Select all the correct answers Each of these scatter plots has a line of fit for its data points. Which graphs have a line that is a line of best for the data
Answers
There should be as much as many dots above the line and below the line . The line of best fits represent the trend of the data whether positive or negative correlation
The graphs that have a line that is best for the data are
Graph 1
Graph 4
Related Questions
there are 550 students how many teachers were there be in ratio form
Answers
The ratio of teacher to student is equivalent so teacher to the student ratio is same for all the school A, B, C and D.
Equate the teacher to school ratio for school A and school C to obtain the number of teachers in school C.
[tex]\begin{gathered} \frac{15}{330}=\frac{x}{550} \\ x=\frac{15\cdot550}{330} \\ =25 \end{gathered}[/tex]The number of teacher is school C is 25.
Equate the teachers to students ratio for the school A and school D to obtain the number of students in school D.
[tex]\begin{gathered} \frac{15}{330}=\frac{36}{y} \\ y=\frac{36\cdot330}{15} \\ =792 \end{gathered}[/tex]
The number of students in school D is 792.
6.4 times m minus 12 equals 45.6
Answers
Given
6.4 times m minus 12 equals 45.6
To find: The value of m.
Explanation:
It is given that,
6.4 times m minus 12 equals 45.6.
Then,
[tex]\begin{gathered} 6.4m-12=45.6 \\ 6.4m=45.6+12 \\ 6.4m=57.6 \\ m=\frac{57.6}{6.4} \\ m=9 \end{gathered}[/tex]Hence, the value of m is 9.
In which type of composition does a soloist or a small group of instruments interact wi
dance suite
sonata
concerto
chamber music
Answers
Step-by-step explanation:
Hey! The correct answer is Chamber Music.
If f(x) = 2x + 3 and g(x) = 4x - 1, find f(4).A. 11B. 15C. 5D.17
Answers
You have the following expression for the function f(x):
f(x) = 2x + 3
In order to calculate the value of f(4), just replace x=4 into the function f(x) and simplify it:
f(4) = 2(4) + 3
f(4) = 8 + 3
f(4) = 11
Hence, the answer is:
A) 11
A movie with an aspect ratio of 1.25:1 is shown as a pillarboxed image on a 36-inch 4:3 television. Calculate the Areas of the TV, the Image and One Blackbar
Answers
Explanation
The television has a diagonal that measures 36 inches:
And the ratio is 4:3
[tex]\begin{gathered} \frac{w}{h}=\frac{4}{3} \\ w=\frac{4}{3}h \end{gathered}[/tex]We can use the Pythagorean theorem to find the height of the TV:
[tex]\begin{gathered} 36^2=h^2+w^2 \\ 36^2=h^2+(\frac{4}{3}h)^2 \\ 36^2=h^2(1+\frac{4^2}{3^{2}}) \\ 1296=h^2(1+\frac{16}{9}) \\ 1296=h^2\times\frac{25}{9} \\ h^2=1296\times\frac{9}{25} \\ h=\sqrt[]{1296\times\frac{9}{25}}=21.6 \end{gathered}[/tex]The height of the TV is 60 inches. It's width is:
[tex]w=\frac{4}{3}h=\frac{4}{3}\times21.6=28.8[/tex]w=80 inches
Therefore the area of the TV is
[tex]A_{TV}=w\times h=28.8\times21.6=622.08in^2[/tex]The move has an aspec ratio of 25:1 shown as a pillarboxed image. This means that this is what we see:
So we know that the image height is the same as the TV's, 21.6 inches.
The relation between it's height and it's width is:
[tex]\begin{gathered} \frac{w}{h}=\frac{1.25}{1} \\ w=1.25h \\ \text{if h = 21.6 in} \\ w=27in \end{gathered}[/tex]The area of the image is:
[tex]A_{\text{image}}=w_{\text{image}}\times h=27\times21.6=583.2[/tex]The area of the two blackbars is the difference between the area of the TV and the area of the image:
[tex]A_{2-blackbars}=A_{TV}-A_{image}=622.08-583.2=38.88in^{2}[/tex]Since we need to find the area of just one blackbar, we just have to divide the area of both blackbars by 2:
[tex]A_{1-blackbar}=\frac{A_{2-blackbars}}{2}=\frac{38.88}{2}=19.44in^{2}[/tex]Answer
• Area of the TV: ,622.08 in²
,• Area of the image: ,583.2 in²
,• Area of one blackbar: ,19.44 in²
Amanda is a fashion designer. She has 25 yards of silk material. The skirtAmanda is making requires 1 yards, the dress requires 4 yards, the shirtrequires 7 yards, and the pants requires yards.After making her pieces, how many yards of silk does Amanda have left?
Answers
To determine how much silk Amanda has at the end we need to substract the amount each pice need from the original amount:
[tex]\begin{gathered} 25-\frac{18}{7}-\frac{11}{2}-\frac{7}{4}-\frac{25}{7}=25-\frac{43}{7}-\frac{11}{2}-\frac{7}{4} \\ =25-\frac{86+77}{14}-\frac{7}{4} \\ =25-\frac{163}{14}-\frac{7}{4} \\ =25-\frac{652+98}{56} \\ =25-\frac{750}{56} \\ =\frac{1400-750}{56} \\ =\frac{650}{56} \\ =\frac{325}{28} \\ =11\frac{17}{28} \end{gathered}[/tex]Therefore Amanda has 11 17/28 yards of silk left.
Find the range of the graphed function.A. -9 < y < 5B. y is all real numbers.C. O < y < 10D. y > 0
Answers
The range of a function is all the values that the function can take on the y-axis.
So, the y values of this function are between -9 and 5.
It means that the range is:
A. -9 < y < 5
The population of one country changed from 23 million to 54 million. Use the information to find the unknown values in the bar diagrams a = L.347 b
Answers
The population of one country changed from 23 million to 54 million. Use the information to find the unknown values in the bar diagrams a = L.347 b
y
PLEASE HELP!!!! Explain in depth!!! In a geometry course, the grade is based on the average score on six tests, each worth 100 points. W. Orrier has an average of 88.5 on his first four tests. What is the lowest average he could obtain on his next two tests and still receive an A (an average of 90 or better)?
Answers
Answer:
93 marks
Step-by-step explanation:
If he has an average of 88.5 marks on the first four tests then the total score for these four tests is:
[tex]\implies 88.5 \times 4=354[/tex]
To obtain an average of at least 90 marks on each test the total number of marks needed for the six tests is:
[tex]\implies 90 \times 6=540[/tex]
So the minimum total marks he needs to obtain an A is 540.
To find the lowest average he could obtain on his next two tests to still receive an A, subtract the total for the first four tests from the total needed for the six tests and divide by two:
[tex]\implies \dfrac{540-354}{2}=\dfrac{186}{2}=93[/tex]
Therefore, he needs to score an average of at least 93 marks on his next two tests to still receive an A grade.
You are helping with some repairs at home. You drop a hammer and it hits the floor at a speed of 12 feet per second. If the acceleration due to gravity (g) is 32 feet/second2, how far above the ground (h) was the hammer when you dropped it? Use the formula:A.8.5 feetB.1.0 footC.2.25 feetD.18.0 feet
Answers
Solution
Step 1:
Given data:
[tex]\begin{gathered} v\text{ = 12} \\ \text{g = 32} \\ h\text{ = ?} \end{gathered}[/tex]Step 2:
[tex]\begin{gathered} v\text{ = }\sqrt{2gh} \\ \\ 12\text{ = }\sqrt{2\times32\times h} \\ \\ 12\text{ = }\sqrt{64h} \\ \\ Take\text{ square of both sides} \\ \\ 12^2\text{ = \lparen}\sqrt{64h})^2 \\ \\ 144\text{ = 64h} \\ \\ h\text{ = }\frac{144}{64}\text{ = 2.25 feet} \end{gathered}[/tex]Final answer
C. 2.25 feet
Convert 15% to a fraction. Write in lowest terms.Convert 26% to a fraction. Write in lowest terms.Read the "Fractions, Decimals & Percents" lesson. Then answer each of the following questions to practice converting between fractions, decimals and percents.
Answers
Convert 15% to a fraction. Write in the lowest terms.
So,
[tex]15\%=\frac{15}{100}=\frac{5\times3}{5\times20}=\frac{3}{20}[/tex]So, the answer will be 15% = 3/20
=========================================================
Convert 26% to a fraction. Write in the lowest terms.
So,
[tex]\frac{26}{100}=\frac{2\times13}{2\times50}=\frac{13}{50}[/tex]So, the answer will be 26% = 13/50
The steps for deriving the Quadratic formular are shown. Which best choose for the missing reason?
Answers
In the part inside the yellow circle, we multiplied by 1 the term -c/a, that is
[tex]-\frac{c}{a}=-\frac{c}{a}\times1=-\frac{c}{a}(\frac{4a}{4a})=-\frac{4ac}{4a^2}[/tex]where 1 was written as 4a/4a.
Since we must add this result to
[tex]\frac{b^2}{4a^2}[/tex]the answer is option C, change to LCD ( Least Common Denominator) because both terms must have the same denominator, which is 4a^2.
Last week you worked 28 hours, and earned $266. What is your hourly pay rate? $ per hour Give your answer in dollars and cents (like 5.50)
Answers
1) Gathering the data
Last week
28 worked hours = $266
What is your hourly pay rate?
2) To find out that, let's set a proportion
Worked hours $
28------------------------ 266
1--------------------------- x
Let's use the fundamental property of a proportion that allows us to cross multiply the ratios of that proportion
So the hourly pay rate is approximately $11.08 per hour.
Find the number of complex roots and the number of possible real roots for the equation: 2x^4-3x^3+x^2-7x+3=0
Answers
You have the following polynomial:
2x⁴ - 3x³ + x² + 7x + 3 = 0
Based on the grade of the previous polynomial, you can conclude that there are 4 roots.
The complex roots are always present in pairs. Then, it's possible the given polynomial has 4 complex roots. In case there are 2 real roots, then, there are two comlpex roots.
Otherwise, there are 4 real roots.
Then, you can conclude for the possible roots of the polynomial:
- 4 real roots
- 4 complex roots
- 2 real roots and 2 complex roots
Which inequality represents the phrase, the quotient of w and four is at least 3.
Answers
The inequality that represents the phrase is:
[tex]\frac{w}{4}\ge3[/tex]A triangle has vertices on a coordinate grid at P(4, -9), Q(-1, -9), and R(4,6).What is the length, in units, of PQ?
Answers
Given:
The coordinates of point P, (x1, y1)=(4, -9).
The coordinates of point Q, (x2, y2)=(-1, -9).
The length of PQ can be calculated as,
[tex]\begin{gathered} PQ=\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ PQ=\sqrt[]{(-1-4)^2+(-9-(-9))^2} \\ PQ=\sqrt[]{(-5)^2+0} \\ PQ=\sqrt[]{5^2} \\ PQ=5 \end{gathered}[/tex]Therefore, the length PQ
anwsers a. x = 9; angle measure is 27°b. x = 9; angle measure is 45°c. x = 15; angle measure is 45°d. x = 15; angle measure is 27°
Answers
The sum of angle 3x and 45 is equal to 72. So equation for x is,
[tex]3x+45=72[/tex]Simplify the equation to obtain the value of x.
[tex]\begin{gathered} 3x+45=72 \\ 3x=72-45 \\ 3x=27 \\ x=9 \end{gathered}[/tex]Determine the measure of angle 3x.
[tex]\begin{gathered} 3x=3\cdot9 \\ =27 \end{gathered}[/tex]So value of x is 9 and measure of angle 3x is 27 degree.
Rewrite (4x4 + 8x2 + 3)/(4x2) in the form q(x) + r(x)/b(x) where q(x) = quotient, r(x) = remainder, and b(x) = divisor.
Answers
ANSWER
(x² + 2) + 3/4x²
EXPLANATION
Since the divisor is a single-term polynomial, to write the answer in the requested form, we can distribute the divisor into each of the terms of the dividend,
[tex]\frac{4x^4+8x^2+3}{4x^2}=\frac{4x^4}{4x^2}+\frac{8x^2}{4x^2}+\frac{3}{4x^2}[/tex]And simplify,
[tex]\frac{4x^4}{4x^2}+\frac{8x^2}{4x^2}+\frac{3}{4x^2}=(x^2^{}+2)^{}+\frac{3}{4x^2}[/tex]Hence, the answer is (x² + 2) + 3/4x².
At the Avonlea Country Club, 54% of the members play bridge and swim, and 89% of the members play bridge. If a member is selected at random, what is the probability that the members swims, given that the member plays bridge?
Answers
ANSWER
[tex]P(S|B)=0.61[/tex]EXPLANATION
We are given that 54% of the members at the club play bridge and swim, and 89% of the members play bridge.
[tex]\begin{gathered} P(\text{BnS)}=0.54 \\ P(B)=0.89 \end{gathered}[/tex]To find the probability that the member swims given that he/she plays bridge, we have to apply conditional probability.
The probability that the member swims given that he/she plays bridge is gotten by dividing the probability that the member plays bridge and swims by the probability that the member plays bridge:
[tex]\begin{gathered} P(S|B)=\frac{P(B\cap S)}{P(B)} \\ \Rightarrow P(S|B)=\frac{0.54}{0.89} \\ P(S|B)=0.61 \end{gathered}[/tex]That is the answer.
A purse sells for $325. What was the original price of the purse if it is being sold at a 1625% markup?
Answers
You have that the price of a purse is $325 with a 16.25% markup.
In order to determine what was the original price of the purse, you consider that the original price minus 16.25% of the unknown original price x is equal to 325.
Consider that the 16.25% of a quantity is simply the multiplication of (16.25/100) for such a quanity.
Then, you have:
x - (16.25/100)x = 325 "original price minus 16.25% of the original price"
calculate the quotient left side:
x - 0.1625x = 325
simplify like terms left side:
0.8375x = 325
divide by 0.8375 both sides:
x = 325/0.8375
x = 388.05
Hence, the original price of the purse was $388.05
Write an equation in slope-intercept form with aslope of 10 that passes through (0,6)A.x + y = 6B. y + 10x + 6C. 7x + y = 10D. y = 10x + 6
Answers
Solve theses equations by elimination y= 3/2x -10 and -2x -4y =-8
Answers
SOLUTION
We want to solve the question with elimination method
[tex]\begin{gathered} y=\frac{3}{2}x-10.\text{ . . . . . . equation 1} \\ -2x-4y=-8\text{ . . . . . . . equation 2} \\ multiply\text{ equation 1 by 2, so as to remove the fraction } \\ 2\times y=(2\times\frac{3}{2}x)-(2\times10) \\ 2y=3x-20 \\ re-arranging\text{ we have } \\ -3x+2y=-20 \end{gathered}[/tex]So our paired equation becomes
[tex]\begin{gathered} -3x+2y=-20 \\ -2x-4y=-8 \end{gathered}[/tex]To eliminate y, multiply the upper equation by 4 and the lower by 2, we have
[tex]\begin{gathered} 4(-3x+2y=-20) \\ 2(-2x-4y=-8) \\ -12x+8y=-80 \\ -4x-8y=-16 \\ we\text{ have } \\ (-12x-4x)+(8y-8y)+(-80-16) \\ -16x+0=-96 \\ -16x=-96 \\ x=\frac{-96}{-16} \\ x=6 \end{gathered}[/tex]So put x for 6 into the second equation, we have
[tex]\begin{gathered} -2x-4y=-8 \\ -2(6)-4y=-8 \\ -12-4y=-8 \\ -4y=-8+12 \\ -4y=4 \\ y=\frac{4}{-4} \\ y=-1 \end{gathered}[/tex]Hence x = 6 and y = -1
The graph is shown below
Hence the point of intersection is (6, -1)
Aidan walked 440 feet in one minute. Find his average rate in miles per hour.
Answers
Take into account the following equivalences as conversion factors:
1 mi = 5280 ft
1 h = 60 min
Then, you have:
[tex]440\frac{ft}{\min}\cdot\frac{1mi}{5280ft}\cdot\frac{60\min }{1h}=5mph[/tex]Hence, the average rate is 5 miles per hour
Which of the following is equivalent to –(–5.25) ? 5 5.25 –5 –5.25please answer fast
Answers
the given expression is,
= - ( - 5.25)
= 5.25
thus, the answer is 5.25
17. A publisher marks up a textbook by 60%, and a bookstore further marks up the textbook by 25%. What percentage of the original cost do you pay?%
Answers
A publisher marks up a textbook by 60%, and a bookstore further marks up the textbook by 25%. What percentage of the original cost do you pay?
Let
x ------> original cost
so
1) publisher marks up a textbook by 60%
cost=1.60x
2) bookstore further marks up the textbook by 25%
cost=1.60x(1.25)=2x
therefore
200%hello. I need help with solving log6 129 on a calculator.
Answers
With the aid of a scientific calculator (most smart phones are equipped with one), you need to look out for the "LOG" button.
The button usually has the inscription shown as;
[tex]\text{Log}_{10}[/tex]Press the Second Function button and this key changes to;
[tex]\text{Log}_y[/tex]This second function button means,
"The log of x base y".
In this case it means, you take the log of 129, base 6.
The steps are;
[tex]\begin{gathered} (1)\text{Press 129} \\ (2)\text{Press Second Function button} \\ (3)\text{Press 6} \\ (4)\text{Press the "equal to" button} \end{gathered}[/tex]find the missing side. triangle trig
Answers
Answer:
see below; round to the correct number of digits (I couldn't see this part)
Step-by-step explanation:
cos(28°) = x / 14
x = 14cos(28°) ⇒ calculator
x ≈ 12.3612663
Answer:
x ≈ 12.36
Step-by-step explanation:
using the cosine ratio in the right triangle
cos28° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{x}{14}[/tex] ( multiply both sides by 14 )
14 × cos28° = x , that is
x≈ 12.36 ( to 2 dec. places )
Rachel is bowling with her friends. Her bowling ball has a radius of 4.1 inches. As she bowls she tracks the location of the finger hole above the ground. She starts tracking the location when the finger hole is at the 12 o'clock position and she notices that she got some backspin on the ball and it rotates counter-clockwise.Write a function f that determines the height of the finger hole above the ground (in inches) in terms of the number of radians a the ball has rotated since she started tracking the finger hole. (Note that aa is a number of radians swept out from the 12-o'clock position.)f(a)=
Answers
Given that radius is r= 4.1 inches.
let track the location of finger hole is at 12 o'clock.
i.e. the angle is 0 degree.
at 12 o'clock
[tex]\theta=0[/tex]Now when the finger hole changed by 45 degree:
[tex]\theta=45[/tex]Now convert 45 degree into radians:
[tex]\begin{gathered} \theta=45\times\frac{\pi}{180} \\ \theta=\frac{\pi}{4} \end{gathered}[/tex]So angle is such that:
[tex]\begin{gathered} \theta\in\lbrack0,\frac{\pi}{4}\rbrack \\ 0\leq\theta\leq\frac{\pi}{4} \end{gathered}[/tex]Now calculate the measure of function in polar coordinates:
[tex]\begin{gathered} \theta=0,\text{ f(}\theta\text{)}=r \\ \theta=\frac{\pi}{2},\text{ f(}\theta)=r\cos \theta \end{gathered}[/tex]Taking measurement of function:
[tex]\begin{gathered} f(\theta)=r+r\cos \theta \\ f(\theta)=r(1+\cos \theta) \end{gathered}[/tex]So the function become and the limit is:
[tex]f(\theta)=r(1+\cos \theta),\text{ 0}\leq\theta\leq\frac{\pi}{4}[/tex]26. Find the perimeter of the polygon.3 ina. 15 inb. 21 inc. 9 in
Answers
To find the perimeter of the regular polygon, that in this case is a pentagon, multiply 5 by the sidelength of the pentagon, it means 5 times 3.
[tex]\begin{gathered} P=5\cdot3 \\ P=15 \end{gathered}[/tex]The perimeter of the polygon is 15in
A vase can be modeled using x squared over 6 and twenty five hundredths minus quantity y minus 4 end quantity squared over 56 and 77 hundredths equals 1 and the x-axis, for 0 ≤ y ≤ 20, where the measurements are in inches. Using the graph, what is the distance across the base of the vase, and how does it relate to the hyperbola? Round the answer to the hundredths place.
Answers
We are given that a vase is modeled by the following hyperbola:
[tex]\frac{x^{2}}{6.25}-\frac{\left(y-4\right)^{2}}{56.77}=1[/tex]we are asked to determine the distance across the base. To do that we will first look at the graph of the equation:
Therefore, the base of the vase is the distance between the x-intercepts of the graph. To determine the x-intercepts we will set y = 0 in the equation. We get:
[tex]\frac{x^2}{6.25}-\frac{(0-4)^2}{56.77}=1[/tex]Solving the operation on the parenthesis we get:
[tex]\frac{x^2}{6.25}-\frac{16}{56.77}=1[/tex]Now we solve the fraction:
[tex]\frac{x^2}{6.25}-0.28=1[/tex]Now we add 0.28 to both sides:
[tex]\begin{gathered} \frac{x^2}{6.25}=1+0.25 \\ \\ \frac{x^2}{6.25}=1.25 \end{gathered}[/tex]Now we will multiply 6.25:
[tex]\begin{gathered} x^2=1.25(6.25) \\ x^2=7.81 \end{gathered}[/tex]Taking square root to both sides:
[tex]\begin{gathered} x=\sqrt[]{7.81} \\ x=\pm2.8 \end{gathered}[/tex]Therefore, the x-intercepts are -2.8 and 2.8.
Now we need to determine the distance between these two points. We will use the distance between two points in a line:
[tex]d=\lvert x_2-x_1\rvert[/tex]Substituting the points we get:
[tex]d=\lvert2.8-(-2.8)\rvert=\lvert2.8+2.8\rvert=5.6[/tex]Therefore, the distance is 5.6 inches and is related to the hyperbola in the sense that it is the distance between the x-intercepts.
