Answer:
Answer:
2.5 m
Explanation:
Load ( L ) = 500 N
Effort ( E ) = 200 N
Load distance ( LD ) = 3 m
Effort distance ( ED ) = ?
Now, Let's find the Effort distance ( ED )
We know that,
Output work = Input work
i.e L × LD = E × ED
plug the values
multiply the numbers
Swipe the sides of the equation
Divide both sides of the equation by 200
Calculate
Hope this helps..
best regards!!
The frequency of sound wave A is 250 Hz. Find the time period.
the current in circuit a is two times the current in circuitb. the light bulb in circuit a has one half the resistance of the light bulb in circuit b. which cicuit has the greatest power? and by waht factor
The power in circuit A is two times the power in circuit B. Therefore, Circuit A has the greatest power, and it is by a factor of 2.
Given that the current in circuit A is two times the current in circuit B and the light bulb in circuit A has one-half the resistance of the light bulb in circuit B, we need to find out which circuit has the greatest power.
The power of an electric circuit is given as `P = VI`, where V is the voltage across the circuit and I is the current flowing through the circuit. The voltage across a circuit is directly proportional to the resistance of the circuit.
That is, as the resistance of a circuit increases, the voltage across the circuit also increases.
Hence, we can rewrite the equation for power as `P = I²R`.
For circuit A, let the current be I₁ and resistance be R₁. For circuit B, let the current be I₂ and resistance be R₂.
Given that, I₁= 2I₂ and R₁ = (1/2)R₂.
Substituting the values in the equation for power,
P1 = I₁²R₁ and P₂
= I₂²R₂P₁/P₂
= (I1²R₁) / (I₂²R₂)
= (4I₂²(1/2)R₂) / (I₂²R₂)
= 2/1
= 2
Hence, the power in circuit A is two times the power in circuit B.
Therefore, Circuit A has the greatest power, and it is by a factor of 2.
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A rock climber, of total mass 62kg, holds herself in horizontal equilibrium against a vertical cliff. She pulls
on a rope that is fixed at the top of the cliff and presses her feet against the cliff.
(a) Calculate the total weight of the climber.
(b) State the two conditions needed for equilibrium.
(c) The climber’s centre of mass is 0.90m from the cliff.
(i) Calculate the moment about her feet due to her weight
(ii) The line of the rope meets the horizontal line through her centre of mass at distance of 1.2m from the
cliff, as shown in the figure. The rope is at an angle of 60° to the horizontal. Determine the tension in the
rope. (Take g = 10ms-2
)
Answer:
(a) The total weight of the climber is equal to her mass multiplied by the acceleration due to gravity. Therefore, W = mg = 62 kg x 10 m/s^2 = 620 N.
(b) The two conditions needed for equilibrium are that the net force acting on the climber is zero and the net torque acting on the climber is zero.
(c)(i) The moment about her feet due to her weight is equal to the weight of the climber multiplied by the distance between her feet and the cliff. Therefore, M = W x d = 620 N x 0.9 m = 558 Nm.
(ii) To determine the tension in the rope, we need to resolve the forces acting on the climber in the horizontal and vertical directions. In the horizontal direction, the tension in the rope is balanced by the force of friction between the climber's feet and the cliff. Therefore, T = F.
In the vertical direction, the climber's weight is balanced by the normal force of the cliff and the tension in the rope. Therefore, N + Tcos(60) = W.
Since the climber is in equilibrium, the net torque acting on her must be zero. Therefore, the torque due to the tension in the rope must be equal and opposite to the torque due to the climber's weight. Therefore, Tsin(60) x 1.2 = M.
Substituting the values we have, we get:
N + Tcos(60) = W
Tsin(60) x 1.2 = M
Solving for T, we get:
N = W - Tcos(60) = 620 N - T(0.5)
Substituting this into the second equation, we get:
Tsin(60) x 1.2 = M
Tsin(60) = M / 1.2 = 558 Nm / 1.2 m = 465 N
Substituting this value of T into the first equation, we get:
N = 620 N - T(0.5) = 620 N - 465 N(0.5) = 388 N
Therefore, the tension in the rope is 465 N and the normal force of the cliff on the climber is 388N
What is the density of mercury if 67.67g fills a 2mL graduated cylinder? Include the unit
for full credit (remember the unit is mass unit /volume unit).
Answer:
[tex]Density = 33835kg/m^3[/tex]
Explanation:
Given
[tex]Mass = 67.67g[/tex]
[tex]Volume = 2mL[/tex]
Required
Determine the density
[tex]Density = \frac{Mass}{Volume}[/tex]
First, we need to convert mass to kg
[tex]Mass = 67.67g[/tex]
[tex]Mass = \frac{67.67kg}{1000}[/tex]
[tex]Mass = 0.06767kg[/tex]
Next, we need to convert volume to m^3
[tex]Volume = 2mL[/tex]
[tex]Volume = 2 * 10^{-6}m^3[/tex]
Density is then calculated as follows:
[tex]Density = \frac{0.06767}{2 * 10^{-6}}[/tex]
[tex]Density = \frac{0.06767 * 10^6}{2}[/tex]
[tex]Density = \frac{67670}{2}[/tex]
[tex]Density = 33835kg/m^3[/tex]
weightless spring has a spring constant of 1.85 n/m. a 500-g mass is attached to the spring. it is then displaced 10.0 cm and released. find the total energy of the mass
The mass is displaced 10.0 cm and released. We will use the formula for the total energy of the mass.Total energy of a mass-energy system is the sum of potential energy and kinetic energy. Mathematically, it is given as:Etotal = Ep + Ekwhere,
Etotal = Total energy of the systemEp = Potential energy of the systemEk = Kinetic energy of the systemGiven,Mass of the system = 500 g = 0.5 kgSpring constant of the spring, k = 1.85 N/mDisplacement, x = 10.0 cm = 0.1 mWe can find the potential energy of the mass using the formula for potential energy stored in a spring as,Ep = (1/2)kx²Putting the values,Ep = (1/2) × 1.85 N/m × (0.1 m)²Ep = 0.00925 JThe mass is displaced and released, so the potential energy of the mass converts into kinetic energy at the maximum displacement.
Therefore, we can find the kinetic energy of the mass using the formula,Ek = (1/2)mv²where, v is the velocity of the mass at maximum displacement. We can find the velocity using the conservation of energy principle that is total energy of the system is equal to kinetic energy at the maximum displacement.Etotal = EkUsing the values,0.00925 J + Ek = EkEk = 0.00925 JThe kinetic energy is also given asEk = (1/2)mv²Putting the values,0.00925 J = (1/2) × 0.5 kg × v²v² = 0.0185 m²/s²v = 0.136 m/sNow, we can calculate the kinetic energyEk = (1/2)mv²Putting the values,Ek = (1/2) × 0.5 kg × (0.136 m/s)²Ek = 0.00587 JTherefore, the total energy of the mass attached to the spring is,Etotal = Ep + Ek= 0.00925 J + 0.00587 J= 0.01512 JHence, the total energy of the mass is 0.01512 J.
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What is the equivalent resistance (total resistance) of the series circuit shown?
Answer:
In a series circuit, the equivalent resistance is the algebraic sum of the resistances. The current through the circuit can be found from Ohm's law and is equal to the voltage divided by the equivalent resistance. The potential drop across each resistor can be found using Ohm's law.
Why ground roll cannot be separated from reflectors in F-K
domain?
In the F-K domain, ground roll cannot be separated from reflectors as it refers to the low-frequency noise or energy that is associated with seismic waves propagating through the near-surface layers of the Earth.
It typically appears as a coherent and continuous signal in the seismic data. In the F-K domain, which represents the data in terms of frequency and wavenumber, the ground roll and the reflectors share similar characteristics in terms of their frequency content and wavenumber distribution. As a result, it becomes challenging to separate the ground roll from the reflectors based solely on their F-K domain representation.
The F-K domain provides information about the frequency and spatial characteristics of the seismic data. However, it does not provide direct information about the physical properties or origins of the seismic energy. Both ground roll and reflectors can have similar frequency-wavenumber signatures, making it difficult to distinguish between them in this domain. Additional processing techniques and analysis, such as filtering or velocity analysis, are often required to separate the ground roll from the desired reflectors and enhance the interpretability of the seismic data.
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A 65 kg person dives into the water from the 10 m platform. a. What is her speed as she enters the water? (Hint: Think freefall.) h=12mm=65 kg V= 2⋅9.8⋅10V= 196 V=14 m/s b. She comes to a stop 2.0 m below the surface of the water. Sketch a force diagram of the diver and a kinematics stacks at right. c. What sum force did the water exert on the swimmer? What direction is this sum force?
A 65 kg person dives into the water from the 10 m platform.(a)The speed of the person as she enters the water is approximately 14 m/s.(c) The sum force exerted by the water on the swimmer is equal to the buoyant force and acts in the upward direction.
a. The speed of the person as she enters the water can be determined using the equation for free fall.
Given:
Mass of the person (m) = 65 kg
Height of the platform (h) = 10 m
Acceleration due to gravity (g) = 9.8 m/s^2
Using the equation for free fall:
v = √(2 ×g ×h)
Substituting the given values:
v = √(2 × 9.8 m/s^2 ×10 m)
v = √(196 m^2/s^2)
v ≈ 14 m/s
Therefore, the speed of the person as she enters the water is approximately 14 m/s.
b. Unfortunately, as a text-based AI, I am unable to directly sketch a force diagram or kinematics stack. However, I can describe them to you:
Force diagram:
Weight (mg): The force of gravity acting vertically downward with a magnitude of 65 kg * 9.8 m/s^2.
Buoyant force (Fb): The upward force exerted by the water on the diver, opposing the force of gravity
Kinematics stack:
Initial velocity (Vi): The initial velocity of the diver as she enters the water, which is 14 m/s.
Final velocity (Vf): The final velocity of the diver as she comes to a stop 2.0 m below the water's surface, which is 0 m/s.
Acceleration (a): The deceleration experienced by the diver as she comes to a stop.
c. To determine the sum force exerted by the water on the swimmer, we need to consider the forces acting on the diver when she comes to a stop below the surface of the water.
The sum force exerted by the water on the swimmer is equal to the buoyant force acting on her, as this force balances out the force of gravity (weight) to bring her to a stop. The direction of the sum force is upward, opposing the downward force of gravity.
Therefore, the sum force exerted by the water on the swimmer is equal to the buoyant force and acts in the upward direction.
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a uniformly charged rod with length and line charge density is bent to form one quadrant of a circle. what is the magntiude of the electric field at the center of the circle?
Let's consider a uniformly charged rod with length "l" and line charge density "λ." A quadrant of a circle with radius "R" is formed by bending the rod. We have to find out the magnitude of the electric field at the center of the circle. Let's assume that the arc is made up of n sections.
For small segments of the arc, we can assume the electric field is constant and perpendicular to the segments. Hence, we can treat each segment as a point charge with the amount of charge given by dq = λ × ds. Here, "ds" is the small length of the arc segment, and "λ" is the line charge density. The distance from each segment to the center of the arc is equal to R.
Let's find out the magnitude of the electric field at the center of the circle by using the formula;
E = ∫ dE
The formula for the electric field due to a point charge q at a distance r is:
E = k × (q / r²)
Here, k is Coulomb's constant, which is equal to 9 × 10⁹ Nm²/C².So, we can write the equation for dE as;d
E = k × dq / r² Now, let's substitute the value of "dq" into the above equation;
dE = k × λ × ds / R² For a quadrant of a circle, we have a total length of πR/2. If we divide the arc into n sections, each section will have a length of (πR/2) / n. Hence, we can write the total electric field at the center as;
E = ∑ dE
= k × λ × (∑ ds / R²)
= k × λ × (∑ (πR/2) / n × R²)
= (kλπR) / (2n)
As we know, the line charge density (λ) = q/l. So, we can rewrite the above equation as:
E = (kqπR) / (2nl)
Therefore, the magnitude of the electric field at the center of the circle is given by; E = (kqπR) / (2nl)
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The Navy Pier Ferris Wheel in Chicago has a circumference that is 56% of the circumference of the first Ferris wheel built in 1893. a. What is the radius of the Navy Pier Ferris Wheel? To the nearest foot, the radius of the Navy Pier Ferris Wheel is 1$$70 feet. b. What was the radius of the first Ferris wheel? To the nearest foot, the radius of the first Ferris wheel was 2$$125 feet. c. The first Ferris wheel took 9 minutes to make a complete revolution. How fast was the wheel moving? To the nearest tenth, the wheel was moving at a speed of 3$$87.2 feet per min
Answer: a. 70 ft
b. 125 ft
c. 87.2 ft/sec
Explanation:
Here is the complete question:
If the navy pier ferris wheel in chicago has a circumference that is 56% of the circunference of the first ferris wheel built in 1893.
a. What is the radius of the navy pier wheel?
b. what was the radius of the first ferris wheel?
c. The first ferri wheel took nine minutes to make a complete revolution. how fast was the wheel moving?
C=439.6 ft.
a. What is the radius of the navy pier wheel?
Since circumference = 2πr
where π = 3.142
r = radius
Therefore, 2πr = 439.6
(2×3.142×r) = 439.6
6.284r = 439.6
Radius = 439.6/6.284
Radius = 69.9 = 70 feet
b. What was the radius of the first ferris wheel?
Since the Navy Pier Ferris Wheel in Chicago has a circumference that is 56% of the circumference of the first Ferris wheel. This can be mathematically written as:
56% of f = 439.6
0.56f = 439.6
f = 439.6/0.56
f = 785
The circumference of the first wheel is 785ft
Radius will now be:
2πr = 785
r = 785/2π
r = 785/(2×3.142)
r = 785/6.284
r = 124.9 = 125ft
c. The first ferri wheel took nine minutes to make a complete revolution. how fast was the wheel moving?
= 785/9
= 87.2 ft/sec
What quantity (or quantities) is transferred during an interaction between two obiects.
During a contact push/pull interaction between two objects, what do you think is transferred from one obiect to the other? At a speed-time graph and infer something about the force acting on the object, to look at a force-time graph and infer something about how the speed of the object is changing.
During a contact push/pull interaction between two objects, the quantity that is transferred from one object to the other is force.
When an object exerts a force on another object, that force is transmitted through the contact point, causing the second object to experience an equal and opposite force. This transfer of force allows for the interaction and results in the acceleration or movement of the objects.
By examining a speed-time graph, we can infer something about the force acting on the object. If the graph shows a steep upward slope, it indicates that the object is experiencing a large acceleration and therefore a significant force is being applied to it. On the other hand, a flat line on the graph suggests that the object is moving at a constant speed, indicating a balance between the forces acting on it.
Similarly, by looking at a force-time graph, we can infer something about how the speed of the object is changing. If the graph shows a sudden increase or decrease in force, it indicates a change in the object's acceleration. This change in acceleration will, in turn, affect the object's speed. For example, a sudden increase in force would imply an increase in acceleration and therefore an increase in speed, while a decrease in force would suggest a decrease in acceleration and a decrease in speed.
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a 5.50-kg bowling ball moving at 9.00 m/s collides with a 0.850-kg bowling pin, which is scattered at an angle to the initial direction of the bowling ball and with a speed of 15.0 m/s. what is the magnitude of the final velocity of the bowling ball?
The magnitude of the final velocity of the bowling ball is 4.31 m/s.ExplanationAccording to the Law of Conservation of Momentum, the initial momentum of the system is equal to the final momentum of the system before and after the collision.
This can be mathematically represented as:Initial momentum of the system = Final momentum of the systemInitially, the bowling ball is moving with a velocity of 9.00 m/s and has a mass of 5.50 kg. The bowling pin has a mass of 0.850 kg, and its velocity after the collision is 15.0 m/s.
Let v be the velocity of the bowling ball after the collision, then applying the law of conservation of momentum;5.5 kg × 9.0 m/s + 0.85 kg × 0 = (5.5 kg + 0.85 kg) × vfinal = 4.31 m/sTherefore, the magnitude of the final velocity of the bowling ball is 4.31 m/s.
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what color is the sky when you feel down
Answer:
black
Explanation:
Answer:
Still blue bc it doesn't change just bc you feel down
Explanation:
the blank tells how many and the blank tells of what
Answer: and a theme
Explanation:
what is a radio active element
A radioactive element, also known as a radionuclide or radioisotope, is an element that exhibits radioactivity.
Radioactive elements are the elements that have an unstable nucleus and emit radiation when their nucleus undergoes a process called radioactive decay. Radioactive decay is a random process that occurs in some of the elements with unstable atomic nuclei.
During this process, the nucleus emits alpha, beta, or gamma particles, which transform the nucleus into a more stable state. As a result, these elements are radioactive and can release high-energy particles or electromagnetic waves in the form of radiation, which can be dangerous for living organisms. Radioactive elements are mainly classified into two types: natural radioactive elements and artificially produced radioactive elements.
Natural radioactive elements are those that occur in nature, and their nuclei naturally undergo radioactive decay. For example, Uranium, thorium, and radium are natural radioactive elements. The artificially produced radioactive elements are those that are synthesized through nuclear reactions in a laboratory. For example, technetium and plutonium are artificially produced radioactive elements.
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A small object A, electrically charged, creates an electric field. At a point P located 0.250 m directly north of A, the field has a value of 40.0 N/C directed to the south. What is the charge of object A? a. 1.11 Times 10^-9 C b. -1.11 Times 10^-9 C c. 2.78 Times 10^-10 C d. -2.78 Times 10^-10 C e. 5.75 Times 10^12 C f. -5.75 Times 10^12 C
The electric field created by a point charge is given by the equation E = k * (Q / [tex]r^{2}[/tex]).The charge of object A is -1.11 × [tex]10^{-9}[/tex] C (option b).
In this case, the electric field at point P is 40.0 N/C directed to the south. Since the field is directed towards the south, the charge of object A must be negative. Plugging the given values into the equation, we have:
40.0 N/C = (9 × [tex]10^{9}[/tex] N [tex]m^2/C^2[/tex]) * (Q / (0.250 [tex]m)^2)[/tex]
Simplifying the equation, we can solve for Q:
Q = (40.0 N/C) * (0.250 [tex]m)^2[/tex] / (9 × 10^9 N [tex]m^2/C^2)[/tex]
Calculating the expression, we find Q ≈ -1.11 × [tex]10^{-9}[/tex] C. Therefore, the charge of object A is approximately -1.11 × [tex]10^{-9}[/tex] C, which corresponds to option b.
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Typical electrical wires in your house are generally made of copper (electron density of 8.47∗1024 electrons per cm3 ) and are usually either 14 gauge (diameter of 1.63 mm ), 12 gauge (diameter of 2.05 mm ), or 10gauge(2.59 mm) wires.
(A) If you have a 14 gauge wire that is carrying the maximum current of 20 , what would be the average drift speed of the electrons in the wire? Tries 1/8
(B) Usinq the averaqe speed you just calculated in Part (A), how much time would it take an electron to travel 8.84 m?
A. The average drift speed of the electrons in the wire is 1.19 x [tex]10^{-3}[/tex]cm/s.
B. The time it would take an electron to travel 8.84 m is 7.43 x [tex]10^{5}[/tex]sec
(A) To find the average drift speed of electrons in a wire, we can use the equation:
I = nAvq
Where:
I is the current in Amperes
n is the electron density in electrons per [tex]cm^{3}[/tex]
A is the cross-sectional area of the wire in [tex]cm^{2}[/tex]
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x [tex]10^{-19}[/tex] Coulombs
First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:
A = π[tex]r^{2}[/tex]
Where:
A is the area of the circle
r is the radius of the circle
Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:
r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm
Now, we can calculate the area:
A = [tex]π(0.0815 cm)^{2}[/tex] = 0.0209 [tex]cm^{2}[/tex]
Next, we can rearrange the equation to solve for v:
v = I / (nAq)
Given that the current is 20 A and the electron density is 8.47 x [tex]10^{24}[/tex]electrons per [tex]cm^{3}[/tex], we can substitute these values into the equation:
v = 20 A / (8.47 x [tex]10^{24}[/tex] electrons per cm^3 * 0.0209 cm^2 * 1.6 x [tex]10^{-19}[/tex] C)
Simplifying the expression:
v = 1.19 x [tex]10^{-3}[/tex] cm/s
Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x [tex]10^{-3}[/tex] cm/s.
(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:
t = d / v
Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second
Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:
v = 1.19 x [tex]10^{-3}[/tex] cm/s * 0.01 m/cm = 1.19 x [tex]10^{-5}[/tex] m/s
Now, we can substitute the values into the formula:
t = 8.84 m / 1.19 x [tex]10^{-5}[/tex]m/s
Simplifying the expression:
t = 7.43 x [tex]10^{5}[/tex]s
Therefore, it would take approximately 7.43 x [tex]10^{5}[/tex] seconds for an electron to travel a distance of 8.84 m.
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A 148-g baseball is dropped from a tree 15.0 m above the ground.
If it actually hits the ground with a speed of 7.50 m/s, what is the magnitude of the average force of air resistance exerted on it?
The magnitude of the average force of air resistance exerted on the baseball is 0.313 N.
To find the magnitude of the average force of air resistance exerted on the baseball, we can use the principles of kinematics and dynamics. When the baseball is dropped from a height of 15.0 m, it undergoes free fall under the influence of gravity. The acceleration due to gravity is approximately 9.8 [tex]m/s^2.[/tex]
Using the equation of motion for free fall, we can find the time it takes for the baseball to reach the ground. The equation is:
[tex]h = (1/2)gt^2,[/tex]
where h is the height, g is the acceleration due to gravity, and t is the time. Rearranging the equation, we have:
[tex]t^2 = (2h)/g.[/tex]
Plugging in the values, we find:
[tex]t^2 = (2 * 15.0 m) / (9.8 m/s^2).[/tex]
Calculating this expression, we get t = 1.75 s. This is the time it takes for the baseball to fall and reach the ground.
Next, we can use the equation of motion to find the average force of air resistance. The equation is:
v = gt,
where v is the final velocity of the baseball (7.50 m/s) and g is the acceleration due to gravity. Rearranging the equation, we have:
t = v/g.
Plugging in the values, we find:
[tex]t = (7.50 m/s) / (9.8 m/s^2)[/tex]
Calculating this expression, we get t = 0.765 s. This is the time it takes for the baseball to decelerate from its initial velocity to 0 m/s due to air resistance.
Finally, we can use Newton's second law of motion to find the magnitude of the average force of air resistance. The equation is:
F = mΔv/Δt,
where F is the force, m is the mass of the baseball (148 g), Δv is the change in velocity, and Δt is the change in time. Since the baseball starts from rest, Δv is equal to the final velocity (7.50 m/s). Plugging in the values, we find:
F = (148 g)(7.50 m/s) / (0.765 s).
Calculating this expression, we get F = 0.313 N. Therefore, the magnitude of the average force of air resistance exerted on the baseball is 0.313 N.
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How strong is the electric field between the plates of a 0.80 μF air-gap capacitor if they are 3.0 mm apart and each has a charge of 77 μC ?
The electric field between the plates of a 0.80 μF air-gap capacitor with charges of 77 μC and a plate separation of 3.0 mm is 34,222 V/m.
The electric field (E) between the plates of a capacitor can be calculated using the following formula:
E = V/d
where V is the potential difference between the plates and d is the distance between the plates.
The potential difference (V) between the plates of the capacitor can be calculated using the following formula:
V = Q/C
where Q is the charge on each plate and C is the capacitance of the capacitor.
Substituting the given values, we get:
Q = 77 μC
C = 0.80 μF
d = 3.0 mm = 0.003 m
Using the formula for potential difference, we get:
V = Q/C
= (77 × 10^-6 C) / (0.80 × 10^-6 F)
= 96.25 V
Using the formula for electric field, we get:
E = V/d = (96.25 V) / (0.003 m)
= 34,222 V/m
Therefore, the electric field between the plates of the capacitor is 34,222 V/m.
In conclusion, we have calculated the electric field between the plates of a 0.80 μF air-gap capacitor with charges of 77 μC and a plate separation of 3.0 mm. The result of our calculation is that the electric field is 34,222 V/m.
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safety is one of the main concerns surrounding nuclear power. one issue is that once fission in a reactor has been started, additional heat is produced from post-fission radioactive decays and will continue even after the reactor is shut off. for which of the essential safety functions does this cause the most trouble?
The essential safety function that is most troubled by the additional heat produced from post-fission radioactive decays, which continues even after the reactor has been shut off, is called decay heat removal. Decay heat is the heat that is produced as a result of nuclear fission and radioactive decay of the nuclear fuel inside the reactor even after the reactor has been shut down and the control rods have been inserted into the core to stop the nuclear reaction.
Therefore, the decay heat removal function is one of the most important safety functions of a nuclear power plant. This is because, if the decay heat is not removed from the reactor core, the core can overheat and cause a nuclear meltdown, which can have catastrophic consequences. Several cooling systems are used to remove decay heat from the reactor core, such as the primary coolant system, the secondary coolant system, and the emergency cooling system.
These systems remove heat from the reactor core and transfer it to the environment outside the power plant through a series of heat exchangers. It is essential to keep these cooling systems working in case of an emergency shutdown. If they fail, the reactor core will become too hot and could melt, releasing radioactive material into the environment, and leading to serious health risks and environmental damage.
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A car drives 2 miles north, 4 miles west, 2 miles south and then drives 6 miles east. What is the car's distance?
What is the car's displacement in this same example? (2 answers) (Must show work)
Answer:
Ok, so the car has traversed a total of 2 + 4 + 2 + 6 = 14 miles.
That's the car's distance! :)
For the displacement, you can draw out a diagram. I'll try my best to make one using a keyboard xDDD
- - - - |
| |
| - - - start - end!
So, this is the journey of the car: Going two up, 4 left, 2 down, and 6 right.
This ends up 2 to the right of the beginning!
That's a 2 mile displacement :)
Can you give me brainliest for my splendid diagram? xD
find the most probable speed for nitrogen molecules at 295 k. group of answer choices 320 m/s 419 m/s 450 m/s 519 m/s
The most probable speed for nitrogen molecules at 295K can be found using the Maxwell-Boltzmann distribution of speeds equation. The equation is as follows:f(v) = 4π(\frac{m}{2πkT})^{\frac{3}{2}}v^2e^{\frac{-mv^2}{2kT}}$$where,m = \text{mass of one molecule of nitrogen}T = \text{temperature in Kelvi k = \text{Boltzmann constant}
Now, substituting the values for nitrogen molecules, we get,$$m = 4.65 × 10^{-26}\text{ kg}$$$$T = 295 \text{ K}k = 1.38 × 10^{-23}\text{ J/K}Substituting these values in the equation, we get,f(v) = 4π(\frac{4.65 × 10^{-26}}{2π×1.38 × 10^{-23}×295})^{\frac{3}{2}}v^2e^{\frac{-4.65 × 10^{-26}v^2}{2×1.38 × 10^{-23}×295}}Simplifying the expression gives:f(v) = 4.351 × 10^{-25}v^2e^{\frac{-5.022 × 10^{-27}v^2}{1}}We need to find the most probable speed, which is where the distribution function is maximum. Therefore, we differentiate the above equation w.r.t. v and equate it to zero.f'(v) = 0\frac{d}{dv}[4.351 × 10^{-25}v^2e^{\frac{-5.022 × 10^{-27}v^2}{1}}] = 08.702 × 10^{-25}v e^{\frac{-5.022 × 10^{-27}v^2}{1}}- 2.575 × 10^{-51}v^3 e^{\frac{-5.022 × 10^{-27}v^2}{1}}= 0$$$$v = \sqrt{\frac{2kT}{m}} = \sqrt{\frac{2×1.38 × 10^{-23}×295}{4.65 × 10^{-26}}} = 517.3 \text{ m/s}$$Therefore, the most probable speed for nitrogen molecules at 295K is 517.3 m/s (approx). Hence the closest option available is 519 m/s.For such more question on temperature
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The most probable speed for nitrogen molecules at 295 K can be calculated using the formula: VMP = √(2kT/m) T is the temperature in Kelvin, and m is the mass of the molecule in kilograms.
For nitrogen (N2),
m = 28 g/mol or 0.028 kg/mol. Now, let's plug in the values:
vmp = [tex]√(2(1.38 × 10^-23 J/K)(295 K)/(0.028 kg/mol)[/tex]
)vmp = [tex]√(8.038 × 10^-21 J/kg)[/tex]
vmp =[tex]8.96 × 10^2 m/s[/tex]
Therefore, the most probable speed for nitrogen molecules at 295 K is approximately 896 m/s. the most probable speed for nitrogen molecules at 295 K" is 896 m/s.
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Consider a lawnmower of mass m which can slide across a horizontal surface with a coefficient of friction μ. In this problem the lawnmower is pushed using a massless handle, which makes an angle θ with the horizontal. Assume that Fh, the force exerted by the handle, is parallel to the handle. Take the positive x direction to be to the right and the postive y direction to be upward. Use g for the magnitude of the acceleration due to gravity.
Find the magnitude, Fh, of the force required to slide the lawnmower over the ground at constant speed by pushing the handle.
The magnitude of the force required to slide the lawnmower over the ground at constant speed by pushing the handle is given by Fh = mg * μ * sin(θ).
To determine the force required, we consider the forces acting on the lawnmower. The force of gravity pulling the lawnmower downward can be represented by mg, where m is the mass of the lawnmower and g is the acceleration due to gravity. The normal force exerted by the ground balances out the force of gravity in the vertical direction.
In the horizontal direction, the force required to overcome the frictional force is given by F_friction = μ * N, where μ is the coefficient of friction and N is the normal force. The normal force can be calculated as N = mg * cos(θ).
Since the lawnmower is pushed at constant speed, the applied force Fh must exactly balance the frictional force. Therefore, Fh = F_friction = μ * N = μ * mg * cos(θ).
Simplifying the equation, we have Fh = mg * μ * cos(θ). However, we are given that Fh is parallel to the handle, which means it is in the horizontal direction. Thus, we need to consider the horizontal component of the force, which is Fh = mg * μ * sin(θ).
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The force required to slide the lawnmower over the ground at constant speed can be calculated using the formula Fh = μ * m * g, where Fh is the force exerted by the handle, μ is the coefficient of friction, m is the mass of the lawnmower, and g is the acceleration due to gravity.
Explanation:In this problem, we need to consider two directions; the horizontal (x-direction) and the vertical (y-direction). In the horizontal direction, we know that the force exerted by the handle must overcome the frictional force on the lawnmower. Since the lawnmower moves at a constant speed, the net force in the horizontal direction is zero (0).
Thus, Fh * cosθ (component of the handle's force in the x-direction) = μ * m * g * cosθ (friction).
Through this we establish that Fh = μ * m * g.
Where:
Fh is the force exerted by the handle.
μ is the coefficient of friction.
m is the mass of the lawnmower.
g is the acceleration due to gravity.
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The ____ will convert the electrical energy to some other form of energy.
a load
b battery
c wire
d conductor
Answer:
I believe it d I'm not completely sure but yeah
Please help me please
Why force is directly proportional to mass product of the two object?
Answer:
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.
Explanation
Explain how each of the following changes as you travel across the spectrum: wavelength, frequency, and energy
The frequency and energy increases while the wawelength decreases on moving from left to right.
Since the energy of the wave is directly proportion to the frequency and indirectly proportionl to the wavelength.
On moving from left to right (Gamma to radio waves), the wavelenth in creases.On moving from left to right (Gamma to radio waves), frequency decreases.On moving from left to right (Gamma to radio waves), energy decreases.To know more about energy of the wave,
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interrelationship between health population and environment education and Science and Technology
Answer:
Answer: Science and technology are relatively modern developments. For most of the past 50,000 years of civilization, there was religion, dogma, ritual an tradition. These kept civilization safe but prevented growth.
After the modern scientific method was developed during the Rennaisance, civil action took off.
Health, as expressed as life expectancies, has increased massively. Population growth has increased to levels thought impossible before. But yes, the environment has suffered.
Why does Ice melt in an open space?
proof the equation of motion third
The proof of third equation of motion is determined as v² = 2as + u².
What is the proof of third equation of motion?
The proof of third equation of motion is determined as follows;
The first equation is given as;
v = u + at
t = ( v - u ) /a
where;
u is the initial velocitya is the accelerationt is the time of motionThe formula for the average distance traveled by an object is;
s = (v + u)/2 x t
Expand the equation above as;
s = (v + u)/2 x (v - u)/a
s = (v² - u²) / 2a
2as = v² - u²
v² = 2as + u², proved
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