Step 1: For each circle (A-G) in the table below, use the given information to determine the missing
information. Include supporting work showing and explaining how you found the missing information.
Circle
Center
Radius
Equation
A
(x - 9)2 + (y - 12)2 = 64
B
(-1,-17)
5
С
(-9,13)
9n
D
x2 + (0 - 1)2 = 36
E
x2 + y2 – 26x = -160
F
*2 + y2 + 22x +12y = -93
G
x2 + y2 – 10x+12y = -52

Answer:

The answer is "sometimes".

Step-by-step explanation:

A one-way ANOVA was merely performed on one collected data and the null hypothesis was rejected after an ANOVA F test. Assume we could randomize ANOVA block design with the same information. This null hypothesis for full equality is sometimes rejected for the randomized complete block design ANOVA. Therefore we understand the use of randomized ANOVA block if the null hypothesis is denied of a one-way ANOVA but the rejection of a null RBD ANOVA hypothesis isn't conditional mostly on denial of the yet another ANOVA null.

Answer:

y = 480 + 1.5 (x-40)

Step-by-step explanation:

sometimes its better to answer the question and make the formula from that

40 x 12 = 480

1.5 for overtime

x

y = 480 + 1.5 (x-40)

Answer:

I am assuming that you meant to write π/5.

Step-by-step explanation:

Radius r = 5 meters

Circumference = 2πr = 10π

Central angle θ = π/5 radian

Arc length = 10π × θ/(2π radians)

= 5θ

= π meters

Answer:

[tex]Drink = 354.882\ mL[/tex]

Step-by-step explanation:

Given

[tex]Drink = 12oz[/tex]

Required

Equivalent in mL

We have:

[tex]1\ oz = 29.5735\ mL[/tex]

So:

[tex]Drink = 12 * 29.5735mL[/tex]

[tex]Drink = 354.882\ mL[/tex]

Answer:

3,200

Step-by-step explanation:

3 is less than 5 so you round down to 3,200

Answer:

[tex]Weighted\ Average = 73[/tex]

Step-by-step explanation:

Given

[tex]Lab = 21\%[/tex]

[tex]Tests = 25\%[/tex]

[tex]Exam = 29\%[/tex]

[tex]Lab\ Score = 60[/tex]

[tex]First\ Test = 81[/tex]

[tex]Second\ Test = 69[/tex]

[tex]Exam = 79[/tex]

Required

The weighted average

To do this, we simply multiply each score by the corresponding worth.

i.e.

[tex]Weighted\ Average = Lab\ worth * Lab\ score + Tests\ worth * Tests\ score.....[/tex]

So, we have:

[tex]Weighted\ Average = 21\% * 60 + 25\% * 81 + 25\% * 69 + 29\% * 79[/tex]

Using a calculator, we have:

[tex]Weighted\ Average = 73.01[/tex]

[tex]Weighted\ Average = 73[/tex] --- approximated

Answer:

50.24 or 50.272

Step-by-step explanation:

Square radius and then times by 3.14 or 3.142

4^2*3.14 = 50.24

4^2*3.142 = 50.272

Answer:

Remember that the division by zero is not defined, this is the criteria that we will use in this case.

1) [tex]\frac{y^2 - 1}{y} + \frac{y}{y - 3}[/tex]

So the fractions are defined such that the denominator is never zero.

For the first fraction, the denominator is zero when y = 0

and for the second fraction, the denominator is zero when y = 3

Then the fractions exist for all real values except for y = 0 or y = 3

we can write this as:

R / {0} U { 3}

(the set of all real numbers except the elements 0 and 3)

2) [tex]\frac{b + 4}{b^2 + 7}[/tex]

Let's see the values of b such that the denominator is zero:

b^2 + 7 = 0

b^2 = -7

b = √-7

This is a complex value, assuming that b can only be a real number, there is no value of b such that the denominator is zero, then the fraction is defined for every real number.

The allowed values are R, the set of all real numbers.

3) [tex]\frac{a}{a*(a - 1) - 1}[/tex]

Again, we need to find the value of a such that the denominator is zero.

a*(a - 1) - 1 = a^2 - a - 1

So we need to solve:

a^2 - a - 1 = 0

We can use the Bhaskara's formula, the two values of a are given by:

[tex]a = \frac{-(-1) \pm \sqrt{(-1)^2 + 4*1*(-1)} }{2*1} = \frac{1 \pm \sqrt{5} }{2}[/tex]

Then the two values of a that are not allowed are:

a = (1 + √5)/2

a = (1 - √5)/2

Then the allowed values of a are:

R / {(1 + √5)/2} U {(1 - √5)/2}

Answer:

W = 4.95

Step-by-step explanation:

You want to start by writing down what you know, and forming a system of equations.

L= length W= width

2L+2W=14.7    

L= 2.4

On the left side of the equation, you're adding all your side lengths, and on the right, is the total perimeter. (Also could be written L+L+W+W = 14.7)

You would then substitute L from the bottom equation into the top equation to get:

2(2.4) +2W=14.7

Solving:

4.8+2w=14.7

W= 4.95

To check your answer simply add all the sides together and make sure it equals your perimeter. You can also plug W and L back into the original equation.

Answer:

C: 44

Step-by-step explanation:

Answer:

48.45in

Step-by-step explanation:

To get the height of Dakota, we will use the SOH CAH TOA

Given the following

angle of elevation = 39degrees

distance from the top of Dakotas head to the tip of the shadow = 77in (Hyp)

Required

Height of Dakota (Opp)

Sin 39 = opposite/hyp

Sin39 = H/77

H = 77sin39

H = 77(0.6293)

H = 48.45in

Hence the Dakota is 48.45in

Answer:

Hope this helps!

Answer:

188 degrees

Step-by-step explanation:

The measure of the arc is the center angle, that is double of the circumference one

94 * 2 = 188 degrees

Answer:

16X+134

Step-by-step explanation:

Answer:

60 miles/hour

Step-by-step explanation:

960÷16

=60 hours

Step-by-step explanation:

2nd number = x

1st number = x - 7

5 (x - 7) = 6x + 9

5x - 35 = 6x + 9

- x = 44

x = - 44

1st number = -51

2nd number = -44

Proof: 5 (-51) = 6(-44) + 9

-255 = -264 + 9

-255 = -255

hope it helps.

Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.

Answer:

Step-by-step explanation:

If X is a normal random variable with a mean of 6 and a standard deviation of 3.0, then find the value x such that P(Z>x)is equal to .7054.

-----

Find the z-value with a right tail of 0.7054

z = invNorm(1-0.7054) = -0.5400

x = zs+u

x = -5400*3+6 = 4.38

Answer:

A

Step-by-step explanation:

180 - 75 = 105

Answer:

Step-by-step explanation:

l -> length

b -> width

h -> height

Find the area of four walls and ceiling. then subtract the area of four windows and a door form that area.

Area of four walls + ceiling = 2( lh + bh) +lb

 = 2*(20*5 + 15*5) + 20*15

= 2( 100 + 75) + 300

= 2* 175 + 300

= 350 +300

= 650 sq m

Area of window = 2 *3 = 6 sq.m

Area of four windows = 4*6 = 24 sq.m

Area of door = 2 * 1 =  2 sq.m

Area of four walls excluding 4 windows and door = 650 - 24 - 2 = 624 sq.m

Cost of painting = 624 * 6.50

                          = $ 4056

Answer:  1950 dollars to paint the ceiling only (ignoring the walls)

The cost to paint the walls only is 2106 dollars.

The cost to paint the walls and ceiling is 4056 dollars.

==================================================

Explanation:

It seems a bit strange how your teacher mentions the windows and doors, but then asks about the ceiling only. Perhaps this is a red herring, but I'm not sure.

Anyway, to directly answer the question, we'll need to find the area of the ceiling first. The ceiling is a rectangle of dimensions 20 m by 15 m, so its area is 20*15 = 300 square meters.

Since paint costs 6.50 dollars per square meter, the total cost for the ceiling alone is 6.50*300 = 1950 dollars

If your teacher only cares about the ceiling, then you can stop here (and ignore the next section below).

---------------------------

If you wanted to find the cost to paint the walls, then we need to find the area of the walls.

For now, ignore the windows and door. Two opposite walls have area of 20*5 = 100 m^2 each. That accounts for 2*100 = 200 m^2 of wall area so far.

The other pair of opposite walls have area 15*5 = 75 m^2 each. That's another 2*75 = 150 m^2 of wall area.

In all, the total wall area without considering the windows or door is 200+150 = 350 m^2.

Now we consider the windows. Each window is 2 m by 3 m, yielding an area of 2*3 = 6 m^2. Four such windows have a total area of 4*6 = 24 m^2.

The door is 2 m by 1 m, so its area is 2*1 = 2 m^2

We'll subtract the wall area and the combined window+door areas to get

wallArea - windowArea - doorArea = 350-24-2 = 324

So after accounting for the windows and door, the amount of wall to paint is 324 m^2, which leads to a cost of 6.50*324 = 2106 dollars.

Therefore, painting the walls and ceiling gets us a total cost of 1950+2106 = 4056 dollars

This section is entirely optional if your teacher only cares about the ceiling.

Answer: 21

Step-by-step explanation:

My teacher just did it

Answer:

the adjustment made to the cost of goods sold is -$2,014

Step-by-step explanation:

The computation of the adjustment made to the cost of goods sold is given below:

Total actual overhead expenses $110,822

Less: Total overheads allocated -$112,836

Adjustment made to the cost of goods sold -$2,014

Hence, the adjustment made to the cost of goods sold is -$2,014

The same should be considered

Answer:

cube(v=l×l×l)

cylinder (v= πr^2h)

cone(v=1/3πr^2h)

rectangular prism (v= area of base×lenght)

pyramid (v=1/3×area of base×h)

Step-by-step explanation:

Cube:-a^3

Cuboid:-lbh

Cylinder :-pi r^2h

Cone:-1/3pi r^2h

Answer:

1.a+4=11

a=7

2.6=g+8

g=2

3.

?

4.k+8=3

k=-5

5.j+0=9

j=9

6.12+y=15

y=3

7.h-4=0

h=4

8.m-7=1

m=8

9.w+5=4

w=-2

10.b-28=33

b=61

11.45+f=48

f=3

12.n+7.1=8.6

n=1.5

Hope This Helps!!!

Answer:

He needs to borrow: 86667.84

His monthly payment would be: 514.06

He would pay a total of: 185061.6 over the life of the loan

Step-by-step explanation:

roger would need to borrow .72*120372= 86667.84

2.)

calculate the effective rate .059/12= .004916667

[tex]86667.84=x\frac{1-(1+.004916667)^{-30*12}}{.004916667}\\x=514.0585984[/tex]

which we round to 514.06

3.) he is going to pay a total of 514.06*30*12= 185061.6 over the life of the loan

Answer: 32 room

Step-by-step explanation:

[tex]7\frac{3}{4} =\frac{4(7)+3}{4} =\frac{28+3}{4} =\frac{31}{4}=7.75[/tex]

If 1 room = 7.75 yd of carpet ⇒ x rooms = 250 yd of carpet

Use proportions & cross-multiply to solve:

[tex]\frac{1}{7.75} =\frac{x}{250}\\7.75x=250\\x=\frac{250}{7.75} =32.258[/tex]

So 250 yd of carpet can cover about 32 rooms.

Answer:

58.8 in²

Step-by-step explanation:

you have no calculator ?

since you clearly have a computer or smart phone - there are calculator apps on all of them.

you really just need to use the given numbers and multiply and add them following the formula. so, what is your problem ?

anyway,

2pi×r×h + 2pi×r²

h = 5.9

r = 1.3

2pi × 1.3 × 5.9 + 2pi × 1.3² = 2pi × 7.67 + 2pi × 1.69 =

= 58.8 in²

Given:

Edge of a cubic box = n inches.

He decided to make the box 1 inch taller and 2 inches longer, while keeping its depth at n inches.

To find:

How many cubic inches greater than the box he originally planned to build?

Solution:

Edge of a cubic box is n inches, so the volume of the original cube is:

[tex]V_1=(edge)^3[/tex]

[tex]V_1=n^3[/tex]

According to the given information,

New width of the box = n+1

New length of the box = n+2

New height of the box = n

So, the volume of the new box is:

[tex]V_2=Length\times width\times h[/tex]

[tex]V_2=(n+2)(n+1)n[/tex]

[tex]V_2=(n^2+2n+n+2)n[/tex]

[tex]V_2=(n^2+3n+2)n[/tex]

[tex]V_2=n^3+3n^2+2n[/tex]

Now, the difference between new volume and original volume is:

[tex]V_2-V_1=n^3+3n^2+2n-n^3[/tex]

[tex]V_2-V_1=3n^2+2n[/tex]

So, the volume of new box is 3n^2+2n cubic inches more than the original box.

Therefore, the correct option is A.

Answer:

10

Step-by-step explanation:

As it could be inferred from the name, repeated measure design may be explained as experimental measures involving multiple (more than one) measures of a variable on the same observation, subject or participants which are taken at either various times or periodic intervals, different levels, different conditions. Hence, a repeated measurement taken with the same sample but under different treatment conditions. Therefore, since the measurement will be performed on a the same subjects(paired) , then the number of subjects needed will be 10. As it is this same samples that will be used for the other levels or conditions.

Answer:

a = 2

b = 5

Step-by-step explanation:

Given :

(ar^b)^4 = 16r^20 ; a and b are positive integers :

Opening the bracket :

a^4r^4b = 16r^20

a^4 = 16 - - - - - (1)

r^4b = r^20 - - - (2)

a^4 = 16

Take the 4th root of both sides :

(a^4)^(1/4) = 16^1/4

a = 2

From (2)

r^4b = r^20

4b = 20

Divide both sides by 4

4b/4 = 20/4

b = 5

Hence ;

a = 2

b = 5

Answer:

three

P A R

A R A D

A D I S E 

P Q R

A B C D

A B C D E

There are three such pairs of letters.