A rotation is a hard transformation that revolves an item around a central point. The direction of the form is different, but it still maintains its orientation. In a translation, the object's points are all moved in the same direction in a straight line.
Motion in which a moving body's points travel uniformly in one direction. We can observe that there is no change in the object's orientation if it is moving in a translatory manner. Motion that is translated is sometimes referred to as translational motion.
Although an object's position, size, or orientation can change during a transformation, its shape is not altered. Transformations can be non-rigid or rigid or isometric, where the size of the image remains constant.
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The half-life of Tl
-201 is 3.0 days. How many days will it take until the activity of the Tl
-201 in Simones body is one-fourth of the initial activity?
It will take approximately 4.39 days until the activity of the Tl-201 in Simone's body is one-fourth of the initial activity.
How does Half-Life Reaction work?The time it takes for half of a substance's radioactive nuclei to decay is known as its half-life. It is a radioactive substance is characteristic property that is used to determine a material's rate of decay. A decay curve that plots the number of radioactive atoms remaining over time can be used to determine a substance's half-life. Radiometric dating, nuclear medicine, and radiation safety all make use of half-life.
The decay of Tl-201 follows first-order kinetics. The equation for the decay of a radioactive substance is given by:
N = N0 × [tex]1/2^{t/t/2}[/tex]
where N is the amount of the substance at time t, N0 is the initial amount of the substance, t1/2 is the half-life of the substance, and t is the time that has elapsed.
We are given that the half-life of Tl-201 is 3.0 days. This means that if we start with an initial activity of A0, the activity at any time t is given by:
A = A0 * [tex]1/2^{t/3}[/tex]
We want to know how many days it will take until the activity of the Tl-201 in Simone's body is one-fourth of the initial activity. Let's call this time t₁ :
A = A 0/4
= A0 × (1/2)[tex]^{t^{1/3} }[/tex]
Dividing both sides by A0 and taking the logarithm of both sides, we get:
ln(1/4)
= - [tex]t^{1/3}[/tex] × log(2)
Solving for t₁, we get:
t₁ = (3/log(2)) × log(4)
= 4.39 days
Therefore, it will take approximately 4.39 days until the activity of the Tl-201 in Simone's body is one-fourth of the initial activity.
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An aqueous solution of glucose (mm = 180. 2 g/mol) has a molality of 5. 21 m and a density of 1. 20 g/ml. What is the molarity of glucose in the solution?.
The molality and density of an aqueous solution of glucose (mm = 180. 2 g/mol) are 5. 21 and 1. 20 g/ml, respectively. Therefore, the molarity of glucose in the solution is 0.0355 M.
Molality is the number of moles of solute per kilogram of solvent, while molarity is the number of moles of solute per liter of solution.
molarity (M) = molality (m) * (density of solvent in g/mL) / (molar mass of solute in g/mol)
molality (m) = 5.21 m
the density of solvent (g/mL) = 1.20 g/mL
molar mass of solute (g/mol) = 180.2 g/mol
So, molarity (M) = 5.21 m * (1.20 g/mL) / (180.2 g/mol)
molarity (M) = 5.21 m * 0.0067 g/mL/g mol
molarity (M) = 0.0355 M
Therefore, the molarity of glucose in the solution is 0.0355 M.
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Consider 1.00 mole of hydrogen gas, H2. How many dihydrogen molecules are present? How many hydrogen atoms are present? What is the mass of this sample?
Consider 1.00 mole of hydrogen gas, H₂. The number of molecules in H₂ is12.044 × 10²³ molecules. The number of hydrogen atoms is 12.044 × 10²³ molecules and the mass of the sample is 2 g.
The moles of the hydrogen = 1 mol
The one mole of the substance = 6.022 × 10²³ atoms / molecules
The number of the hydrogen atoms in H₂ = 2 × 6.022 × 10²³ atoms
The number of the hydrogen atoms in H₂ = 12.044 × 10²³ atoms
The number of the hydrogen molecules in H₂ = 12.044 × 10²³ molecules
The molar mass of the H₂ = 2 g/mol
The moles of the H₂ = mass / molar mass
The mass of the H₂ = moles × molar mass
The mass of the H₂ = 1 ×2
The mass of the H₂ = 2 g
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2) A solution was made by dissolving 755 g of Na₂SO4 in 53, 100 g of
water. Calculate the morality, molality, and mole fraction of Na₂SO4.
A) Molarity
B) Molality
c) Mole fraction
Answer:
0.101 M
0.1 mol/kg
0.644
Explanation:
To calculate the molarity, molality, and mole fraction of Na2SO4 in a solution, you need to know the moles of Na2SO4 in the solution and the volume or mass of the solution.
A) Molarity: Molarity (M) is defined as the number of moles of solute per liter of solution. To calculate molarity, we need to divide the number of moles of Na2SO4 by the volume of the solution in liters.
First, calculate the number of moles of Na2SO4:
mass of Na2SO4 = 755 g
molecular weight of Na2SO4 = 142 g/mol
number of moles = mass/molecular weight = 755 g / 142 g/mol = 5.34 moles
Next, calculate the volume of the solution:
mass of water = 53,100 g
density of water = 1 g/mL
volume of water = mass/density = 53,100 g / 1 g/mL = 53,100 mL = 53.1 L
Finally, calculate the molarity:
molarity = number of moles / volume of solution = 5.34 moles / 53.1 L = 0.101 M
B) Molality: Molality (m) is defined as the number of moles of solute per kilogram of solvent. To calculate molality, we need to divide the number of moles of Na2SO4 by the mass of the solvent in kilograms.
mass of water = 53,100 g
mass of solvent in kilograms = mass in grams / 1000 g/kg = 53,100 g / 1000 g/kg = 53.1 kg
Finally, calculate the molality:
molality = number of moles / mass of solvent = 5.34 moles / 53.1 kg = 0.1 mol/kg
C) Mole fraction: The mole fraction (X) is defined as the ratio of the number of moles of solute to the total number of moles of solute and solvent in a solution. To calculate the mole fraction of Na2SO4, we need to divide the number of moles of Na2SO4 by the total number of moles of Na2SO4 and water.
number of moles of Na2SO4 = 5.34 moles
number of moles of water = 53.1 kg * 1000 g/kg / 18.015 g/mol = 2.96 moles
total number of moles = number of moles of Na2SO4 + number of moles of water = 5.34 moles + 2.96 moles = 8.30 moles
Finally, calculate the mole fraction:
mole fraction of Na2SO4 = number of moles of Na2SO4 / total number of moles = 5.34 moles / 8.30 moles = 0.644
The molarity of Na2SO4 in the solution is 0.101 M, the molality is 0.1 mol/kg, and the mole fraction of Na2SO4 is 0.644.
Kinetic energy is proportional to the square of the car's speed. How do the tables and your graph on the previous page show this relationship?(must answer rn!!!)
Answer:
The Speed squared is equal to the Kinetic Energy
Explanation:
1^{2} = 1
2^{2} = 4
3^{2} = 9
4^{2} = 16
Therefore the data on the table proves that the Speed squared is equal to the Kinetic Energy
It shows that the number of individuals in the population will ________ until the carrying capacity of the environment is reached.
Ecological models are _________ because they help scientists ________ what will occur in real life.
Explain what happened to the carrying capacity of reindeer on St. Matthew Island over time. ________
In ________ times, populations do well, and the number of individuals _________ rapidly. A period of rapid population ________ often follows, followed again by a ________ in numbers.
Give some examples of organisms present in a pond community: ___________________________________
A community and its ________ _ (nonliving) environment make up an ________
It shows that the number of individuals in the population will decrease until the carrying capacity of the environment is reached.
What is the environment?
Built environments stand in stark contrast to natural environments. With the conversion of agricultural land into urban areas and other built environments, humans have fundamentally altered the landscape. The result is a greatly altered natural environment that is now more suited to human life. Even seemingly less severe actions like constructing a mud home or a solar system in the desert turn the environment into an artificial one. Despite the fact that many animals construct structures to improve their living conditions, since they are not human, beaver dams and termite mounds are seen as natural.To know more about environment, click the link given below:
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Calculate the freezing point of 0.300 molal aqueous solution of magnesium chloride,
(MgCl₂). Assume that the MgCl₂ has ionized completely and the Kf= 1.853 °C / molal
Answer: answer of the question is given below
Explanation:
Answer:
0.556 °C.
Explanation:
The freezing point depression of a solution can be calculated using the equation:
ΔTf = Kf x molality
Where ΔTf is the change in freezing point, Kf is the molal freezing point depression constant, and molality is the concentration of solute in mol/kg.
For magnesium chloride, Kf = 1.853 °C/molal. The molality of the solution can be calculated as follows:
molality = moles of solute / mass of solvent (in kilograms)
= 0.300 mol / (0.300 mol x 1000 g/mol) = 0.300 g/1000 g = 0.0003 kg/kg = 0.300 mol/kg
Now, substituting the values into the equation:
ΔTf = Kf x molality
= 1.853 °C/molal x 0.300 mol/kg
= 0.556 °C
So the freezing point of the 0.300 molal aqueous solution of magnesium chloride will be lower than the freezing point of pure water by 0.556 °C.
ALLEN
how many molecules are represented 11.5 g of C2H5OH
According to the question the molar mass of C2H5OH is 46.07 g/mol.
What is molar mass?Molar mass is the mass of a given substance (expressed in grams) divided by the amount of substance (expressed in moles). It is also known as the molecular weight of a substance, and is the sum of the atomic masses of all the atoms in a molecule. Molar mass is used to calculate the mass of a compound in a given volume, and is commonly used in the fields of chemistry, physics, and biology to identify, quantify, and measure substances. It is also used to determine the density of a given substance, and is an important part of formulas used to calculate the concentration of a particular substance in solution.
To calculate the number of molecules, we must divide the given mass of 11.5 g by the molar mass of C2H5OH. This gives us a result of 250.03 molecules of C2H5OH.
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An anion X-3 has 31 nucleons and has atomic numbe equal to 15. The number of electron having m = 0 i it, is:-
Answer: 23
Explanation:
because it is been multiplyed by 3 has s 31 nucleons and has atomic numbe equal to 15. The number of electron having m = 0 i
Answer:
The number of electrons with magnetic quantum number m = 0 can be calculated from the atomic number of the element. The atomic number gives the number of protons, and thus the number of electrons in a neutral atom. For the anion X-3, we have 15 - 3 = 12 electrons. The magnetic quantum number m can have integer values from -j to +j, where j is a half-integer representing the total angular momentum quantum number of the electron. In this case, j can be equal to 1/2, 3/2, 5/2, and so on. For the lowest value of j, which is 1/2, the magnetic quantum number m can have two values, +1/2 and -1/2. Thus, there are two electrons with m = 0. The number of electrons with m = 0 is equal to the number of electrons in the lowest energy level, which is the 1s orbital. In this case, two electrons occupy the 1s orbital, and both have m = 0.
Explanation:
how many moles of o2 are needed to react fully with 4 mol of octane
Answer:
50 moles of oxygen
Explanation:
The reaction between octane (C8H18) and oxygen (O2) can be represented by the following equation:
C8H18 + 12.5O2 -> 8CO2 + 9H2O
So, to react fully with 4 mol of octane, we need 4 mol * 12.5 mol O2/1 mol C8H18 = 50 moles of oxygen.
ALLEN
Balance the following reaction.
Cu + Ag(NO3) --> Cu(NO3)2 + Ag
If you are given 2.5 grams of copper and 5 g of silver nitrate
What is the Limiting Reactant? __________ (Cu/AgNO3)
How much of each product do you produce?
_________ g Cu(NO3)2
_________ g Ag
Answer:
The balanced chemical equation for this reaction is:
2 Cu + Ag(NO3)2 -> 2 Cu(NO3)2 + Ag
The limiting reactant is the reactant that runs out first and determines the amount of product that can be produced. To determine the limiting reactant, we need to calculate the number of moles of each reactant.
From the given mass of copper, we can calculate the number of moles as follows:
2.5 g Cu / 63.55 g/mol = 0.0395 mol Cu
From the given mass of silver nitrate, we can calculate the number of moles as follows:
5 g AgNO3 / 169.87 g/mol = 0.0295 mol AgNO3
Since 0.0295 mol of AgNO3 is less than 0.0395 mol of Cu, AgNO3 is the limiting reactant.
To calculate the amount of each product produced, we can use the stoichiometry of the balanced equation.
For Ag, the reaction produces 1 mole of Ag for every 2 moles of AgNO3, so we have:
0.0295 mol AgNO3 * 1 mole Ag / 2 moles AgNO3 = 0.0148 mol Ag
And converting moles to grams:
0.0148 mol Ag * 107.87 g/mol = 1.59 g Ag
For Cu(NO3)2, the reaction produces 2 moles of Cu(NO3)2 for every 2 moles of AgNO3, so we have:
0.0295 mol AgNO3 * 2 moles Cu(NO3)2 / 2 moles AgNO3 = 0.0295 mol Cu(NO3)2
And converting moles to grams:
0.0295 mol Cu(NO3)2 * 164.46 g/mol = 4.86 g Cu(NO3)2
Therefore, the limiting reactant is AgNO3 (Cu/AgNO3) and the reaction produces 1.59 g of Ag and 4.86 g of Cu(NO3)2.
Question 6 of 10
Which shows an isomer of the molecule below?
O A.
OB.
O C.
O D.
The molecule D shows an isomer of the molecule given below. Therefore, option D is correct.
What is an isomer ?The term Isomer is defined as the compounds that contain exactly the same number of atoms, i.e., they have exactly the same empirical formula, but differ from each other by the way in which the atoms are arranged.
Isomerism is the phenomenon in which more than one compounds have the same chemical formula, but they have different chemical structures.
Therefore, given molecule and D molecule are isomers of each other because they have the same number of atoms, but they differ in arrangement of the atoms.
Thus, option D is correct.
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What type of reaction would most likely occur when magnesium reacts with bromine?
you gonna get magnesium bromide MgBr2
Magnesium is metal and bromine is non-metal, and the combination of the two produces an ionic compound called magnesium bromide
Used as a catalyst.
Used for position-specific analysis of Triglycerols.
Widely used as an anticonvulsant for the treatment of neuropathy.
It is used as a mild sedative.
For parts of the free-response question that require calculations, clearly show the method used and the steps involved in arriving at your answers. You must show your wo
your answer. Examples and equations may be included in your answers where appropriate.
Н
H:O:H
H:C:H
Н
:CI:
:CI:C:CI:
:CI:
Answer the following questions about CH, and CC14. The Lewis electron-dot diagrams for molecules of the compounds are shown above.
(a) Which compound has the higher boiling point? Justify your answer. The type(s) of intermolecular force(s) in both substances should be included in your answer.
The CCl4 molecule is larger and has more electrons hence it is more polarizable and has a larger boiling point
Does higher molar mass imply a higher boiling point?A higher molar mass does imply a higher boiling point for a substance, assuming that the other conditions (pressure, temperature, etc.) are constant.
This is because the boiling point is a measure of the temperature at which a substance changes from a liquid to a gas at a given pressure. As the molar mass of a substance increases, the intermolecular forces between the molecules tend to be stronger, which makes it more difficult to separate the molecules and vaporize the substance. As a result, the boiling point generally increases with increasing molar mass.
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state and explain Five causes of accidents in science laboratory
Explanation:
Chemical hazards: Handling toxic substances can cause irritation and carcinogenicity.
Biological hazards: Biological hazards include hazards from working with small animals, working with bloodborne pathogens and working with biological agents, such as viruses and bacteria.
Physical hazards: Physical hazards include exposure to noise, poor posture and the explosibility and flammability of substances.
Safety hazards: Safety hazards include unbalanced centrifuges, danger when handling hot sterilized items and electrical hazards, such as shock, explosions, blasts and electrocutions.
Allergy hazards: A common allergy hazard in the laboratory setting is a latex allergy, as many of the materials used in a laboratory setting are latex.
Dangers in the laboratory setting can also come from unsafe practices, including:
Working alone in the laboratory
Neglecting to wear a lab coat
Lack of safety training
Practice Problem 13.27b Predict the products that are expected when the following compound is heated with concentrated HBr. Modify the given drawing of the starting material to draw only the organic products. O- CH3 Edit
The given starting material is not visible, but if it has an -OH functional group attached to a methyl group (-OCH3), then the reaction with concentrated HBr will lead to the following products:
The -OH group will be replaced by a Br atom, forming methyl bromide (CH3Br).
Water (H2O) will also be produced as a byproduct of the reaction.
So, the organic products of the reaction are:
O-CH3 + HBr → CH3Br + H2O
In organic chemistry, a methyl group is an alkyl produced from methane that has the chemical formula CH3, one carbon atom bound to three hydrogen atoms. The group's name is frequently shortened to Me in formulas. In numerous organic molecules, this hydrocarbon group can be found. In most compounds, the group is extremely stable.
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Water is constantly diffusing into the cytosol of freshwater single-celled organisms. In order to maintain the proper solute concentrations in the cytosol, contractile vacuoles pump out the excess water. An experimenter placed single-celled organisms into various saline concentrations and recorded the ATP used by the contractile vacuole. The data are shown in the graph. Of the following, which additional investigation can be used to determine when the cells are in an isotonic solutionA. Decreasing the salinity of the environment a little at a time until the ATP usage reaches a maximum
B. Decreasing the salinity of the environment a little at a time until ATP usage reaches a minimum
C. Increasing the salinity of the environment a little at a time until ATP usage reaches a maximum
D. Increasing the salinity of the environment a little at a time until the ATP usage reaches a minimum
To determine when the cells are in an isotonic solution, the additional investigation that can be used is option B. Decreasing the salinity of the environment a little at a time until ATP usage reaches a minimum.
An isotonic solution is one where the solute concentration outside the cell is the same as the solute concentration inside the cell. In this state, there is no net movement of water into or out of the cell, and the contractile vacuole does not need to pump out excess water. As the salinity of the environment is decreased, the solute concentration outside the cell will decrease, and water will enter the cell, leading to an increase in the workload of the contractile vacuole. However, when the salinity of the environment is decreased to the point where it becomes isotonic with the cytosol of the cell, the workload of the contractile vacuole will reach a minimum, as there is no more excess water to be pumped out.
Therefore, by decreasing the salinity of the environment a little at a time until the ATP usage reaches a minimum, the experimenter can determine when the cells are in an isotonic solution.
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Platinum is a transition metal and forms two different ions, Pt2+ and Pt4+. Write the formulas for the compounds for each platinum ion with bromide ions.
The formulas for the compounds formed between platinum ions and bromide ions are Platinum (II) bromide (PtBr2) and Platinum (IV) bromide (PtBr4)
In both of these compounds, the bonding between the platinum ion and the bromide ions is primarily ionic in nature.
In platinum (II) bromide (PtBr2), each platinum ion is surrounded by two bromide ions, and each bromide ion is bonded to one platinum ion. The platinum ion has a +2 charge, and the two bromide ions have a -1 charge each, so the overall charge of the compound is neutral.
In platinum (IV) bromide (PtBr4), each platinum ion is surrounded by four bromide ions, and each bromide ion is bonded to one platinum ion. The platinum ion has a +4 charge, and the four bromide ions have a -1 charge each, so the overall charge of the compound is neutral.
The bond between the platinum ion and the bromide ions is a result of the attraction between their opposite charges.
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Calculate strain energy for the conformer pictured below, using strain energy increments from the table.
Strain Energy for Alkanes
Interaction / Compound kJ/mol kcal/mol
H : H eclipsing 4.0 1.0
H : CH3 eclipsing 5.8 1.4
CH3 : CH3 eclipsing 11.0 2.6
gauche butane 3.8 0.9
cyclopropane 115 27.5
cyclobutane 110 26.3
cyclopentane 26.0 6.2
cycloheptane 26.2 6.3
cyclooctane 40.5 9.7
(Calculate your answer to the nearest 0.1 energy unit, and be sure to specify units, kJ/mol or kcal/mol. The answer is case sensitive.)
13.8 kJ [tex]mol-1\\[/tex] is strain energy for the conformer pictured below, using strain energy increments from the table.
The problem is based on the concept of used strain energy in the conformers.
When two non bonded groups approach each other, it results in repulsion and causes steric strain in the molecule.
Structure of conformer in eclipsed form in Newman projection is as follows:
4.0 kJ mo is energy of eclipsed H-H bond
Energy of eclipsedН-СH, 3 bond is 5.8 kJ mol
Total strain energy of conformer (S,)
E 2x eclipsed (H-H)+ eclipsed (H-CH,)
Replace eclipsed (H-H) with 4.0 kJ mol and eclipsed (H-CH) with 5.8 kJ mol to get
E 2x4.0 kJ mol +5.8 kJ mol =13.8 kJ mol
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a specie with initial concentration 1.4×10^-2 mol L-1 decay by first order kinetics with a rate constant 2.35×10^2L mol-1 s-1. what is the half-life if this specie?
Answer:
293 ms
Explanation:
The half-life of a first-order reaction can be calculated using the following formula:
t1/2 = 0.693 / k
Where t1/2 is the half-life and k is the rate constant.
For this reaction, the rate constant is 2.35 x 10^2 L/mol/s, so:
t1/2 = 0.693 / (2.35 x 10^2 L/mol/s) = 0.293 / (2.35 x 10^2) s = 0.000293 s = 293 ms
Answer:
0.293 / 2.35 × 10^2 seconds.
Explanation:
The half-life of a first order reaction can be calculated using the equation:
t1/2 = 0.693 / k
where t1/2 is the half-life, k is the rate constant, and 0.693 is the natural logarithm of 2.
Substituting the values given in the question:
t1/2 = 0.693 / 2.35 × 10^2 L mol-1 s-1 = 0.293 / 2.35 × 10^2 s
So, the half-life of the species is approximately 0.293 / 2.35 × 10^2 seconds.
With respect to the reaction shown,
BLANK # 1: type of compound that
will form
BLANK #2: name of the reaction
With respect to the reaction shown, the type of compound that will form is a hemiketal, and the name of the reaction is "hemiketal formation.
What are hemiacetals and hemiketals?A hemiketal is created when an alcohol reacts with a ketone, whereas a hemiacetal is created when an alcohol reacts with an aldehyde.
Organic substances called hemiacetal and hemiketal are hybrid molecules that have an ether group and a hydroxyl group in the same molecule.
The name of reaction that forms hemiketals and hemiacetals is called "hemiacetal formation" or "hemiketal formation," depending on the specific functional group involved.
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Calculate the atomic mass of element "X", if it has 2 naturally occurring isotopes with the following masses and natural abundances: X-45 44. 8776 amu 32. 88% X-47 46. 9443 amu 67. 12%
46.2648
Explanation:Atomic mass describes the number of protons and neutrons in an atom.
Percent Abundance
Percent abundance is the percentage of atoms within a sample that have a specific mass number. The reason that different atoms within a sample would have different mass numbers is that they are different isotopes. For example, if the isotope Cl-35 has a percent abundance of 75%, then 75% of all Chlorine atoms within a sample will have a mass number of 35. Percent abundance refers to the likelihood of an isotope occurring in a natural sample. Percent abundance does not take into account artificial samples of elements.
Finding Atomic Mass
The atomic mass of an element is found through the mass of isotopes and their percent abundances. The formula for atomic mass is:
m₁*p₁ + m₂*p₂In this formula, the m is the mass of the isotope and p is the percent abundance. The percent abundance should be expressed as a decimal for all calculations. Now, plug in the values and solve.
(44.8776 * 0.3288) + (46.9443 * 0.6712)Rounded to 4 decimal places, this equals 46.2648. This means that the atomic mass of element "X" is 46.2648 amu.
Sophie is pushing her bike up a hill with 10N if she increases her force to 12n
Sophie is pushing her bike up a hill with 10N if she increases her force to 12N, then there will be decrease the bike's mass. Therefore, the correct option is option C.
What is force?A force is indeed an effect in physics that may modify the velocity of an item. A force can cause a mass object to change its velocity (e.g., moving from rest), i.e., to accelerate.
Intuitively, force may be characterized as a push or even a pull. A force is a vector quantity since it has both direction and magnitude. It really is measured in newtons, the SI unit of mass (N). Sophie is pushing her bike up a hill with 10N if she increases her force to 12N, then there will be decrease the bike's mass.
Therefore, the correct option is option C.
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Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.
2NaClO3 --> 2NaCl +3O2
How many moles of NaClO3 were needed to produce 30 moles of O2? Round your answer to the nearest whole number.
Answer:
10 moles of NaClO3 were needed to produce 30 moles of O2
Explanation:
From the equation, we know that 2 moles of NaClO3 produce 3 moles of O2. To find out how many moles of NaClO3 are needed to produce 30 moles of O2, we divide the number of moles of O2 by the mole ratio:
30 moles O2 / 3 moles O2 per 2 moles NaClO3 = 10 moles NaClO3
So, 10 moles of NaClO3 were needed to produce 30 moles of O2.
A 7.132 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 11.88 g CO₂ and
3.891 g H₂0 are produced.
In a separate experiment, the molar mass is found to be 132.1 g/mol. Determine the empirical formula and the molecular formula
of the organic compound.
Answer:
C4H8O4
Explanation:
The empirical formula of a compound can be determined from its elemental composition. To determine the empirical formula, we first need to convert the mass of each element to moles, and then divide by the smallest number of moles of any element to obtain the mole ratio.
From the combustion analysis, the number of moles of CO₂ produced is 11.88 g / 44.01 g/mol = 0.2694 mol. The number of moles of H₂O produced is 3.891 g / 18.015 g/mol = 0.2169 mol.
Next, we convert the carbon and hydrogen present in the compound to moles by dividing the mass of each element by its atomic mass:
C = (7.132 g - 11.88 g - 3.891 g) / 12.01 g/mol = 0.2694 mol
H = 2 * 0.2169 mol = 0.4338 mol
Now, we divide each number of moles by the smallest number of moles (0.2694 mol) to obtain the mole ratio:
C = 0.2694 mol / 0.2694 mol = 1
H = 0.4338 mol / 0.2694 mol = 1.6
O = 0.2694 mol / 0.2694 mol = 1
The empirical formula of the compound is therefore C1H1.6O1, which can be simplified to C1H2O.
To determine the molecular formula, we use the molar mass of the compound, 132.1 g/mol, and compare it to the molar mass calculated from the empirical formula. The molar mass of C1H2O is 12.01 g/mol + 2 * 1.01 g/mol + 16.00 g/mol = 30.03 g/mol. To find the molecular formula, we divide the molar mass of the compound by the molar mass of the empirical formula and multiply each element in the empirical formula by this number:
132.1 g/mol / 30.03 g/mol = 4.40
C = 1 * 4.40 = 4.40
H = 2 * 4.40 = 8.80
O = 1 * 4.40 = 4.40
The molecular formula of the compound is therefore C4H8O4.
Aɳʂɯҽɾҽԃ Ⴆყ ɠσԃKEY ꦿ
Answer:
11 * CH₂ = C₁₁H₂₂
Explanation:
The empirical formula of a compound can be determined by finding the ratio of the number of atoms of each element present in the compound. To find the empirical formula of this organic compound, we need to calculate the number of moles of each element present in the sample.
First, we find the number of moles of carbon by dividing the mass of CO₂ produced by the molar mass of CO₂:
11.88 g CO₂ / 44.01 g/mol CO₂ = 0.269 mol C
Next, we find the number of moles of hydrogen by dividing the mass of H₂O produced by the molar mass of H₂O:
3.891 g H₂O / 18.02 g/mol H₂O = 0.216 mol H
To find the empirical formula, we divide the number of moles of each element by the smallest number of moles calculated:
0.269 mol C / 0.216 mol H = 1.244
0.216 mol H / 0.216 mol H = 1
So the empirical formula of the organic compound is CH₂.
The molecular formula of a compound is a multiple of its empirical formula, with the multiple determined by the molar mass. To find the molecular formula of this organic compound, we divide the molar mass of the sample by the molar mass of the empirical formula:
132.1 g/mol / (12.01 g/mol + 2 * 1.01 g/mol) = 11
So the molecular formula of the organic compound is 11 * CH₂ = C₁₁H₂₂.
ALLEN
Which coefficients correctly balance the equation below
Ba3N2+HOH - -> Ba(OH)2+NH3
1,6,1,2
1,3,3,2
1,6,3,2
2,6,3,2
The coefficients that correctly balance the given equation is 1. 6, 3,2
The correct option is C
What is a balanced equation of a reaction?A balanced equation of a reaction is an equation in which the moles of atoms of elements of the reactants are equal to the moles of atoms of the product.
According to the law of conservation of matter, matter is neither created nor destroyed, hence, the mass of the reactants must be equal to the mass of products at the end of any given chemical reaction.
The balanced equation of the given reaction is as follows:
Ba₃N₂+ 6 HOH - -> 3 Ba(OH)₂ + 2 NH₃
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Calculate the Percentage of 1) Oxygen in Calcium nitrate dihydrate.
Answer:
Percentage of Oxygen in Ca(NO3)2•2H2O
Ankit Mishra
Calculate the Percentage of 1) Oxygen in Calcium nitrate dihydrate.
Calcium nitrate dihydrate, also known as calcium nitrate (II) hydrate, has the chemical formula Ca(NO3)2•2H2O. The percentage of oxygen in calcium nitrate dihydrate can be calculated by determining the number of oxygen atoms in the formula and dividing that by the total number of atoms in the formula, then multiplying by 100 to express the answer as a percentage.
Here's the calculation:
1 calcium atom (Ca) = 40.08 g/mol
2 nitrogen atoms (N) = 14.01 g/mol
10 oxygen atoms (O) = 16.00 g/mol
So, the molar mass of Ca(NO3)2•2H2O is (40.08 + 2 x 14.01 + 10 x 16.00) g/mol = 158.08 g/mol.
The percentage of oxygen in calcium nitrate dihydrate can then be calculated as follows:
(10 x 16.00 g/mol) / 158.08 g/mol x 100% = 63.18%
So, the percentage of oxygen in calcium nitrate dihydrate is approximately 63.18%.
Lechatliers principle
Need help figuring out the arrows directions.
According to Lechatliers principle, as the concentration of HCl is decreasing, the reaction will shift to the reactant side to increase HCl, then the Keq decreases, since product concentration is decreases.
What is Lechatliers principle ?According to Lechatliers principle, when an any disorder imbalance the equilibrium of a reaction system, the system itself balances the factors and shifts to a new equilibrium.
If the concentration of any component is increased, then the reaction shifts to the direction in which it is consumed. If the concentration is decreased, the reaction shifts to the direction in which the component is produced.
Hence, as the HCl decreases, the reaction shifts to backwards direction to produce more HCl, then, concentration of reactants HCl and Mg increases, and that products and Keq decreases.
The reaction is an exothermic reaction. Hence, as the temperature is increased, the reaction shifts to the backward direction in which heat is used. Hence, reactant concentration increases, product concentration decreases, Keq also decreases.
If the temperature is reduced, the reaction shift to the forward direction. Hence, concentration of HCl, and Mg decreases but MgCl2 increases and Keq increases.
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Commercial vinegar contains close to 5 g of acetic acid (ch_3cooh) per 100 ml (1 l = 1000 ml) of solution. What is the molarity of acetic acid in vinegar?.
If commercial vinegar contains around 5 g of acetic acid (ch 3cooh) per 100 ml (1 l = 1000 ml) in solution, its molarity is 0.83 M.
Molarity is the amount of solute in moles per litre of solution.
Acetic acid's mass is reported as 5.0 g, and the solution's volume is 100.0 mL.
We divide the grammes of acetic acid by the molar mass in order to convert them from grammes to moles.
Acetic acid's chemical formula is CH₃COOH. Molar mass of acetic acid is equal to 2(12.01), 4(1.01), 2(16), 24.02, 4.04, and 32 grammes per mol. Acetic acid has a molecular weight of 5.0/60.06, or 0.083 moles.
Transform mL to L.
1 L equals 1000 mL, as we are aware.
The solution's molarity is equal to 0.083moles per 0.1000L, or 0.83M, thus we divide by 1000 to convert from mL to L. 100/1000 = 0.1000 L
Therefore, 0.83 M of acetic acid is present in vinegar.
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Analysis of a compound indicates that it contains 1. 04 g k, 0. 70 g cr, and 0. 86 g o. Find its empirical formula.
the empirical formula of the compound that contains 1. 04 g k, 0. 70 g cr, and 0. 86 g o. is K0.5Cr1O2.
The empirical formula of a compound is the simplest whole-number ratio of atoms of each element in the compound. To find the empirical formula of a compound, you need to determine the number of moles of each element present in the sample.
First, you need to convert the masses of each element to moles:
For potassium (K), 1.04 g / 39.10 g/mol = 0.0264 moles
For chromium (Cr), 0.70 g / 51.99 g/mol = 0.0134 moles
For oxygen (O), 0.86 g / 16.00 g/mol = 0.0538 moles
Next, divide each number of moles by the smallest number of moles to get the simplest whole-number ratio:For potassium (K), 0.0264 moles / 0.0264 moles = 1
For chromium (Cr), 0.0134 moles / 0.0264 moles = 0.5
For oxygen (O), 0.0538 moles / 0.0264 moles = 2.0
Therefore, the empirical formula of the compound is K0.5Cr1O2. This represents the simplest whole-number ratio of atoms of each element in the compound.
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