment in the next period, given the current state. In period one, the price of a one-period bond for each possible state is given by:

[tex]Price(y1=L) = Pr(y2=L | y1=L) * 1 + Pr(y2=H | y1=L) * 1 = 0.667 + 0.333 = 1Price(y1=H) = Pr(y2=L | y1=H) * 1 + Pr(y2=H | y1=H) * 1 = 0.167 + 0.833 = 1[/tex]

(c) The price of a ten-period bond represents the expected present value of receiving ten units of the endowment in the next ten periods, given the current state. In period one, the price of a ten-period bond for each possible state is given by:

[tex]Price(y1=L) = Pr(y2=L | y1=L) * 1 + Pr(y2=H | y1=L) * 2 + ... + Pr(y11=L | y1=L) * 10 = 0.667 + 0.667 + ... + 0.667 = 6.67Price(y1=H) = Pr(y2=L | y1=H) * 1 + Pr(y2=H | y1=H) * 2 + ... + Pr(y11=L | y1=H) * 10 = 0.167 + 0.167 + ... + 0.167 = 1.67[/tex]

(d) The unconditional mean price for the one-year bond is the average of the prices for each possible state in period one:

Unconditional mean price for one-year bond =

(Price(y1=L) + Price(y1=H)) / 2 = (1 + 1) / 2 = 1 The unconditional mean price for the ten-year bond is the average of the prices for each possible state in period one:

Unconditional mean price for ten-year bond = (Price(y1=L) + Price(y1=H)) / 2 = (6.67 +

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Approximately 99.7% of employees in the company earn between $5.40 and $24.60 per hour.

To find the interval within which 99.7% of employees' salaries fall, we can use the properties of the normal distribution.

Given:

Mean (μ) = $15.00 per hour

Standard deviation (σ) = $3.20

In a normal distribution, approximately 99.7% of the data falls within three standard deviations of the mean. So, we can calculate the interval as follows:

Lower bound = μ - 3σ

Upper bound = μ + 3σ

Lower bound = $15.00 - 3 * $3.20

= $15.00 - $9.60

= $5.40

Upper bound = $15.00 + 3 * $3.20

= $15.00 + $9.60

= $24.60

Therefore, approximately 99.7% of employees in the company earn between $5.40 and $24.60 per hour.

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Answer: L=-0.5t + 10

Step-by-step explanation:

                                       [tex]\left[\begin{array}{ccc}Your\;Answer\;is\;1.\end{array}\right][/tex]

[tex]Explanation[/tex] \/

Find the prime factorization of 6

[tex]6=2*3[/tex]

Find the prime factorization of 35

[tex]35 = 5 * 7[/tex]

To find the GCF, multiply all the prime factors common to both numbers:

Therefore, [tex]GCF = 1[/tex]

1 is the largest positive integer that divides both 6 and 35 without leaving a remainder.

The greatest common factor (GCF), also known as the greatest common divisor (GCD), of two numbers is the largest positive integer that divides both of the numbers without leaving a remainder.

Step 1: Prime factorization of 6

The prime factors of 6 are 2 and 3.

So, 6 = 2 * 3.

Step 2: Prime factorization of 35

The prime factors of 35 are 5 and 7.

So, 35 = 5 * 7.

Step 3: Determine the common prime factors

The common prime factors of 6 and 35 are 1.

Step 4: Multiply the common prime factors

Multiplying the common prime factors gives us 1.

Therefore, the GCF of 6 and 35 is 1.

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a. The transition matrix P from the standard basis to the prime basis can be found by arranging the columns of the prime basis vectors as the coefficients of the standard basis vectors.

b. Using the transition matrix P and matrix A, we can find the coordinate vectors [v] and [T(v)] with respect to the prime basis.

c. The inverse of the transition matrix P can be calculated, and it represents the transition from the prime basis to the standard basis. The matrix for T relative to the prime basis can be found using the formula T' = P^(-1)AP.

d. The coordinate vector [T(v)]' with respect to the prime basis can be obtained by multiplying the matrix for T relative to the prime basis with the coordinate vector [v]'.

a. To find the transition matrix P from the standard basis to the prime basis, we arrange the prime basis vectors as columns of the matrix. So, P = [(1, -2), (3, -2)].

b. Given the matrix A and the vector [v]' = [-1, 2] with respect to the prime basis, we can find the coordinate vector [v] with respect to the standard basis by multiplying [tex]P^{-1}[/tex] with [v]'. Then, [tex][v] = P^{-1}[v]'[/tex].

c. The inverse of matrix P, denoted as [tex]P^{-1}[/tex], can be calculated. To find the matrix for T relative to the prime basis, denoted as T', we use the formula [tex]T' = P^{-1}AP[/tex].

d. To find [T(v)]' with respect to the prime basis, we multiply the matrix T' with the coordinate vector [v]'. So, [T(v)]' = T'[v]'.

By following these steps, we can find the transition matrix, coordinate vectors, and matrix representations for T with respect to different bases.

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Answer:

lw

Step-by-step explanation:

The formula to find the area of a rectangle is A = lw

A = Area

l = length

w = width

The rearranged equation for V is V = 25 / (14.475 + 2.625g). This expression represents the value of V in terms of the given equation and the variable g.

To rearrange the equation (0.75V * 19.3) + (0.25V * 10.5) * g = 25 for V, we can start by expanding and simplifying the terms on the left side of the equation. The equation becomes (14.475V) + (2.625V * g) = 25.

Next, we can combine like terms by adding the coefficients of V. This gives us (14.475 + 2.625g)V = 25.

To isolate V, we divide both sides of the equation by the coefficient (14.475 + 2.625g). This results in V = 25 / (14.475 + 2.625g).

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Answer:

x=20

Step-by-step explanation:

3x-1+31+90=180

Combine like terms

3x+120=180

Subtract by 120 on both sides

3x=60

x=20

Answer:

59 degrees

Step-by-step explanation:

so first things first you have the tringle it has a right angle meaning that this triangle will equal 90 degrees so here is what our equation would look like:

90=31+(3x-1)

So in order to solve this equation you must subtract add and divide.

First Rule in doing these equations: what you do to one side of the equal sign you do to the other side.

so we subtract 31 from 90 to equal 59 so the equation looks like this:

59=(3x -1)

you then add a one to the negative one and the 59 to get 60 making the equation look like this

60= 3x

we then divide 60 by 3 to get 20

so 20= x

But this is not our answer this is simply the solvation for x in (3x - 1)

so the equation now looks like this (3(20) - 1) and this equals 59 degrees

now to check our work!

31 + 59 = 90 or 90- 31 = 59

Answer:

They finish at 2:15.

Step-by-step explanation:

One hour equals 60 minutes,  and on clocks, they go up to 59 minutes on the right side.

So, if we add 60 to the 15 on the minute side, we get 1:75, this leaves the 15 minutes remaining, and adds one to the left side, leaving us with 2:15.

Let me know if there are any questions, I tried my best to explain!

Answer:

see below

Step-by-step explanation:

1.  The inverse means take the not of both sides

If it is Saturday, then there is no school.

 Inverse     If it is not Saturday, then there is school.

The converse flips the then and the if

If there is no school, then it is Saturday.

2.) The first given part is the if, what will happen is the then part

If you are a freshman, then you are required to attend orientation.

3.)

Given: 3x+1=-14 Prove: x=-5

Statements    Reasons

1. 3x+1=-14     Given

2. 3x=-15          Subtraction Property of equality  ( since we subtract 1 from                         each side)

3. X=-5          Division Property  ( since we divide each side by 3)

Answer:

1. 24

2. [tex]10+2n[/tex] where n denotes number of days.

3. 70

Step-by-step explanation:

1.

Consider the sequence: [tex]12,14,16,18,...[/tex]

Here,

[tex]14-12=2\\16-14=2\\18-16=2[/tex]

Take the common difference as d = 2 and the first term as a = 12

Use the formula: [tex]a_n=a+(n-1)d[/tex]

To find expected gain at the end of the week, find [tex]a_7[/tex]

[tex]a_7=12+(7-1)2\\=12+6(2)\\=12+12\\=24[/tex]

2.

Yes, the gain shows the pattern.

Put [tex]a=12,d=2[/tex] in [tex]a_n=a+(n-1)d[/tex]

[tex]a_n=12+(n-1)2\\=12+2n-2\\=10+2n[/tex]

Here, n denotes number of days.

3.

To find expected gain at the end of 30  days, put [tex]n=30[/tex] in [tex]a_n=10+2n[/tex]

[tex]a_{30}=10+2(30)\\ =10+60\\=70[/tex]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Cost of large candle (a) = 25 each

Cost of small candles (y) = 10 each

Amount needed = $600

Number of each that must be sold to raise needed amount:

25a + 10y = 600.

Here a = number of large candles that must be sold at the price

y = number of small candles that must be sold at the price

Summing the revenue both should result in the required amount.

Answer:

Step-by-step explanation:

Area of a circle = πr²

where

r is the radius of the circle

From the question

r = 58 cm

The area of the circle is

A = 58²π

= 3364π

= 10568.3176866761...

We have the final answer as

Hope this helps you

Here we are given with the radius of a circle and we have to find the area using formula.

✤ Formula for finding area of a circle:

[tex] \large{ \boxed{ \sf{\red{Area \: of \: \circ = \pi {r}^{2} }}}}[/tex]

Where r is the radius of the circle. So let's plug in the values for finding the area of the circle:

➝ Area = π(58 cm)²

➝ Area = 3.14 × 58 cm × 58 cm

➝ Area = 10562.96 cm²

Now let's round off upto 3 significant figures: 10600 cm² (Answer)

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Answer:

[tex]x=3[/tex]

Step-by-step explanation:

[tex]x+3=6[/tex]

Subtract 3 from both sides:

[tex]x+3-3=6-3\\x=3[/tex]

Hope this helps!

TestedHyperr

The missing value is for the givens series is found to be 31.

To find the missing value of the given set of data values, we first need to understand the concept of median. The median is the middle value when a data set is ordered.

In other words, it is the value that separates the lower half of the data from the upper half.

Given that the median for the given set of six ordered data values is 30.5 and we have to find the missing value, we can proceed as follows:

Since the median is the middle value when a data set is ordered, we have to find the middle value.

As we know, there are 6 values in total, so there will be two middle values.

Therefore, we have to take the average of the two middle values.

The given set of data values are 9, 12, 21, __, 41, and 50.

To find the missing value, let us calculate the average of the two middle values, which is 30.5.

We know that the two middle values are 21 and 41.

Now we can apply the formula to find the average of the two middle values:

Average of the two middle values = (21 + 41) / 2

= 62 / 2

= 31

So, the missing value is 31.

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While there is agreement on the use of focus groups for evaluating brand names, there are differences in the methods proposed for identifying symbolism associated with posting selfies and searching for ideas for new applications.

In comparing my initial post with my classmate's initial post, there are both areas of agreement and disagreement regarding the research methods suggested for different scenarios.

Agreement:

Both my initial post and my classmate's post agree on the use of focus groups for evaluating potential brand names for a new app. Focus groups allow for gathering opinions and insights from individuals in a controlled environment, as my classmate mentioned. I also referenced Babin (2019) to support this method.

Disagreement:

In terms of identifying the symbolism associated with posting selfies online, I suggested using detailed interviews, while my classmate proposed depth interviews.

While both methods aim to uncover deeper motivations and intentions, my classmate specifically highlighted the need for probing and asking a series of questions. Both approaches can provide valuable insights, but the emphasis on depth interviews suggests a more targeted and focused approach.

For searching for ideas for new smartphone or tablet applications, I suggested conducting detailed interviews with target customer groups, while my classmate proposed creating an attribute list.

While my suggestion focuses on gathering specific customer preferences and needs through direct interaction, my classmate's suggestion of attribute listing involves breaking down existing products and recombining their attributes to generate new ideas. These are two different approaches to idea generation, and the choice depends on the specific context and objectives of the research.

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a.  MUx = ∂u/∂x1 = 1 - x1

And MUy = ∂u/∂x2 = 1 - x2

b. This suggests that Elena's utility function does not satisfy monotonicity or strict monotonicity.

c. MRSx,y = MUx / MUy = (1 - x1) / (1 - x2)

d. We also have the budget constraint:

Px * x1 + Py * x2 = I

4x1 + 10x2 = 1200

(a) To find the marginal utilities (MUx and MUy), we need to differentiate the utility function with respect to each variable.

Given:

u(x1​,x2​) = (x1​−21​x12​)+(x2​−21​x22​)

Differentiating with respect to x1:

∂u/∂x1 = 1 - 2x1/2 = 1 - x1

Differentiating with respect to x2:

∂u/∂x2 = 1 - 2x2/2 = 1 - x2

So, MUx = ∂u/∂x1 = 1 - x1

And MUy = ∂u/∂x2 = 1 - x2

(b) Monotonicity requires that if x increases, then utility should increase as well. Strict monotonicity requires that utility strictly increases as x increases.

In this case, since MUx = 1 - x1 and MUy = 1 - x2, we can see that both marginal utilities decrease as their respective goods' quantities increase. This suggests that Elena's utility function does not satisfy monotonicity or strict monotonicity.

(c) The Marginal Rate of Substitution (MRS) between two goods, x and y, is given by the ratio of their marginal utilities:

MRSx,y = MUx / MUy = (1 - x1) / (1 - x2)

(d) To find the equilibrium quantities for goods x and y, we need to set the MRS equal to the price ratio Px / Py and solve for x1 and x2.

MRSx,y = (1 - x1) / (1 - x2) = Px / Py = 4 / 10 = 2 / 5

Now we can solve for x1 and x2. Rearranging the equation:

(1 - x1) / (1 - x2) = 2 / 5

Cross-multiplying:

5(1 - x1) = 2(1 - x2)

Expanding:

5 - 5x1 = 2 - 2x2

Rearranging terms:

5x1 - 2x2 = 3

We also have the budget constraint:

Px * x1 + Py * x2 = I

4x1 + 10x2 = 1200

Now we have a system of two equations with two variables. Solving this system will give us the equilibrium quantities for goods x and y.

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Answer:

a) b = 8, c = 13

b) The equation of graph B is y = -x² + 3

Step-by-step explanation:

* Let us talk about the transformation

In the given question

∵ y = x² - 3

∵ The graph is translated 4 units to the left

→ That means substitute x by x + 4 as 4th rule above

∴ y = (x + 4)² - 3

→ Solve the bracket to put it in the form of y = ax² + bx + c

∵ (x + 4)² = (x + 4)(x + 4) = (x)(x) + (x)(4) + (4)(x) + (4)(4)

∴ (x + 4)² = x² + 4x + 4x + 16

→ Add the like terms

∴ (x + 4)² = x² + 8x + 16

→ Substitute it in the y above

∴ y = x² + 8x + 16 - 3

→ Add the like terms

∴ y = x² + 8x + 13

∴ b = 8 and c = 13

a) b = 8, c = 13

∵ The graph A is reflected in the x-axis

→ That means y will change to -y as 1st rule above

∴ -y = (x² - 3)

→ Multiply both sides by -1 to make y positive

∴ y = -(x² - 3)

→ Multiply the bracket by the negative sign

∴ y = -x² + 3

b) The equation of graph B is y = -x² + 3

In question 1, we will show that the set W = {(a, 0, b) | a, b ∈ R} is a subspace of R³. In question 2, we will determine if the set W = {(a, 2, b) | a, b ∈ R} is a subspace of R³. In question 3, we will prove that the set W = {au + Bvla | ß ∈ R} is a subspace of vector space V, given u and v as vectors in V. In question 4, we will prove that Ov = 0 for all vectors v ∈ V.

1. To show that W = {(a, 0, b) | a, b ∈ R} is a subspace of R³, we need to verify three conditions: (i) W is non-empty, (ii) W is closed under addition, and (iii) W is closed under scalar multiplication. By checking these conditions, we can conclude that W is indeed a subspace of R³.

2. To determine if W = {(a, 2, b) | a, b ∈ R} is a subspace of R³, we again need to check the three conditions: (i) non-empty, (ii) closed under addition, and (iii) closed under scalar multiplication. By analyzing these conditions, we can determine if W is a subspace or not.

3. Given vectors u and v in vector space V, we need to prove that the set W = {au + Bvla | ß ∈ R} is a subspace of V. To do so, we need to show that W satisfies the three conditions: (i) non-empty, (ii) closed under addition, and (iii) closed under scalar multiplication. By providing a proof for each of these conditions, we can establish that W is a subspace of V.

4. In a vector space V, we want to prove that Ov = 0 for all vectors v ∈ V. Here, O represents the zero vector in V. To demonstrate this, we need to show that Ov satisfies the properties of a zero vector, which include being an additive identity and scalar multiplication yielding the zero vector. By providing the necessary proof, we can establish that Ov = 0 for all vectors v ∈ V.

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Answer:

m∠RQS = 102

m∠TQS = 78

Step-by-step explanation:

m∠RQS = (20x + 2)°

m∠TQS = (15x + 3)°

m∠RQS + m∠TQS = 180°

20x + 2 + 15x + 3 = 180

35x + 5 = 180

35x = 175

x = 5

m∠RQS = 20(5) + 2 = 100 + 2 = 102

m∠TQS = 15(5) + 3 = 75 + 3 = 78

Answer:

m∠RQS = 102°

m∠SQT = 78°

General Formulas and Concepts:

Definition of a Line: A line is 180°

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Set up equation

m∠RQS and m∠SQT must add up to m∠RQT.

m∠RQS + m∠SQT = m∠RQT

(20x + 2) + (15x + 3) = 180

Step 2: Solve for x

Step 3: Find m∠RQS

Step 4: Find m∠SQT