Answer:
a) 3n^2 + 11n + 8
b) 350
Step-by-step explanation:
10) 3(10^2)+ 5*10 = 350
n+1) 3(n+1)^2 + 5(n+1)
3(n^2 + 2n + 1) + 5n+5
3n^2 + 6n+3 + 5n + 5
3n^2 + 11n + 8
What are the coordinates of the terminal point for 8 = 330°?
1
A.
-
I
22
1
V3
O B.
2
V3
1
O c.
2
D.
1 3
2 2
Answer:
Step-by-step explanation:
If you plot this angle in the coordinate plane, you will find yourself in the fourth quadrant with a referencew angle of 30. Constructing the triangle from that reference angle and using the Pythagorean triple for a 30-60-90 triangle, you get that the side adjacent to the reference angle is √3, the side opposite the reference angle is a -1, and the hypotenuse (which is NEVER negative!) is 2. The x and y coordinates of the terminal point result from the cos (related to the x coordinate) and the sin (related to the y coordinate). The cos of 30:
[tex]cos(30)=\frac{\sqrt{3} }{2}[/tex] and the sin of 30:
[tex]sin(30)=-\frac{1}{2}[/tex] so the coordinates of the terminal point on that angle are
[tex](\frac{\sqrt{3} }{2},-\frac{1}{2})[/tex]
You could also just go to your unit circle, find the angle 330 and look at the coordiantes they give you there for (cos, sin). But I'm a high school math teacher so I wanted you to know how to find this outside of the unti circle. Cuz what if you lost it!?
A boy had 3 apples and lost one, how many does he have now
Step-by-step explanation:
i would love to say 2 but the word had shows that he does not have 3 apples anymore so the answer is either
0 or -1
The number of apples left after taking the 1 apple from 3 apples by a person is 2 apples.
What is subtraction?Subtraction stands for the resultant number, which exists acquired by taking the difference of a number from another number.
Let a number be subtracted from the number b. Then the consequent number after subtracting b from a will be,
d = b - a
Here, (a, b) exists the real numbers.
It exists given that there exist 3 apples. 1 apple stand was taken. Let's assume after taking the 3 apples, that there exist x apples remaining.
As there exist a total of 3 apples and 1 apple stand taken, then to estimate the number of apples left, we must subtract 1 apple from 3 apples.
Therefore, the total apples left exist,
x = 3 - 1
x = 2
To learn more about subtraction operation
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What is the sum of the first 7 terms of the geometric series:
Answer:
-15.875
Step-by-step explanation:
First, we can sum up the first 5 terms.
-8 + (-4) = -12
-12 + (-2) = -14
-14 + (-1) = -15
-15 + (-1/2) = -15.5
Next, we can find a pattern in the data. We can tell that the next number is one half of the current number. For example, -4 is one half of -8. To find the next number, we simply multiply our current number by one half. Thus, the sixth number is -1/4 and the seventh is -1/8. Adding these to our current total, we have
-15.5 - 1/4 = -15.75
-15.5 - 1/8 = -15.875 as our answer
If f(x) = 4^x-8 and g(x) = 5x+6, find (f + g)(x)
A. (F+g)(x) = -4^x - 5x + 2
B.(F+g)(x) = 4^x + 5x - 2
C.(F+g)(x) = 4^x - 3x + 6
D.(F+g)(x) = 9x - 2
Hey there!
We are given two functions - one is Exponential while the another one is Linear.
[tex] \large{ \begin{cases} f(x) = {4}^{x} - 8 \\ g(x) = 5x + 6 \end{cases}}[/tex]
1. Operation of Function
(f+g)(x) is a factored form of f(x)+g(x). We can common factor out x. Therefore:[tex] \large{(f + g)(x) = f(x) + g(x)}[/tex]
2. Substitution
Next, we substitute f(x) = 4^x+8 and g(x) = 5x+6.[tex] \large{(f + g)(x) = ( {4}^{x} - 8) + (5x + 6)}[/tex]
3. Evaluate/Simplify
Cancel out the brackets and combine like terms.[tex] \large{(f + g)(x) = {4}^{x} - 8 + 5x + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 8 + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 2}[/tex]
4. Final Answer
(f+g)(x) = 4^x+5x-2the radius of the right circular cylinder shown below is growing at a rate of 2ft/min while it's height is shrinking at 3ft/min. At what rate is the volume of the cylinder changing, with respect to time, when the radius is 4ft and the volume is 32 ft cubed.
Answer:
The volume is decreasing at a rate of about 118.8 cubic feet per minute.
Step-by-step explanation:
Recall that the volume of a cylinder is given by:
[tex]\displaystyle V=\pi r^2h[/tex]
Take the derivative of the equation with respect to t. V, r, and h are all functions of t:
[tex]\displaystyle \frac{dV}{dt}=\pi\frac{d}{dt}\left[r^2h\right][/tex]
Use the product rule and implicitly differentiate. Hence:
[tex]\displaystyle \frac{dV}{dt}=\pi\left(2rh\frac{dr}{dt}+r^2\frac{dh}{dt}\right)[/tex]
We want to find the rate at which the volume of the cylinder is changing when the radius if 4 feet and the volume is 32 cubic feet given that the radius is growing at a rate of 2ft/min and the height is shrinking at a rate of 3ft/min.
In other words, we want to find dV/dt when r = 4, V = 32, dr/dt = 2, and dh/dt = -3.
Since V = 32 and r = 4, solve for the height:
[tex]\displaystyle \begin{aligned} V&=\pi r^2h \\32&=\pi(4)^2h\\32&=16\pi h \\h&=\frac{2}{\pi}\end{aligned}[/tex]
Substitute:
[tex]\displaystyle\begin{aligned} \frac{dV}{dt}&=\pi\left(2rh\frac{dr}{dt}+r^2\frac{dh}{dt}\right)\\ \\ &=\pi\left(2(4)\left(\frac{2}{\pi}\right)\left(2\right)+(4)^2\left(-3\right)\right)\\\\&=\pi\left(\frac{32}{\pi}-48\right)\\&=32-48\pi\approx -118.80\frac{\text{ ft}^3}{\text{min}}\end{aligned}[/tex]
Therefore, the volume is decreasing at a rate of about 118.8 cubic feet per minute.
Please help! Thank you!
Answer:
B
Step-by-step explanation:
Divide both sides by 3
Take square root of both sides.
Add 9 to both sides.
What is the y-coordinate of the point that divides the
directed line segment from J to k into a ratio of 2:3?
13
12+
11+
10
9
8
7+
v = ( my mom n Ilv2 – va) + ve
O 6
0-5
6+
05
5
07
5
4+
3+
1 27
Mi
Answer:
5
Step-by-step explanation:
took the test
The coordinates of the point that divides the line segment from J to K into a ratio of 2:3 are P(-5,7), and the y-coordinate is 7, the correct option is D.
What is the ratio?Ratio is described as the comparison of two quantities to determine how many times one obtains the other. The proportion can be expressed as a fraction or as a sign: between two integers.
We are given that;
Ratio= 2:3
Now,
Let the point we are looking for be denoted as P(x,y), and let the ratio be 2:3, which means that the distance from J to P is 2/5 times the distance from J to K.
Using the distance formula, we can find the distance between J and K as:
d = sqrt((x2-x1)^2 + (y2-y1)^2)
= sqrt((-8 - (-3))^2 + (11 - 1)^2)
= sqrt(25 + 100)
= sqrt(125)
The distance from J to P is 2/5 of the total distance, which is:
(2/5)d = (2/5)sqrt(125) = 2sqrt(5)
Using the ratio formula, we get:
x = (3* (-3) + 2 * (-8)) / (3+2) = -5
y = (31 + 211) / (3+2) = 7
Therefore, by the given ratio answer will be 7.
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Exam V Psych 2317 Name: _____________________________
Attention: Read carefully each sentence and choose the best answer (2 points each)
1) While comparing a sample to a population, which design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
2) While comparing two samples of different individuals, which research design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
3) While comparing the same individuals two times, which research design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
4) While comparing three samples of different individuals with an interest in one variable, which design is appropriate?
If $3000 is invested at 3% interest, find the value of the investment at the end of 7 years if the interest is compounded as follows. (Round your answers to the nearest cent.)
(i) annually
(ii) semiannually
(iii) monthly
(iv) weekly
(v) daily
(vi) continuously
Answer:
annualy=$3689.62
semiannually=$3695.27
monthly=$3700.06
weekly=$3700.81
daily=$3701.00
Continuously=$3701.03
Step-by-step explanation:
Given:
P=3000
r=3%
t=7 years
Formula used:
Where,
A represents Accumulated amount
P represents (or) invested amount
r represents interest rate
t represents time in years
n represents accumulated or compounded number of times per year
Solution:
(i)annually
n=1 time per year
[tex]A=3000[1+\frac{0.03}{1} ]^1^(^7^)\\ =3000(1.03)^7\\ =3689.621596\\[/tex]
On approximating the values,
A=$3689.62
(ii)semiannually
n=2 times per year
[tex]A=3000[1+\frac{0.03}{2}^{2(4)} ]\\ =3000[1+0.815]^14\\ =3695.267192[/tex]
On approximating the values,
A=$3695.27
(iii)monthly
n=12 times per year
[tex]A=3000[1+\frac{0.03}{12}^{12(7)} \\ =3000[1+0.0025]^84\\ =3700.0644[/tex]
On approximating,
A=$3700.06
(iv) weekly
n=52 times per year
[tex]A=3000[1+\frac{0.03}{52}]^3^6 \\ =3000(1.23360336)\\ =3700.81003[/tex]
On approximating,
A=$3700.81
(v) daily
n=365 time per year
[tex]A=3000[1+\frac{0.03}{365}]^{365(7)} \\ =3000[1.000082192]^{2555}\\ =3701.002234[/tex]
On approximating the values,
A=$3701.00
(vi) Continuously
[tex]A=Pe^r^t\\ =3000e^{\frac{0.03}{1}(7) }\\ =3000e^{0.21} \\ =3000(1.23367806)\\ =3701.03418\\[/tex]
On approximating the value,
A=$3701.03
5.11.
A manufacturing process produces 500 parts per hour. A sample part is selected about every half hour, and after five parts are obtained, the average of these five measurements is plotted on an x control chart.
(a) Is this an appropriate sampling scheme if the assignable cause in the process results in an instantaneous upward shift in the mean that is of very short duration?
(b) If your answer is no, propose an alternative procedure. If your answer is yes, justify.
5.12.
Consider the sampling scheme proposed in Exercise 5.11. Is this scheme appropriate if the assignable cause results in a slow, prolonged upward drift in the mean? If your answer is no, propose an alternative procedure.
Answer:
Following are the response to the given points:
Step-by-step explanation:
For question 5.11:
For point a:
For all the particular circumstances, it was not an appropriate sampling strategy as each normal distribution acquired is at a minimum of 30(5) = 150 or 2.5 hours for a time. Its point is not absolutely fair if it exhibits any spike change for roughly 10 minutes.
For point b:
The problem would be that the process can transition to an in the state in less than half an hour and return to in the state. Thus, each subgroup is a biased selection of the whole element created over the last [tex]2 \frac{1}{2}[/tex] hours. Another sampling approach is a group.
For question 5.12:
This production method creates 500 pieces each day. A sampling section is selected every half an hour, and the average of five dimensions can be seen in a [tex]\bar{x}[/tex]line graph when 5 parts were achieved.
This is not an appropriate sampling method if the assigned reason leads to a sluggish, prolonged uplift. The difficulty would be that gradual or longer upward drift in the procedure takes or less half an hour then returns to a controlled state. Suppose that a shift of both the detectable size will last hours [tex]2 \frac{1}{2}[/tex] . An alternative type of analysis should be a random sample of five consecutive pieces created every [tex]2 \frac{1}{2}[/tex] hour.
The width of a rectangular slab of concrete is 7 m less than the length. The area is 98 m squared. Find the dimensions
Answer:
Length = 14 m, Width = 7 m
Step-by-step explanation:
Let the length is l and width is b.
Width, b = l-7
Area of the rectangle, A = 98 m²
We know that, the area of a rectangle is as follow :
[tex]A=lb[/tex]
So,
[tex]98=l(l-7)\\\\98=l^2-7l\\\\l^2-7l-98=0\\\\l^2+7l-14l-98=0\\\\l(l+7)-14(l+7)=0\\\\l=14,-7[/tex]
Length can't be negative. So,
Width, b = 14-7 = 7 m
So, the dimensions of the rectangle are 14 m and 7 m respectively.
Graph 9x + 15y = 15.
Need help please.. :(
Answer:
option d is correct one in which value of T lies
Which choice is equivalent to √10*√5
Answer:
5√2
Step-by-step explanation:
Given √10*√5
Using surd, the expression can be evaluated further as :
√10*√5 = √50
√50 can be expressed as :
√50 = √25*2 = √25 * √2
√25 = 5
Hence,
√50 = √25 * √2 = 5√2
Hence, √10*√5 = 5√2
25 x 2
help me
plz understand me by opening
Answer:
[tex]25 \times 2 = 50 \\ you \: are \: idiot \: [/tex]
really?! :|
What is the smallest three-digit number that is divisible by 3? Explain how you know without multiplying or dividing.
What piece of information is needed to prove
the triangles are congruent through ASA?
Answer:
B. <B is congruent to the <Z
OPTION B is the correct answer
If the bearing of P and
Q is
145°. What is the bearing of
Q from P?
9514 1404 393
Answer:
325°
Step-by-step explanation:
The bearing in the reverse direction is 180° more (or less) than the bearing in the forward direction.
145° +180° = 325°
The bearing of Q from P is 325°.
If the bearing of P and
Q is 145°
Soo,
the bearing of Q from P is 145+180=325°
Because it is reserve in the forward direction
[tex]\sf{ }[/tex] [tex]\sf{ }[/tex] [tex]\sf{ }[/tex]
Visually demonstrate the decimal .3 in the hundred square below. Explain how you what to shade.
(-4x+6)+(x-5) please answer I’ll be happy :)
Answer:
− 3 x + 1
Step-by-step explanation:
Answer: -3x + 1
Step-by-step explanation: I know Math O_O
Use Lagrange multipliers to solve the following exercise. A home improvement contractor is painting the walls and ceiling of a rectangular room. The volume of the room is 18042.75 cubic ft. The cost of wall paint is $0.06 per square foot and the cost of ceiling paint is $0.11 per square foot. Find the room dimensions that result in a minimum cost for the paint.
Answer:
Let the width of the garden =x meter
Then length=(x+4) meter
Half perimeter =36 m
So perimeter of garden =(2×36)=72 meters
According to the question
⇒2(l+b)=72
⇒2(x+x+4)=72
⇒2x+2x+4=74⇒4x=64⇒x=16 meters
Hence,the width of the garden =16 meters
The length of the garden =(16+4)=20 meters
What is the segment
Parallel lines
How many degrees are in a quarter circle? 25° 40° 90° 100°
Answer:
90
Step-by-step explanation:
360 ÷ 4 = 90
what is the probability of the two numbers being the same if two regular dice are thrown?
Answer:
1/6
Step-by-step explanation:
1 and 1
2 and 2
3 and 3
4 and 4
5 and 5
6 and 6
6/36 = 1/6
Answer:
1/6.
Step-by-step explanation:
The favourable outcomes are 1,1 2,2 3,3 4,4 5,5 and 6,6 = 6 outcomes.
All the possible outcomes for 2 regular dice = 36.
Therefore the required probability = 6/36
= 1/6.
csc(π/2) =__
a.0
b.-1
c.1
d.undefined
Hi there!
[tex]\large\boxed{C. \text{ } 1}[/tex]
csc (π/2)
π/2 is located at (0, 1)
csc is equal to 1/y, or the reciprocal of the y-value
Therefore:
csc(π/2) = 1/1 = 1. C is the correct answer.
Thinking Critically and Solving Problems
About how much did the percent of working women with some college or an associate degree change
from 1996 to 2016?
Use the graph to answer the question.
Percent of women in the labor
force by educational attainment
100%
OOOO
A) 0%
B) 8%
C) 12%
D) 70%
80%
60%
Less than a high school diploma
High school graduates, no college
Some college or associate degree
Bachelor's degree and higher
40%
20%
0%
SUBMIT
1996
2006
2016
Source: U.S. Bureau of Labor Statistics
Question 16 of 21
31 AM
Answer:maybe B?
Step-by-step explanation:
Angles PTQ and STR are vertical angles and congruent.
Circle T is shown. Line segments T P, T Q, T R, and T S are radii. Lines are drawn to connect the points on the circle and form secants P Q, Q R, R S, and S P. Angles P T Q and S T R are congruent.
Which chords are congruent?
QP and SR
QR and
PR and RS
PR and PS
9514 1404 393
Answer:
(a) QP and SR
Step-by-step explanation:
The congruent central angles intercept congruent arcs QP and SR. Chords of congruent arcs are congruent.
chords QP and SR are congruent
Answer: its A
Step-by-step explanation:
CLB is better than DONDA
It has been determined that 60% of the people in a certain midwest city who are responsible for preparing the evening meal have no idea what they are going to prepare as late as 4PM in the afternoon. A recent survey was conducted from 1000 of these individuals. For the sampling distribution of the sample proportion to be reasonably Normal, the sample must have been obtained in the right way (ideally, a simple random sample) and the sample size must be large (so that at least 10 or more successes and failures). Are these conditions met
Answer:
Random sample, [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], so yes, both conditions were satisfied.
Step-by-step explanation:
60% of the people in a certain midwest city who are responsible for preparing the evening meal have no idea what they are going to prepare as late as 4PM in the afternoon.
This means that [tex]p = 0.6[/tex]
A recent survey was conducted from 1000 of these individuals.
This means that [tex]n = 1000[/tex]
Also, a random sample, so the first condition was satisfied.
The sample size must be large (so that at least 10 or more successes and failures).
[tex]np = 1000*0.6 = 600 \geq 10[/tex]
[tex]n(1-p) = 1000*0.4 = 400 \geq 10[/tex]
So yes, both conditions were met.
Examine the following expression.
p squared minus 3 + 3 p minus 8 + p + p cubed
Which statements about the expression are true? Check all that apply.
The constants, –3 and –8, are like terms.
The terms 3 p and p are like terms.
The terms in the expression are p squared, negative 3, 3 p, negative 8, p, p cubed.
The terms p squared, 3 p, p, and p cubed have variables, so they are like terms.
The expression contains six terms.
The terms p squared and p cubed are like terms.
Like terms have the same variables raised to the same powers.
The expression contains seven terms.
Answer:
the terms in the expression are p squared, negative 3,3p, negative 8,p,p cubed
Step-by-step explanation:
hope that helps
Solve the right triangle ABC, with C = 90.00◦ , a = 15.21 cm, b = 17.34 cm. Round to two decimal places.
Answer:
the hypotenuse side, c = 23.1 cmangle A = 41.26 ⁰angle B = 48.74 ⁰Step-by-step explanation:
Given;
first leg of the right triangle, a = 15.21 cm
second leg of the right triangle, b = 17.34 cm
Angle C = 90 ⁰
The missing parameters;
the hypotenuse side = cangle Aangle BUse Pythagoras theorem to calculate the missing side "c", which is the hypotenuse
c² = a² + b²
c² = (15.21)² + (17.34)²
c² = 532.02
c = √532.02
c = 23.1 cm
The missing angle A is calculated as;
[tex]tan(A) = \frac{a}{b} \\\\tan(A) = \frac{15.21}{17.34} \\\\tan(A) = 0.8772 \\\\A = tan^{-1} (0.8772)\\\\A = 41.26^0[/tex]
The missing angle is calculated as;
B = 90⁰ - A
B = 90⁰ - 41.26⁰
B = 48.74⁰
