Show that the minimum ratio of cation radius to anion radius at coordination number equal to 8 should be 0.732.

If all of the resistors in the diagram below are equivalent, then the voltage across the resistor R2 is 2.5 V.

The value of resistor is not give take the value of resistor 5Ω

R2 and R3 are in series hence its equivalent resistor Rs is R2 + R3 = 10Ω

R1 = 5Ω and Rs = 10Ω both this resistors are in parallel hence,

I()s = V/Rs = 5/10 = 0.5 A

I(1) = V/R1 = 5 / 5 = 1 A

In order to get voltage across R2 we have to apply voltage devider rule,

voltage across R2 is

V(R2) = R2 ÷ (R1 + R2) V

Putting all the values

V(R2) = 5/10 × 5

V(R2) = 5/10 × 5 = 2.5 V

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The weight-watcher is need to climb approximately 0.298 kilometers to burn off the equivalent of a large piece of chocolate cake rated at 605 food Calories.

To determine the height that the weight-watcher needs to climb, we first need to calculate the amount of potential energy that would be required to burn off 605 food Calories.

First, we need to convert 605 food Calories into calories:

605 food Calories x 103 calories/food Calorie = 62315 calories

Next, we need to convert calories to joules:

1 calorie = 4.184 joules

62315 calories x 4.184 joules/calorie = 260808.56 joules

Now we can calculate the height that the weight-watcher must climb using the formula for potential energy:

potential energy = mass x gravity x height

where, mass = 89.4 kg, gravity = 9.8 m/s², and

potential energy = 260808.56 joules

Solving for height, we get:

height = potential energy / (mass x gravity)

height = 260808.56 joules / (89.4 kg x 9.8 m/s²)

height = 298.47 meters

Finally, we convert the height to kilometers:

298.47 meters = 0.29847 kilometers

Therefore, the weight-watcher needs to climb approximately 0.298 kilometers to burn off the equivalent of a large piece of chocolate cake rated at 605 food Calories.

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The average velocity of a car that is moving round a circular track at 120 mph is given as 0

When a car is moving around a given moves round a circular track at 120 mph, it would have a direction that is constantly changing while it is moving around the track.

After the full lap has been completed, the car is going to have to go back to its starting point. Hence the displacement is 0, average velocity is 0. This is regardless of its speed. Hnece the velocity is 0

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The wavelength of the wave is 6.84 m.

Speed of the wave, v = 342 m/s

frequency of the wave, f = 50 Hz

We know that speed of a wave,

v = fλ

Therefore, wavelength of the wave,

λ = v/f

λ = 342/50

λ = 6.84 m

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Answer: 3 days

Explanation:

Sphere A has a net charge of approximately -1.0 Coulombs and after the spheres are separated, they will have equal but opposite charges.

Define Coulombs ?

Coulombs (C) is the unit of electric charge in the International System of Units (SI). It is defined as the charge transported by a constant current of one ampere in one second.

(Part A) The addition of electrons to sphere A will give it a negative charge. The number of excess electrons on sphere A can be calculated as:

n = Q/e

where n is the number of excess electrons, Q is the total charge on sphere A, and e is the elementary charge. Since [tex]1.0*10^{12[/tex] electrons are added to sphere A, we have:

n = [tex]1.0*10^{12[/tex]  electrons / ([tex]1.6*10^{-19[/tex] C/electron) = [tex]6.25*10^{30[/tex] electrons

Thus, the total charge on sphere A is:

Q = ne = ( [tex]6.25*10^{30[/tex] electrons) × ( [tex]1.6*10^{-19[/tex]  C/electron) ≈ -1.0 C

So, sphere A has a net charge of approximately -1.0 Coulombs.

(Part B) Since the two spheres were in contact, they shared the same potential before they were separated. Therefore, after the spheres are separated, they will have equal but opposite charges. Sphere B will have a net charge of +1.0 Coulombs to balance the -1.0 Coulombs on sphere A.

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When the wood comes down the change in potential energy of mass 2 kg and velocity 12 m/s is 144 J.

When the object is thrown vertically upwards, the height increases. The potential energy also increases with respect to the height. The potential energy is maximum, and the kinetic energy is zero when the stone moves vertically upwards.

When the object comes down, the potential energy decreases and results in increasing in kinetic energy. When the stone comes down, the potential energy is converted to kinetic energy, and the change in potential energy results in kinetic energy.

From the given,

mass of the wood (m) = 2kg

the velocity of the wood (v) = 12 m/s

kinetic energy (K.E) = mv² / 2

                                = (2×12×12) / 2

                                = 144 J

Thus, the change in kinetic energy is 144 J.

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The point where the object's speed is one-half its final speed may located at 3/4 of the initial height of the object, the answer would be "lower than the midpoint of the path."

Assuming the object is subject to a constant acceleration due to gravity, the speed of the object at any given point can be described by the following equation:

v² = u² + 2as

Where:

v = final velocity

u = initial velocity

a = acceleration due to gravity (approximately 9.8 m/s² near the Earth's surface)

s = distance traveled

Let's suppose the object is dropped from rest at a height h above the ground. Then its initial velocity is u=0, and the equation simplifies to:

v² = 2gh

where g is the acceleration due to gravity and h is the initial height of the object.

To find the point at which the object's speed is one-half its final speed, we can set v = 1/2 * √(2gh) and solve for s:

1/2 * √(2gh) = √(2gh - 2gs)

Simplifying this equation, we get:

1/4 * 2gh = 2gh - 2gs

s = 3/4 * h

This means that the point where the object's speed is one-half its final speed is located at 3/4 of the initial height of the object. Therefore, the answer is "lower than the midpoint of the path."

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It's worth noting that increasing any of these factors too much can cause the wire to overheat, potentially damaging the wire or the battery. So, the student should exercise caution and avoid exceeding safe limits.

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The horizontal distance of the ball is determined as 2.71 m.

The horizontal distance traveled by the ball is calculated by applying the following formula as shown below;

X = Vₓt

where;

X = 4 m/s x cos (45) x 0.96 s

X = 2.71 m

Thus, the horizontal distance of the ball is a function of the horizontal velocity and time of motion.

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According to the question the image is located 18.00 cm away from the lens and the image is a real, inverted image.

Lens is an optical device used to focus or disperse light, or to change the optical properties of a beam of light. It is made from transparent materials like glass, plastic or quartz and can be used in a variety of applications such as cameras, microscopes, telescopes and other optical instruments. A lens can also be used to bend light, change its direction, and magnify objects.

The image is located 18.00 cm away from the lens and the image is a real, inverted image. This can be determined using the lens equation given by 1/f = 1/d_o + 1/d_i, where f is the focal length, d_o is the object distance, and d_i is the image distance. Plugging in the given values, we get 1/9.00 = 1/27.0 + 1/d_i, which simplifies to 1/d_i = 1/9.00 - 1/27.0, or d_i = 18.00 cm.

Since the image distance is positive, this indicates that the image is real, meaning it is actually formed at the image distance. This is further confirmed by the fact that the image is inverted, as a real image is always inverted.

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Answer:

First, we need to find the torque applied to the wheel. The torque formula is given by:

τ = r × F × sin(θ)

where

r = radius of the wheel = 50 cm = 0.5 m

F = force applied tangentially = 20 N

θ = angle between the force and the radius (which is 90 degrees for a tangential force)

So, τ = 0.5 × 20 × sin(90) = 10 Nm

The moment of inertia of a solid cylinder (which the wheel can be approximated to) is given by:

I = 0.5 × m × r^2

where

m = mass of the wheel = 2.5 kg

r = radius of the wheel = 0.5 m

So, I = 0.5 × 2.5 × 0.5^2 = 0.3125 kgm^2

The angular acceleration can be calculated using the formula:

α = τ / I

So, α = 10 / 0.3125 = 32 rad/s^2 (rounded to two decimal places)

Therefore, the angular acceleration when a force of 20N is applied tangentially to the tire of a 2.5 kg bicycle wheel with a radius of 50cm is 32 rad/s^2.

Based on the information provided, it seems like Jessica's sun powered pop it has stopped working because it is not receiving enough sunlight to power the device.

To fix the issue, she should try holding it in a place where it can receive direct sunlight for an extended period of time. Alternatively, if the device has a rechargeable battery, she could try charging it using a USB cable or other charging method if one is available.

If neither of these solutions work, there may be a more serious issue with the device itself and it may need to be replaced or repaired.

While this answer may provide helpful information for your inquiry, it is important to remember that using it verbatim could be seen as plagiarism. To avoid this, it is best to use your own words and properly cite any sources used. This will ensure that you are giving credit to the original author and presenting your own unique perspective on the topic.

~~~Harsha~~~

Answer:(a) To find the height of the satellite's orbit if its total energy were 550 MJ greater, we can use the following equation:

K2 + U2 = K1 + U1 + 550 MJ

Since the satellite is in a circular orbit, its kinetic energy is given by:

K = (1/2)mv^2

where m is the mass of the satellite, and v is its velocity.

We can use the following equation to relate the height of the satellite's orbit to its velocity:

v = sqrt(GM/R)

where G is the gravitational constant, M is the mass of the Earth, and R is the radius of the Earth plus the height of the satellite's orbit.

Therefore, we can express the kinetic energy of the satellite in terms of its height:

K = (1/2)m(GM/R)

Using these equations, we can rewrite the conservation of energy equation as:

(1/2)m(GM/(R1+h1)) - GMm/(R1+h1) = (1/2)m(GM/(R2+h2)) - GMm/(R2+h2) + 550 MJ

where R1 is the radius of the Earth, and R2 is the radius of the Earth plus h2.

Simplifying and solving for h2, we get:

h2 = [(GMm/(R1+h1)) - (GMm/(R2+h2)) - 550 MJ/(GM/(R2+h2))]^(-1) - R2

Plugging in the given values, we get:

h2 = 931 km

Therefore, the height of the satellite's orbit would be 931 km if its total energy were 550 MJ greater.

(b) To find the difference in the system's kinetic energy, we can use the following equation:

Delta K = K2 - K1

Substituting the expressions for K1 and K2, we get:

Delta K = (1/2)m(GM/(R2+h2)) - (1/2)m(GM/(R1+h1))

Plugging in the given values, we get:

Delta K = -7.5 x 10^9 J

The negative sign indicates that the system's kinetic energy has decreased.

(c) To find the difference in the system's potential energy, we can use the following equation:

Delta U = U2 - U1

Substituting the expressions for U1 and U2, we get:

Delta U = -GMm/(R2+h2) + GMm/(R1+h1)

Plugging in the given values, we get:

Delta U = 5.9 x 10^9 J

The positive sign indicates that the system's potential energy has increased.

Explanation:

Work done by a force in a moving object is 100J . It was traveling at a speed of 2m/s and comes down to 1 m/s.

Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J). i.e. Work(W) is force(F) times displacement(s). W=F× s When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule. Writing for it's dimension, W=F× s.

W = Fs

In this problem mass of the object is not given, consider the mass of the object is 2kg, time to speed down the object is 5s and distance is 25m then,

given,

W = 100J

M = 2kg

t = 5s

s = 25m

then,

W = m.Δv/Δt.s

100 = 2(2-v₂)/5 .25

2 - v₂= 100×5/50

2 - v₂  = 3

v₂ = 1 m/s

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According to the information we can infer that the decrease in speed is offset by the increase in radius.

To calculate the speed the ice cube we have to consider that the gravitational force on the ice cube is balanced by the normal force provided by the cone. So, the speed of the ice cube must be such that the centripetal force equals the gravitational force.

In this case, to find the speed of the ice cube let M be the mass of the ice cube and r be the radius of the circular path. The gravitational force on the ice cube is given by Fg = Mg, where:

g = acceleration due to gravity.

The centripetal force is given by Fc = Mv^2/r, where:

v = speed of the ice cube

Setting Fg = Fc, we get:

Solving for v, we get:

v = sqrt(gr)

No piece of data is unnecessary for the solution.

According to the information, when R is made two times larger, the required speed will decrease. For example:

From part (a), v is proportional to the square root of R. Therefore, if R is doubled, v will be multiplied by the square root of 2, which is approximately 1.414.

To know if the time required for each revolution will increase, decrease or stay constant we have to consider that shen R is made two times larger, the time required for each revolution will increase. To see this, note that the period T of the circular motion is given by:

T = 2πr/v

According to the information, the answers to parts (c) and (d) are not contradictory because the decrease in speed is offset by the increase in radius, resulting in a longer period of revolution. The net effect is that the ice cube will travel the same distance in each revolution, so the total time required for one complete revolution will remain constant.

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Answer:

Explanation:

The speed of a wave in terms of frequency and wavelength is given by :

V= Fx

V = 620 x 10.5

V = 65010 m/s

So, the speed of sound in steel is 6510 m/s.

The activation energy required to light a match is obtained by the chemical energy transferred into the thermal energy. When the match stick and head are rubbed together, the friction force is developed and hence, lightning occurs.

Activation energy is the minimum amount of energy available for the chemical reaction to occur. It involves the Breaking of adhesion between the match head and the striking surface causing the particle to vibrate.

The energy of vibration provides the activation energy required to light the match. The thermal energy of the vibrating particles on the head of the match is transferred from cool to hot regions.

As the head moves across the striking surface, its particles adhere to the surface for a short period of time and produce heat and light energy.

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Answer:

The rate of heat loss by radiation is given by the formula:

Q = ε * σ * A * (T^4 - T0^4)

where Q is the rate of heat loss, ε is the emissivity of the pot (0.60), σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2K^4), A is the surface area of the pot (which we can assume is about the same as the area of a sphere with a diameter of 0.2 m, which is the typical size of a pot), T is the temperature of the water (95°C + 273.15K = 368.15K), and T0 is the temperature of the surroundings (20°C + 273.15K = 293.15K).

Plugging in the numbers, we get:

Q = 0.60 * 5.67 x 10^-8 * 4π(0.1)^2 * (368.15^4 - 293.15^4)

Q = 39.17 W

Therefore, the water’s rate of heat loss by radiation is 39.17 W.

Answer:

Electrical potential energy is increased.

Explanation:

When a complete circuit with a capacitor is turned on, charges are moved from one plate to another through the battery, increasing the electrical potential energy.

Change in kinetic energy after explosion is 32.9 x 10⁵J.

Mass of the first piece, m₁ = 5 kg

Mass of the second piece, m₂ = 12 kg

Mass of the third piece, m₃ = 8 kg

Velocity of the rock initially, v = 2 m/s

Velocity of the second piece, v₂ = 400 m/s

Velocity of the third piece, v₃ = 9 m/s

According to conservation of momentum,

mv = m₁v₁ + m₂v₂ + m₃v₃

Therefore velocity of the first piece,

v₁ = (mv - m₂v₂ - m₃v₃)/m₁

v₁ = [(25 x 2) - (12 x 400) - (8 x 9)]/5

v₁ = -964.4 m/s

Kinetic energy of the rock initially,

KE = 1/2 mv²

KE = 1/2 x 25 x 4

KE = 50 J

Kinetic energy after explosion,

KE' = 1/2(m₁v₁²+ m₂v₂²+ m₃v₃²)

KE' = 1/2[(5 x 93 x 10⁴) + (12 x 16 x 10⁴) + (8 x 81)]

KE' = 328.5 x 10⁴

Change in kinetic energy = KE' - KE = 32.9 x 10⁵J

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Answer: 3.26 * 10^3

Explanation:

The time taken for the helicopter rotor to double its angular velocity over the initial speed is 1 minute.

If the rotor speed changed from 225 rev/min to 300 rev/min in one minute.

This means the change in angular velocity (Δω) is:

Δω = ω2 - ω1 = 300 rev/min - 225 rev/min = 75 rev/min

We are given that the rotor doubles its angular velocity over the initial speed, so ω2 = 2ω1.

Substituting ω2 = 2ω1 into the equation for Δω, we get:

75 rev/min = 2ω1 - ω1

Simplifying, we get:

75 rev/min = ω1

Now we can solve for the time taken for the rotor to double its angular velocity over the initial speed.

Δω = αt

Substituting Δω = 75 rev/min and ω1 = 75 rev/min, we get:

75 rev/min = αt

Now we can solve for t:

t = Δω / α

We need to find α, the angular acceleration.

α = Δω / t = 75 rev/min / 1 min = 75 rev/min²

Now we can substitute the value of α back into the equation for t:

t = Δω / α = 75 rev/min / 75 rev/min² = 1 minute

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Answer:

according to the internet

The force exerted by the wall on the ladder is 468 N, and the normal reaction exerted by the floor on the ladder is 1152 N.

Explanation:

The force exerted by the wall on the ladder is zero, and the normal reaction exerted by the floor on the ladder is 1176 N.

A reaction force is a force that occurs in response to an action force. According to Newton's third law of motion, "For every action, there is an equal and opposite reaction." This means that whenever an object exerts a force on another object, the second object exerts an equal and opposite force back on the first object.

For example, when you push against a wall, your body is exerting a force on the wall, but the wall is also exerting an equal and opposite force back on your body. This force is known as the reaction force. Another example is when a rocket propels itself forward by expelling exhaust gases backward. The exhaust gases exert a force on the rocket, and the rocket exerts an equal and opposite force back on the exhaust gases.

Here in the Question,

To solve this problem, we need to consider the forces acting on the ladder. There are three forces to consider: the weight of the ladder and the two forces exerted by the wall and the floor on the ladder.

Let's start by finding the weight of the ladder and the person standing on it. The weight is given by:

W = mg

where m is the mass and g is the acceleration due to gravity. For the ladder, we have:

W_ladder = 40 kg x 9.8 m/s^2 = 392 N

For the person:

W_person = 80 kg x 9.8 m/s^2 = 784 N

Next, we need to find the horizontal and vertical components of the forces exerted by the wall and the floor. Since the ladder is in equilibrium, the sum of the forces in the horizontal and vertical directions must be zero.

Let's start with the horizontal direction. The only force in this direction is the force exerted by the wall, which we'll call F_wall. Since there is no acceleration in the horizontal direction, we have:

F_wall = 0

This means that the force exerted by the wall on the ladder is zero.

Now let's look at the vertical direction. The forces in this direction are the weight of the ladder and the person (W_ladder + W_person), the normal force exerted by the floor (N_floor), and the force exerted by the wall (F_wall). Since the ladder is not accelerating in the vertical direction, the sum of the forces in this direction must be zero:

N_floor + F_wall - W_ladder - W_person = 0

Since we know that F_wall = 0, we can simplify this equation to:

N_floor - W_ladder - W_person = 0

Now we can plug in the values we found earlier:

N_floor - 392 N - 784 N = 0

Solving for N_floor, we get:

N_floor = 1176 N

So the normal reaction exerted by the floor on the ladder is 1176 N.

Therefore, the force exerted by the wall on the ladder is zero, and the normal reaction exerted by the floor on the ladder is 1176 N.

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If the pop was immersed in water or subjected to strong chemicals during the washing process, it may have been harmed.

A dead battery can be to blame. Jess has to make sure the battery is placed and charged correctly. She might need to get help from the manufacturer if the battery cannot be changed.

If the pop uses solar panels for electricity, Jess has to make sure that they are clear of obstructions like debris and are functioning properly. She can use a soft cloth and some water to clean the solar panels if they are filthy.

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Answer:

1) Terahertz (Tera)

2) Kilolitre (kilo)

3) Mega

4) Gigawatt (Giga)

The electric flux through a surface is calculated by the equation, φ = ∫E•dA, where E is the electric field, dA is the area vector and the integral is taken over the surface area.

Electric flux is a measure of the amount of electric field passing through a given area. It is represented by the letter Φ (phi) and is measured in units of volt-meters (Vm). Electric flux is related to the strength of electric fields, and the amount of electric flux passing through a given area is determined by the electric field strength and the area through which it passes. Electric flux is often used in calculations of electric field strength and electric field energy, as well as in the field of electromagnetism. Electric flux can also be used to calculate the total amount of electric charge passing through a given area.

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The image characteristics will be real ,inverted and formed between centre of curvature and focal point.

Why would you use a concave mirror?

Telescopes that use reflection employ concave mirrors. They also offer an enlarged view of the face for shaving or applying makeup.

Concave mirrors are frequently employed as reflectors in headlights, torchlights, railroad engines, and other parts of autos and motor vehicles. Since the light source is positioned near the mirror's focal point, the light rays are reflected and travel over a considerable distance as parallel, highly intense light beams. Since a convex mirror reflects light outward, it cannot be utilized to concentrate light. Because the focus and center of curvature are fictitious positions inside the mirror and are therefore unreachable, convex mirrors or curved mirrors always produce a virtual image.

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Part A) Magnitude of force on 6.5 nC charge in the middle of figure due to four other charges is calculated as 9.89 x 10⁻³ N ; Part B) Direction of the force on 6.5 nC charge in the middle of figure due to four other charges is towards the center of square.

Electric charges determine how objects interact with each other through  electromagnetic force

Let's label the four charges forming square as q₁, q₂, q₃, and q₄, and the charge in the center as q₅. The magnitude of the charges q₁-q₄ is 2.0 nC, and the magnitude of q₅ is 6.5 nC.

Part A: Force on q₅ due to each of the other charges given by Coulomb's law is : F = k * |q₁||q₅| / r²

k is Coulomb constant (k = 9.0 x 10⁹ N·m²/C²), |q₁| and |q₅| are magnitudes of charges and r is distance between charges.

Since the four charges q₁-q₄ are equidistant from q₅, then net force on q₅ due to them will be directed towards the center of square.

Distance between q₁ and q₅ is a/√2, since the diagonal of the square is √2 times the length of one side. Therefore, force on q₅ due to one of the charges is:

F₁ = k * |q₁||q₅| / (a/√2)²

F₁ = (9.0 x 10⁹ ) * (2.0 x 10⁻⁹) * (6.5 x 10⁻⁹) / (0.04 m)²

F₁ = 2.47 x 10⁻³ N

Total force on q₅ due to the four charges is: Fnet = 4F₁ = 9.89 x 10⁻³ N

Hence, magnitude of the force on 6.5 nC charge due to the four other charges is calculated as 9.89 x 10⁻³ N.

Part B: Force on q₅ due to each of the four charges is directed towards the center of square. Since the four forces are equal in magnitude and direction, then net force on q₅ due to the four charges will also be directed towards the center of the square.

So, the direction of the force on 6.5 nC charge in the middle due to four other charges is towards the center of the square.

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a. The student's final position is 100.5 meters at an angle of 25.2° north of east from her initial position and b. The student would have to head in the direction of 334.8° south of east to return to her initial position.

a. To find the student's final position, we can use vector addition. We can start by breaking each displacement vector into its x- and y-components. First displacement (70 m at 37° north of east),

x-component = 70 cos(37°) = 56.02 m

y-component = 70 sin(37°) = 42.49 m

Second displacement (82 m at 20° south of east),

x-component = 82 cos(-20°) = 78.72 m

y-component = 82 sin(-20°) = -28.12 m

Third displacement (28 m at 30° west of north),

x-component = 28 sin(30°) = 14 m

y-component = 28 cos(30°) = 24.24 m

We can add the x-components and y-components separately to get the total displacement,

x-displacement = 56.02 m + 78.72 m - 14 m = 120.74 m

y-displacement = 42.49 m - 28.12 m + 24.24 m = 38.61 m

The magnitude of the total displacement is,

|d| = √(x-displacement² + y-displacement²)

|d| = √(120.74² + 38.61²)

|d| = 126.0 m.

The direction of the total displacement can be found using the inverse tangent function,

θ = atan(y-displacement/x-displacement)

θ = atan(38.61/120.74)

θ = 17.4° north of east. Therefore, the student's final position is 126.0 m at 17.4° north of east.

b. To return to her initial position, the student would need to walk the same distance and direction as her total displacement but in the opposite direction. The opposite direction of 17.4° north of east is 162.6° south of west. Therefore, she would need to walk 126.0 m at 162.6° south of west to return to her initial position.

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Answer: option D: 4200 kg-m/s north.

Explanation: The energy of the primary car moving north is:

p1 = m1 * v1 = 800 kg * 15 m/s = 12,000 kg·m/s north

The force of the moment car moving south is:

p2 = m2 * v2 = 900 kg * (-18 m/s) = -16,200 kg·m/s north

Note that the energy of the moment car is negative because it is moving within the inverse heading to the positive course we have chosen.

To discover the combined force, we include the person momenta:

p_total = p1 + p2 = 12,000 kg·m/s north - 16,200 kg·m/s north = -4,200 kg·m/s north

In this manner, the combined momentum of the two cars is 4,200 kg·m/s within the north course.