sketch the region enclosed by the given curves. y = cos(x), y = sin(2x), 0 ≤ x ≤ 2

Segment AB - Leg

Segment BC - Leg

Segment AC - Hypotenuse

Answer:

-7[tex]x^{3}[/tex] + 9[tex]x^{2}[/tex] -4x

Step-by-step explanation:

-4[tex]x^{3}[/tex] + 8[tex]x^{2}[/tex] - 4x - 3[tex]x^{3}[/tex] + [tex]x^{2}[/tex]

-7[tex]x^{3}[/tex] + 9[tex]x^{2}[/tex] -4x

S10 = 4000.  To determine the entries of the next row in Pascal's Triangle, we add adjacent terms from the current row.

Thus, the next row will be:

1 7 21 35 35 21 7 1

5a) The sequence has first term t1 = 9, and a common difference of d = 6. Then, the general term is given by tn = 6n + 3. Thus, t7 = 6(7) + 3 = 45.

5b) The sequence has first term t1 = 8192, and a common ratio of r = -2. Then, the general term is given by tn = 8192(-2)^(n-1). Thus, t11 = 8192(-2)^(10) = -8388608.

The series is an arithmetic series with first term a=800, common difference d=−600/3=−200, and number of terms n = 10. Thus, using the formula for the sum of an arithmetic series, we have:

S10 = (n/2)(a + tn) = (10/2)(800 + (800 + (n-1)d)) = 4000

Therefore, S10 = 4000.

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The sum of the series ∑(j=0 to n) (-1/2)^j is equal to (2^(n+1) + (-1)^n)/(3 * 2^n) for any non-negative integer n.

To prove the given equation, we'll use mathematical induction.

Base case (n = 0):

For n = 0, the series becomes (-1/2)^0 = 1. Plugging this into the right side of the equation, we have (2^(0+1) + (-1)^0)/(3 * 2^0) = (2 + 1)/(3 * 1) = 3/3 = 1. Thus, the equation holds true for the base case.

Inductive hypothesis:

Assume that the equation holds true for some positive integer k, i.e., ∑(j=0 to k) (-1/2)^j = (2^(k+1) + (-1)^k)/(3 * 2^k).

Inductive step:

We need to prove that the equation also holds true for k + 1, i.e., ∑(j=0 to k+1) (-1/2)^j = (2^(k+2) + (-1)^(k+1))/(3 * 2^(k+1)).

Expanding the left side of the equation:

∑(j=0 to k+1) (-1/2)^j = ∑(j=0 to k) (-1/2)^j + (-1/2)^(k+1).

Using the inductive hypothesis, we substitute the sum of the first k terms:

∑(j=0 to k+1) (-1/2)^j = (2^(k+1) + (-1)^k)/(3 * 2^k) + (-1/2)^(k+1).

Simplifying the right side of the equation:

= (2^(k+1) + (-1)^k)/(3 * 2^k) + (-1/2) * (1/2)^(k+1).

Combining the terms:

= (2^(k+1) + (-1)^k)/(3 * 2^k) - (1/2)^(k+2).

Finding a common denominator and combining the fractions:

= (2^(k+1) + (-1)^k - 2(1/2)^(k+2))/(3 * 2^k).

Expanding the terms:

= (2^(k+1) + (-1)^k - 2/2^(k+2))/(3 * 2^k).

Simplifying further:

= (2^(k+1) + (-1)^k - 1/2^(k+1))/(3 * 2^k).

Using algebraic manipulation:

= (2^(k+1) + 2*(-1)^k - 1)/(3 * 2^k).

Rearranging the terms:

= (2 * 2^(k+1) + (-1)^(k+1))/(3 * 2^(k+1)).

Simplifying:

= (2^(k+2) + (-1)^(k+1))/(3 * 2^(k+1)).

This expression matches the right side of the equation for k + 1, which completes the inductive step.

By the principle of mathematical induction, the equation holds true for all non-negative integers n.

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the area integral over the bottom disk:

∬S F · ds = ∬S F · n ds

To find the area integral of the vector field F over the surface S, we can use the formula:

∬S F · ds

where F is the vector field and ds is the vector differential surface on the S surface.

In this case we have three surfaces: cylinder S, top disk and bottom disk. Let's calculate the surface integrals separately for each surface:

Cylinder S:

The equation of the cylinder is x^2 + y^2 = 4 and extends along the z-axis. To parametrize the surface, we can use cylindrical coordinates:

r(θ, z) = (2cos(θ), 2sin(θ), z), where 0 ≤ θ ≤ 2π and 0 ≤ z ≤ 3.

The unit normal vector to the surface S is given by:

n(θ, z) = (2cos(θ), 2sin(θ), 0)

Now we can calculate the area integral over the cylinder S:

∬S F · ds = ∬S F · n ds

Upper disc:

The equation of the disk is x^2 + y^2 < 4, z = 3. We can use polar coordinates to parametrize the surface:

r(ρ, θ) = (ρcos(θ), ρsin(θ), 3), where 0 ≤ ρ ≤ 2 and 0 ≤ θ ≤ 2π.

The unit normal vector to the surface is given by:

n(ρ, θ) = (0, 0, 1)

Now we can calculate the surface integral over the upper disk:

∬S F · ds = ∬S F · n ds

Bottom disc:

The equation of the disk is x^2 + y^2 < 4, z = 1. We can use polar coordinates to parametrize the surface:

r(ρ, θ) = (ρcos(θ), ρsin(θ), 1), where 0 ≤ ρ ≤ 2 and 0 ≤ θ ≤ 2π.

The unit normal vector to the surface is given by:

n(ρ, θ) = (0, 0, -1)

Now we can calculate the area integral over the bottom disk:

∬S F · ds = ∬S F · n ds

Please enter the vector field F to continue calculations.

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Answer:

So, the surface area of the sphere is 100π cm².

Step-by-step explanation:

To calculate the surface area of a sphere with a radius of 5 cm, you can use the formula:

Surface area = 4πr²

Where r is the radius of the sphere. In this case, r = 5 cm. Plugging in the value for r, we get:

Surface area = 4π(5 cm)²

Now, we can simply square the radius (5 cm) and multiply the result by 4π:

Surface area = 4π(25 cm²)

Surface area = 100π cm²

Therefore , the surface area of the sphere is 100π cm².

The type I error that corresponds to the given hypothesis is option C:

A type I error occurs when we reject the null hypothesis when it is actually true. In this case, the null hypothesis states that the percentage of households with Internet access is less than 60%. The type I error would be to reject this null hypothesis (incorrectly) when the actual percentage is indeed less than 60%.

Option C corresponds to this type I error because it states that we reject the null hypothesis that the percentage is less than 60% when it is actually true. This means that we mistakenly conclude that the percentage is not less than 60% when it actually is.

On the other hand, option A is the correct decision since it correctly states that we fail to reject the null hypothesis when it is true. Options B and D do not correspond to a type I error as they refer to the null hypothesis being equal to 60% rather than less than 60%.

Therefore, the correct answer is option C: Reject the null hypothesis that the percentage of households with Internet access is less than 60% when that percentage is actually less than 60%.

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The trapezoid's height given the area of 245 is 14 units

Trapezoid is two-dimensional quadrilateral that have two parallel sides and two non-parallel sides. It is also called Trapezium. It is polygon that has only one pair of parallel sides.

How to determine this

Area of Trapezoid = [tex]\frac{a+b}{2} h[/tex]

Where a = 14

b = 21

Height, h = ?

Area of Trapezoid = 245

To find the height,

245 = [tex]\frac{14+21}{2}[/tex]* h

245 = 35/2 * h

245 = 17.5 * h

divides through by 17.5

245/17.5 = 17.5*h/17.5

14 = h

Height = 14 units

Therefore, the height of the trapezoid is 14 units

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A perfect square trinomial factors to a binomial squared, option a.

A perfect square trinomial is a trinomial expression that can be factored into the square of a binomial. It has the form:

(ax² + bx + c)²

To factor it, you can take the square root of the first term (ax²) and the square root of the last term (c). The middle term (bx) will be twice the product of these square roots. Therefore, the factored form of the perfect square trinomial is:

(ax² + bx + c)² = (√(ax^2) + √(c))² = (√(ax^2) + √(c))(√(ax^2) + √(c))

This can be simplified to:

(ax² + bx + c)² = (√(ax²) + √(c))² = (√(a)x + √(c))²

So, a perfect square trinomial factors into the square of a binomial, where the first term of the binomial is the square root of the coefficient of the squared term, and the second term is the square root of the constant term.

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The given mathematical system M=({0,a,b,c},#, &) can be verified whether it is a Boolean algebra by checking if it satisfies the four axioms of Boolean algebra: commutativity, associativity, distributivity, and complementation.

1. Commutativity: a # b = b # a, a & b = b & a 2. Associativity: (a # b) # c = a # (b # c), (a & b) & c = a & (b & c) 3. Distributivity: a # (b & c) = (a # b) & (a # c), a & (b # c) = (a & b) # (a & c) 4. Complementation: there exists a complement of each element x such that x # x' = 0 and x & x' = 1 Using these axioms, it can be seen that the given mathematical system M satisfies all four axioms, and therefore, it is a Boolean algebra. The complements of elements 0, a, b, and c can be found as follows: - Complement of 0 is 1 - Complement of a is a' - Complement of b is b' - Complement of c is c'

The given mathematical system M is a Boolean algebra, and the complements of its elements 0, a, b, and c are 1, a', b', and c', respectively.

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a)  the vectors in b are linearly independent and span R^2, we can conclude that b is a basis for R^2.

(a) To prove that the set of vectors b = {(3, 4), (1, 2)} is a basis for R^2, we need to show two things: linear independence and spanning.

Linear independence: We need to show that the vectors in b are linearly independent, which means that there is no non-trivial linear combination of the vectors that equals the zero vector.

Let's assume that we have scalars a and b such that a(3, 4) + b(1, 2) = (0, 0). This leads to the following system of equations:

3a + b = 0

4a + 2b = 0

Solving this system, we find that a = 0 and b = 0. Since the only solution to the system is the trivial solution, the vectors (3, 4) and (1, 2) are linearly independent.

Spanning: We need to show that any vector in R^2 can be expressed as a linear combination of the vectors in b. In other words, we need to show that for any vector (x, y) in R^2, there exist scalars a and b such that a(3, 4) + b(1, 2) = (x, y).

Solving this system of equations, we find a = (2x - y)/5 and b = (3y - x)/5. This shows that any vector (x, y) in R^2 can be expressed as a linear combination of (3, 4) and (1, 2).

(b) To perform the Gram-Schmidt orthonormalization process on the set of vectors b = {(3, 4), (1, 2)}, we can follow these steps:

Step 1: Normalize the first vector:

u1 = (3, 4) / ||(3, 4)|| = (3, 4) / 5 = (0.6, 0.8)

Step 2: Subtract the projection of the second vector onto the first vector:

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The measure of the m[tex]\widehat{ST}[/tex], obtained from the measure of the inscribed angle ∠SVT is; [tex]m\widehat{ST}[/tex] = 90°

An arc is a curved part of the circumference of a circle. The angle of an arc is the angle subtended by the two radii inscribed by the arc at the center of the circle.

The arc indicated is the [tex]\widehat{ST}[/tex], therefore, the measure of the [tex]\widehat{ST}[/tex] can be found as follows;

The angle formed at the circumference of the [tex]\widehat{ST}[/tex] = 45°

The angle formed at the center = 2 × The measure of the inscribed angle formed at the circumference

Therefore;

The measure of the [tex]\widehat{ST}[/tex] = 2 × The measure of the inscribed angle ∠SVT

The measure of the [tex]\widehat{ST}[/tex] = 2 × 45° = 90°

The measure of the [tex]\widehat{ST}[/tex] = 90°

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The tip of the minute hand on a clock travels a distance of 15π inches in 45 minutes.

The distance traveled by the tip of a minute hand on a clock can be calculated using the circumference formula.

The circumference of a circle is given by the formula:

C = 2πr C is the circumference, π is pi (approximately 3.14159) and r is the radius.

The distance from the center of the clock to the tip of the minute hand is the radius is 10 inches.

The circumference of the circle traced by the tip of the minute hand is:

C = 2πr

= 2π(10)

= 20π inches

Since the minute hand travels the full circumference of the circle in 60 minutes, in 45 minutes it will cover 45/60 = 3/4 of the circumference.

The distance traveled by the tip of the minute hand in 45 minutes is:

Distance = (3/4) × C

= (3/4) × (20π)

= 15π inches

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The correct formula for computing equivalent units for the period under the weighted average approach is option A) which is "Equivalent units = (Units transferred + Ending inventory units) × Percentage complete".

This formula takes into account both the units that were completed and transferred out of the production process during the period, as well as the units that were partially completed and remained in the ending inventory at the end of the period.

By multiplying the total number of units (completed and partially completed) by the percentage of completion for the partially completed units, we can calculate the equivalent units for the period.

This formula is commonly used in manufacturing and production processes to measure the output of a particular period.

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Since 2/9 equals 0.2 repeating, 12/54 equals the same.

Answer: 12

it takes approximately 27.1 minutes for the water to cool to 80°F.

To determine the value of the constant a in Newton's law of cooling, we can use the formula:

ΔT/Δt = -a(T - T_r)

where:

ΔT/Δt is the rate of change of temperature,

T is the temperature of the object (whirlpool bath water),

T_r is the ambient temperature (room temperature), and

a is the constant of proportionality.

Given that the temperature cools from 102°F to 86°F in 10 minutes, we can substitute these values into the formula to solve for a:

(86 - 102) / 10 = -a(102 - 69)

-16 / 10 = -33a

-8/5 = -33a

a = (8/5) / 33

a ≈ 0.0242

Therefore, the value of the constant a in Newton's law of cooling is approximately 0.0242.

To find the value of the constant k, we can use the relationship between a and k:

k = a / m

where m is the mass of the object. Since the mass of the whirlpool bath water is not provided, we cannot determine the value of k without additional information.

To find the water temperature after 20 minutes, we can use Newton's law of cooling:ΔT/Δt = -a(T - T_r)

(ΔT/Δt) * Δt = -a(T - T_r) * Δt

(T - T_r) = (T_0 - T_r) * exp(-aΔt)

where T_0 is the initial temperature (102°F), T_r is the room temperature (69°F), and Δt is the time interval (20 minutes).

Plugging in the given values:

(T - 69) = (102 - 69) * exp(-0.0242 * 20)

Simplifying and solving for T:

T ≈ 80.82°F

Therefore, the water temperature after 20 minutes is approximately 80.82°F.

To determine how long it takes the water to cool to 80°F, we can rearrange the equation:

(T - T_r) = (T_0 - T_r) * exp(-aΔt)

80 - 69 = (102 - 69) * exp(-0.0242 * Δt)

11 = 33 * exp(-0.0242 * Δt)

Taking the natural logarithm of both sides:

ln(11/33) = -0.0242 * Δt

Solving for Δt:

Δt ≈ -ln(11/33) / 0.0242

Δt ≈ 27.1 minutes

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To solve the exponential equation e^(2x-6) = 58^x - 10, we can take the natural logarithm (ln) of both sides to remove the exponential terms:

ln(e^(2x-6)) = ln(58^x - 10)

Using the property ln(e^a) = a, we have:

2x - 6 = ln(58^x - 10)

Now, let's solve for x algebraically.

2x - 6 = ln(58^x - 10)

Adding 6 to both sides:

2x = ln(58^x - 10) + 6

Dividing both sides by 2:

x = (ln(58^x - 10) + 6) / 2

This is the exact expression for the solution. To obtain a decimal approximation, you can substitute the expression into a calculator or computer software.

Using a calculator or computer software, the decimal approximation for x is approximately x ≈ 2.50 (rounded to two decimal places).

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Answer:

it's 70°

Step-by-step explanation:

the opposite sides are equal, so it's 70°

To find the total differential of the function w = e^y * cos(x) * z^2, we can take the partial derivatives with respect to each variable (x, y, and z) and multiply them by the corresponding differentials (dx, dy, and dz).

The total differential can be expressed as:

dw = (∂w/∂x) dx + (∂w/∂y) dy + (∂w/∂z) dz

Let's calculate the partial derivatives:

∂w/∂x =   [tex]-e^{y} * sin(x) * z^{2}[/tex]

∂w/∂y =  [tex]e^{y} * cos(x) * z^{2}[/tex]

∂w/∂z =  [tex]2e^{y} *cos (x)* z[/tex]

Now, let's substitute these partial derivatives into the total differential expression:

[tex]dw = (-e^{y} * sin(x) * z^{2} ) dx + (e^{y}* cos(x) * z^{2} ) dy + 2e^{y} *cos (x)*z) dz[/tex]

Therefore, the total differential of the function w = e^y * cos(x) * z^2 is given by:

[tex]dw = (-e^{y} * sin(x) * z^{2} ) dx + (e^{y} * cos(x) * z^{2} ) dy + ( 2e^{y} * cos(x) * z) dz[/tex]

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Answer:

S=(-2,5) T=(-3,4) U=(-4,0)

The equation of the straight line passing through Q and the midpoint of the line segment PR is 12x + 13y = 71.

To solve this question, we use the principles of 2-D coordinate geometry, which is the plane consisting of all points (x,y).

The midpoint  C between two points A(x₁,y₁) and B(x₂,y₂) is defined as

C(x,y) = [(x₁+x₂)/2 , (y₁+y₂)/2]

Thus, the midpoint of the points P(2,4) and R(-1,6), labelled as M, will be

M = [(2-1)/2 , (4+6)/2]

M = [ (1/2) , 5]

Now, the equation of the line segment between two points A and B is defined as

(y-y₁)/(x-x₁) = (y₂-y₁)/(x₂-x₁)

*This is called the two-point form of a line.

Using the two points M and R through which we need the required line segment to pass, we apply the above formula to arrive at the answer.

Thus by simplifying,

(y - 5)/(x-0.5) = (-1 - 5)/(7-0.5)

(y - 5)/(x-0.5) = (-6/6.5) = [-12/13]

(y - 5) = (-12/13)(x-0.5)

(y - 5) = -12x/13 + 6/13

13y - 65 = -12x + 6

13y + 12x = 71

Hence, we can say that the equation of the line passing through the midpoint of P and R, and through Q is 12x + 13y = 71

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The general solution to the given boundary value problem is y(t) = c₁e^(4t) + c₂e^(8t)

To solve the given boundary value problem, we can use the method of solving linear second-order homogeneous differential equations. The equation can be rewritten as:

d²y/dt² - 12% dt + 32y = 0

First, we can find the characteristic equation by assuming the solution has the form y = e^(rt), where r is a constant:

r² - 12% r + 32 = 0

Next, we solve this quadratic equation for r. We can factor it or use the quadratic formula:

(r - 4)(r - 8) = 0

This gives us two distinct roots: r₁ = 4 and r₂ = 8.

Therefore, the general solution of the homogeneous differential equation is:

y(t) = c₁e^(4t) + c₂e^(8t)

To find the particular solution that satisfies the given boundary conditions, we substitute the boundary values into the general solution:

y(0) = c₁e^(4*0) + c₂e^(8*0) = c₁ + c₂ = 2   ... (1)

y(1) = c₁e^(4*1) + c₂e^(8*1) = c₁e^4 + c₂e^8 = 8   ... (2)

From equation (1), we can express c₁ in terms of c₂:

c₁ = 2 - c₂

Substituting this into equation (2), we have:

(2 - c₂)e^4 + c₂e^8 = 8

Simplifying the equation, we can solve for c₂:

2e^4 - c₂e^4 + c₂e^8 = 8

2e^4 + c₂(e^8 - e^4) = 8

c₂(e^8 - e^4) = 8 - 2e^4

c₂ = (8 - 2e^4) / (e^8 - e^4)

Once we have the value of c₂, we can substitute it back into c₁ = 2 - c₂ to find c₁.

Finally, we can substitute the values of c₁ and c₂ into the general solution:

y(t) = c₁e^(4t) + c₂e^(8t)

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sensitivity analysis is concerned with how certain changes affect group of is d. the optimal solution.

Sensitivity analysis is a technique used to analyze how changes in the input parameters or constraints of a mathematical optimization model affect the optimal solution. It helps in understanding the stability and reliability of the optimal solution in response to variations in the problem's parameters or constraints. Sensitivity analysis provides valuable insights into the robustness and flexibility of the optimal solution under different scenarios.

what is mathematical?

Mathematics is a field of study that deals with the properties, relationships, and structures of numbers, quantities, shapes, and patterns. It involves the use of logical reasoning and abstract concepts to explore and understand various mathematical principles and phenomena. Mathematics provides a language and framework for expressing and analyzing patterns and relationships in the physical, natural, and social sciences, as well as in everyday life. It encompasses various branches such as algebra, geometry, calculus, statistics, and more, and plays a fundamental role in scientific research, problem-solving, and technological advancements.

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Use dot products to express y as a linear combination of the vectors in S.

To represent y as a linear combination of the vectors in S using dot products, we calculate the dot product of y with each vector in S and divide it by the squared length of the corresponding vector. The coefficients obtained from the dot products form the linear combination. The steps for each exercise are as follows:

Let S = {7, 20} and y = {-1, 0, 9}.

Dot product with the first vector: (-1)⋅7 = -7

Dot product with the second vector: 0⋅20 = 0

y = (-7/149)⋅7 + (0/400)⋅20 = (-7/149)⋅7

Let S = {3, 1, 2, 0, 9} and y = {5, 5, -1}.

Dot product with the first vector: 5⋅3 = 15

Dot product with the second vector: 5⋅1 = 5

Dot product with the third vector: -1⋅2 = -2

Dot product with the fourth vector: 0⋅0 = 0

Dot product with the fifth vector: 9⋅9 = 81

y = (15/19)⋅3 + (5/26)⋅1 + (-2/14)⋅2 + (0/5)⋅0 + (81/186)⋅9

Let S = {-1, 0} and y = {1, 0}.

Dot product with the first vector: 1⋅(-1) = -1

Dot product with the second vector: 0⋅0 = 0

y = (-1/1)⋅(-1) + (0/1)⋅0 = -1

Let S = {5, 5, -1, -1} and y = {2, 1}.

Dot product with the first vector: 2⋅5 = 10

Dot product with the second vector: 1⋅5 = 5

Dot product with the third vector: 2⋅(-1) = -2

Dot product with the fourth vector: 1⋅(-1) = -1

y = (10/50)⋅5 + (5/50)⋅5 + (-2/2)⋅(-1) + (-1/2)⋅(-1)

Let S = {A, B} and v = {p}.

Dot product with the first vector: p⋅A

Dot product with the second vector: p⋅B

y = (dot product with A)⋅A + (dot product with B)⋅B

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Answer:

Step-by-step explanation:

You want to match the given values of f(y) to the y that gives them.

The attached calculator display shows the function values for -2, -4, 0, 2, 4. Comparing those to the listed values of f(y), we see the correspondence shown above.

The function is evaluated by putting the y-value where y is in the function expression and doing the arithmetic. A calculator or spreadsheet can perform this repetitive math for you, so you only have to enter the y-values once.

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Answer:

Approx 54,432.53 cubic feet

Step-by-step explanation:

Volume = (1/3) * π * (13 feet)^2 * 18 feet

≈ 54432.5286 cubic feet

Therefore, the volume of the cone is approximately 54,432.53 cubic feet.

The degrees of freedom for the t-statistic in this scenario would be (16 - 1) = 15. So, the correct answer is A. 15.

What is normal population?

In statistics, a normal population refers to a theoretical population that follows a normal distribution. The normal distribution, also known as the Gaussian distribution or bell curve, is a symmetric probability distribution characterized by a bell-shaped curve.

A normal distribution is defined by its mean (μ) and standard deviation (σ). The curve is symmetric around the mean, and the area under the curve represents the probability of observing a particular value or range of values.

To determine the degrees of freedom for the t-statistic, we need to consider the sample size. In this case, the sample size is given as 16 observations from a Normal population.

To clarify, the degrees of freedom for a t-statistic in a one-sample t-test is equal to the sample size minus 1. In this case, the sample size is 16 observations.

The degrees of freedom for a t-distribution in this case is calculated as (n - 1), where n is the sample size. Therefore, the degrees of freedom for the t-statistic in this scenario would be (16 - 1) = 15. So, the correct answer is A. 15.

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The solution of the expression is,

⇒ S = - 5100

Since, An sequence has the ratio of every two successive terms is a constant, is called a Geometric sequence.

We have to given that;

Sequence is,

⇒ ∑ n = 1 to n = 4 [ 100 (- 4)ⁿ⁻¹ ]

Now, We get;

⇒ a (n) = [ 100 (- 4)ⁿ⁻¹ ]

Replace n to n + 1;

⇒ a (n + 1) = 100 (- 4)ⁿ

And, For n = 1;

⇒ a (n) = [ 100 (- 4)ⁿ⁻¹ ]

⇒ a (1) = [ 100 (- 4)¹⁻¹ ]

⇒ a (1) =  100

And, Common ratio = - 4

Hence, The sum of geometric ratio is,

⇒ S = 100 (1 - (- 4)⁴) / (1 + 4)

⇒ S = 100 (1 - 256) / 5

⇒ S = - 5100

Thus, The solution of the expression is,

⇒ S = - 5100

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Answer:

292 1/8

Step-by-step explanation:

The volume of the rectangular prism is just length*width*height.

If we just turn all mixed numbers into improper fractions and multiply them together...

3*41/2*19/4=2337/8=292 1/8

Therefore, the second option is the correct one

Feel free to tell me if I did anything wrong! :)

If the width of the rectangular prism is doubled, then the volume is twice as large, the correct option is C.

We are given that;

The rectangular prism measures 3ft*4ft*2ft

Now,

A rectangular prism is a three-dimensional shape that has two at the top and bottom and four are lateral faces.

The volume of a rectangular prism= Length X Width X Height

When the width = 2W

before the width is doubled we have our volume as;

V =  LWH

Also when the width = 2W

V =  LWH

V =  L(2W)H

V =  2LWH

Therefore, the volume will become twice as large as before.

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