Solve for x 11x + 13 13x - 1

Answer:

b= -8/5

Step-by-step explanation:

-5-3=7b-3b

-8=5b

b= -8/5

Answer:

5

Step-by-step explanation:

Just by counting, 1 2 3 4 5. five is near the end, there for it is greater

Answer:

A.

bc if you have the answer 16 you look at 6 and see that 6 is a even number so the whole thing's even lol

Answer:

I think the answer is A

Step-by-step explanation

Answer:

-6k+3

Step-by-step explanation:

3(-2k+1)=?

3(-2k)= -6k

3(1)= 3

3(-2k+1)= -6k+3

Answer:

I will use x as the distance traveled in 7 hours

450/5.5 = x/7.7 - set up proportion

5.5x = 3465 - cross products

5.5x/5.5 = 3465/5.5 - divide each side by 5.5

x = 630 - answer

hope this helps.

Step-by-step explanation:

Answer:

x=-1/2

Step-by-step explanation:

Answer:

i

Step-by-step explanation:

you have nothing for us to solve so if you need the definition of it just let me know, but it is represented by the letter "i"

Answer:

Step-by-step explanation:

p^3*(-9)^2*q^2

8*-18*9

-144*9

-1296

Answer:

Step-by-step explanation:

The distributive property states that for any three real numbers a, b, and c, we have:
a(b + c) = ab + ac

This property is very useful when multiplying polynomials, because it allows us to distribute each term in one polynomial to every term in the other polynomial.

For example, to square the binomial (a + b), we can use the distributive property twice:
(a + b)^2 = (a + b)(a + b)
= a(a + b) + b(a + b)
= a^2 + ab + ab + b^2
= a^2 + 2ab + b^2

We can see that the distributive property allows us to multiply each term in the first polynomial by each term in the second polynomial. We then group like terms and simplify to get the final product.

Similarly, to square the binomial (a - b), we can use the same process:
(a - b)^2 = (a - b)(a - b)
= a(a - b) - b(a - b)
= a^2 - ab - ab + b^2
= a^2 - 2ab + b^2

Again, we see that the distributive property enables us to distribute the terms in one polynomial to the other polynomial. We then group like terms and simplify to get the final product.
To find the product of (a - b)(a + b), we can use the distributive property again:
(a - b)(a + b) = a(a + b) - b(a + b)
= a^2 + ab - ab - b^2
= a^2 - b^2

This time, we see that the product is a difference of squares, which means that it can be factored further. In general, the product of two binomials that are conjugates of each other (i.e. have the same terms, but with one sign changed) will be a difference of squares.

Answer:

3³

Step-by-step explanation:

Using the rules of exponents

[tex]a^{m}[/tex] × [tex]a^{n}[/tex] ⇔ [tex]a^{(m+n)}[/tex]

[tex](a^{m}) ^{n}[/tex] = [tex]a^{mn}[/tex]

Given

27³ × [tex]3^{-6}[/tex]

Note that 27 = 3³ , thus

= (3³)³ × [tex]3^{-6}[/tex]

= [tex]3^{9}[/tex] × [tex]3^{-6}[/tex]

= [tex]3^{(9-6)}[/tex]

= 3³

Mika changed the fraction to a decimal by dividing. Now she can change the decimal to a percent by moving the decimal two places to the right and adding a percent sign.

To convert the number 0.125 to a percent form, Mika should multiply number 100 with it in her next step.

Percentage of a number is the part of the whole number which is expressed in the fraction of hundredth. It is represented with "%" symbol.

To write a number in percentage from it need to be multiplied with 100. Mika used division to rewrite 5/ 40 as 0.125.

[tex]\dfrac{5}{40}=0.125[/tex]

Now, to convert this number in percentage form, it has to be multiplied with 100.

[tex]0.125\times100\\12.5\%[/tex]

Thus, to convert the number 0.125 to a percent form, Mika should multiply number 100 with it in her next step.

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Answer:

a∈R

Step-by-step explanation:

Use the distributive property to multiply 3 by 2a+3.

6a+9−2a=2(5+2a)−1

Combine 6a and −2a to get 4a.

4a+9=2(5+2a)−1

Use the distributive property to multiply 2 by 5+2a.

4a+9=10+4a−1

Subtract 1 from 10 to get 9.

4a+9=9+4a

Subtract 4a from both sides.

4a+9−4a=9

Combine 4a and −4a to get 0.

9=9

Compare 9 and 9.

True

This is true for any a.

a∈R

Answer:

mass divided by volume

Step-by-step explanation:

Answer:

1:20

Step-by-step explanation:

well a scale is comparing one thing to another so if 1cm on a map is equal to 20 km then the scale is cm to km

1 cm to 20 km

1:20

Answer:

0.00001:20

Step-by-step explanation:

First of all, we have to realize that we are converting the scale in real life. That means, in kilometers.

So, we know that there are 100,000 cm in 1 kilometer, therefore we can know that 1 cm will equal to 0.00001 kilometers. (I divided by 1 by 100,000. Move the decimal point from 1. by six places.)

There you have the answer: 0.00001:20

The equation that can be used to find the cost of shipping boxes is: 3p + 11 = 34.70. By solving the equation, we get p = $7.23.

The problem is about finding the cost of shipping boxes. Ava purchased 3 flat-rate shipping boxes, and a book of stamps, spending a total of $34.70. The problem asks to find out how much the post office charged for each shipping box, given that the cost of a book of stamps is $11.

To find the cost of a single flat-rate shipping box, let's assume that the post office charged p dollars for each shipping box. Therefore, the cost of three shipping boxes will be 3p dollars.

Along with this, Ava also bought a book of stamps which cost her $11.

So, the total amount she spent can be written as the sum of the cost of the shipping boxes and the cost of the book of stamps. This is given by:

3p + 11 = 34.70

Solving for p, we get:

p = (34.70 - 11)/3p = $7.23 (approx)

Therefore, each shipping box costs $7.23.

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Answer:

The midpoint is (8,8)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates of the endpoint and divide by 2

( 10+6)/2 = 16/2 = 8

To find the y coordinate of the midpoint, add the y coordinates of the endpoint and divide by 2

( 6+10)/2 = 16/2 = 8

The midpoint is (8,8)

Answer:

(8, 8 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )

Here (x₁, y₁ ) = (10, 6) and (x₂, y₂ ) = (6, 10) , thus

midpoint = [tex]\frac{10+6}{2}[/tex] , [tex]\frac{6+10}{2}[/tex] ) = ([tex]\frac{16}{2}[/tex] , [tex]\frac{16}{2}[/tex] ) = (8, 8 )

Answer:

B

Step-by-step explanation:

60+40+x=180(angles in a triangle)

x= 180-100

x=80°

80+z=180(angles on a str line)

z= 100°

100+15+y=180(angles in a triangle)

y=180-115

y=65°

Answer:

c: x = 80, y = 65, z = 100

Step-by-step explanation:

The sum of all angles in a triangle is 180

so 40 + 60 + x = 180 and 15 + y + z = 180

40 + 60 + x = 180

100 + x = 80

x = 80

supplementary angles are equal to 180

x and z are supplementary

80 + z = 180

z = 100

15 + 100 + y = 180

115 + y = 180

y = 65

Answer: f(2) = 5

Explanation: If f(x) - 4x - 3, then f(2) = 4(2) - 3 which simplifies to 5.

The pressure altitude of 3,750 ft affects the aircraft's performance. Higher altitude results in decreased air density, which affects lift generation and engine performance.

To determine the total distance required to land over a 50-foot obstacle, we need to consider the pressure altitude and headwind. The pressure altitude affects the performance of the aircraft, while the headwind affects the groundspeed.

The total distance required to land can be calculated using the following formula:

Total Distance = Ground Roll + Obstacle Clearance Distance

1. Ground Roll:

The ground roll is the distance required for the aircraft to decelerate and come to a complete stop after touchdown. It is influenced by factors such as aircraft weight, runway conditions, and wind.

2. Obstacle Clearance Distance:

The obstacle clearance distance is the additional distance required to safely clear the 50-foot obstacle during the landing. It depends on the aircraft's climb performance, which is affected by factors such as aircraft type, engine power, and atmospheric conditions.

Given the pressure altitude of 3,750 ft and the headwind of 12 kts, we can estimate the total distance required to land over the 50-foot obstacle.

It's important to note that the specific performance data and aircraft characteristics are needed to calculate the exact distances. The following explanation provides a general understanding of the factors involved.

The pressure altitude of 3,750 ft affects the aircraft's performance. Higher altitude results in decreased air density, which affects lift generation and engine performance. This can increase the ground roll and obstacle clearance distance required for landing.

The headwind of 12 kts reduces the aircraft's groundspeed during the landing. A headwind component helps reduce the groundspeed, resulting in a shorter ground roll and obstacle clearance distance.

To calculate the total distance required, we would need more specific data such as the aircraft type, performance charts, and other factors that influence landing distance calculations. These factors include aircraft weight, runway conditions, temperature, and other variables.

It is recommended to consult the aircraft's performance manual or a qualified aviation professional to accurately determine the total distance required to land over a 50-foot obstacle given the specific aircraft and conditions.

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Answer:

24 is lowest common denominator

Step-by-step explanation:

List the multiples of 6 and 8

For example:

6 x 2 = 12 6 x 3 = 18 6 x 4 = 24

8 x 2 = 16 8 x 3 = 24

Theorem 4.3.9 can be proved using either the 0 characterisation of continuity or the sequential characterisation of continuity. Both characterisations are important and useful in different situations.

Theorem 4.3.9: Suppose f: X → Y. TFAE:(i) f is continuous on X(ii) For every open subset V of Y, the inverse image f^-1 (V) is open in X(iii) For every convergent sequence x_n→x, we have f(x_n)→f(x).

A proof for Theorem 4.3.9 using the 0 characterisation of continuity is given below:

Suppose f: X → Y is continuous on X. Let V be open in Y. Let a∈f^-1 (V). Then f(a)∈V, so there exists an ɛ > 0 such that B(f(a), ɛ) ⊆ V.

Since f is continuous at a, there exists a δ > 0 such that x ∈ X and d(x, a) < δ implies d(f(x), f(a)) < ɛ. That is, f(B(a, δ)) ⊆ B(f(a), ɛ) ⊆ V.

This implies B(a, δ) ⊆ f^-1 (V). Thus f^-1 (V) is open in X.For the other direction, suppose for every open subset V of Y, the inverse image f^-1 (V) is open in X. Let a ∈ X. Let ɛ > 0. Set V = B(f(a), ɛ). Then V is open in Y, so f^-1 (V) is open in X.

Since a ∈ f^-1 (V), there exists a δ > 0 such that B(a, δ) ⊆ f^-1 (V). Then f(B(a, δ)) ⊆ V. That is, d(f(x), f(a)) < ɛ whenever d(x, a) < δ. Thus f is continuous at a.This gives us a proof of Theorem 4.3.9 using the 0 characterisation of continuity.

A proof for Theorem 4.3.9 using the sequential characterisation of continuity is given below:Suppose f: X → Y. Suppose (x_n) is a sequence in X converging to x. Then (x_n) is a net in X. By Theorem 4.3.2(iii), if f is continuous at x, then f(x_n) converges to f(x).Now suppose that for every convergent sequence (x_n) in X that converges to x, we have f(x_n) converges to f(x).

Let V be open in Y. Let a∈f^-1 (V). Suppose that f is not continuous at a. Then there exists an ɛ > 0 such that for every δ > 0, there exists an x ∈ B(a, δ) such that d(f(x), f(a)) ≥ ɛ. Let δ_n = 1/n. Then for each n, there exists x_n ∈ B(a, δ_n) such that d(f(x_n), f(a)) ≥ ɛ. Then (x_n) converges to a, but (f(x_n)) does not converge to f(a). This contradicts our assumption.

Thus f is continuous at a.Hence we have a proof for Theorem 4.3.9 using the sequential characterisation of continuity.

We first showed the proof of Theorem 4.3.9 using the 0 characterisation of continuity.

We then showed the proof of Theorem 4.3.9 using the sequential characterisation of continuity.We used the 0 characterisation of continuity to show that f is continuous on X if and only if for every open subset V of Y, the inverse image f^-1 (V) is open in X. This result follows from the definitions of continuity and openness.

We used this characterisation to prove Theorem 4.3.9. We showed that f is continuous on X if and only if for every convergent sequence x_n→x, we have f(x_n)→f(x).

This characterisation is important because it allows us to prove continuity of a function using the open sets of the codomain. We do not need to use sequences or nets to prove continuity.

This is useful in some cases where we cannot use sequences or nets, for example, in metric spaces that are not first-countable.We then used the sequential characterisation of continuity to show that f is continuous on X if and only if for every convergent sequence x_n→x, we have f(x_n)→f(x).

This characterisation follows from the definition of continuity and the sequential characterisation of convergence. We used this characterisation to prove Theorem 4.3.9. We showed that f is continuous on X if and only if for every open subset V of Y, the inverse image f^-1 (V) is open in X.

This characterisation is important because it allows us to prove continuity of a function using sequences.

This is useful in many cases, for example, in metric spaces that are first-countable. It also allows us to prove that some spaces are not first-countable by finding a function that is not continuous using sequences.

Therefore, Theorem 4.3.9 can be proved using either the 0 characterisation of continuity or the sequential characterisation of continuity. Both characterisations are important and useful in different situations.

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Answer:

The answer is

Step-by-step explanation:

The distance between two points can be found by using the formula

[tex]d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\[/tex]

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(8, -4), (-7, 6)

We have

[tex]d = \sqrt{( {8 + 7})^{2} + ({ - 4 - 6})^{2} } \\ = \sqrt{ {15}^{2} + ({ - 10})^{2} } \\ = \sqrt{225 + 100} \\ = \sqrt{325} \: \: \: \: \: \: \: \: \: \: \: \: \\ = 5 \sqrt{13} \: \: \: \: \: \: \: \: \: \: \: \: \\ =18.027756 ...[/tex]

We have the final answer as

[tex]5 \sqrt{13} \: \: \: \: or \: \: \: \: 18.03 \: \: \: \: units[/tex]

Hope this helps you

Answer:

x≥-1

Step-by-step explanation:

4x+12 ≥8

Subtract 12 from each side

4x+12-12 ≥8-12

4x≥-4

Divide each side by 4

4x/4 ≥-4/4

x≥-1

Answer:

4x+12 is greater than 8 4x+12=16x

Step-by-step explanation

Add 4+12

Then since we don't know what x equals you would put x at the end of your answer therefore your answer would be 16x which is greater than 8

Answer:

x = 5

Step-by-step explanation:

Step 1: Write equation

x = 3x - 10

Step 2: Solve for x

Step 3: Check

Plug in x to verify it's a solution.

5 = 3(5) - 10

5 = 15 - 10

5 = 5

2sin(x)cos(x) = sin(x)

2sin(x)cos(x) - sin(x) = 0

sin(x)(2cos(x) - 1) = 0

sin(x) = 0

x = 0, pi, 2pi

2cos(x) - 1 = 0

cos(x) = 1/2

x = pi/3,  5π/pi

x = 0, pi/3, pi, 5 pi/3,  2 pi

hope it helps

The set of points in space that satisfy the given pairs of inequalities can be described geometrically as follows: The inequality y ≤ x^2 represents a parabolic region in the x-y plane where the y-coordinate is less than or equal to the square of the x-coordinate. This corresponds to a downward-opening parabola that opens towards the negative y-axis.

The inequality z ≥ 0 represents the region above the xy-plane, including the xy-plane itself. This is a half-space extending upwards from the xy-plane.

The inequality x ≥ z^2 represents a region in the x-z plane where the x-coordinate is greater than or equal to the square of the z-coordinate. This corresponds to a sideways-opening parabola that opens towards the positive x-axis.

The inequality -5 ≤ y ≤ 0 represents a vertical range of values for the y-coordinate between -5 and 0, inclusive. This corresponds to a segment on the negative y-axis between y = -5 and y = 0.

By combining these geometric descriptions, the set of points in space satisfying both pairs of inequalities is the region that lies below the parabolic surface, above or on the xy-plane, and to the right of the sideways-opening parabola, within the specified range on the negative y-axis. It is a three-dimensional region that can be visualized as a solid bounded by these surfaces.

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Give a geometric description of the set of points in space whose coordinates satisfy the given pairs of inequalities.

yx2 , z0

xz2 , -5y0

Answer:

$34.00

Step-by-step explanation:

Add 9 to 25 to find your answer

Answer:

C

Step-by-step explanation:

Step-by-step explanation:

Given that,

Total length of the fence is 26 feet

The side of the house that does not need a fence is 9 feet long.

We need to find the missing length of the kenel.

26 feet is the perimeter of the kennel. Perimeter is the sum of all sides of a rectangle.

P = l+b+l+b

P=2b+l (because side of the kennel against the house does not need a fence

So,

26=2b+9

2b=17

⇒ b = 8.5 feet

l = 9 feet

So, the missing length of the kennel is 9 feet.

Answer:

E. X= 5+ (gcf)37/6

F. x= 5 - (gcf)37/6

Step-by-step explanation:

put in calculator MOD 5 3

write the values: -

                             a= 3    b= -5    c= -1