a) The angular acceleration of a disk is 2.0 rad/s².
b) The average angular velocity of the disk is 5 rad/s.
What is angular acceleration?The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second.
Rotational acceleration is another name for angular acceleration. It is a numerical representation of the variation in angular velocity over time.
A pseudoscalar, angular acceleration, exists. If the angular speed rises counterclockwise, the sign of angular acceleration is taken to be positive; if it grows clockwise, it is taken to be negative. Angular acceleration is used to study the motion of rotating objects like the wheel, fan, and earth.
Assume that the sense of rotation is positive.
This means that w, α, and other quantities will then be positive also.
a) we know,
25 rad = 1/2 α 5²
α = 2.0 rad/s²
∴ the angular acceleration of a disk is 2.0 rad/s².
b) w avg = Δθ/Δt
w avg = 25rad/5s
w avg = 5rad/s
∴ the average angular velocity of the disk is 5 rad/s.
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3. how are the voltage and current related? are they in phase or out of phase? what is the phase angle between the voltage and the current?
The voltage and current are related is to resistive circuit.
What is resistive circuit?
In a fully resistive circuit, current and voltage are in phase, and the power factor is 1. In a circuit where the current lags the voltage by 90 degrees, the power factor is zero trailing. The current leads the voltage in a completely capacitive circuit by 90 degrees, and the power factor is zero.
What is the relationship between the phases of voltage and current?
Current and voltage in a pure resistive circuit are in phase with one another. Thus, the peak values of both the current and the voltage will occur simultaneously.
Therefore, the phase angle between the voltage and the current is, capacitive circuit by 90 degrees, and the power factor is zero.
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the engine of a locomotive exerts a constant force of magnitude 6.5 105 n to accelerate a train to 60 km/h. determine the time taken for the train of mass 1.4 107 kg to reach this speed from rest.
The time taken for the train of mass 1.4 107 kg to reach the speed of 60 km/h is 362.39 seconds
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
mass of the train = 1.4 × 10⁷ kg
constant force F = 6.5 × 10⁵ N
Using Newton's second law
F = ma
a = F/m
= 6.5 × 10⁵ N /1.4 × 10⁷ kg
= 0.046 m/s²
This acceleration accelerates from
initial velocity u = 0
Final velocity v = 60 km/hr = 16.67 m/s
Using,
V = U + at
t = V - U/a
= 16.67 / 0.046
= 362.39 seconds
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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a ball is kicked with an initial velocity of 23 m/s in the horizontal direction and 14 m/s in the vertical direction. (assume the ball is kicked from the ground. for each answer, enter a number.) (a) at what speed (in m/s) does the ball hit the ground? m/s (b) for how long (in s) does the ball remain in the air? s (c) what maximum height (in m) is attained by the ball?
The speed of the ball is 192m/s. The long of the ball is 2.85s.The height of the ball is 2.13m.
How to calculate speed?A)The speeds at these points are equal since the starting position and the point at which it touches the ground have the same elevation. Solving the product of the horizontal and vertical velocities yields the final speed. Which is
vf=√(V[tex]ox[/tex])²+(V[tex]oy[/tex])²
vf=√(23m/s)²+(14m/s)²
vf=192m/s
How to calculate long?B)Take into account the starting point and the highest point, respectively.
We are aware that the vertical velocity is zero at the highest point. Additionally, we are aware that the duration of the flight from start to finish is twice as long.
So, we'll apply the formula t=v[tex]f[/tex]-v[tex]o[/tex]/a
t=2(v[tex]top[/tex]-v[tex]o[/tex])/a
t=2(0m/s-14m/s)/-9.81m/s
t=2.85s
How to calculate height?C)Using the formula, the highest height that can be reached can be determined.(v[tex]f[/tex])²=(v[tex]0[/tex])²+2ay
This is how the maximum height is determined:
(v[tex]f)[/tex]²=(v[tex]0)[/tex]²+2ay
y[tex]max[/tex]=(v[tex]top[/tex])²-(v[tex]o[/tex])²÷2a
y[tex]max[/tex]=(0m/s)²-(14m/s)²÷2(-9.81m/s)²
=2.13m
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a roller coaster moves 85 m horizontally, then travels 45 m at an angel of 30 above the horizontal. what is its displacement from its starting point? use graphical techniques.
Explanation:
done with the meeting today so I m ready for bed k tai you
Answer:
Explanation:
Dx = 85 + 45·cos 30° = 85 + 45·(√3 / 2) ≈ 124 m
Dy = 45·sin 30° = 45·(1/2) = 22.5 m
D = √ (Dx² + Dy²) = √ (124² + 22.5²) ≈ 126 m
A 30.0 kg object is falling in air and experiences a force due to air resistance of 50.0 N. What is the net force acting on the object?
Answer:
250N
Explanation:
weight of object - air resistance= net force
weight=mg
=30×10
=300N
air resistance =50
300-50=250
a 1,200 kg car can accelerate with a force of 3,000n. if the car is stopped at a red light and then accelerates for 15 s after the light turns green, how far (in m) will the car be from the light?
Acceleration: the rate at which the speed and direction of a moving object vary over time.A point or object going straight ahead is accelerated when it accelerates or decelerates.
Find the Acceleration ?Three different accelerated motion types exist: average acceleration, non-uniform acceleration, and uniform acceleration.
a = F / m
1 N = 1 kg•m/s²
F = ma; where F = force in newtons (N), m = mass in kg, and a = acceleration in m/s².
Known and Unknown
F = 3000 N = 3000kg•m/s²
m = 1200 kg
a = F/m
a = (3000 kg•m/s²)/(1200 kg)
Kilograms cancel.a = 2.5m/s²
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Insulators can by charged only by this method
a. Induction
b. Conduction
c. Friction
Insulators can by charged only by friction.
An electrical insulator is a cloth wherein electric powered modern-day does no longer drift freely. The atoms of the insulator have tightly certain electrons which can not quite simply move. Other substances—semiconductors and conductors—conduct electric modern greater effortlessly.
Insulators are used in electric system to help and separate electrical conductors with out allowing current thru themselves. An insulating material utilized in bulk to wrap electrical cables or other gadget is known as insulation. The time period insulator is likewise used greater specially to consult insulating supports used to utility poles and transmission towers.to attach electric powered strength distribution or transmission lines
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A 440 hz tuning fork is used with a resonting colum to detemine the velocity of sound in helium gas . if the spacing between resonances in 110cm , what is the velocity of sound in helium gas?
The velocity of sound in helium gas is 968 m/s if the spacing between resonances is 110cm.
We have to go from antinode to antinode. In an air column, the spacing between resonance is wavelength /2 as we have to go from antinode to antinode.
wavelength = 220 cm = 2.2m
As we know the velocity formula
Then Velocity = f * λ
Where f is the frequency and λ is the wavelength.
So Velocity of wave = 440 * 2.2 = 968m/s
Hence, the velocity of sound in helium gas is 968 m/s if the spacing between resonances is 110cm.
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the weight of the builder and new roof tiles is 640N. draw a diagram to calculate the components of the total weight parallel and perpendicular to the slope of the roof
Answer:
Explanation:
is there a diagram of the question?
The parallel component of the total weight is 320 N and the perpendicular component of the total weight is 554.3 N.
What are the components of the Total weight?The components of the total weight of the builder and the new roof tile which may be of two types, i.e. parallel components or perpendicular components.
The parallel component and new roof tiles can be calculated as;
Fn ( parallel ) = W sin ( θ )
where;
W is the total weight
θ is the slope or angle of inclination of the total weight
So,
Fn ( parallel ) = 640 sin ( 30 )
Fn ( parallel ) = 320 N
The perpendicular component and new roof tiles is calculated as follows;
Fn ( parallel ) = W cos ( θ )
where;
W is the total weight
θ is the slope or angle of inclination of the total weight
So,
Fn ( perpendicular ) = 640 cos ( 30 )
Fn ( perpendicular ) = 554.3 N
Thus, the parallel component of the total weight is 320 N and the perpendicular component of the total weight is 554.3 N.
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Your question is incomplete, most probably the complete question is :
The weight of the builder and new roof tiles is 640 N. The slope is at 30 degrees on the given diagram. Draw a diagram to calculate the components of the total weight parallel and perpendicular to the slope of the roof.
if an alpha particle (2 protons) experiences an electric force of 0.250 n at a point in space, what electric force would a proton experience at the same point?
electric force would a proton experience at the same point is .156 × 10⁻¹⁹ N/C.
Electric field :
The electric field is the amount of electric force per charge, and the electric force on a charge at a given point in space is the amount of charge multiplied by the electric field at that location.
E = F/q
where,
E = electric field
F = force
q = charge
A force experienced by an alpha particle = 0.250N
E = F/q
E = 0.250 /1.6 × 10⁻¹⁹
E = 0.156 × 10⁻¹⁹ N/C
electric force would a proton experience at the same point is .156 × 10⁻¹⁹ N/C.
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How many moles of CaCo2 are in 50g of calcium carbonate
an inelastic collision between two objects is characterized by the following a) total momentum of the system is conserved b) total energy of the system is conserved c) total kinetic energy of the system remains constant d) both a and b are true e) both a and c are true
An inelastic collision between two objects is characterized by the fact that a) the total momentum of the system is conserved. Choice A is correct
Inelastic collisions are the collisions in which the kinetic energy is lost. The momentum of the system is conserved in inelastic collisions, but kinetic energy is not. This is because some of the kinetic energy was transferred to another.
Suppose two similar cars are approaching. They collide, but the sled is equipped with a magnetic clutch so that when they collide they combine into a single agglomerate. This type of collision is completely inelastic as the maximum possible kinetic energy is lost. This does not mean that the final kinetic energy of the system is necessarily zero. Momentum is not yet maintained.
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Mars has an orbital period of 4333 earth days, find the semi major axis of it's orbit
Answer:372
Explanation:
a proton moves at constant velocity in the y direction, through a region in which there is an electric field and a magnetic field. the electric field is in the x direction, and has magnitude 400 v/m. the magnetic field is in the -z direction, and has magnitude 0.65 t.what is the magnitude of the net force on the proton?
The magnitude of the net force on the proton is 0.
What happens when the net force is zero?An object with zero net force will either remain stationary if initially stationary or maintain a constant velocity.
Fₙ = F₁ - F₂
Fₙ = Net force
F₁ and F₂ are applied forces
Now, F = ma
0 = ma
a = 0
Since acceleration is zero this implies that the object is moving with a constant velocity.
For the given case,
The proton is moving with a constant velocity along the y direction, which means the acceleration is zero. So, the net force is:
Fₙ = ma
Fₙ = m × 0
Fₙ = 0
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the picture tube in a television uses magnetic deflection coils rather than electric deflection plates. suppose an electron beam is accelerated through a 55.0 -kv potential difference and then through a region of uniform magnetic field 1.00 cm wide. the screen is located 6.0 cm from the center of the coils and is 60.0 cm wide. when the field is turned off, the electron beam hits the center of the screen. what field magnitude is necessary to deflect the beam to the side of the screen? ignore relativistic corrections.
The field magnitude required to divert the beam away from the screen is 3.1588 × [tex]10^{-4}[/tex].
A magnetic force is applied to a charged particle when it enters a magnetic field. This force's strength is determined by the particle's speed, magnetic field, and charge density. Fleming's Left Hand Rule determines the force's direction. The component of the velocity transverse to the magnetic field provides the required centripetal force if the charged object arrives at an angle.
V = 55.0 kV
d = 1.00cm
Tan∅ = ((1 ÷ 2) × 60) ÷ 6.0 = 5
∅ = 26.6°
Sin∅ = 1 ÷ R
R = 1 ÷ Sin(26.6°)
R = 1 ÷ 0.44
R = 2.27
Total work completed equals Kinectic Energy change
1 ÷ 2 mv² = qΔV
0.5 × 9.1 × [tex]10^{-31}[/tex] × v² = 1.6 × [tex]10^{-19}[/tex] × 55.0 × [tex]10^{3}[/tex]
v² = (8.8 × [tex]10^{-15}[/tex]) ÷ (4.55 × [tex]10^{-31}[/tex])
v² = 1.93 × [tex]10^{16}[/tex]
v = √1.93 × [tex]10^{16}[/tex]
v = 138924439
v = 1.3 × [tex]10^8[/tex]
The magnetic force produces the centripetal force.
qvB = mv² ÷ R
B = (mv ÷ qR)
B = (9.1 × [tex]10^{-31}[/tex] × 1.3 × [tex]10^8[/tex]) ÷ (1.6 × [tex]10^{-19}[/tex] × 2.27)
B = (11.83 × [tex]10^{-23}[/tex]) ÷ (3.745 × [tex]10^{-19}[/tex])
B = 3.1588 × [tex]10^{-4}[/tex]
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A 0. 0850-kg arrow is fired horizontally. If the bowstring exerts an average force of 89. 0 n on the arrow over a distance of 0. 782 m, with what speed does the arrow leave the bow?.
The arrow leaves the bow at a speed of 40.47 m/s.
When the arrow is released from its bow, the arrow will move and accelerate. Newton's second law of motion applies to the arrow. The formula F = ma
m = mass of the arrow (kg) = 0.0850 kga = acceleration of the arrow (m/s²)F = force (N) = 89.0 N[tex]a \:=\: \frac{F}{m}[/tex]
[tex]a \:=\: \frac{89.0}{0.0850}[/tex]
a = 1,047.059 m/s²
When the object has acceleration, the object will move in a non-uniform motion. The formula
v = u+atv² = u² + 2ad[tex]d \:=\: v_0 \times t \:+\: \frac{1}{2} \times a \times t^2[/tex]u = initial speed (m/s) = 0 m/s (arrow stationary in bowstring)v = final speed (m/s) a = acceleration (m/s²) = 1,047.059 m/s²t = interval (s)d = distance (m) = 0.782 mv² = u² + 2ad
v² = 0² + (2×1,047.059×0.782)
v² = 1,637.6
[tex]v_t \:=\: \sqrt{1,637.6}[/tex]
[tex]v_t[/tex] = 40.47 m/s
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Michael uses his bike to apply 456 N to himself and the bike by pedaling as he approaches a 1.4 m tall ramp which is 3.0 m away. He starts from rest to accomplish this feat. How fast will he be moving just before he hits the ramp? (Mike and the bike have a combined mass of 136 kg)
*WORK OUT AND USE UNITS*
The speed of Mike and his bike before hitting the ramp is 4.48 m/s.
What is the acceleration of Michael and his bike?The acceleration of Michael and his bike is determined by applying Newton's second law of motion as follows.
According this law, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
a = F/m
where;
a is the acceleration of Michaelm is mass of Michaela = (456) / (136)
a = 3.35 m/s²
The speed of Mike and his bike before hitting the ramp is calculated as follows;
v² = u² + 2as
where;
u is the initial speed of Mike = 0a is acceleration of Mikev is the final velocity of Mikes is the distance travelled by Mikev² = 0 + 2(3.35)(3)
v² = 20.1
v = √20.1
v = 4.48 m/s
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if at a particular instant and at a certain point in space the electric field is in the x-direction and has a magnitude of 5.00 v/m , what is the magnitude of the magnetic field of the wave at this same point in space and instant in time? express your answer in teslas.
The magnitude of the magnetic field of the wave at this same point in space and instant in time is 1.67 × 10 ⁻⁸ T
The direction of the electric field is pointing in the positive x direction and the direction of propagation of the wave is in the positive z direction. Therefore, the direction of the magnetic field is in the positive y direction. Because in an electromagnetic wave, the direction of the electric field, the direction of wave propagation, and the magnetic field all lie perpendicular to each other.
According with the right-hand rule, the thumb points within the route of the current, the hands factor inside the course of the magnetic subject, and the resulting pressure at the charge points outwards from the palm. The pressure on a negatively charged particle is inside the opposite path.
Calculation:-
B₀ = E₀/c
= 5 / 3 × 10⁸
The magnitude of the magnetic field is equal to = 1.67 × 10 ⁻⁸ T
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A source vibrating at constant frequency generates a sinusoidal wave on a string under constant tension. If the power delivered to the string is quadrupled, by what factor does the amplitude change?.
If the power is quadrupled, The amplitude changes by factor of 2 means double.
What is meant by Amplitude?The greatest displacement or distance moved by a point on a vibrating body or wave from its equilibrium position. It is one-half of the length of the vibration path.
Given,
If the amount of power applied to the string is quadrupled.
The power transmitted by a sinusoidal wave on a stretched string formula is,
P=[tex]1/2[/tex](μω²A²v)
Where μ mass per unit length
ω=angular speed
A= amplitude
v=wave speed
P=power delivered.
We only need two terms in this case: power and amplitude.
P∝ A²
For our problem, all other quantities are constant.,
A= k √P
Where k= constant
Power is quadrupled here, which means four times.,
A=√4P
A=2√P
Changing the amplitude by a factor of two means doubling.
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Question 1 of 10
What type of diagram is used to show all of the forces acting on an object?
A. Stability diagram
B. Algebraic diagram
C. Free-body diagram
D. Potential energy diagram
Answer:
c. Free body diagram
Explanation:
Free-body diagrams are diagrams used to show the relative magnitude and direction of all forces acting upon an object in a given situation.
You are bowling for a spare. There is just one pin left, and you make a nice play. As the 5.1 kg ball approches at a velocity of 3.40 m/s north it hits the pin! The 1.5 kg pin is sent into motion and the bowling ball continues to roll at a velocity of 0.87 m/s north. What is the final velocity of the pin?
Answer:
11.56 m/s
Explanation:
The momentum of the ball is transferred into the pin so the transfer of momentum has the formula, m1*v1 = m2 * v2
substituting the values,
5.1 * 3.40 = 1.5 * V2
17.34 = 1.5 * V2
V2 = 17.24 / 1.5
V2 = 11.56 m/s
a bullet fired from a rifle begins to fall when?
Answer: As soon as it leaves the barrel.
Explanation:
A bullet fired from a rifle begins to fall immediately upon leaving the barrel. Despite its initial forward momentum, the bullet is subject to the force of gravity.
The gravitational force acts vertically downward and causes the bullet to accelerate downward due to its free fall. However, due to its initial high velocity, the bullet's downward acceleration is minimal compared to its forward motion. As a result, the bullet follows a curved trajectory known as a ballistic trajectory.
Over time, the effects of gravity become more significant, causing the bullet to gradually descend and eventually hit the ground, following a parabolic path.
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a description of one real-life problem that has to be solved or decision that has to be made
Your example may be an example from your life or an imaginary example.
Your description should include three obstacles from the list below related to solving the problem or making a decision.
belief perseverance
confirmation bias
counterproductive heuristics
framing effect
fixation
functional fixedness
overconfidence
a brief explanation related to how the obstacles you described were overcome, or how each obstacle could be overcome in the future
A description of Benson's real-life problem that has to be solved is below:
Benson, a final year medical student shared a reflection of his past problems before gaining admission into the higher institution.
His power driven message to those who wish to overcome their obstaclesI have cried countless times as a result of my failures in the past. Sometimes when I was still in my high school, I was too overconfident in myself as to the level of my intelligence in class. This continued to the extent at which I stopped attending classes and at the end all these, I was shocked to receive the news that I had failed GSCE results.
I was mocked by all and sundry and humiliated. I repeated this exams for 5 years. Solving this problem made me remain on a fixed point and became a tool of fixation of failure to myself and those that were following my footsteps back in highschool.
Thank goodness for my father who stood by me in all my trials and injected me with alot of belief perseverance that I will come out of this problem and live my dream of becoming a medical doctor. Finally, I conquered the situation after many years and later continue my pursuit to apply for medicine and surgery in higher institution.
So therefore, it can be deduced from all said and done above that: you are what has happened to you. Take responsibility for your problems.
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Jamari is doing a project on the levels of the rain forest. Which would be the most useful visual display to help make his information clear?(1 point)
Responses
a map of where rain forests are located
a map of where rain forests are located
a diagram with the parts of the rainforest labeled
a diagram with the parts of the rainforest labeled
a video of a nature photographer walking in a rain forest
a video of a nature photographer walking in a rain forest
a picture of ants on the rainforest floor
It is a diagram with the parts of the rainforest labeled
what is the final velocity (in m/s) of a hoop that rolls without slipping down a 5.00-m-high hill, starting from rest?
The final velocity (in m/s) of a hoop that rolls without slipping down a 5.00-m-high hill, starting from rest will be 31.30 m/s
given
initial velocity = 0
displacement = s = 50 m
using kinematics equation
2as = [tex]v^{2} - u^{2}[/tex]
2* (g) * s = [tex]v^{2}[/tex] - 0
[tex]v^{2}[/tex] = 2 * (9.8) * 50
v = 31.30 m/s
The final velocity will be v = 31.30 m/s
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A 25.0 kg mass is traveling to the right with a speed of 3.00 m/s on a smooth horizontal surface when it collides with and sticks to a second 25.0 kg mass that is initially at rest but is attached to one end of a light, horizontal spring with force constant 190.0 n/m. the other end of the spring is fixed to a wall to the right of the second mass. what is the frequency?
The frequency of the given mass is 0.31Hz.
Frequency:
the term frequency refers to the number of waves that pass a fixed point in unit time. It also describes the number of cycles or vibrations undergone during one unit of time by a body in periodic motion.
Here we have to find the frequency.
Formula to find the frequency:
f = ω /2π
ω = [tex]\sqrt{\frac{k}{M} }[/tex]
= [tex]\sqrt{\frac{190}{50} }[/tex]
= 1.95
Now putting the values we have
f = 1.95/ 2π
= 0.31 Hz
Therefore the frequency is 0.31Hz.
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It is typical for people in hypnotic trances to temporarily __________. a. begin speaking languages they do not know b. lose track of their immediate surroundings c. become aware of past lives and buried memories d. feel completely paralyzed and unable to act please select the best answer from the choices provided a b c d
It is typical for people in hypnotic trances to temporarily begin speaking languages they do not know .
Option a is correct
Who are people when they are hypnotized?Although hypnosis is frequently described as a sleep-like condition, it is actually better described as a state of sharpened focus, increased suggestibility, and vivid fantasies. People who are hypnotized frequently appear tired and disoriented, yet they are actually hyperaware.
What transpires while a person is tranced?Our brain waves must slow down in order to enter a trance. Throughout the course of the day, people alternate between several brain wave states. Different stages of the brain wave include sleeping, daydreaming, and being fully alert and focused.
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a baseball and a bowling ball with the same momentum are rolling toward you. which one needs more efforts (either longer time or larger force) to be stopped?
The baseball will require longer time and the bowling ball will require more effort to be stopped.
The bowling ball and baseball is moving with same momentum.
Let us say the momentum of the bowling ball is MV and the momentum of the baseball is mv.
According to second law of newton,
F = ΔMV/Δt
F = MΔv/Δt
So, the force is directly proportional to the speed of the object.
The speed of the bowling ball will be less than that of the baseball because the mass of the bowling ball is more and the mass of the baseball is less.
So, a greater force will be required to stop the baseball ball,
F = mΔv/Δt
v is more and the contact period Δt of the transfer of momentum is less so baseball will require longer time and a grater force will be required to stop the bowling ball because the speed is less.
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If the gravity of the moon is 1/6 of Earth’s gravity, what is the mass of an object that has a weight of 115N on the moon? a)89 b)71.9 c)30.2 d)20
it's 115/6 which is 19.1667
Explanation:
The weight would be 115/6 because the moon has one sixth of the gravity on earth so the weight would be on sixth of that on earth.
a 5000 kg airplane is flying a circle with a diameter of 1 km as shown below in the figure. it takes the airplane 30 seconds to complete a trip around the circle. what is the angle of incline of the plane?
The angle of incline of the plane is 65.9°.
What exactly are inclination and plane?A basic device called an inclined plane with a sloping surface is used to lift heavy objects. Even after accounting for friction, the force needed to lift an object up an incline is less than the weight being raised. The needed force approaches the real weight closer with a greater slope or gradient.
m = 5000 kg
F =force by air
Diameter of circle
D = 1000m
R = D/₂ = radius of circle
Fcosθ =mg----1
Fsinθ = mw² R
Fsinθ = mw² R---2
from 1 and 2 ( divide 2 by 1)
tanθ = w² R/g = 4 πR/T²g
tanθ = 4 π 500/30²×9.8
tanθ = 29.236
θ = tan⁻¹(29.236) = 65.9°.
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