Solve ⅔ + ⅚ and put answer in simplest form. O A.% O B. 1½ O c.⅔ O D.™

A recent survey conducted on a sample of 425 individuals revealed that 102 of them had visited the cinema within the past month.

This data suggests that approximately 24% of the surveyed population had engaged in movie going activities during the specified period.

The findings highlight a significant proportion of the respondents who have recently enjoyed the cinematic experience.

However, it is important to note that this data is based on a limited sample size and may not be representative of the entire population.

Further research and surveys involving a larger and more diverse sample are recommended to obtain a more accurate understanding of movie attendance trends.

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Answer:

C.  5x(-x + 2)

Step-by-step explanation:

To factor the expression -5x² + 10x, we need to look for a common factor that can be factored out.

Finding a common factor involves identifying a term or expression that can be factored out from each term of a given expression.

Both terms have the common factor of 5x, so we can factor out 5x:

5x(-x + 2)

Therefore, the factored form of -5x² + 10x is -5x(x - 2).

[tex]\hrulefill[/tex]

Additional notes:

If we expand the expressions in the given answer options, we get:

  A.  −5x(x + 2) = -5x² - 10x

  B.  5(−x² + 10x) = -5x² + 50x

  C.  5x(−x + 2) = -5x² + 10x

  D.  x(5x + 10) = 5x² + 10x

Hence confirming that the correct answer is option C.

To factor [tex]-5x^2+10x[/tex], we can begin by factoring out the greatest common factor, which is [tex]-5x[/tex]:

We can check our answer by distributing [tex]-5x[/tex] to the expression inside the parentheses:

[tex]\therefore[/tex] The answer is [tex]-5x(x-2)[/tex].

[tex]\blue{\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}[/tex]

Therefore, Heather can make a maximum of 4 biscuits with the given ingredient quantities.

To determine how many biscuits Heather can make, we need to compare the amount of each ingredient required for a single biscuit to the total amount of ingredients she has.

Let's calculate the number of biscuits she can make based on the ingredient quantities provided:

First, we need to find the ratio of each ingredient required per biscuit:

Flour: 100g per biscuit

Butter: 120g per biscuit

Icing sugar: 80g per biscuit

Chocolate: 25g per biscuit

Next, we divide the total amount of each ingredient by the respective ratio to find the maximum number of biscuits she can make:

Flour: 2kg / 100g = 20 biscuits

Butter: 1kg / 120g = 8.33 biscuits (approximately)

Icing sugar: 340g / 80g = 4.25 biscuits (approximately)

Chocolate: 200g / 25g = 8 biscuits

Since we can only make a whole number of biscuits, the limiting factor is the icing sugar. Heather can only make 4 biscuits since she has 4.25 times the required amount of icing sugar.

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The expression that is equivalent to StartRoot [tex]8 x^7 y^8[/tex] EndRoot is ([tex]2 x^3 y^4[/tex] StartRoot 2 x EndRoot)^2.

To understand why this is the case, let's break down each expression and simplify them step by step:

StartRoot [tex]8 x^7 y^8[/tex] EndRoot:

We can rewrite 8 as [tex]2^3[/tex], and since the square root can be split over multiplication, we have StartRoot [tex](2^3) x^7 y^8[/tex] EndRoot. Applying the exponent rule for square roots, we get StartRoot [tex]2^3[/tex] EndRoot StartRoot [tex]x^7[/tex] EndRoot StartRoot [tex]y^8[/tex] EndRoot.

Simplifying further, we have 2 StartRoot [tex]2 x^3 y^4[/tex] EndRoot StartRoot [tex]2^2[/tex] EndRoot StartRoot [tex]x^2[/tex] EndRoot StartRoot [tex]y^4[/tex] EndRoot. Finally, we obtain 2 [tex]x^3 y^4[/tex] StartRoot 2 x EndRoot, which is the expression in question.

([tex]2 x y^2[/tex] StartRoot 8 x^3 EndRoot)^2:

Expanding the expression inside the parentheses, we have [tex]2 x y^2[/tex]StartRoot [tex](2^3) x^3[/tex] EndRoot. Applying the exponent rule for square roots, we get [tex]2 x y^2[/tex] StartRoot [tex]2^3[/tex] EndRoot StartRoot [tex]x^3[/tex] EndRoot.

Simplifying further, we have [tex]2 x y^2[/tex] StartRoot 2 x EndRoot. Squaring the entire expression, we obtain ([tex]2 x y^2[/tex] StartRoot 2 x EndRoot)^2.

Therefore, the expression ([tex]2 x^3 y^4[/tex] StartRoot 2 x EndRoot)^2 is equivalent to StartRoot [tex]8 x^7 y^8[/tex] EndRoot.

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The value of the equation that defines the function is f(x) = 3(5/3)ˣ

From the question, we have the following parameters that can be used in our computation:

(0, 3) and (1, 5)

An exponential function is represented s

y = abˣ

Where,

a = y when x = 0

So, we have

y = 3bˣ

Using the other point, we have

3b = 5

This gives

b = 5/3

So, we have

f(x) = 3(5/3)ˣ

Hence, the equation defining f is f(x) = 3(5/3)ˣ

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Answer:

To the nearest tenth, we have,

z = 19.9

Step-by-step explanation:

The missing side is the hypotenuse,

And we are given the side adjacent to the angle,

z = hupotenuse = H = ?

Adjacent = A = 15

Angle = α = 41

Since we have to find hypotenuse and we are given adjacent,

Using SOHCAHTOA,

We know the angle and adjcent but need to find Hypotenuse,

So, we use CAH

or,

cos(α) = A/H

cos(α) = 15/z

(since z = hypotenuse)

zcos(α) = A

z = A/(cos(α))

z = 15/cos(41)

z = 19.8752

To the nearest tenth, we get,

z = 19.9

Answer:

The probability that on a particular week, the hospital will receive on high BP pregnant woman is 0.0068

Step-by-step explanation:

We use the Exponential distribution,

Since we are given that on average, 5 pregnant women with high blood pressure come per week,

So, average = m = 5

Now, on average, 5 people come every week, so,

5 women per week,

so, we get 1 woman per (1/5)th week,

Hence, the mean is m = 1/5 for a woman arriving

and λ = 1/m = 5 = λ

we have to find the probability that it takes higher than a week for a high BP pregnant woman to arrive, i.e,

P(X>1) i.e. the probability that it takes more than a week for a high BP pregnant woman to show up,

Now,

P(X>1) = 1 - P(X<1),

Now, the probability density function is,

[tex]f(x) = \lambda e^{-\lambda x}[/tex]

And the cumulative distribution function (CDF) is,

[tex]CDF = 1 - e^{-\lambda x}[/tex]

Now, CDF gives the probability of an event occuring within a given time,

so, for 1 week, we have x = 1, and λ = 5, which gives,

P(X<1) = CDF,

so,

[tex]P(X < 1)=CDF = 1 - e^{-\lambda x}\\P(X < 1)=1-e^{-5(1)}\\P(X < 1)=1-e^{-5}\\P(X < 1) = 1 - 6.738*10^{-3}\\P(X < 1) = 0.9932\\And,\\P(X > 1) = 1 - 0.9932\\P(X > 1) = 6.8*10^{-3}\\P(X > 1) = 0.0068[/tex]

So, the probability that on a particular week, the hospital will receive on high BP pregnant woman is 0.0068

The factored form of 3x^2 - 5x - 18x + 30 is (3x - 5)(x - 6).

To factor the expression3x^2 - 5x - 18x + 30, we can group the terms and then factor out common factors.

Step 1: Group the terms.

3x^2 - 5x - 18x + 30,

Step 2: Factor out the common factors from each group.

x(3x - 5) - 6(3x - 5)

Step 3: Notice that we now have a common binomial factor of (3x - 5).

(3x - 5)(x - 6)

Therefore, the factored form of the expression 3x^2 - 5x - 18x + 30 is (3x - 5)(x - 6).

In this factored form, (3x - 5) and (x - 6) are the factors of the expression. To check if the factoring is correct, you can multiply the factors back together to see if you get the original expression:

(3x - 5)(x - 6) = 3x(x) - 3x(6) - 5(x) + 5(6)

=3x^2 - 18x - 5x + 30

= 3x^2 - 23x + 30  

The result matches the original expression, so the factoring is correct.

Therefore, the factored form of 3x^2 - 5x - 18x + 30 is (3x - 5)(x - 6).

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keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the second line

[tex](\stackrel{x_1}{4}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{4}) ~\hfill~ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{5}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{4}}} \implies \cfrac{ -1 }{ 2 } \implies - \cfrac{1}{2}[/tex]

so we're really looking for the equation of a line whose slope is -1/2 and it passes through (2 , -2)

[tex](\stackrel{x_1}{2}~,~\stackrel{y_1}{-2})\hspace{10em} \stackrel{slope}{m} ~=~ - \cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-2)}=\stackrel{m}{- \cfrac{1}{2}}(x-\stackrel{x_1}{2}) \implies y +2 = - \cfrac{1}{2} ( x -2) \\\\\\ y+2=- \cfrac{1}{2}x+1\implies {\Large \begin{array}{llll} y=- \cfrac{1}{2}x-1 \end{array}}[/tex]

Answer:

Line passing through (4, 5) and (6, 4):

[tex]m = \frac{4 - 5}{6 - 4} = - \frac{1}{2} [/tex]

Line passing through (2, -2) and with slope -1/2:

-2 = (-1/2)(2) + b

-2 = -1 + b, so b = -1

y = (-1/2)x - 1

-2y = x + 2

-x - 2y = 2

x + 2y = -2

The measure of angle Q is given as follows:

m < Q = 70º.

Two angles are defined as supplementary angles when the sum of their measures is of 180º.

In a parallelogram, we have that consecutive interior angles are supplementary, hence the value of x is obtained as follows:

6x + 4 + 10x = 180

16x = 176

x = 176/16

x = 11.

Then the measure of angle Q is given as follows:

m < Q = 6 x 11 + 4

m < Q = 70º.

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Answer:

[tex]x = \dfrac{9}{2}=4.5[/tex]

Perimeter = 52

Step-by-step explanation:

A tangent is a straight line that touches a circle at only one point.

The given diagram shows a circle with three points of tangency: S, T and U.

According to the Two-Tangent Theorem, if two tangents to a circle meet at one exterior point, the tangent segments are congruent.

The exterior points are P, Q and R. Therefore, the congruent segments are:

[tex]\overline{PS} = \overline{PT} = 9[/tex]

[tex]\overline{QT} = \overline{QU} = 4[/tex]

[tex]\overline{RS} = \overline{RU} = 13[/tex]

To find the value of x, use the equation PS = PT:

[tex]\overline{PS} = \overline{PT}[/tex]

 [tex]2x = 9[/tex]

  [tex]x = \dfrac{9}{2}=4.5[/tex]

To calculate the perimeter of triangle PQR, sum the tangent segments.

[tex]\begin{aligned}\textsf{Perimeter}&=\overline{PS}+\overline{PT}+\overline{QT}+\overline{QU}+\overline{RS}+\overline{RU}\\&=9+9+4+4+13+13\\&=52\end{aligned}[/tex]

Therefore, the perimeter of triangle PQR is 52 units.

The calculated values of x and y in the figure are x = 2 and y = 4

from the question, we have the following parameters that can be used in our computation:

The figure

Where, we have

equal side lengths

This means that

2y - 1 = 3y - 5

Evaluate

y = 4

Next, we have

x + 3 = 3/2x + 2

So, we have

1/2x = 1

This gives

x = 2

Hence, the values of x and y in the figure are x = 2 and y = 4

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Rounded to the nearest tenth of a percent, the probability is approximately 27.8%.

To determine if the event of rolling a pair of dice and getting doubles or a sum of 6 is mutually exclusive, we need to assess whether the two outcomes can occur simultaneously or if they are mutually exclusive.

Let's analyze the two outcomes separately:

1. Getting doubles: When rolling a pair of dice, getting doubles means that the numbers on both dice are the same. The possible outcomes for getting doubles are (1,1), (2,2), (3,3), (4,4), (5,5), and (6,6). There are a total of 6 outcomes that satisfy this condition.

2. Getting a sum of 6: To get a sum of 6, the numbers on the two dice should add up to 6. The possible outcomes for this condition are (1,5), (2,4), (3,3), (4,2), and (5,1). There are a total of 5 outcomes that satisfy this condition.

Now, to determine if the two outcomes are mutually exclusive, we need to check if there are any outcomes that satisfy both conditions. In this case, the outcome (3,3) satisfies both conditions (doubles and sum of 6).

Since there is one outcome that satisfies both conditions, we can conclude that the event of rolling a pair of dice and getting doubles or a sum of 6 is not mutually exclusive.

To find the probability of this event, we need to determine the total number of possible outcomes when rolling a pair of dice. Each die has 6 sides, so there are 6 possible outcomes for each die, resulting in a total of 6 * 6 = 36 possible outcomes when rolling a pair of dice.

The probability is calculated by dividing the number of favorable outcomes (satisfying the condition) by the total number of possible outcomes.

Favorable outcomes = 6 (for doubles) + 5 (for sum of 6) - 1 (for the overlapping outcome) = 10

Probability = Favorable outcomes / Total number of outcomes = 10 / 36 ≈ 0.2778

Rounded to the nearest tenth of a percent, the probability is approximately 27.8%.

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The domain of the function is all real numbers less than 5, and the range is all real numbers greater than or equal to 9.

The given function is f(x) = -log(5-x) + 9.

To determine its domain and range, we need to consider the restrictions on x and the possible values of f(x).

Domain:

The domain refers to the set of all valid inputs or values of x for which the function is defined.

In this case, the function contains a logarithmic term, -log(5-x), which is only defined for positive values inside the logarithm.

Therefore, we must ensure that the expression 5-x is greater than zero:

5 - x > 0

Solving this inequality, we find:

x < 5

Hence, the domain of the function is (-∞, 5).

Range:

The range refers to the set of all possible output values or values of f(x). Since the logarithm term can take any positive value, and we add 9 to it, the range of the function is shifted upward by 9 units.

The range can be defined as all real numbers greater than or equal to 9:

Range: [9, +∞)

To summarize, the domain of the function f(x) = -log(5-x) + 9 is (-∞, 5), and the range is [9, +∞), indicating that f(x) can take any value greater than or equal to 9.

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The answer is:

C. circumference

Work/explanation:

Here's the correct answer:

The distance around a circle is called the circumference.

How to find the circumference :

1. Mr. John received more than 2 cords of wood based on the sizes of the stacked piles.

2. Based on the stacked piles, Mr. John received approximately 11,974 pieces of actual wood.

3. The cost per standard piece of wood is approximately $0.0417.

1. To determine if Mr. John received more or less than 2 cords of wood, we need to calculate the volume of each pile and compare it to the volume of a standard cord of wood.

Calculating the volume of each pile:

PILE #1:

Volume = 72 inches * 167 inches * 16 inches = 1,523,584 cubic inches

PILE #2:

Volume = 65 inches * 266 inches * 16 inches = 2,068,480 cubic inches

Calculating the volume of a standard cord of wood:

Volume of a standard cord = 4 feet * 4 feet * 8 feet = 128 cubic feet

Since 1 foot = 12 inches, the volume in cubic inches is 128 * 12 * 12 * 12 = 221,184 cubic inches.

Comparing the volumes:

Pile #1: 1,523,584 cubic inches

Pile #2: 2,068,480 cubic inches

Standard cord: 221,184 cubic inches

It is evident that both piles have significantly more volume than a standard cord of wood. Therefore, Mr. John received more than 2 cords of wood.

2. To determine the number of standard pieces of wood received, we need to calculate the number of pieces that can be obtained from the total volume of the piles.

Total volume of the piles = Volume of Pile #1 + Volume of Pile #2

Total volume = 1,523,584 cubic inches + 2,068,480 cubic inches = 3,592,064 cubic inches

Volume of a standard piece of wood = 5 inches * 5 inches * 12 inches = 300 cubic inches

Number of standard pieces of wood received = Total volume of the piles / Volume of a standard piece of wood

Number of pieces = 3,592,064 cubic inches / 300 cubic inches = 11,973.55 pieces (rounded to the nearest whole number)

Therefore, Mr. John received approximately 11,974 pieces of actual wood based on his stacked piles.

3. To calculate the cost per standard piece of wood, we need to divide the total cost of the two cords by the number of standard pieces received.

Total cost for both cords of wood = 2 cords * $250/cord = $500

Cost per standard piece of wood = Total cost / Number of standard pieces

Cost per piece = $500 / 11,974 = $0.0417 (rounded to four decimal places)

Therefore, the cost per standard piece of wood is approximately $0.0417.

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Answer:

10: Zero-degree monomial.

8x^4: Quartic monomial.

5x² - 7x + 9: Quadratic trinomial.

2x³ + 3: Cubic binomial.

Step-by-step explanation:

10: This is a constant term, and it can be classified as a zero-degree monomial.

8x^4: This is a monomial with a degree of 4, and it contains one term. It can be classified as a quartic monomial.

5x² - 7x + 9: This is a polynomial with three terms. The highest power of the variable, x, is 2, so it is a quadratic polynomial. Therefore, it can be classified as a quadratic trinomial.

2x³ + 3: This is a polynomial with two terms. The highest power of the variable, x, is 3, so it is a cubic polynomial. Hence, it can be classified as a cubic binomial.

10: Zero-degree monomial.

8x^4: Quartic monomial.

5x² - 7x + 9: Quadratic trinomial.

2x³ + 3: Cubic binomial.

A. The volume of the hemisphere with a diameter of 48 yards is approximately 1001.1 cubic yards.

B. The volume of the sphere with a circumference of a great circle approximately equal to 26 meters is approximately 359.4 cubic meters.

A. To find the volume of a hemisphere, we first need to calculate the radius. The diameter is given as 48 yards, so the radius is half of that, which is 24 yards.

The formula for the volume of a hemisphere is (2/3)πr^3, where r is the radius. Plugging in the values:

Volume = (2/3) * π * (24^3)

Volume ≈ 1001.1 cubic yards (rounded to the nearest tenth)

Therefore, the volume of the hemisphere is approximately 1001.1 cubic yards.

B. To find the volume of a sphere, we need to know the radius. Since the circumference of a great circle is given as approximately 26 meters, we can use the formula C = 2πr, where C is the circumference and r is the radius.

We can rearrange the formula to solve for the radius: r = C / (2π). Plugging in the circumference:

r = 26 / (2π)

r ≈ 4.134 meters (rounded to the nearest thousandth)

The formula for the volume of a sphere is (4/3)πr^3. Substituting the radius:

Volume = (4/3) * π * (4.134^3)

Volume ≈ 359.4 cubic meters (rounded to the nearest tenth)

Therefore, the volume of the sphere is approximately 359.4 cubic meters.

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1) 10% stock dividend: Increase in shares, no change in equity value.

2) 2 for 1 stock split: Doubles shares, no change in equity value.

3) 1 for 5 reverse stock split: Decreases shares, no change in equity value.

The decisions made by Mahmud Mahtab regarding stock dividend, stock split, and reverse stock split would result in the following changes to the accounts:

1) 10% Stock Dividend:

A stock dividend is a distribution of additional shares of stock to existing shareholders. In this case, a 10% stock dividend means that for every 10 shares held, shareholders will receive an additional share. As a result, the following changes would occur:

- Common stock: The number of shares would increase by 10% (3,000 additional shares).

- Additional paid-up capital: There would be no change.

- Retained earnings: There would be a reduction of the amount equal to the market value of the shares issued as dividends.

2) 2 for 1 Stock Split:

A stock split involves dividing existing shares into a larger number of shares. In a 2 for 1 stock split, each existing share would be split into two shares. The following changes would take place:

- Common stock: The number of shares would double (60,000 shares).

- Additional paid-up capital: There would be no change.

- Retained earnings: There would be no change.

3) 1 for 5 Reverse Stock Split:

A reverse stock split combines a number of existing shares into a smaller number of shares. In a 1 for 5 reverse stock split, every five shares would be consolidated into one share. The accounts would be affected as follows:

- Common stock: The number of shares would decrease by 80% (24,000 shares).

- Additional paid-up capital: There would be no change.

- Retained earnings: There would be no change.

Note: The above changes would affect the number of shares and their par value, but the total shareholders' equity (1,00,00,000 TK) would remain unchanged.

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The slope, "m," indicates the rate of change of the line, while the y-intercept, "b," represents the value of y when x equals zero.

I apologize, but as a text-based AI model I'm unable to directly view or analyze any attached images or graphs. However, if you provide me with the equation of the line in the slope-intercept form or describe the relevant details from the graph, I can certainly help you with a response within the given word limit.

The slope-intercept form of a linear equation is given by y = mx + b, where "m" represents the slope of the line and "b" represents the y-intercept, the point where the line intersects the y-axis.

Using this equation, you can determine the slope and y-intercept by comparing the given equation with the slope-intercept form.

Once you provide me with the equation or necessary information, I'll be able to assist you further in understanding the line and its characteristics.

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The sum diverges to negative infinity.

Here we want to find the value of the sum:

[tex]\sum_{m=1}^{ \infty}} (-11/2)*(3/2)^{m + 1}[/tex]

So, that sum goes for infinite values of m, that is bad because you can see that the term with an exponent is larger than 1.

So when m is a really large value, then the term will also be a really large value, which means that the fuction eventually diverges to negative inifnity.

The usual rule that we need to check is that, for large values of m, as m increases, the absolute value of each term decreases.

Here this cleraly does not happen, so the sum diverges.

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Answer: 3√11.

Step-by-step explanation:

To simplify the radical expression √99, we can look for perfect square factors of 99.

The prime factorization of 99 is 3 * 3 * 11.

We can rewrite √99 as √(3 * 3 * 11).

Taking out the perfect square factors, we get:

√(3 * 3 * 11) = 3√11.

Therefore, the simplified radical expression for √99 is 3√11.

The distance from F to G on walkway C is approximately 19.21 units.

To determine the distance from point F to point G on walkway C, we can use the information provided in the map and apply some basic geometric principles.

Looking at the map, we can see that walkway A and walkway B are parallel. Let's use this information to find the distance from F to G on walkway C.

First, let's identify the relevant points on the map. We have point F on walkway C and point G on walkway C. The map also shows two intersecting lines, representing walkways A and B, but we don't need to consider those for this particular calculation.

To find the distance from F to G on walkway C, we need to focus on the segment of walkway C that connects F and G. Based on the map, we can see that the segment of walkway C is perpendicular to both walkway A and walkway B.

Since walkway A and walkway B are parallel, and the segment of walkway C is perpendicular to both, we can conclude that the segment FG forms a right triangle with walkway A and walkway B.

In a right triangle, we can use the Pythagorean theorem to find the length of one side (FG) if we know the lengths of the other two sides.

Let's assume the length of the segment FG is represented by the variable 'd' (which we need to find).

From the map, we can see that the distance from F to walkway A is 15 units. Similarly, the distance from G to walkway B is 12 units.

Applying the Pythagorean theorem, we have:

d^2 = 15^2 + 12^2

d^2 = 225 + 144

d^2 = 369

Taking the square root of both sides, we find:

d ≈ √369

d ≈ 19.21

As a result, it takes 19.21 units to get from F to G on walkway C.

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There can be multiple outputs (monthly charges) for a given input (number of credit cards), violating the definition of a function. hence, Situation 3 does not represent a function.

Situation 3: the total amount of money charged monthly on credit cards to the number of credit cards owned does not represent a function.

In a function, each input (or x-value) should have a unique output (or y-value). However, in this situation, the total amount of money charged monthly on credit cards depends on the number of credit cards owned. It is possible to have different credit card numbers but still have the same total amount of money charged monthly.

For example, two people could own different numbers of credit cards but have the same monthly charges.

As a result, the definition of a function can be violated by having many outputs (monthly charges) for a single input (number of credit cards).

Because of this, case 3 does not represent a function.

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Average speed of the humpback whale: 27 kilometers per hour.

To calculate the average speed of the humpback whale, we can use the formula:

Average speed = Total distance / Total time

Given that the humpback whale traveled a distance of 13.5 kilometers in 30 minutes, we need to convert the time to hours. There are 60 minutes in an hour, so 30 minutes is equal to 0.5 hours.

Now, we can substitute the values into the formula:

Average speed = 13.5 kilometers / 0.5 hours

Average speed = 27 kilometers per hour

Therefore, the average speed of the humpback whale is 27 kilometers per hour.

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Answer:

the property of a material of undergoing elastic deformation or (of a gas) change in volume when subjected to an applied force. It is equal to the reciprocal of stiffness.

The probability that a point chosen at random lies on the shaded region is given as follows:

4/7.

The parameters that are needed to calculate a probability are listed as follows:

Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes.

The area of the shaded region in this problem is given as follows:

4² = 16.

The total area of the figure is given as follows:

16 + 2 x 1/2 x 3 x 4 = 28.

Hence the probability is given as follows:

16/28 = 4/7.

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If 20 tickets were purchased, there would be 22 entries in the raffle drawing.

Based on the information given in the table, we can see that the number of entries in the raffle drawing is always 2 more than the number of tickets purchased.

Let's represent the number of tickets purchased as x and the number of entries in the raffle drawing as y.

From the table, we can observe the relationship between x and y:

When x = 1, y = 3

When x = 2, y = 4

When x = 3, y = 5

When x = 4, y = 6

We can notice that for each value of x, y is always 2 more than x.

So, we can write the equation as y = x + 2.

To find the number of entries in the raffle drawing if 20 tickets were purchased, we substitute x = 20 into the equation:

y = x + 2

y = 20 + 2

y = 22

Therefore, if 20 tickets were purchased, there would be 22 entries in the raffle drawing.

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Answer: The domain of the expression is all real numbers except where the expression is undefined.

Step-by-step explanation: