Answer:
1) an observer in B 'sees the two simultaneous events
2)observer B sees that the events are not simultaneous
3) Δt = Δt₀ /√ (1 + v²/c²)
Explanation:
This is an exercise in simultaneity in special relativity. Let us remember that the speed of light is the same in all inertial systems
1) The events are at rest in the reference system S ', so as they advance at the speed of light which is constant, so it takes them the same time to arrive at the observation point B' which is at the point middle of the two events
Consequently an observer in B 'sees the two simultaneous events
2) For an observer B in system S that is fixed on the Earth, see that the event in A and B occur at the same instant, but the event in A must travel a smaller distance and the event in B must travel a greater distance since the system S 'moves with velocity + v. Therefore, since the velocity is constant, the event that travels the shortest distance is seen first.
Consequently observer B sees that the events are not simultaneous
3) let's calculate the times for each event
Δt = Δt₀ /√ (1 + v²/c²)
where t₀ is the time in the system S' which is at rest for the events
Which of the following is a type of natural disaster that has impacted Florida? A. Avalanche B. Flood C. Typhoon D. Volcano
If you get it right you get 100 points and brainliest
Answer:
B-flood
Explanation:
The Sunshine State is famous all around the world for many great things but also is famous because of a big array of natural disasters.From hurricanes, tropical storms, tornadoes, to fires and floods many natural disasters in Florida affect the lives of residents.
Answer:
B. Flood
Explanation:
I would say Floods because hurricanes creates floods so...yeah
Dr. John Paul Stapp was U.S. Air Force officer whostudied the effects of extreme deceleration on thehuman body. On December 10, 1954, Stapp rode a rocketsled, accelerating from rest to a top speed of 282 m/s(1015 km/h) in 5.00 s, and was brought jarringly back torest in only 1.40 s! Calculate his:
a. Acceleration
b. Deceleration.
Express each in multiples ofby taking its ratio to the acceleration ofgravity.
Answer:
(a) a = 56.4 m/s², his acceleration a, in multiples of gravity g, is 5.76 g
(b) a = -201.43 m/s², his deceleration -a, in multiples of gravity g, is -20.56 g
Explanation:
(a)
When moving upwards, the initial velocity, u = 0 (he accelerated from rest)
When moving upwards, the final velocity, v = 282 m/s
time of motion during this acceleration, t = 5 s
His acceleration is calculated as;
v = u + at
282 = 0 + 5a
a = 282 / 5
a = 56.4 m/s²
Ratio of his acceleration, a to gravity, g = a/g = 56.4 / 9.8 = 5.76
a = 5.76 g
(b)
When moving downwards, the initial velocity, u = 282 m/s
When moving downwards, the final velocity, v = 0 (he was brought to rest)
time of motion during this deceleration, t = 1.4 s
His deceleration is calculated as;
v = u + at
0 = 282 + 1.4a
1.4a = -282
a = -282 / 1.4
a = -201.43 m/s²
Ratio of his deceleration, -a to gravity, g = -a/g = 201.43 / 9.8 = 20.56
a = -20.56 g
A(n) ____ is an example of a mechanical wave.
Answer:
like fixing are car engine would be an example of a mechanical wave
Chloe's mother threatens to ground her for life if she comes home after curfew. Chloe knows her mother cannot follow through with that punishment and comes home late anyway. Chloe's mother should have used which tip for effective punishment?
She should have used a punishment that is really punishing.
She should have punished Chloe immediately after the bad behavior occurred.
She should have remained calm while punishing Chloe to eliminate the chance of abuse.
She should have punished Chole each and every time the bad behavior occurred.
Answer:
The third option
Explanation:
The third option would be the best choice because while staying calm, Cloe will feel guilty and her mother will not be stressed. Staying calm also shows that Cloe's mother loves her but is disapointed, making Cloe think twice about her actions, while yelling and whipping only puts fear into her mind.
In this example we will analyze the forces acting on your body as you move in an elevator. Specifically, we will consider the case where the elevator is accelerating. Suppose that you stand on a bathroom scale that rests on the floor of an elevator. (Don’t ask why!) Standing on the scale compresses its internal springs and activates a dial that indicates your weight in newtons. When the elevator is at rest, the scale reads 600 N. Suppose that the elevator is accelerating downward at 2.50 m/s2 . What does the scale read during the acceleration?
Answer:
The reading of the scale during the acceleration is 446.94 N
Explanation:
Given;
the reading of the scale when the elevator is at rest = your weight, w = 600 N
downward acceleration the elevator, a = 2.5 m/s²
The reading of the scale can be found by applying Newton's second law of motion;
the reading of the scale = net force acting on your body
R = mg + m(-a)
The negative sign indicates downward acceleration
R = m(g - a)
where;
R is the reading of the scale which is your apparent weight
m is the mass of your body
g is acceleration due to gravity, = 9.8 m/s²
m = w/g
m = 600 / 9.8
m = 61.225 kg
The reading of the scale is now calculated as;
R = m(g-a)
R = 61.225(9.8 - 2.5)
R = 446.94 N
Therefore, the reading of the scale during the acceleration is 446.94 N
Which notation is commonly used on force diagrams to show forces acting on an object? (FD, FZ, FN or FX)
Answer:
FD guys
Explanation:
The notation that is commonly used on force diagrams to show forces acting on an object is FD.
What is free body diagram (FD)
A free body diagram is a diagram that contains all the forces acting on an object.
These forces acting on an object include the following:
Upward force (normal reaction due to weight of the object)Downward force (downward force due to weight of the object)Frictional force (force resisting the motion)Thus, the notation that is commonly used on force diagrams to show forces acting on an object is FD.
Learn more about free body diagram here: https://brainly.com/question/21691401
The mass of the planet Mars is 6.39 x 10^23 kg. Using Newton's Law of Gravitation, calculate the force of gravity between the planet Mars and the 74 kg Mars Rover drone on the surface if the distance between the center of Mars and surface is 2129.9 km. Show all work.
Need it ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Answer:
F = 695.25 N
Explanation:
The force between Mars and Rover can be given by Newton's Law of Gravitation can be written as follows:
F = Gm₁m₂/r²
where,
F = Force of Gravity = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = mass of rover = 74 kg
m₂ = mass of mars = 6.39 x 10²³ kg
r = distance between the centers of mars and rover = 2.1299 x 10⁶ m
Therefore,
F = (6.67 x 10⁻¹¹ N.m²/kg²)(74 kg)(6.39 x 10²³ kg)/(2.1299 x 10⁶ m)²
F = 695.25 N
Students use a stretched elastic band to launch carts of known mass horizontally on a track. The elastic bands exert a force F, which is nonlinear as a function of the distance xx that the band is stretched. A meterstick is used to measure xx , and a motion detector is used to measure the resulting maximum speed of the carts. This procedure is repeated to gather data for several different values of x. Which of the following graphs, if linear, supports the hypothesis that F is a function of x^2?
A. A graph of the cart's maximum speed as a function of x
B. A graph of the cart's maximum speed as a function of x^2
C. A graph of the cart's maximum speed squared as a function of x
D. A graph of the cart's maximum speed squared as a function of x^2
E. A graph of the cart's maximum speed squared as a function of x^3
Answer:
the correct answer is E
A graph of the cart's maximum speed squared as a function of x^3
Explanation:
For this exercise let's use Newton's second law
F = m a
force has the form
F = k x²
and acceleration is related to velocity
a = dv / dt
Let's use the chain rule or L'Hospital
a = dv /dx dx/dt
a = dv /dx v
let's substitute
k x² = m v dv / dx
k /m x² dx = v dv
we integrate
k /m x³ /3 = v² / 2
v² = (2k /3m) x³
This is the expression for the variation of the speed as a function of the position, to make a linear graph realism the changes of variable
y = v²
x´ = x³
y = (2k/3m) x´
if we graph y vs x 'we have a linear graph whose slope is
m = 2k / 3m
By reviewing the different answers, the correct answer is E
Why vacuum flask is known as thermos flak?
The flask was later developed using new materials such as glass and aluminum; however, Dewar refused to patent his invention. ... The name later became a genericized trademark after the term "thermos" became the household name for such a vacuum-insulated container for liquids.
what was his gift to the pope
one way to increase acceleration is by
Answer:
One way to increase acceleration is by changing the velocity.
Consider the free-body diagram. Assume there is a net force of 30N to the right and the friction force equals 20N. What is the applied force in this situation?
A.) 20N
B.) 30N
C.) 50N
D.) 80N
Answer:the answer would be C.50N
Explanation:I just took the test
Answer:
50n
Explanation:
You are a member of a geological team in Central Africa. Your team comes upon a wide river that is flowing east. You must determine the width of the river and the speed of the current (the speed of the water relative to the earth). You have a small boat with an outboard motor. By measuring the time it takes to cross a pond where the water isn’t flowing, you have calibrated the throttle settings to the speed of the boat in still water. You set the throttle so that the speed of the boat relative to the river is a constant vv1. Traveling due north across the river, you reach the opposite bank in tt1. For the return trip, you change the throttle setting so that the speed of the boat relative to the water is vv2. You travel due south from one bank to the other and cross the river in tt2. (a) How wide is the river, and what is the speed of the current? (b) With the throttle set so that the speed of the boat relative to the water is 6.00 m/s, what is the shortest time in which you could cro
The process of testing a hypothesis by collecting data is called
2. A student drives 7.8-km trip to school and averages a speed of
32.6 m/s. On the return trip home, the student travels with an
average speed of 36.8 m/s over the same distance. What is the
average speed (in m/s) of the student for the two-way trip? (Be
careful.) Also, what is the total time taken for the trip?
Answer:
The total time is: t=451.22 sec
The average speed is: V=34.57 m/s
Explanation:
Average speed
The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).
[tex]\displaystyle V=\frac{x}{t}[/tex]
Since the student makes the trip in two parts, we have to calculate the total distance and the total time.
We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is
x=2*7,800 m=15,600 m
The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:
[tex]\displaystyle t1=\frac{x1}{v1}=\frac{7,800}{32.6}=239.26\ sec[/tex]
The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:
[tex]\displaystyle t2=\frac{x2}{v2}=\frac{7,800}{36.8}=211.96\ sec[/tex]
The total time is:
[tex]t=239.26\ sec+211.96\ sec=451.22\ sec[/tex]
[tex]\boxed{t=451.22\ sec}[/tex]
The average speed is:
[tex]\displaystyle V=\frac{15,600}{451.22}=34.57\ m/s[/tex]
[tex]\boxed{\displaystyle V=34.57\ m/s}[/tex]
A number is written in scientific notation when it is the product of a number less than 10 but greater than or equal to 1 and a power of 10. All numbers in scientific notation have the following form.
A✕10^n
The mass of the Sun is 1,990,000,000,000,000,000,000,000,000,000 kg. Express the mass in kg using scientific notation. (Enter your answer using one of the following formats: 1.2e-3 for 0.0012 and 1.20e+2 for 120. WebAssign allows you to enter answers using scientific notation. For example, a number in scientific notation such as 1.32 104 would need to be entered as 1.32e4. The system requires that you do not use spaces. Enter your answer to two decimal places.)Â
____________kg
Answer:
[tex]Mass = 1.99 * 10^{30} kg[/tex]
Explanation:
Given
[tex]Mass = 1,990,000,000,000,000,000,000,000,000,000\ kg[/tex]
Required
Rewrite using scientific notation
The format of a number in scientific notation is
[tex]Digit = a * 10^n[/tex]
Where [tex]1 \geq\ a\geq\ 10[/tex]
So the given parameter can be rewritten as
[tex]Mass = 1.99 * 1,000,000,000,000,000,000,000,000,000,000\ kg[/tex]
Express as a power of 10
[tex]Mass = 1.99 * 10^{30} kg[/tex]
Hence, the equivalent of the mass of the sun in scientific notation is:
[tex]Mass = 1.99 * 10^{30} kg[/tex]
You are pulling a sled along a level surface. The weight on the sled increases as some packages are added. How do you think that the force you exert to pull the sled changes?
A. It increases
B. It decreases
C. It remains the same
Answer: A it increases cuz da more heavy the object or whatever the more force u gotta use to pull it
What kind of waves can travel through empty space or a vacuum?
A.Sound
B.Light
C.Frequency
D.Wavelength
Answer:
the answer is B.
Answer:
light
Explanation:
you can see stuff in space but cant hear it
Questions:
(a) Why should the amplitude of oscillation be small on a pendulum experiment
who is sitting in the rear of their boat in still water, entertains Juliet by playing his guitar. After the song, Juliet, who was sitting in the front of the boat (closest to shore), carefully moves to the rear to plant a kiss on Romeo's cheek. The 100-kg boat is facing shore and the 50 kg Juliet moves towards the 70 kg Romeo. The length of the boat is 4 m, and we can neglect water resistance when the boat moves. How far does the boat move? Does it move toward or away from the shore?
Answer:
Δx = -1.27 m
the boat moves away from the shore
Explanation:
Let's analyze the exercise a little, to know when the boat has moved, we can fixate on a point, let's use the point of the center of mass, before and after the movement of people.
The center of mass is defined by.
[tex]x_{cm}[/tex]= 1 /M ∑ m_i x_i
where M is the total mass of the object, x_i and m_i are the positions and masses of each part of the system.
let's find the total mass
M = m_boat + m_Juliet + m_Romeo
M = 100 + 50 + 70
M = 220 kg
now let's look for the center-mass position
initial. Before the movement of people
x_{cm1} = 1/M (x_boat m_boat + x_juliet m_juliet + x_romeo m_romeo)
Let's find the position of each object, let's fix our reference system on the front of the boat
The boat its center of mass coincides with its geometric center
x_boat = 2 m
Julliet is sitting in the front of the boat
x_juliet = 0 m
Romeo is sitting in the back of the boat
x_romeo = 4 m
we substitute
x_{cm1} = 1/220 (2 100 + 50 0 + 70 4)
x_{cm1} = 2.1818 m
final. After the movement of people
positions
boat
x_boat = 2 m
Juliet
x_juliet = 0 m
Romeo
x_romeo = 0 m
we substitute
x_{cm2} = 1/220 (2 100 + 50 0 + 500 0)
x_{cm2} = 0.9090 m
the movement of the boat is
Δx = x_cm2 - xcm1
Δx = 0.9090 - 2.1818
Δx = -1.27 m
The negative sign indicates that the boat moves in the opposite direction to the movement of people, therefore the boat moves away from the shore
How does the lens from which you view the world shape your approach to research inquiry?
Why is it important as a scholar-practitioner engaged in research to acknowledge your worldview ?
LEARNING RESOURCES Required Readings
Babbie, E. (2017). Basics of social research (7th ed.). Boston, MA: Cengage Learning.
Chapter 1, “Human Inquiry and Science”
Burkholder, G. J., Cox, K. A., Crawford, L. M., & Hitchcock, J. H. (Eds.). (2020). Research designs and methods: An applied guide for the scholar-practitioner. Thousand Oaks, CA: Sage.
Chapter 1, "Introduction to Research"
Chapter 2, “Philosophical Foundations and the Role of Theory in Research”
Acknowledging one's worldview as a scholar-practitioner is crucial as it influences research inquiry. It shapes research questions, methods, and interpretations. Recognizing biases and being open to diverse perspectives ensures reliable and valid research.
As a scholar-practitioner engaged in research, it is important to acknowledge your worldview because your worldview affects the approach you take to research inquiry. It shapes your research questions, methods, and interpretations. The lens through which you view the world is informed by your background, culture, experiences, and beliefs. Therefore, two scholars may approach the same research question differently based on their worldviews. For instance, a scholar from an individualistic culture may approach a research question on teamwork differently from a scholar from a collectivistic culture. The individualistic scholar may focus on the individual's contribution to the team, while the collectivistic scholar may focus on the team's contribution to the individual.To conduct research that is reliable and valid, it is crucial for the scholar-practitioner to acknowledge their worldview and recognize that it shapes their approach to research inquiry. By acknowledging their worldview, the scholar-practitioner can identify and manage their biases and take steps to minimize them. They can also be open to multiple perspectives and incorporate them into their research to enhance its credibility. In conclusion, acknowledging your worldview as a scholar-practitioner is essential for conducting research that is reliable and valid. It helps you identify and manage your biases and be open to multiple perspectives.For more questions on interpretations
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A woman holds a tuning fork that vibrates at frequency 0 f while she runs horizontally toward a vertical wall at speed w v . The speed of sound is v. She holds the tuning fork in such a way that the smooth wall reflects the sound perfectly. This reflection produces a Doppler shift in frequency, equivalent to what would happen if there were a second woman on the other side of the wall running toward the original woman.
What beat frequency does the woman detect (in terms of the given quantities)?
Answer: The beat frequency detect by the woman is f0 [ 2v / ( v - vW) ]
Explanation:
given a Doppler effect,
the frequency heard by the listener in terms of frequency of source is expressed as;
fL = [ (v + vL) / (v + vS) ] fS
vL is the velocity of the listener, vS is the velocity of the source and V is the velocity of sound.
Now What beat frequency does the woman detect (in terms of the given quantities)?
The wall will receive and reflect pulses at a frequency of;
fWALL =( v / (v - v0)) f0
so the woman will hear this wave;
fWOMAN = ((v + vW) / v) ( v / (v - vW)) f0
fWOMAN = (( v + vW) / ( v - vW)) f0
Now the beat frequency will be;
fBEAT = ((v + vW) / (v - vW)) f0 - f0
fBEAT= f0 [ ((v + vW) / (v - vW)) - 1 ]
fBEAT= f0 [ 2v / ( v - vW) ]
The beat frequency detect by the woman is f0 [ 2v / ( v - vW) ]
Two resistances of 100ohms and 0 ohms were connected in parallel. What is the overall resistance
Answer:
20 ohms,100*2/10=20
Explanation:
since it as to be in parallel arrangement and connected in side by side due to same p.d in a cross each resistor
Consider an object with mass m that is thrown with an initial speed 0 at an angle θ with respect to the ground. The gravitational acceleration is g and it can be assumed to be constant. Derive the differential equations, and initial conditions, that govern the horizontal and vertical motion of the object assuming
(a) no air resistance and
(b) air resistance is proportional to the speed of the object.
Answer:
a) dx = v₀o cos θ dt , dy = (v_{oy} - g t) dt
b) dx / dt = v₀ₓ e^{- (\gamma/ m) t} , dv_y/dt - γ/m v_y + g =0
Explanation:
For this exercise we will use Newton's second law on each axis
F = m a
F = m d²x / dt²
let's use trigonometry for the components of the initial velocity
cos θ = v₀ₓ / v₀
sin θ = v_{oy} / v₀
v₀ₓ = vo cos θ
v_{oy} = v₀ sin θ
now we will work on each component
a) in this case there is no air resistance
X axis
Fₓ = 0
0 = m d²x / dt²
0 = m dv / dt
we integrate once
m dv = 0
m (vf- vo) = 0
v_f = v₀
we use the definition of velocity
v = dx / dt
vₓ = dx / dt
dx = v₀ₓ dt
dx = v₀o cos θ dt
we integrate once
x_f-x₀ = vₓ cos θ (t-0)
y axis
in this case the force is the weight of the body
F = W = - mg
F = m a
-m g = ma
a = -g
we use the relationship between acceleration and velocity
a = dv / dt
dv / dt = -g
dv = -g dt
we integrate
(v_y-v_{oy}) = -g (t-0)
v_y = v_{oy} - g t
now we love the relationship
v = dy / dt
dy / dt = v_{oy} - g t
dy = (v_{oy} - g t) dt
we integrate
y- y_o = v_{oy} - ½ g t²
y = y_o + v₀ sin tea t - ½ g t²
B) in this case there is air resistance, we will assume that in the two axes
x-axis) resistance always opposes movement
fr = - g v
∑ F = m aₓ
- γ vx = m dvₓ / dt
dvₓ / vₓ = - γ/m dt
ln vₓ / ln v₀ₓ = - γ/m (t-0)
vₓ = v₀ₓ [tex]e^{- (\gamma/ m) t}[/tex]
let's use the relationship between speed and distance
dx / dt = v₀ₓ e^{- (\gamma/ m) t}
dx = v₀ₓ e^{- (\gamma/ m) t} dt
Y axis
∑ F = m a_y
fr- W = m a_y
γ v_y - m g = m a_y
a_y = γ/m v_y - g
d v_y / dt = (γ /m v_y - g)
dv_y/dt - γ/m v_y + g =0
in this equation differences for the initial time the velocities vo = vo sin θ
A projectile only has _____ acceleration and ______ velocity at the top of its path?
a. vertical, vertical
b. horizontal, horizontal
c. horizontal, vertical
d. vertical, horizontal
Answer:
d. vertical, horizontal
Explanation:
A projectile's acceleration is constantly downwards.
At the top of the path, the vertical velocity is 0, leaving only the horizontal component.
The time [tex]t[/tex] in seconds that it takes an object to fall a distance from [tex]d[/tex] ft from rest is given the formula [tex]\sqrt[]{2d/8}[/tex] where g is the acceleration due to gravity. Find the value of d when g = 32 ft/s² and [tex]t[/tex] = 3 s.
Answer:
144 ft
Explanation:
t = √(2d/g)
3 s = √(2d / (32 ft/s²))
9 s² = 2d / (32 ft/s²)
d = 144 ft
Answer:
d = 144 ft
General Formulas and Concepts:
Math
Order of Operations: BPEMDASPhysics
Vertical Kinematics Equation: d = 1/2gt²Gravity g is always equal to 9.8 m/s² or 32 ft/s²Explanation:
Step 1: Define
[tex]t=\sqrt{\frac{2d}{g} }[/tex] - we get this from algebraically solving to t from the kinematics equation
g = 32 ft/s²
t = 3 seconds
Step 2: Solve
Substitute: [tex]3=\sqrt{\frac{2d}{32} }[/tex]Square both sides: [tex]9=\frac{2d}{32}[/tex]Multiply 32 on both sides: [tex]288=2d[/tex]Divide 2 on both sides: [tex]144=d[/tex]Rewrite: [tex]d=144[/tex]An object has a constant acceleration of 2.0 meters
per second2
. The time required for the object to
accelerate from 8.0 meters per second to 28 meters
per second is
Answer: 10s
Explanation:
The time required for the object to accelerate is 10 seconds.
Given the following data:
Acceleration = 2.0 [tex]m/s^2[/tex]Initial velocity = 8.0 m/s.Final velocity = 28 m/s.To find the time required for the object to accelerate, we would use the first equation of motion:
Mathematically, the second equation of motion is given by the formula;
[tex]V = U + at[/tex]
Where:
V represents the final velocity. U is the initial velocity. a represents the acceleration.t is the time measured in seconds.Substituting the parameters into the formula, we have;
[tex]28.0 = 8.0 + 2t\\\\2t = 28.0 - 8.0\\\\2t = 20.0\\\\t = \frac{20.0}{2}[/tex]
Time, t = 10 seconds.
Therefore, the time required for the object to accelerate is 10 seconds.
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Can I get a essay about cell theory? 50 points worth plus brainlest answer 75 points!
Answer:
A Prussian physician Rudolph Virchow proposed in 1855 that all cells are produced from the same division of existing cells. The observations and conclusions of these scientists and others are summarized as the cell theory.
The cell theory is one of the fundamental ideas of modern biology
and includes three principles.
1. All living organisms are composed of one or more cells.
2. Cells are the basic unit of cell structure and organization of all living organisms.
3. Cells arise only from previously existing cells, with cells passing copies of their genetic material on to their daughter cells.
~I hope I helped you! :)~
An egg is thrown upward with a velocity of 4.5 m/s. How long will it take to reach it's maximum height?
Answer:
0.45 seconds
Explanation:
Letting the value of g = 10 m/s/s
final velocity (v) = 0 m/s (since the egg will come to rest at the maximum height)
initial velocity(u) = 4.5 m/s
acceleration = -10 m/s/s (since the gravity is acting against the egg)
time = t seconds
From the first equation of motion:
v = u + at
0 = 4.5 + (-10)t
t = -4.5 / -10
t = 0.45 seconds
What atmospheric gas is common in the outer planets but rare in the inner planets
Answer:
hydrogen
Explanation:
