Solutions generated from PCA vs. Factor analysis

Answers

Answer 1

PCA (Principal Component Analysis) and Factor Analysis are both statistical techniques used to reduce the dimensionality of large datasets. However, they have different goals and methods.


PCA is an unsupervised technique used to identify the most important variables in a dataset by transforming the original variables into a new set of uncorrelated variables called principal components. These components are linear combinations of the original variables and are ranked in order of the variance they explain. The primary goal of PCA is to simplify the dataset by reducing its dimensionality while preserving the maximum amount of variance.

Factor Analysis, on the other hand, is a technique that aims to identify underlying factors or latent variables that explain the correlations among the observed variables. It is often used in social sciences and psychology to identify constructs or concepts that cannot be directly measured. Factor Analysis helps in understanding the structure of the data and the relationships between the observed variables.

In summary, PCA focuses on explaining the maximum amount of variance in the dataset by creating a new set of uncorrelated variables, whereas Factor Analysis seeks to identify latent factors underlying the correlations among the observed variables. Both techniques can be useful in simplifying large datasets, but their goals and methods differ, which leads to distinct solutions depending on the specific objectives of the analysis.

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Related Questions

5. Longest Palindromic Substring
Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000.
Example:
Input: "babad"
Output: "bab"
Note: "aba" is also a valid answer.
Example:
Input: "cbbd"
Output: "bb"

Answers

def longest_palindromic_substring(s):
   def is_palindrome(sub):
       return sub == sub[::-1]
   
   n = len(s)
   if n == 0:
       return ""
   
   ans = s[0]
   

To solve this problem, we can use the following approach:

1. Create a function to check whether a given substring is a palindrome or not. We can do this by comparing the first and last characters of the substring and then moving towards the center until we have checked all the characters.

2. Start with a substring of length one and check if it is a palindrome. If it is, we update our answer to be this substring.

3. Then we expand our substring by adding one character to the left and one to the right. We check if this new substring is a palindrome, and if it is, we update our answer to be this substring.

4. We keep expanding our substring until we reach the end of the string. At each step, we check if the substring is a palindrome and update our answer accordingly.

5. Finally, we return the longest palindrome substring we found.

Here's the Python code for this approach:

```
def longest_palindromic_substring(s):
   def is_palindrome(sub):
       return sub == sub[::-1]
   
   n = len(s)
   if n == 0:
       return ""
   
   ans = s[0]
   
   for i in range(n):
       for j in range(i+1, n+1):
           sub = s[i:j]
           if is_palindrome(sub) and len(sub) > len(ans):
               ans = sub
               
   return ans
```

This solution has a time complexity of O(n^3) because we are checking all possible substrings of the input string. However, we can optimize this solution by using dynamic programming or Manacher's algorithm to reduce the time complexity to O(n^2) or O(n), respectively.

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A simple random sample of 100 8th graders at a large suburban middle school indicated that 87% of them are involved with some type of after school activity. Find the 95% confidence interval that estimates the proportion of them that are involved in an after school activity.

Answers

The 95% confidence interval that estimates the proportion of them that are involved in an after school activity lies between 80.53% and 93.47% .

To find the 95% confidence interval for the proportion of 8th graders involved in after-school activities. The key terms involved in this question are simple random sample, confidence interval, proportion, and after-school activity.

In this case, a simple random sample of 100 8th graders is taken, which ensures an unbiased representation of the population. From this sample, it's found that 87% (or 0.87) of the students are involved in an after-school activity.

To calculate the 95% confidence interval, we need to use the formula:

CI = p ± Z * √(p(1-p) / n)

where CI is the confidence interval, p is the sample proportion (0.87), Z is the Z-score for a 95% confidence interval (1.96), and n is the sample size (100).

Plugging in the values, we get:

CI = 0.87 ± 1.96 * √(0.87(1-0.87) / 100)

CI = 0.87 ± 1.96 * √(0.1131 / 100)

CI = 0.87 ± 1.96 * 0.033

CI = 0.87 ± 0.06468

Thus, the 95% confidence interval is approximately (0.80532, 0.93468).

In conclusion, based on the sample, we can estimate with 95% confidence that the true proportion of 8th graders at the suburban middle school who are involved in after-school activities lies between 80.53% and 93.47%. This means that we can be 95% certain that the actual proportion falls within this range.

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22. A quadratic function is graphed on the grid.
Write the domain and range of the function.

Answers

The domain of the function is the set of all real values and the range of the function is y >= 5

Writing the domain and range of the function.

From the question, we have the following parameters that can be used in our computation:

The graph of the quadratic function

As a general rule

The domain of a quadratic function is the set of all real values

For the range, we have

The graph has a minimum value at y = 5

Also, the values of the function output (y values) increases

This means that the range is y >= 5

Hence the domain is the set of all real values and the range is y >= 5

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Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.) P(â1.12 ⤠z ⤠2.73) =

Answers

The probability that z lies between -1.12 and 2.73 in a standard normal distribution is approximately 0.8653.

Let z be a random variable with a standard normal distribution. You need to find the probability P(-1.12 ≤ z ≤ 2.73).
To find this probability, follow these steps:
1. Identify the given values: z1 = -1.12 and z2 = 2.73.
2. For a standard normal distribution, you need to use the standard normal table (z-table) or a calculator with a built-in standard normal distribution function to find the probabilities associated with z1 and z2.
3. Look up the probabilities for z1 and z2 in the z-table or use a calculator:
  P(z ≤ -1.12) = 0.1314 and P(z ≤ 2.73) = 0.9967.


4. Calculate the probability of the given range by subtracting the smaller probability from the larger one:
  P(-1.12 ≤ z ≤ 2.73) = P(z ≤ 2.73) - P(z ≤ -1.12) = 0.9967 - 0.1314 = 0.8653.
5. Round your answer to four decimal places:
  P(-1.12 ≤ z ≤ 2.73) = 0.8653.
So, the probability that z lies between -1.12 and 2.73  is approximately 0.8653.

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What is the area of the composite shape?

Answers

There is pair of parallel sides, so area of the figure is 24 square units

The figure has 1 pair of parallel sides and is therefore a trapezium.

The area (A) of a trapezium is calculated as

Area = 1/2(Base 1 + Base 2)height

=1/2(4+4)6

=1/2(8)6

=48/2

=24 square units

Hence, the area of the given figure is 24 square units

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If today is Monday, what day of the week will it be 1,000 days from today?

Answers

1,000 days from today will be a Sunday.

To determine the day of the week 1,000 days from today, we need to divide 1,000 by 7 to determine how many weeks have elapsed, and then find the remainder to determine which day of the week it will be. Since there are 7 days in a week, every 7 days the day of the week repeats.

1,000 ÷ 7 = 142 with a remainder of 6.

This means that 1,000 days from today will be 142 full weeks plus 6 days later. Since today is Monday, we can count 6 days ahead to determine the day of the week 1,000 days from today:

Monday + 1 day = Tuesday

Tuesday + 1 day = Wednesday

Wednesday + 1 day = Thursday

Thursday + 1 day = Friday

Friday + 1 day = Saturday

Saturday + 1 day = Sunday

Therefore, 1,000 days from today will be a Sunday.

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Carmen sells beaded necklaces for $5. 60. Each large necklace sells for and each small necklace sells for $4. 6. How much will she earn from selling 1 large necklace and 6 small necklaces?

Answers

Carmen will earn $33.20 from selling 1 large necklace and 6 small necklaces.

Let's start by calculating how much Carmen earns from selling one large necklace:

1 large necklace sells for $5.60, so Carmen earns $5.60 for each large necklace sold.

Now let's calculate how much Carmen earns from selling six small necklaces:

1 small necklace sells for $4.60, so Carmen earns $4.60 for each small necklace sold.

Therefore, for 6 small necklaces, Carmen earns:

6 x $4.60 = $27.60

Now we can calculate the total amount that Carmen earns from selling 1 large necklace and 6 small necklaces by adding the amounts earned from each type of necklace:

$5.60 (1 large necklace) + $27.60 (6 small necklaces) = $33.20

Therefore, Carmen will earn $33.20 from selling 1 large necklace and 6 small necklaces.

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Noshima Industries issued dividends totaling $0.60 last year. For the next two years, it expects dividends to increase by 50% annually and then remain constant thereafter. How much is one share of Noshima Industries stock worth today if you require a 9% rate of return? a. $13.45
b. $13.77 c. $14.59 d. $15.00
e. $15.14

Answers

One share of Noshima Industries stock is worth $8.27 today if you require a 9% rate of return.

To calculate the present value of the future dividend payments, we can use the formula for the present value of a growing perpetuity:

PV = C / (r - g)

where PV is the present value, C is the annual cash flow (dividend), r is the required rate of return, and g is the annual growth rate of the cash flow.

In this case, the annual cash flow starts at $0.60 and then grows by 50% for two years, so we can calculate the cash flows for the next three years as follows:

Year 1: $0.60

Year 2: $0.60 × 1.5 = $0.90

Year 3: $0.90 × 1.5 = $1.35

After the third year, the dividend payments are expected to remain constant, so we can calculate the present value of perpetuity using the constant dividend payment of $1.35 per year.

Using a required rate of return of 9%, the annual growth rate for the first two years of 50%, and the constant growth rate of 0% after that, we can calculate the present value of the future cash flows as follows:

PV = 0.60/(0.09 - 0.50) + (0.90/(1+0.09)²)/(0.09 - 0.50) + (1.35/(1+0.09)³)/(0.09 - 0.00)

PV = $8.27174733765

PV = $8.27

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Yall can you solve out 400 - 12.98 please?

Answers

Answer:

387.02

Step-by-step explanation:

Answer: 387.02

it’s subtraction right

Explain how two samples can have the same mean but different standard deviations. Draw a bar graph that shows the two samples, their means, and standard deviations as error bars. PLEASE draw out the graph with the information written.

Answers

Two samples can have the same mean but different standard deviations if one sample has more variability than the other. For example, one sample may have data points that are tightly clustered around the mean, while the other sample may have data points that are more spread out.

This can result in the same mean value for both samples, but different levels of variability.

Here's an example bar graph to illustrate this concept:

     Sample 1                Sample 2

 ╭────────────────╮   ╭────────────────╮

 │      Mean      │   │      Mean      │

 ├────────────────┤   ├────────────────┤

 │                │   │    ╭─╮         │

 │                │   │    │ │         │

 │                │   │    │ │         │

 │                │   │    ╰─╯         │

 │     o o o      │   │  o o o o o o  │

 │                │   │                │

 │                │   │                │

 │                │   │                │

 ╰────────────────╯   ╰────────────────╯

     Std. Dev.            Std. Dev.

In this example, both Sample 1 and Sample 2 have a mean value of 5. However, Sample 1 has lower variability with a standard deviation of 1, while Sample 2 has higher variability with a standard deviation of 3. The error bars on the graph represent the standard deviation for each sample.

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I am a quadrilateral with two pairs of opposite sides always parallel. Who am I?
(square, rhombus, rectangle, parallelogram, kite, isosceles trapezoid, trapezoid)

Answers

A quadrilateral with two pairs of opposite sides always parallel is a  parallelogram. A parallelogram is a quadrilateral with two pairs of opposite sides that are always parallel.

It is a special type of quadrilateral because its properties allow it to be manipulated in unique ways. For example, if one angle of a parallelogram is a right angle, it becomes a rectangle. If all four sides are congruent, it becomes a rhombus. If both pairs of opposite sides are congruent, it becomes a square.

If only one pair of opposite sides is congruent, it becomes a kite. And if it has two parallel sides that are not congruent, it becomes an isosceles trapezoid. A trapezoid also has two pairs of opposite sides, but they are not always parallel. Therefore, it cannot be the answer to this question. Overall, the parallelogram is a versatile shape with unique properties that make it an important concept in geometry.

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The board of directors of national soft-drink manufacturer has been alarmed by the amount of criticism it has been receiving in the press regarding the content of its lime cola bottle. To investigate the situation it collected a very large random sample of bottle that should contain 750 ml. The actual amount in the bottle follows a normal distribution with a mean of 751. 5 ml and the standard deviation of 5. 0 ml. Find the proportion of Lime Cola battles that have contents in each of the following ranges:

3. 2. 1 less than 755 mL

3. 2. 2 between 740 mL ad 764 mL

3. 2. 3 more than 760 mL

3. 2. 3 not between 746 mL and 754

Answers

a. the proportion of Lime Cola bottles that have contents less than 755 mL is 0.7580. b. the proportion of Lime Cola bottles that have contents between 740 mL and 764 mL is 0.9936. c. the proportion of Lime Cola bottles that have contents more than 760 mL is 0.0446.

To solve this problem, we need to use the standard normal distribution with a mean of 0 and a standard deviation of 1. We can convert the given values to the standard normal distribution using the formula:

z = (x - μ) / σ

where z is the standard score, x is the given value, μ is the mean, and σ is the standard deviation.

(a) We need to find the proportion of Lime Cola bottles that have contents less than 755 mL. We can calculate the z-score as:

z = (755 - 751.5) / 5 = 0.7

Using the standard normal distribution table or calculator, we can find that the proportion of values less than 0.7 is approximately 0.7580. Therefore, the proportion of Lime Cola bottles that have contents less than 755 mL is 0.7580.

(b) We need to find the proportion of Lime Cola bottles that have contents between 740 mL and 764 mL. We can calculate the z-scores as:

z1 = (740 - 751.5) / 5 = -2.3

z2 = (764 - 751.5) / 5 = 2.5

Using the standard normal distribution table or calculator, we can find the proportion of values between -2.3 and 2.5 is approximately 0.9936. Therefore, the proportion of Lime Cola bottles that have contents between 740 mL and 764 mL is 0.9936.

(c) We need to find the proportion of Lime Cola bottles that have contents more than 760 mL. We can calculate the z-score as:

z = (760 - 751.5) / 5 = 1.7

Using the standard normal distribution table or calculator, we can find the proportion of values more than 1.7 is approximately 0.0446. Therefore, the proportion of Lime Cola bottles that have contents more than 760 mL is 0.0446.

(d) We need to find the proportion of Lime Cola bottles that have contents not between 746 mL and 754 mL. We can calculate the z-scores as:

z1 = (746 - 751.5) / 5 = -1.1

z2 = (754 - 751.5) / 5 = 0.5

Using the standard normal distribution table or calculator, we can find the proportion of values less than -1.1 and more than 0.5 is approximately 0.4088. Therefore, the proportion of Lime Cola bottles that have contents not between 746 mL and 754 mL is 0.4088.

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Shelby is in a hot air balloon where the balloon is shaped like a sphere with a diameter of 50 feet. Find the amount of space occupied by the balloon. Use 3.14 for pi and round your answer to the nearest tenth.
( Please Help Me)

Answers

The amount of space occupied by the balloon is approximately 65,449 cubic feet.

The amount of space occupied by the balloon can be found using the formula for the volume of a sphere:

V = (4/3)πr³

where r is the radius of the sphere. We can find the radius by dividing the diameter (50 feet) by 2:

r = 50/2 = 25 feet

Substituting this value into the formula and using 3.14 for π, we have:

V = (4/3)π(25)³

Simplifying:

V ≈ 65,449 cubic feet

Therefore, the amount of space occupied by the balloon is approximately 65,449 cubic feet.

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What would be decay rate k if half life of 3106 years

Answers

The decay rate k for a substance with a half-life of 3106 years is approximately 0.000223 per year.

The formula for radioactive decay is:

N(t) = N0 * e^(-kt)

where N(t) is the amount of the radioactive substance at time t, N0 is the initial amount of the substance, k is the decay rate, and e is the mathematical constant approximately equal to 2.718.

The half-life of a radioactive substance is the time it takes for half of the initial amount to decay. So if the half-life of a substance is 3106 years, then after 3106 years, the amount of the substance remaining will be half of the initial amount, or N0/2.

Using the formula above, we can set N(t) equal to N0/2 and t equal to the half-life:

N0/2 = N0 * e^(-k * 3106)

Dividing both sides by N0 and taking the natural logarithm of both sides, we get:

ln(1/2) = -k * 3106

Solving for k, we get:

k = ln(2)/3106

Using a calculator, we get:

k ≈ 0.000223

Therefore, the decay rate k for a substance with a half-life of 3106 years is approximately 0.000223 per year.

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c) Find the average rate of change over the interval [1,4].
12
2.8 3.1 4
y|8 8 14 17 21 25
x
X
5.3
29

Answers

Answer:4.333.

Step-by-step explanation:

To find the average rate of change over the interval [1,4], we can use the formula:

Average rate of change = (change in y)/(change in x)

In this case, the values of x and y are given in the table as follows:

x: 1 2 3 4

y: 8 14 17 21

So, the change in x over the interval [1,4] is 4 - 1 = 3, and the change in y is 21 - 8 = 13.

Plugging these values into the formula, we get:

Average rate of change = (13)/(3) = 4.333...

So, the average rate of change over the interval [1,4] is approximately 4.333.

(30 − 12) x 2
Question 1
Which is a way to show this expression in words?
Responses
A First, subtract 12 from 30, then multiply by 2.First, subtract 12 from 30, then multiply by 2.
B Find the sum of 30 and 12 before multiplying by 2.Find the sum of 30 and 12 before multiplying by 2.
C Find the difference of 30 and 12, then divide by 2.Find the difference of 30 and 12, then divide by 2.
D First, find the product of 30 and 12, then multiply by 2.First, find the product of 30 and 12, then multiply by 2.
Question 2
What is another way to show this expression in words?
Responses
A Double the difference between 30 and 12.Double the difference between 30 and 12.
B Subtract 30 from 12 before multiplying by 2.Subtract 30 from 12 before multiplying by 2.
C First subtract 12 from 30, then triple the result.First subtract 12 from 30, then triple the result.
D Find the sum of 12 and 30 before multiplying by 2.Find the sum of 12 and 30 before multiplying by 2.
Skip to navigation

Answers

First, subtract 12 from 30, then multiply by 2. Therefore, option A is the correct answer.

The given expression is (30-12)×2.

Here, determine the difference between 30 and 12, that is 30-12=18

Multiply the difference by 2, that is

18×2=36

Therefore, option A is the correct answer.

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A wire of length 10 m is divided into two pieces and each piece is bent into a square. How should this be done in order to minimize the sum of the areas of the two squares

Answers

Answer:

A(x) = (x/4)^2 + ((10 - x)/4)^2

A'(x) = 2(x/4)(1/4) + 2((10 - x)/4)(-1/4)

x/8 + (x - 10)/8 = 0

x + x - 10 = 0

2x = 10, so x = 5

Cut the 10-meter wire into two 5-meter pieces. The area of each square is (5/4)^2 = 25/16 = 1.5625 square meters, so the combined area for both squares is 25/8, or 3.125 square meters (1.5625 square meters per square).

7 x B is less than 14, but greater than 7

Answers

If 7 times B is less than 14 but greater than 7, then we can represent this inequality as:

7 < 7B < 14

To solve for B, we can divide all parts of the inequality by 7:

1 < B < 2

Therefore, B must be greater than 1 but less than 2.

Answer:

7 < 7B < 14

Step-by-step explanation:

The equation 7 x B represents a product of two factors, where B is one of the factors. The equation states that the value of this product is between 7 and 14, exclusive. Therefore, B must be a fractional value between 1 and 2. Specifically, B could be any value between 1 and (2/7), exclusive, since any value greater than (2/7) would result in a product greater than 14, and any value less than 1 would result in a product less than 7, This will be represented as 7 < 7B < 14

1.18 A student walks 1.0 mi west and then 1.0 mile north, after ward how far is she from her starting point?
A 1.0 mi
B 1.4 mi
C 1.6 mi
D 2.0 Mi

Answers

The distance between the student's starting point and ending point is approximately 1.4 mi. The correct option is B.

We can use the Pythagorean theorem to find the distance between the student's starting point and ending point, which is the length of the straight line between the two points (i.e., the distance between the two points).

If we draw a diagram, we can see that the student's displacement forms the hypotenuse of a right triangle with legs of length 1.0 mi (the distance traveled due west) and 1.0 mi (the distance traveled due north).

So, we can use the Pythagorean theorem to find the length of the hypotenuse:

distance = √[(1.0 mi)² + (1.0 mi)²] ≈ 1.4 mi

Thus, the distance between the student's starting point and ending point is approximately 1.4 mi.

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Find hf if ge= 43 yd.

Answers

Step-by-step explanation:

Area of this kit = 1/2 (gf * hf)    

   258 yd^2  = 1/2 (43 * HF )

      HF =   258 *2 / 43 = 12 yds

Solve the following proportion for the variable x

Answers

Answer:

Step-by-step explanation:

A proportion is a fancy way of saying that two fractions are the same. To find out what the missing number is, we can do some magic called cross-multiplication, which means we multiply the numbers that are diagonal from each other and make them equal. For example, if we have a proportion like a/b = c/d, we can cross-multiply and get ad = bc. Then we can find the missing number by moving things around until it's by itself. Let's try this trick on this problem:

7/x+2 = 4/x+1

Cross-multiply:

7(x+1) = 4(x+2)

Spread out:

7x + 7 = 4x + 8

Take away 4x from both sides:

3x + 7 = 8

Take away 7 from both sides:

3x = 1

Cut both sides by 3:

x = 1/3

So, the answer is x = 1/3.

If a tangent and a diameter meet at the point of tangency, then they are perpendicular to one another.


What theorem is this? I am writing a proof and came across a theorem close to this in my notebook, but not one that would satisfy.


Will mark brainlilest if someone gives a good answer and explanation. This question is 50 points

Answers

The theorem described of the point of tangency would be the "Perpendicular Tangent Theorem.

What is the Perpendicular Tangent Theorem?

If a tangent and diameter intersect at the point of tangency, then according to the Perpendicular Tangent-Diameter Theorem, they create a perpendicular. To prove this theorem, it is important to consider that every tangent line touches the circle's radius at a 90-degree angle at the point of intersection.

Thus, when a diameter passes through the center of the circle, it becomes a special type of radius - one which intersects with two points on the circumference instead of just one. At each point where it intercepts the circumference, we see a right-angle between the tangent line and the diameter, as required by the Perpendicular Tangent-Diameter Theorem.

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In a correlated groups experiment, if we must estimate the population standard deviation to determine the significance of the sample results, the appropriate statistical test is _________.

Answers

The appropriate statistical test for a correlated groups experiment where the population standard deviation needs to be estimated to determine the significance of the sample results is the paired t-test.

The appropriate test is the paired t-test for a correlated groups experiment where the population standard deviation needs to be estimated to determine the significance of the sample results. The paired t-test is used when the data is dependent, meaning that there is a natural pairing or correlation between the two groups being compared. In this type of experiment, the same group of subjects is measured twice, or two groups of subjects are matched based on some characteristic.The paired t-test requires the assumption of normality of the differences between the paired observations and the use of the t-distribution to estimate the population mean difference. However, when the population standard deviation is unknown, it needs to be estimated from the sample using the sample standard deviation. The resulting test statistic follows a t-distribution with n-1 degrees of freedom, where n is the number of pairs of observations.The paired t-test is a powerful test that can detect differences between groups even when the individual observations are highly variable, as it focuses on the differences between pairs, rather than the absolute values of the observations.

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The price of a sweater was reduced from $70 to $35. the sweater is __% off.

Answers

The sweater is 50% off.

In mathematics, a percentage is a number or ratio that can be expressed as a fraction of 100. If we have to calculate percent of a number, divide the number by the whole and multiply by 100.

To calculate the percentage off the sweater is, we can use the following formula:

Percentage Off = (Original Price - Sale Price) / Original Price * 100

In this case, the original price of the sweater is $70 and the sale price is $35.

Percentage Off = (70 - 35) / 70 * 100 = 50%

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Without doing any​ computation, decide which has a higher​ probability, assuming each sample is from a population that is normally distributed with 100 and 15. Explain your reasoning. ​(a)​ P(90​110) for a random sample of size n10 ​(b)​ P(90​110) for a random sample of size n20

Answers

We can conclude that both probabilities in parts (a) and (b) are approximately 0.95, regardless of the sample size.

Assuming that the population is normally distributed with a mean of 100 and a standard deviation of 15, we can use the central limit theorem to approximate the sampling distribution of the sample means as normal, regardless of the sample size.

Since we're interested in the probability that the sample mean falls within a certain range, we can standardize the sampling distribution of the sample means using the formula:

z = ([tex]\bar X[/tex] - μ) / (σ / √n)

where [tex]\bar X[/tex] is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size.

For both parts (a) and (b), we want to find P(90 < [tex]\bar X[/tex] < 110), which we can rewrite as P((90 - 100) / (15 / √n) < ([tex]\bar X[/tex] - 100) / (15 / √n) < (110 - 100) / (15 / √n)).

Simplifying this expression, we get P(-2√n < z < 2√n), where z is a standard normal random variable.

The probability that a standard normal random variable falls within ±2 standard deviations of the mean is approximately 0.95. Therefore, we can conclude that both probabilities in parts (a) and (b) are approximately 0.95, regardless of the sample size.

This is because the sample size n only affects the standard deviation of the sampling distribution of the sample means (i.e., σ / √n), but not its shape or center. Therefore, the probability that the sample mean falls within a certain range is largely determined by the width of that range relative to the standard deviation of the sampling distribution, which is approximately constant regardless of the sample size.

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Jane buys 12 flats of flowers. Flats of geraniums cost $2. 00, and flats of roses cost $1. 25. The total cost, c, in terms of the number of flats of geraniums, g, is given by c=2. 00g+1. 25(12-g). Determine the rate at which his cost is changing with respect to g

Answers

The rate at which the cost is changing with respect to g is 0.75 dollars per flat of geraniums. This means that for each additional flat of geraniums, Jane buys, her total cost increases by $0.75.

Given information:

Jane buys 12 flats of flowers.

Flats of geraniums cost $2. 00, and flats of roses cost $1. 25. The total cost, c, in terms of the number of flats of geraniums, g, is given by c=2. 00g+1. 25(12-g).

We can start by taking the derivative of the cost function, c, with respect to the number of flats of geraniums, g:

dc/dg = 2.00 - 1.25

Simplifying this expression gives:

dc/dg = 0.75

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What is a z-statistic?
The standardized statistic; a measurement of how many standard deviations from the mean the observed statistic is on the null distribution

Answers

The z-statistic is a valuable tool in statistical analysis to evaluate the significance of a sample statistic in relation to its null distribution.

The z-statistic definition

A z-statistic, also known as a standardized statistic, is a measurement used in hypothesis testing to determine how many standard deviations an observed statistic is from the mean of the null distribution.

This value helps in understanding how likely an observed result is under the null hypothesis.

By comparing the z-statistic to a critical value, one can determine if the observed statistic is significantly different from the null hypothesis expectation.

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HELP PLEASE NO ESSAY PLESE JUST ANSWER FIRST ANSWER THATS CORRECT GRT BRAINLIEST

Answers

Answer:

  224 in²

Step-by-step explanation:

You want the surface area of a square base prism 12 inches long with a base that is 4 inches on a side.

Area

The area of the prism is given by ...

  A = 2(LW +H(L+W))

Filling in the given information, this is ...

  A = 2(4·4 +12(4 +4)) = 224 . . . . square inches

The surface area is 224 in².

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David has two bags of Skittles. The first bag contains 8 red Skittles, 6 blue Skittles, and 6 green Skittles. The second bag contains 5 red Skittles, 4 blue Skittles, and 6 green Skittles. David will randomly select 1 Skittle from each bag. What is the probability that David will select a blue Skittle from each bag?

Answers

The probability that David will select a blue Skittle from each bag is 17/30

Given that, David has 8 red Skittles, 6 blue Skittles, and 6 green Skittles in one bag and second bag contains 5 red Skittles, 4 blue Skittles, and 6 green Skittles.

He randomly selected 1 Skittle from each bag, we need to find the probability that David will select a blue Skittle from each bag,

So, the total number of skittles in one bag = 20

P(getting blue from one bag) = 6/20

The total number of skittles in 2nd bag = 15

P(getting blue from 2nd bag) = 4/15

P(selecting a blue Skittle from each bag) = 6/20 + 4/15 = 17/30

Hence, the probability that David will select a blue Skittle from each bag is 17/30

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2. I lost my knife
3. This pencil is too short.
4. The cake was stale.
5. The bird flew away.
6. The sea beat against the rocks.
7. The dog barked at the postman.
8. Summer is the warmest season.
9. The plane landed safely.
10. Only one apple was left in the bush.
Nouns

Answers

According to the information, the nouns of the sentences are: knife, pencil, cake, bird, sea, rocks, dog, postman, summer, season, plane, apple, and bush.

How to identify the nouns of sentences?

To identify the nouns of the sentences we must read each one of them and identify the elements (objects, people, places, among others) that refer to who is performing an action. According to the above, the nouns would be:

2. I lost my knife = knife3. This pencil is too short = pencil4. The cake was stale = cake5. The bird flew away = bird6. The sea beat against the rocks = sea, rocks.7. The dog barked at the postman = dog, pstman.8. Summer is the warmest season = summer, season.9. The plane landed safely = plane.10. Only one apple was left in the bush = apple, bush.

Note: This question is incomplete. Here is the complete information:

Find the nouns in these sentences.

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