SOLVE THE FOLLOWING PROBLEMS.
A) IN HOW MANY WAYS CAN THE LETTERS OF THE WORD “TRACK” BE ARRANGED?
B) A STUDENT MUST SELECT AND ANSWER SIX OUT OF TEN QUESTIONS ON AN EXAM. IN HOW MANY WAYS CAN THIS BE DONE?
C) A TEACHER DECIDES TO GIVE SIX IDENTICAL PRIZES TO 6 OF THE 20 STUDENTS IN HIS CLASS. IN HOW MANY WAYS CAN THIS BE DONE

By solving a linear equation, we conclude that you bought 4 buns and 5 cakes.

We will define the two variables:

We know that you spent exactly £4.35, then we only need to solve the linear equation:

x*0.40 + y*0.55 = 4.35

We need to solve that equation for x and y, such that the values of x and y can only be positive whole numbers.

We can rewrite the equation as:

y*0.55 = 4.35 - x*0.40

y = (4.35 - x*0.40)/0.55

Now we only need to evaluate it in different values of x, and see for which value of x, the outcome y is also a whole number.

We will see that for x = 4, we have:

y = (4.35 - 4*0.40)/0.55 = 5

So you bought 4 buns and 5 cakes.

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40p + 55p = 95p

435p ÷ 95p = 4.57...

So, the sum of the two pairs can go into £4.35 four times.

That meant if I increase the buns & cakes four times, it will help me get closer to the sum of £4.35 & work out which was extra

(40 x 4 = 160) & (55 x 4 = 220)

160 + 220= 380p or £3.80

Adding them up I get 380 pence & that's 55p short to getting to the sum of 435p or £4.35

(435-380=55p)

Thus, the extra is the cake, meaning you bought 4 buns and 5 cakes.

Hope this helps!

Step-by-step explanation:

Completing the square is a method that is used for converting a quadratic expression of the form ax² + bx + c to the vertex form a(x - h)² + k. The most common application of completing the square is in solving a quadratic equation.

Completing the Square is a technique which can be used to find maximum or minimum values of quadratic functions. We can also use this technique to change or simplify the form of algebraic expressions. We can use it for solving quadratic equations.

[tex]x {}^{2} + 6 = - 2 \\ x {}^{2} + 6x + 9 = 7 \\ (x + 3) {}^{2} = 7[/tex]

Answer:

233.35488 km (Rounded to 233 km)

Step-by-step explanation:

If you convert miles to kilometers then you would use this conversion factor:

1 mile = 1.609344 km (or 1.61 km)

so in this case,

145 mile = 1.609344 km x 145

145 mile = 233.35488 km

I could also round it to 233 km.

Since your on a trip... i hope u enjoy ur journey to Las Vegas!

One second later, the distance between the two stones will change in a speed of 6.86 m/s

Distance can be defined as the length of change of position. When an object change from one position to another, the length between the points or position is known as distance.

If a dropped stone has a distance d = 4.9t²

Let us assumed that the time taken = 3 seconds

The distance d = 4.9 × 3² = 44.1 m

If another stone is dropped one second later, then the time t = 4 s

The distance = 4.9 × 4² = 78.4 m

One second later, the time = 5 seconds

The speed of change in distance = ( 78.4 - 44.1 )/ 5

The speed of change in distance = 34.3 / 5

The speed of change in distance = 6.86 m/s

Therefore, one second later, the distance between the two stones will change in 6.86 m/s

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Answer:

17

Step-by-step explanation:

i think its the right answer

Using it's concept, the integer numbers in the data-set are given as follows:

6/1, -14, 56/7.

The other numbers, -74.48 and 3/17, are not integers.

Integer numbers are numbers that have no decimal part. They can be represented by pure numbers, either negative or positive, or also fractions that result in an exact division.

In this problem, we have that:

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the coordinates of the vertices of D2(WXYZ) are;

W' ( 2, 3)

X' ( 3, -1)

Y' ( -2, -2)

Z'(−1, −2)

It is important to note that the general formula for finding the transformation of the coordinates is;

M ( h, k) = M' ( k, -h)

Where

For the quadrilateral WXYZ we have to find the transformed coordinates

For W, we have

W(−3, 2)

h = -3

k = 2

Substitute the values

W' ( 2, 3)

For X,

X(1, 3)

h = 1

k = 3

Substitute the values

X' ( 3, -1)

For Y

Y(2, −2)

h = 2

k = -2

Substitute the values

Y' ( -2, -2)

For Z

Z(−1, −2)

h = -1

k = -2

Z'(−1, −2)

Thus, the coordinates of the vertices of D2(WXYZ) are;

W' ( 2, 3)

X' ( 3, -1)

Y' ( -2, -2)

Z'(−1, −2)

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Answer:

[tex]x^{2}+\frac{1}{2} x + \frac{33}{16}= 2 + (x + \frac{1}{4})^2[/tex]

Step-by-step explanation:

[tex]x^{2}+\frac{1}{2} x=x^{2}+2 \times \frac{1}{4} \times x +(\frac{1}{4})^2 - (\frac{1}{4})^2[/tex]

[tex]=[x^{2}+2 \times \frac{1}{4} \times x +(\frac{1}{4})^2] - (\frac{1}{16})[/tex]

[tex]=[x + \frac{1}{4}]^2 - (\frac{1}{16})[/tex]

____________________

then

[tex]x^{2}+\frac{1}{2} x = [x + \frac{1}{4}]^2 - (\frac{1}{16}) -2 + 2[/tex]

then

[tex]x^{2}+\frac{1}{2} x = [(x + \frac{1}{4})^2 - (\frac{1}{16}) -2] + 2[/tex]

then

[tex]x^{2}+\frac{1}{2} x = [(x + \frac{1}{4})^2 - (\frac{33}{16}) ] + 2[/tex]

then

[tex]x^{2}+\frac{1}{2} x = (x + \frac{1}{4})^2 - \frac{33}{16} + 2[/tex]

then

[tex]x^{2}+\frac{1}{2} x + \frac{33}{16}= (x + \frac{1}{4})^2 + 2[/tex]

then

[tex]x^{2}+\frac{1}{2} x + \frac{33}{16}= 2 + (x + \frac{1}{4})^2[/tex]

Based on the calculations, the coordinates of the point of congruency of the altitudes (H) are (-160/11, 40/11).

A triangle can be defined as a two-dimensional geometric shape that comprises three (3) sides, three (3) vertices and three (3) angles only.

A slope is also referred to as gradient and it's typically used to describe both the ratio, direction and steepness of the function of a straight line.

Mathematically, the slope of a straight line can be calculated by using this formula;

[tex]Slope, m = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope, m = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}[/tex]

Assuming the following parameters for triangle ABC:

For the slope of BC, we have:

Slope of BC = (2 - 8)/(4 - 0)

Slope of BC = -6/4

Slope of BC = -3/2.

For the slope of CA, we have:

Slope of CA = (2 - 0)/(4 - (-2))

Slope of CA = 2/6

Slope of CA = 1/3.

For the slope of AB, we have:

Slope of AB = (8 - 0)/(0 - (-2))

Slope of AB = 8/2

Slope of AB = 4.

Note: The point of concurrency of three altitudes in a triangle is referred to as orthocenter.

Since side AB is perpendicular to side QC, we have:

m₁ × m₂ = -1

Slope of AB × Slope of QC = -1

Slope of QC = (k - 4)/(h - 2)

4 × (k - 4)/(h - 2) = -1

(4k - 16)/(h - 2) = -1

4k - 16 = -h + 2

4k + h = 18    .......equation 1.

Similarly, we have the following:

Slope of BC × Slope of AH = -1

-3/2 × (k)/(h + 2) = -1

3k/(2h + 4) = 1

3k = 2h + 4

3k - 2h = 4     .......equation 2.

Solving eqn. 1 and eqn. 2 simultaneously, we have:

8k + 2h = 36

3k - 2h = 4

11k = 40

k = 40/11.

For the value of h, we have:

h = -4k

h = -4 × (40/11)

h = -160/11

Therefore, the coordinates of the point of congruency of the altitudes (H) are (-160/11, 40/11).

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Answer:

x = -7

x = 5

Step-by-step explanation:

The standard form of quadratic equations is

Ax^2 + Bx + C = 0

The factors need to multiply together to be C and add together to be B.

The two numbers that will multiply together to be -35 and add together to be 2 are -5 & 7.

The factor pairs are (x+7)(x-5). Zero product property means we set each of those factor pairs = 0 and solve.

x + 7 = 0

-7 -7 Subtract 7 from each side to solve

x = -7

x - 5 = 0

+5 +5 Add 5 to each side to solve

x = 5

To solve the equation, factor x²+2x−35 use the formula x² +(a + b) x + ab = (x + a)(x + b). To find a and b, set up a system to be solved.

a + b = 2

ab = −35

Since ab is negative, a and b have opposite signs. Since a+b is positive, the positive number has a greater absolute value than the negative. Show all pairs of integers whose product is −35.

Calculate the sum of each pair.

The solution is the pair that gives sum 2.

Rewrite the factored expression (x + a)(x + b) with the values obtained.

To find solutions to equations, solve x−5=0 and x+7=0.

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[tex]y = \frac{ - 1}{4} x + \frac{1}{2} [/tex]

Answer: [tex]a_n=12(-\frac{1}{2})^{n-1}[/tex]

Step-by-step explanation:

Let's first find the common ratio this sequence. To get to the next term, we divide by 2 and we alternate signs. Hence, the common ratio is [tex]-\frac{1}{2}[/tex].

We can now use the formula [tex]a_n=a_1(r)^{n-1}[/tex] to get the formula, where [tex]a_1[/tex] is the first term and r is the common ratio.

[tex]a_n=a_1(r)^{n-1}\\a_n=12(-\frac{1}{2})^{n-1}[/tex]

The 7th term of an Arithmetic Progression 50+45+40 is 20

The Arithmetic Progression is given as:

50+45+40

In the above Arithmetic Progression, we have

First term, a= 50

Common difference, d = 45 - 50 = -5

The nth term of the Arithmetic Progression is calculated as:

Tn = a + (n - 1)d

Substitute the known values in the above equation

Tn = 50 + (n - 1) * -5

Substitute 7 for n in the above equation

Tn = 50 + (7 - 1) * -5

Evaluate the product

Tn = 50 - 30

Evaluate the difference

T7 = 20

Hence, the 7th term of an Arithmetic Progression 50+45+40 is 20

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Answer:

8.5 years

Step-by-step explanation:

It will take 102 more payments

8.5 years

Interest will be $26,239

It would take approximately 15 years to pay back the loan of 95000 which is compounding monthly and the rate of interest is 6%.

Compound interest is basically the interest which is calculated on the primcipal with addition to aggregate interest. The formula of sum after compounding is as under:

S=P[tex](1+r/n)^{nt}[/tex] in which P is principal amount, r is rate per annum, n is number of times of compounding and t is time period.

We have been given that the amount of loan is $95000, installment is $1200 , rate of interest is 6% and it is compounded monthly.

First of all we have to find the effective rate=6%/12=0.005.

The future value of 95000 at a rate of 6% compunded monthly should be equal to the amount of all installments. So,

95000[tex](1+0.005)^{12n}[/tex]=12*1200*n

95000[tex]1.005^{12n}[/tex]=14400n

[tex]1.005^{12n}[/tex]=14400n/95000

[tex]1.005^{12n}[/tex]=0.1515n

We have to make graph of this to find the value of n which after graphing will come approx 15.

Hence it would take 15 years to pay back loan amount.

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The number of strings that can be formed by ordering the letters SCHOOL using some or all of the letters is 1440 strings

Permutation can be defined as number of ways in which things can arranged.

We were given to find how many strings that can be formed by ordering the letters SCHOOL using some or all of the letters.

First of all, How many distinct letters are in the word SCHOOL ?

The distinct letters are 5 in numbers.

What is the total number of letters in the word SCHOOL ?

The total number of letters is 6.

Then

6! + 5[tex]P_{5}[/tex]

That is, 6 factorial + 6 permutation 5

( 6 x 5 x 4 x 3 x 2 x 1 ) + 6!/( 6 - 5)!

720 + 720

1440 strings

Therefore, the number of strings that can be formed by ordering the letters SCHOOL using some or all of the letters is 1440 strings

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The surface area of the balloon is 249 in².

A balloon has the shape of a sphere. The distance round the sphere is equal to the circumference of the sphere.

Circumference of the sphere = 2πr

Where:

Radius - circumference / 2π

28 / ( 2 x 22/7) = 4.45 inches

Surface area of a sphere = 4πr²

4 x 22/7 x 4.45² = 249 in²

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The probability that the project will be completed before the graduation time is 0.6873.

It should be noted that probability simply means the likelihood of the occurence of an event.

From the table attached, it can be seen that the probability that the project will be completed before the graduation time is 0.6873.

Also, the probability that the project will be completed before the end of week 15 will be 0.3983.

Lastly, the probability that the project will be completed before the end of week 13 will be 0.0203.

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The length of the arc of the circle is 3.67 meters

The arc of a circle is a part of the circumference that makes up the circle

From the question, we have the following parameters

Diameter, d = 14 meters

Central angle = π/6 radians

Start by calculating the radius of the circle using

Radius, r = Diameter/2

This is so because radius is half the diameter

So, we have

r = 14 meters/2

Evaluate the quotient of 14 meters and 2

r = 7 meters

The length of the arc of the circle is then calculated using

L = Radius * Central angle

Substitute known values in the above equation

L = 7 meters * π/6

Evaluate the product of 7 and π/6

L = 3.67 meters

Hence, the length of the arc of the circle is 3.67 meters

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Answer:

C. 8√3

Step-by-step explanation:

* = multiply or times

To find √192 in its simplest form we need to divide it by a square number like 64.

192/64 = 3

√192 = √64 * √3 = 8√3

The false statement is given by:

c. If b×b=c, then c is even integer.

Hence, since b is odd, b x b = c is odd, hence statement c is false.

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The equation for the horizontal asymptote will be y = -2.

Since the degree of the numerator and denominator of f(x) is the same both being 1, therefore horizontal asymptote exists and is given by:

y = Leading coefficient of numerator of f(x) / Leading coefficient of denominator of f(x)

= y = -2/1

= y = -2

The vertical asymptote will be f(x) = -2x / (x + 3). To find the vertical asymptote we will equate the denominator of f(x) = 0

= x + 3 = 0

= x = -3

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Answer:

339

Step-by-step explanation:

Since the cost of the renovation or overhauling of the existing line would be recovered in Year 4 and the NPV of the new production line is $-360,000, Crane Manufacturing should renovate.

Renovation restores an old asset to a better state.  Replacement rids the old in preference for a new asset.

When the two investment options are weighed, a better choice can be arrived at.

Year 1 = $93,324 ($280,000 x 33.33%)

Year 2 = $124,460 ($280,000 x 44.45%)

Year 3 = $41,468 ($280,000 x 14.81%)

Year 4 = $20,748  ($280,000 x 7.41%)

Total cost = $280,000

NPV of new production line = $-360,000

Thus, based on the cost recovery of the old production line and the negative NPV of the new production line, Crane Manufacturing should renovate.

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Should Crane replace or renovate the existing line?

The solution to the following equations is given below;

y - 6 = 12

y = 12 + 6

y = 18

-5 + k = 1

k = 1 + 5

k = 6

-2g = -14

g = -14/-2

g = 7

y - 4 = 12

y = 12 + 4

y = 16

12 + u = -12

u = -12 - 12

u = -24

f - 7 = 10

f = 10 + 7

f = 17

8t = 42

t = 42/8

t = 5.25

-9 + z = 18

z = 18 + 9

z = 27

7 + w = 14

w = 14 - 7

w = 7

13 - 5 = 12

8 ≠ 12

D - 2 = -10

D = -10 + 2

D = -8

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Answer:

12km/h

Step-by-step explanation:

s=d/t

900m is 0.9km and 4min and 30sec is 0.075h

0.9/0.075=12 which gives us 12km/h

Answer:

Step-by-step explanation:

4 min 30 seconds = 270 seconds

900m = 270 seconds

100m = 30 seconds

1000m= 300 seconds (5min)

12,000m=3600seconds (60min)

Answer = 12km/h

Answer:

Step-by-step explanation:

Let r(y)=x.

[tex]x=\frac{2}{3}(4y-5)\\\\\frac{3}[2}x=4y-5\\\\\frac{3}{2}x+5=4y\\\\y=\frac{3}{8}x+\frac{5}{4}\\\\r^{-1}(x)=\frac{3}{8}x+\frac{5}{4}[/tex]

Answer:

-

-

+

+

Step-by-step explanation:

The number of license plates is 11232000

The given parameters are:

Characters = 6 i.e. 3 letters and 3 digits

Letters = 3 different letters

Digits = 3 different digits

There are 10 different digits and 26 different letters.

Since each character is different from the other, then we have:

Digits = 10, 9 and 8

Characters = 26, 25 and 24

The number of license plates is then calculated as:

n = 10 * 9 * 8 * 26 * 25 * 24

Evaluate the product

n = 11232000

Hence, the number of license plates is 11232000

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