Simplify the following polynomial expression.
(5x4 - 9x3 + 7x - 1) + (-8x4 + 4x2 - 3x + 2) - (-4x3 + 5x - 1)(2x - 7)

Step-by-step explanation:

that is only possible, if we don't need to use a 2 and a 5 (but especially the 2) to create the 1 in the middle (log(10) = log(2×5) or log (5×2) = 1).

in other words, if the 1 in the middle is just a given, and does not use any of our digits for is creation, then a solution is possible.

first of all, the upper left corner has to be log(0⁰). we cannot use the digit 0 for anything else. and 0^n (except for n = 0) is not a valid argument for a logarithm.

log(0⁰) = 0 log(2×1) = 0.3... log(9/4) = 0.35...

log(1×2) = 0.3... 1 log(3×6) = 1.26...

log(7/3) = 0.37... log(4×5) = 1.3... log(6⁹) = 7.0...

but as soon as we need to build the center 1 by log(10), which takes then away one of the 2s (as the only way to build 10 by multiplication is 2×5 or 5×2), there is no possible solution.

Answer:

Please see attachment.

Step-by-step explanation:

There are many possible solutions to this problem.

A few things to note:

There are 8 red boxes and 8 blue boxes, so we do not have to use every digit from 0 to 9.

Place zero in the blue box in the top left of the grid, since any number raised to zero is 1 and [tex]\log_a1=0[/tex].  Leave the red box blank for the moment, and fill it with any number not used at the end.

The value of the product of the red and blue boxes in the top-middle and left-middle of the grid should be less than 10.  It is advisable to place the lowest numbers in these boxes, i.e. 1 and 2.

The value of the product of the red and blue boxes in the bottom-middle and right-middle of the grid should be more than 10.  

It is advisable to place some of the highest numbers in the bottom right corner of the grid, as this is the box with the greatest value.

Please see the attached image for one possible way of filling the grid.  The actual values of the logarithms (to 3 decimal places) have been placed in the bottom right corners of each box of the grid for verification.

The measure of the angle ∠PQR is 90 degrees

The equation of the line PQ is given as:

3x - y - 2 = 0

The coordinates of the QR are given as:

(0, -2) and (6, -4)

Make y the subject in 3x - y - 2 = 0

y = 3x - 2

The slope of the above line is

m1 = 3

Next, we calculate the slope (m2) of points Q and R.

So, we have:

m2 = (y2- y1)/(x2 - x1)

This gives

m2 = (-4 + 2)/(6 - 0)

Evaluate

m2 = -1/3

The slopes of perpendicular lines are opposite reciprocals.

m1 = 3 and m2 = -1/3 are opposite reciprocals.

This means the lines PQ and QR are perpendicular lines.

The angle at the point of perpendicularity is 90 degrees

Hence, the measure of the angle ∠PQR is 90 degrees

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The statement that justifies the relationship is: D. it represents a function because no length has more than one price.

For a relation to be considered a function, any of the following criteria must be met:

In the scenario given:

Length of ribbon = input (x-value)

Price of ribbon = output (y-value).

We can observe that each length of ribbon (input) has its own price (output), therefore, we can conclude that the price of ribbon is a function of the length of the ribbon.

The answer is: D. This relationship represents a function because no length has more than one price.

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Answer:

C. 109x

Step-by-step explanation:

We know that there are 109 students in the fourth grade, who each have x cupcakes. In order to find the total amount of cupcakes, we could add all of the cupcakes together to get:

x + x + x + x + .... x

109 times because there are 109 students.

This can be simplified to become 109x.  

Applying the same-side interior angles theorem,

7. m∠4 = 50°; m∠5 = 130°

8. m∠2 = 15°; m∠8 = 15°.

The same-side interior angles theorem holds that, two interior angles on a side of a transversal are supplementary, that is they add up to 180 degrees.

According to the alternate exterior angles theorem, exterior angles that alternate each other along a transversal are congruent, that is they have equal measures.

7. m∠4 + m∠5 = 180 [same-side interior angles theorem]

Substitute

y + 2y + 30 = 180

3y + 30 = 180

3y = 180 - 30

3y = 150

y = 50

m∠4 = y = 50°

m∠5 = 2y + 30 = 2(50) + 30

m∠5 = 130°

8. m∠2 = m∠8 [alternate exterior angles theorem]

Substitute

x - 30 = 3x - 120

x - 3x = 30 - 120

-2x = -90

x = 45

m∠2 = x - 30 = 45 - 30 = 15°

m∠8 = 3x - 120 = 3(45) - 120 = 15°

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The median value is 63 and Lower quartile range is 48 and Interquartile range is 80.

According to the given statement

we have given data set and we have to find the five number summary.

So, For this purpose,

the given data set is:

48, 50, 54, 56, 63, 63, 64, 68, 74, 74, 79, 80

Firstly we have to find the upper quartile means median for it.

So, Median = n /2

median = 12/2

median = 6th term.

So, Upper quartile range for this data set is 63.

And

Lower quartile for data set is the lower value of the data set.

So, That's why

Lower quartile range for this data set is 48.

And now, we have to find the Interquartile range

so, Interquartile range means maximum value of data.

So, That's why

Interquartile range of this data is 80.

So, The median value is 63 and Lower quartile range is 48 and Interquartile range is 80.

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Answer:

perimeter = 24

Step-by-step explanation:

formula:

In an equilateral triangle with sides of lengths ‘a’

The height of the triangle is equal to :

[tex]= \frac{\sqrt{3} }{2} a[/tex]

……………………………………………

Calculating ‘a’ :

We have to solve the equation:

[tex]4\sqrt{3} =\frac{\sqrt{3} }{2} a[/tex]

[tex]\Longleftrightarrow 4=\frac{1 }{2} a[/tex]

[tex]\Longleftrightarrow a = 8[/tex]

Calculating the perimeter:

= 3a

= 3 × 8

= 24

Answer:

11. 333... which can also be written as 11 1/3.

Step-by-step explanation:

Sure.

√(6c - 4) = 8

Squaring both sides:

6c - 4 = 64

6c = 64 + 4 = 68

c = 68/6

  = 11. 333...

Answer:

[tex]c=\dfrac{34}{3}[/tex]

Step-by-step explanation:

Given equation:

[tex]\sqrt{6c-4}=8[/tex]

Square both sides:

[tex]\implies (\sqrt{6c-4})^2=8^2[/tex]

[tex]\implies 6c-4=64[/tex]

Add 4 to both sides:

[tex]\implies 6c-4+4=64+4[/tex]

[tex]\implies 6c=68[/tex]

Divide both sides by 6:

[tex]\implies \dfrac{6c}{6}=\dfrac{68}{6}[/tex]

[tex]\implies c=\dfrac{34}{3}[/tex]

Verify the solution by inputting the found value of c back into the equation:

[tex]\implies \sqrt{6\left(\dfrac{34}{3}\right)-4}[/tex]

[tex]\implies \sqrt{\dfrac{204}{3}-4}[/tex]

[tex]\implies \sqrt{68-4}[/tex]

[tex]\implies \sqrt{64}[/tex]

[tex]\implies \pm 8[/tex]

Therefore, the solution of the found value of c is verified.

The value of the given expression is 105.

To find the value of the given expression:

Follow the PEMDAS order of operations:

Multiply and divide (left to right).

Add and subtract (left to right)

Therefore, the value of the given expression is 105.

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The Created cone  with the possible record  of the the values of the radius, and  height is given in the image attached.

A scale factor is known to be a number that is known to often multiplies (doubles or triples, etc.,“scales”) a given quantity.

Since the volume is not attached, it will be manually created here.

Note that the resulting volumes must be in terms of 7.

Hence:

Volume  Formula:   V=V  x  k³

When scale factor is 2, radius  = 4, height  = 8,  then volume will be:

7π x 2³

=  56π

When scale factor is 3, radius  = 6, height  = 18,  then volume will be:

7π x 3³

= 189π

When scale factor is 4, radius  = 8, height  = 24,  then volume will be:

7π x 4³

= 448π

Hence the volume that will be fixed into the scale factor diagram will be:

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La altura del triangulo está dada por el polinomio:

p(x) = a + 4

Recordar que para un triangulo de base B y altura H, el area es

A = B*H/2

En este caso, sabemos que la base es B = (4*a^2 + 6)

Y el area es A = 2a^3 + 8a^2 +3a +12

Entoces la altura será un polinomio tal que:

P(a)*(4*a^2 + 6)/2 = 2a^3 + 8a^2 +3a +12

P(a)*(4*a^2 + 6) = 2*(2a^3 + 8a^2 +3a +12) = 4a^3 + 16a^2 + 6a + 24

Podemos ver que p(a) va a ser un polinomio de grado 1, entonces:

p(a) = (c*a + b)

Reemplazando eso:

(c*a + b)*(4*a^2 + 6) = 4a^3 + 16a^2 + 6a + 24

Expandiendo:

(4c)*a^3 + (6c)*a + (4b)*a^2 + 6*b = 4a^3 + 16a^2 + 6a + 24

Comparando terminos del mismo exponente, podemos ver que:

(4c) = 4

6c = 6

4b = 16

6b = 24

Resolviendo esas ecuaciones para c y b, podemos ver que:

b = 16/4 = 4

c = 4/4 = 1

Entonces la altura del triangulo está dada por el polinomio:

p(x) = a + 4

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the total volume of the chimney is:

V =456 in^3

Remember that the volume of a rectangular prism of dimensions L, W, and H is:

V = L*W*H

If you look at the image of the chimney (bottom right image) you can see that the figure can be viewed as 2 rectangular prisms, one smaller of dimensions:

4in x 12in x 9 in

Then the volume of the larger part is:

V = (4in)*(12in)*(9in) = 432 in^3

The smaller prism has dimensions:

of (6in - 4in) = 2in x 3in x 4in

Then the volume is:

V = (2in)*(3in)*(4in) = 24 in^3

Then the total volume of the chimney is:

V = 432 in^3 +  24 in^3 = 456 in^3

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[tex]\\ \tt{:}\dashrightarrow \ell=\dfrac{\Theta}{180}\pi r[/tex]

[tex]\\ \tt{:}\dashrightarrow \Theta=\dfrac{180\ell}{\pi r}[/tex]

[tex]\\ \tt{:}\dashrightarrow \Theta=\dfrac{180(13)}{5\pi}[/tex]

[tex]\\ \tt{:}\dashrightarrow \Theta=149^{\circ}[/tex]

[tex]\\ \tt{:}\dashrightarrow \Theta=149(60)[/tex]

[tex]\\ \tt{:}\dashrightarrow \Theta=8940'[/tex]

The angle subtended at the center of a circle of radius 5 cm by a length of 13 cm is 149.1°.

Given that,

The angle is subtended at the center of a circle of radius 5 cm by a length of 13 cm.

Here, Lenght of an arc = 13 cm

The radius of an arc = 5 cm

Used the formula for the angles (θ);

Length of an arc = 2πrθ / 360°

Substitute all the values, we get;

13 = 2 × 3.14 × 5 × θ / 360°

Solve for θ;

13 × 360° = 31.4 × θ

4,680° = 31.4 × θ

θ = 4,680°/31.4

θ = 149.1°

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When two coins are flipped simultaneously 24 times, on average 12 times we will get a head and a tail.

For given question,

When two coins are tossed simultaneously, the sample space is as follows:

S = { HH, HT, TH, TT} where H denotes Head and T denotes tail.

Using the formula of probability,

P = Number of favorable outcomes/total number of outcomes,

we get,

P(HT) = 1/4

and

P(TH) = 1/4

We know that the occurrence of two mutually exclusive events is the sum of their individual probabilities.

So, P(Head on one and Tail on other)

= P(HT) + P(TH)

= 1/4 + 1/4

= 2/4

= 1/2

= 0.5

So, when two coins flipped simultaneously, the probability of flipping 2 coins and getting a head and a tail is 0.5

In this question, we need to find the number of times getting a head and a tail when two coins are flipped simultaneously 24 times

= 0.5 × 24

= 12

Therefore, When two coins are flipped simultaneously 24 times, on average 12 times we will get a head and a tail.

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The roots of the resulting polynomial equation are [tex](x_{1} ,y_{1} ) = (-2 , -26), (x_{2} ,y_{2} ) = ( 0.11 , 1.94 )[/tex] and [tex]( x_{3} , y_{3} ) = ( 4.39, - -9.81)[/tex] , respectively.

What is a polynomial easy definition?

A mathematical expression of one or more algebraic terms each of which consists of a constant multiplied by one or more variables raised to a nonnegative integral power (such as a + bx + cx2).

Ariana must graph two polynomic expressions:

[tex]f(x) = x^{3} -5 . x^{2} + 2[/tex] and [tex]g(x) = -x^{3} + 17 . x[/tex]

The roots of the resulting polynomial equation are found by means of this formula-

f(x) - g(x) = 0.........................1

Then, we must look for every point so that  f(x) = g(x)

The roots of the resulting polynomial equation are [tex](x_{1} , y_{1} ) = ( -2,-26) , (x_{2} ,y_{2} ) = ( 0.114 , 1.937 )[/tex] and [tex](x_{3},y_{3} ) = ( 4. 386 , -9. 812)[/tex]  respectively.

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Answer:

D

Step-by-step explanation:

Answer:

Step-by-step explanation:

y=-1/2x+6

The quantity of the radioactive material which would remain 2 years from now is; 4 grams.

Since, it follows from the task content that after two year, the quantity of the radioactive substance decrease by 1 gram. Consequently, it follows from proportion that the quantity remaining in 2 years from now is; 5-1 = 4 grams.

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the function is increasing from x = 0 to x = 1

when x = 0, y = 2

when x = 1, y = 8

this shows an increase of +6, so we know this statement is true

we can see the rest are false simply because they state a decrease when there is an increase. this question is only confusing because we ask you about the increase and decrease in the function, when really its the same thing as asking about an increase or decrease in the y variable.

in other words, all youre looking for is the variation of the value of the y variable that is attached to the specific x variables.

hope this helps!!

The number of days christen’s book is overdue is 22.

The number of days christen’s book is overdue:

According to the graph, the fine levied stops rising after 20 overdue days and then stays at 10 for the remaining days.

Additionally, if Christen's fine was the same as yesterday, her late dates must be longer than 21 days (because the fine on day 20 will be the same).

22 might therefore be the number of days past due based on the options provided.

The number of days christen’s book is overdue is 22.

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Answer:

f(x) = -x²

Step-by-step explanation:

Writing f(x) = -x² in vertex form gives f(x)=-(x-0)^2+0 which shows that the vertex (h,k) is at (0,0)

The other equations written in vertex form do not have (h,k) = (0,0)

Answer:

6cm,20cm,80cm,1m,1m,1.15m,132cm

Step-by-step explanation:

Hence,1 m=100 cm

Answer: 4

Step-by-step explanation:

2.03 / 7 = 0.29

1.16 / 0.29 = 4

Mason will get 4 oranges on spending 1.16$

What is Rate of change?

A rate is anything that can be measured over time. Common rates include velocity (which is the rate of distance traveled), power (rate of work being done), etc. All these have one thing in common which is that they are all divided by the amount of time it took to obtain a certain measurement.

Here it is given that a grocery store sells a bag of 7 oranges for $2.03,

Now firstly let calculate for 1$ how many oranges Mason get by dividing 7 with 2.03$ :

For 1$ we get = 7/2.03 = 3.5 oranges

Therefore to calculate for 1.16 $ amount spend by Mason will be multiplication of 3.5 with 1.16$ : 3.5 x 1.16 = 4 oranges

Therefore, Mason will get 4 oranges on spending 1.16$

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The inclination to the nearest tenth of a degree exists 0.24146

The given scenario includes a right-angled triangle where the length of the ramp exists hypotenuse and the rise of ramp exists the perpendicular.

Given: H = 4.6 m and P = 1.1 m

We have to use the trigonometric ratios to find the angle. The ratio that has to be used should involve both perpendicular and hypotenuse

Let x be the angle then

sin x = P/H

sin x = 1.1/4.6

sin x = 0.23913

[tex]$$sin^{-1} x[/tex] = 0.24146

The inclination to the nearest tenth of a degree exists 0.24146

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The linear equation can represent the ages of two sisters that are born one-year apart.

Here we have the linear equation:

y = x + 1

So the value of y is always one more than the value of x, so for example, suppose that two sisters are born one-year appart, then we can use the above linear equation to represent the age of the older sister as a function of the age of of the younger one.

In that case, the slope of 1 means that both of the sisters age at the same ritm.

The y-intercept of 1 means that the older sister is 1 years old when the younger sister was born.

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It takes 1 hour 43 minutes to finish mowing the lawn.

The rate of work done by Gregory and Jennifer finish mowing the lawn in

1 hour 43 minutes.

According to the question

Gregory can mow the family's lawn in 3 hours, she mows at a rate of 1/3 of the lawn per hour(1/3 lawn/hour)

Jennifer can mow it in 4 hours, which means her rate is 1/4 lawn/hour.

Together , their rates are 1/3 + 1/4.

This equals 7/12 lawns/hr.

We want to know how many hours they have to mow in order to mow 1 lawn.

This can be represented by the equation : [tex]\frac{7}{12} \times x = 1[/tex]

To solve for x, we would divide both sides by 7/12.

This leaves us with x = 12/7 which is 1.714.

Convert 1.714 to minutes by multiplying 60.

This gives you a final answer of about 1 hour 43 minutes.

Hence, It takes 1 hour 43 minutes to finish mowing the lawn.

The rate of work done by Gregory and Jennifer finish mowing the lawn in

1 hour 43 minutes.

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The probability of pulling a black or red card  = 3/10

Probability that a white card will be drawn, P(white) = 1/25

Probability that a blue card will be dealt, P(black)  = 1/5

Probability that a black card will be dealt, P(red) = 1/10

Probability that a pink card will be revealed, P(pink)  = 1/15

All of these occurrences are distinct from one another and do not relate to one another.

The likelihood that any one of any two events, A and B, with probability P(A) and P(B), will occur is:

                                        P( A ∪ B ) = P(A) + P(B)

Here, event A can be compared to getting a black card, and

incident B is comparable to receiving a red card.

So, P(black or red) = P(black) + P (red)

= (1/5) + (1/10)

= ( 2 + 1 )/10

= 3/10

So, the likelihood that a black or red card will be pulled from the hat:

= 3/10

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Answer:

[tex]Question 1\\1+i\\-1-i\\Question 2\\\\-1+i\\1-i[/tex]

Step-by-step explanation:

Complex Numbers:

   Complex numbers can generally be expressed in the form: [tex]a+bi[/tex] where a and b are both real numbers, with the a part representing the real part of the complex number, and the bi representing the imaginary part.

   We can also graph these numbers using the complex plane. The complex plane has the real axis where the x-axis would normally be, and the imaginary axis where the y-axis would normally be. So by this definition the "a" is what determines the horizontal position or the position on the real axis and the "b" is what determines the vertical position or the position on the imaginary axis.

I attached a diagram of the complex plane, and it's essentially the same as a normal graph, with a=x, and b=y.

Question 1:

So when a complex number lies above the real-axis, that means the imaginary part is greater than 0. When a complex numbers lies to the right of the imaginary axis, that means the real part is greater than 0.

This means we have the form: [tex]a+bi \text { where } a > 0 \text{ and } b > 0[/tex]. You can literally plug in any number for a and b, so long as it fits this. For example we can just do: [tex]1+i[/tex]

So when a complex number lies below the real-axis, that means the imaginary part is less than 0. when a complex numbers lies to the left of the imaginary axis, the real part is less than 0.

This means we have the form: [tex]a+bi \text { where } a < 0\text{ and }b < 0[/tex]. You can plug in any real number that lies within this restriction. An example would be:

[tex]-1-i[/tex]

Question 2:

Above real axis and to the left of the imaginary axis means: b>0 and a<0. So we can plug in any number into the standard form that fits this restriction. an example would be: [tex]-1+i[/tex]

Below real axis and to the right of the imaginary axis means: b<0 and a>0. So we can plug in any number into the standard form that fits this restriction. An example would be: [tex]1-i[/tex]

Answer:

C

Step-by-step explanation:

y > 2x² - 6x - 36 is the inequality in standard form represents the region greater than the quadratic function with zeros –3 and 6 and includes the point (–2, –16) on the boundary line. This can be obtained by finding zeroes of each inequality to check whether the zeroes are –3 and 6 and then substituting (–2, –16) in the inequality.

To find the zeroes of the inequality we use the formula,

x = (-b ± √b² - 4ac)/ 2a, where a, b and c are the coefficients of x², x and constant respectively.

Find the zeroes,

x = (3/2 ± √9/4 + 18)

x = 3/2 ± 9/2

⇒ x = 12/2 = 6, x = -6/2 = - 3

Putting x = –2 in the inequality we get,

1/2 x² - 3/2x - 9 = 1/2 (-2)² - 3/2(-2) - 9

                         = 2 + 3 - 9 = - 4 ≠ -16

Therefore option 1 is incorrect

Find the zeroes,  

x = (-6 ± √36 + 288) / 4

x = (-6 ± 18) / 4

⇒ x = 12/4 = 3, x = -24/4 = - 6

Therefore option 2 is incorrect

Find the zeroes,  

x = (6 ± √36 + 288) / 4

x = (6 ± 18) / 4

⇒ x = 24/4 = 6, x = -12/4 = - 3

Also , Putting x = –2 in the inequality we get,

2 x² - 6x - 36 = 2 (-2)² - 6(-2) - 36

                     = 8 + 12 -36

                     = - 16

The inequality includes the point (–2, –16) on the boundary line.

Hence y > 2x² - 6x - 36 is the inequality in standard form represents the region greater than the quadratic function with zeros –3 and 6 and includes the point (–2, –16) on the boundary line.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Which inequality in standard form represents the region greater than the quadratic function with zeros –3 and 6 and includes the point   (–2, –16) on the boundary line?

a) y > 1/2 x² - 3/2x - 9

b) y > 2 x² - 6x - 36

c) y > 2 x² - 6x - 36

d) y > 1/2 x² + 3/2x - 9

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