Answer:
[0.25, 2]
Step-by-step explanation:
We have
4t² ≤ 9t-2
subtract 9t-2 from both sides to make this a quadratic
4t²-9t+2 ≤ 0
To solve this, we can solve for 4t²-9t+2=0 and do some guess and check to find which values result in the function being less than 0.
4t²-9t+2=0
We can see that -8 and -1 add up to -9, the coefficient of t, and 4 (the coefficient of t²) and 2 multiply to 8, which is also equal to -8 * -1. Therefore, we can write this as
4t²-8t-t+2=0
4t(t-2)-1(t-2)=0
(4t-1)(t-2)=0
Our zeros are thus t=2 and t = 1/4. Using these zeros, we can set up three zones: t < 1/4, 1/4<t<2, and t>2. We can take one random value from each of these zones and see if it fits the criteria of
4t²-9t+2 ≤ 0
For t<1/4, we can plug in 0. 4(0)²-9(0) + 2 = 2 >0 , so this is not correct
For 1/4<t<2, we can plug 1 in. 4(1)²-9(1) +2 = -3 <0, so this is correct
For t > 2, we can plug 5 in. 4(5)²-9(5) + 2 = 57 > 0, so this is not correct.
Therefore, for 4t^2 ≤ 9t-2 , which can also be written as 4t²-9t+2 ≤ 0, when t is between 1/4 and 2, the inequality is correct. Furthermore, as the sides are equal when t= 1/4 and t=2, this can be written as [0.25, 2]
At a hockey game, a vender sold a combined total of 228 sodas and hot dogs. The number of sodas sold was two times the number of hot dogs sold. Find the number of sodas and the number of hot dogs sold.
9514 1404 393
Answer:
152 sodas76 hot dogsStep-by-step explanation:
Of the items sold, sodas were 2/(2+1) = 2/3 of the total.
(2/3)(228) = 152 . . . sodas were sold
152/2 = 76 . . . . hot dogs were sold
A field book is a private notepad used by a surveyor to transcribe notes and is not considered a legal document True False
Answer:
False
Step-by-step explanation:
A field book is a private notepad used by a surveyor to record measurements and notes.
Basically, the size of a field book is 200 millimeters × 120 millimeters (20 centimeters × 12 centimeters) and it's typically opened lengthwise. There are two (2) main types of field book and these includes;
I. Double-line field book.
II. Single-line field book.
As a general rule, it's best that all findings, entries (notes) and observations are recorded or made into a field book after each and every measurement have been taken by a surveyor.
In conclusion, a field book is considered to be a legal document used by surveyors to keep records of accomplished field work or work done in the field. Thus, it's not a private notepad used by a surveyor to transcribe notes.
Answer:
False
Step-by-step explanation:
A field book is a private notepad used by a surveyor to transcribe notes and is not considered a legal document is False.
Figure A
Figure B
Figure C
3 ft
3 ft
Sf
3 ft
3 ft
5 ft
5 ft
3 ft
3 ft
Sft
3 ft
3 ft
Х
?.
None of the figures
(a) Which figures are rectangles?
Mark all that apply.
Figure A Figure B Figure C
(b) Which figures are squares?
Mark all that apply.
Figure A Figure B Figure C
(c) Which figures are parallelograms?
Mark all that apply.
Figure A
Figure B
Figure C
None of the figures
None of the figures
Answer:
a) Figure B and Figure C
b) Figure C
c) Figure A, Figure B, and Figure C
Step-by-step explanation:
a) Rectangles are shapes that have four sides, and four right angels. Right angles are angles that are 90 degrees.
The only shapes with four sides AND four right angles are Figure C and Figure B.
b) Squares are shapes with four EQUAL sides and four right angles. The only shape with four equal sides and four right angles is Figure C.
c) Parallelograms are any shapes with four sides. All of these shapes have four sides.
Hope this helps!
please i meed help!!! im stuck and cant concentrate
Total outcomes=6 i.e{1,2,3,4,5,6 }
No.of favourable outcomes = 3 i.e {I, 3,5}
P(odd)=3/6=1/2
Answer:
1/ 2
Step-by-step explanation:
[tex]probability \: of \:an \:event\: = \frac{number \: of \: favorable outcomes}{total \: number \: of \: outcomes} [/tex]
favorable outcomes = odd numbers
=1, 3, 5
number of favorable outcomes = 3
total outcomes
= 1, 2, 3, 4, 5, 6
total number of outcomes = 6
probability = 3/ 6
= 1/ 2
1.6000×6+787838837÷748+783998-8387=
2.45000÷45×463×6377+6388-894=
Determine which of the following equations are linear equations in x
A party supply company makes cone shaped party hats for children using thin cardboard. To the nearest square centimeter, how much cardboard is required to make the party hate use pie = 3.14.
Answer:
A. 754 cm²
Step-by-step explanation:
Amount of cardboard needed = surface area of the cone
Curved surface area of the cone = πrl
Where,
π = 3.14
r = ½(20) = 10 cm
l = 24 cm
Plug in the values into the formula
Curved surface area = 3.14 × 10 × 24 = 753.6 ≈ 754 cm²
One number is 1/4 of another number. The sum of the two numbers is 5. Find the two numbers. Use a comma to separate your answer
Answer: 1, 4
Step-by-step explanation:
Number #1 = xNumber #2 = [tex]\frac{1}{4} x[/tex][tex]\frac{1}{4} x+x=5\\\\\frac{1}{4} x+\frac{4}{4} x=5\\\\\frac{5}{4} x=5\\\\5x=4*5\\5x=20\\x=4[/tex]
Number #1 = x = 4Number #2 = [tex]\frac{1}{4} x[/tex] = [tex]\frac{1}{4} *4=\frac{4}{4} =1[/tex]What is the meaning proportion between 3 and 27?
Answer:
you mean the mean not the meaning right?
The mean proportional of 3 and 27 = +√3×27 = +√81 = 9.
Find two positive numbers whose difference is 3 and whose product is 1638.
Answer:
42 and 39
Step-by-step explanation:
The best method in my opinion is to guess and check. So, you would start off by dividing 1638 by any number you see fit (I started with 34), and keep increasing or decreasing until you get whole numbers that are three integers apart. I understand that this is a little tedious but I'm not aware of a better solution as of right now, so that's the best that I've got! Please let me know if you need more help and I will be happy to help!
Can someone help please ??
Answer:
x=40
Step-by-step explanation:
In the picture, it seems that angles BHC, CHD, and DHE form a line, 180 degrees. So to solve, set up an equation:
[tex](2x+5)+55+40=180[/tex]
Take off the parentheses and solve.
Subtract 5, 55 and 40 from both sides, or add them together, then subtract.
5+55+40=100
You get:
[tex]2x=80[/tex]
Divide both sides by 2
You get:
[tex][x=40][/tex]I hope this helps!
Four cups of pure water are added to a 20-cup bowl of punch that is 75% juice. What percentage of the new punch is juice?
Amount of Juice
15
0
Amount of Punch
20
4
27%
37.5%
62.5%
75%
Answer:
62.5%
Step-by-step explanation:
Given that :
20 cup bowl of punch = 75% Juice
We can infer that :
The number of cups of JUICE is :
75% * 20 = 0.75 * 20 = 15 cups
Adding 4 cups of water to the 20 cups, we have = 24 cups
With 15 cups of JUICE ;
The percentage of the new punch that is juice will be x
x% of 24 cups = 15 cups
x/100 * 24 = 15
0.01x * 24 = 15
0.24x = 15
x = 15 / 0.24
x = 62.5
x = 62.5%
Answer:
It's C
62.5% btw
Step-by-step explanation:
Did the quiz lol
what is the value of x?
what is the value of y?
type in an integer or decimal
9514 1404 393
Answer:
x = 5.6y = 65Step-by-step explanation:
There are a couple of relations that are applicable to these questions.
the product of segment lengths of crossed chords is the same for both chordsthe angle formed at crossed chords is the average of the intercepted arc measures__
The segment lengths relation tells us ...
10x = 8×7 . . . . . . products of segment lengths are equal
x = 56/10 = 5.6 . . . . divide by 10
__
The value of y° is the average of the intercepted arcs:
y° = (85° +45°)/2 = 65°
_____
Additional comment
This diagram does not have enough information to allow computation of z. We would need to know the intercepted arc, or the length of the secant that meets tangent z.
A sports company has the following production function for a certain product, where p is the number of units produced with x units of labor and y units of capital.
p(x,y)=2500x1/5y1/5
Find:
1. Number of units produced with 26 units of labor and 1333 units of capital.
2. Marginal productivities.
3. Evaluate the marginal productivities at x=25, and y=1333
Answer:
(a) 20226 units
(b) Marginal productivities
[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]
[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex]
(c) Evaluation of the marginal productivities
[tex]P_x =803[/tex]
[tex]P_y = 15[/tex]
Step-by-step explanation:
Given
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex]
Solving (a): P(x,y) when x = 26 and y = 1333
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes
[tex]P(26,1333) = 2500*26^\frac{1}{5}*1333^\frac{1}{5}[/tex]
[tex]P(26,1333) = 20226[/tex] --- approximated
Solving (b): The marginal productivities
To do this, we simply calculate Px and Py
Differentiate x to give Px, so we have:
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes
[tex]P_x =2500 * x^{\frac{1}{5}-1} & y^\frac{1}{5}[/tex]
[tex]P_x =2500 * x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]
[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]
Differentiate y to give Py, so we have:
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes
[tex]P_y =2500 * x^\frac{1}{5} & y^{\frac{1}{5}-1}[/tex]
[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex]
Solving (c): Px and Py when x = 25 and y = 1333
[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex] becomes
[tex]P_x =2500 * 25^{-\frac{4}{5}} * 1333^\frac{1}{5}[/tex]
[tex]P_x =803[/tex] --- approximated
[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex] becomes
[tex]P_y =2500 * 25^\frac{1}{5} * 1333^\frac{-4}{5}[/tex]
[tex]P_y = 15[/tex]
Which function has least rate of change?
O y = 4x + 5
O 3x - y = 9
O x + y = 8
0 4x + 2y = 8
Answer:
O 4x+2y=8.
Hope this helps you
Which of these tables represents a function
Answer:
W and X
Y and Z arent functions because some of their domains (x value) have different inputs. Each domain can only have one input.
Solve the following differential equations using classical methods. Assume zero initial conditions.
a. dx/dy +7x = 5cos2t
b. d^2x/dt^2 + 6 dx/dt + 8x = 5sin3t
I'll use the integrating factor method for the first DE, and undetermined coefficients for the second one.
(a) Multiply both sides by exp(7t ):
exp(7t ) dx/dt + 7 exp(7t ) x = 5 exp(7t ) cos(2t )
The left side is now the derivative of a product:
d/dt [exp(7t ) x] = 5 exp(7t ) cos(2t )
Integrate both sides:
exp(7t ) x = 10/53 exp(7t ) sin(2t ) + 35/53 exp(7t ) cos(2t ) + C
Solve for x :
x = 10/53 sin(2t ) + 35/53 cos(2t ) + C exp(-7t )
(b) Solve the corresonding homogeneous DE:
d²x/dt ² + 6 dx/dt + 8x = 0
has characteristic equation
r ² + 6r + 8 = (r + 4) (r + 2) = 0
with roots at r = -4 and r = -2. So the characteristic solution is
x (char.) = C₁ exp(-4t ) + C₂ exp(-2t )
For the particular solution, assume an ansatz of the form
x (part.) = a cos(3t ) + b sin(3t )
with derivatives
dx/dt = -3a sin(3t ) + 3b cos(3t )
d²x/dt ² = -9a cos(3t ) - 9b sin(3t )
Substitute these into the non-homogeneous DE and solve for the coefficients:
(-9a cos(3t ) - 9b sin(3t ))
… + 6 (-3a sin(3t ) + 3b cos(3t ))
… + 8 (a cos(3t ) + b sin(3t ))
= (-a + 18b) cos(3t ) + (-18a - b) sin(3t ) = 5 sin(3t )
So we have
-a + 18b = 0
-18a - b = 5
==> a = -18/65 and b = -1/65
so that the particular solution is
x (part.) = -18/65 cos(3t ) - 1/65 sin(3t )
and thus the general solution is
x (gen.) = x (char.) + x (part.)
x = C₁ exp(-4t ) + C₂ exp(-2t ) - 18/65 cos(3t ) - 1/65 sin(3t )
Use reduction of order to find a second linearly independent solution
(2x+5)y′′−4(x+3)y′+4y=0,x>−52,y1=e2x
Given that exp(2x) is a solution, we assume another solution of the form
y(x) = v(x) exp(2x) = v exp(2x)
with derivatives
y' = v' exp(2x) + 2v exp(2x)
y'' = v'' exp(2x) + 4v' exp(2x) + 4v exp(2x)
Substitute these into the equation:
(2x + 5) (v'' exp(2x) + 4v' exp(2x) + 4v exp(2x)) - 4 (x + 3) (v' exp(2x) + 2v exp(2x)) + 4v exp(2x) = 0
Each term contains a factor of exp(2x) that can be divided out:
(2x + 5) (v'' + 4v' + 4v) - 4 (x + 3) (v' + 2v) + 4v = 0
Expanding and simplifying eliminates the v term:
(2x + 5) v'' + (4x + 8) v' = 0
Substitute w(x) = v'(x) to reduce the order of the equation, and you're left with a linear ODE:
(2x + 5) w' + (4x + 8) w = 0
w' + (4x + 8)/(2x + 5) w = 0
I'll use the integrating factor method. The IF is
µ(x) = exp( ∫ (4x + 8)/(2x + 5) dx ) = exp(2x - log|2x + 5|) = exp(2x)/(2x + 5)
Multiply through the ODE in w by µ :
µw' + µ (4x + 8)/(2x + 5) w = 0
The left side is the derivative of a product:
[µw]' = 0
Integrate both sides:
∫ [µw]' dx = ∫ 0 dx
µw = C
Replace w with v', then integrate to solve for v :
exp(2x)/(2x + 5) v' = C
v' = C (2x + 5) exp(-2x)
∫ v' dx = ∫ C (2x + 5) exp(-2x) dx
v = C₁ (x + 3) exp(-2x) + C₂
Replace v with y exp(-2x) and solve for y :
y exp(-2x) = C₁ (x + 3) exp(-2x) + C₂
y = C₁ (x + 3) + C₂ exp(2x)
It follows that the second fundamental solution is y = x + 3. (The exp(2x) here is already accounted for as the first solution.)
The sum of a number and 2 times its reciprocal is -3
Answer:
(-2,-1)
Step-by-step explanation:
let the number=x
its reciprocal=1/x
x+2(1/x)=-3
x+2/x=-3
x²+2=-3x
x²+3x+2=0
(x+2)(x+1)=0
x=-2,-1
Find m angle LKJif m angle LKD=60^ and m angle DKJ=55^
Answer:
<LKJ = 115°
Step-by-step explanation:
<LKJ = <LKD + <DKJ
<LKJ = 60°+55°
<LKJ = 115°
Answered by GAUTHMATH
Answer:
We're provided - m ∠ LKD = 60° , m ∠ DKJ = 55° and we're asked to find out m ∠ LKJ. Now , Look the figure more carefully , we can see that we can create an equation and solve for m ∠ LKJ.[tex] \large{ \tt{✺ \: m \: \angle \: LKJ= m \: \angle} \: LKD \: + \: m \: \angle \: dKJ}[/tex]
[tex] \large{ \tt{⟶ \: m \: \angle \: LKJ= 60 \degree + 55 \degree}}[/tex]
[tex] \large{ \boxed{ \tt{⟶ \: m \: \angle \: LKJ = 115 \degree}}}[/tex]
Hence , Our final answer is 115° . Hope I helped! Let me know if you have any questions regarding my answer and also notify me , if you need any other help! :)▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
what is the difference between dot product and cross product?
Answer:
A dot product is the product of the magnitude of the vectors and the cos of the angle between them. A cross product is the product of the magnitude of the vectors and the sine of the angle that they subtend on each other.
Step-by-step explanation:
Quality control. As part of a quality control process for computer chips, an engineer at a factory randomly samples 212 chips during a week of production to test the current rate of chips with severe defects. She finds that 27 of the chips are defective.
(a) What population is under consideration in the data set?
(b) What parameter is being estimated?
(c) What is the point estimate for the parameter?
(d) What is the name of the statistic can we use to measure the uncertainty of the point estimate?
(e) Compute the value from part (d) for this context.
(f) The historical rate of defects is 10%. Should the engineer be surprised by the observed rate of defects
during the current week?
(g) Suppose the true population value was found to be 10%. If we use this proportion to recompute the value in part (e) using p = 0.1 instead of pˆ, does the resulting value change much?
Answer:
See Explanation
Step-by-step explanation:
According to the Question,
Given That, As part of a quality control process for computer chips, an engineer at a factory randomly samples 212 chips during a week of production to test the current rate of chips with severe defects. She finds that 27 of the chips are defective.(a) The sample is from all computer chips manufactured at the factory during the week of production. We might be tempted to generalize the population to represent all weeks, but we should exercise caution here since the rate of defects may change over time.
(b) The fraction of computer chips manufactured at the factory during the week of production that had defects.
(c) Estimate the parameter using the data: phat = 27/212 = 0.127.
(d) Standard error (or SE).
(e) Compute the SE using phat = 0.127 in place of p:
SE ≈ √(phat(1−phat)/n) = 0.023.
(f) The standard error is the standard deviation of phat. A value of 0.10 would be about one standard error away from the observed value, which would not represent a very uncommon deviation. (Usually beyond about 2 standard errors is a good rule of thumb.) The engineer should not be surprised.
(g) Recomputed standard error using p = 0.1: SE = 0.021. This value isn't very different, which is typical when the standard error is computed using relatively similar proportions (and even sometimes when those proportions are quite different!).
Please answer of question num 20 and 21 only please
Answer:
Iam going to do question 21
Step-by-step explanation:
1/7*x=2
1/7x=2
x=2:1/7
x=2*7/1
x=14
Find m∠GHIm∠GHI if m∠GHI=14x+6m∠GHI=14x+6, m∠QHI=130∘m∠QHI=130∘, and m∠GHQ=3x−3m∠GHQ=3x−3.
Answer:
m∠GHI = 160
Step-by-step explanation:
From the question given above, the following data were obtained:
m∠GHI = 14x + 6
m∠QHI = 130°
m∠GHQ = 3x – 3
m∠GHI =?
Next, we shall determine the value of x. This can be obtained as follow:
m∠GHI = m∠QHI + m∠GHQ
14x + 6 = 130 + (3x – 3)
14x + 6 = 130 + 3x – 3
Collect like terms
14x – 3x = 130 – 3 – 6
11x = 121
Divide both side by 11
x = 121 / 11
x = 11
Finally, we shall determine the value m∠GHI. This can be obtained as follow:
m∠GHI = 14x + 6
x = 11
m∠GHI = 14(11) + 6
m∠GHI = 154 + 6
m∠GHI = 160
(c) Construct a 99% confidence interval for u if the sample
size, n, is 35.
Answer:
The confidence interval is [tex](\overline{x} - 1.99\frac{\sigma}{\sqrt{35}}, \overline{x} + 1.99\frac{\sigma}{\sqrt{35}})[/tex], in which [tex]\overline{x}[/tex] is the sample mean and [tex]\sigma[/tex] is the standard deviation for the population.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]
Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
In this question:
[tex]M = 1.99\frac{\sigma}{\sqrt{35}}[/tex]
The lower end of the interval is the sample mean subtracted by M, while upper end of the interval is the sample mean added to M. Thus, the confidence interval is [tex](\overline{x} - 1.99\frac{\sigma}{\sqrt{35}}, \overline{x} + 1.99\frac{\sigma}{\sqrt{35}})[/tex], in which [tex]\overline{x}[/tex] is the sample mean and [tex]\sigma[/tex] is the standard deviation for the population.
please help! i need this ASAP!
Answer:
C. y=7/9x+17/9
Step-by-step explanation:
Take the slope. slope= m = y2-y1/x2-x1
=5-(-2)/4-(-5)
=7/9
Then put it into point-slope form.
y-y1=m(x-x1)
=y-5=7/9(x-4)
Simplify.
y=7/9x-28/9+5
y=7/9x+17/9
Answer:
C
Step-by-step explanation:
First find the slope (change in y/ change in x) which is positive 7/9.
Then use y=mx+b and plug in the slope, and one of the given points to solve for b.
5= 7/9*4+b
5=28/9+b
5-28/9=b
45/9-28/9=b
17/9=b
Then with the slope and y intercept(b) you get the equation shown in answer c.
Hope that helps!
Ms. Weaver plans to decorate the bulletin board in her classroom. She purchased 30 sheets of construction paper for $0.30 per sheet, 5 boxes of thumbtacks for $0.70 per box, and 4 framed pictures for $6.00 per picture. How much money did Ms. Weaver spend for the items?
Answer:
$36.5 money ms.weaver spent for the items
jenna is playing an online trivia game. she has 50 points and earns 2 points for each correct answer. she will advance to the next amount if her score is over 68 points. which inequality can jenna use to find how many more questions she must answer correctly to advance to the next round?
Answer:2x + 50 > 68
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
because is you skip count on two you will count on to 68 so that is why the answer is 7.
what is the solution for 2y=x+2
x-3y=-5
Answer:
x = 4
y = 3
Step-by-step explanation:
Given equations :-
2y = x + 2 x - 3y = -5Second equation can be written as ,
x - 3y = -5 -3y = -x - 5Adding them :-
-3y + 2y = 2 -5 -y = -3 y = 3Put this in (ii) :-
x = 3y - 5 x = 3*3 - 5 x = 9 -5X = 4The equations of two lines are given. Determine if the lines are parallel, perpendicular, or neither.
8x - 7y = 6
8x - y = -8
Answer:
8x-7y=6
or, -7y=-8x+6
or, y=8x/7-6/7
so the slope is 8/7
8x-y=-8
or, -y=-8x-8
or, y=8x+8
So the slope is 8
Both has different slope and they don't satisfy the property of being perpendicular to each others, so they're neither parallel nor perpendicular.
Answered by GAUTHMATH
