Someone help me please
30-60-90 triangles

The domain of the exponential function shown in the graph is -oo < x < oo

The function on the graph is an exponential function.

The domain is the set of x values the function can take

From the graph, we have the following x values

This means that the domain of x in the graph is -oo < x < oo

Hence, the domain of the exponential function shown in the graph is -oo < x < oo

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The average rate of change of [tex]f(x)[/tex] on [tex]12\le x\le36[/tex] is the difference quotient

[tex]\dfrac{f(36) - f(12)}{36 - 12} = \dfrac{28 - 34}{24} = \boxed{-\dfrac14}[/tex]

Answer: D

Step-by-step explanation: The line of best fit is a straight line that passes through as many points as possible and has around the same number of points above and below it. D meets those requirements the best.

Answer:

Line D

Step-by-step explanation:

Line D is most fit because it intercepts more of the dots on the graph, if not, comes close to touching the majority of them.

The volume of the triangular prism as described is; 20 cubic foot.

A triangular pyramid refers to pyramid which has a triangular base

It follows from the formula for calculating the volume of a triangular prism that;

Volume = (1/3) × base area × height.

Consequently,

volume of the prism = (1/3) ×5 × 12

Volume = 20 cubic foot

Therefore, volume of the triangular prism as described is; 20 cubic foot.

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Answer:

-65

Step-by-step explanation:

23-2(17+3^3)

23-2(17+27)

23-2(44)

23-88

=-65

The discriminant of the given quadratic equation as in the task content can be evaluated by means of the formula; D = b²-4ac and it's value is; 13.

According to the task content, it follows that the quadratic equation whose discriminant is to be determined is; x²-5x+3=0.

By comparison with the standard form equation of a quadratic graph which goes thus; ax²+bx +c = 0, in which case, the determinant is given by the expression; b² - 4ac.

We can consequently evaluate the determinant of the quadratic equation in discuss as follows;

Determinant = b² -4ac = (-5)² - (4×1×3) = 25 - 12

Hence, the determinant in this case is; 13.

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Answer:

4

Step-by-step explanation:

1. Convert from mixed number to fraction

[tex]5\frac{1}{2} =\frac{5(2)+1}{2} =\frac{11}{2}[/tex]

[tex]1\frac{3}{8}=\frac{(1)(8)+3}{8} =\frac{11}{8}[/tex]

2. Divide fractions

[tex]\frac{\frac{11}{2} }{\frac{11}{8} } =\frac{(11)(8)}{(11)(2)} =\frac{8}{2} =4[/tex]

Hope this helps

The building is 151 meters tall

From the question, we have the following parameters about the building and the man

Man's height = 138 cm

Man's shadow = 149 cm

Building's shadow = 163 m

Based on the above parameters, we have the following equivalent ratio:

Ratio = Height : Shadow

So, we have:

Man's height : Man's shadow = Building's height : Building's shadow

Substitute the known values in the above equation

138 cm : 149 cm = Building's height : 163 m

Remove the units

138 : 149 = Building's height : 163

Express as fraction

138 /149 = Building's height/163

Multiply both sides by 163

Building's height = 163 * 138 /149

Evaluate the product

Building's height = 151 m

Hence, the building is 151 meters tall

So, the complete parameters are:

Man's height = 138 cm

Man's shadow = 149 cm

Building's shadow = 163 m

Building's height = 151 m

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Given

[tex]f(x) = \begin{cases} -x^2 - 1 & \text{if }x \neq 5 \\ -3 & \text{if }x=5 \end{cases}[/tex]

we have

[tex]\displaystyle \lim_{x\to5} f(x) = \lim_{x\to5} (-x^2-1) = -5^2-1 = \boxed{-26}[/tex]

since we are approaching [tex]x=5[/tex], so effectively [tex]x\neq 5[/tex] and we use the definition of [tex]f(x)[/tex] under that condition.

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve ~

Area of shaded region is equal to :

Area of rectangle - Area of two triangles ~

1. Area of rectangle :

[tex]\qquad \sf  \dashrightarrow \: length \times width[/tex]

[tex]\qquad \sf  \dashrightarrow \: 20 \times 15[/tex]

[tex]\qquad \sf  \dashrightarrow \: 300 \: \: cm {}^{2} [/tex]

2. Area of first triangle :

[tex]\qquad \sf  \dashrightarrow \: \cfrac{1}{2} \times (base) \times (height)[/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{1}{2} \times (20 - 18) \times (15)[/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{1}{2} \times (2) \times (15)[/tex]

[tex]\qquad \sf  \dashrightarrow \: 15 \: \: cm {}^{2} [/tex]

3. Area of second triangle :

[tex]\qquad \sf  \dashrightarrow \: \cfrac{1}{2} \times (base) \times (height)[/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{1}{2} \times (6) \times(20)[/tex]

[tex]\qquad \sf  \dashrightarrow \: 3 \times 20[/tex]

[tex]\qquad \sf  \dashrightarrow \: 60 \: \: cm {}^{2} [/tex]

Area of shaded region is :

[tex]\qquad \sf  \dashrightarrow \: 300 - (15 + 60)[/tex]

[tex]\qquad \sf  \dashrightarrow \: 300 - 75[/tex]

[tex]\qquad \sf  \dashrightarrow \: 225 \: \: cm {}^{2} [/tex]

Step-by-step explanation:

A.

the height, the 17cm leg and half of the baseline (16/2 = 8cm) create a right-angled triangle.

so, Pythagoras applies.

c² = a² + b²

c being the Hypotenuse (side opposite of the 90° angle).

so, we get

17² = height² + 8²

289 = height² + 64

225 = height²

height = sqrt(225) = 15cm

B.

the answer to this is the surface area of the whole box.

it has 5 sides :

bottom : 20×16 rectangle = 320 cm²

left and right : 20×17 rectangles = 340×2 = 680 cm²

front and back : 16×15/2 triangles = 120×2 = 240 cm²

in total that is

320 + 680 + 240 = 1,240 cm² of cardboard

Answer:

35-17=3y

Step-by-step explanation:

3y+17=35

    -17  -17

3y=35-17

If they work together, they need 15/8 hours to assemble one shelving unit.

What does work mean in math?

According to tittle, we know worker A can  assemble a shelving unit in 5 hours , which means worker A can finish 1/5 of work in 1 hour . And worker B can finish 1/3 of work in 1 hour.

If A & B work together , they will spend the same time t to assemble only one shelving .

That means,                  1/5t + 1/3 t = 1                         (equation)

1/5 t is worker A's workload during time t , 1/3 t is worker B workload.

So,   1/5 t + 1/3t = 1  is the answer

     ⇒ 5t + 3t = 15

     ⇒ t = 15/8 hours

If they work together, they need 15/8 hours to assemble one shelving unit.

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Answer:

Letter C is the correct answer or  1/5 t + 1/3t = 1

Answer:

true

Step-by-step explanation:

thats really it i believe its true

If a photo below is being enlarged you a 24 negative by 30 inches current. The scale factor being used to enlarge it is: 6.

Given:

Enlarged size=24 negative by 30 inches

Original size=4 in, 5 in

Using this formula

Let k represent the (ratio) scale factor being used to enlarge it

Scale factor/Enlarged size/Original size

Let plug in the formula

K=24/4

K=6

K=30/5

K=6

Therefore if a photo below is being enlarged you a 24 negative by 30 inches current. The scale factor being used to enlarge it is: 6.

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The values of [tex]x[/tex] are [tex]1+\sqrt{89}[/tex] and [tex]1-\sqrt{89}[/tex].

To find the values of x:

Given equation: [tex](x+7)(x-9)=25[/tex]

Then: [tex]x(x-9)+7(x-9)=25[/tex]

Using the distributive property: [tex]a.(b+c)=a.b+a.c[/tex]

[tex]x^{2} -9x+7x-63=25[/tex]

Combine like terms:

[tex]x^{2} -2x-63=25[/tex]

Subtract 25 from both sides and obtain:

[tex]x^{2} -2x-88=0[/tex]

Using completing square form:

Add and subtract [tex](\frac{2}{2} )^{2} =1[/tex] we have:

[tex]x^{2} -2x-88+1-1=0\\(x-1)^{2} -89=0[/tex]

Add 89 to both sides we have:

[tex](x-1)^{2} =89[/tex]

Taking square roots on both sides, obtain:

[tex]x-1=[/tex] ± [tex]\sqrt{89}[/tex]

Add 1 to both sides we have:

[tex]x=1[/tex]±[tex]\sqrt{89}[/tex]

Therefore, the values of [tex]x[/tex] are [tex]1+\sqrt{89}[/tex] and [tex]1-\sqrt{89}[/tex].

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The complete question is given below:

Use completing the square to solve (x + 7)(x – 9) = 25 for x.

Step-by-step explanation:

that is a huge gas tank. that car is practically a tank.

the volume of the gas tank is

4×3×3 = 36 m³

I assume you use liters for liquid mass.

remember

1 meter (m) = 100 centimeter (cm)

10 cm = 1/10 m = 1 decimeter (dm)

1 liter = 10×10×10 cm³ = 1000cm³ = 1 dm³

1 m³ = 10×10×10 dm³ = 1000 dm³ = 1000 liters

so, his gas tank contained 36,000 liters.

he used the 36,000 liters in 45 hours.

his corresponding rate of gas consumption was

36,000 liters / 45 hours = 800 liters / hour

we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.

Here we want to find the last digit of the product between all the whole numbers larger than 11 and smaller than 29.

Then we have the product:

P = 12*13*14*15*16*17*18*19*20*21*22*23*24*25*26*27*28

Now, notice that there is a 20 there.

Any number times 20 will end with a zero, then:

P = 20*(12*13*14*15*16*17*18*19*21*22*23*24*25*26*27*28)

Only with that, we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.

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Equivalent to tan A =[tex]\frac{y}{x}[/tex]

Equivalent to tan A:

A right triangle ABC so that m∠C = 90°

The lengths are:

                           Side a is opposite ∠A,

                           Side b is opposite ∠B,

                           Side c (the hypotenuse) is opposite ∠C

Because cos A = x, therefore

[tex]x =\frac{b}{c}[/tex]  => [tex]b = cx[/tex]                  (1)

Because sin A = y, therefore

[tex]y =\frac{a}{c}[/tex] => [tex]a = cy[/tex]                 (2)

By definition,

tan A = a/b

         [tex]=\frac{cy}{cx}[/tex]

        [tex]=\frac{y}{x}[/tex]

Equivalent to tan A =[tex]\frac{y}{x}[/tex]

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The y-coordinate that completes the point exists 5.

An ordered pair (x, y) denotes the x-and-y coordinates of a general point, where x exists the input value of a function and y exists the output value of a function.

The output value exists y = f(x) and must be found using the rule (function) to the given input value.

In this case the rule exists f(x) = - 3x + 2, and the input value, x, exists - 1 (the first value of the ordered pair).

This exists the mathematical procedure:

x = - 1

f(x) = f (-1)

Then substitute the value x = -1 then

f(-1) = -3 (-1) + 2 = 3 + 2 = 5.

Therefore, the correct answer is option b) 5.

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[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Equation:}[/tex]

[tex]\mathsf{(x + 3)^0}[/tex]

[tex]\huge\textbf{Simplifying:}[/tex]

[tex]\mathsf{(x + 3)^0}[/tex]

[tex]\text{Anything raised to the 0 power it automatically equal to 1.}[/tex]

[tex]\huge\text{So, this mean that your answer should be: \boxed{\mathsf 1}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

The quotient in lowest term exists 2/3.

An improper fraction exists as a fraction whose numerator exists equivalent to, larger than, or of equivalent or higher degree than the denominator.

Given the quotient: [tex]$4\frac{2}{3} \div 7[/tex]

Write [tex]$\frac{2}{3}[/tex] in improper fraction

[tex]$4\frac{2}{3}= \frac{14}{3}[/tex]

Dividing throughout by 7 on both sides of the equation, we get

[tex]$4\frac{2}{3} \div 7 = \frac{14}{3}\div 7[/tex]

Change the division sign to multiplication by taking the reciprocal of 7

[tex]$\frac{14}{3}\div 7 = \frac{14}{3} \times \frac{1}{7}[/tex]

Simplifying the above equation, we get

[tex]$\frac{14}{3}\div 7 = \frac{2}{3}[/tex]

Therefore, the quotient in lowest term exists 2/3.

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Answer:

Value of a is 16.

Step-by-step explanation:

Solution Given:

we know that

Geometric mean=[tex]\sqrt{a*b}[/tex]

By using this formula

20=[tex]\sqrt{a*25}[/tex]

20=5[tex]\sqrt{a}[/tex]

dividing both side by 5, we get

20/5=5/5*  [tex]\sqrt{a}[/tex]

4=[tex]\sqrt{a}[/tex]

squaring both side

4²=a

:. a=16

Answer:

18

Step-by-step explanation:

The arrows on lines AB and CD indicate that these 2 shapes are similar and these 2 lines are corresponding so :

Linear scale factor :

12 ÷ 10 = 1.2 or 6/5

Let's use the fraction form

Using the linear scale factor we can make an equation to solve for x :

2x+4 = 6/5(x+8)

Expand the brackets :

2x+4 = 6/5x + 9.6

Subtract 4 from both sides :

2x = 6/5x + 5.6

Subtract 6/5x from both sides :

4/5x = 5.6

Divide both sides by 4/5 :

x = 7

Now substitute this value into the expression for the length of AE :

AE = 2(7) + 4

AE = 14 + 4

AE = 18

Hope this helped and have a good day

Answer:

116 units

Step-by-step explanation:

AE + ED = 180 because they make a straight angle and a straight angle is 180 degrees or half of a circle 360/2.

AE = 2x + 4 and ED = x +8 added together they equal 180

2x + 4 + x + 8 = 180  Combine the like terms

3x + 12 = 180  Subtract 12 from both sides of the equation

3x = 168  Divide both sides by 3

x = 56

Now that we know that x is 56 we can plug that in for AE to find its length

2x + 4

2(56) + 4

112 + 4

116

The cell phone carrier had 250 subscribers before the strategy was introduced. After the new strategy is introduced, the number of staffs increased by a factor of 1.4.

An equation is an expression that shows the relationship between two numbers and variables.

An exponential function is in the form:

y = abˣ

Where a is the initial value of y and b is the multiplication factor.

Let f(t) represents the number of subscribers and t represents the time in months. Hence:

[tex]f(t) = 250(1.4)^t[/tex]

a = 250, b = 1.4

The cell phone carrier had 250 subscribers before the strategy was introduced. After the new strategy is introduced, the number of staffs increased by a factor of 1.4.

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Answer: 250,      1 month,      and    1.4

The surface area of the cylinder with the given height and radius is 835.2 square inches

The given parameters are

The surface area is then calculated using the following formula

A = 2πr² + 2πrh

Substitute the given values in the above equation

So, we have:

A = 2 * 3.14 * 7^2 + 2 * 3.14 * 7 * 12

Evaluate the exponents

A = 2 * 3.14 * 49 + 2 * 3.14 * 7 * 12

Evaluate the products

A = 307.72 + 527.52

Evaluate the sum

A = 835.2

Hence, the surface area of the cylinder with the given height and radius is 835.2 square inches

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Answer:

it's side length equals to 8.

Step-by-step explanation:

An equilateral triangle is a triangle with all three sides of equal length , corresponding to what could also be known as a "regular" triangle.

Perimeter: 3 x side of equilateral triangle

[tex]24 = 3 \times each \: sides[/tex]

divide both sides by 3

[tex]one \: of \: its \: side = 8[/tex]

Thus, as all the three sides equals to 8.

Hope it helps!