Solve for y. 3y^(2)=7y+6 If there is more than one solution, separate them wit If there is no solution, click on "No solution."

The future value of the investment after 6 years is $14,370.88; while the effective annual interest rate is 2.56%.

To calculate the future value of the investment, we can use the formula: FV = PV (1 + r/n)^(nt), where FV is the future value, PV is the present value, r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the number of years.

In this case, PV = $12,000, r = 0.025, n = 12 (compounded monthly), and t = 6.

Plugging these values into the formula, we get:

FV = $12,000 (1 + 0.025/12)^(12*6)

FV = $12,000 (1.002083333)^72

FV = $14,370.88

Therefore, the future value of the investment after 6 years is $14,370.88.

To calculate the effective annual interest rate, we can use the formula: EAR = (1 + r/n)^(n) - 1, where r is the annual interest rate and n is the number of times the interest is compounded per year.

In this case, r = 0.025 and n = 12 (compounded monthly).

Plugging these values into the formula, we get:

EAR = (1 + 0.025/12)^(12) - 1

EAR = (1.002083333)^12 - 1

EAR = 0.02568245

Therefore, the effective annual interest rate is 2.568245%.

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The Addition Property of Equality, If a=b, then a+c=b+c depicts the notion that "If equals are added to equals, then the wholes are equal". The correct answer is option e.

Addition Property of Equality is a law that describes the possibility of adding the same quantity on both sides of an equation to maintain equality. If a=b, then a+c=b+c represents the Addition Property of Equality. It denotes that if you add the same quantity on both sides of an equation, the result will remain equal.

The Addition Property of Equality also mentions that if two numbers are equal to each other, then adding the same number to both of them will also result in two equal numbers. This means that if a=b, then a+c=b+c. Therefore, the correct answer is option "e.  

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The dosage of Jack and Jill is obtained using geometric series formula which is 500 mg and 225 mg respectively.

What is geometric series?

A geometric series is a collection of terms in mathematics that have an unlimited number and a fixed ratio between each term. A geometric series is typically expressed as a + ar + ar² + ar³ + ..., where r is the common ratio between neighbouring terms and a is the coefficient of each term.

Let's start by finding the amount of medication that Jack takes in total.

Each hour, Jack takes a dosage that is 80% of the previous dosage (since it drops by 20%).

So his dosages form a geometric sequence with first term 100 and common ratio 0.8 -

100, 80, 64, 51.2, 40.96, ...

The sum of an infinite geometric series with first term a and common ratio r (where |r| < 1) is given by -

sum = a / (1 - r)

In this case, a = 100 and r = 0.8, so the sum is -

sum = 100 / (1 - 0.8) = 500

Therefore, Jack takes a total of 500 mg of medication.

Now let's find the original dosage for Jill.

If Jill takes half the amount of medication that Jack eventually took, then she takes -

500 / 2 = 250 mg

Let's call Jill's original dosage x.

Then her dosages form a geometric sequence with first term x and common ratio 0.7 (since it drops by 30%).

The sum of this sequence must be 250.

x + 0.7x + 0.49x + 0.343x + ... = 250

This is an infinite geometric series with first term x and common ratio 0.7, so we can use the formula for the sum of an infinite geometric series -

sum = x / (1 - 0.7) = x / 0.3

Simplifying the equation from before -

x / 0.3 × (1 + 0.7 + 0.49 + 0.343 + ...) = 250

x / 0.3 × (1 / (1 - 0.7)) = 250

x / 0.3 × 3.333... = 250

x = 250 / 1.111... = 225

Therefore, Jill's original dosage was 225 mg.

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Answer: 7704

Step-by-step explanation:

( see image !)

Step-by-step explanation:

please answer this question quickly

Answer:

H<5

Step-by-step explanation:

u solve it as a normal equation but with the symbol <.

The simplified expression of (1)/(13)(13y)  is 169y.

To simplify the expression (1)/(13)(13y) using the commutative or associative property, we can rearrange the terms and group them together.

Using the commutative property, we can rearrange the terms so that the two 13's are next to each other:

(1)(13)(13y) = (13)(13y)(1)

Now, using the associative property, we can group the two 13's together and simplify:

(13)(13y)(1) = (13*13)(y)(1) = (169)(y)(1)

Finally, we can simplify further by multiplying the 169 and 1 together:

(169)(y)(1) = (169y)(1) = 169y

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Answer:

Step-by-step explanation: First you multiply 23 and 12 and you get 276. Then you do 276 divided by 6 and you get 46. So your final answer will be 43 inches.

144x² - 24x + 1 = 12²x² - 24x + 1 = (12x)² - 2(12x) + 1² = (12x - 1)²

the above question, we may state that Hence, the surface area rectangular prism has a surface area of 148 square centimeters.

An object's surface area is a measure of how much space it takes up overall. The entire amount of space around a three-dimensional form is its surface area. The total surface area of a three-dimensional form is referred to as its surface area. By summing the areas of each face, one may get the surface area of a cuboid with six rectangular faces. Instead, you may identify the box's dimensions using the following formula: Surface (SA) equals 2lh, 2lw, and 2hw. The total amount of space occupied by the surface of a three-dimensional form is measured as surface area.

Shown above is a rectangular prism. We may apply the formula: to determine the surface area.

2lw + 2lh + 2wh = Surface Area

where the prism's length, breadth, and height are indicated by l, w, and h, respectively.

As we look at the image, we can see that it is 6 cm long, 4 cm wide, and 5 cm tall. These values can be used as substitutes in the formula:

Surface Area = (2,6,4,2,6,5,2) (5)

Area of Surface = 48 + 60 + 40

Area of Surface = 148

Hence, the rectangular prism has a surface area of 148 square centimeters.

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The slope of the line passing through the points (-5,5) and (5,8) is 0.3.

The slope of a line is the rate at which it rises or falls as it moves from left to right. It is defined as the change in the vertical distance divided by the change in the horizontal distance between any two points on the line.

The slope of a line passing through two points (x₁,y₁) and (x₂,y₂) can be calculated using the slope formula:

slope = (y₂-y₁)/(x₂-x₁)

Using the coordinates (-5,5) and (5,8), we can plug in the values to get:

slope = [tex]\frac{(8-5)}{(5-(-5))}[/tex]

slope = [tex]\frac{3}{10}[/tex]

slope = 0.3

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If there are 240 students in the sixth-grade class then the number of votes that Naomi received is: 336 votes.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

Bridgette and Naomi ran for sixth-grade class president.

In the election, every sixth-grade student voted for either Bridgette or Naomi.

Bridgette received 5 votes for every 7 votes Naomi received.

the first figure represents 5:7 ratio in the story.

Since Bridgette received 5 votes for every 7 votes Naomi received, Bridgette received 5/7 of the total votes and Naomi received 2/7 of the total votes.

We know that the total number of votes cast is equal to the total number of students in the class, which is 240.

Therefore, we can set up the equation:

⁵/₇(x) + ²/₇(x) = 240

Simplifying the equation, we get:

(5x + 2x)/7 = 240

7x/7 = 240

x = 240 × 7/5

x = 336

Therefore, If there are 240 students in the sixth-grade class then Naomi received 336 votes.

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The properties of logarithms to expand the expression as a sum, difference, and/or constant multiple of logarithms ln(√z) = (1/2)ln(z)

What is the logarithms?

Logarithms are mathematical functions that help to solve exponential equations. They are used to express very large or very small numbers in a more convenient and manageable way.

We can use the property of logarithms that states:

logb (a∙c) = logb a + logb c

to expand the expression as a sum of logarithms:

ln(√z) = ln(z^(1/2))

Using the power rule of logarithms, we can simplify this as:

ln(z^(1/2)) = (1/2)ln(z)

Hence, we can write:

ln(√z) = (1/2)ln(z)

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Answer:

a) The minimum normal value of the platelet count of a healthy person in usual form is 105,000,000,000 per liter (or 105 x 10^9 per L).

b) The platelet count of Allen in the usual form is 65,000,000,000 per liter (or 65 x 10^9 per L).

c) Allen needs to gain 40,000,000,000 more platelets per liter (or 40 x 10^9 per L) to reach the normal value of a healthy person.

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here's your Answer ~

A.) minimum number of platelet count for a healty person :

[tex]\qquad \sf\dashrightarrow \:105000000000 \: \: per \: litre[/tex]

[ That's the usual form, you just need to add 9 zeros to the value ]

B.) The value of platelet count of Allen :

[tex]\qquad \sf\dashrightarrow \:65000000000 \: \: per \: litre[/tex]

C.) platelet count she should gain to be equal to the normal value :

[tex]\qquad \sf  \dashrightarrow \: 105 \times 10 {}^{9} - 65 \times 10 {}^{9} [/tex]

[ taking 10⁹ common ]

[tex]\qquad \sf  \dashrightarrow \: 10 {}^{9} (105 - 65)[/tex]

[tex]\qquad \sf  \dashrightarrow \: 40 \times 10 {}^{9} \: \: per \: \: litre[/tex]

In normal value, it will be :

[tex]\qquad \sf\dashrightarrow \:40000000000 \: \: per \: litre[/tex]

Answer:

see below

Step-by-step explanation:

84

i took the test

end{bmatrix} = \begin{bmatrix} 1 \\ \frac{1}{5} \\ 1 \end{bmatrix}.

(a) Let $a^1 = \begin{bmatrix} 1 \\ 1 \\ 2 \\ 1 \end{bmatrix}, a^2 = \begin{bmatrix} -1 \\ 2 \\ 0 \\ -2 \end{bmatrix},$ and $a^3 = \begin{bmatrix} 1 \\ 4 \\ 4 \\ 0 \end{bmatrix}.$ Write the matrix $A = \begin{bmatrix} a^1 & a^2 & a^3 \end{bmatrix}$ in the form $A = QR$ by using the Gram-Schmidt process. (b) Use the QR factorization of $A$ in part (a) to solve the equation $Ax = b,$ where $b = \begin{bmatrix} 3 \\ 1 \\ 2 \\ 1 \end{bmatrix}.$The Gram-Schmidt algorithm is a numerical method to produce orthonormal basis of a subspace in Hilbert space that spans the same space, which makes the basis more convenient to work with. As for the first part of the question, let us begin by applying the Gram-Schmidt algorithm to $a^1, a^2, a^3.$ We begin by defining $q_1 = a^1 / \|a^1\|.$ Hence,$$q_1 = \frac{1}{3}\begin{bmatrix} 1 \\ 1 \\ 2 \\ 1 \end{bmatrix} = \begin{bmatrix} 1/3 \\ 1/3 \\ 2/3 \\ 1/3 \end{bmatrix}.$$Next, we define $v_2 = a^2 - \langle q_1, a^2 \rangle q_1.$ Therefore,$$v_2 = a^2 - \frac{-1}{3}(1/3)q_1 = \begin{bmatrix} -7/9 \\ 8/9 \\ -2/9 \\ -4/9 \end{bmatrix}.$$Now, we can define $q_2 = v_2 / \|v_2\|.$ Thus,$$q_2 = \frac{1}{3}\begin{bmatrix} -7 \\ 8 \\ -2 \\ -4 \end{bmatrix}.$$Finally, we define $v_3 = a^3 - \langle q_1, a^3 \rangle q_1 - \langle q_2, a^3 \rangle q_2.$ Then,$$v_3 = a^3 - \frac{5}{9}q_1 - \frac{7}{27}q_2 = \begin{bmatrix} -1/27 \\ 5/9 \\ 22/27 \\ -5/27 \end{bmatrix}.$$Lastly, we can define $q_3 = v_3 / \|v_3\|,$ so$$q_3 = \frac{1}{3}\begin{bmatrix} -1 \\ 5 \\ 22 \\ -5 \end{bmatrix}.$$Now, we can write $A = QR$ as $$\begin{bmatrix} a^1 & a^2 & a^3 \end{bmatrix} = \begin{bmatrix} q_1 & q_2 & q_3 \end{bmatrix} \begin{bmatrix} r_{11} & r_{12} & r_{13} \\ 0 & r_{22} & r_{23} \\ 0 & 0 & r_{33} \end{bmatrix}.$$We can obtain the entries of the $R$ matrix by calculating the inner product of each $q_i$ with $a^j.$ Thus,$$r_{11} = \|a^1\| = \sqrt{7},$$$$r_{12} = \langle q_1, a^2 \rangle = \frac{-1}{3}\sqrt{7},$$$$r_{13} = \langle q_1, a^3 \rangle = \frac{5}{9}\sqrt{7},$$$$r_{22} = \|v_2\| = \frac{5}{3}\sqrt{2},$$$$r_{23} = \langle q_2, a^3 \rangle = \frac{-7}{9}\sqrt{2},$$$$r_{33} = \|v_3\| = \frac{2}{3}\sqrt{6}.$$Therefore,$$\begin{bmatrix} a^1 & a^2 & a^3 \end{bmatrix} = \begin{bmatrix} q_1 & q_2 & q_3 \end{bmatrix} \begin{bmatrix} \sqrt{7} & -\frac{1}{3}\sqrt{7} & \frac{5}{9}\sqrt{7} \\ 0 & \frac{5}{3}\sqrt{2} & -\frac{7}{9}\sqrt{2} \\ 0 & 0 & \frac{2}{3}\sqrt{6} \end{bmatrix}.$$Now, let us solve the equation $Ax = b$ by using the QR factorization of $A.$ We can write $Ax = QRx = b.$ Since $Q$ is orthogonal, we can multiply both sides of the equation by $Q^T$ to obtain $Rx = Q^Tb.$ Note that $Q^Tb$ is easy to compute since $Q^T$ is just the matrix with the $q_i$'s as rows. Thus,$$\begin{bmatrix} \sqrt{7} & -\frac{1}{3}\sqrt{7} & \frac{5}{9}\sqrt{7} \\ 0 & \frac{5}{3}\sqrt{2} & -\frac{7}{9}\sqrt{2} \\ 0 & 0 & \frac{2}{3}\sqrt{6} \end{bmatrix} \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix} = \begin{bmatrix} \frac{2}{3} \\ \frac{1}{3} \\ \frac{2}{3} \end{bmatrix}.$$This gives the system of equations$$\begin{cases} \sqrt{7}x_1 - \frac{1}{3}\sqrt{7}x_2 + \frac{5}{9}\sqrt{7}x_3 = \frac{2}{3}, \\ \frac{5}{3}\sqrt{2}x_2 - \frac{7}{9}\sqrt{2}x_3 = \frac{1}{3}, \\ \frac{2}{3}\sqrt{6}x_3 = \frac{2}{3}. \end{cases}$$Solving the last equation for $x_3,$ we obtain $x_3 = 1.$ Substituting this into the second equation, we obtain $x_2 = \frac{1}{5}.$ Finally, substituting these values into the first equation gives us $x_1 = 1.$ Therefore,$$x = \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix} = \begin{bmatrix} 1 \\ \frac{1}{5} \\ 1 \end{bmatrix}.$$

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For initial speeds of 30, 35 and 40 mph, displacement, velocity and acceleration can be computed.

The single mass - single energy absorber model of a 2021 Volkswagen ID.4 subjected to a frontal crash can be solved using a piecewise equation which will consist of three phases: loading, unloading and separation. The loading stiffness is 993.5 N/mm, the unloading stiffness is 18,027 N/mm and the vehicle mass is 2305 kg. The closed form solution for displacement, velocity and acceleration as a function of vehicle mass, initial velocity and energy absorber spring constants can be written as follows:

Displacement:

Loading phase:

$x_1(t) = \frac{F_{crash}}{m}t^2 + v_{in}t$

Unloading phase:

$x_2(t) = \frac{F_{crash}}{m}t^2 + v_{in}t - \frac{K_u}{m}t^2$

Separation phase:

$x_3(t) = \frac{F_{crash}}{m}t^2 + v_{in}t - \frac{K_u}{m}t^2 - \frac{K_u}{m}t^3$

Velocity:

Loading phase:

$v_1(t) = \frac{2F_{crash}}{m}t + v_{in}$

Unloading phase:

$v_2(t) = \frac{2F_{crash}}{m}t + v_{in} - \frac{2K_u}{m}t$

Separation phase:

$v_3(t) = \frac{2F_{crash}}{m}t + v_{in} - \frac{2K_u}{m}t - \frac{3K_u}{m}t^2$

Acceleration:

Loading phase:

$a_1(t) = \frac{2F_{crash}}{m}$

Unloading phase:

$a_2(t) = \frac{2F_{crash}}{m} - \frac{2K_u}{m}$

Separation phase:

$a_3(t) = \frac{2F_{crash}}{m} - \frac{2K_u}{m} - \frac{6K_u}{m}t$

For initial speeds of 30, 35 and 40 mph, displacement, velocity and acceleration can be computed and plotted versus time. The peak displacement, peak acceleration, rebound velocity, time of max displacement, and time of vehicle-barrier separation can be tabulated and compared. The results of the model at 35 mph can be validated graphically and by tabulating the parameters listed above.

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The quadrants that contain all the points found on the linear function -3x + 5y = 15 are given as follows:

The linear function for this problem is defined as follows:

-3x + 5y = 15.

In slope-intercept format, it is given as follows:

5y = 3x + 15

y = 0.6x + 3.

The features of the line are given as follows:

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The equation for the exponential function is

The graph is attached

Exponential function is a function of the form  f(x) = a(b)ˣ

where

the starting = a

the base = b

the exponents = x

Using the table, f(x) = a(b)ˣ

a = 20

solving for b

10 = 20(b)¹

10 = 20b

b = 1/2

the equation for the function is f(x) = 20(0.5)ˣ

check

for x = 3

f(x) = 20(0.5)³ = 2.5

for x = 4

f(x) = 20(0.5)⁴ = 1.25

The graph of exponential decay is a decreasing function that approaches the x-axis, but never touches it. The rate at which the function decays depends on the value of b - the smaller the value of b, the slower the decay

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The answer of another zero - polynomial function with real coefficient at 1+2i is 1-2i

The other zero of the polynomial function  with real coefficients and a zero at 1+2i is 1-2i.

This is because if a polynomial function with real coefficients has a complex zero,

then the conjugate of that zero is also a zero of the function. The conjugate of a complex number is obtained by changing the sign of the imaginary part.

Therefore, the conjugate of 1+2i is 1-2i. So, if 1+2i is a zero of the polynomial function, then 1-2i is also a zero of the function.

In summary, the other zero of the polynomial function with real coefficients and a zero at 1+2i is 1-2i.

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In response to the supplied query, we may state that Therefore, the area of the circle is approximately 113.1 cm² (rounded to one decimal place).

A circle is created in the plane by each point that is a specific distance from another point (center). Hence, it is a curve made up of points that are separated from one another by a defined distance in the plane. Moreover, it is rotationally symmetric about the centre at every angle. Every pair of points in a circle's closed, two-dimensional plane are evenly spaced apart from the "centre." A circular symmetry line is made by drawing a line through the circle. Moreover, it is rotationally symmetric about the centre at every angle.

We must make certain assumptions because the diagram was not created precisely. Assume that the quarter circle is a perfect quarter circle and that its radius is 12 cm (as given in the question).

A = r2, where r is the radius, is the formula for calculating a circle's surface area. Due to the fact that we only have a quarter of a circle, we must divide the outcome by 4. Hence, the quarter circle's area is:

[tex]A = (1/4)\pi r^2\\A = (1/4))\pi(12^2)\\A = (1/4))\pi(144)\\A = 36)\pi[/tex]

Therefore, the area of the shape is approximately 113.1 cm² (rounded to one decimal place).

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So, with one acute angle measuring 23.58 degrees and another acute Pythagorean theorem angle measuring 66.42 degrees, we may define this triangle as a right triangle.

The fundamental Euclidean geometry relationship between the three sides of a right triangle is the Pythagorean Theorem, sometimes referred to as the Pythagorean Theorem. This rule states that the areas of squares with the other two sides added together equal the area of the square with the hypotenuse side. According to the Pythagorean Theorem, the square that spans the hypotenuse (the side that is opposite the right angle) of a right triangle equals the sum of the squares that span its sides. It may also be expressed using the standard algebraic notation, a2 + b2 = c2.  

A triangle with the vertices A, B, and C with sides measuring 5, 12, and 13 units is seen in the illustration.

Let's use our triangle to illustrate this theorem:

[tex]a = 5, b = 12, c = 13\\a^2 + b^2 = 25 + 144 = 169\sc \\a^2 = 13^2 = 169\\[/tex]

Our triangle complies with the Pythagorean theorem because a2 + b2 = c2. Triangle ABC is a right triangle as a result, and the side with the length 13 is opposite the right angle.

[tex]A = arcsin(5/13)[/tex] = 23.58 degrees when sin(A)

= opposite/hypotenuse

= 5/13 A.

[tex]arccos(12/13) = 66.42 degrees B = cos(A) = adjacent/hypotenuse = 12/13[/tex]

A, B, and C are all at 90 degrees.

So, with one acute angle measuring 23.58 degrees and another acute angle measuring 66.42 degrees, we may define this triangle as a right triangle.

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pool = length x width x height

pool = 15 x 9 x ?

270 = 135x

x = 2

the height is 2 meters.

The answer are LCD (least common denominator) of the set of fractions (7)/(20) and (9)/(40) is 40.

Here is a step-by-step explanation on how to find the LCD:

1. Find the multiples of each denominator.

- Multiples of 20: 20, 40, 60, 80, 100, 120, 140, 160, 180, 200...

- Multiples of 40: 40, 80, 120, 160, 200, 240, 280, 320, 360, 400...

2. Compare the multiples of each denominator and find the smallest number that appears in both lists.

- The smallest number that appears in both lists is 40.

3. The smallest number that appears in both lists is the LCD.

- Therefore, the LCD of the set of fractions (7)/(20) and (9)/(40) is 40.

So the answer to the question "Find the LCD (least common denominator) of the set of fractions. Do not combine the fractions; only find the LCD. (7)/(20) and (9)/(40)" is 40.

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Brendan is currently 37 years old.

To solve this problem, we can use algebra. Let's let V represent Valerie's age and B represent Brendan's age. We can set up the following equations based on the information given in the question:
B = V + 5 (Brendan is 5 years older than Valerie)
B + 6 + V + 6 = 81 (In 6 years, the sum of their ages will be 81)
Simplifying the second equation, we get:
B + V + 12 = 81
B + V = 69
Substituting the first equation into the second equation, we get:
V + 5 + V = 69
2V = 64
V = 32
Now that we know Valerie's age, we can use the first equation to find Brendan's age:
B = 32 + 5
B = 37
So Brendan's current age is calculated to be 37 years

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a)T(v)=∥v∥ is not a linear transformation.

b)T(v)=v⋅x is a linear transformation.

c)TA(x)=y.

d)B must also be invertible.

a) The function T:Rn→R defined by T(v)=∥v∥ is not a linear transformation.

b) The function T:Rn→R defined by T(v)=v⋅x is a linear transformation.

c) Let A∈Mnxn(F) be an invertible matrix, and let TA:Fn→Fn be the linear transformation determined by A. For all y∈Fn, there exists a unique x∈Fn such that TA(x)=y.

d) Let A,B∈Mnxn(F). Suppose that AB=AT and that A is invertible. Then B must also be invertible.

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To find the image for each given value of k, we need to multiply the original volume (100 cubic units) by the scale factor (k).

Volume is a measure of the amount of space occupied by an object or substance. It is expressed as a numerical value, usually in cubic units, such as milliliters (mL) or cubic centimeters (cc). It is also used to measure the capacity of a container, such as a bottle, or a tank.

Dilation is a transformation that changes the size of a shape. When a solid is dilated by a scale factor of k, the new solid will be k times larger than the original solid. For example, if a solid has a volume of 100 cubic units and is dilated by a scale factor of 2, the image solid will have a volume of 200 cubic units (2 x 100).

To find the image for each given value of k, we need to multiply the original volume of the solid (100 cubic units) by the scale factor (k). We can use the equation V = kV0, where V0 is the original volume and V is the new volume, to calculate the new volume of the solid.

For example, if k = 3, the new volume will be 3 x 100 = 300 cubic units. If k = 4, the new volume will be 4 x 100 = 400 cubic units. In general, for any given value of k, the new volume will be k times the original volume.

To summarize, when a solid with a volume of 100 cubic units is dilated by a scale factor of k, the image solid will have a volume of k times the original volume (V = kV0). Therefore, to find the image for each given value of k, we need to multiply the original volume (100 cubic units) by the scale factor (k).

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Answer:

Aquí hay tres situaciones en las que se hace necesario el uso de números negativos:

Temperaturas: Las temperaturas pueden ser positivas o negativas, dependiendo de si estamos midiendo la temperatura por encima o por debajo del punto de congelación del agua. Por ejemplo, si la temperatura es de -10°C, significa que hace 10 grados bajo cero.

Deudas: Cuando una persona toma un préstamo o usa una tarjeta de crédito, puede acumular una deuda que debe ser pagada en el futuro. Esta deuda se representa con un número negativo, ya que representa el dinero que se debe.

Altitud: Cuando se mide la altitud de un lugar, puede ser por encima o por debajo del nivel del mar. Si la altitud es por debajo del nivel del mar, se representa con un número negativo. Por ejemplo, la altitud del Mar Muerto es de aproximadamente -430 metros.

The required, value of x in the rational equation x⁵=618 is approximately 4.951.

Simplification involves applying rules of arithmetic and algebra to remove unnecessary terms, factors, or operations from an expression.

Here,
To solve for x in the rational equation x^5 = 618, we need to isolate x on one side of the equation.

Taking the fifth root of both sides, we get:

[tex]x = 618^{1/5}[/tex]

The approximate value of the fifth root of 618 is approximately 4.951.

Therefore, the value of x is approximately 4.951.

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She gets $114 to work at grocery store for 6 hours and $200 at the nursery.

A rate in arithmetic is a ratio that contrasts two separate values with various unit systems. For instance, if John types 50 words per minute, that means he types 50 words per minute.

We are dealing with a rate because the word "per" is there. The symbol "/" can be used in place of the word "per" in issues.

When two or more similar amounts or numbers are being compared using the same units, a ratio is utilized. When referring to the ratio of one quantity "to" the second quantity in spoken language, it is frequently written with a colon.

Eli has two summer jobs. During the week he works in the grocery store, and on the weekend he works at a nursery. He gets paid $20 per hour to work at the grocery store and $17 per hour to work at the nursery.

14 hours at the grocery store and 9 hours at the nursery? How much does he earn if he works

Therefore, She gets $114 to work at grocery store for 6 hours and $200 at the nursery.

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Answer: f(g(2)) = 1   and g(f(1)) = 2

Step-by-step explanation:

The equation of the parabola is f(x) = x² - 4x + 4

The equation of the line is g(x) = x + 1

To find f(g(2)), you must first find g(2)

g(2) = (2) + 1

g(2) = 3

Now find f(g(2)) by using 3 for g(2)

f(3) = (3)² - 4(3) + 4

f(3) = 9 - 12 + 4

f(3) = 1

f(g(2)) = 1

To find g(f(1)), you must first find f(1)

f(1) = (1)² - 4(1) + 4

f(1) = 1 - 4 + 4

f(1) = 1

Now find g(f(1)) by using 1 for f(1)

g(1) = (1) + 1

g(1) = 2

g(f(1)) = 2

Hope this helps!