Redline John walk 6 yards before driving in his stake.
Blue line Paul drove 16 yards before driving in his stake.
Distance between John and Paul = 17.10
Red line represent the path john walked
1 box = 1 yard
Total number of boxes = 6
Total distance travelled = 6 yards
Blue line represent the path paul walked
1 box = 1 yard
Total number of boxes = 16
Total distance travelled = 16 yards
Using Pythagorean theorem
(hypotenuse)² = (perpendicular)² + (base)²
(hypotenuse)² = 6² + 16²
(hypotenuse)² = 36 + 216
(hypotenuse)² = 292
hypotenuse = 17.08
hypotenuse = 17.10
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A large toiletry distributor claims that 35% of all individuals who purchase toilet paper from the stores that carry its product choose original toilet paper, 28% choose sensitive toilet paper, 20% choose ultra-strong toilet paper, and 17% choose ultra-soft toilet paper. To investigate this claim, researchers collected data from a random sample of customers in a large city. The results were 170 packages of original, 105 sensitive, 80 ultra-strong, and 45 ultra-soft toilet paper purchases. Are the data from the sample consistent with the distributor's claim? Conduct an appropriate statistical test at the 5% significance level to support your conclusion. Make sure to include parameters, check conditions, and show calculations before formulating a conclusion.
__________________________________
No, The Data From The Sample Is Not Consistent With The Distributor's Claim.CLAIM:Original: 35%Sensitive: 28%Ultra-Strong: 20%Ultra-Soft: 17%= 35% + 28% + 20% + 17%= 100%DATA: Original: 170 PacksSensitive: 105 PacksUltra-Strong: 80 PacksUltra-Soft: 45 Packs= 170 Packs + 105 Packs + 80 Packs + 45 Packs= 400 PacksOriginal = 170 ÷ 400 × 100 = 42.5%Sensitive = 105 ÷ 400 × 100 = 26.25%Ultra-Strong = 80 ÷ 400 × 100 = 20% Ultra-Soft = 45 ÷ 400 × 100 = 11.25%= 42.5% + 26.25% + 20% + 11.25%= 100%_________________________________
You are trying to answer a multiple choice question on a standardized test. There are four choices. If you get the question right, you gain one point, and if you get it wrong, you lose 1/3 point. Assume you have no idea what the right answer is, so you pick one of the choices at random. What is the expected value of the number of points you get? What is the expected value of the number of points you get? Round the answer to two decimal places. The expected value of the number of points you get is
Answer:
1/3
Step-by-step explanation:
Answer:
Since you have no idea what the right answer is, each choice has a probability of 1/4 of being correct. Let X be the number of points you get.
If you answer correctly, X = 1 with probability 1/4.
If you answer incorrectly, X = -1/3 with probability 3/4.
Thus, the expected value of X is:
E(X) = (1/4)×1 + (3/4)×(-1/3)
E(X) = 1/4 - 1/4
E(X) = 0
Therefore, the expected value of the number of points you get is 0.
Step-by-step explanation:
gg
which multiplication equation can you use to find 5/1 over 3
Answer:
5/1÷3 is = to 5/3
Step-by-step explanation:
I hope this helps
A particle is moved along the x-axis by a force that measures 8/(3 + x)2 pounds at a point x feet from the origin. Find the work W done in moving the particle from the origin to a distance of 9 ft.
Answer:
2 ft·lb
Step-by-step explanation:
You want the work done on a particle moving it from 0 to 9 ft using a force that is 8/(3+x)² pounds at each point.
WorkThe incremental work is the product of the force and the incremental distance:
dW = 8/(3+x)²·dx
The work done over the distance of interest is the integral of this incremental work over that distance.
[tex]\displaystyle W=\int_0^9{\dfrac{8}{(x+3)^2}}\,dx=(-8(x+3)^{-1})_0^9=-8\left(\dfrac{1}{12}-\dfrac{1}{3}\right)=2[/tex]
The work done on the particle is 2 ft·lb.
If the space in her entertainment center is 19.87 inches high and 42 long, will the tv for in her entertainment center ? Yes or no
The 43-inch TV will fit in Susan's entertainment center.
To determine if the 43-inch TV will fit in Susan's entertainment center, we need to make sure that the height, width, and diagonal of the TV are all smaller than or equal to the corresponding measurements of the entertainment center.
Since the entertainment center has a height of 19.87 inches, the 43-inch TV will fit in terms of height if its height is 19.87 inches or smaller.
Similarly, since the entertainment center has a length of 42 inches, the 43-inch TV will fit in terms of length if its length is 42 inches or smaller. Since the length of the TV is 37.41 inches, it will fit.
Finally, we need to check the diagonal. The diagonal of a rectangle can be found using the Pythagorean theorem. If we let a be the height and b be the length, then the diagonal d is given by:
d = sqrt(a² + b²)
For the entertainment center, this gives a diagonal of approximately 45.53 inches. Since the diagonal of the TV is 43 inches, it will also fit.
Therefore, the 43-inch TV will fit in Susan's entertainment center.
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Its about fractions please help me
The times the 7 in the Susan's scores is greater than Sarah's score is 100 times
How many times is the 7 in the scores greater than the otherFrom the question, we have the following parameters that can be used in our computation:
Susan = 87, 325
Sarah = 46, 175
The values of the 7's in their scores are
Susan = 7, 000
Sarah = 70
So, we have
Number of times = 7000/70
Evaluate
Number of times = 100
Hence, the number of times is 100
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Sketch the graph of the following system of equations and label at least 3 points on each graph. At what point do the equations intersect ?
3x + 7y = 7
5x − 7y = −63
PLEASE HELP TIMED QUIZ!! 25 POINTS!!
The points on the equations intersect at (-7, 4)
At what point do the equations intersect ?From the question, we have the following parameters that can be used in our computation:
3x + 7y = 7
5x − 7y = −63
The above equations is an illustration of a system of equations
Next, we plot the graph using a graphing tool
The graph is added as an attachment, where the point of intersection is (-7, 4)
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0.15
11A) Suppose a 2 is rolled on a number cube with sides numbered 1, 2, 3, 4, 5, and 6.
Which outcome(s) make up the complement of this event? Select all that apply.
rolling a 1
rolling a 2
rolling a 3
rolling a 4
☐ rolling a 5
rolling a 6
11B) What is the probability of the complement written as a fraction in simplest form?
6
A. rolling a 1,3,4,5,6
B. The probability of the complement event is 5/6.
What is a complement event?An experiment's probability of an event occurring is measured by its probability of occurring. When there are only two outcomes, or complement, we can say that it is the complete opposite of an event.
11(A ) Rolling any number other than 2 on the number cube is the complement of rolling a 2. Therefore, the complement's outcomes are as follows: rolling a one, a three, a four, a five, and a six
So, the correct answers are:
☐ rolling a 1
☐ rolling a 3
☐ rolling a 4
☐ rolling a 5
☐ rolling a 6
11B) Since there is only one favorable outcome (rolling a 2) out of six possible outcomes, the probability of rolling a 2 is 1/6. By deducting the probability of rolling a 2 from 1, the probability of the complement event (rolling any number other than 2) can be determined:
P(complement) = 1 - P(rolling a 2) = 1 - 1/6 = 5/6
Therefore, the probability of the complement event is 5/6.
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ac and eb are diameters of circle r identify each arc as a major arc minor arc or semicircle of the circle then find its measure in degrees
The arc DEB is major arc.
The arcs, arc EA, arc CB, arc DC and arc AB are minor arcs.
The arc CDA is semicircle.
An arc which has a measure of less than 180° is called minor arc.
An arc whose measure is more than 180° is major arc.
Measure of arc EA = 180° - (30° + 100°) = 50°
[Since AC is a diameter CD + DE + EA = 180°]
Measure of arc CB = 50°
Measure of arc DC = 100°
Measure of arc DEB = 360° - (100° + 50°) = 210°
[ Whole circle = 360°]
Measure of arc AB = DEB - (DE + EA) = 210° - (30° + 50°) = 130°
Measure of arc CDA = 180° [Since AC is a diameter.]
Hence the Major arcs are arc DEB, minor arcs are arc EA, arc CB, arc DC and arc AB. Semicircle is arc CDA.
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The figure is given below.
A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess board. On the second square the King would place two grains of wheat, on the third square, four grains of wheat, and on the fourth square eight grains of wheat. If the amount of wheat is doubled in this way on each of the remaining squares, how many grains of wheat should be placed on square 30? Also find the total number of grains of wheat on the board at this time and their total weight in pounds. (Assume that each grain of wheat weighs 1/7000 pound.) How many grains of wheat should be placed on square 30?
Answer: 2,635,799,463,387 pounds
Step-by-step explanation:
In Exercises 11 and 12, solids A and B are similar. Use the given information and scale factor k from solid A to solid B
to find the surface area of solid B.
11. The surface area of pyramid A is
72 square centimeters and k =
12. The surface area of cone A is
150# square meters and k =
5
The surface area of solid B is 3,750 square meters.
How to calculate the surface area of solid?Since the solids are similar with a scale factor k from solid A to solid B, the ratio of their surface areas is k². Therefore, the surface area of solid B is:
Surface area of solid B = Surface area of solid A * k²
Substituting the given values, we get:
Surface area of solid B = 72 * 12²
Surface area of solid B = 10368 square centimeters.
Therefore, the surface area of solid B is 10,368 square centimeters.
Following the same approach as above:
Surface area of solid B = Surface area of solid A * k²
Substituting the given values:
Surface area of solid B = 150 * 5²
Surface area of solid B = 3750 square meters
Therefore, the surface area of solid B is 3,750 square meters.
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4.Sarah wants to give her friend a fish tank for her birthday.
The tank is a cylinder that measures 10 inches high and has a
diameter of 8 inches.
a.What is the minimum amount of wrapping paper Sarah will
need to cover the present? (Please show your work for credit)
Please help me
The minimum amount of wrapping paper Sarah will need to cover the present is; 351.68 square inches and one gallon of filtered water is not enough because the capacity of fish tank will be 2.17 gallons.
WE are Given that, the dimensions of cylindrical fish tank are height=10 inches and radius = 8/2 = 4 inches.
Now the total surface area of a cylinder is 2πr(r + h).
Here, the required wrapping paper = 2×3.14 ×4(4+10)
= 2×3.14×4×14
= 351.68 square inches
We know that, the volume of cylinder = πr²h
= 3.14 × 4² × 10
= 502.4 cubic inches
Thus, 1 gallon is equal to 231 cubic inches
Number of gallons of filtered water required = 502.4/231
= 2.17 gallons
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Polygon ABCD is rotated to get polygon A′B′C′D′.
Graph of polygon ABCD in quadrant 2 with point A at negative 7 comma 5, point B at negative 2 comma 8, point C at negative 2 comma 4, and point D at negative 4 comma 3 and polygon A prime B prime C prime D prime in quadrant 1 with point A prime at 5 comma 7, point B prime at 8 comma 2, point C prime at 4 comma 2, and point D prime at 3 comma 4
Determine the direction and angle of rotation.
270° clockwise rotation
270° counterclockwise rotation
90° counterclockwise rotation
180° clockwise rotation
The direction and the angle of rotation if polygon ABCD is rotated to get polygon A′B′C′D′ is 270° counterclockwise rotation.
Given are graphs of polygon ABCD and A′B′C′D′.
The points of ABCD are,
A(-7, 5), B(-2, 8), C(-2, 4) and D(-4, 3).
The points of A′B′C′D′ are,
A'(5, 7), B'(8, 2), C'(4, 2) and D'(3, 4).
A point (x, y) is changed to the point (y, -x).
This transformation is done if the angle of rotation is 270 degrees counterclockwise or 90 degrees clockwise.
Hence the correct option is 270° counterclockwise rotation.
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which inequality matches the graph
The inequality x<4 matches the graph
A number line is a picture of a graduated straight line that serves as visual representation of the real numbers.
As we observe the graph , it starts at 4 which has a dot which is open and the direction of arrow is left side
The left direct indicates that it is decreasing and open dot indicates the number 4 is not included.
So the inequality x<4 matches the graph
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Determine the exact value of θ in the following equation if 0≤θ<2π.
8cos^2 θ+2=8
List your answers as exact answers in terms of π, separated by a comma if necessary.
The exact values of θ are θ = π/6 and θ = 11π/6.
Given that;
The expression is,
⇒ 8 cos² θ + 2 = 8
Now, We ca simplify as;
⇒ 8 cos² θ + 2 = 8
Subtracting 2 from both sides:
8cos² θ = 6
Then we divide both sides by 8:
cos² θ = 3/4
Taking the square root of both sides, we get:
cos θ = ±√(3/4)
cos θ = ±(√3)/2
Since 0 ≤ θ < 2π,
And, we know that θ is in either the first or the fourth quadrant.
Hence, In the first quadrant, cos θ is positive, and in the fourth quadrant, cos θ is negative.
Therefore, we can eliminate the negative solution and conclude that:
cos θ = (√3)/2
Using the inverse cosine function, we find:
θ = π/6 or 11π/6
So, the exact values of θ are θ = π/6 and θ = 11π/6.
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(b) One of the worst nuclear disasters in history occurred on April 26, 1986 when the Chernobyl nuclear power plant (located in what is now known as Ukraine) exploded scattering radioactive material over parts of Asia and Europe. One radioactive element involved was cesium-137, which has a half-life of 30 years. It is almost 37 years since the Chernobyl disaster. Let Ao be the amount of cesium-137 present near the disaster site at the time of the explosion. What percentage of cesium-137 is still near the disaster site today (after 37 years)? Your answer will be a percentage of Ao. Make sure to leave k in exact form in your calculation. Round your answer to 2 decimal places.
The result, when rounded to two decimal places, is 23.87%.
What is a decimal ?In algebra, a decimals is one of the number types that has a full integer and a fractional component divided by a point that is decimal. 34.5 is an illustration of a decimal number.
The formula A = Ao * (1/2)(t/30) can be used to determine how much cesium-137 is still present after t years, where Ao is the initial amount and t is the amount of time in years.
After simplifying and replacing t=37, we obtain:
A = Ao * (1/2)^(37/30)
A = Ao * (1/2)^(37/30)
After 37 years, there is a proportion of cesium-137 left, which is:
% is equal to (A/Ao) * 100 = (Ao * (1/2)(37/30)/Ao) * 100 = (1/2)(37/30) * 100.
Calculating (1/2)(37/30) yields the result: (1/2)(37/30) 0.2387
Consequently, the percentage of cesium-137 still present in the area now is about equal to: percentage 0.2387 * 100 23.87%
The result, when rounded to two decimal places, is 23.87%.
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About 21.44% of cesium-137 is still near the disaster site today.
What is algebra?
Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.
The amount of cesium-137 present near the disaster site at the time of the explosion is Ao.
The half-life of cesium-137 is 30 years. This means that after 30 years, half of the initial amount will have decayed, leaving us with 1/2 of the initial amount. After another 30 years, half of the remaining amount will have decayed, leaving us with 1/4 of the initial amount.
Since it is almost 37 years since the Chernobyl disaster, we can calculate the percentage of cesium-137 that is still near the disaster site today as follows:
Amount of cesium-137 present today = Ao * (1/2)^(37/30)
Percentage of cesium-137 present today = (Amount of cesium-137 present today / Ao) * 100
= (Ao * [tex](1/2)^{(37/30)}[/tex] / Ao) * 100
= [tex](1/2)^{(37/30)}[/tex]) * 100
= [tex](1/2)^{(37/30)}[/tex]) * 100%
≈ 21.44%
Therefore, about 21.44% of cesium-137 is still near the disaster site today.
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Ricky is making soup. He uses 1 quart of water and 3 tablespoons of seasoning. After tasting the soup, he decides to add double the amount of seasoning. What is the ratio of cups to tablespoons of seasoning after Ricky doubles the amount?
Answer:
Step-by-step explanation:
Since there are 16 tablespoons in 1 cup, we can convert the original 3 tablespoons of seasoning to cups by dividing by 16:
3 tablespoons / 16 = 0.1875 cups
After Ricky doubles the amount of seasoning, he will have:
2 * 3 tablespoons = 6 tablespoons
Converting to cups:
6 tablespoons / 16 = 0.375 cups
Therefore, the ratio of cups to tablespoons of seasoning after Ricky doubles the amount is:
0.375 cups / 1 tablespoon = 0.375 : 1
Answer: The ratio of cups to tablespoons of seasoning after Ricky doubles the amount is 0.375 : 1
Answer B ONLY!!!
Please I need help with this
If 453 teenagers were surveyed, the number of teenagers who would receive a weekly allowance is approximately 263.
Given that,
According to a survey,
Percent of teenagers who will receive a weekly allowance for doing household chores = 58%
So, if the number of teenagers surveyed is 453,
Number of teenagers who will receive a weekly allowance for doing household chores = 58% × 453
= (58/100) × 453
= 0.58 × 453
= 262.74 ≈ 263
Hence the number of teenagers who will receive a weekly allowance for doing household chores is approximately 263.
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PLS HELP WITH THIS MATH PROBLEM! The problem is attached to this problem.
The quintic equation has integer coefficients for x = - 5 / 3.
How to find the values of the missing coefficients of a quintic equation
In this question we need to determine the missing coefficients of a quintic equations, that is, a polynomial of grade 5, on the basis that the coefficients are integers.
First, we evaluate on each case:
x = - 5 / 3
12 · (- 5 / 3)⁵ + a · (- 5 / 3)³ + b · (- 5 / 3)² - 3 · (- 5 / 3) + 15 = 0
- 12500 / 81 - (125 / 27) · a + (25 / 9) · b + 5 + 15 = 0
- (125 / 27) · a + (25 / 9) · b = 10880 / 81
- (5 / 3) · a + b = 2176 / 45
b = (5 / 3) · a + 2176 / 45
x = - 4 / 3
12 · (- 4 / 3)⁵ + a · (- 4 / 3)³ + b · (- 4 / 3)² - 3 · (- 4 / 3) + 15 = 0
- 4096 / 81 - (64 / 27) · a + (16 / 9) · b + 4 + 15 = 0
- (64 / 27) · a + (16 / 9) · b = 2557 / 81
- (4 / 3) · a + b = 2557 / 144
b = (4 / 3) · a + 2557 / 144
x = 3 / 5
12 · (3 / 5)⁵ + a · (3 / 5)³ + b · (3 / 5)² - 3 · (3 / 5) + 15 = 0
2916 / 3125 + (27 / 125) · a + (9 / 25) · b - 9 / 5 + 15 = 0
(27 / 125) · a + (9 / 25) · b - 2709 / 3125 + 46875 / 3125 = 0
(27 / 125) · a + (9 / 25) · b + 44166 / 3125 = 0
(27 / 125) · a + (9 / 25) · b = - 44166 / 3125
(3 / 5) · a + b = - 14722 / 375
b = - (3 / 5) · a - 14722 / 375
x = 6 / 5
12 · (6 / 5)⁵ + a · (6 / 5)³ + b · (6 / 5)² - 3 · (6 / 5) + 15 = 0
12 · (7776 / 3125) + (216 / 125) · a + (36 / 25) · b - 18 / 5 + 15 = 0
93312 / 3125 + (216 / 125) · a + (36 / 25) · b - 18 / 5 + 15 = 0
82062 / 3125 + (216 / 125) · a + (36 / 25) · b + 15 = 0
(216 / 125) · a + (36 / 25) · b = - 128937 / 3125
(6 / 5) · a + b = - 3223425 / 112500
(6 / 5) · a + b = - 644685 / 22500
(6 / 5) · a + b = - 128937 / 4500
b = - (6 / 5) · a - 128937 / 4500
After using a graphing tool, we conclude that x = - 5 / 3 can be found by using the following integers:
(a₁, b₁) = (19, 80), (a₂, b₂) = (31, 100), (a₃, b₃) = (79, 180)
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When keith had 5 years left in college, he took out a student loan for $14,342. The student loan has an annual interest rate of 2.7%. Keith graduated 5 years after acquiring the loan and began repaying the loan immediately upon graduation What was his subsided monthly payment
Keith's subsidized monthly payment upon graduation would be approximately $135.65.
Keith took out a student loan for $14,342 with an annual interest rate of 2.7%. He had 5 years left in college before he began repaying the loan. To find his subsidized monthly payment, we need to first calculate the total amount he owes after 5 years and then divide that by the number of months in the repayment period.
1. Convert the annual interest rate to a decimal: 2.7% ÷ 100 = 0.027
2. Calculate the interest for one year: $14,342 × 0.027 = $387.234
3. Calculate the total interest for 5 years: $387.234 × 5 = $1,936.17
4. Add the interest to the principal amount: $14,342 + $1,936.17 = $16,278.17
5. Assume a standard repayment period of 10 years (120 months) after graduation.
6. Divide the total amount owed by the number of months in the repayment period: $16,278.17 ÷ 120 = $135.65
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Find the missing side. Round to the nearest tenth
The value of the missing side is 23. 5. Option A
How to determine the valueTo determine the value of the missing length, we have to note that the trigonometric identities are;
sinetangentcosinecotangentsecantcosecantUsing the cosine identity, we have;
cos θ = adjacent/hypotenuse
Substitute the values, we get;
cos36 = 19/x
Cross multiply the values
x = 19/cos 36
Divide the values
x =19/0. 8090
x = 23. 5
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A cafeteria manager placed slices of pie into a display case. there were 20 apple, 24 cherry , 12 chocolate cream , 14 pecan, and 10 peach slices of pie . determine the percent distribution for the 5 types of pie slices in the case
Answer:Percent distribution is:Apple: 25%
Cherry: 30%
Chocolate Cream: 15%
Pecan: 17.5%
Peach: 12.5%
Step-by-step explanation:
Given,
Appple=20
Cherry=24
Chochlate cream=12
Pecan=14
Peach=10
Step 1: To find the total number of pie slices=
20 + 24 + 12 + 14 + 10 = 80
Step 2: Calculate the percentage for each type of pie slice.
Divide the number of pie slices for each type by the total number of pie slices, and then multiply by 100 to get the percentage.
For apple pie slices:
20 / 80 = 0.25 or 25%
For cherry pie slices:
24 / 80 = 0.3 or 30%
For chocolate cream pie slices:
12 / 80 = 0.15 or 15%
For pecan pie slices:
14 / 80 = 0.175 or 17.5%
For peach pie slices:
10 / 80 = 0.125 or 12.5%
So, the percent distribution is:
Apple: 25%
Cherry: 30%
Chocolate Cream: 15%
Pecan: 17.5%
Peach: 12.5%
The graph of function f is shown. Function g is represented by the table. x -1 0 1 2 3 4 g(x) 24 6 0 -2 Which statement correctly compares the two functions? A. They have different end behavior as x approaches -∞ and different end behavior as x approaches ∞. B. They have the same end behavior as x approaches -∞ but different end behavior as x approaches ∞. C. They have the same end behavior as x approaches -∞ and the same end behavior as x approaches ∞. D. They have different end behavior as x approaches -∞ but the same end behavior as x approaches ∞.
The answer choice which correctly draws a comparison between the end behaviors of the functions is; Choice C; They have the same end behavior as x approaches -∞ and same end behavior as x approaches ∞.
As given in the task content; the graph of the exponential function passes through (-4, 9), (0, 1), (1, 0), and (5, -2).
It therefore follows that as; x reduces (approaches -∞), the y value increases.
And, as x -increases (approaches +∞), the y-value decreases.
For the table, the values can be written as coordinates as follows; (-1,2), (0,4), (1,6), (2, 0), (3,-2).
Consequently, as x reduces (approaches -∞), the y- values decrease.
And, as x increases (approaches +∞), the y-values decrease.
Ultimately, the two functions in discuss can be concluded to have; Choice C.
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Pls hurry quick answer now
Which details from the poster suggest that giving women the vote will destroy home life?
Step-by-step explanation:
the fourth one
...
.
.
...
..
Answer:
O.D) The broken plate, the creaming children, and the boiling tea kettle.
No explanation needed.a school has $3,245 that it will divide equally among 11 clubs how much will each club receive
A certain drug is made from only two ingredients: compound A and compound B. There are 3 milliliters of compound A used for every 5 milliliters of compound
B. If a chemist wants to make 728 milliliters of the drug, how many milliliters of compound A are needed?
? milliliters of compound A
The chemist will need 273 ml of compound A to make 728 ml of the drug.
It is given that 8 parts of drug are made by using 2 parts of compound A and 5 parts of compound B.
So the proportion (ml of compound A)/(ml of drug) = 3/8
Suppose the chemist needs x ml of compound A to make 728 ml of the drug.
So we have, [tex]\frac{x}{728} = \frac{3} {8}[/tex]
So , [tex]x = \frac{(728)(3)}{8} = 273\,\,ml.[/tex]
How do we solve ratio and proportion questions.
How do we solve ratio and proportion questions.Consider this question?
Suppose every project team will have equal no of boys and girls. Suppose a particular team will have 10 members. How many boys will be in this team. To answer this question we find the the key proportionality or ratio in the problem. it is #boys/#girls = 1/1. So #boys/#team members = 1/(1+1)=1/2. So if the team size is 10. then #boys = (1/2)(10) = 5. This is the way we solve problems in ratio and proportion.
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Solve for the zeros of the quadratic function f(x) = 9x² + 6x +1. Write the answer as a fraction.
1.
2.
X=
x=
-b± √b²-4ac
2a
4. x=
-6±√(6)2-4(9)(1)
2(9)
3. x=-6±√36-36
18
Step-by-step explanation:
To solve for the zeros of a quadratic function, we need to find the values of x where f(x) equals zero. This means that we need to set the quadratic function equal to zero and solve for x.
In this case, our quadratic function is f(x) = 9x² + 6x + 1. To set it equal to zero, we write:
9x² + 6x + 1 = 0
Now we can use the quadratic formula to solve for x:
x = (-b ± √b² - 4ac) / 2a
In this equation, a, b, and c are the coefficients of the quadratic function. In our case, a = 9, b = 6, and c = 1. Substituting these values into the equation, we get:
x = (-6 ± √36 - 4(9)(1)) / 2(9)
Simplifying, we get:
x = (-6 ± √0) / 18
Since the square root of 0 is 0, we have:
x = -6/18 and x = -6/18
Reducing the fractions, we get:
x = -1/3 and x = -1/3
Therefore, the zeros of the quadratic function f(x) = 9x² + 6x + 1 are x = -1/3 and x = -1/3.
what are the coordinates of a quadrillateral stuv after a 270 degree rotation about the orgin?
The new coordinates of the quadrilateral STUV after a 270-degree rotation about the origin are STUV' = (S', T', U', V') = [(-y₁, x₁), (-y₂, x₂), (-y₃, x₃), (-y₄, x₄)]
To find the new coordinates of the quadrilateral STUV after a 270-degree rotation about the origin, we can apply the rotation matrix formula.
The rotation matrix for a 270-degree rotation is:
R = [ cos(270) -sin(270) ]
[ sin(270) cos(270) ]
which simplifies to:
R = [ 0 -1 ]
[ 1 0 ]
We can then multiply this matrix by each of the four vertices of the quadrilateral in order to obtain their new coordinates. Let the original coordinates of the vertices be:
S = (x₁, y₁)
T = (x₂, y₂)
U = (x₃, y₃)
V = (x₄, y₄)
Then the new coordinates of the vertices after the 270-degree rotation about the origin are:
S' = RS = (0x₁ - y₁, 1x₁ + 0y₁) = (-y₁, x₁)
T' = RT = (0x₂ - y₂, 1x₂ + 0y₂) = (-y₂, x₂)
U' = RU = (0x₃ - y₃, 1x₃ + 0y₃) = (-y₃, x₃)
V' = RV = (0x₄ - y₄, 1x₄ + 0y₄) = (-y₄, x₄)
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Yesterday the movie theater sold a total of 180 tickets. Of these tickets, 45 tickets were sold at a discounted price. What percent of all the tickets were sold at a discounted price?
Answer:
25%
Step-by-step explanation:
[tex]\frac{45}{180}[/tex] x 100%
.25 x 100% = 25%
Helping in the name of Jesus.
The accompanying table shows the value of a car over time that was purchased for
15700 dollars, where x is years and y is the value of the car in dollars. Write an
exponential regression equation for this set of data, rounding all coefficients to the
nearest hundredth. Using this equation, determine the value of the car, to the nearest
cent, after 9 years.
Years (x)
0
1
2
3
4
5
6
Value in Dollars (y)
15700
14220
13060
11446
10927
9140
8418
Answer:
To write an exponential regression equation for this set of data, we can use the formula y = ab^x, where y is the value of the car in dollars, x is the number of years since purchase, a is the initial value of the car, and b is the rate of depreciation.
To find the values of a and b, we can use the first two data points:
y = ab^x
14220 = ab^1
Solving for a, we get:
a = 14220 / b
Now, we can substitute this expression for a into the first data point:
y = ab^x
15700 = (14220 / b) * b^0
Simplifying, we get:
15700 = 14220
This is not a valid equation, so we need to adjust our estimate for the rate of depreciation, b. One way to do this is to take the average of the depreciation rates between each pair of consecutive data points:
b = (14220/15700)^(1/6)
b = 0.9497
Now, we can use this value of b to find the value of a:
a = 14220 / b
a = 14955.15
Therefore, the exponential regression equation for this set of data is:
y = 14955.15 * 0.9497^x
To find the value of the car after 9 years, we can substitute x = 9 into the equation:
y = 14955.15 * 0.9497^9
y = 7327.78
Therefore, the value of the car, to the nearest cent, after 9 years is $7327.78.