The equation is solved to a simplified form as x = -4 ±√14
How to solve the expression
From the information given, we have that the quadratic equation is given as;
x² + 4x = 3
collect the like terms
x² + 4x - 3 = 0
Using the quadratic formula, we have
x = -b±√b² - 4ac/2a
From the equation;
ax + bx + c = 0
a = 1
b = 4
c = -3
Substitute the values
x = -4 ± √(4)² - 4(1)(-3)/2(1)
expand the bracket, we get;
x = -4 ± √16 + 12/2
Add the values
x = -4 ± √28/2
Divide the values
x = -4 ±√14
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A random sample of 21 items is drawn from a population whose standard deviation is unknown. The sample mean is x¯ = 910 and the sample standard deviation is s = 20 Use Appendix D to find the values of Student’s t.
1. Construct an interval estimate of mu with 99% confidence. (Round your answers to 3 decimal places.)
The 99% confidence interval is from_____ to ______ .
2. Construct an interval estimate of mu with 99% confidence, assuming that s = 40. (Round your answers to 3 decimal places.)
The 99% confidence interval is from_____ to ______ .
3. Construct an interval estimate of mu with 99% confidence, assuming that s = 80. (Round your answers to 3 decimal places.)
The 99% confidence interval is from_____ to ______ .
1. The 99% confidence interval is from 877.094 to 942.906.
2. The 99% confidence interval is from 883.267 to 936.733.
3. The 99% confidence interval is from 838.437 to 981.563.
What is interval?
In statistics, an interval refers to a range of values in which a population parameter, such as the mean or proportion, is estimated to lie with a certain level of confidence.
Using the t-distribution with 20 degrees of freedom and a 99% confidence level (two-tailed), we find the t-value from Appendix D to be 2.861.
The 99% confidence interval for the population mean is:
lower bound = [tex]\bar{x}[/tex] - t*(s/√n) = 910 - 2.861*(20/√21) = 877.094
upper bound = [tex]\bar{x}[/tex] + t*(s/√n) = 910 + 2.861*(20/√21) = 942.906
Therefore, the 99% confidence interval is from 877.094 to 942.906.
Using the t-distribution with 20 degrees of freedom and a 99% confidence level (two-tailed), we find the t-value from Appendix D to be 2.861.
The 99% confidence interval for the population mean is:
lower bound = [tex]\bar{x}[/tex] - t*(s/√n) = 910 - 2.861*(40/√21) = 883.267
upper bound = [tex]\bar{x}[/tex] + t*(s/√n) = 910 + 2.861*(40/√21) = 936.733
Therefore, the 99% confidence interval is from 883.267 to 936.733.
Using the t-distribution with 20 degrees of freedom and a 99% confidence level (two-tailed), we find the t-value from Appendix D to be 2.861.
The 99% confidence interval for the population mean is:
lower bound = [tex]\bar{x}[/tex] - t*(s/√n) = 910 - 2.861*(80/√21) = 838.437
upper bound = [tex]\bar{x}[/tex] + t*(s/√n) = 910 + 2.861*(80/√21) = 981.563
Therefore, the 99% confidence interval is from 838.437 to 981.563.
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What is the area of the composite figure?
54 units2
152 units2
136 units2
160 units2
The area of the composite figure is 136 sq. units.
Given that a composite figure we need to find it area,
The figure is composed of a triangle and a rectangle,
So to find its area we will simply calculate the areas of both the polygons and add them,
So, the area of a triangle = 1/2 x base x height
The area of a rectangle = length x width
So,
The required area = 1/2 x (16-8)(13-7) + 7 x 16
= 1/2 x 8 x 6 + 112
= 24 + 112
= 136
Hence, the area of the composite figure is 136 sq. units.
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Given Z find |Z| please help
Answer:
|Z| = √((-6)^2 + 12^2) = √(36 + 144) = √180
= (√36)(√5) = 6√5
Which value of b satisfies both inequalities for b?
2b-8>5
3b 13 < 9
Use substitution to find the answer.
A. 5
B. 7
C. 8
D. 10
Since these inequalities contradict each other, there is no value of b that satisfies both.
We have,
Starting with the first inequality:
2b - 8 > 5
Adding 8 to both sides:
2b > 13
Dividing by 2:
b > 6.5
Moving on to the second inequality:
3b + 13 < 9
Subtracting 13 from both sides:
3b < -4
Dividing by 3:
b < -4/3
So, we need to find a value of b that satisfies both b > 6.5 and b < -4/3. Since these inequalities contradict each other, there is no value of b that satisfies both.
Therefore,
Since these inequalities contradict each other, there is no value of b that satisfies both.
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PLEASE HELP I WILL GIVE 40 POINTS!!!!!!!
a. For the supermarket manager, the mode is one that is the right tool as the appropriate form of the measure of central tendency as it would tell them which type of lettuce that was bought most often.
What is the central tendency about?b. For the students, the mean is one that will be the right measure of central tendency as it would give them the idea of the average of all their test scores.
c. For the real estate agent, the median is one that is be the right measure of central tendency as it would tell them the selling price that is in the middle of all the given comparable houses.
Lastly, The student that is known to be is reporting the mean as the average. , this is one that tends to misrepresents their course performance due to the fact that the mean is affected by outliers for example as the 75%, 70%, and 55% scores. The median is one that can give a better representation of their performance.
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See text below
1. Here are three examples where the mean, median, and mode can be used to describe a situation. Which measure of central tendency would you use for each one? Why? (Don't forget the why.)
a. A supermarket manager wants to know how many types of lettuce customers purchase most often.
b. Students want to know the average of all their test scores in a certain grading period.
c. A real estate agent wants to set the selling price of a three-bedroom house so that there are as many comparable houses above as below the price. 2. A student's parents promise to pay for next semester's tuition if an A average is earned in chemistry. With examination grades of 97%, 97%, 75%, 70%, and 55%, the student reports that an A average has been earned. Which measure of central tendency is the student reporting as the average? How is this student misrepresenting the course performance with statistics?
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I need help with this problem if do thank you a lot
Answer:
The equation of the circle is (x + 7)^2 + (y - 13)^2 = 25.
Step-by-step explanation:
The equation of a circle with a center (a,b) and radius r is given by:
(x - a)^2 + (y - b)^2 = r^2
So, for the center (-7, 13) and a radius of 5 units, the equation of the circle is: (x - (-7))^2 + (y - 13)^2 = 5^2
Simplifying this equation, we get:
(x + 7)^2 + (y - 13)^2 = 25
Therefore, the equation of the circle with center (-7,13) and radius 5 units is (x + 7)^2 + (y - 13)^2 = 25.
A factory worker can make 15 products in 45 minutes. What is the workers unit rate of completion?
Answer:
[tex]\frac{1}{3}[/tex] product per minute
Step-by-step explanation:
We Know
A factory worker can make 15 products in 45 minutes.
What is the worker's unit rate of completion?
We Take
15 / 45 = [tex]\frac{1}{3}[/tex] product per minute
So, the workers unit rate of completion is [tex]\frac{1}{3}[/tex] product per minute
i need help on this equation
[tex]{\Large \begin{array}{llll} \cfrac{x^{-\frac{1}{2}}}{x^{\frac{2}{3}}x^{\frac{3}{2}}}\implies \cfrac{1}{x^{\frac{2}{3}}x^{\frac{3}{2}}x^{\frac{1}{2}}}\implies \cfrac{1}{x^{\frac{2}{3}+\frac{3}{2}+\frac{1}{2}}}\implies \cfrac{1}{x^{\frac{2}{3}+2}}\implies \cfrac{1}{x^{\frac{8}{3}}} \end{array}}[/tex]
Need help will give brainliest and 5 stars for quick answers! I have 20 minutes to do this!
Answer:
Step-by-step explanation:
(n-2) x 180 = 1260
n-2 = 1260/180
n-2 = 7
n = 9
Therefore, the regular polygon has 9 sides.
what is the y value of the functionin the table when the x value is 0
Answer:
The y-value of the function is 4 in the table when the x-value is 0 after framing the linear equation.
Step-by-step explanation:
- Hope this helps
find the distance between 5,1 and 5,4
Answer:
3
Step-by-step explanation:
By using distance formula
√(x2-x1)^2+(y2-y1)^2
√(5-5)^2+(4-1^2
√0+(3)^2
√9
=3
Can someone help with these two questions on my Calc 3 hw? It is due tonight. Thank you!
Question #14:
Find the work done by the force field, [tex]\vec F(x,y,z)= < x-y^2, \ y-z^2, \ z-x^2 >[/tex],
on a particle that moves along the line segment from (0,0,1) to (3,1,0).
The parametrized form of a line is given as,
[tex]x=x_0+v_xt[/tex]
[tex]y=y_0+v_yt[/tex]
[tex]z=z_0+v_zt[/tex]
Where [tex](x_0,y_0,z_0)[/tex] is a point the line passes through and [tex]\vec v= < v_x,v_y,v_z >[/tex] is the direction of the line.
[tex]\Longrightarrow \vec v= < 3-0,1-0,0-1 > \Longrightarrow \boxed{ \vec v= < 3,1,-1 > }[/tex]
[tex]\Longrightarrow \boxed{(x_0,y_0,z_0)=(0,0,1)}[/tex]
[tex]z=-t+1, 0\leq t\leq 1[/tex]
This would imply that, [tex]dx=3dt,dy=dt,dz=-dt[/tex]
[tex]Work, W=\int\limits^a_b {\vec F(x,y,z) \cdot} < dx,dy,dz > \,dt[/tex]
[tex]\Longrightarrow \vec F(x,y,z)= < 3t-t^2, \ t-(-t+1)^2, \ -t+1-(3t)^2 >[/tex]
[tex]\Longrightarrow \boxed{\vec F(x,y,z)= < 3t-t^2, \ -t^2+3t-1, \ -9t^2-t+1 > }[/tex]
[tex]\Longrightarrow W=\int\limits^1_0 { [ < 3t-t^2, \ -t^2+3t-1, \ -9t^2-t+1 > \cdot} < 3,1,-1 > ] \,dt[/tex]
[tex]\Longrightarrow W=\int\limits^1_0 { [( 3t-t^2)(3)+(-t^2+3t-1)(1)+(-9t^2-t+1)(-1) ] \,dt[/tex]
[tex]\Longrightarrow W=\int\limits^1_0 { [ 9t-3t^2-t^2+3t-1+9t^2+t-1 ] \,dt[/tex]
[tex]\Longrightarrow W=\int\limits^1_0 { [5t^2+13t-2 ] \,dt[/tex]
Using the power rule to integrate: [tex]\frac{d}{dx}[x^n]=nx^{n-1}[/tex]
[tex]\Longrightarrow W=\frac{5}{3}t^3+\frac{13}{2}t^2-2t \left. \right|_{0}^1[/tex]
[tex]\Longrightarrow W=[\frac{5}{3}(1)^3+\frac{13}{2}(1)^2-2(1)]-[0][/tex]
[tex]\Longrightarrow W=\frac{5}{3}+\frac{13}{2}-2[/tex]
[tex]\Longrightarrow \boxed{ W=\frac{37}{6}} \therefore Sol.[/tex]
Question #15:
Given:
[tex]w_m=170 \ lb[/tex]
[tex]w_c=25 \ lb[/tex]
[tex]w_m+w_c=195 \ lbs[/tex]
[tex]r_s=25 \ ft[/tex]
[tex]h_s=90 \ ft[/tex]
[tex]1 \ rev. =2\pi \Rightarrow 3 \ rev. =\bold{6\pi}[/tex]
Find:
[tex]W= \ ?? \ ft-lbs[/tex]
Equation:
[tex]W=\int\ {\vec F \cdot } \, d\vec r \Longrightarrow W=\int\ {[\vec F(\vec r(t)) \cdot r'(t)}]dt[/tex]
[tex]\vec F(x,y,z)= < 0,0,195 > \ and \ r(t)= < 25cos(t),25sin(t),\frac{90}{6\pi}t >[/tex]
[tex]r'(t)= < -25sin(t),25cos(t),\frac{15}{\pi} >[/tex]
[tex]\Longrightarrow W=\int\ {[\vec F(\vec r(t)) \cdot r'(t)}]dt[/tex]
[tex]\Longrightarrow W=\int\ {[ < 0,0,195 > \cdot < -25sin(t),25cos(t),\frac{15}{\pi} > ]dt[/tex]
[tex]\Longrightarrow W=\int\ {[ (195)(\frac{15}{\pi}) ]dt[/tex]
[tex]\Longrightarrow W=\int\ {\frac{2925}{\pi} dt[/tex]
Limits: [tex]0\leq t\leq 6\pi[/tex]
[tex]\Longrightarrow W=\int\limits^{6\pi}_0 {\frac{2925}{\pi} } \, dt[/tex]
[tex]\Longrightarrow W= {\frac{2925}{\pi}t \left. \right|_{0}^{6\pi}[/tex]
[tex]\Longrightarrow W= [{\frac{2925}{\pi}(6\pi)]-[0][/tex]
[tex]\Longrightarrow \boxed{W= 17,550 \ ft-lbs} \therefore Sol.[/tex]
Let me know if these were correct! As I strive to give the most accurate answers! Thank you.
Classify the quadrilateral shown
A. Parallelogram
B. Rectangle
C. Rhombus
D. Square
Answer:
A. parallelogram
Step-by-step explanation:
It's not a rectangle because all 4 angles are not 90
It's not a rhombus because all 4 sides are not equal.
It's not a square because all 4 sides are not equal and all 4 angles are not 90.
It's a parallelogram because it's a quadrilateral with 2 pairs of opposite sides that are parallel.
If 35% of students went to Disneyland and 1924 of students went to Knotts what is the total number of students
The total number of students is 2960.
How to find the total number of student?35% of students went to Disneyland and 1924 of students went to Knotts.
Therefore, the total number of student can be calculated as follows:
The total number of student is the total number of student that went to Disneyland and Knotts.
let
x = total number of student
Therefore,
35% of x = Student that went to Disneyland
Hence,
65% of x = 1924
65 / 100 x = 1924
cross multiply
65x = 192400
divide both sides of the equation
x = 192400 / 65
x = 2960
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Barry took out a 20-year loan for $55,000 at an APR of 6,8%, compounded monthly, and he is making monthly payments of $ 419.84Assuming that his balance is $31,019.97 with 8 years left on the loan, how much would he save by paying off the loan 8 years early?
Answer: Barry would save approximately $15,208.08 by paying off the loan 8 years early.
Step-by-step explanation:
To calculate how much Barry would save by paying off the loan 8 years early, we first need to calculate the total amount of interest he would pay over the remaining 8 years.
We can use the formula for calculating the remaining balance on a loan:
Balance = (P * ((1 + r/n)^(nt)) - (A * (((1 + r/n)^(nt)) - 1)/(r/n)))
where:
P = principal amount (initial loan amount)
r = annual interest rate (in decimal form)
n = number of times interest is compounded per year
t = time (in years)
A = monthly payment
Substituting the given values in the formula, we can calculate the remaining balance:
Balance = ($55,000 * ((1 + 0.068/12)^(1220)) - ($419.84 * (((1 + 0.068/12)^(1220)) - 1)/(0.068/12)))
Balance = $31,019.97
Now, we need to calculate the total interest paid over the remaining 8 years. We can do this by subtracting the remaining balance from the total amount of interest that would be paid over the entire 20-year loan term:
Total interest paid over 20 years = (A * 12 * 20) - P
Total interest paid over 20 years = ($419.84 * 12 * 20) - $55,000 = $50,969.63
Total interest paid over the remaining 8 years = (A * 12 * 8) - Balance
Total interest paid over the remaining 8 years = ($419.84 * 12 * 8) - $31,019.97 = $35,761.58
Therefore, Barry would save approximately $15,208.08 by paying off the loan 8 years early.
Rocco wants to use the rest of the money in his savings account to buy a set of golf irons that has
an original price of $350 including tax. Does Rocco have enough money to buy the golf irons?
Explain your answer.
We get a negative number, which means that Rocco does not have enough money to make the purchase. In fact, he is short by $158.
What is equation?An equation is a mathematical statement that shows that two expressions are equal. Equations are used to represent relationships between variables and to solve problems in various fields such as mathematics, physics, engineering, and economics. In an equation, there are typically two sides separated by an equals sign (=). The expressions on each side of the equals sign may include variables, constants, mathematical operations, and functions. The goal of solving an equation is to find the value(s) of the variable(s) that make both sides of the equation equal.
Here,
If Rocco has only $192 in his savings account and the set of golf irons costs $350, then he does not have enough money to buy the golf irons.
To see why, we can subtract the price of the golf irons from Rocco's savings:
$192 (Rocco's savings) - $350 (price of golf irons) = -$158
Therefore, Rocco does not have enough money to buy the set of golf irons with the remaining amount in his savings account.
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A triangle is shown with its exterior angles. The interior angles of the triangle are angles 2, 3, 5. The exterior angle at angle 2 is angle 1. The exterior angle at angle 3 is angle 4. The exterior angle at angle 5 is angle 6. Which statements are always true regarding the diagram? Select three options. m∠5 + m∠3 = m∠4 m∠3 + m∠4 + m∠5 = 180° m∠5 + m∠6 =180° m∠2 + m∠3 = m∠6 m∠2 + m∠3 + m∠5 = 180°
A triangle is shown with its exterior angles and the interior angles of the triangle are angles 2, 3, 5. The true statements are m∠3 + m∠4 + m∠5 = 180°, m∠5 + m∠6 = 180°, and m∠2 + m∠3 = m∠6. The correct answers are B, C, and E.
We know that the sum of the measures of the interior angles of a triangle is always 180 degrees. We can use this fact, along with the properties of exterior angles of a triangle, to determine which statements are always true regarding
m∠5 + m∠3 = m∠4 This statement is not always true. It is only true in this case because angle 4 is an exterior angle at vertex 3, which means that m∠4 = m∠3 + m∠5. Therefore, m∠5 + m∠3 = m∠3 + m∠5, which simplifies to m∠5 = m∠5. However, in general, this statement is not always true.
m∠3 + m∠4 + m∠5 = 180° This statement is always true, because the sum of the measures of the three exterior angles of a triangle is always 360 degrees. Therefore, m∠3 + m∠4 + m∠5 = 360°, which simplifies to m∠3 + m∠4 + m∠5 = 180°.
m∠5 + m∠6 = 180° This statement is always true, because the sum of an exterior angle and its adjacent interior angle is always 180 degrees. Therefore, m∠5 + m∠6 = m∠1 (because angle 1 is an exterior angle at vertex 2), and m∠1 + m∠2 + m∠3 = 180° (because the sum of the measures of the interior angles of a triangle is 180 degrees). Therefore, m∠5 + m∠6 = m∠2 + m∠3, which is equal to 180° (because m∠2 + m∠3 = m∠1, and m∠5 + m∠6 = m∠1).
m∠2 + m∠3 = m∠6 This statement is not always true. It is only true in this case because angle 6 is an exterior angle at vertex 5, which means that m∠6 = m∠5 + m∠3. Therefore, m∠2 + m∠3 = m∠2 + m∠5 + m∠3, which simplifies to m∠2 + m∠3 = m∠5 + m∠3. Then, by subtracting m∠3 from both sides, we get m∠2 = m∠5. However, in general, this statement is not always true.
m∠2 + m∠3 + m∠5 = 180°: This statement is always true, because the sum of the measures of the interior angles of a triangle is always 180 degrees. Therefore, m∠2 + m∠3 + m∠5 = 180°.
Based on the above analysis, the statements that are always true regarding the diagram are
m∠3 + m∠4 + m∠5 = 180°
m∠5 + m∠6 = 180°
m∠2 + m∠3 + m∠5 = 180°
Therefore, the correct options are B, C, and E.
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A call center claims that the mean wait time for a customer to connect with a customer care executive is less than 2 minutes. A random sample of 50 calls at the call center yielded a test statistic of -1.07. What is the corresponding p-value? Round your answer to three decimal places.
The corresponding p-value is 0.147 rounded to three decimal places.
Now, For find the p-value, we need to use a t-distribution with (n - 1) degrees of freedom,
where n is the sample size.
Since n = 50,
Hence, we have;
n - 1 = 50 - 1 = 49 degrees of freedom.
Hence, Using a t-table or calculator with 49 degrees of freedom, we find that the p-value for a t-statistic of -1.07 is approximately 0.147.
Therefore, the corresponding p-value is 0.147 rounded to three decimal places.
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In your class, 10 out of 19 students have a job.
Task 1: Obtain a point estimate for the proportion of GSU students who have a job.
Task 2: What conditions must be met to create a confidence interval for the proportion of GSU students
who have a job? Are they met? (There are 5776 students enrolled at GSU).
Task 3: Regardless of your previous answer, create a 95% confidence interval for the proportion of GSU
students who have a job.
Task 4: Regardless of your previous answer, create a 99% confidence interval for the proportion of GSU
2
students who have a job.
Task 5: What sample size should be obtained if you want to be within 3 percentage points using your
estimate from the class data?
Task 6: What sample size should be obtained if you want to be within 3 percentage points using no prior
estimate
a) Point estimate = 10/19 = 0.526
b) The sample should be randomly selected from the population.
The sample size should be large enough such that both np and n(1-p) are greater than or equal to 10, where n is the sample size and p is the proportion of students who have a job in the population.
The sampling distribution of the sample proportion should be approximately normal.
c) confidence interval = (0.259, 0.793)
d) confidence interval = (0.176, 0.876)
e) n = 365 students
Given data ,
a)
The point estimate for the proportion of GSU students who have a job is simply the proportion of students in the class who have a job, which is:
point estimate = 10/19 = 0.526 (rounded to three decimal places)
b)
To create a confidence interval for the proportion of GSU students who have a job, the following conditions must be met:
The sample should be randomly selected from the population.
The sample size should be large enough such that both np and n(1-p) are greater than or equal to 10, where n is the sample size and p is the proportion of students who have a job in the population.
The sampling distribution of the sample proportion should be approximately normal.
c)
Assuming the conditions for a confidence interval are met, a 95% confidence interval for the proportion of GSU students who have a job can be calculated as follows:
margin of error = z√(p(1-p)/n)
where z is the z-score corresponding to a 95% confidence level (z = 1.96), p is the point estimate of the population proportion (0.526), and n is the sample size (19).
margin of error = 1.96 √(0.5260.474/19) = 0.267 (rounded to three decimal places)
confidence interval = point estimate ± margin of error = 0.526 ± 0.267
confidence interval = (0.259, 0.793)
Therefore, we can say with 95% confidence that the true proportion of GSU students who have a job is between 0.259 and 0.793.
d)
A 99% confidence interval for the proportion of GSU students who have a job can be calculated using the same formula as above, but with a z-score of 2.576 (corresponding to a 99% confidence level):
margin of error = 2.576sqrt(0.5260.474/19) = 0.350 (rounded to three decimal places)
confidence interval = 0.526 ± 0.350
confidence interval = (0.176, 0.876)
Therefore, we can say with 99% confidence that the true proportion of GSU students who have a job is between 0.176 and 0.876.
e)
To determine the sample size needed to be within 3 percentage points of the true proportion with the point estimate of 0.526, we can use the formula:
n = (z² * p * (1-p)) / E²
where z is the z-score corresponding to the desired confidence level (z = 1.96 for a 95% confidence level), p is the point estimate of the population proportion (0.526), and E is the desired margin of error (0.03).
n = (1.96^2 * 0.526 * 0.474) / 0.03^2
n = 364.16
Hence , we would need a sample size of at least 365 students to be within 3 percentage points of the true proportion using the point estimate from the class data.
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The area of rectangle rug is 60 square yards. If the width of the rug is 10 yards what is the length of the rug
Answer:
6
Step-by-step explanation:
60/10=6
Hope this helps :)
The table below shows the spot rates for the given lengths of time. Numbers 4 5 6 of years Effective 2.5% 3.1% 3.4% 3.6% 4% 4.2% annual spot ratee Calculate the swap rate for a two- year deferred, three- year interest rate swap with settlement at the end of the year. [10]
The swap rate for a two-year deferred, three-yearinterest rate swap with settlement at the end of the year is 3.7%
How to calculate the rateImplied forward rate = (1+Present year rate)^Present year /(1+Previous year rate)^Previous year -1
The swap rate for a two-year deferred, three-yearinterest rate swap with settlement at the end of the year=
= [(1 +0.034)2 / (1+0.031)1 ] -1
= [1.069156 / 1.031] -1
= 1.037 - 1
= 0.037
= 3.7%
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tally's teacher divides her class of 16 students into 4 equally sized teams red team yellow team green team and blue team what is the probability that tally will be on the red team answerd in simplified form
Tally's probability of being on the red team is 1/4, or 0.25 when represented as a decimal.
How to determine the probability that tally will be on the red teamEach team has four students because there are four equal-sized teams.
So Tally's chances of being on the red team are 4 (the number of students on the red team) divided by 16 (the total number of students):
4/16 = 1/4
As a result, Tally's likelihood of being on the red team is 1/4, or 0.25 when represented as a decimal.
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Which is the value of this expression when j=-2 and k=-1 (jk^-2/j^-1k^-3)^3
The value of the expression when j=-2 and k=-1 is 8.
What is expression?A mathematical expression is a phrase that has a minimum of two numbers or variables and at least one mathematical operation. Let's examine the writing of expressions.
Let's substitute j=-2 and k=-1 in the given expression and simplify it:
(jk⁻²/j⁻¹k⁻³)³
= ((-2)(-1)⁻²)/((-2)⁻¹(-1)⁻³))³ // Substitute j=-2 and k=-1
= ((-2)/(1/(-1)²))/((-1/(-1)³)))³
= ((-2)/1)/(-1/1))³
= (-2)/(-1))³
= 8
Therefore, the value of the expression when j=-2 and k=-1 is 8.
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Kellen runs for at least 1 hour but for no more than 2 hours. He runs at at an average rate of 6.6 kilometers per hour. The equation that models the distance he runs for t hours is d=6.6t. Find the theoretical and practical domains of this equation.
Kellen runs for at least 1 hour but for no more than 2 hours. He runs at at an average rate of 6.6 kilometers per hour. The equation that models the distance he runs for t hours is d = 6. 6t
Find the theoretical and practical ranges of this equation.
The equation's usable range is 6.6 km d 13.2 km.
What is an expression?Expression is the relation of the numbers and the variables written by the use of mathematical signs.
Kellen exercises for a minimum of an hour and a maximum of two hours. As a result, the equation's useful domain is 1 t 2. Since that time can take on any positive or negative value, the theoretical scope of the equation d = 6.6t is all real numbers.
Substitute the values of the practical domain into the equation.
t = 1, d = 6.6(1) = 6.6 km.
t = 2, d = 6.6(2) = 13.2 km.
Therefore, the equation's usable range is 6.6 km d 13.2 km.
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solve substituted methode
[tex]2x - 24 = 4 \\ 3x + 44 = 8[/tex]
Associative property is not followed by which type of numbers?
Associative property holds for all types of numbers and associative properties holds true addition as well as multiplication but not true for subtraction as well as division.
What is Number system?A number system is defined as a system of writing to express numbers.
The associative property holds for all types of numbers including real numbers, complex numbers, integers, fractions, and even irrational numbers.
There is no type of number for which the associative property does not hold.
associative properties holds true addition as well as multiplication but not true for subtraction as well as division.
Hence, associative property holds for all types of numbers and associative properties holds true addition as well as multiplication but not true for subtraction as well as division.
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747.748 + 848.398 + 8,327.82 =
Answer:
Answer: 9,924.966.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Sorry it is hard to explain the process by typing!
please help me find the area!! please
You can rent a car from company a for $40 plus $50 per Day write an expression to find the cost of a car per day, D
Using the interactive tool, select the Market Research data and request a sample size of 41. Request a plot of the Age variable. a. With Overall Mean selected, what is the length of the first dotted line shown at the top of the chart? (Hint: Use the Show Data button in the calculations window.) (Report two decimal places. Do not include a negative sign.)
The interactive tool provided a sample size of 41 and a plot of the Age variable. The three dotted lines shown at the top of the chart had lengths of 23.39, 23.28, and 24.17 respectively.
What is length?Length is a concept used to describe the magnitude of a particular object or distance between two points. It is typically measured in units such as feet, inches, meters, miles, and kilometers. Length is often used to describe the size of an object and the distance between two points. Length can also be used to measure the time required to travel between two points. Length is a fundamental concept in mathematics, physics, and engineering.
The first dotted line shown at the top of the chart is 23.39.
b. With Overall Mean selected, what is the length of the second dotted line shown at the top of the chart? (Hint: Use the Show Data button in the calculations window.) (Report two decimal places. Do not include a negative sign.)
The second dotted line shown at the top of the chart is 23.28.
c. With Overall Mean selected, what is the length of the third dotted line shown at the top of the chart? (Hint: Use the Show Data button in the calculations window.) (Report two decimal places. Do not include a negative sign.)
The third dotted line shown at the top of the chart is 24.17.
Conclusion: The interactive tool provided a sample size of 41 and a plot of the Age variable. The three dotted lines shown at the top of the chart had lengths of 23.39, 23.28, and 24.17 respectively. This data can be used to analyze the age of respondents in Market Research.
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